5. A student graphed f of x. equals. x. and g of x. equals. 1 over 3. f of x. plus 5 on the same coordinate grid. Which statements are true?

Select THREE correct answers.
To create g, the graph of f is shifted 5 units up.

To create g, the graph of f is shifted 5 units down.

The graph of f is steeper than the graph of g.

The graph of g is steeper than the graph of f.

The y-intercept of g is 5 units below the y-intercept of f.

The y-intercept of g is 5 units above the y-intercept of f.

\(\\ \sf\longmapsto f(x+4)=3x+4\)

\(\\ \sf\longmapsto f(x)=3x+4-4\)

\(\\ \sf\longmapsto f(x)=3x\)

Now

\(\\ \sf\longmapsto f(4)\)

\(\\ \sf\longmapsto 3(4)\)

\(\\ \sf\longmapsto 12\)

Answer:

the answer  is 8

Step-by-step explanation:

yes Ezra can plant 8 sunflowers

hope this helpsss :)

The level of measurement used in the classification is ordinal.

Ordinal levels of measurement group variables into categories like nominal scales, but also convey the order of the variables. For example, rate pain on a scale of 1 to 5, or classify income as high, medium, or low.

An ordinal scale is a second-level measure that indicates the ranking and order of data without actually specifying the degree of variation among the data. The order measurement level is his second of the four measurement scales. "Ordinal" means "order".

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Answer:

A x<1125

Step-by-step explanation:

The necessary components to describe a rotation on a coordinate plane include the center of rotation, the shape of the figure, and the number of degrees of rotation.

To describe a rotation of a figure on a coordinate plane, the necessary components include the center of rotation, the shape of the figure, and the number of degrees of rotation.

a. The center of rotation is a fixed point around which the figure rotates. It serves as the anchor for the rotation and determines the position of the figure after the rotation is applied.

b. The shape of the figure refers to its size, proportions, and geometric characteristics. This information is crucial as the figure retains its original shape during the rotation.

c. The number of degrees of rotation determines the magnitude of the rotation. It specifies how much the figure is rotated around the center of rotation. Positive angles indicate counterclockwise rotations, while negative angles represent clockwise rotations.

d. The direction of rotation is not necessary to describe a rotation on a coordinate plane. The rotation can be defined solely by the center, shape, and angle of rotation.

In summary, the essential components to describe a rotation on a coordinate plane include the center of rotation, the shape of the figure, and the number of degrees of rotation. The direction of rotation is not required to define the rotation.

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The solutions to the equation 3x^2 - 9x - 12 = 0 are x = 4 and x = -1.

To solve the quadratic equation 3x^2 - 9x - 12 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a),

where a, b, and c are the coefficients of the quadratic equation.

In this case, a = 3, b = -9, and c = -12. Substituting these values into the quadratic formula, we have:

x = (-(-9) ± √((-9)^2 - 4 * 3 * (-12))) / (2 * 3)

= (9 ± √(81 + 144)) / 6

= (9 ± √(225)) / 6

= (9 ± 15) / 6.

We have two possible solutions:

For the positive root:

x = (9 + 15) / 6

= 24 / 6

= 4.

For the negative root:

x = (9 - 15) / 6

= -6 / 6

= -1.

The solutions to the equation 3x^2 - 9x - 12 = 0 are x = 4 and x = -1.

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(A) Circular orbits of stable particles are possible at radii greater than three times the Schwarzschild radius for the non-rotating spherically symmetric mass.

This represents the radius of a black hole's event horizon, within which nothing can escape. The Schwarzschild radius is the event horizon radius of a black hole with mass M.

M can be calculated using the formula: r+ = 2Mwhere r+ is the radius of the event horizon.

(B)  1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ R. This is the required expression.

Tau is the proper time of the particle moving around a circular orbit. Hence, by making use of the formula given above:1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ dt.

(C) Time passes differently in different gravitational fields, and it follows that the period as measured at infinity should be larger than that measured by the particle.

The principle of equivalence can be defined as the connection between gravitational forces and the forces we observe in non-inertial frames of reference. It's basically the idea that an accelerating reference frame feels identical to a gravitational force.

(D) The period of the orbit as measured by an observer at infinity is 16π M^(1/2) and the period of the orbit as measured by the particle is 16π M^(1/2)(1 + 9/64 M²).

The period of orbit as measured by an observer at infinity can be calculated using the formula: T = 2π R³/2/√(M). Substitute the given values in the above formula: T = 2π (8M)³/2/√(M)= 16π M^(1/2).The period of the orbit as measured by the particle can be calculated using the formula: T = 2π R/√(1-3M/R).

Substitute the given values in the above formula: T = 2π (8M)/√(1-3M/(8M))= 16π M^(1/2)(1 + 9/64 M²).

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Answer:

3. The number of students that rode on each bus

Step-by-step explanation:

The equation they give us is:

2b + 6 = 70

The question already tells us that in this equation:

2 is the 2 buses that the school hired

6 is the 6 leftover kids who couldn't fit on the 2 buses

The question also tells us that the 2 buses only have a total of 64 seats, so 32 seats on 1 bus (64/2 = 32).

So that means b would equal the 32 seats on 1 bus, or the number of students that rode on each bus.

Hope it helps (●'◡'●)

Answer:

60

Step-by-step explanation:

3/5 x 100

0.6 x 100

60

Brainliest Appreciated!

Answer:

56

Step-by-step explanation:

Answer:

The equation for the given equation will be

\(y = 8\)

Step-by-step explanation:

If you have any questions tag on comments

Hope it helps!!!

Answer: 416

Step-by-step explanation:

Answer:

416

Step-by-step explanation: the tickets cost 17 each and there is a discount of $4 for a field trip so for that you do 17 minus 4 and you get 13 and then you will multiply 13 by 32 students and you get 416.

I hope this helps!!

Answer: 6ft per second

Step-by-step explanation: Its 18ft per 3 seconds. 6x3=18.

To prove that 3x ≤ y, assume the opposite, that is, 3x > y, rearrange the inequality substitute x < 2y and simplify, contradict the given condition that x < 2y, therefore, concluding that 3x ≤ y.

Start by assuming the opposite, that is, 3x > y.

From the given inequality,\(7xy \leq 3x^2 + 2y^2,\), we can rearrange to get:
\(7xy - 3x^2 \leq 2y^2\)

We can substitute \(x < 2y\) into this inequality:
\(7(2y)x - 3(2y)^2 \leq 2y^2\)

Simplifying, we get:
\(y(14x - 12y) \leq 0\)

Since y is a real number, this means that either y ≤ 0 or 14x - 12y ≤ 0.

If y ≤ 0, then 3x ≤ y is trivially true.

If 14x - 12y ≤ 0, then we can rearrange to get:
3x ≤ (12/14)y
3x ≤ (6/7)y
3x < y (since we assumed 3x > y)

But this contradicts the given condition that x < 2y, so our assumption that 3x > y must be false.

Therefore, we can conclude that 3x ≤ y.

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Answer:

Step-by-step explanation:

Step-by-step explanation:

Let x represents the number of cans of repellent and y represents the number of mosquitos,

If f be the relation from x to y,

Then by the given table,

f(x) = { (0, 11), (1, 8), (5, 2), (4,5), (2, 9), (3, 6)}

∵ If for each input in a relation has exactly one output, the relation is called a function.

Here, for each value of x there is exactly one value of y,

Hence, f(x) is a relation from x to y,

Answer:

domain = -3 \(\leq\) x \(\leq\) 3

range = 2 \(\leq\) x \(\leq\) 1

Step-by-step explanation:

remember, the domain is the input

and the range is the output

so in this case the domain would be the x values, and the range the y values

the x values are

-3 \(\leq\) x \(\leq\) 3

the y values are

2 \(\leq\) x \(\leq\) 1

To solve this problem we need to use the technique of Counting principle for the total number of strings of length 8 using digits 0, 1, 2, 3, 4, 5.

And, to create strings, we can start with the second character because the first character must follow a certain pattern. Then, after the second character has been chosen, the third, fourth, and fifth characters can be chosen in any order because they are unrestricted. Finally, the last three characters can be selected by specifying that the last two characters are different from the sixth and seventh characters, respectively.

The difference between the first and second digits is congruent to ±1 (mod 6), meaning that the second digit can be 1, 2, or 5 if the first digit is 0. If the first digit is 1, the second digit can be 0, 2, or 3, and so on. Therefore, the first two digits of the string can be chosen in\($3 \times 2 = 6$ ways.\)

Next, we must consider the third, fourth, and fifth digits of the string, which are unrestricted. Each of these digits can be chosen from one of six possible values, resulting in \($6 \times 6 \times 6 = 216$\) possible strings of length 8 with the first five digits.The final three digits of the string must be chosen such that the sixth, seventh, and eighth digits are distinct, and this can be done in\($5 \times 4 \times 3 = 60$ ways.\)

The total number of strings of length 8 is given by the product of the number of ways to choose each of the three groups of digits:\($6 \times 216 \times 60 = 77760$\)

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Answer:

The value of x is 7 if the equation can be reduced to (x + 9)³ = 4096 after applying the properties of the integer exponent option (C) 7 is correct.

What is an integer exponent?

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

It is given that:

The equation is:

After solving:

(x + 9)³ = 4096

x + 9 = ∛4096

x + 9 = 16

x = 7

Thus, the value of x is 7 if the equation can be reduced to (x + 9)³ = 4096 after applying the properties of the integer exponent option (C) 7 is correct.

Answer:

Side length ≈ 12.04

Step-by-step explanation:

145 = x²

144 is the closest  square, with the root 12

The square root of 145 is approximately 12.04

If my answer is incorrect, pls correct me!

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Answer:

The approximate side length is 12.0 in

Step-by-step explanation:

The area of a square is given by

A = s^2  where s is the side length

145 = s^2

Taking the square root of each side

sqrt(145) = sqrt(s^2)

12.04159458 = s

The approximate side length is 12.0 in

Answer: Based on the given information and the analysis provided, none of the options A, B, C, or D accurately describe the comparison between the y-intercepts and slopes of f(x) and g(x).

Step-by-step explanation:

To compare the y-intercepts and slopes of the linear functions f(x) and g(x), we need to examine the given table for f(x) and the equation g(x) = 2x + 1.

The y-intercept of a linear function represents the point where the graph of the function intersects the y-axis (when x = 0). In the table for f(x), the y-intercept is the value of f(0). However, since the table for f(x) is not provided, we cannot determine the y-intercept of f(x) based on the given information.

The slope of a linear function represents the rate of change of the function. For the linear function g(x) = 2x + 1, the slope is 2. This means that for every unit increase in x, the corresponding y-value increases by 2.

Based on the information provided, we can conclude that the slope of f(x) is not determined, so we cannot compare it to the slope of g(x) accurately. Therefore, none of the given answer options accurately describe the comparison between the y-intercepts and slopes of f(x) and g(x).

It's important to note that without additional information, we cannot determine the exact relationship between the y-intercepts and slopes of f(x) and g(x).

The y-intercept for f(x) and g(x) is the same, and the slope of f(x) is less than the slope of g(x). Therefore, the correct answer is choice A.

The y-intercept is the y-value of the function when x equals zero. Looking at the table for f(x), when x equals zero f(x) equals 1, so the y-intercept for f(x) is 1, same to g(x) which also is 1. This makes choice C and D incorrect.

Next, we calculate the slope of each function. The slope is represented by the change in y over the change in x, this can be represented by the formula (delta_y/delta_x). For g(x), in its equation form of y=mx+b, m, the coefficient next to x represents its slope, so its slope is 2. Looking at f(x), we can use the given two points to calculate the slope. Consider the points (0,1) and (2,4), (delta_y/delta_x) equals (4-1)/(2-0)=1.5,which is less than the slope of g(x). So, the slope of f(x) is less than the slope of g(x). This makes the answer choice A.

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\( - 9x + 3y - 27 = 0 \\ a = - 9 \\ b = 3 \\ c = 0 \\ {b}^{2} - 4ac = 9 - 4( - 9)( - 27) = 0 \\ x = \frac{ - b}{2a} = \frac{ - 3}{ - 18} = \frac{1}{6} \\ x = \frac{1}{6} \\ y = ( - 9 \times \frac{1}{6} ) + 3y = 27 \\ \frac{ - 3}{2} + 3y = 27 \\ 3y = 27 + \frac{3}{2 } \\ 3y = \frac{57}{2} \\ y = \frac{57}{6} = \frac{19}{2} \\ \)

i hope it helps u.....

Answer:

320 degrees.

Step-by-step explanation:

The number of the seats within the 25th row is 227.

According to the statement

We have to seek out that the quantity of seats are within the twenty-fifth row of the left section.

So, For this purpose, we all know that the

According to the information:

The number of seats within the first row of the left section of the Ming-Sun Theater is 9.

As with the middle section, the amount of seats in each succeeding row is 2 over the row ahead of it.

From this information, the equation become to search out the seats is:

Number of seats within the given row(x) = 9x+2

And the number of seats is: Number of seats within the 25th row(25) = 9(25)+2

Number of seats within the 25th row(25) = 225+2

Number of seats within the 25th row(25) = 227.

So, The amount of the seats within the 25th row is 227.

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Answer:

what are the options for the selection

Average angular acceleration Cav-z for the time interval t = 0 to t = 3.00 s is -0.2266 rad/s².

Given data:ωz(t) = γ - βt² = -βt² + γWhere, β = 0.835 rad/s³y = ωz(t) = 4.65 rad/s

To find:Average angular acceleration Cav-z for the time interval t = 0 to t = 3.00 s.

Average acceleration formula is given as:Cav-z = Δω/Δt

We can calculate Δω as follows:Δω = ωf - ωi

Where,ωf = final angular velocityωi = initial angular velocity

Since the time interval is given from t = 0 to t = 3 s, initial angular velocity is:ωi = ωz(0) = γ = constant = 5.33 rad/s

Final angular velocity is given as:ωf = ωz(t) = 4.65 rad/sΔω = ωf - ωi = 4.65 - 5.33 = -0.68 rad/s

Now, we can calculate Δt = 3 - 0 = 3 s

Therefore, the average angular acceleration Cav-z is:Cav-z = Δω/Δt= -0.68/3= -0.2266 rad/s²

Answer:Average angular acceleration Cav-z for the time interval t = 0 to t = 3.00 s is -0.2266 rad/s².

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The function F(x, y) has a local maximum at (-2, -3), saddle points at (2, -3) and (-2, 1), and a local minimum at (2, 1).

To find the critical points and classify them as local maxima, local minima, or saddle points, we need to find the partial derivatives of the function F(x, y) and evaluate them at each critical point.

Given the function F(x, y) = x³ - 12x + y³ + 3y² - 9y, let's find the partial derivatives:

∂F/∂x = 3x² - 12

∂F/∂y = 3y² + 6y - 9

To find the critical points, we set both partial derivatives equal to zero and solve the resulting system of equations:

3x² - 12 = 0 --> x² = 4 --> x = ±2

3y² + 6y - 9 = 0 --> y² + 2y - 3 = 0 --> (y + 3)(y - 1) = 0 --> y = -3 or y = 1

Therefore, the critical points are (-2, -3), (2, -3), and (-2, 1).

To classify these critical points, we use the second partial derivatives test. The second partial derivatives are:

∂²F/∂x² = 6x

∂²F/∂y² = 6y + 6

Now, let's evaluate the second partial derivatives at each critical point:

At (-2, -3):

∂²F/∂x² = 6(-2) = -12 (negative)

∂²F/∂y² = 6(-3) + 6 = -12 (negative)

Since both second partial derivatives are negative, the point (-2, -3) corresponds to a local maximum.

At (2, -3):

∂²F/∂x² = 6(2) = 12 (positive)

∂²F/∂y² = 6(-3) + 6 = -12 (negative)

Since the second partial derivative with respect to x is positive and the second partial derivative with respect to y is negative, the point (2, -3) corresponds to a saddle point.

At (-2, 1):

∂²F/∂x² = 6(-2) = -12 (negative)

∂²F/∂y² = 6(1) + 6 = 12 (positive)

Since the second partial derivative with respect to x is negative and the second partial derivative with respect to y is positive, the point (-2, 1) corresponds to a saddle point.

Therefore, the critical points are classified as follows:

Local maximum: (-2, -3)

Saddle points: (2, -3) and (-2, 1)

Local minimum: (2, 1)

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True. BCNF (Boyce-Codd Normal Form) decomposition guarantees that we can still verify all original functional dependencies (FDs) without needing to perform joins.

BCNF decomposition ensures that the resulting relations have no non-trivial FDs that violate BCNF, which means all FDs in the original relation are preserved in the decomposed relations. Therefore, we can still verify all original FDs in the decomposed relations without the need to perform joins.

The statement "BCNF decomposition guarantees that we can still verify all original FDs without needing to perform joins" is true. BCNF (Boyce-Codd Normal Form) decomposition ensures the preservation of all original functional dependencies (FDs) without requiring additional join operations.

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Answer:

Step-by-step explanation:

Answer:

4xy(3a+2b+1)

Step-by-step explanation:

1)  Find the Greatest Common Factor (GCF).

1 - What is the largest number that divides evenly into 12axy, 8bxy and 4xy?

It is 4.

2 -  What is the highest degree of \(a\)  that divides evenly into 12axy, 8bxy and 4xy?

It is 1, since a is not in every term.

3 -  What is the highest degree of \(x\) that divides evenly into 12axy, 8bxy and 4xy?

It is x.

4 - What is the highest degree of \(y\)  that divides evenly into  12axy, 8bxy and 4xy?

It is y.

5 -  What is the highest degree of \(b\) that divides evenly into 12axy, 8bxy and 4xy?

It is 1, since \(b\) is not in every term.

6 - Multiplying the results above,

GCF = 4xy

2)  Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

\(4xy(\frac{12axy}{4xy} +\frac{8bxy}{4xy} +\frac{4xy}{4xy} )\)

3) Simplify each term in parentheses.

\(4xy(3a+2b+1)\)

Answer:

last option, x = -1

Step-by-step explanation:

\(x^{2} + 2x + 1 = 0\\x_{1} = \frac{-2 + \sqrt{2^{2} - 4(1)(1) } }{2(1)}\\x_{2} = \frac{-2 - \sqrt{2^{2} - 4(1)(1) } }{2(1)}\\x_{1} = \frac{-2 + \sqrt{0} }{2}\\x_{2} = \frac{-2 - \sqrt{0} }{2}\\x = \frac{-2}{2} \\x = -1\)

The value of x by using the Quadratic Formula is,

⇒ x = - 1

An algebraic equation with the second degree of the variable is called an Quadratic equation.

Given that;

Equation is,

⇒ x² + 2x + 1

Now, We can use the Quadratic Formula for x as;

⇒ x² + 2x + 1

⇒ x = - 2 ± √2² - 4×1×1 / 2

⇒ x = - 2 ± √4 - 4 / 2

⇒ x = - 2 / 2

⇒ x = - 1

Thus, The value of x by using the Quadratic Formula is,

⇒ x = - 1

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