7(+5)=21
can you please help with math problem
​

The relationship of the graph g(x) = (x − 2)³ + 6 compare to the parent function of f(x) = x³ is that g(x) is shifted 2 units to the right and 6 units up.

Translations are a transformation technique that changes the position of an object from one point on the plane to another.

Given is a function, g(x) = (x − 2)³ + 6, we need to compare the graph of g(x) = (x + 2)³ - 6 to the parent function of f(x) = x³

The function compared to f(x) = x³, shows a translation of f(x) by 2 unit to the right along the horizontal and vertical translation of the function 6 units up

Hence, the relationship of the graph g(x) = (x − 2)³ + 6 compare to the parent function of f(x) = x³ is that g(x) is shifted 2 units to the right and 6 units up.

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Answer:

Amplitude= |A|= |2|=2

Step-by-step explanation:

comparing the function with F(x)= a cos bx

then a=2 and b =-4

so Amplitude=|A|= |2|=2

The mean of the following data 0,5,30,25,16,18,19,26,0,20,28 is 17.

Hence option D is the correct option.

Mean is the average value of a given set of data. It is calculated by the formula,

Mean =  {Summation of all the values in the data set} / {Number of observations is the data set}

That is, Mean = {Σ all values in the data set} / {number of observations}

The given data set is as follows,

0,5,30,25,16,18,19,26,0,20,28

The number of observations in the data set is 11.

The summation of all the values in the data set is = {0 + 5 + 30 + 25 +
16 + 18 + 19 +26 + 0 + 20 + 28} = 187

Therefore, by applying  the formula of Mean we get

Mean = 187/ 11 = 17

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Answer:

Use this formula to solve SA= \(\frac{1}{2}\) p (l) + B

Step-by-step explanation:

p= perimeter of base

l= slant height  (2.8)

B= Base

Based on the project's probabilities and the weight of the outcomes, the expected value of these outcome is $362.50

The expected value of the given outcomes can be found as:

= ∑(Weight x Outcome)

Solving gives:

= (250 x 25%) + (350 x 50%) + (25% x 500)

= 62.5 + 175 + 125

= $362.50

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Answer:

1. <

2. <

Step-by-step explanation:

Have a good day :)

Answer: d. (if a polygon has congruent angles, then it is regular)

Step-by-step explanation:

Converses follow the format of "if q, then p" (while  the original conditional is "if p, then q")

Just because there are clouds does not mean its raining (cloudy days)

just because it has four equal sides does not make it a square (rhombi have four equal sides but are not squares)

just because you cannot see the sun does not mean it is not daytime (solar eclipses)

if a polygon is regular, it must have congruent angles

we are given the vector-valued function r(t) = <3e^(2t), 3e^(-2t), 3te^(2t)>, and we need to find T(0), r''(0), and r'(t) · r''(t).

T(0) represents the unit tangent vector of r(t) at t = 0. To find T(0), we need to calculate the derivative of r(t) with respect to t, normalize it to obtain the unit vector, and evaluate it at t = 0.

r''(0) represents the second derivative of r(t) with respect to t, evaluated at t = 0. To find r''(0), we need to calculate the second derivative of r(t) and evaluate it at t = 0.

Finally, r'(t) · r''(t) represents the dot product between the first derivative of r(t) and the second derivative of r(t) at a general value of t.

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The values are: (a)\(2^{1-i}\) , (b)\((\cos i)^i\) , (c) \((1+i)^{1+i}\) , and (d) \(i^{\sin i}\).

To find the value of \(\(2^{1-i}\)\), we can rewrite it using the properties of exponents. We have:

\[2^{1-i} = 2^1 \cdot 2^{-i}

       = 2 \cdot \frac{1}{2^i}.\]

Now, we can express \(\(2^i\)\) in terms of complex numbers using Euler's formula:

\[2^i = e^{i\ln(2)}

   = \cos(\ln(2)) + i\sin(\ln(2)).\]

Substituting this back into the expression, we have:

\[2^{1-i} = 2 \cdot \frac{1}{2^i}

       = 2 \cdot \frac{1}{\cos(\ln(2)) + i\sin(\ln(2))}.\]

Next, let's determine the value of \((\cos i)^i\).

We can use Euler's formula again to express \(\cos(i)\) as a complex number:

\[\cos(i) = \frac{e^{i \cdot i} + e^{-i \cdot i}}{2}

         = \frac{e^{-1} + e}{2}.\]

Substituting this back into the expression, we have:

\((\cos i)^i = \left(\frac{e^{-1} + e}{2}\right)^i.\)

Now, let's find the value of \((1+i)^{1+i}\). We can rewrite it as:

\((1+i)^{1+i} = e^{(1+i)\ln(1+i)}.\)

Lastly, let's determine the value of \(i^{\sin i}\). We can rewrite it as:

\[i^{\sin i} = e^{\ln(i) \cdot \sin i}.\]

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The selling price of the calculator in order to obtain a 35% profit should be  $3267.

Profit is total revenue less total cost.

Profit = selling price - cost price

Cost price of the calculator = service fee + cost

2370 + 50 = 2420

Selling price = (1 + profit) x cost price

1.35 x 2420 = $3267

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Step-by-step explanation:

The question basically requires us to check if the number is between the two range of numbers;

Lower limit = .006

Upper limit = .14

.006: This is the lower limit, hence it lies between.

.14: This is the upper limit, hence it lies between.

.001 :  This number is below the lower limit, hence it does not lie between the numbers.

.110: This number is below the upper limit but above the lower limit hence it lies between the numbers.

.05: This number is below the upper limit but above the lower limit hence it lies between the numbers.

.042: This number is below the upper limit but above the lower limit hence it lies between the numbers.

.0014: This number is below the lower limit, hence it does not lie between the numbers.

.18: This number is above the upper limit, hence it does not lie between the numbers.

It rained approximately 4.47 inches on Tuesday.

The meaning of SUBTRACT is to take away by or as if by deducting. How to use subtract in a sentence.

On Monday, it rained 4(1/2) inches.

On Tuesday, it rained 0.03 inches less than on Monday.

To find out how much it rained on Tuesday, we need to subtract 0.03 inches from the rainfall on Monday.

4(1/2) inches - 0.03 inches = 4.5 inches - 0.03 inches = 4.47 inches

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Answer:

x = 7 , y = 7\(\sqrt{2}\)

Step-by-step explanation:

A 45- 45- 90 triangle is an isosceles right triangle with the 2 legs being congruent , that is

x = 7

Using Pythagoras' identity in the right triangle, then

y² = 7² + 7² = 49 + 49 = 98 ( take square root of both sides )

y = \(\sqrt{98}\) = \(\sqrt{49(2)}\) = \(\sqrt{49}\) × \(\sqrt{2}\) = 7\(\sqrt{2}\)

Answer:

Step-by-step explanation:

from the figure we understand that it is an isosceles right triangle, two equal angles and two equal sides, so x has the value 7, we solve with Pythagoras

x = 7

y = √ (7² + 7²)

y = √(49 + 49)

y = √98

y = 9.9

When we calculate probabilities involving one event AND another event occurring, we multiply their probabilities.

According to me , independent is the word which is associated with multiplication when computing probabilities . Because when the events are independent then we multiply the probabilities .

According to the multiplication rule of probability, the probability of occurrence of both the events A and B is equal to the product of the probability of B occurring and the conditional probability that event A occurring given that event B occurs.

The probability of the union of two events is equal to the sum of individual probabilities. The union of two set contains all the elements of previous sets. The union is denoted by ∪. The equation for the students earnings will be expressed as P(A∪B). The occurrence of event A changes the probability of B then the events are dependent. If the probability of two events happening together is zero then the events are mutually exclusive.

Therefore,

When we calculate probabilities involving one event AND another event occurring, we multiply their probabilities.

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We are given that the distribution of maximum oxygen uptake for elite athletes is approximately normal with mean 69 and standard deviation 7.6.

To find the probability that an elite athlete has a maximum oxygen uptake of at least 84.2 ml/kg, we need to standardize the value using the formula:

z = (x - μ) / σ

where,

x = the value of 84.2 ml/kg

μ = the mean of 69 ml/kg

σ = the standard deviation of 7.6 ml/kg.

Plugging in the values, we get:

z = (84.2 - 69) / 7.6

    = 2.03

Using a standard normal distribution table or calculator, we find that the probability of a standard normal variable being greater than or equal to 2.03 is 0.0217. Therefore, the probability that an elite athlete has a maximum oxygen uptake of at least 84.2 ml/kg is 0.0217.

z = (58.36 - 69) / 7.6

   = -1.36

Using a standard normal distribution table or calculator, we find that the probability of a standard normal variable being less than or equal to -1.36 is 0.0869. Therefore, the probability that an elite athlete has a maximum oxygen uptake of at most 58.36 ml/kg is 0.0869.

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\(Answer:\\\)

\(368\)

\(Step\: by\: step \:explanation:\\\)

\(12a^2-3ab+2b ; \\ \: if \: a=-5 \: and \: b=4

\\ 12a^2-3ab+2b = 12( - 5)^2-3( - 5)(4))+2(4) \\ 12a^2-3ab+2b = 300 + 60 + 8 \\ 12a^2-3ab+2b = 368\)

Answer:

join

Step-by-step explanation:

meet./vyc-hwbw-svg

Answer:

see explanation

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

(1)

Here m = 2 and (a, b) = (- 1, 3 ) , then

y - 3 = 2(x - (- 1) ), that is

y - 3 = 2(x + 1)

(2)

Here m = - 5 and (a, b) = (4, 0 ) the coordinates of the x- intercept

y - 0 = - 5(x - 4) , that is

y = - 5(x - 4)

The equation of the line is y= 3x+45.

What is the equation of the line in point-slope

A line is a one-dimensional figure in geometry since it has length but no breadth. A line is created from a collection of points that may be stretched indefinitely in opposite directions. It is determined by two points in a two-dimensional plane. But there are other ways to express a line's equation in a two-dimensional coordinate plane. The point-slope form, slope-intercept form, and general or standard form of the equation of a line are the three most often used techniques. The point-slope form, as its name implies, combines the straight-line slope with a line point. It is feasible to express the equations of infinite lines with a specified slope, but when we specify that the line passes through a certain point, we obtain a singular straight line.

y – y1 = m(x – x1) is the equation of a straight line's point slope from the formula.

Here, m equals the slope of the line at point (x1, y1), where the supplied line passes.

The given points:

x y

-16 -85

-8 -65

0 -45

8 -25

16 -5

So from here have to find the slope:

For slope we know the formula:

y2 – y1 = m (x2 – x1)

\(m=\frac{y_2-y_1}{x_2-x_1}\)

om table we take points [5,60],[10,75]

Now substitute in the formula:

\(\begin{aligned}&m=\frac{75-60}{10-5} \\&m=\frac{15}{5} \\&m=3\end{aligned}\)

for cross-check we can take another points:[15,90],[20,105]

\(\begin{aligned}&m=\frac{105-90}{20-15} \\&m=\frac{15}{5} \\&\mathrm{~m}=3\end{aligned}\)

Therefore, the slope of the line is m =3.

now we substitute m and point (5,60) in the equation: y – y1 = m (x – x1)

Therefore,

The equation of the line in a point-slope form that passes through the given points in the table:

y-60=3(x-5)

y=3x-15+60

y=3x+45

Write the equation in slope intercept form as:

y=mx+b

Now use the slope and point (5,60) to find the y-intercept.

y=mx+b

60=3(5)+b

b=60-15

b=45

Hence, the equation of the line is y= 3x+45.

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Answer: 99/130

Payment made by any method except credit card is 95+4=99 and altogether there is three payment method including a credit card which sums up to 130.

So the probability is 99/130.

Answer:

  q = 250,000·(0.6^t)

Step-by-step explanation:

You want an equation that models the graph of an exponential function that has an initial value of 250,000 and a value of 150,000 after 1 week.

An exponential function has the form ...

  q = a·b^t

where 'a' is the initial value, and 'b' is the decay factor over a period of one time unit of t.

The graph with this problem shows the initial value (for t=0) to be a=250,000. The decay factor will be ...

  b = 150,000/250,000 = 3/5 = 0.6

Then the exponential function can be written as ...

  q = 250000·(0.6^t) . . . . . . where t is in weeks

Answer:

25 units

Step-by-step explanation:

TR = TQ

2x + 10 = 18

2x = 8

x = 4

RS = QS

RS = 9x - 11

RS = 9(4) - 11

RS = 25

Simplifying the linear equation 4a + 7 when a= 1/2 is 9

Linear equation is an equation in whi8ch the highest power of the variable is 1

From the linear equation, 4a + 7 when a = 1/2

By substituting for a in the equation

=4(1/2) + 7

By expanding the bracket

=(4x1/2) + 7

=4/2+7

=2+7

=9

Hence, The final answer to the linear equation 4a + 7 when a= 1/2 = 9

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Answer:\(\color{iron}{}\)

Amplitude:

\(\color{iron}{5π/4}\)

Period:

\(\color{iron}{3.14 x (4)²}\)

\(\color{iron}{3.14 x 16}\)

\(\color{iron}{A=5.4π}\)

The condition for a portfolio to be self-financing in the Black-Scholes model is that the portfolio's value does not change due to trading (buying or selling) costs or external cash flows. In other words, the portfolio's value remains constant over time, excluding the effects of the underlying assets' price changes.

For the given portfolio, a = -t (units of the stock) and b = S_t (units of the savings account). To determine if this portfolio is self-financing, we need to check if its value remains constant over time. Using Ito's lemma, we can express the value of the portfolio as:

d(Vt) = a_t * d(St) + b_t * d(Ct)

Substituting the values of a and b, we have:

d(Vt) = -t * (2St * dt + 4St * dBt) + S_t * d(t)

Simplifying this expression, we get:

d(Vt) = -2tSt * dt - 4tSt * dBt + S_t * dt

The portfolio is self-financing if d(Vt) = 0. However, in this case, we can see that the terms involving dBt do not cancel out, indicating that the portfolio is not self-financing.

Girsanov's theorem states that under certain conditions, it is possible to transform a Brownian motion under the real-world measure into a Brownian motion under an equivalent martingale measure (EMM). The EMM is a probability measure under which the discounted asset prices are martingales. By applying Girsanov's theorem or alternative techniques, we can derive the expression for St, the stock price, under the EMM. Unfortunately, without further information or specifications, it is not possible to provide the specific expression in this case.

To determine the price Ct of the call option on the stock at time t ≤ 2, with an exercise price K = 1 and expiration date T = 2, additional information or an appropriate result is required. Without specific details, such as the volatility of the stock or the risk-free interest rate, it is not possible to provide an expression for Ct.

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Answer:

2:45 p.m.

Step-by-step explanation:

60 miles per hour for 3 hours

time: 12:30

miles driven: 180

45 minutes for lunch

time: 1:15

miles driven: 180

60 miles an hour till she hits 270

270-180=90

90 miles = 1.5 hours of driving

1.5 hours plus 1:15 = 2:45

Answer:

Step-by-step explanation:

2x-3

2(21)-3

42=3

39

Answer:

its 5

3(2x-3)=21

6x-9=21

6x=30

x=5

Answer:

a) \(\overrightarrow{PQ} = (8,8, 2)\) or \(\overrightarrow{PQ} = 8\,i + 8\,j + 2\,k\), b) The magnitude of segment PQ is approximately 11.489, c) The two unit vectors associated to PQ are, respectively: \(\vec v_{1} = (0.696,0.696, 0.174)\) and \(\vec v_{2} = (-0.696,-0.696, -0.174)\)

Step-by-step explanation:

a) The vectorial form of segment PQ is determined as follows:

\(\overrightarrow {PQ} = \vec Q - \vec P\)

Where \(\vec Q\) and \(\vec P\) are the respective locations of points Q and P with respect to origin. If \(\vec Q = (13,13,3)\) and \(\vec P = (5,5,1)\), then:

\(\overrightarrow{PQ} = (13,13,3)-(5,5,1)\)

\(\overrightarrow {PQ} = (13-5, 13-5, 3 - 1)\)

\(\overrightarrow{PQ} = (8,8, 2)\)

Another form of the previous solution is \(\overrightarrow{PQ} = 8\,i + 8\,j + 2\,k\).

b) The magnitude of the segment PQ is determined with the help of Pythagorean Theorem in terms of rectangular components:

\(\|\overrightarrow{PQ}\| =\sqrt{PQ_{x}^{2}+PQ_{y}^{2}+PQ_{z}^{2}}\)

\(\|\overrightarrow{PQ}\| = \sqrt{8^{2}+8^{2}+2^{2}}\)

\(\|\overrightarrow{PQ}\|\approx 11.489\)

The magnitude of segment PQ is approximately 11.489.

c) There are two unit vectors associated to PQ, one parallel and another antiparallel. That is:

\(\vec v_{1} = \vec u_{PQ}\) (parallel) and \(\vec v_{2} = -\vec u_{PQ}\) (antiparallel)

The unit vector is defined by the following equation:

\(\vec u_{PQ} = \frac{\overrightarrow{PQ}}{\|\overrightarrow{PQ}\|}\)

Given that \(\overrightarrow{PQ} = (8,8, 2)\) and \(\|\overrightarrow{PQ}\|\approx 11.489\), the unit vector is:

\(\vec u_{PQ} = \frac{(8,8,2)}{11.489}\)

\(\vec u_{PQ} = \left(\frac{8}{11.489},\frac{8}{11,489},\frac{2}{11.489} \right)\)

\(\vec u_{PQ} = \left(0.696, 0.696,0.174\right)\)

The two unit vectors associated to PQ are, respectively:

\(\vec v_{1} = (0.696,0.696, 0.174)\) and \(\vec v_{2} = (-0.696,-0.696, -0.174)\)