4. Which of the following NOT TRUE about real gas
1. The molecules actually do occupy some space
II. Intermolecular force are negligible
III. No repulsion between molecules when molecules
become closer
IV. When the distance between molecules decrease,
the attraction or repulsion become greater
O A. II & III
O B.
C. IV
O D. 11 & IV

Explanation:

1. atom B has more neutrons than atom A

2. the name for this is Isotopes

3.atom A is lighter

Answer:The correct answer is A.

Explanation:Properties of ideal gases have different volumes under very high pressure. These gases take up additional volume when there is high pressure exerted, and the predicted volume of these gases will end up being smaller than the actual values of the gas volumes. Therefore, the true volume of the gases will be higher than the low ones that were predicted, giving your answer A.

Answer:

44.01 g/mol

Explanation:

Carbon dioxide is produced when carbon and oxygen are burned.

To totally burn carbon into carbon dioxide, or CO2, we require one mole of oxygen for every gram of carbon by weight.

or alternatively:

You produce 12+216=44 g of carbon dioxide for every 12 g of carbon.

The weight of CO2 in kg may be calculated if the amount of CO2 in litres is known by converting it to moles and multiplying it by 44.

The temperature and pressure of the left box is 250c (298 K), and 1 atm pressure.

The right box is at standard temperature and pressure.

Standard temperature and pressure is 00c (273.15 K) and 1 atm.

Hence, the pressure is the same, therefore the position is piston will be the same as the left figure.

At constant pressure, volume is directly proportional to absolute temperature.

\(V \propto T .\)

Now, as the temperature at the right box is less than 250c that of the left box, hence the volume decreases significantly.

The arrangement of molecules in the right box will be closer.

A diagram of the right box is given below.

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Answer:

Approximately \(19.1\; \rm g\).

Explanation:

The unit of concentration in this question is "\(\rm M\)". That's equivalent to "\(\rm mol \cdot L^{-1}\)" (moles per liter.) In other words:

\(c(\mathrm{MgSO_4}) = 2.68\; \rm M = 2.68\; \rm mol \cdot L^{-1}\).

However, the unit of the volume of this solution is in milliliters. Convert that unit to liters:

\(\displaystyle V = 59.3\; \rm mL = 59.3 \; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.0593\; \rm L\).

Calculate the number of moles of \(\rm MgSO_4\) formula units required to make this solution:

\(\begin{aligned}n(\rm MgSO_4) &= c \cdot V \\ &= 2.68 \; \rm mol \cdot L^{-1} \times 0.0593\; \rm L \approx 0.159\; \rm mol \end{aligned}\).

Look up the relative atomic mass data of \(\rm Mg\), \(\rm S\), and \(\rm O\) on a modern periodic table:

Calculate the formula mass of \(\rm MgSO_4\) using these values:

\(M(\mathrm{MgSO_4}) = 24.305 + 32.06 + 4 \times 15.999 \approx 120.361\; \rm g \cdot mol^{-1}\).

Using this formula mass, calculate the mass of that (approximately) \(0.159\; \rm mol\) of \(\rm MgSO_4\) formula units:

\(\begin{aligned}m(\mathrm{MgSO_4}) &= n \cdot M \\&\approx 0.159 \; \rm mol \times 120.361 \; \rm g \cdot mol^{-1} \approx 19.1\; \rm g\end{aligned}\).

Therefore, the mass of \(\rm MgSO_4\) required to make this solution would be approximately \(19.1\; \rm g\).

The reactant present in more amounts is called excess reagent. In the reaction between Mg and sulphuric acid, the reaction gradually stopped due to the consumption of the acid. Thus, option B is correct.

An excess reagent is a chemical reactant present in more quantity than the other substance or reactant in the reaction. They are not totally consumed after the reaction ends, unlike the limiting reagent.

In the reaction, magnesium is the excess reagent while dilute sulphuric acid is a limiting reagent that determines the reaction rate and the product formation. At first, the reaction will be fast but gradually will become slow as all dilute sulphuric acid will be consumed slowing downs and stopping the reaction.

Therefore, dilute sulphuric acid will be used up at the end of the reaction.

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The net force of the runner, given the data from the question is 280 N

From the question given above, the following data were obtained:

The net force of the runner can be obtained as illustrated below:

Net force = Exerting force - resistance force

Net force = 325 - 45

Net force = 280 N

From the calculation made above, we can conclude that the runner's net force is 280 N

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The net force of the runner would be 280 N.

Hope this helps! Also, if you need help with the other questions regarding this assignment, feel free to check out the study set I made on Quizlet. Thanks and good luck!

Quizlet - "Unit 6: Lesson 2 Newton's First Law QC"

h t t p s : / / q u i z l e t. c o m / 7 3 7 7 5 9 5 5 5 / u n i t - 6 - l e s s o n - 2 - n e w t o n s - f i r s t - l a w - f l a s h - c a r d s / ? n e w

Answer:

\(2LiCl +Br_2 \rightarrow 2LiBr +Cl_2\)

Single displacement reaction.

Explanation:

Hello!

In this case, by firstly rearranging the chemical reaction as shown below:

\(LiCl +Br_2 \rightarrow LiBr +Cl_2\)

It is also necessary to balance it at follows:

\(2LiCl +Br_2 \rightarrow 2LiBr +Cl_2\)

Thus, since bromine and chlorine are being exchanged as a result of the atoms rearrangement, we infer this is a single displacement reaction.

Best regards!

Explanation:

as it is cation so 4+

it loses four electron

Answer:

0.101 M

0.1 mol/kg

0.644

Explanation:

To calculate the molarity, molality, and mole fraction of Na2SO4 in a solution, you need to know the moles of Na2SO4 in the solution and the volume or mass of the solution.

A) Molarity: Molarity (M) is defined as the number of moles of solute per liter of solution. To calculate molarity, we need to divide the number of moles of Na2SO4 by the volume of the solution in liters.

First, calculate the number of moles of Na2SO4:

mass of Na2SO4 = 755 g

molecular weight of Na2SO4 = 142 g/mol

number of moles = mass/molecular weight = 755 g / 142 g/mol = 5.34 moles

Next, calculate the volume of the solution:

mass of water = 53,100 g

density of water = 1 g/mL

volume of water = mass/density = 53,100 g / 1 g/mL = 53,100 mL = 53.1 L

Finally, calculate the molarity:

molarity = number of moles / volume of solution = 5.34 moles / 53.1 L = 0.101 M

B) Molality: Molality (m) is defined as the number of moles of solute per kilogram of solvent. To calculate molality, we need to divide the number of moles of Na2SO4 by the mass of the solvent in kilograms.

mass of water = 53,100 g

mass of solvent in kilograms = mass in grams / 1000 g/kg = 53,100 g / 1000 g/kg = 53.1 kg

Finally, calculate the molality:

molality = number of moles / mass of solvent = 5.34 moles / 53.1 kg = 0.1 mol/kg

C) Mole fraction: The mole fraction (X) is defined as the ratio of the number of moles of solute to the total number of moles of solute and solvent in a solution. To calculate the mole fraction of Na2SO4, we need to divide the number of moles of Na2SO4 by the total number of moles of Na2SO4 and water.

number of moles of Na2SO4 = 5.34 moles

number of moles of water = 53.1 kg * 1000 g/kg / 18.015 g/mol = 2.96 moles

total number of moles = number of moles of Na2SO4 + number of moles of water = 5.34 moles + 2.96 moles = 8.30 moles

Finally, calculate the mole fraction:

mole fraction of Na2SO4 = number of moles of Na2SO4 / total number of moles = 5.34 moles / 8.30 moles = 0.644

The molarity of Na2SO4 in the solution is 0.101 M, the molality is 0.1 mol/kg, and the mole fraction of Na2SO4 is 0.644.

Answer:

4.0561×0.03÷63.5= 0.001916 mol cu

A coin is 3.00% Cu by mass. If the mass of the coin is 4.0561g, moles of Cu does it contain 0.001916 mole of Cu.

It is the most fundamental characteristic of matter and one of the fundamental quantities in physics.

Mass is a term used to describe how much matter is there in a body. The kilogramme is the SI unit of mass (kg). A body's mass does not alter at any point in time.

Given mass of coin = 4.0561g , moles =? , Cu by mass= 3.00%

4.0561×0.03÷63.5= 0.001916 mole Cu.

Thus, A coin is 3.00% Cu by mass. If the mass of the coin is 4.0561g, moles of Cu does it contain 0.001916 mole of Cu.

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Answer:

d=m/

Explanation:

d is density, m is mass, v is volume

Given: m =10.4g, v=12.2mL

substituting in equation,

d=10.4/ 12.2

d=0.8524g/mL

To learn more about density:

The density of the liquid is 0.852 g/mL.

To calculate the density of the liquid, we need to use the formula:

Density = Mass / Volume

Given that the mass of the liquid is 10.4 g and the volume is 12.2 mL, we can substitute these values into the formula:

Density = 10.4 g / 12.2 mL

Simplifying this expression, we find:

Density = 0.852 g/mL

Density is a physical property of a substance and is defined as the amount of mass per unit volume. In this case, the density tells us that for every milliliter of the liquid, there is 0.852 grams of mass. The units of grams per milliliter (g/mL) indicate that the density is a ratio of mass to volume.It is important to note that the density of a substance can vary with temperature, so this value is only valid under the conditions at which the measurement was made. Additionally, the density can provide valuable information about the identity of a substance, as different substances have different densities.

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Answer:

The answer is barium phosphate

The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)

In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.

The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.

The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.

In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.

It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.

Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.

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Answer:

Mg S2 O3

Explanation:

.691 g of Mg  is .284 mole

1.84 g of S    is .5739 mole

1.365 g of O is  .8531 mole      you can see the ratio is ~  1 :2 :3

                                                        Mg S2 O3

The correct answer is B. 8 molecules \(SO_3\). Option B

In the given reaction:

S(s) + \(O_2\)(g) → \(SO_3\)(g)

The stoichiometric coefficient in front of the \(SO_3\)molecule is 8, which indicates that 8 molecules of \(SO_3\)are formed as a product. This coefficient represents the ratio of the number of molecules involved in the reaction.

Option A (8 atoms \(SO_3\)) is incorrect because it only mentions the number of atoms, not molecules. The stoichiometric coefficient does not represent the number of atoms, but rather the number of molecules.

Option C (80.07g \(SO_3\)) is incorrect because it mentions a specific mass. The stoichiometric coefficient does not directly represent the mass of the substance, but rather the relative amount of molecules involved in the reaction.

Option D (32 \(SO_3\)) is incorrect because it mentions a specific volume. The stoichiometric coefficient does not directly represent the volume of the substance, but rather the relative amount of molecules involved in the reaction.

Therefore, the correct way to describe the \(SO_3\)component in the reaction is option B: 8 molecules \(SO_3\). This represents the ratio of the number of molecules of \(SO_3\)that are produced in the reaction.

Option B

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The standard enthalpy change for the reaction 2A + B ⇌ 2C + 2D   is 195 kJ/mol.

The enthalpy of a reaction is a measure of the heat changes that occur when reactants form a product in a given reaction.

The enthalpy change of a reaction can be calculated using the formula given below:

Enthalpy of reaction = sum of enthalpies of the products  - sum of enthalpies of the reactants

Considering the given reaction: 2A + B ⇌ 2C + 2D  

Enthalpy of reaction = (2 * C + 2 * D) - (2 * A + B)

Enthalpy of reaction = {[2 * 177 + 2 * (-515)] - [2 * (-231) + (-409)]}

Enthalpy of reaction = 195 kJ/mol

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Answer:

: kinetic energy is the energy transformation that occurs in a hot balloon.

Explanation:

Hot air balloons use a propane burner that converts chemical energy to thermal energy. The hot air is less dense than than the colder air and it lifts the balloon

Mendeleev sketched out the table he had in mind. Mendeleev created the so-called Periodic Law while assembling these atomic data cards.

Periodic law is defined as a rule that the elements fall into recurrent groupings when enumerated in order of their atomic numbers, causing elements with similar qualities to appear frequently. "The physical and chemical properties of the elements are periodic functions of their atomic numbers," is how the current Periodic law is best summarized.

Mendeleev found that when all the known chemical elements were arranged in order of increasing atomic weight, the resulting table revealed a periodicity, or repeated pattern, of characteristics within groupings of elements.

Thus, Mendeleev sketched out the table he had in mind. Mendeleev created the so-called Periodic Law while assembling these atomic data cards.

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Answer:

Gamma Ray's have the highest frequency.

Answer:

gamma rys espero te sirva

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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the concentration of the \(HNO_3\) solution is 0.0410M when a 0.105 L sample of an unknown \(HNO_3\) solution required 43.1 mL of 0.100 M \(Ba(OH)_2\) for complete neutralization.

Given the volume of sample of \(HNO_3\) = 0.105L

The concentration of \(Ba(OH)_2\)= 0.10M

The volume of solution of \(Ba(OH)_2\) = 43.1mL

The concentration of \(HNO_3\) be = M1

The reaction is as follows:

\(HNO_3 + Ba(OH)_2 -- > Ba(NO_3)_2 + H_2O\)

Since the molar ratio of \(HNO_3\) to \(Ba(OH)_2\) is 1:1, we can calculate the amount of \(HNO_3\) in the sample by multiplying the moles of \(Ba(OH)_2\) used to neutralize. Molarity(M) = number of moles(n)/volume of solution(V)

M1V1 = M2V2 such that:

\(M1 * 0.105 * 10^3 = 0.10 * 43.1\)

Molarity of \(HNO_3\)(M1) = (43.1 mL x 0.100 M \(Ba(OH)_2\)) / 0.105 L)

Molarity of \(HNO_3\)(M1) = 0.041 M

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Answer: The concept behind hydroelectric power is simple: Rather than combusting fossil fuels, like coal, oil, or natural gas, which put over 52 million kilotons of greenhouse gases into the atmosphere each year, dams block the water flowing in rivers or lakes and use the force of the would-be flow to turn turbines,

Explanation:

Answer:

The mass of sucrose in grams required to make  7% weight volume in 100 mL solution of water is 7g

Explanation:

The percentage weight of a solution is mostly referred to as percentage weight per volume (% w/v). The formula for this is

% w/v = g of solute/100 mL of solvent

sucrose is the solute here while water is the solvent. The mass (in grams) of the solute is the unknown

7% = g of solute/100 mL of water

where 7% equals/the same with 7/100;

7/100 = g of solute/100 mL of water

g of solute = 7 × 100/100

g of solute = 7 g

The mass of sucrose in grams required to make  7% weight volume in 100 mL solution of water is 7g

Answer:

83.86g/mol is the molecular weight of the acid

Explanation:

Molecular weight is the ratio of mass in grams and moles present. That means we need to determine the mass in grams (400.0mg = 0.400g) and the moles of the acid that can be detemined by using its reaction with NaOH:

Moles acid:

First, we need to assume the acid is a monoprotic acid (Only 1 proton is acid and reacts with a base).

when the acid, HX, reacts with NaOH there is produced:

HX + NaOH → H₂O + NaX

Where 1 mole of HX reacts per mole of NaOH. That means the moles at the endpoint of NaOH = Moles of HX:

Moles NaOH:

15.90mL= 0.01590L * (0.0750mol / L) = 1.193x10⁻³ moles of NaOH = Moles of HX are present.

The acidic solution was diluted to 100.0mL but only 25.00mL were taken, that is:

25.00mL / 100.00mL = 1/4 of the acid was titrated.

And moles of HX in the original solution are:

1.193x10⁻³ moles of HX * 4 = 4.77x10⁻³ moles of HX

It is multiplied by 4 because the real amount of acid is 4 times the titrated amount.

Thus, molecular weight is:

0.4000g / 4.77x10⁻³ moles of HX =

Answer:

hey, I believe it's.

It is a liquid

hope you have a good day

To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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