74. Seven workers are hired to seed a field by hand. Each is given a plot 7 x 7
feet in size. What is the total area of the field?

Answer:

1+1

Step-by-step explanation:

Answer:

the answer is going to be 9

Answer:

13

Step-by-step explanation:

9 3/4 feet = 3/4 minutes

39/4 = 3/4

= 13

Answer:

6 and 8

Step-by-step explanation:

vertical lines yes, theyre across from each other making it vertical line

Vertical angles are the angles at the opposite sides of a transversal

The vertical angles are <6 and <8

For a pair of angles to be vertical angles, there must be a transversal line, and the two angles must be at the either sides of the transversal

This means that the following angles are vertical angles

Hence, the vertical angles are <6 and <8

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The molar solubility of Ba₃(PO₄)₂ is its concentration of pure substance

The correct equation for the ksp is Ksp = 6x⁵

Start by writing the reaction for the solution of Barium phosphate

Ba₃(PO₄)₂  ⇌3Ba²⁺ +2PO₄³⁻

Next, we make an ICE chart

Let "x" be the molar solubility of Barium phosphate

          Ba₃(PO₄)₂(s)  ⇌3Ba²⁺ +2PO₄³⁻

I                                 0                  0

C                              +3x               +2x

E                                3x³                 2x²

Lastly, we write the expression for the solubility product constant (Ksp)

This is represented as:

Ksp = [3Ba²⁺] × [2PO₄³⁻]²

Ksp = 3x³ × 2x²

Evaluate the product

Ksp = 6x⁵

Hence, the correct equation for the ksp is Ksp = 6x⁵

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The molar solubility of Ba₃(PO₄)₂ is its concentration of a pure substance.

The correct equation for the ksp is Ksp = 6x⁵.

The solubility product constant is the equilibrium constant for the dissolution of a solid substance into an aqueous solution. It is denoted by the symbol Ksp.

Start by writing the reaction for the solution of Barium phosphate.

Ba₃(PO₄)₂  ⇌3Ba²⁺ +2PO₄³⁻

Let "x" be the molar solubility of Barium phosphate

         Ba₃(PO₄)₂(s)  ⇌3Ba²⁺ +2PO₄³⁻

I                                 0                  0

C                              +3x               +2x

E                                3x³                 2x²

Lastly, we write the expression for the solubility product constant (Ksp),

This is represented as:

Ksp = [3Ba²⁺] × [2PO₄³⁻]²

Ksp = 3x³ × 2x²

Evaluate the product

Ksp = 6x⁵

Hence, the correct equation for the ksp is Ksp = 6x⁵

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The the final exam score according to the linear equation is 69. Thus, Option A is correct.

According to the statement

we have to find that the exam of the midterm which is Y with the help of the given equation.

So, For this purpose, we know that the

The value of p is 0.0001 and the given equation is Y=1.5 + .9(75).

Which is a linear equation.

So,

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

So, From given equation

Y=1.5 + .9(75).

Solve this equation

Y = 1.5 + 67.5

Y = 69.

So, The the final exam score according to the linear equation is 69. Thus, Option A is correct.

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

Professor Smith ran a simple regression equation using midterm exam scores to predict final exam scores. The R square was 0.91 and this was statistically significant (p=0.0001). Using the following simple regression equation generated by Professor Smith, predict the final exam score Y when the midterm score is 75: Y=1.5 + .9(75).

A. 69

B. 55

C. 82

D. 91

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all three statements P, Q, and R are correct.

To determine whether statements P, Q, and R are correct, we'll examine each one separately:

P: The domain of f(x, y) is R²

To find the domain of f(x, y), we need to identify any restrictions on x and y. In this case, we see that the function is undefined when x = y because it results in division by zero. Thus, the domain of f(x, y) is all points in R² except (0, 0). Therefore, statement P is correct.

Q: lim(x, y)→(0,0) f(x, y) exists

To determine if the limit exists as (x, y) approaches (0, 0), we need to evaluate the function along different paths and check if the limit is the same regardless of the path chosen.

Let's consider the limit along the path y = x:

lim(x, y)→(0,0) f(x, y) = lim(x, x)→(0,0) (x² - x²)/(x - x) = lim(x, x)→(0,0) 0/0

Here, we encounter an indeterminate form of 0/0, indicating that further evaluation is needed. By simplifying the expression, we get:

lim(x, y)→(0,0) f(x, y) = lim(x, x)→(0,0) 0 = 0

The limit is equal to 0, regardless of the chosen path. Hence, the limit exists as (x, y) approaches (0, 0). Therefore, statement Q is correct.

R: f(x, y) is continuous at (0, 0)

For a function to be continuous at a point, the following conditions need to be satisfied:

1. The function must be defined at that point (0, 0) - which it is.

2. The limit of the function as (x, y) approaches (0, 0) must exist - we established in statement Q that the limit is 0.

Both conditions are met, indicating that f(x, y) is continuous at (0, 0). Therefore, statement R is correct.

In summary, all three statements P, Q, and R are correct.

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Complete question is below

Let f(x, y) = { (x² - y²)/(x-y)   (x,y)≠(0,0)

= { 0 , (x, y) = (0, 0)

Which of the following is/are correct?

P The domain of f(x,y) is R²

Q lim(x, y)→(0,0) f(x, y) exists

R f(x,y) is continuous at (0,0)

d=first diver depth

s=second diver depth

d= 30

S= 30-12=18

the equation given and the gauge must be wrong because the equation for the second duvet souls be s=d-12 since the first diver is DEEPER than the second.

Answer:

648

Step-by-step explanation:

8×3^4=648

8×81=648

Answer:

8 shirts

Step-by-step explanation:

Given the equation a = 3b, where

a = the number of shirts  Wanda has

b = the number of shirts Wanda's brother (Will) has

Hence if Wanda has 24 shirts then

24 = 3b

Divide both sides by 3

24/3 = b

b = 8 shirts

Will has 8 shirts.

Answer:

8 shirts

Step-by-step explanation:

Answer:

Step-by-step explanation:

They give you the equation and wish that you evaluate that expression by terms provided. You need only to substitue the values given into the equation

a)3(2^1)=3(2)=6

b)3(2^4)=3(16)=48

Answer:

a. 3 x 2^1 = 6

b. 3 x 2^4 = 48

Step-by-step explanation:

You basically just fill in the "t" spot with 1 and 4 and then solve it from there.

Hope this helped!!

Answer:

i think its 1/8

Answer:

1/8

Step-by-step explanation:

To estimate the regression in the given model Yi = B0 + B1Xi + B2Ziui, where the variance of Ui is Σi^2 = Σ(zi^2), you can use the method of weighted least squares (WLS). The weights for each observation can be determined by the inverse of the variance of Ui, that is, wi = 1/zi^2.

In the given model, Yi = B0 + B1Xi + B2Ziui, the error term Ui is assumed to have a constant variance, given by Σi^2 = Σ(zi^2), where zi represents the individual values of Z.

To estimate the regression coefficients B0, B1, and B2, you can use the weighted least squares (WLS) method. WLS is an extension of the ordinary least squares (OLS) method that accounts for heteroscedasticity in the error term.

In WLS, you assign weights to each observation based on the inverse of its variance. In this case, the weight for each observation i would be wi = 1/zi^2, where zi^2 represents the variance of Ui for that particular observation.

By assigning higher weights to observations with smaller variance, WLS gives more importance to those observations that are more precise and have smaller errors. This weighting scheme helps in obtaining more efficient and unbiased estimates of the regression coefficients.

Once you have calculated the weights for each observation, you can use the WLS method to estimate the regression coefficients B0, B1, and B2 by minimizing the weighted sum of squared residuals. This involves finding the values of B0, B1, and B2 that minimize the expression Σ[wi * (Yi - B0 - B1Xi - B2Ziui)^2].

By using the weights derived from the inverse of the variance of Ui, WLS allows you to estimate the regression in the presence of heteroscedasticity, leading to more accurate and robust results.

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Sara needs 4.75 cans of 40 packages of Cute Puppy to feed her puppies for two months.

To determine the number of can packages of cute puppies that Sara needs to purchase, we need to divide the total number of cans eaten by the two puppies by the 40 can package using a fraction method.

A fraction is a number that shows the numerator and denominator separated by a division line.

Sara has two puppies:

Since Sonny eats 8.25 can of food per week.

There are 8 weeks In two months. As such, Sonny will eat:

Cher will eat (15.5 × 8) cans in two months

The total number of cans eaten by the two puppies is:

Recall that:

Therefore;

= (190 /40) cans

= 4.75 cans

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I think is B

I added 12 on the ride

Answer:

y = 7X

Step-by-step explanation:

Answer:

50 p Is a better deal

Step-by-step explanation:

if wrong let me know

8

i did this before so have fun on your future work :D

Answer:

The first blank is 4 next is x next is 15 next is 6 next is x next is 10.

Answer:

15 ; 4 ; 10 ; 6 ; same ; 2.5

Step-by-step explanation:

1) 15 because the initial height is a constant, so it can‘t be multiply for a variable

2) 4. The x represent the weeks and the growing of the plant depends on the weeks

3) 10 because the initial height is a constant

4) 6. The x represent the weeks and the growing of the plant depends on the weeks

5) same

6) we have to solve the equation

-  add at the two members -6x

4x + 15 -6x = 6x + 10 -6x

-2x + 15 = 10

- add at the two members -15

-2x + 15 - 15 = 10 - 15

-2x = -5

- divide the two members by -2

x = 5/2

x = 2,5

Using the principle of proportional relationship, you can go 165km farther after the trip of 360km with 42L gasoline in the tank.

Consumption rate =\(8L\) for \(100 km\)

So, per  number of Km per Litre is

\(8L = 100km\)

\(1 L = x\)

so,

\(8x = 100\)

\(x=8 \div 100\\\)

\(x= 12.5\) kilometer per Litre

Number of kilometers for \(42 L\)

\(12.5 km = 1 L\)

\(y=42L\)

On, Cross multiplying

\(y = 12.5\times42\)

\(y = 525 km\)

The difference in the distance \(= 525 - 360 = 165 km\)

Therefore, the gas can go for a further \(165 km\)

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The value of K is 20

The LHS (Left Hand Side) reduces to 2 x 10^1005

2 x 10^1005  =k x 10^1004                    

k =[2 x10^1005] / [10^1004] = 2 x 10

k =20                                                    

A positive integer is defined as a whole number greater than zero. All counting numbers are included in the set of positive integers.

Positive numbers include: 1, 2, 88, 800, 9000, and so on. Positive numbers are whole numbers with the symbol (+) in front of the numerical value. Most of the time, the plus sign is simply represented without the symbol. Positive numbers outnumber negative numbers and zero. On the number line, positive numbers are represented to the right of zero

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Answer:

$40,068

Step-by-step explanation:

37,800 x 0.06  = 2,268

37,800 + 2,268 = 40,068

when getting a bearing, we're referring to the angle from the North line moving clockwise, so of D from C?  well, the "from" point gets the North line and we check the angle from that North line clockwise to the other point, Check the picture below.

Answer:

Step-by-step explanation:

cause 100 cats can catch 100 bunnies in 300 min

Answer:

E

Step-by-step explanation:

Answer:

18x+24

Step-by-step explanation:

Use the distributive property

The equivalence classes of the equivalence relation {(0, 0), (1, 1), (1, 2), (2, 1), (2, 2), (3, 3)} on the set {0, 1, 2, 3} are {[0], [1, 2], [3]}.

The given equivalence relation {(0, 0), (1, 1), (1, 2), (2, 1), (2, 2), (3, 3)} on the set {0, 1, 2, 3} defines relationships between pairs of elements. An equivalence relation partitions a set into subsets or equivalence classes. Each equivalence class contains elements that are related to each other based on the given relation.

In this case, let's examine the pairs in the relation:

(0, 0): This pair states that 0 is related to itself.

(1, 1): Similarly, 1 is related to itself.

(1, 2) and (2, 1): These pairs show that 1 and 2 are related to each other. This indicates a symmetric relationship.

(2, 2): Again, 2 is related to itself.

(3, 3): 3 is related to itself.

From these pairs, we can identify the equivalence classes:

[0]: This equivalence class contains the element 0, which is related only to itself.

[1, 2]: This class includes elements 1 and 2, which are related to each other due to the symmetric relationship in the pairs (1, 2) and (2, 1).

[3]: The equivalence class [3] consists of the element 3, which is related only to itself.

Each equivalence class is a subset of the set {0, 1, 2, 3} and represents a distinct group of related elements. These classes help us understand the relationships and similarities between the elements based on the given equivalence relation.

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Answer:

Step-by-step explanation:

let 'x' represent the amount removed, then we require:

40-0.25 <= 48-x <= 40+0.25

which solves to:

7.75 <= x <= 8.25

the carpenter must saw off between 7.75 and 8.25 inches

Answer:

Step-by-step explanation:

We have that

ax -y=4

if the graph of the equation would pass through the point M (3, 5)

then

for the point M (3, 5)

x=3

y=5 I substitute the values of x and y in the --> a*3-5-4------> a*3=4+5------->

equation

ax -y=4- a=9/3

a=3

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Answer:

x = c + 5 / a

Step-by-step explanation:

Let's solve for x.

ax - c = 5

Step one : Add C to both sides of the equation.

ax - c + c = 5 + c

ax - c = c + 5

Step two : divide both sides of the eqaution by a .

ax ÷ a = C + 5 ÷ a

Therefore, your answer is x = c + 5 / a

This situation does not contradict Rolle's Theorem because Rolle's Theorem requires the function to be continuous on a closed interval and differentiable on an open interval, which is not satisfied by f(x) = tan x in the interval (0, π).

To show that f(0) = f(π), we evaluate the tangent function at these points. At x = 0, tan(0) = 0, and at x = π, tan(π) = 0. Therefore, f(0) = f(π).

To investigate whether there exists a number c in the interval (0, π) such that f'(c) = 0, we need to find the derivative of f(x). The derivative of tan x is given by f'(x) = sec² x. However, the secant squared function is never equal to zero. Therefore, there is no c in the interval (0, π) where f'(c) = 0.

This situation does not contradict Rolle's Theorem because Rolle's Theorem requires certain conditions to be met. First, the function must be continuous on the closed interval [a, b], which is not satisfied by f(x) = tan x since it is not defined at x = π/2. Second, the function must be differentiable on the open interval (a, b), but f'(x) = sec^2 x is not defined at x = π/2. Thus, the requirements of Rolle's Theorem are not fulfilled, and its conclusion does not apply to f(x) = tan x in the interval (0, π).

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