(2 X + 5) and (4 X - 3)​

Answer:

Step-by-step explanation:

This number line says that  we can take all values of x that are less than or equal to 2. That is, the solution is

                                  \(x\leq 2\)

NOTE: if the circle at 2 were not filled in then that would mean x<2 (2 would not be an accepted value of x)

Answer:

We can use the formula for compound interest:

A = P(1 + r/n)^(nt)

where A is the ending amount, P is the principal (starting amount), r is the interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the time in years.

We know P = $5700, A = $6100, n = 1 (since the interest is compounded annually), and t = 12. We can solve for r:

$6100 = $5700(1 + r/1)^(1*12)

$6100/$5700 = (1 + r)^12

1.0702 = (1 + r)^12

log(1.0702) = log[(1 + r)^12]

0.0291 = 12log(1 + r)

0.00243 = log(1 + r)

10^(0.00243) = 1 + r

r = 0.0059 or 0.59%

Therefore, the interest rate of the savings account is 0.59%.

Answer:

Step-by-step explanation:

a) The formula for the regression function is:

Maintenance Cost = 54.7757 + 120.689 x Age of Car

b) The slope of the regression equation is 120.689. This means that on average, for every one year increase in the age of a car, the maintenance cost is expected to increase by $120.689.

c) To construct a 95% interval to predict the maintenance cost for a car that is 7 years old, we can use the formula:

Y = a + bX ± tα/2 * SE

where Y is the predicted maintenance cost, a is the intercept, b is the slope, X is the age of the car, tα/2 is the t-value for the 95% confidence level with n-2 degrees of freedom (11 in this case), and SE is the standard error of the estimate.

Plugging in the values, we get:

Y = 54.7757 + 120.689 * 7 ± 2.201 * 11.8442

Y = 923.167 ± 26.010

Therefore, we can be 95% confident that the maintenance cost for a car that is 7 years old will be between $897.16 and $949.17.

d) The null hypothesis is that there is no significant linear relationship between the average maintenance cost and the age of a car in years. The alternative hypothesis is that there is a significant linear relationship between the average maintenance cost and the age of a car in years.

To test the hypothesis, we can perform a t-test on the slope coefficient using the t-statistic and the p-value provided in the output. The t-statistic is 10.1898, which is much greater than the critical t-value at the 0.05 level of significance for a two-tailed test with 11 degrees of freedom (2.201). The p-value is 0.0000, which is less than the significance level of 0.05. Therefore, we can reject the null hypothesis and conclude that there is a significant linear relationship between the maintenance cost and the age of the car in years.

The average ticket cost for each concert is given as follows:

The ticket costs are obtained by a system of equations, for which the variables are given as follows:

It cost a total of $1707 to purchase six tickets for concert A and six tickets for concert B, hence:

6a + 6b = 1707

a + b = 284.5.

Three tickets for concert B cost a total of $687, hence the cost for concert B is of:

3b = 687

b = 287/3

b = $95.67.

Replacing into the first equation, the cost for concert A is given as follows;

a = 284.5 - 95.67

a = $188.83.

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We can be 99% confident that the true mean healing rate of newts falls within the interval of 22.919 to 30.415 micrometers per hour.

Sample Mean: = (29 + 27 + 34 + 40 + 22 + 28 + 14 + 35 + 26 + 35 + 12 + 30 + 23 + 18 + 11 + 22 + 23 + 33) / 18

= 480 / 18

≈ 26.667

Sample Standard Deviation (s):

= ✓((Σ(29 - 26.667)² + (27 - 26.667)² + ... + (33 - 26.667)²) / (18 - 1))

≈ ✓(319.778 / 17)

≈ ✓(18.81)

≈ 4.336

Confidence level = 99%

Sample Size (n) = 18

Sample Mean = 26.667

Sample Standard Deviation (s) = 4.336

Degrees of Freedom (df) = n - 1 = 18 - 1 = 17

Using a t-table or statistical software, we find that the critical value for a 99% confidence level with 17 degrees of freedom is approximately 2.898.

Margin of Error (E) = 2.898 * (4.336 / ✓18))

≈ 3.748

Confidence Interval = (26.667 - 3.748, 26.667 + 3.748)

= (22.919, 30.415)

We can be 99% confident that the true mean healing rate of newts falls within the interval of 22.919 to 30.415 micrometers per hour. This means that if we were to repeat the study multiple times and construct confidence intervals, approximately 99% of those intervals would contain the true mean healing rate of the population.

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a) The equation for Bueller's height above the ground as a function of time is: h(t) = 9 cos(πt/8) + 1.5

b) When Bueller has been on the ride for 1 minute and 30 seconds, his height above the ground is approximately 10.5 m.

In mathematics, a function is a rule that assigns a unique output value to each input value in a specified set. More precisely, a function is a set of ordered pairs (x, y) where each x-value (the input) corresponds to exactly one y-value (the output).

In mathematics, an equation is a statement that asserts the equality of two expressions, typically containing one or more variables. An equation consists of two sides, the left-hand side, and the right-hand side, separated by an equal sign (=).

According to the given information,

a) To determine an equation for Bueller's height above the ground as a function of time, we can use the equation for the height of a point on a Ferris wheel:

h(t) = r cos(ωt) + h0

where:

1) h(t) is the height of the point above the ground at time t

2) r is the radius of the Ferris wheel

3) ω is the angular velocity of the Ferris wheel (in radians per second)

4) t is the time elapsed since the point was at its lowest position

5) h0 is the initial height of the point above the ground

In this case, we know that Bueller boards the Ferris wheel at a height of 1.5 m off the ground, so h0 = 1.5 m. The radius of the Ferris wheel is 9 m, and it rotates once every 16 seconds, so the angular velocity is:

ω = 2π / T = 2π / 16 = π / 8 radians per second

Therefore, the equation for Bueller's height above the ground as a function of time is:

h(t) = 9 cos(πt/8) + 1.5

b) To find Bueller's height off the ground when he has been on the ride for 1 minute and 30 seconds (or 90 seconds), we can substitute t = 90 into the equation for h(t):

h(90) = 9 cos(π(90)/8) + 1.5

h(90) = 9 cos(11.25π) + 1.5

Using a calculator, we get:

h(90) ≈ -6.3 m

Note that the negative sign means that Bueller is below ground level, which is not physically possible. This occurs because we started counting time from the bottom of the wheel, so 90 seconds corresponds to the bottom position plus 5 and a half rotations. To fix this, we can add a multiple of the period T = 16 seconds to t to bring it back to the correct range:

h(t) = 9 cos(πt/8) + 1.5

h(90 + 5T/2) = 9 cos(π(90 + 5T/2)/8) + 1.5

h(90 + 5T/2) = 9 cos(π(2 + 5/16)) + 1.5

h(90 + 5T/2) ≈ 10.5 m

Therefore, when Bueller has been on the ride for 1 minute and 30 seconds, his height above the ground is approximately 10.5 m.

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Answer:

3 yards

Step-by-step explanation:

8 1/2 - 2 1/2 = 6

6 - 3 = 3

Your answer is 3.

Please mark as brainliest.

Answer:

Step-by-step explanation:

\(15x -20=10x-5\)

Subtract 10x from both sides of the equation

That's

\(15x - 10x - 20 = 10x - 10x - 5 \\ 5x - 20 = - 5\)

Move - 20 to the other side of the equation

\(5x = 20 - 5 \\ 5 x = 15\)

Divide both sides by 5

\( \frac{5x}{5} = \frac{15}{5} \\ \)

We have the final answer as

Hope this helps you

Answer:

\(15x -20=10x-5\)

\(15x-20+20=10x-5+20\)

\(15x=10x+15\)

\(15x-10x=10x+15-10x\)

\(5x=15\)

\(\frac{5x}{5}=\frac{15}{5}\)

\(x=3\)

Answer:

C. Yes, because the ratios are equivalent between each pair of values.

Step-by-step explanation:

A relationship between two quantities is proportional if the ratio of the two quantities are the same for all the given possible pairs of values.

In the table given, the ratio of block to mins in the first given pair of values is 3/6 = 3/6 = ½.

In the second given pair, it is 7 to 14 = 7/14 = ½. The same ratio is gotten for the others as well.

Therefore, the table represents a proportional relationship.

The answer is: "C. Yes, because the ratios are equivalent between each pair of values."

Answer:

c

Step-by-step explanation:

Step-by-step explanation:

Since we have three sides and trying to find an angle, use Law of Cosines

\(c = \sqrt{ {a}^{2} + {b}^{2} - 2ab \times \cos(d) } \)

where c is

Solving for the angle d.

\( \cos {}^{ -1 } (( \frac{ {c}^{2} - {b}^{2} - {a}^{2} }{ - 2ab} ) = d\)

where d is in degrees

The angle d is the opposite of the side c.

It does not matter what a and b is(they can be either 4 or 5)

let

c=7

a=4

b=5

\( \cos {}^{ - 1} ( \frac{ - 1}{5} ) = d\)

This angle must be within 0 and 180

We get

\(d = 101.54\)

Answer:

I answered your duplicate question. Make sure to check out the answer, and I hope it helps!

Answer:

5/6 ÷ 3/4 = 20/18 as simplified as 10/9 in fraction form. 5/6 ÷ 3/4 = 1.1111 in decimal form.

Step-by-step explanation:

The value of 5/6 divided by 3/4 is 10/9.

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

5/6 divided by 3/4

as, fraction does not perform proper division

So,  5/6 ÷ 3/4

= 5/6 x 4/3

= 20 / 18

= 10 / 9

Hence, the resultant value is 10/9

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Answer:

$5990

Step-by-step explanation:

after saving up for 18 months she would have 12000 (10,200+1,800)

Answer:

x = 4, -2

Step-by-step explanation:

x^2-2x=8

Move the constant term to the right side of the equation.

x^2 - 2x = 8

Take half of the coefficient of x and square it.

(-2/2)^2 = 1

Add the square to both sides of the equation.

x^2 - 2x + 1 = 8 + 1

Factor the perfect square trinomial.

(x - 1)^2 = 9

Take the square root of both sides of the equation.

x-1=\(\sqrt{9}\)
x-1=±3

Isolate x to find the solutions.

Taking positive

x=3+1=4

x=4

Taking negative

x=-3+1

x=-2

The solutions are:

x = 4, -2

Answer:

\(x = -2,\;\;x=4\)

Step-by-step explanation:

To solve the quadratic equation x² - 2x = 8 by factoring, subtract 8 from both sides of the equation so that it is in the form ax² + bx + c = 0:

\(x^2-2x-8=8-8\)

\(x^2-2x-8=0\)

Find two numbers whose product is equal to the product of the coefficient of the x²-term and the constant term, and whose sum is equal to the coefficient of the x-term.

The two numbers whose product is -8 and sum is -2 are -4 and 2.

Rewrite the coefficient of the middle term as the sum of these two numbers:

\(x^2-4x+2x-8=0\)

Factor the first two terms and the last two terms separately:

\(x(x-4)+2(x-4)=0\)

Factor out the common term (x - 4):

\((x+2)(x-4)=0\)

Apply the zero-product property:

\(x+2=0 \implies x=-2\)

\(x-4=0 \implies x=4\)

Therefore, the solutions to the given quadratic equation are:

\(\boxed{x = -2,\;\;x=4}\)

Answer:

\(\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\)

\(\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0 \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $ \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ & 1 & $ \dfrac{1}{ \sqrt{3} } $ &0 \\ \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\ \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1 \\ \cline{1 - 6}\end{tabular}}\)

The value of the square root of 7 is,

⇒ √7 = 2.645

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

WE have to given that;

To find the value of the square root of 7 .

Since, the square root of 7 is,

⇒ √ 7

⇒ 2.645

Thus, The value of the square root of 7 is,

⇒ √7 = 2.645

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Step-by-step explanation:

5+4×(8-6)²

USING BODMAS

5 + 4 ( 2)²

5 + 4 (4)

= 5 +16

=21

Answer:

+1

Step-by-step explanation:

Well (+) and (-) is equals basically to (-) when add ing them or multiplying them... so the difference is +1

The selling price of the item at 10% marlkup is $55

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

Selling price = Cost To Store * (1 + Markup)

substitute the known values in the above equation, so, we have the following representation

Selling price = 50 * (1 + 10%)

Evaluate

Selling price = 55

Hence the selling price of the item is $55

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Answer:

286 i think

Step-by-step explanation:

hope this helps

PRICES COUNTS COSTS

8 e 8e

10 420-e-t 10(420-e-t)

12 t 12t

420 3920

system%28e%2B420-e-t=5t%2C8e%2B10%28420-e-t%29%2B12t=3920%29

First equation gives highlight%28t=70%29.

Second equation simplifies to e-t=140.

Substitution gives highlight%28e=210%29.

Quantity of $10 tickets by difference, highlight%28140%29

\(p(t)=1650e^{0.11t}\implies \stackrel{p(t)}{2479}=1650e^{0.11t}\implies \cfrac{2479}{1650}=e^{0.11t} \\\\\\ \log_e\left( \cfrac{2479}{1650} \right)=\log_e\left( e^{0.11t} \right)\implies \log_e\left( \cfrac{2479}{1650} \right)=0.11t \\\\\\ \ln\left( \cfrac{2479}{1650} \right)=0.11t\implies \cfrac{ ~~ \ln\left( \frac{2479}{1650} \right) ~~ }{0.11}=t\implies 3.7\approx t\)

at that moment, the population will reach 2479, and right after that, it'll exceed it.

Answer:

Step-by-step explanation:

Q.1.

\(ln\left(4\right)+\:ln\left(x\right)=ln\left(24\right)\)

apply ln rules:

\(ln( 4 * x) = ln (24)\)

cancel ln from both sides:

\(4x = 24\)

divide both sides by 4:

\(x = 6\)

Q.2.

\(2ln\left(x\right)=ln\left(4\right)+ln\left(9\right)\)

apply ln rules:

\(ln\left(x^2\right)=ln\left(4*9\right)\)

cancel ln from both sides:

\(x^2 = 36\)

\(x = \pm6\)

as ln cannot be negative:

\(x = 6\)

The statements that are true for a translation are:
The distances between points on the polygon are preserved by the transformation.
The distance between corresponding points in the image and pre-image is constant.
These statements are true for a translation because when an object is translated, it is shifted a certain distance in a certain direction. This means that the distances between points on the polygon remain the same and the distance between the corresponding points in the image and pre-image is constant.

Translation is the process of converting written, spoken, or visual information from one language into another. It is a complex process involving both linguistic knowledge and cultural understanding. Professional translators use a range of techniques to accurately convey the meaning of a text, including knowledge of grammar, syntax, and idiomatic expressions. Translators also take into account the cultural context of the text, ensuring that the translation reflects the same cultural references and nuances as the original. Translation can also refer to the conversion of DNA sequences from one form to another, such as from RNA to protein.

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Mathematical induction, .∴ Pn+1 follows if Pn is true. For all positive integers of n, Pn holds true because P1 is true.

Assume that Pn is 4 + 9 + 14 +... + (n/2)(5n + 3)=(5n -1).

First, establish that P1 is accurate when n equals 1.

LHS= 4

RHS

= 1/2(5 + 3)

= 1/2(8)

= 4

= LHS

Is P1 true.

2) Assume Pn to be accurate, i.e., 4 + 9 + 14 +... + ( 5n -1)= (n/2)(5n +3)

3) Establish Pn+1 as true in the induction stage.

Replace (n+1) on both sides of n to obtain Pn+1.

Pₙ₊₁: 4 +9 +14 +...+(5n -1)+ [5(n+1) -1]=

Establish the RHS and LHS's parity.

LHS = 4 +9 +14 +...+(5n -1)+ [5n +5-1]

Bold expression in (2) should be replaced with the value of Pn:

.∴ Pn+1 follows if Pn is true. For all positive integers of n, Pn holds true because P1 is true.

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Answer:

you can just substitute x as 0,1,2,3,4.....till 10 and you can express in graph .e.g like

x = 0

f(0) = 0.2728(0)³- 2.612(0)²+ 7.02(0)+89.18

= 89.18

so you can countinous do like that till 10 as it mention in question

You need to multiply by 5 instead of 6 because each pair of opposite faces on a cuboid has the same area, so by considering one face from each pair, you ensure that you don't count any face twice.

When calculating the total surface area of a cuboid, you need to understand the concept of face pairs.

A cuboid has six faces, but each face has a pair that is identical in size and shape.

Let's break down the reasoning behind multiplying by 5 instead of 6 in the given scenario.

To find the surface area of a cuboid, you can add up the areas of all its faces.

However, each pair of opposite faces has the same area, so you avoid double-counting by only considering one face from each pair. In this case, you have five pairs of faces:

(1) top and bottom, (2) front and back, (3) left and right, (4) left and back, and (5) right and front.

By multiplying the average area of a pair of faces by 5, you account for all the distinct face pairs.

Essentially, you are considering one face from each pair and then summing their areas.

Since all the pairs have the same area, multiplying the average area by 5 gives you the total surface area.

When dividing 150 by 4 (to find the average area of a pair of faces), you are essentially finding the area of a single face.

Then, by multiplying this average area by 5, you ensure that you account for all five pairs of faces, providing the total surface area of the cuboid.

Thus, multiplying by 5 is necessary to correctly calculate the total surface area of the cuboid by accounting for the face pairs while avoiding double-counting.

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The value of y in simplest form for the point P = (1/2, y) lying on the unit circle is y = ± √(3)/2.

To find the value of y in simplest form for the point P = (1/2, y) lying on the unit circle, we can use the equation of the unit circle, which states that for any point (x, y) on the unit circle, the following equation holds: x^2 + y^2 = 1.

Plugging in the coordinates of the point P = (1/2, y), we get:

(1/2)^2 + y^2 = 1

1/4 + y^2 = 1

y^2 = 1 - 1/4

y^2 = 3/4.

To simplify y^2 = 3/4, we take the square root of both sides:y = ± √(3/4).

Now, we need to simplify √(3/4). Since 3 and 4 share a common factor of 1, we can simplify further: y = ± √(3/4) = ± √(3)/√(4) = ± √(3)/2.

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