The cost to rent a moving yan for a day is an initial cost of $29 plus $0.35 per mile driven, Find a function to model the cast of the moving van rental
based on the initial cost and miles driven
Hello!
miles driven = x
the initial cost = 29
f(x) = 29 + 0.35x
Solve. You must factor first.
8n^2 29n + 15 = 0
Please show work
Answer: Multiply n299 by n by adding the exponents
Step-by-step explanation:
8n230+15=0
Find equation of the line shown
The equation of the line is y = x + 6
How to detemrine the equatiin of the lineFrom the question, we have the following parameters that can be used in our computation:
The graph
On the graph, we have the following highlights
The graph intersect the y-axis at y = 6
This means that the intercept c is 6
Also, as x changes by 1, the y values changes by 1
This mean sthat the slope is 1
So, we have
y = mx + c
This gives
y = x + 6
Hence, the equation is y = x + 6
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The linear equation on the graph can be written as:
y = (3/2)*x + 6
How to find the equation in the graph?A general linear equation can be written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
If the line passes through two points (x₁, y₁), then the slope will be:
a = (y₂ - y₁)/(x₂ - x₁)
In this case we can see the points (0, 6) (so the y-intercept is b = 6) and (4, 10)
Then the slope will be:
a = (10 - 6)/(4 - 0) = 6/4 = 3/2
Then the linaer equation is:
y = (3/2)*x + 6
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A tube-feeding formula is administered to a patient via Gastrostomy at 75
ml/hr. The formula contains 6.5% protein. How much protein will the patient
receive in the entire day, if the feeding must be held (stopped) for 2 hours
before and 2 hours after the administration of Dilantin twice a day?
39
Answer:
97.5ml protein
Step-by-step explanation:
20hr * 75ml/hr = 1500ml
1500ml * .065 = 97.5ml protein
The patient will receive 78 ml protein in the entire day.
What is an expression?An expression is a number, or a variable, or a combination of numbers and variables and operation symbols.
Now it is given that,
Tube feeding formula = 75 ml/hr
Protein content = 6.5% of 75 ml/hr = 0.065*75 ml/hr
⇒ Protein content = 4.875 ml/hr
Now since, the feeding must be held (stopped) for 2 hours before and 2 hours after the administration of Dilantin twice a day
So, Stoppage total hours = 2(2 + 2) = 2*4
⇒ Stoppage total hours = 8
Thus, total hours in a day when formula is feed = 24 - 8 = 16 hours
Thus Protein received by patient = 16hr * 4.875 ml/hr
⇒ Protein received by patient = 78 ml
Thus, the patient will receive 78 ml protein in the entire day.
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Pls help
I need help asap
Michelle had 7 paperback books and 4 hardcover books on the shelf by her bed. Write a ratio to represent the ratio of paperback books to hardcover books
Answer:
7:4 that would be the ratio
An odometer show that a car has traveled 40,000 miles by January 1, 2020. The car travels 16,000 miles each year. Write an equation that represents the number y of miles on the car’s odometer x years after 2020.
y = __
The equation will be \(y=40000+16000*x\)
How do you resolve a two-variable equation?Solve one of the equations for a particular variable. After that, insert that into the other equation and find the variable there. To find the value for the other variable, enter that value into either equation.
Two variables are used in what kind of equation?Equations come in two varieties: identities and conditional equations. All possible values of the variables result in an identity. Only certain combinations of the variables' values make a conditional equation true. Two expressions joined by the equals symbol ("=") form an equation.
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Find the degree of the monomial. -3q4rs6
Therefore, the degree of the given monomial is 11.
What is monomial?In algebra, a monomial is an expression consisting of a single term. A term can be a constant, a variable, or the product of a constant and one or more variables. In other words, a monomial is a polynomial with only one term. The degree of a monomial is the sum of the exponents of its variables.
Here,
The degree of a monomial is the sum of the exponents of its variables.
For the monomial -3q⁴rs⁶, the degree would be:
4 + 1 + 6 = 11
Therefore, the degree of the monomial -3q⁴rs⁶ is 11.
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12. After 2 hours, Morgan had earned $12.75 at her lemonade stand. After 5
hours, she had earned $44.25. Assuming a linear function, write an
equation in the form y=mx+b that shows the profit earned from selling
lemonade for x hours.
Answer:
y = 10.5x - 8.25
Step-by-step explanation:
m = (44.25 - 12.75)/(5 - 2) = 10.5
y = mx + b
y = 10.5x + b
12.75 = 10.5 × 2 + b
b = -8.25
y = 10.5x - 8.25
help please and thank you
Answer:
1) 9x
2) 3b
3) 3m
4) 5a
5) 7x
6) 3a + 5b
7) 9x - 4
8) 2b + m
9) 13a + b + 6c
10) 9b + 1
11) 7p
12) 2a + b -10
Step-by-step explanation:
solve the equation for x state any restrictions on the variables that may exist
bx + c = dx -e
e + c = dx - bx
e + c = x(d - b)
(e + c)/(d - b) = x where d ≠ b
help me asap!!!!!!!!?!??
Answer:
9.225 x 10^18 is what it is in standard form
Step-by-step explanation:
Answer:
ummm, it should be 9,225,000,000,000,000,000. =D
Step-by-step explanation:
move the decimal at the end of my answer, over to the left 18 spaces, and it should end up back at 9.225!
If ABCD is a parallelogram and angle A is 120 degrees, what is the measure of angle D?
Answer:
given angle A =120degree
angle D =60 degree
because angle A+angle B=180 degree
hope it is right answer for it!!
In a class of tenth graders, no student participated in more then 1 of the following extracurricular activities: 2/3 the class played in the band; 1/6 sang in the chorus; 1/10 played football and 1/60 played basketball. What is the fraction of the class did not participate in any of 1 of these 4 activities?
the fraction of the class that did not participate in any of these activities is 1 - n * (151/60).
What is the fraction?
A fraction represents a part of a number or any number of equal parts. There is a fraction, containing a numerator(upper value) and denominator(lower value).
Let's call the number of students in the class "n".
2/3 of the class played in the band, so:
n * 2/3 participated in the band
1/6 of the class sang in the chorus, so:
n * 1/6 participated in the chorus
1/10 of the class played football, so:
n * 1/10 played football
1/60 of the class played basketball, so:
n * 1/60 played basketball
The fraction of the class that participated in one of these activities is the sum of these fractions:
n * (2/3 + 1/6 + 1/10 + 1/60) = n * (7/6 + 1/10 + 1/60)
So, the fraction of the class that did not participate in any of these activities is:
1 - n * (7/6 + 1/10 + 1/60) = 1 - (7/6 + 1/10 + 1/60) * n = 1 - n * (151/60)
Therefore, the fraction of the class that did not participate in any of these activities is 1 - n * (151/60).
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The boat rental company gave a rowing team a discount of $10 off for every
4 days of rental. The team rented a boat for 12 days. Their coach paid 35%
of the total discounted rental cost. The remaining rental cost was divided
equally among the 16 team members.
Determine the total cost for the team to rent a boat,
Determine the cost per team member
Part a: total discounted rental cost for the boat = $690.
Part b: cost per team member = $32.34
Explain about the linear equation?A two-variable linear equation can be thought of as a linear relationship involving x and y, or two variables whose values rely on each other (often y and x) (usually x).
From the graph:
Part a: Rental cost for boat for 3 days is 180.
For 1 day = 180/3 = 60.
So,
Total cost for the team to rent a boat for 12 days:
total discounted rental cost = 12*60 - 12/4 *10
total discounted rental cost = $720 - $30
total discounted rental cost = $690
Part b: cost per team member
total discounted rental cost = 35% paid by coach.
remaining 75% is equally divided in all 16 team members.
Then,
cost per team member = 0.75*690 / 16
cost per team member = $32.34
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Complete question
The boat rental company gave a rowing team a discount of $10 off for every
4 days of rental. The team rented a boat for 12 days. Their coach paid 35%
of the total discounted rental cost. The remaining rental cost was divided
equally among the 16 team members.
Determine the total cost for the team to rent a boat,Determine the cost per team memberThe table for the data is shown.
The table shows the cookie sales for Tina's troop. If each box costs $3.50, show two ways that
HELP PLZ!!!
Tina could find the troop's total cookie sales.
Kind of Cookie
Mint
Vanilla sandwich
Peanut butter
Number of Boxes
60 boxes
42 boxes
56 boxes
Answer:
you can multiply the number of cookies with the cost of each box
Step-by-step explanation:
60 (number of boxes) x 3.50 (the cost for each box) = $210
42 (number of boxes) x 3.50 (the cost for each box) = $147
56 (number of boxes) x 3.50 (the cost for each box) = $196
I hope this helpsss :)
For the polynomial below, 3 is a zero.
g(x)= x³ - 2x² - 5x + 6
Express g (x) as a product of linear factors.
The complete factorization of the polynomial is:
h(x) = (x - 3)*(x - 1)*(x + 2)
How to factorize the polynomial?Here we have the polynomial:
g(x)= x³ - 2x² - 5x + 6
And we know that x = 3 is a zero, then (x - 3) is a factor.
So if f(x) = a*x² + b*x + c
We can write:
h(x) = (x - 3)*f(x)
Let's find f(x).
Expanding that:
x³ - 2x² - 5x + 6 = (x - 3)*(a*x² + b*x + c)
x³ - 2x² - 5x + 6 = ax³ + bx² + cx - 3ax² - 3bx - 3c
x³ - 2x² - 5x + 6 = ax³ + (b - 3a)x² + (c - 3b)x - 3c
Comparing like terms, we can see that:
a = 1
b - 3 a = -2
c - 3b = -5
-3c = 6
With the first and last equation we can get:
a = 1
c = 6/-3 = -2
Now with one of these values and the second or third equation we can find the value of b.
b - 3 a = -2
b - 3*1 = -2
b - 3 = -2
b = -2 + 3 = 1
Then:
f(x) = x² + x - 2
The zeros of this quadratic function are given by:
\(x = \frac{-1 \pm \sqrt{1^2 - 4*1*-2} }{2} \\\\x = \frac{-1 \pm 3}{2}\)
x = (-1 + 3)/2 = 1
x = (-1 - 3)/2 = -2
Then we can factorize this as:
f(x) = (x - 1)*(x + 2)
And then we can write h(x) as:
h(x) = (x - 3)*(x - 1)*(x + 2)
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A scientist mixes water (containing no salt) with a solution that contains 35% salt. She wants to obtain 140 ounces of a mixture that is 15% salt. How many
ounces of water and how many ounces of the 35% salt solution should she use?
Answer:
.35x = 140(.15)
.35x = 21
x = 60 oz of 35% salt.
The scientist will need 60 oz of the 35% salt solution and 80 oz of water.
PLEASE HELP ! worth 18 points :)
Using the Law of Cosines Given SAS
Information
Z
Find the value of x to the nearest tenth.
Which of the following equations correctly sets up
the law of cosines to solve for x?
552 - 52 +82-25)(8)· cos(X)
2-52 +82-2(5)(8).cos(559)
O * - (5+8) -2(5)(8).cos(559)
552 - 52 +82-2(5)(8) cos(x)
5
55°
Y
DONE
8
The equations correctly set up the law of cosines to solve for x will be x² = 5² + 8² - 2 (5)·(8) cos 55°. Then the correct option is B.
What is the cosine law?The squared of the size of any solitary side of either a triangle is equal, by the cosine rule, to the total of the squares of the lengths of the other two sides, times by the cosine of something like the angle they are a part of.
Let the triangle ΔABC, then the cosine law is given as,
c² = a² + b² - 2 a·b cos C
From the graph, the measure of the length 'x' is calculated as,
x² = 5² + 8² - 2 (5)·(8) cos 55°
The equations correctly set up the law of cosines to solve for x will be x² = 5² + 8² - 2 (5)·(8) cos 55°. Then the correct option is B.
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A standard die is rolled three times. What is the probability of rolling a number less than 5 on all three rolls?
Answer:
5/6
Step-by-step explanation:
This is because when you roll three times, there are 18 possible numbers (six numbers three times). If you want to get less than five each time, that is 5 number x 3 rolls = 15 numbers.
So...You get 15/18 which simplifies to 5/6
what is 12 = -5x + 2
Answer:
Hi there!
Your answer is;
-2= x
Step-by-step explanation:
12= -5x +2
-2
10= -5x
/-5
-2 = x
Hope this helps
Answer: x = -2 give me brainliest
Step-by-step explanation:
According to a Human Resources report, a worker in the industrial countries spends on average 419 minutes a day on the job. Suppose the standard deviation of time spent on the job is 30 minutes.
a. If the distribution of time spent on the job is approximately bell shaped, between what two times would 68% of the figures be?
enter the lower limit for the interval where 68% of the values would fall
to enter the upper limit for the interval where 68% of the values would fall
b. If the distribution of time spent on the job is approximately bell shaped, between what two times would 95% of the figures be?
enter the lower limit for the interval where 95% of the values would fall
to enter the upper limit for the interval where 95% of the values would fall
c. If the distribution of time spent on the job is approximately bell shaped, between what two times would 99.7% of the figures be?
enter the lower limit for the interval where 99.7% of the values would fall
to enter the upper limit for the interval where 99.7% of the values would fall
d. If the shape of the distribution of times is unknown, approximately what percentage of the times would be between 360 and 478 minutes?
At least enter percentages rounded to 1 decimal place
% (Round the intermediate values to 3 decimal places. Round your answer to 1 decimal place.)
e. Suppose a worker spent 400 minutes on the job. What would that worker’s z score be, and what would it tell the researcher?
z score = enter the z score rounded to 3 decimal places
(Round your answer to 3 decimal places.)
This worker is in the lower half of workers but within select the distance from the mean
standard deviation of the mean.
Step-by-step explanation:
Ah statistics
68-95-99.7
a. 68% is between -1 and 1 standard deviation, which is between 389 and 449 minutes
b. 95% is between -2 and 2 standard deviations, which is between 359 and 479 minutes
c. 99.7% is between -3 and 3 standard deviations, which is between 329 and 509 minutes
d. Use table A with a z-score of (360-419)/30 = -1.96666667
and with a z-score of (478-419)/30 = 1.96666667
NOTE THESE ARE NOT THE ANSWERS, but use the z-scores to find the percentage on table A
e. (400-419)/30 = -0.633333333 as his z-score
now find that value on table A
We are given the mean and the standard deviation. If the distribution is normal(bell-shaped), the Empirical Rule is used, otherwise, if the distribution is unknown, Chebyshev's Theorem is used.
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by \(100(1 - \frac{1}{k^{2}})\).
In this question:
Mean of 419, standard deviation of 30.
Question a:
Within 1 standard deviation of the mean, so:
419 - 30 = 389.
419 + 30 = 449.
Between 389 and 449 minutes.
Question b:
Within 2 standard deviations of the mean, so:
419 - 60 = 359
419 + 60 = 479
Between 359 and 479 minutes.
Question c:
Within 3 standard deviations of the mean, so:
419 - 90 = 329
419 + 90 = 509
Between 329 and 509 minutes.
Question d:
Have to find how many standard deviations it is from the mean:
(478 - 419)/30 = 1.97
(360 - 419)/30 = -1.97
Considering \(k = 1.97\)
\(100(1 - \frac{1}{1.97^{2}}) = 74.2\)
At least 74.2% of the times would be between 360 and 478 minutes.
Question e:
The z-score is:
\(Z = \frac{X - \mu}{\sigma}\)
In which X is the measure, \(\mu\) is the mean and \(\sigma\) is the standard deviation.
For this question, X = 400, \(\mu = 419, \sigma = 30\)
So
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{400 - 419}{30}\)
\(Z = -0.633\)
This worker is in the lower half of workers but within 0.633 standard deviations of the mean.
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Which line has the least
rate of change?
1
1
A. The line passing through (2,4) and (5,13)
B. The line passing through (-1,4) and (1,7)
C. The line passing through (1,1) and (3,3)
D. The line passing through (0,6) and (12,9)
1
Answer:
B
Step-by-step explanation
my sister said it was-
im sorry if its not right i hope it helps
Which expression is equivalent to StartRoot 8 x Superscript 7 Baseline y Superscript 8 Baseline EndRoot? Assume x greater-than-or-equal-to 0.
x y squared StartRoot 8 x cubed EndRoot
2 x cubed y cubed StartRoot x y squared EndRoot
2 x cubed y Superscript 4 Baseline StartRoot 2 x EndRoot
4 x cubed y Superscript 4 Baseline StartRoot x EndRoot
The expression that is equivalent to StartRoot \(8 x^7 y^8\) EndRoot is (\(2 x^3 y^4\) StartRoot 2 x EndRoot)^2.
To understand why this is the case, let's break down each expression and simplify them step by step:
StartRoot \(8 x^7 y^8\) EndRoot:
We can rewrite 8 as \(2^3\), and since the square root can be split over multiplication, we have StartRoot \((2^3) x^7 y^8\) EndRoot. Applying the exponent rule for square roots, we get StartRoot \(2^3\) EndRoot StartRoot \(x^7\) EndRoot StartRoot \(y^8\) EndRoot.
Simplifying further, we have 2 StartRoot \(2 x^3 y^4\) EndRoot StartRoot \(2^2\) EndRoot StartRoot \(x^2\) EndRoot StartRoot \(y^4\) EndRoot. Finally, we obtain 2 \(x^3 y^4\) StartRoot 2 x EndRoot, which is the expression in question.
(\(2 x y^2\) StartRoot 8 x^3 EndRoot)^2:
Expanding the expression inside the parentheses, we have \(2 x y^2\)StartRoot \((2^3) x^3\) EndRoot. Applying the exponent rule for square roots, we get \(2 x y^2\) StartRoot \(2^3\) EndRoot StartRoot \(x^3\) EndRoot.
Simplifying further, we have \(2 x y^2\) StartRoot 2 x EndRoot. Squaring the entire expression, we obtain (\(2 x y^2\) StartRoot 2 x EndRoot)^2.
Therefore, the expression (\(2 x^3 y^4\) StartRoot 2 x EndRoot)^2 is equivalent to StartRoot \(8 x^7 y^8\) EndRoot.
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PLZ HELPPPPP WILL GIVE BRAINLIEST AND NO WRONG ANSWER PLZ
Answer:
D
Step-by-step explanation:
Answer:
D.
Step-by-step explanation:
D. because it has a proper domain and range and no other answer has correct domain/range. Therefore, D is the answer.
Met Manufacturing produces inexpensive sunglasses. The selling price per pair is $9.44, with variable costs per pair being $2.19. Fixed costs, which include paying off the plant, labor, insurance, marketing, and management, are $748,374. What is the break-even point?
The sοlutiοn οf the given prοblem οf unitary methοd cοmes οut tο be fοr Met Manufacturing tο turn a prοfit, 103,184 sunglasses must be sοld.
Definitiοn οf a unitary methοd.The well-knοwn straightfοrward apprοach, actual variables, and any relevant infοrmatiοn frοm the initial and specialist questiοns can all be used tο finish the assignment. Custοmers may be given anοther chance tο try the gοοds in respοnse. If nοt, significant expressiοn in οur understanding οf prοgrams will be lοst.
Here,
We must figure οut hοw many pairs οf sunglasses must be sοld tο cοver the fixed and variable cοsts in οrder tο reach the break-even pοint.
Assume that X sunglasses must be sοld tο break even.
Fixed cοst plus variable cοst equals tοtal cοst.
Selling price x Number οf units sοld equals tοtal revenue.
The tοtal revenue and entire expense are equal at the break-even pοint.
Thus, we can cοnstruct the equatiοn:
Fixed cοst plus variable cοst multiplied by the selling price equals the quantity sοld.
=> $9.44 X = $748,374 + $2.19 X
=> $9.44 X - $2.19 X = $748,374
=> $7.25 X = $748,374
=> X = $748,374 / $7.25
=> X = 103,184
Therefοre, fοr Met Manufacturing tο turn a prοfit, 103,184 sunglasses must be sοld.
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Solve the system by back substitution.- 4x - 8y - 22 - 6w = 4y +62 + 2w = 8Z + W = 25w = 15The solution set is ? (Type an integer or a simplified fraction.)
Solve the system by back substitution.
- 4x - 8y - 22 - 6w = 4 (I)
y +62 + 2w = 8 (II)
Z + W = 2 (III)
5w = 15 (IV)
We'll start by equation (IV):
5w=15
w=3
Now, (III):
z+w=2
z+3=2
z=-1
Now, we follow to (II)
y+62+2w=8
y+62+6=8
y=8-68
y=-60
FInally, equation (I):
-4x-8*(-60)-22-6*3=4
-4x +480-22-18=4
-4x=4-440
-4x=-436
x=109
The solution set is: S={109, -60, -1, 3}
reflecting the graph y=cos x across the y axis is the same as not reflecting it at all
what kind of single transformation changes shape A to shape b
Graphs of a function and its inverse are shown on the same coordinate grid.
Which statements accurately compare the function and its inverse? Check all that apply.
The domains of the two functions extend to positive infinity.
The ranges of the two functions are all real numbers.
The x-intercept of f(x) and the y-intercept of f–1(x) are reciprocals of each other.
The point of intersection of the two functions indicates that the functions are inverses.
Neither function has a minimum.
The correct statements are;
The x-intercept of f(x) and the y-intercept of f–1(x) are reciprocals of each other.
The point of intersection of the two functions indicates that the functions are inverses.
Option C and D
How to determine the correct statementsTo accurately compare a function and its inverse based on the graphs, we have to know the following;
The domains of the two functions extend to positive infinity if the domain of the inverse function is equivalent to the range of the original function.The ranges of the two functions are all real numbers if the graphs cover the entire y-axis without any gaps or discontinuities.If the graphs intersect at the point (a, b), it means that f(a) = b and f^(-1)(b) = a, indicating that the functions are inverses of each other.
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express 2 cos 35 sin 67 as a sum
2 cos 35 sin 67 can be expressed as the sum of sin(102) and -sin(32).
To express 2 cos 35 sin 67 as a sum, we can use the trigonometric identity for the product of two sine or cosine functions.
Specifically, the identity states that 2 cos A sin B can be written as
sin(A + B) + sin(A - B).
Applying this identity, we have:
2 cos 35 sin 67 = sin(35 + 67) + sin(35 - 67)
Simplifying the expressions inside the sine functions:
sin(102) + sin(-32)
Since the sine function is an odd function,
sin(-x) = -sin(x),
so we can rewrite the equation as:
sin(102) - sin(32)
Therefore, 2 cos 35 sin 67 can be expressed as the sum of sin(102) and -sin(32).
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