1. What properties of metals makes them useful
in these applications?
(a) Aluminum is used to make the outside surface
of some car doors.

(b) Thin gold wires are used to connect one part of
a computer chip to another.

(C) The bottoms of some frying pans are made of
copper
This is science

The aluminum hydroxide is dissolved, as well as any other acids or bases present that can affect the pH. Without this information, it is not possible to provide a specific pH value for the solution.

To determine the pH of a solution containing aluminum hydroxide (Al(OH)3), we need additional information. Aluminum hydroxide is a weak base, and its pH will depend on its dissociation in water.

First, we can calculate the number of moles of aluminum hydroxide using its molar mass. The molar mass of Al(OH)3 is 78 grams/mol (27 g/mol for aluminum and 3 × 17 g/mol for three hydroxide groups). Therefore, we have 78 g / 78 g/mol = 1 mol of Al(OH)3.

Since aluminum hydroxide is a weak base, it will undergo partial dissociation in water, releasing hydroxide ions (OH-) and aluminum ions (Al3+). The hydroxide ions will increase the pH of the solution.

However, to determine the pH accurately, we need to know the initial volume of water.

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1) 2F  is required  to liberate 1 mole of X.

2) The charge is + 2

3) The hydroxide of X is X(OH)2

We can see from the question that we are dealing with the kind of reaction that would occur in the electrochemical cell and we are going to deal with the problem as seen.

We know that the element is strontium. Thus we have to know that the ionic charge that the element X would carry is + 2 and that we would need 2F to remove the electron that is there as we have from the statements that are above.

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Answer:

1 Sodium, 1 Aluminum (1 Sulfur, 4 Oxygen)

Explanation:

hope that helps

Answer:

56.9 amu

Explanation:

Depending on the number of isotopes an element has, the Average atomic mass of isotopes of an element can be calculated using:

(atomic mass of isotope1 × decimal abundance of isotope1) + (atomic mass of isotope2 × decimal abundance of isotope2)

According to this question, two isotopes of element Z were given

- Isotope Z- 56 with atomic mass 56 is 70% abundance. This means that its decimal abundance is 0.70

- Isotope Z- 59 with atomic mass 59 is 30% abundance. This means that its decimal abundance is 0.30

Therefore, average atomic mass of element Z is:

= (56 × 0.70) + (59 × 0.30)

= (39.2) + (17.7)

= 56.9

The new temperature is 332.45 K (Kelvin) and 59.3°C (Celsius).To find the new temperature in Kelvin, we can use the formula:

T2 = T1 * (P2 / P1)

where T2 is the new temperature, T1 is the initial temperature, P2 is the new pressure, and P1 is the initial pressure.
Plugging in the given values, we have:
T2 = 59.3°C + 273.15 = 332.45 K (new temperature in Kelvin)
To convert the temperature back to Celsius, we subtract 273.15 from the new temperature in Kelvin:
T2 = 332.45 K - 273.15 = 59.3°C (new temperature in Celsius)
So, the new temperature is 332.45 K (Kelvin) and 59.3°C (Celsius).

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The given statement is False. The cumulative incidence of disease for the three-year period will not necessarily equal the prevalence of disease measured on the last day of the study period.

Cumulative incidence measures the number of new cases of a disease that occur within a specific time period in a population initially free of the disease.

On the other hand, prevalence measures the proportion of individuals in a population who have the disease at a particular point in time, regardless of when they developed it.

Prevalence is influenced by both the incidence and duration of the disease, while cumulative incidence only considers the occurrence of new cases. Therefore, the two measures can be different, and the statement is false.

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Answer:

5867ml is the answer to 5.867L to ml

Answer:

Explanation:She was wrong

Sue should prepare 0.750 L of solution.

To prepare a 2.50 M solution of potassium iodide using 75.0 g of the compound, Sue needs to first calculate the molar mass of KI, which is 166 g/mol. Then, she can use the formula M = n/V, where M is the molarity, n is the number of moles, and V is the volume in liters. By rearranging the formula, she can solve for V, which is V = n/M.

To find the number of moles, she can divide the mass by the molar mass: n = 75.0 g / 166 g/mol = 0.451 moles. Substituting these values, she gets V = 0.451 moles / 2.50 mol/L = 0.180 L. However, this is the volume needed for a 2.50 M solution.

To adjust the concentration to the desired value, she can use the formula M1V1 = M2V2, where M1 and V1 are the initial concentration and volume, and M2 and V2 are the final concentration and volume. Solving for V2, she gets V2 = M1V1 / M2 = 2.50 mol/L x 0.180 L / 0.750 mol/L = 0.600 L. Therefore, Sue should prepare 0.750 L of solution.

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When you add acid to a buffer, the reaction shifts towards the direction that consumes the added acid, typically resulting in an increase in the concentration of the conjugate base.

A buffer is a solution that resists changes in pH when an acid or base is added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer's ability to maintain a relatively constant pH relies on the equilibrium between the weak acid and its conjugate base.

When acid is added to a buffer, it increases the concentration of the hydrogen ions (H⁺) in the solution. According to Le Chatelier's principle, the system will shift to counteract the addition of the acid. In this case, the equilibrium will shift towards the side that consumes the excess H⁺ ions. Since the buffer contains a weak acid and its conjugate base, the reaction will shift towards the formation of more conjugate base, thereby reducing the concentration of H⁺ ions.

This shift helps maintain the buffer's pH by neutralizing the added acid. The exact direction and extent of the shift depend on the specific components and concentrations of the buffer system.

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Answer:

You can find in the given attachemnet

Explanation: The radius of an object is found from the center of the object to the perimeter. Radius can be any number, but it is the measurement from the center to the perimeter.

In any aqueous solution at 25°C, the ionic-product of water (Kw) is a constant value equal to 1.0 x 10⁻¹⁴ mol²/L².

Due to the auto-ionization or self-ionization of water, water molecules dissociate into hydronium ions (H₃O⁺) and hydroxide ions (OH⁻). At 25°C, the Kw is equal to 1.0 x 10⁻¹⁴ mol²/L².

This constant value of Kw plays a crucial role in understanding the acidity and basicity of aqueous solutions. It helps to establish the relationship between the concentrations of hydronium and hydroxide ions, as their product remains constant at a given temperature. The pH and pOH scales are derived from this relationship, providing a convenient method for measuring the acidity or basicity of a solution.

In summary, the ionic-product of water, Kw, remains constant at 1.0 x 10⁻¹⁴ mol²/L² for any aqueous solution at 25°C. This constant is a result of the auto-ionization of water and helps to understand the relationship between hydronium and hydroxide ions in the context of acidity and basicity.

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Answer:

C

Explanation:

Boyle's law states that "the volume of a given mass of gas is inversely proportional to its pressure at constant temperature."

Inverse proportionality means that as one quantity is increasing, the other quantity is decreasing and vice versa.

Hence, as the pressure was increased, the volume decreases accordingly in obedience to Boyle's law.

Answer:

What is TRUE about the missing volume is option C.

C. The volume will decrease due to inverse relationship of V & P

Explanation:

The given parameters of the gas are;

The initial pressure of the gas, P₁ = 2 atm

The initial volume of the gas, V₁ = 1.5 L

The final pressure of the gas, P₂ = 2 atm

Boyle's law states that, at constant temperature, the volume, 'V', of a given mass is inversely proportional to its pressure, 'P';

Mathematically, Boyle's law can be expressed as follows;

P ∝ 1/V

From which we have;

P·V = Constant

∴ P₁·V₁ = P₂·V₂

For the given gas, we get;

2 atm × 1.5 L = 6 atm × V₂

∴ V₂ = 2 atm × 1.5 L/(6 atm) = 0.5 L

Therefore, the volume decreases from 1.5 L to 0.5 L.

Answer:

wavelength, amplitude, frequency, time period, and velocity

Explanation:

There are five main characteristics of soundwaves, that being;

wavelength, amplitude, frequency, time period, and velocity

Answer:

A

Explanation:

1g=1000mg

1g= 1000 000 micro gram

1g= 1000 000 000 nm = 10^9

Answer: The correct answer is A. 1 x 10^9.

Answer:

god says dont use any assault language okay?

Explanation:

The percent abundance of post-1982 pennies in the sample is 60% as per the given data.

Data sampling is a statistical analysis technique that uses a representative subset of data points to identify patterns and trends in the larger data set under consideration.

To find the percent abundance of post-1982 pennies in the sample data, we need to determine the total number of pennies and the number of post-1982 pennies.

The total number of pennies is:

8 + 12 = 20

To find the number of post-1982 pennies, we need to know the total mass of the pennies. We can use the average mass of the pre-1982 and post-1982 pennies to estimate the number of post-1982 pennies.

The total mass of the pre-1982 pennies is:

8 x 3.1 g = 24.8 g

The total mass of the post-1982 pennies is:

12 x 2.5 g = 30 g

The total mass of all the pennies is:

24.8 g + 30 g = 54.8 g

We can estimate the number of post-1982 pennies by dividing the total mass of the post-1982 pennies by the average mass of a post-1982 penny:

30 g / 2.5 g = 12

So there are 12 post-1982 pennies in the sample.

To find the percent abundance of post-1982 pennies, we can use the following formula:

Percent abundance = (number of post-1982 pennies / total number of pennies) x 100%

Percent abundance = (12 / 20) x 100% = 60%

Therefore, the percent abundance of post-1982 pennies in the sample is 60%.

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Answer:yeee

Explanation:

bc

Answer:

1. The solute in this case is H₂SO₄, which stands for sulfuric acid.

2. The solvent is the substance in which the solute is dissolved. In this case, the solvent is not explicitly mentioned, but it is typically water (H₂O) for most aqueous solutions.

3.

Given:

Molarity (M) = 3.59 M

Volume (V) = 1.00 L

The formula to calculate the number of moles (n) of solute is:

n = M * V

Substituting the given values:

n = 3.59 mol/L * 1.00 L = 3.59 mol

To determine the mass of the solute in grams, we need to know the molar mass of H₂SO₄. The molar mass of sulfur (S) is approximately 32.07 g/mol, oxygen (O) is approximately 16.00 g/mol, and hydrogen (H) is approximately 1.01 g/mol.

The molar mass of H₂SO₄ is:

2(1.01 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 98.09 g/mol

Finally, we can calculate the mass of the solute:

mass = n * molar mass

mass = 3.59 mol * 98.09 g/mol ≈ 350.96 g

Therefore, approximately 350.96 grams of H₂SO₄ are needed to make a 1.00 L solution with a molarity of 3.59 M.

Answer:

Explanation:

D. Vaporization occurs with liquid particles gain energy and "fly away" into a gas.

Think of when you're boiling something on the stove.

Answer:

The mass of 42.3 moles of potassium sulfate is 7,371.1557 grams

Explanation:

Potassium sulfate K₂SO₄ which is also known as sulphate of potash is a water soluble common component of fertilizer

The molar mass of potassium sulfate, M = 174.259 g/mol

The given number of moles of potassium sulfate, n = 42.3 moles

The mass, 'm', of a given number of moles of potassium sulfate, 'n', is given as follows;

m = n × M

Therefore, we have;

The mass, 'm', of 42.3 moles of potassium sulfate is found by plugging in the values for 'M', and 'n', in the above equation as follows;

m = 42.3 moles × 174.259 g/mol = 7,371.1557 grams

The mass of 42.3 moles of potassium sulfate, m = 7,371.1557 grams.

Answer:

Power = Work done * time

P = (F * d) * t

P = (mg * d) * t

d = 1 step = 10 cm

30 steps = 300 cm

300 cm = 3m

P = (60*9.8 * 3) * 10

P = 17640 Watt

P = 1.764 Kilowatt

Ans: 60 watt

Explanation:

Solution

M=60kg, G=10

Distance=10*10/100

=1m

Time=10sec

Now,

W=M×G×H

=60×10×1

=600

P=w÷t

=600÷10

=60watt

Hence, the power of the man is 60watt

Answer:

Explanation:

The insects have been defined as the most successful arthropods. There are far more species in the class Insecta than in any other group of animals. The insects are the only invertebrates with wings.

The insects play a very important role in the web of the life in every environment. Their jobs include pollinating flowering plants, since it is the source of food for insectivorous animals and it assist in the decomposition of plants and animals.

The two different methods which help to identify the species of the insects from the eggs on human remains are by using a small paint brush dipped in water and the other way is by using the forceps.

The study of insects and their life cycle are found to be important for the forensic entomologist. This is because it could set a timeline on when the crime is happened. The life cycle of a blowfly starts as an egg and then goes to be maggots.

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Taking into account the reaction stoichiometry, a mass of 49.6 grams of NO can be formed from 4.96 moles of NO₂.

In first place, the balanced reaction is:

3 NO₂ + H₂O  → 2 HNO₃ + NO

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate:

The following rule of three can be applied: if by reaction stoichiometry 3 moles of NO₂ form 30 grams of NO, 4.96 moles of NO₂ form how much mass of NO?

mass of NO= (4.96 moles of NO₂× 30 grams of NO)÷3 moles of NO₂

mass of NO= 49.6 grams

Finally, 49.6 grams of NO can be formed.

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Answer:  0.050 moles of NaOH

Explanation:  The molar mass of NaOH is 40.0g/mole

2.0g/40.0g/mole  =  0.050 moles (2 sig fig)