50 points.... Y’all are mean and don’t help me but help everyone else.... correct answer will get brainliest.... if y’all help me....anyway...

Answer:

A. Amplitude: 1; midline: y = 1

Answer:

A. Amplitude: 1; midline: y = 1

Step-by-step explanation:

i took the test

In a perfectly symmetrical distribution, the median equals the mean. This means that half of the values in the distribution fall below the mean and half fall above it. So , the correct option is C.

In a perfectly symmetrical distribution, the median equals the mean. This means that half of the values in the distribution fall below the mean and half fall above it. The mean and median are both measures of the central tendency of a distribution and in a symmetrical distribution, they are the same value.

Option (a) is false because the range is the difference between the largest and smallest values in a distribution, whereas the interquartile range is the difference between the first quartile (25th percentile) and the third quartile (75th percentile), which are measures of variability.

Option (b) is false because the interquartile range is always smaller than the mean in any distribution, symmetrical or not.

Option (d) is false because in a symmetrical distribution, the variance and standard deviation may be equal, but this is not always the case.

So , the correct option is c.

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Answer:

23: 21\(\frac{23}{55}\)  25: 1\(\frac{44}{45}\)

Step-by-step explanation:

Question 23:

1) add the whole numbers together: 15+5=20

2)To add fractions, both need to have the same denominator. Find a number that is a multiple of both denominators (in this case 55)

\(\frac{9}{11}\) → \(\frac{45}{55}\) (multiply the numerator and denominator by 5)

\(\frac{3}{5}\) → \(\frac{33}{55}\) (multiply the numerator and denominator by 11)

3) add the fractions together

\(\frac{45}{55}\) + \(\frac{33}{55}\) = \(\frac{78}{55}\) (add the numerators)

4) Turn the improper fraction into a mixed number

Divide 78 by 55. You'll get a whole number and a remainder. The remainder is the new numerator: In this case 55 enters 78 once with a remainder of 23. Therefore:

1\(\frac{23}{55}\)

5) Add the whole numbers together to get the final answer:

20+1= 21

Answer: 21\(\frac{23}{55}\)

Question 25:

Follow the above steps but subtract instead of adding

Answer:

\(\displaystyle{y-1=5(x+6)}\)

Step-by-step explanation:

A point-slope form is written in the equation of  \(\displaystyle{y-y_1=m(x-x_1)}\). Where \(\displaystyle{(x_1,y_1)}\) is a coordinate point and \(\displaystyle{m}\) is slope.

The definition of parallel is to both lines have same slope. The given line equation has slope of 5. Therefore, we can write the equation in point-slope form as:

\(\displaystyle{y-y_1=5(x-x_1)}\)

Next, we are also given the point p(-6,1). Substitute \(\displaystyle{x_1}\) = -6 and \(\displaystyle{y_1}\) = 1 in:

\(\displaystyle{y-1=5[x-(-6)]}\\\\\displaystyle{y-1=5(x+6)}\)

Hence, the line equation that’s parallel to y = 5x - 4 and passes through a point (-6,1) is y - 1 = 5(x + 6)

Answer:

y - 1 = 5 ( x + 6 )

Step-by-step explanation:

       Here,

          m ⇒ slope

    y = 5x - 4 ← equation of the old line

         Now it is clear to us that,

         m ⇒ slope of the line ⇒ 5

         c  ⇒ y-intercept ⇒ -4

                 That is, m = 5

                   y - y₁ = m ( x - x₁ ).

        m = slope

           ( -6 , 1 ) ⇔ ( x₁ , y₁ )

        Let us solve this now

         y - y₁ = m ( x - x₁ )

         y - 1 = 5 ( x - ( -6) )

         y - 1 = 5 ( x + 6 )

                y - 1 = 5 ( x + 6 )

By using the z value, it can be calculated that

P value for upper tail = 0.0455

P value for lower tail = 0.9545

P value for two tail  = 0.091

What is z value?

z value determines the number of standard deviation, the event is above the mean value. That means z value determines the distance of the event from the mean and it is measured in terms of Standard Deviation.

z value = 1.76

From the z table

P value for upper tail = 1 - 0.9545 = 0.0455

P value for lower tail = 0.9545

P value for two tail = 0.0455 \(\times\) 2 = 0.091

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The mean of the data set {8, 12, 16, 17, 20, 23, 25, 27, 31, 34, 38} is 22.1818 and the standard deviation is 9.854.

The data set is {8, 12, 16, 17, 20, 23, 25, 27, 31, 34, 38}. (a) The mean of this data set can be found by adding all the values and dividing by the total number of values.Using a calculator, the mean is found to be 22.1818. The standard deviation can also be calculated using a calculator. Using StatKey, the standard deviation is found to be 9.854.

Mean: The mean (average) is the sum of all the values divided by the total number of values in a dataset. It is a measure of the center of the data set. In order to find the mean, we add up all the values and divide by the number of values. In this case, the mean is (8 + 12 + 16 + 17 + 20 + 23 + 25 + 27 + 31 + 34 + 38) / 11 = 22.1818. This means that the average of this data set is about 22.18.

Standard deviation: The standard deviation is a measure of the spread of the data. It tells us how far away the values are from the mean. A low standard deviation means that the data is clustered closely around the mean, while a high standard deviation means that the data is more spread out.

The formula for the standard deviation is:  sqrt(1/N ∑(xᵢ-μ)²) where N is the number of values, xᵢ is each individual value, and μ is the mean. Using StatKey, we find that the standard deviation of this data set is 9.854 In conclusion, the mean of the data set {8, 12, 16, 17, 20, 23, 25, 27, 31, 34, 38} is 22.1818 and the standard deviation is 9.854.

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The variables in the equations are aligned as follows:   2x - 3y = 9 and

2x - 3y = 8/3

When we talk about aligning a system of linear equations, we mean rearranging the equations so that the variables are in the same order and have the same coefficients. This is done to make it easier to apply methods for solving systems of equations, such as substitution or elimination.

In a system of linear equations, each equation typically involves two or more variables. The variables may have different coefficients in each equation, and they may appear in a different order. Aligning the system involves rearranging the equations in a way that puts the variables in the same order, with the same coefficients.

Align the variables in given the system of linear equations :

To align the variables in the given equations, we need to rearrange the second equation so that the coefficients of  and  are the same as in the first equation.

To align the variables in the equations, we need to rearrange the terms so that the x, y, and constant terms are all grouped together.

Starting with the first equation:

2x - 3y = 9

We can rearrange this as:

2x = 3y + 9

Now we can divide both sides by 2 to get x by itself:

x = (3/2)y + 4.5

Now let's move on to the second equation:

1-6x +9y = -7

We can rearrange this as:

-6x + 9y = -8

Next, we'll divide both sides by -3 to get x by itself:

2x - 3y = 8/3

Now both equations are in the form of:

ax + by = c

where a, b, and c are constants. The aligned equations are:

2x - 3y = 9

2x - 3y = 8/3

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Given:

A couple has seven children.

n(S)=49

a)

Let A be the event that they have all boys.

b)

Let B be the event that they have atleast one boy.

By converting the given double integral I = ∫_(-2)^2∫_(√4-x²)^0dy dx into an equivalent double integral in polar coordinates, we obtain a new integral with polar limits and variables.

The equivalent double integral in polar coordinates is ∫_0^(π/2)∫_0^(2cosθ) r dr dθ.

To explain the conversion to polar coordinates, we need to consider the given integral as the integral of a function over a region R in the xy-plane. The limits of integration for y are from √(4-x²) to 0, which represents the region bounded by the curve y = √(4-x²) and the x-axis. The limits of integration for x are from -2 to 2, which represents the overall range of x values.

In polar coordinates, we express points in terms of their distance r from the origin and the angle θ they make with the positive x-axis. To convert the integral, we need to express the region R in polar coordinates. The curve y = √(4-x²) can be represented as r = 2cosθ, which is the polar form of the curve. The angle θ varies from 0 to π/2 as we sweep from the positive x-axis to the positive y-axis.

The new limits of integration in polar coordinates are r from 0 to 2cosθ and θ from 0 to π/2. This represents the region R in polar coordinates. The differential element becomes r dr dθ.

Therefore, the equivalent double integral in polar coordinates for the given integral I is ∫_0^(π/2)∫_0^(2cosθ) r dr dθ.

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a) The amount of water in the pool after 2 hours can be calculated using the equation.

Water in pool = 10L/hour × 2 hours = 20L.

b) The pool will be 80L when the equation is satisfied: 80L = 10L/hour × Time.

Solving for Time, we find Time = 8 hours.

c) Part b) is linear.

a) To calculate the amount of water in the pool after 2 hours, we can use the equation:

Water in pool = Water filling rate × Time

Since the pool gets filled up with 10L of water per hour, we can substitute the values:

Water in pool = 10 L/hour × 2 hours = 20L

Therefore, after 2 hours, there will be 20 liters of water in the pool.

b) To determine the number of hours it takes for the pool to reach 80 liters, we can set up the equation:

Water in pool = Water filling rate × Time

We want the water in the pool to be 80 liters, so the equation becomes:

80L = 10 L/hour × Time

Dividing both sides by 10 L/hour, we get:

Time = 80L / 10 L/hour = 8 hours

Therefore, it will take 8 hours for the pool to contain 80 liters of water.

c) Part b) is linear.

The equation Water in pool = Water filling rate × Time represents a linear relationship because the amount of water in the pool increases linearly with respect to time.

Each hour, the pool fills up with a constant rate of 10 liters, leading to a proportional increase in the total volume of water in the pool.

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Step 1:

The number with fewer digits is always smaller (Option A is correct)

Step 2

Numbers with different numbers of digits are never equal. (Option E is correct).

The pair of triangle formed are congruent using the side-side-side congruency theorem.

Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent.

Since the opposite sides of a parallelogram are congruent, if the parallelogram is cut through the diagonal, the pair of triangle formed are congruent using the side-side-side congruency theorem.

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Answer:

it should be 680

Step-by-step explanation:

1 kilogram is 1000 grams

720*6=4320

5000-4320=680

The value οf each variable is a=4, b=8, c=4 and d= 4√3

In simple geοmetry, twο geοmetric items are perpendicular if the meeting at the place οf intersectiοn knοwn as a fοοt results in right angles. The perpendicular symbοl can be used tο visually depict the state οf perpendicularity.

Perpendicular lines are twο lines that meet οr crοss at right angles οf 90° in mathematics. The Latin wοrd "perpendicularis," which denοtes a straight line, is where the wοrd "perpendicular" first appeared.

Sin45°= perpendicular/hypοtenuse = a/4√2

Or, Sin45°= a/4√2

Or, 1/√2= a/4√2

Or, a=4

The value οf a is 4

Sin45°= perpendicular/hypοtenuse = c/4√2

Or, Sin45°= c/4√2

Or, 1/√2= c/4√2

Or, c=4

The value οf c is 4

Sin30°= a/b

Or, ½= 4/b

Or, b= 8

The value οf b is 8

Sin60°= d/b

Or, √3/2 = d/8

Or, 2d= 8√3

Or, d= 4√3

The value οf d is 4√3

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Answer:

The fraction is 3/10 = .3

The probability of 3 students arriving at a randomly selected office hour is 0.27(27%). This can be calculated by using the Poisson distribution equation which is P(x)=e^(-λ)*(λ^x/x!).

In the above equation, λ is equal to the average number of arrivals which is 3.3. Plugging these values into the equation gives us  P(3)= e^(-3.3)*(3.3^3/3!) = 0.27, this means that the probability of 3 students arriving in randomly selected office hours is 0.27.The Poisson distribution is used to calculate the probability of a certain number of events occurring in a fixed interval of time or space. It is commonly used in engineering, economics, and other fields.

This equation is especially useful in situations like this one where the arrival rate is known and the probability of a certain number of arrivals needs to be determined.

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A statistics professor finds that when she schedules an office hour for student help, an average of 3.3 students arrive. Find the probability that in a randomly selected office hour, the number of student arrivals is 3.

Answer: 433 of course

432 is the whole number and 846 is the decimal,

the number closest to the whole number is 8

we can only round the number forward if the number is 5 or more than 5 (6,7,8,9)

so 432.856 rounds to 433

Answer:

433

Step-by-step explanation:

846 is closer to 433 than it is to 432.

So, the answer is 433.

Hope this helps!

Answer:

∠T = 130°

Step-by-step explanation:

The figure we are given is a quadrilateral, a 4 sided shape.

There are many different types of quadrilaterals, such as a rhombus, rectangle, etc.

How will we know which quadrilateral the given figure is?

We will have to look at the given properties of the figure to find out.

We are given that there are two adjacent pairs of congruent sides.

RS = RU, and ST = UT.

Thus, the given quadrilateral is a kite.

Now that we know that the given figure is a kite, we can utilize a kite's angle properties to find out ∠T.

In a kite, the non-vertex angles (∠S and ∠U) are congruent.

If ∠S = 60°, then ∠U = 60°.

In a kite, the sum of the interior angles is 360°.

Hence:

∠R + ∠S + ∠T + ∠U = 360°

Therefore, we can substitute the angles we know into the equation and solve for ∠T.

∠R + ∠S + ∠T + ∠U = 360°

110 + 60 + ∠T + 60 = 360

110 + 120 + ∠T = 360

230 + ∠T = 360

∴ ∠T = 130°

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A gas station is 36 kilometers away the gas station is approximately 22.5 miles away .

To convert kilometers to miles, we can use the conversion factor of

1 mile = 1.6 kilometers .

Distance to the gas station = 36 kilometers

To find the distance in miles, we divide the distance in kilometers by the conversion factor

Distance in miles = Distance in kilometers / Conversion factor

Distance in miles = 36 kilometers / 1.6 kilometers per mile

Distance in miles = 22.5 miles

Therefore, the gas station is 36 kilometers away and it is approximately 22.5 miles away .

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Answer:

y=(4/3)x - 3

Step-by-step explanation:

Use equation (y-y1) =m (x-x1)

slope is m= (y1-y2)/(x1-x2)=1+3/3-0=4/3

use one of the points and this slope to complete the equation

(y-1)=(4/3)(x-3) distribute and add1 to both sides

y=(4/3)x-(3*4/3)+1

y=(4/3)x - 3

Answer:

y =  \(\frac{4}{3}\) x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (3, 1) and (x₂, y₂ ) = (0, - 3)

m = \(\frac{-3-1}{0-3}\) = \(\frac{-4}{-3}\) = \(\frac{4}{3}\)

The line crosses the y- axis at (0, - 3) ⇒ c = - 3

y = \(\frac{4}{3}\) x - 3 ← equation of line

important to know the size of the freshman classes in relation to the population size before using z-procedures in this situation, so the answer will be option C

In statistical inference, when using z-procedures such as hypothesis testing or constructing confidence intervals, one of the assumptions is that the samples are independent. In this scenario, knowing that the university had 6000 or more entering freshmen is important to ensure that the sample size is less than 10% of the population size.

The 10% condition is necessary to maintain the independence of samples. When the sample size is small relative to the population size, each sample observation has a greater impact on the population proportion, potentially violating the assumption of independence.

By ensuring that the sample size is less than 10% of the population size, we can reasonably assume that each sample observation is independent of each other. This allows us to use z-procedures and rely on the properties of the normal distribution for inference.

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Answer:

ok what else i need the whole question because good for her she has gaterade and water

Step-by-step explanation:

fix it

Answer:

y = -x + 6

y = -1/2x - 4

Step-by-step explanation:

slope of function in table is -2

the greater the absolute value of the slope, the steeper the line

so the absolute values of -1 and -1/2 are less than absolute value of -2

The total distance traveled, d, can be calculated by summing the distances covered during each phase of the journey.

First, we calculate the distance covered during the first phase of the journey, where the speed is v₁ = 65.6 mph for t₁ = 2.84 hours:

Distance₁ = v₁ * t₁

Since the speed is given in miles per hour, we need to convert the time to hours:

t₁ = 2.84 hours

Distance₁ = 65.6 mph * 2.84 hours

Next, we calculate the distance covered during the second phase, where the speed is v₂ = 56.2 mph for t₂ = 0.80 hours:

Distance₂ = v₂ * t₂

Distance₂ = 56.2 mph * 0.80 hours

Finally, we sum the distances covered in both phases to find the total distance:

d = Distance₁ + Distance₂

Now, let's calculate the average speed, v, for the entire journey. Average speed is defined as total distance divided by total time:

Total time = t₁ + t_stop + t₂

Note that the stoppage time, t_stop, needs to be converted from minutes to hours:

t_stop = 33.6 min / 60

Total time = 2.84 hours + t_stop + 0.80 hours

Average speed, v, is then:

v= d / (t₁ + t_stop + t₂)

The total distance, d, traveled is calculated by summing the distances covered in each phase of the journey. The average speed, v, is obtained by dividing the total distance by the total time taken for the entire journey.

To find the total distance traveled, we need to calculate the distances covered in each phase separately and then sum them up. In the first phase, the speed is given as 65.6 mph and the time is 2.84 hours. To find the distance covered, we multiply the speed by the time:

Distance₁ = 65.6 mph * 2.84 hours

In the second phase, the speed is 56.2 mph and the time is 0.80 hours:

Distance₂ = 56.2 mph * 0.80 hours

Now, we sum the distances covered in both phases:

d = Distance₁ + Distance₂

To find the average speed, we need to calculate the total time taken for the entire journey. This includes the time spent in the stoppage. The stoppage time is given as 33.6 minutes, so we need to convert it to hours by dividing by 60:

t_stop = 33.6 min / 60

The total time taken is the sum of the time in the first phase, stoppage time, and the time in the second phase:

Total time = t₁ + t_stop + t₂

Finally, we can calculate the average speed by dividing the total distance by the total time:

v= d / (t₁ + t_stop + t₂)

By calculating the above expressions, we can determine the total distance traveled and the average speed for the journey.

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Answer:

1

Step-by-step explanation:

This is where the line intercepts (crosses) the x-axis, here is 1.

The present value of payments at the end of each quarter of $245 for ten years with an interest rate of 4.35% compounded monthly is approximately $25,833.42.

To find the present value of the payments, we can use the present value formula for an ordinary annuity. The formula for the present value of an ordinary annuity is:
PV = PMT * ((1 - (1 + r)^(-n)) / r)

Where:
PV = Present Value
PMT = Payment amount
r = Interest rate per period
n = Number of periods

In this case, the payment amount is $245, the interest rate is 4.35% compounded monthly, and the number of periods is 10 years or 40 quarters (since there are 4 quarters in a year).

Let's plug in the values into the formula:
PV = $245 * ((1 - (1 + 0.0435/12)^(-40)) / (0.0435/12))

First, let's simplify the exponent part:
(1 + 0.0435/12)^(-40) ≈ 0.617349

Now, let's plug in the values and calculate:
PV = $245 * ((1 - 0.617349) / (0.0435/12))
PV = $245 * (0.382651 / 0.003625)
PV = $245 * 105.4486339
PV ≈ $25,833.42

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Answer:

\(\frac{1}{7}\)

Step-by-step explanation:

\(\frac{2}{5} / \frac{14}{5}\\\frac{2}{5} * \frac{5}{14} \\\frac{1}{7}\)

Answer:

C

Step-by-step explanation:

edge 21

Answer:

C or 3

Step-by-step explanation:

took the test

At the 0.05 significance level, the watchdog agency can conclude that the mean number of complaints per airport is less than 15 per month based on the provided sample data.

a. Before conducting a test of hypothesis, the assumption of normality should be satisfied. In this case, we assume that the population of the number of complaints per airport follows a normal distribution.

Additionally, we assume that the samples are independent and representative of the population.

b. To determine if it is reasonable to conclude that the population follows a normal distribution, we can plot the number of complaints per airport in a frequency distribution or a dot plot. Let's create a dot plot using the provided data:

Number of Complaints:

10   12   12   12   13   13   13   14   14   14

14   15   15   15   16   16

Based on the dot plot, the data appears to be roughly symmetric around the mean, indicating that the assumption of normality is reasonable.

c. To conduct a test of hypothesis, we will perform a one-sample t-test to compare the mean number of complaints per airport with the hypothesized value of 15. Here are the steps and calculations:

H0: The mean number of complaints per airport is 15.

H1: The mean number of complaints per airport is less than 15.

Using a significance level of α = 0.05, we will perform a one-sample t-test.

Sample mean:

x = (14 + 14 + 16 + 12 + 12 + 14 + 13 + 16 + 15 + 14 + 12 + 15 + 15 + 14 + 13 + 13 + 12 + 13 + 10 + 13) / 20

= 13.6

Sample standard deviation:

s = √[((14 - 13.6)² + (14 - 13.6)² + ... + (10 - 13.6)²) / (20 - 1)]

= √[(4.64 + 0.64 + ... + 8.84) / 19]

≈ 1.46

The t-value:

t = (x - μ) / (s / √n)

= (13.6 - 15) / (1.46 / √20)

≈ -2.07

The critical t-value for a one-tailed test with α = 0.05 and 19 degrees of freedom. From the t-distribution table or software, the critical t-value is approximately -1.73.

The calculated t-value with the critical t-value. Since -2.07 < -1.73, the calculated t-value falls in the rejection region.

Interpretation: Since the calculated t-value falls in the rejection region, we reject the null hypothesis. There is sufficient evidence to conclude that the mean number of complaints per airport is less than 15 per month.

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