1. Opposite charges
O repel
attract

Answer:

yes

Explanation:

its not a good thing for the rest of your life but you have a PS4

Answer:

Sy = S sin θ = 17.8 sin 63 = 15.9 m          north of east from the start

Answer:

Without knowing the actual distances involved, it's difficult to give a specific answer. However, we can use the information given in the question to determine the distance between points A and C using the Pythagorean theorem.

Let's assume that the boy walked a distance of x units from point A to point B, and a distance of y units from point B to point C. Then we can use the following diagram:

           C

           |

y           |

|           |   x

|-----------B

           |

           |

           A

According to the problem, the boy first walked a certain distance x in a direction that is not specified (we only know that it's forward and north). Then he turned 136 degrees to his right and walked a distance y to reach point C. Since the turn was to the right, the boy turned towards the east, so we can draw a line from point B towards the right to represent this change in direction.

Now we can apply the Pythagorean theorem to find the distance between points A and C:

AC² = AB² + BC²

We know that AB = x, and we need to find BC. To do so, we can use trigonometry. Since the boy turned 136 degrees to his right, he ended up facing 180 - 136 = 44 degrees east of north. This means that the angle between BC and AB is 90 - 44 = 46 degrees.

Using trigonometry, we can express BC in terms of y and the tangent of the angle 46 degrees:

tan(46) = BC / y

BC = y tan(46)

Substituting this expression for BC into the Pythagorean theorem equation, we get:

AC² = x² + (y tan(46))²

Simplifying:

AC² = x² + y² tan²(46)

We can calculate tan²(46) using a calculator or a table of trigonometric functions. Let's assume that tan²(46) is equal to 1.470. Then we have:

AC² = x² + 1.470y²

To find the distance between A and C, we need to take the square root of both sides of the equation:

AC = sqrt(x² + 1.470y²)

Without more information about the distances involved, we cannot compute the actual numerical value of AC.

Answer:

directly

Explanation:

Answer: Directly

Explanation:

Answer:

Explanation: The correct equation for Newton's second law in the horizontal direction for the block-spring system when it is displaced a distance x from the equilibrium position is:

m(d^2x/dt^2) + kx = 0

where m is the mass of the block, k is the spring constant, and x is the displacement from the equilibrium position. This equation represents the balance of forces acting on the block-spring system, with the restoring force of the spring (proportional to x) opposing the force required to accelerate the mass (proportional to d^2x/dt^2).

Answer:

16 times as strong

Explanation:

From the question given above, the following assumptions were made:

Initial Force (F₁) = F

Initial distance apart (r₁) = r

Final distance apart (r₂) = ¼r

Final force (F₂) =?

Next, we shall obtain a relationship between the force and the distance apart. This can be obtained as follow:

F = GM₁M₂ / r²

Cross multiply

Fr² = GM₁M₂

If G, M₁ and M₂ are kept constant, then,

F₁r₁² = F₂r₂²

Finally, we determine the new force as follow:

Initial Force (F₁) = F

Initial distance apart (r₁) = r

Final distance apart (r₂) = ¼r

Final force (F₂) =?

Fr² = F₂ × (¼r)²

Fr² = F₂ × r²/16

Fr² = F₂r² / 16

Cross multiply

16Fr² = F₂r²

Divide both side by r²

F₂ = 16Fr² / r²

F₂ = 16F

From the calculations made above, we can see that the new force is 16 times the original force.

Thus, the new force is 16 times stronger.

Answer:

338N

Explanation:

Use the formula \(f=\frac{\sqrt{\frac{T}{\frac{M}{L}} } }{2L}\)

f is the frequency, T the string tension, M the mass, and L the length

convert units to seconds, kilograms, meters

\(65Hz\ =\ \frac{\sqrt{\frac{T}{\frac{0.005kg}{m}}}}{2\cdot2m}\)

now solve for T

sqrt(T/.005) = 65*4 = 260

T = 338N

Frequency=  30 Hz, Period= 0.0333 s, Wave Number=15.708 rad/m, Wave Function= y(x, t) = 0.05 sin(15.708x - 94.248t), Transverse displacement= -0.013 m, Time= 0.297 s.

(a) To find the frequency (f), we can use the equation: wave speed = frequency x wavelength. Rearranging this equation, we get:

frequency = wave speed / wavelength

Substituting the given values, we get:

frequency = 12 m/s / 0.4 m = 30 Hz

Therefore, the frequency of the wave is 30 Hz.

To find the period (T), we can use the equation:

period = 1 / frequency

Substituting the frequency value we just calculated, we get:

period = 1 / 30 Hz = 0.0333... s (rounded to four decimal places)

Therefore, the period of the wave is approximately 0.0333 s.

To find the wave number (k), we can use the equation:

wave number = 2π / wavelength

Substituting the given values, we get:

wave number = 2π / 0.4 m = 15.708 rad/m (rounded to three decimal places)

Therefore, the wave number of the wave is approximately 15.708 rad/m.

(b) The wave function for a transverse wave on a string is given by:

y(x, t) = A sin(kx - ωt + φ)

where A is the amplitude, k is the wave number, x is the position of the point on the string, t is the time, ω is the angular frequency, and φ is the phase constant.

We already know the values of A, k, and ω from the previous calculations. To find φ, we can use the given initial condition: "at t = 0 end of the string has zero displacement and is moving upward". This means that y(0,0) = 0 and ∂y/∂t(0,0) > 0. Substituting these conditions into the wave function, we get:

0 = A sin(0 + φ)

∂y/∂t = -Aω cos(0 + φ)

Since sin(0 + φ) = sin(φ) = 0 (because sin(0) = 0), we get:

φ = nπ, where n is an integer

Since cos(0 + φ) = cos(φ) = 1 (because cos(0) = 1) and ∂y/∂t(0,0) > 0, we get:

n = 0 or 2

Therefore, the possible values of φ are 0 or 2π.

Substituting the values of A, k, ω, and φ, we get:

y(x, t) = 0.05 sin(15.708x - 94.248t)

Therefore, the wave function describing the wave is:

y(x, t) = 0.05 sin(15.708x - 94.248t)

(c) To find the transverse displacement of a wave at x = 0.25 m and t = 0.15 s, we can use the wave function we just found:

y(0.25, 0.15) = 0.05 sin(15.708(0.25) - 94.248(0.15))

y(0.25, 0.15) ≈ -0.013 m (rounded to three decimal places)

Therefore, the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m.

(d) To find how much time must elapse from the instant in part (c) until the point at x = 0.25 m has zero displacement,

From part (c), we know that the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m. We need to find the time it takes for this point to return to zero displacement.

We can use the wave function we found in part (b) and set y(0.25, t) = 0:

0 = 0.05 sin(15.708(0.25) - 94.248t)

Since sin(θ) = 0 when θ = nπ (where n is an integer), we get:

15.708(0.25) - 94.248t = nπ

Solving for t, we get:

t = (15.708(0.25) - nπ) / 94.248

To find the smallest positive value of t that satisfies this equation, we need to use the smallest positive value of n that makes the right-hand side of the equation positive (because we want to find the time it takes for the point at x = 0.25 m to return to zero displacement, which happens after the point has completed a full cycle). We can see from the equation that n must be an even integer to make the right-hand side positive. The smallest even integer greater than zero is 2. Substituting n = 2, we get:

t = (15.708(0.25) - 2π) / 94.248

t ≈ 0.297 s (rounded to three decimal places)

Therefore, the time it takes for the point at x = 0.25 m to return to zero displacement is approximately 0.297 s.

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Two natural sources of light: the sun and the stars

Two artificial sources of light: light bulb and torches

Answer:

Natural lights: Sunlight, Moonlight, or Lightning

Artificial: Light bulb, Candles, or a lighter/matches

Explanation:

The value of 3993 BTUs in Joules is 4212838.0195 Joules.

The value of spring constant (k) is 25 N/m.

Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.

To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.

Formula apply

U=mgh

U=1/2kx^2

putting the value of K ,x ,mass and g then

k is 25N/m

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Answer:

V = mRT /  (\(\frac{\pi }{4}\)d²)PM

Therefore, pressure decreases as velocity increases.

This is a hypothetical concept as the friction which causes the velocity to increases also makes the pressure decrease.

Explanation:

Given the data in the question;

we know that an ideal gas equation is;

\(_p\) = PM/RT --------------- let this be equation 1

P is pressure, M is molecular weight, R is universal gas constant and T is the absolute temperature.

The volumetric flow rate from the continuity equation is;

Q = AV

and A =  \(\frac{\pi }{4}\)d²

so, Q = (\(\frac{\pi }{4}\)d²)V ---------let this be equation 2

Expression for mass m in flowrate is;

m = Q\(_p\) ------------------let this be equation 3

so, m = (\(\frac{\pi }{4}\)d²)V × PM/RT

solve for V

V = mRT /  (\(\frac{\pi }{4}\)d²)PM

Therefore, pressure decreases as velocity increases.

This is a hypothetical concept as the friction which causes the velocity to increases also makes the pressure decrease.

Answer:

b is the ans......

Explanation:

"b" (and any subsequent words) was ignored because we limit queries to 32 words.

Answer:

Centripetal Force = 483.3 N

Explanation:

A centripetal force is the force that tends to keep a mocing object along a curved path and it is directed towards the centre of the rotatio, while centrifugal force is an apparent force that tends to force a rotating object away from the center of the rotation.

The formula for centripetal force is given by:

\(F_c = \frac{mv^2}{r} \\where:\\F_C = centripetal\ force\\m = mass\ = 22kg\\\omega =angular\ velocity = 40.0\ rev/min\)

Let us work on the angular velocity (ω), by converting to radians/ seconds

ω = 40 rev/min,

1 rev = 2π rad

∴ 40 rev = 2π × 40 rad = 80π rad

1 min = 60 seconds

\(\therefore\ 40\ rev \slash min = \frac{80\ \times\ \pi\ rad}{60\ seconds} \\40\ rev \slash min = 4.189\ rad \slash sec\)

Next let us find the velocity (v) from the angular velocity. Velocity (v) and angulsr velocity (ω) are related by the equation:

v = ω × r (m/s)

v = 4.189 × 1.25

v = 5.24 m/s

Finally, the centripetal force is calculated thus:

\(F_c = \frac{mv^2}{r} \\\\F_c = \frac{22 \times (5.24)^2 }{1.25} \\\\F_c = \frac{604.07}{1.25}\\ F_c = 483.3N\)

Answer:

Explanation:

Distance of barrier = 40 m

Distance covered during reaction time = .75 x 40 = 30 m .

distance covered during deceleration can be calculated as follows .

v² = u² - 2 a s

0 = 40² - 2 x 10 x s

s = 80 m

Total distance covered before coming to rest = 30 + 80 = 110 m

Distance of barrier = 40 m , so it will hit the barrier .

The object of interest for this situation is the piano. The forces acting on the piano are: (1) gravitational force acting on the piano (piano's weight). (2) force of the floor on the piano (normal force). (3) force of Chadwick on the piano

In this situation, the object of interest is the piano. The forces acting on the piano are the gravitational force (weight) pulling the piano down, the normal force of the floor pushing up on the piano, and the force of Chadwick pushing on the piano to move it up the ramp. Since the ramp is frictionless, the only force acting to stop the piano from sliding back down the ramp is the normal force of the floor, which is perpendicular to the ramp surface. Therefore, Chadwick must push the piano with a force greater than its weight to overcome gravity and move it up the ramp.

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Complete question:

Chadwick now needs to push the piano up a ramp and into a moving van. The ramp is frictionless. Is Chadwick strong enough to push the piano up the ramp alone or must he get help? To solve this problem you should start by drawing a free-body diagram.

Determine the object of interest for this situation.

Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.

(1) gravitational force acting on the piano (piano's weight)

(2) force of the floor on the piano (normal force)

(3) force of Chadwick on the piano

Answer:

Explanation:

a) the free body diagram of the lower pulley would have two force vectors of equal magnitude acting upward and the block weight acting downward. These must balance so 2F = Wt

                                          F = 262/2 = 131 N

b) as the force needed is half of the block weight, the mechanical advantage is 262 / 131 = 2

c) with a mechanical advantage of 2, he would have to pull twice the distance of block motion or 2(3.00) = 6.00 m

d) W = Fd = 131 N(6.00 m) = 786 J

which is the same as the increase in potential energy of the block

e) W = mgh = 262(3.00) = 786 J

The force that acts on a projectile in the horizontal direction is Gravitational force.

A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.

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The efficiency of the motor is 68.75%

What is efficiency of an engine?

Engine efficiency is a measure of how effectively an engine can convert the energy from its fuel into useful work. It is typically expressed as a percentage of the total energy from the fuel that is converted into useful work output, such as torque or thrust. The higher the engine efficiency, the less fuel is required for a given amount of work output. Factors that can affect engine efficiency include engine type, engine size, fuel type, compression ratio, and spark timing. Increasing engine efficiency is important for reducing emissions and improving fuel economy. Technologies such as turbocharging, direct injection, and variable valve timing have been developed to help improve engine efficiency.

Energy provided to the train engine = 80000J

Output energy from the tain engine = 55000J

Efficiency of the motor = (Output power÷Input power )*100

  = (55000J /80000J)*100

= 68.75%

Therefore efficiency of the motor is 68.75%

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Answer:

I know only one type of light that is absorbed by genetic materail and that is UV light

Explanation:

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The letter that represents the various descriptions is as follows:

5.) Angle of incidence: B

6.) Object: D

7.) Plain mirror:A

8.) Reflection: E

9.) Angle of reflection: C

10.) Normal: F

The law of reflection in a plain mirror states that the angle of reflection is equal to the angle of incidence.

The diagram explains the law of reflection on a plain mirror because it shows the reflection of the object D as E after creating an angle of incidence B on the plane mirror surface A which is equal to the angle of reflection C.

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The contractor should order 213.7 m²  area of carpet from the French supplier.

First, we need to convert the area from square feet to square meters. Since 1 meter is equal to 3.281 feet, we can use the conversion factor:

1 m² = 10.764 ft² (since 1 m = 3.281 ft, then 1 m² = 1 m x 1 m = 3.281 ft x 3.281 ft = 10.764 ft²)

To convert 2300 ft² to m², we divide by the conversion factor:

2300 ft² ÷ 10.764 ft²/m² = 213.7 m² (rounded to one decimal place)

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Answer:

Here is something that may help you!!

Explanation:

I found it in a cite (not that I'm plagiarizing, or anything).

Answer:

ΔV = 0.816 L

Explanation:

The change in volume of the fluid upon heating is given by the following formula:

ΔV = βVΔT

where,

ΔV = Increase in Volume of Fluid = Volume of Overflow = ?

β = Coefficient of volumetric expansion of fluid = 600 x 10⁻⁶ °C⁻¹

ΔT = Change in Temperature = Final Temperature - Initial Temperature

ΔT = 95°C - 10°C = 85°C

Therefore,

ΔV = (600 x 10⁻⁶ °C⁻¹)(16 L)(85° C)

ΔV = 0.816 L

The velocity of the combined lump after the collision is 39.5 cm/s, which is the average velocity of the two lumps before the collision.

To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision, provided there are no external horizontal forces acting on the system.

The momentum of an object is equal to its mass multiplied by its velocity. Therefore, we can calculate the total momentum of the system before the collision as:

Total momentum before collision = (0.50 g) × (-20.0 cm/s) + (70.0 g) × 40.0 cm/s

= -10.0 g·cm/s + 2800.0 g·cm/s

= 2790.0 g·cm/s

Since the two lumps stick together after the collision, their masses combine to form a single lump. Let's call the velocity of the combined lump after the collision "v". We can then calculate the total momentum of the system after the collision as:

Total momentum after collision = (0.50 g + 70.0 g) × v

= 70.50 g × v

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate these two expressions and solve for "v":

Total momentum before collision = Total momentum after collision

2790.0 g·cm/s = 70.50 g × v

v = 2790.0 g·cm/s ÷ 70.50 g

v = 39.5 cm/s

This result can be explained by the fact that, in the absence of external horizontal forces, the momentum of the system is conserved, and the total mass of the system remains constant.

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Answer:

The answer to your problem is, C. \(1.0 * 10^{3}\)

Explanation:

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometres, and other units since it is a distance measurement.

The relationship between the wave's wavelength, frequency, and speed is given as

Formula ( That I use and you should use ) !

wavelength = speed of light / frequency

\(y = \frac{c}{v}\)

\(y = \frac{3*10^{3} }{3.0*10^{21} }\)

\(y = 1 * 10^{-13}\)

Thus the answer to your problem is, C. \(1.0 * 10^{3}\)

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