17 POINTS!!! JUST DO A B C D PLS!!!! PLS DONT COMMENT IF YOU DONT KNOW IT ITS DUE BY TOMORROW AND I CANT KEEP WASTING POINTS PLS

Answer:

Explanation:

You can do this by doing dimensional analysis.

The first step is to change grams to mg

1000 mg = 1 gram

So the fraction will look like this

1.03 g * 1000 mg/ 1 gram = 1030 mg (the grams cancel out)

Now move onto the volume. The volume is actually 1 cm^3. This becomes 1 cm^3 / 1000 mm^3

So the answer becomes

1030 mg / cm^3 * ( 1 cm^3/1000 mm^3) The cm^3 cancel out

1030 mg / 1000 mm^3

1.030 mg/ mm^3

The process of cooling a food until the first ice crystals form is referred to as supercooling. Supercooling occurs when a substance is cooled below its freezing point without undergoing solidification.

This phenomenon is commonly observed in liquids that are pure and free from impurities. Supercooling allows the formation of ice crystals to be delayed until a nucleation site is present or an external disturbance occurs.

Supercooling refers to the state where a substance remains in a liquid phase below its freezing point. When a food is rapidly cooled, it can reach a temperature below the freezing point without solidifying. This occurs because the process of nucleation, which initiates the formation of ice crystals, is hindered. In the absence of nucleation sites or external disturbances, the food remains in a supercooled state.

However, as soon as a nucleation site is introduced or an external disturbance occurs, the supercooled food rapidly crystallizes and forms ice. This process is commonly observed when touching an already supercooled liquid, causing it to freeze instantly. Supercooling can be utilized in various applications, such as in the production of supercooled drinks or in cryopreservation techniques.

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Answer:

There are 1.253*10²⁴ particles in 2.080 moles

Explanation:

Avogadro's number is called the number of particles that make up a substance (usually atoms or molecules) that can be found in the amount of one mole. In other words, Avogadro's number is the number of molecules that one mole of any substance contains.  Its value is 6.023 * 10²³ particles per mole.

So, you can apply a rule of three as follows: if 1 mole has 6.023*10²³ particles, then 2.080 moles, how many particles does it have?

\(amount of particles=\frac{2.080 moles*6.023*10^{23}particles }{1 mole}\)

amount of particles= 1.253*10²⁴ particles

There are 1.253*10²⁴ particles in 2.080 moles

1.  the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.  the final concentration of KOH after adding 550 mL of water to 125 mL of 3.01 M KOH solution is approximately 0.557 M.

1.) If 125 mL of water is added to 45.3 mL of a 0.71 M NaOH solution, the resulting solution will be a diluted NaOH solution. The addition of water will increase the total volume while reducing the concentration of NaOH. To determine the final concentration of NaOH, we need to consider the conservation of moles.

First, let's calculate the moles of NaOH in the initial solution:

moles of NaOH = volume (in L) × concentration (in M)

moles of NaOH = 0.0453 L × 0.71 M = 0.0321433 moles

After adding 125 mL (0.125 L) of water, the total volume of the solution becomes 0.0453 L + 0.125 L = 0.1703 L.

To find the final concentration, we divide the moles of NaOH by the total volume:

final concentration of NaOH = moles of NaOH / total volume

final concentration of NaOH = 0.0321433 moles / 0.1703 L ≈ 0.189 M

Therefore, the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.) If 550 mL of water is added to 125 mL of a 3.01 M KOH solution, the resulting solution will also be a diluted solution. Again, we will apply the conservation of moles to determine the final concentration of KOH.

First, calculate the moles of KOH in the initial solution:

moles of KOH = volume (in L) × concentration (in M)

moles of KOH = 0.125 L × 3.01 M = 0.37625 moles

After adding 550 mL (0.55 L) of water, the total volume of the solution becomes 0.125 L + 0.55 L = 0.675 L.

To find the final concentration, divide the moles of KOH by the total volume:

final concentration of KOH = moles of KOH / total volume

final concentration of KOH = 0.37625 moles / 0.675 L ≈ 0.557 M

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Answer:

False.

Explanation:

Carbon = 12

Beryllium = 9

good luck, i hope this helps :)

The solution obtained from the salt of hydrogen peroxide and ammonia is slightly basic.

The salt obtained from the combination of the weak acid hydrogen peroxide (H2O2) and the weak base ammonia (NH3) is ammonium peroxide (NH4)2O2. To determine the acidity or basicity of the resulting solution, we need to consider the nature of the ions present in the salt.

Ammonium (NH4+) is a weak acid, as it can donate a proton (H+) in water. Peroxide (O2^2-) is a strong base, as it can accept a proton (H+) from water. When ammonium peroxide dissolves in water, it dissociates into ammonium ions (NH4+) and peroxide ions (O2^2-).

The ammonium ion (NH4+) can slightly acidify the solution by donating protons (H+) to water, resulting in the formation of hydronium ions (H3O+). On the other hand, the peroxide ion (O2^2-) can slightly increase the pH by accepting protons (H+) from water, leading to the formation of hydroxide ions (OH^-).

Overall, the presence of ammonium peroxide in water will make the solution slightly basic. However, the exact pH of the solution would depend on the concentrations of the salt and other factors like temperature.

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Answer:

i is the correct answer.

Explanation:

the RAM of aluminum is indeed 27. And since the RAM of substances are measured in terms of the C-12 isotope then R indeed explains why the RAM Al is 27.

The percentage dissociation is 0.97% and the hydrogen ion concentration is 1.93 x 10^-3 mol/dm^3.

we need to use the equation:

Ka = [H^+][A^-] / [HA]

where Ka is the equilibrium constant, [H^+] is the hydrogen ion concentration, [A^-] is the concentration of the dissociated form of the acid (acetate ion), and [HA] is the concentration of the undissociated form of the acid (ethanoic acid).

We know the concentration of ethanoic acid, [HA] = 0.2 mol/dm^3, and the value of the equilibrium constant, Ka = 1.85 x 10^-5 mol/dm^3.

Using the equation:

Ka = [H^+][A^-] / [HA]

1.85 x 10^-5 = [H^+][A^-] / 0.2

[H^+][A^-] = 1.85 x 10^-5 * 0.2

[H^+][A^-] = 3.7 x 10^-6 mol^2/dm^6

Since the concentration of the acetate ion is equal to the concentration of the hydrogen ion, [A^-] = [H^+].

So,

[H^+]^2 = 3.7 x 10^-6 mol^2/dm^6

[H^+] = sqrt(3.7 x 10^-6) = 1.93 x 10^-3 mol/dm^3

The hydrogen ion concentration is 1.93 x 10^-3 mol/dm^3.

To find the percentage dissociation, we divide the concentration of the acetate ion by the initial concentration of ethanoic acid and multiply by 100:

Percentage dissociation = ([A^-] / [HA]) * 100

Percentage dissociation = (1.93 x 10^-3 / 0.2) * 100 = 0.97%.

Therefore, The percentage dissociation is 0.97% and the hydrogen ion concentration is 1.93 x 10^-3 mol/dm^3.

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The value of the resistor R that will produce a force of 9.00×10⁻⁵ N between the two parallel wires separated by 5.0 mm and each having a length of 10 cm is approximately 1.8 Ω.

To calculate the value of the resistor R, we can use the formula for the magnetic force between two parallel wires:

\[ F = \frac{{\mu_0 \cdot I_1 \cdot I_2 \cdot \ell}}{{2 \pi \cdot d}} \]

where F is the force, μ₀ is the permeability of free space, I₁ and I₂ are the currents in the wires, ℓ is the length of the wires, and d is the separation between the wires.

In this case, the force F is given as 9.00×10⁻⁵ N, the length of each wire ℓ is 10 cm (or 0.10 m), and the separation between the wires d is 5.0 mm (or 0.005 m).

By rearranging the formula, we can solve for R:

\[ R = \frac{{2 \pi \cdot d \cdot F}}{{\mu_0 \cdot \ell}} \]

Substituting the given values into the equation, we get:

\[ R = \frac{{2 \cdot 3.1416 \cdot 0.005 \cdot 9.00×10⁻⁵}}{{4\pi × 10^{-7} \cdot 0.10}} \approx 1.8 \, \Omega \]

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Answer:

molecular recognition based on structural complementarity

Explanation:

Enzymes work on the basis of a lock and key model. The substrates on which enzymes act are specifically tailored to suit the shape of the enzyme.

As such, the enzyme just fits into the substrate in the same way as the right key fits into a lock.

Hence, molecular recognition based on structural complementarity is the basis for the specificity of enzyme activity.

The question is incomplete, the complete question is;

Which statement describes a difference between electromagnetic and mechanical waves?

A. Mechanical waves cannot be longitudinal, but electromagnetic waves can.

B. Electromagnetic waves cannot move particles, but mechanical waves can.

C. Electromagnetic waves do not require a medium, but mechanical waves do.

D. Mechanical waves do not transfer energy, but electromagnetic waves do.

Answer:

Electromagnetic waves do not require a medium, but mechanical waves do.

Explanation:

A wave is defined as a disturbance along a medium which transfers energy. Waves may be classified as mechanical waves or electromagnetic waves based on their medium of propagation.

A mechanical wave requires a material medium for propagation. An example of a mechanical wave is sound waves. Sound waves are propagated in air.

Electromagnetic waves do not require a material medium for propagation. They can travel through space. An example of electromagnetic waves is light waves.

The mass of ammonia that can be produced from the reaction of 74.2 g of N₂ and 14.0 moles of H₂ is 90.1 g.

The mole ratio of the reaction for the production of ammonia is obtained from the balanced equation of the reaction as follows:

Equation of the reaction: N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

The mole ratio of the reactants nitrogen and hydrogen is 1 : 3

Moles of nitrogen in 74.2 g of nitrogen = 74.2/28

Moles of nitrogen in 74.2 g of nitrogen = 2.65 moles

Moles of hydrogen present = 14.0 moles

The limiting reactant is nitrogen

Mole ratio of nitrogen to ammonia is 1 : 2

Mass of ammonia produced = 2.65 * 2 * 17 g

Mass of ammonia produced =  90.1 g

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Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question we have

\(density = \frac{37.5}{20} = \frac{15}{8} \\ = 1.875\)

We have the final answer as

Hope this helps you

Answer:

solvent

Explanation:

the solvent is usually a liquid substance

Answer:

The answer is p⁴.

Explanation:

You have to apply Indices Law :

\( {a}^{m} \times {a}^{n} ⇒ {a}^{m + n} \)

For this question :

\( {p}^{3} \times {p}^{1} \)

\( = {p}^{(3 + 1)} \)

\( = {p}^{4} \)

The mole ratio of the Al:Al₂O₃ is given from the question that we have as 3:1

A mole ratio is the ratio of the number of moles of one substance to the number of moles of another substance in a chemical reaction. It is often used to determine the stoichiometry of a reaction, which is the relationship between the relative amounts of reactants and products.

Mole ratios can be used to determine the amounts of reactants and products needed to achieve a specific reaction yield, or to calculate the expected yield of a reaction.

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For the reaction of aluminum metal and ammonium perchlorate, the mole ratio of Al to Al₂O₃ is 3 : 1 (3 is to 1).

Mole ratio requires a balanced equation, the coefficients of the elements and a division of the coefficients.

To find the mole ratio of Al to Al₂O₃, we need to look at the coefficients in the balanced equation.

The balanced equation is:

3Al + 3NH₄ClO₄ → Al₂O₃ + AlCl₃ + 3NO + 6H₂O

The coefficient of Al is 3 and the coefficient of Al₂O₃ is 1.

Therefore, the mole ratio of Al to Al2O3 is 3:1.

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The heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol. To calculate the heat of reaction (ΔH) for the given reaction:

CCl₄(g) + H₂O(g) -> CHCl₃(g) + HCl(g)

You would need the standard enthalpies of formation for each compound involved in the reaction. The standard enthalpy of formation (ΔHf) is the enthalpy change when one mole of a compound is formed from its elements in their standard states.

Here are the standard enthalpies of formation for the compounds involved:

ΔHf[CCl₄(g)] = -135.5 kJ/mol

ΔHf[H₂O(g)] = -241.8 kJ/mol

ΔHf[CHCl₃(g)] = -104.7 kJ/mol

ΔHf[HCl(g)] = -92.3 kJ/mol

To calculate ΔH for the reaction, you need to sum up the enthalpies of formation of the products and subtract the sum of the enthalpies of formation of the reactants:

ΔH = ΣΔHf(products) - ΣΔHf(reactants)

ΔH = [ΔHf[CHCl₃(g)] + ΔHf[HCl(g)]] - [ΔHf[CCl₄(g)] + ΔHf[H₂O(g)]]

ΔH = [(-104.7 kJ/mol) + (-92.3 kJ/mol)] - [(-135.5 kJ/mol) + (-241.8 kJ/mol)]

ΔH = -196.9 kJ/mol - (-377.3 kJ/mol)

ΔH = 180.4 kJ/mol

Therefore, the heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol.

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Answer:

The reason is carbon's ability to form stable bonds with many elements, including itself. 

Explanation:

This property allows carbon to form a huge variety of very large and complex molecules. In fact, there are nearly 10 million carbon-based compounds in living things!

Answer:

Explanation:

The reason is that carbon is able to form stable bonds with many elements, including itself, which allows carbon to form a huge variety of very large and complex molecules.

Answer: EXAMPLEEE

Explanation: Brookite

Mohs scale hardness 51⁄2 to 6

Luster Submetallic

Streak White, greyish or yellowish

Diaphaneity Opaque to translucent

Density is referred to as a characteristic property of matter because Option A. the density of a substance is the same regardless of the mass and the volume of the substance at a given temperature.

Density is the substance's mass consistent with the unit of quantity. The symbol most customarily used for density is ρ, despite the fact that the Latin letter D can also be used. Density is the size of ways tightly a cloth is packed together. it's far defined as the mass consistent with unit quantity.

ρ = m/V, wherein ρ is the density, m is the mass of the item and V is the quantity of the object.

The density of a liquid is a measure of how heavy it is for the quantity measured. in case you weigh the same amounts or volumes of two one-of-a-kind beverages, the liquid that weighs extra is greater dense.

The density is of two types, one is absolute density, and the alternative is relative density. Relative density is also called unique gravity, which is the ratio of the density of a material to the density of a reference material. typically, the reference fabric is water.

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The difference in degrees Fahrenheit between the maximum expected temperatures by the end of the century between the lower and higher emissions scenarios can vary depending on various factors and assumptions.

However, in general, the lower emissions scenario is expected to result in a lower increase in global temperatures compared to the higher emissions scenario.

This means that the maximum expected temperature rise by the end of the century under the lower emissions scenario would be lower than that of the higher emissions scenario.

The specific temperature difference would depend on the specific projections and models used, but it highlights the significant impact that emissions reductions can have on mitigating future temperature increases.

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Answer:

C: water crops often to wet soil.

Explanation:

Working in the plan industry, it becomes obvious that when watering the plants often, it will pack down the topsoil into the plant. Topsoil is lose at first as stated above, but when enough water gets on it, it becomes almost like mud. This is the kind of topsoil you want. No wind or water will mess it up because it already it watered! It will also help the grow. In addition, plowing is not correct because you only need to plow twice in the plant process. Before you plant the seeds, and to harvest the crops. If you plow to soon and often, you won’t have any plants.

The answer is (e) 70 milliliters.

Let's assume that x milliliters of the 35% saline solution were used.

The total amount of saline in the solution can be calculated as follows:

Saline in 35% solution = 0.35 * x

Saline in 75% solution = 0.75 * 10 (since 10 milliliters of the 75% solution were used)

The total amount of saline in the resulting 40% solution can be calculated as:

Saline in 40% solution = 0.40 * (x + 10)

Since the saline is being mixed, the total saline in the resulting solution is equal to the sum of the saline in the individual solutions:

0.35 * x + 0.75 * 10 = 0.40 * (x + 10)

Simplifying the equation:

0.35x + 7.5 = 0.40x + 4

Subtracting 0.35x and 4 from both sides:

7.5 - 4 = 0.40x - 0.35x

3.5 = 0.05x

Dividing both sides by 0.05:

x = 3.5 / 0.05

x = 70

Therefore, 70 milliliters of the 35% saline solution were used. The answer is (e) 70 milliliters.

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Answer:

D. Half-life

Explanation:

Half‐life is the amount of time it takes for approximately half of the radioactive atoms in a sample to decay into a more stable form. Every radioactive element has a different half‐ life.

a. There are 0.0232 mol AsH₃ occupy 0.527 L at STP mol AsH

b. The density of gaseous arsine is 3.43 g/L

c. The mass(in g) of the sample is 2.72 g.

d. There are 1.09 grams of potassium chlorate decompose to potassium chloride

e. The pressure is 9.26 atm

1. Using the ideal gas law, we can solve for the number of moles of AsH3:

PV = nRT

where P = 1 atm (at STP), V = 0.527 L, n = ?, R = 0.08206 L·atm/(mol·K), and T = 273 K

n = (PV)/(RT) = (1 atm)(0.527 L)/(0.08206 L·atm/(mol·K) × 273 K) ≈ 0.0232 mol AsH₃

2. To calculate the density of gaseous AsH₃, we can use the equation:

density = (mass of gas)/(volume of gas)

The molar mass of AsH₃s 77.94 g/mol, so the mass of 0.0232 mol of AsH₃ is:

mass = 0.0232 mol × 77.94 g/mol ≈ 1.81 g

Plugging this value and the given volume into the equation above, we get:

density = 1.81 g / 0.527 L ≈ 3.43 g/L

3. To solve for the mass of chlorine trifluoride gas, we can use the ideal gas law again:

PV = nRT

where P = 767 mmHg (convert to atm by dividing by 760 mmHg/atm), V = 626 mL (convert to L by dividing by 1000 mL/L), n = ?, R = 0.08206 L·atm/(mol·K), and T = 28 + 273 = 301 K

n = (PV)/(RT) = (767/760 atm)(626/1000 L)/(0.08206 L·atm/(mol·K) × 301 K) ≈ 0.0295 mol ClF₃

The molar mass of ClF₃ is 92.45 g/mol, so the mass of 0.0295 mol of ClF₃ is:

mass = 0.0295 mol × 92.45 g/mol ≈ 2.72 g

Therefore, the mass of the sample is approximately 2.72 g.

4. To solve for the mass of KClO3 that decomposes, we need to first calculate the number of moles of O2 produced, using the ideal gas law again:

PV = nRT

where P = 725 torr (convert to atm by dividing by 760 torr/atm), V = 0.344 L, n = ?, R = 0.08206 L·atm/(mol·K), and T = 128 + 273 = 401 K

n = (PV)/(RT) = (725/760 atm)(0.344 L)/(0.08206 L·atm/(mol·K) × 401 K) ≈ 0.0134 mol O2

Since the balanced equation shows that the ratio of KClO₃ to O₂ produced is 2:3, we can say that the number of moles of KClO₃ is:

n(KClO₃) = (2/3) × n(O₂) = (2/3) × 0.0134 mol ≈ 0.00893 mol KClO₃

The molar mass of KClO₃ is 122.55 g/mol, so the mass of 0.00893 mol of KClO₃ is:

mass = 0.00893 mol × 122.55 g/mol ≈ 1.09 g

Therefore, 1.09 g of KClO₃ decompossed

5. Using the ideal gas law:

n = m/M = 60.8 g / 44.02 g/mol = 1.38 mol

P = nRT/V = (1.38 mol) x (0.08206 L·atm/(mol·K) x 387K /  4.73 L

P = 9.26 atm

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After 466 years, the remaining radium left is 81.71 percent.

To determine the percent of radium is left after 466 years, we need to use the formula for exponential decay:

A = A0(1/2)^(t/T), where A0 is the initial amount, A is the amount after time t, T is the half-life, and the exponent is the number of half-lives that have passed.

Since we know the half-life of radium is 1599 years, we can calculate the number of half-lives that have passed in 466 years:

t/T = 466/1599 = 0.29143 (rounded to 5 decimal places).

Substituting this value into the formula, we get:

A = A0(1/2)^0.29143

A/A0 = 0.81709

Multiplying by 100, we get the percentage of radium left after 466 years as: 81.71% (rounded to 2 decimal places). Therefore, the answer is: 81.71%.

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So,

There's an equation that we could use in order to find frequency, and it is the next one:

This equation tells us that the energy of the photon is equal to the product of the Plank constant (h), which is 6.626*10^-34 J.s, and the frequency.

In this problem, we know the value of E and the value of h, so we need to solve for v:

Therefore, the correct answer option is A.