# 5 what will most likely happen when an air mas of low temperature exists above a water body at a higher temperature?
Heat will transfer from the wetter to the air ​

Answer:

Stefan-Boltzmann Law describes the power radiated from a black body in terms of its temperature. Specifically, the total energy radiated per unit surface area of a black body across all wavelengths per unit time is proportional to the fourth power of the black body's thermodynamic temperature

Explanation:

So we now know that

energy per unit area is = zigma x T^4

From this

T = temperature in kelvin

zigma is stefan boltzman constant

So

E/A = 5.67 x 10^-8 x (2200)⁴

= 1.33x 10^6 W/m^2

Answer:

Sample Response: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.

Explanation:

Sample Response: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.

just in case ur one of the people who like to double-check ur answer before turning it in or before u go onto the next thing u have to work on for the day(if ur doing online school) here u go the person above is 100% correct but here it is again if u like to double-check like I do

During the 200-meter race, Michael Phelps moved at a speed of 1.75 metres per second.

More than any other swimmer in history, he won Olympic medals, world titles, US national titles, and set world records. Phelps has made it a priority to support the growth of swimming at all levels during his career. With a total of 28 medals, he is the most successful and decorated Olympian of all time.

Velocity = Distance / Time

In this case, the distance swum is 200 meters and the time taken is 1 minute and 54 seconds, or 114 seconds.

Velocity = 200 meters / 114 seconds

Velocity = 1.75 meters/second (rounded to two decimal places)

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The term "spontaneous generation" is erroneous. Only life can give birth to more life. Airborne microbes can be detected.

A scientific experiment is any method that uses measurements and tests to confirm or deny a theory. A hypothesis is a notion that looks to be true but has yet to be confirmed, from which a study might be created. A basic experiment often addresses a "What would happen if...?" cause-and-effect inquiry. For example, you're wondering if misting a plant with water helps it develop faster. You get a sense of how the plant grows without being misted and then compare it to how it grows after being misted.

Here,

The phrase "spontaneous generation" is incorrect. Only life can create more life. Microbes in the air can be detected.

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The coefficient of kinetic friction between the ice and the puck is approximately 0.002.

1. We are given the initial velocity (u) of the puck as 10.50 m/s and the final velocity (v) as 10.39 m/s.

2. The distance covered by the puck (s) is given as 43 m.

3. We need to find the coefficient of kinetic friction (μ) between the ice and the puck.

4. Using the equation of motion, \(v^2\) = \(u^2\) + 2as, we can calculate the acceleration (a) of the puck.

  Rearranging the equation, we have a = (\(v^2 - u^2\)) / (2s).

  Substituting the given values, we get a = (10.\(39^2 - 10.50^2\)) / (2 * 43).

5. Calculating the value of 'a', we find a = -0.00176 \(m/s^2\).

  Note: The negative sign indicates that the puck is decelerating.

6. The frictional force (f) acting on the puck can be calculated using the equation f = ma, where 'm' is the mass of the puck.

  However, since the mass cancels out while calculating the coefficient of friction, we can skip this step.

7. The force of friction is given by the equation f = μN, where 'N' is the normal force.

  In this case, the normal force is equal to the weight of the puck, N = mg.

8. Substituting the values, we have μmg = f = ma.

  Rearranging the equation, we find μ = a / g, where 'g' is the acceleration due to gravity.

9. Substituting the value of 'a' and 'g' (approximately 9.8 \(m/s^2\)), we can calculate the coefficient of kinetic friction.

  μ = -0.00176 / 9.8 ≈ 0.0001796.

10. Rounding off the value to three decimal places, we get the coefficient of kinetic friction between the ice and the puck as approximately 0.002.

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Answer:

Decrease

Explanation:

Decrease

Vertical component = v sin (angle)

  sin 30 is less than sin 35

Answer:

\(0.15\: \mathrm{Hz}\)

Explanation:

The frequency is of an object is given by \(f=\frac{1}{T}\), where \(T\) is the orbital period of the object.

Since the racecar makes 24 revolutions around a circular track in 162 seconds, it will take the racecar \(\frac{162}{24}=6.75\:\mathrm{s}\) per revolution.

Therefore, the frequency of the racecar is \(\frac{1}{6.75}=\fbox{$0.15\:\mathrm{Hz}$}\) (two significant figures).

The radius of the track is irrelevant in this problem.

Answer:

First aid refers to the emergency or immediate care you should provide when a person is injured or ill until full medical treatment is available.

Explanation:

I believe it is, but report if I'm wrong.

Answer:

I think means of transportation would be muscles and structural support would be bones. Removes waste could be kidneys instead. The others seem right. This is just what I think but I'm not sure

the diameter is the biggest line that can touch the two opposite point of a round wire(circle)

or

d= circumference/π

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Aristotle is a towering figure in ancient Greek philosophy, who made important contributions to logic, criticism, rhetoric, physics, biology, psychology, mathematics, metaphysics, ethics, and politics.

Answer:

The laws of reflection govern how incident light rays are reflected on reflecting surfaces such as mirrors, smooth metal surfaces, and clear water. The laws of reflection are as follows: The incident ray reflected ray, and normal to the mirror’s surface are all in the same plane. The incidence angle equals the reflection angle.

Explanation:

Answer:

C. both a speed and a direction

Distance travelled by insects A and B is respectively 50√26 unit and 300 unit.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Uniform velocity of insect A: \(\bold{v_A}\) =  i+4j+3k unit.

Uniform velocity of insect B: \(\bold{v_B}\) =  4i+2j-4k unit.

Now dot product of two velocity vector is:

\(\bold{v_A}\)·\(\bold{v_B}\) = 50 (i+4j+3k)·50( 4i+2j-4k).

= 2500(4 + 4×2 + 3×(-4))

= 0.

Hence, the velocity vectors of two insects are perpendicular to each other. So, the insect fly at right angles to each other.

After time t = 50 unit, Position of insect A: \(\bold{X_A}\) = time* velocity

= 50 (i+4j+3k) unit.

After time t = 50 unit, Position of insect B: \(\bold{X_B}\) = time* velocity

= 50( 4i+2j-4k).

So, After time t = 50 unit, insect A travels a distance = 50 ×√(1²+4²+3²) = 50√26 unit.

After time t = 50 unit, insect B travels a distance = 50 ×√(4²+2²+(-4)²) = 300 unit.

Hence, distance travelled by insects A and B is respectively 50√26 unit and 300 unit.

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Answer:

The product of the mass and the volume is known as momentum.

According to the law of momentum, it is stated that the two or more bodies remain in a constant state unless an external force is applied in an isolated room.

Momentum depends on the following:-

Mass

Velocity

Momentum = MASS \ X \ VOLUMEMomentum=MASS X VOLUME

\begin{gathered}momentum = 3000kgm/s\\\\mass = 2000kg\\\\velocity =\frac{momentum}{mass}\\\\v= \frac{3000}{2000} \\\\v= 1.5m/s\end{gathered}

momentum=3000kgm/s

mass=2000kg

velocity=

mass

momentum

v=

2000

3000

v=1.5m/s

(A)  The potential energy stored in the two rubber bands together will be 9.90 J. (B) the speed of the stone when it leaves the slingshot will be 10.5 m/s.

To solve this problem, we need to use the formula for potential energy stored in a spring:

U = (1/2)kx²

where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.

(a) To find the potential energy stored in the rubber bands, we need to first calculate the spring constant. We know that it takes a force of 15 N to stretch one rubber band by 1.0 cm, so the spring constant for one rubber band is:

k = F/x = 15 N / 0.01 m = 1500 N/m

The two rubber bands are in parallel, so the effective spring constant for both of them together is:

ktotal = 2k = 3000 N/m

To calculate the displacement of the slingshot when the stone is pulled back. The equilibrium position is where the rubber bands are unstretched, so the displacement is:

x = 0.22 m

Finally, we can calculate the potential energy stored in the rubber bands:

U = (1/2)ktotal × x² = (1/2)(3000 N/m)(0.22 m)² = 9.90 J

Therefore, the potential energy stored in the two rubber bands together is 9.90 J.

(b) To find the speed of the stone when it leaves the slingshot, we need to use the conservation of energy:

U = K

where U is the potential energy stored in the rubber bands and K is the kinetic energy of the stone when it leaves the slingshot.

The potential energy stored in the rubber bands is 9.90 J, and the kinetic energy of the stone when it leaves the slingshot is:

K = (1/2)mv²

where m is the mass of the stone and v is its velocity.

We know the mass of the stone is 47 g, which is 0.047 kg. We can solve for the velocity:

v = √(2K/m) = √(2(9.90 J)/0.047 kg) = 10.5 m/s

Therefore, the speed of the stone when it leaves the slingshot is 10.5 m/s.

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Answer:

The value is  \(\alpha = 3.84 \ rad/s^2\)

Explanation:

From the question we are told that

    The constant angular speed is  \(w = 11.9 \ rad/s\)

     The time taken is  \(t = 3.10 \ s\)

Generally the magnitude of the angular acceleration is  mathematically represented as  

          \(\alpha = \frac{w}{t}\)

=>     \(\alpha = \frac{11.9}{ 3.10 }\)

=>     \(\alpha = 3.84 \ rad/s^2\)

Collins's visionary leadership and strategic thinking were his key strengths, while his risk taking nature could be seen as a weakness.

Michael Collins, the Irish revolutionary and politician, displayed several leadership traits throughout his career. Here are some key traits associated with Collins:

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Answer:

F= (34) × 4.5 = 153 N

The type of image produced by the converging lens when object O is at that position will be virtual and enlarged, Option D.

A virtual image is an image that is formed when light rays do not actually converge at a single point, but instead appear to converge when they are extended backwards. A virtual image is typically created by objects that are behind a lens or mirror that diverts the light rays in such a way that they appear to come from a different location.

An enlarged image, on the other hand, refers to a visual representation that has been magnified or made larger than the original size of the object being viewed.

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This question involves the concept of the conservation of energy.

(a) The child's speed halfway will be "12.13 m/s".

(b) The child's speed three-fourth way will be "14.86 m/s".

(a)

Using the law of conservation of energy:

Potential Energy Lost = Kinetic Energy Gained

\(mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}\)

where,

v = speed = ?

g = acceleration due to gravity = 9.81 m/s²

h = height lost = halfway = height/2 = 15 m/2 = 7.5 m

Therefore,

\(v = \sqrt{(2)(9.81\ m/s^2)(7.5\ m)}\)

v = 12.13 m/s

(b)

Using the law of conservation of energy:

Potential Energy Lost = Kinetic Energy Gained

\(mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}\)

where,

v = speed = ?

g = acceleration due to gravity = 9.81 m/s²

h = height lost = three-fourth way down = \(\frac{3}{4}height = \frac{3}{4}(15\ m) = 11.25\ m\)

Therefore,

\(v = \sqrt{(2)(9.81\ m/s^2)(11.25\ m)}\)

v = 14.86 m/s

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The attached picture shows the law of conservation of energy.

Answer:

Diameter of Newton’s 5th ring = 0.30 cm

Diameter of Newton’s 15th ring = 0.62 cm

Diameter of Newton’s 25th ring = ?

From Newton’s rings experiment we infer that

D2n+m − D2n = 4λmR

For the 5th and 15th rings we have

D215 − D25 = 4λ * 10 * R _______ (1) (m = 10)

For 15th and 25th rings

D225 − D215 = 4λ * 10 * R _______ (2) (m = 10)

We equate the two derivatives

Equation (2) = Equation (1)

D225 − D215 = D215 − D25

D225 = 2D215 – D25

Substituting the values into the equation

D225 = 2 * 0.62 * 0.62 – 0.3 * 0.3 =0.6788 cm2

D25 = 0.8239 cm

Diameter of \(25^{th}\) Newton  Ring = 0.97 cm

Newton Rings is an experiment based on principle of  thin film interference

In Newton Rings Experiment the Diameter of  \(n^{th}\) dark ring is given by equation (1)

\(\rm D_n= 2\sqrt{n\lambda R} ......(1)\\where \; \\D_n = Diameter\; of \; n^{th} \; dark \; ring }\\n = Number \; of \; Ring\\\lambda = Wavelength \\R = Radius \; of \; Curvature \; of\; the \; lens\)

From the condition given

\(\rm D_5 = 0.3 \; cm \\D_{15} = 0.62 \; cm\\\\D_{25} = To \; be \; determined \\\)

Putting the values in equation (1) for fifth diameter we get

\(\rm D_5 = 0.3=2\sqrt{5\lambda R}.......(2) \\D_{15} = 0.62 = 2\sqrt{15\lambda R}.......(3) \\\\Equation \; (3) - Equation (2) \\\\0.32 = 2\sqrt{\lambda R} ( \sqrt{15} -\sqrt{5})\\\\2\sqrt{\lambda R } = 0.1954....(4)\\\)

So  From equation (1) and (4)

\(\rm Diameter \; of \; 25^{th} Ring =D_{25} = 2\sqrt{\lambda R } \times \sqrt{25} \\\\D_{25} = 0.1954\times 5 \\\\D_{25} = 0.97 \; cm\)

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Answer:

mass and distance

Explanation:

dont need to summary this

Answer:

B. mass and distance

Explanation:

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:

c

Explanation:

Answer: C

Explanation:

Answer:

A. Gasoline

B. Apple juice

Explanation:

A homogeneous mixture can be defined as any liquid, solid or gaseous mixture which has an identical or uniform composition and properties throughout any given sample of the mixture. In Chemistry, all solutions are considered to be a homogeneous mixture.

For instance, aqueous hydrogen chloride, HCl(aq) is a homogeneous mixture. The aqueous hydrogen chloride is a homogeneous mixture of water and hydrogen chloride. This ultimately implies that, aqueous hydrogen chloride HCl(aq) is a solution of hydrogen chloride in water and it is commonly referred to as Hydrochloric acid.

Hence, the two mixtures that are homogeneous are gasoline and apple juice.

Answer:

A. Gasoline

B. Apple juice

A homogeneous mixture is a mixture in which the composition is uniform throughout the mixture. The salt water described above is homogeneous because the dissolved salt is evenly distributed throughout the entire salt water sample. Often it is easy to confuse a homogeneous mixture with a pure substance because they are both uniform.  The difference is that the composition of the substance is always the same. The amount of salt in the salt water can vary from one sample to another. All solutions would be considered homogeneous because the dissolved material is present in the same amount throughout the solution.

One characteristic of mixtures is that they can be separated into their components. Since each part of the mixture has not reacted with another part of the mixture, the identities of the different materials is unchanged.

Hence, the two mixtures that are homogeneous are gasoline and apple juice

Explanation: