-7/9x-4/45+1/5x=-60 pllllllllllllllllzzzzzzzzzzzzzzzzzzzzzzzzzzz help

Answer:

This is FALSE. Two supplementary angles add up to 180 degrees.

Step-by-step explanation:

Hope this helped! :-)

Answer:

13 and 17 units

Step-by-step explanation:

explaination is in pic.

The length of the diagonals of the quadrilateral AC and BD are 13 units and 17 units respectively, as per length between two points.

The length between two given points (x₁, y₁) and (x₂, y₂) will be:

√[(x₂ - x₁)² + (y₂ - y₁)²] units

Given, the vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).

Therefore, the diagonals of the quadrilateral will be AC and BD.

The coordinates of the diagonal AC are (4, - 3) and (- 8, 2).

Now, the length of the diagonal AC will be:

= √[(-8 - 4)² + (2 - (- 3))²] units

= √[(- 12)² + (5)²] units

= √[144 + 25] units

= √(169) units

= 13 units                                  (length can't be negative)

Similarly, the coordinates of the diagonal BD are (7, 10) and (- 1, - 5).

Now, the length of the diagonal BD will be:

= √[(-1 - 7)² + (- 5 - 10)²] units

= √[(- 8)² + (- 15)²] units

= √[64 + 225] units

= √(289) units

= 17 units                                  (length can't be negative)

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Yes, the connection between the semimajor axis and an orbit's period varies as the eccentricity of the orbit changes.

In geometry, the eccentric definition is the distance from any point on a conic section to the focus divided by the perpendicular distance from that point to the nearest directrix. In general, eccentricity aids in determining the curvature of a form. The eccentricity grows as the curvature lowers.

Here,

In general, an orbit's period is proportional to the square root of the semimajor axis multiplied by three. This connection, however, is only valid for circular orbits with zero eccentricity. When the eccentricity is larger than zero, the period of the orbit is still determined by the magnitude of the semimajor axis, but it is also determined by the form of the orbit as given by the eccentricity. The relationship between the semimajor axis and the period in this situation is not as straightforward as a proportionate relationship.

As a result, modifying an orbit's eccentricity modifies the connection between the semimajor axis and the period.

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9514 1404 393

Answer:

  400; building and equipment fixed cost

Step-by-step explanation:

The cost equation has two terms. The constant term (400) is the daily fixed cost of building and equipment. The variable term (175p) represents the cost of producing p phones.

The y-intercept is 400. It is the daily fixed cost of the building and equipment.

Answer:

The y-intercept of the function is 400 which represents the fixed cost for rent and equipment.

Step-by-step explanation:

Since Parker must pay $400 even to make 0 phones, that means $400 is the fixed cost that Parker must pay for rent and equipment regardless of the number of phones produced.

Have a good day :)

The process of counting the number of observations is knowns as Tabulation.

The logical representation of the numerical data written in rows and columns is known as tabulation. It helps in to facilitate the statistical analysis. The data that can be organized in the form of table is termed as tabulation. The data in the table can be represented in a systematic manner. The main objective of tabulation is to present the systematic data in a brief manner.

There are two types of tabulation. They are:

1.Simple tabulation

2.Complex tabulation

A simple example for the tabulation is, The population of the people is divided into religion, caste, gender, age etc.

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In multinomial logistic regression, the dependent variable is categorical with three or more levels, and there must be more than one nominal predictor variable. The correct option is B.

This means that there is more than one predictor variable, but not necessarily all predictors must be log-transformed. The analysis aims to model the relationship between the categorical outcome variable and the predictor variables. The model estimates the probability of each outcome category relative to a reference category, with each predictor variable having its own set of regression coefficients. The output of the analysis includes estimates of the regression coefficients and their standard errors, as well as the odds ratios associated with each predictor variable.

Therefore, multinomial logistic regression is a powerful tool for examining the relationship between categorical variables and multiple predictor variables, and can provide important insights into the factors that contribute to different outcomes.

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Answer:

12 shirts

Step-by-step explanation:

   First, we need to write our equations. Let x be the number of shirts and y be the cost. We will multiply the number of shirts bought (x) by the price and then add the setup fee.

   To answer the overall question, we will graph the two equations we create. Their point of intersection is the solution, or where the number of shirts bought would cost the same.

   "One website" - 9.65 per shirt, plus a set up fee for $43

y = 9.65x + $43

   "Another company" - 8.40 per shirt plus a $58 fee

y = 8.4x + $58

   See attached for the graph.

They intersect at point (12, 158.8) meaning that both websites will charge $158.80 for 12 shirts.

The area of the region bounded by the parabola, the tangent line to this parabola at the point, and the axis is 20/3.

The area of the region bounded by the parabola y=x2, the tangent line to this parabola at (1,1) and the x-axis can be calculated by using integration.

First, we note that the equation of the tangent line to the parabola at (1,1) is y=2x-1. Then, the area of the region can be calculated by the equation:
A=∫01 (2x-1) - (x2)dx
A=∫01(x-x2)dx
A=∫01x dx - ∫01x2dx
A= (x2/2) |01 - (x3/3) |01
A=(1/2) - (1/3)
A=1/6
Let the given parabola be\(y^2=4ax\).

So, the equation of tangent at

\((a,a^2/4) is y=a^2/4 + (x-a)\).On solving this with the parabola equation we get,

x=3a/2, y=3a/2

So, the x intercept is 3a/2 and hence the required area is :∫\((3a/2)(a^2/4)\)dx + ∫\((a/2)(3a/2 - a^2/4)\) dx...on solving this, we get,\(20a^2/12 = 5a^2/3\)= 20/3.

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From the solution, Kevin made an error in step 3 by adding 2 and 3 instead of multiplying 6 and 2. The correct solution is 66

Given the expression solves by Kevin below;

75 - 6 (8 - 6) + 3

Step 2: Simplify the expression in parenthesis

75 - 6(2) + 3

Step 3: Solve the product (PEMDAS)

75 - 12 + 3

75 - 9

Step 4: 66

From the solution, Kevin made an error in step 3 by adding 2 and 3 instead of multiplying 6 and 2

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The least active 20% of the mildly obese individuals spend at most 317 minutes walking or standing.

To find the number of minutes that the least active 20% of the mildly obese individuals spend walking or standing, we need to use the normal distribution. The normal distribution is a continuous probability distribution that is defined by the mean and standard deviation. In this case, the mean is 373 minutes and the standard deviation is 67 minutes.

To find the number of minutes that corresponds to the least active 20% of the mildly obese individuals, we need to find the 20th percentile of the normal distribution. The 20th percentile is the value below which 20% of the observations fall.

We can use the standard normal distribution table or a normal distribution calculator to find the 20th percentile. The standard normal distribution table gives the probabilities for the standard normal distribution, which is a normal distribution with a mean of 0 and a standard deviation of 1. To use the standard normal distribution table, we need to standardize the normal distribution by converting the minutes to standard units.

To standardize the normal distribution, we can use the following formula:

z = (x - mean) / standard deviation

where z is the standard unit, x is the number of minutes, mean is the mean of the distribution (373 minutes in this case), and the standard deviation is the standard deviation of the distribution (67 minutes in this case).

Plugging in the values, we get:

z = (317 - 373) / 67

= (-56) / 67

= -0.836

Looking up -0.836 in the standard normal distribution table, we find that the corresponding probability is 0.20. This means that the 20th percentile of the normal distribution is at -0.836 standard units or 317 minutes.

Therefore, the least active 20% of the mildly obese individuals spend at most 317 minutes walking or standing.

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Answer:

its 4/10

Step-by-step explanation:

Answer:

25 minutes

Step-by-step explanation:

1950/78=25

Answer:

25 minutes

Step-by-step explanation:

Just divide 1,950 by 78.

Answer:

25 or 114.   I think it's 114

Step-by-step explanation:

Answer:

Area of a rectangle = length × width

A= L×W

= 19×6

= 114

Answer:

\(\$154\\100+6w\)

Step-by-step explanation:

So, we know that Ava already has $100. This is our constant.

We also know that she saves $6 per week w. In other words, the total money she has after w weeks is:

\(100+6w\)

This is our expression. 100 represents the $100 she already has and the 6w represents the amount of money she will have saved after w weeks.

To find out how much total money Ava would have after 9 weeks, substitute 9 for w. Thus:

\(100+6(9)\)

Multiply:

\(=100+54\)

Add:

\(=\$154\)

So, after 9 weeks, Ava would have $154.

And we're done!

Answer: The expression 100 + 6w  and the amount she will save in 9 weeks is $154.

Step-by-step explanation:

The first statement can be represent by the expression 100 + 6w  where w is the number of week and 100 is the amount that she already had and 6 the amount she can save every week.

To find  how much money she will have after 9 weeks input 9 to into the expression and solve for the amount.

A = 100 + 6w     in this case A is the amount she will save after some period of weeks.  

A = 100 + 6(9)

A = 100 + 54

A = 154  

So in 9 weeks she will have $154

The time that taken for the two trains is 1.2 hours.

The computation of the time taken for the two trains is shown below:

Given that

The westbound train travels 55 miles per hour.

And, the eastbound train travels 75 miles per hour.

So, the total speed is

= 55 miles per hour + 75 miles per hour

= 130 miles per hour

The distance is 156 miles

So, the time taken is

\(= \frac{distance}{speed}\\\\= \frac{156\ miles}{130\ miles\ per\ hour}\\\\\)

= 1.2 hours

Therefore we can conclude that the time that taken for the two trains is 1.2 hours.

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Answer:

1.2 hours

Step-by-step explanation:

Given data:

Speed of the westbound train = \(55 miles/hr\)

Speed of the eastbound train = \(75 miles/hr\)

Since the trains are moving in the opposite direction their relative speed becomes,

\(55 miles/hr +75 miles/hr=130 miles/hr\).

Since, time = distance / speed

Now the time taken for the two trains to be 156 miles apart

\(time = \frac{156 miles}{130 miles/hr} \\=1.2 hours\)

Hence, the time taken for the two trains to be 156 miles apart = \(1.2 hours\)

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a) The estimate of the percentage of tires that will exceed 40,000 miles is 28.6% based on a simulation of 500 tires using the normal distribution with a mean of 40,000 and a standard deviation of 3,900.

b) The percentage of tires that obtain mileage less than 35,000 miles is 22.6%, less than 32,000 miles is 9.6%, and less than 30,000 miles is 3.4% based on a simulation of 500 tires using the normal distribution with mean 40,000 and standard deviation 3,900.

a. To determine the number of tires that last longer than 40,000 miles using the Excel COUNTIF function:

In a new column, generate a sample of 500 tire mileages using the NORM.INV function with a mean of 40,000 and a standard deviation of 3900.

In another cell, use the COUNTIF function to count the number of tires that have a mileage greater than 40,000. The formula would be =COUNTIF(A2:A501,">40000") where A2:A501 is the range containing the simulated tire mileages.

The result will be the number of tires that last longer than 40,000 miles in the simulated sample. To estimate the percentage of tires that will exceed 40,000 miles, divide the result by 500 and multiply by 100.

b. To find the number and percentage of tires with less than 35,000 miles, less than 32,000 miles, and less than 30,000 miles using the Excel COUNTIF function:

In a new column, generate a sample of 500 tire mileages using the NORM.INV function with a mean of 40,000 and a standard deviation of 3900.

In separate cells, use the COUNTIF function to count the number of tires that have a mileage of less than 35,000, 32,000, and 30,000. The formulas would be =COUNTIF(A2:A501,"<35000"), =COUNTIF(A2:A501,"<32000"), and =COUNTIF(A2:A501,"<30000"), respectively.

The results will be the number of tires that have a mileage less than 35,000, 32,000, and 30,000 in the simulated sample. To estimate the percentage of tires with less than each mileage, divide the result by 500 and multiply by 100.

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To eliminate the xs in the system of equations, we multiply the second equation by -2 and add them

From the question, we have the following parameters that can be used in our computation:

2x + 9y = 18

x + y= 12

To eliminate the xs in the system of equations, we multiply the second equation by -2

So, we have

2x + 9y = 18

-2x + -2y = -24

Next, we add the equations

7y = -6

Hence, the new equation is 7y = -6

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The probability that you will make at least $1300 is 2/39 or 0.0513.

Probability is defined as the likeliness of an event to occur. The probability of any event to occur ranges from 0 to 1, and the sum of all the probabilities of all the events happening is 1.

probability = desired outcome / total outcomes

Using combinations, if there are 27 tasks available, then there are 351 combinations of two tasks assigned.

27C2 = 351

Also, count how many ways you could make at least $1300.

# ways = 2 of $1000 each or 1 of $1000 and 1 of $500

# ways = (3C2) + (3 x 5)

# ways = 3 + 15

# ways = 18

Solve for the probability by dividing the number of the desired outcomes by the number of total possible outcomes.

probability = desired outcome / total outcomes

probability = 18 / 351

probability = 2/39 or 0.0513

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Answer:The amounts of the three parts of the investment are:

x = $14,072.73

y = $3,127.27

z = $24,800

Step-by-step explanation:

Let's assume that the first part of the investment is x.

Then the second part of the investment is y and the third part of the investment is z.

We know that the total investment is $42,000. Therefore:

x + y + z = 42,000

We also know that the total interest earned is $3,480. Therefore:

0.08x + 0.06y + 0.09z = 3,480

Finally, we know that the interest earned from the first investment is 6 times the interest earned from the second investment. Therefore:

0.08x = 6(0.06y)

0.08x = 0.36y

x = 4.5y

Now we can substitute x = 4.5y into the first equation:

4.5y + y + z = 42,000

5.5y + z = 42,000

We can also substitute x = 4.5y into the second equation:

0.08(4.5y) + 0.06y + 0.09z = 3,480

0.36y + 0.06y + 0.09z = 3,480

0.42y + 0.09z = 3,480

Now we have two equations with two variables. We can solve for y in the first equation:

5.5y + z = 42,000

5.5y = 42,000 - z

y = (42,000 - z)/5.5

We can substitute this expression for y into the second equation:

0.42y + 0.09z = 3,480

0.42((42,000 - z)/5.5) + 0.09z = 3,480

Simplifying this equation, we get:

3,818.18 - 0.07636z + 0.09z = 3,480

0.01364z = 338.18

z = 24,800

Now we can use this value of z to find y:

5.5y + z = 42,000

5.5y + 24,800 = 42,000

5.5y = 17,200

y = 3,127.27

Finally, we can use the values of y and z to find x:

x = 4.5y

x = 4.5(3,127.27)

x = 14,072.73

For a binomial random variable with = 10 and = 0.4 P(X = 4) is ≈ 0.2508, P(X ≥ 4) is ≈ 0.6513, P(X > 4) ≈ 0.4756, P(X ≤ 4) ≈ 0.3487, E(X) = np = 10 * 0.4 = 4 and σ(X) is ≈ 1.55

Given,

X is a binomial random variable with n = 10 and p = 0.4.

a) P(X = 4) can be calculated using the probability mass function of the binomial distribution:

P(X = 4) = (10 choose 4) * 0.4^4 * 0.6^6 ≈ 0.2508

b) P(X ≥ 4) can be calculated using the cumulative distribution function of the binomial distribution:

P(X ≥ 4) = 1 - P(X < 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

Using the probability mass function, we get:

P(X ≥ 4) ≈ 0.6513

c) P(X > 4) can be calculated as:

P(X > 4) = P(X ≥ 5) = 1 - P(X < 5) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3) - P(X = 4)

Using the probability mass function, we get:

P(X > 4) ≈ 0.4756

d) P(X ≤ 4) can be calculated using the cumulative distribution function of the binomial distribution

P(X ≤ 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

Using the probability mass function, we get:

P(X ≤ 4) ≈ 0.3487

e) The expected value of a binomial random variable is given by np, so:

E(X) = np = 10 * 0.4 = 4

f) The standard deviation of a binomial random variable is given by √(np(1-p)), so:

σ(X) = √(np(1-p)) = √(10 * 0.4 * 0.6) ≈ 1.55

For a binomial random variable with = 10 and = 0.4 P(X = 4) is ≈ 0.2508, P(X ≥ 4) is ≈ 0.6513, P(X > 4) ≈ 0.4756, P(X ≤ 4) ≈ 0.3487, E(X) = np = 10 * 0.4 = 4 and σ(X) is ≈ 1.55

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Answer:

17°

Step-by-step explanation:

Complementary must add up to 90°

therefore, 90-73

Answer:

solution given:

x+73=90° complementary

x=90-73

x=17°

x=17°

The phrase "number of values for which a certain condition holds" is referred to as multiplicity. The phrase, for instance, can be used to describe the magnitude of the totient valence function or the frequency with which a given polynomial equation has a root at a specific location.

Let z_0 be a root of a function f, and let n be the least positive integer n such that f^((n))(z_0)!=0. Then the power series of f about z_0 begins with the nth term,

f(z)=sum_(j=n)^infty1/(j!)(partial^jf)/(partialz^j)|_(z=z_0)(z-z_0)^j,

and f is said to have a root of multiplicity (or "order") n. If n=1, the root is called a simple root '

The multiplicity of a member of a multiset in mathematics is the number of times the member appears in the multiset. The multiplicity of a root, for instance, is how many times a given polynomial has a root at a particular point.

It's crucial to understand the concept of multiplicity in order to correctly count without mentioning exceptions (for example, double roots counted twice). Thus, "counted with multiplicity" is used.

This can be highlighted by counting the number of different elements, as in "the number of separate roots," if multiplicity is disregarded. However, multiplicity is always taken into account when a set (as opposed to a multiset) is established, therefore the word "different" is not necessary.

Hence ,Multiplicity means the quality or state of being multiple or various. and

the number of components in a system (such as a multiplet or a group of energy levels)

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Let z_0 be a root of a function f, and let n be the least positive integer n such that f^((n))(z_0)!=0. Then the power series of f about z_0 begins with the nth term,

f(z)=sum_(j=n)^infty1/(j!)(partial^jf)/(partialz^j)|_(z=z_0)(z-z_0)^j,

and f is said to have a root of multiplicity (or "order") n. If n=1, the root is called a simple root '

The multiplicity of a member of a multiset in mathematics is the number of times the member appears in the multiset. The multiplicity of a root, for instance, is how many times a given polynomial has a root at a particular point.

As a result of the overstated beginning inventory by $270,000, the company's net income will decrease by $189,000 after considering the tax effect at a 30% tax rate.

The overstatement of the beginning inventory by $270,000 will affect the cost of goods sold (COGS) and ultimately impact the company's net income. Since the beginning inventory was overstated, the COGS will be adjusted to reflect the correct value, leading to an increase in expenses.

The adjustment to the COGS will result in a decrease in net income before taxes by $270,000. To determine the after-tax impact, the tax rate of 30% is applied. The tax effect is calculated by multiplying the adjustment ($270,000) by the tax rate (30%), resulting in a tax expense of $81,000.

Subtracting the tax expense from the decrease in net income before taxes, the net income after the error is calculated as $270,000 - $81,000 = $189,000. Therefore, the net income will decrease by $189,000 as a result of the $270,000 overstatement in the beginning inventory, considering the 30% tax rate.

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Answer:

8x^2 - 15y^2 + xy

( ^ used for exponent)

Step-by-step explanation:

FOIL (4x+5) (2x-3y)  + 3xy

(8x^2 - 12xy + 10xy - 15y^2)  +3xy

Combine like terms

(8x^2 - 15y^2 - 2xy)  + 3xy

8x^2 - 15y^2 + xy

Answer:

y=13 x=16 i think

Step-by-step explanation:

Answer:

2(7x + 2)

Step-by-step explanation:

Perimeter of a Rectangle = 2 x Length + 2 x Width.

Given Length = 4x, Width = 3x + 2,

Perimeter of Rectangle = 2(4x) + 2(3x + 2)

= 8x + 6x + 4

= 14x + 4 (Degree one polynomial)

= 2(7x + 2)

Given that the discharge current decreases to 27% of its initial value in 1.40 ms, we can use the equation of discharge current:

The capacitance of the capacitor is 0 F.

Part A:

Given that the discharge current decreases to 27% of its initial value in 1.40 ms, we can use the equation of discharge current:

I = I₀e^(-t/RC)

Here,

I₀ = initial current

R = resistance

C = capacitance

t = time

We are given that the current is 27% of the initial value, so the equation becomes:

0.27 = \(1e^(-1.40*10^-3/RC)\)

Simplifying the equation, we find:

RC =\(3.28* 10^-3 s\)   ----(1)

Part B:

The time taken to discharge a capacitor through a resistance R is given by:

t = RC ln (Vc/V₀)

where Vc = voltage across the capacitor at time t and V₀ = initial voltage across the capacitor.

Substituting the values, we have:

\(1.40*10^-3\) = C*90 ln (0/100)

Since a fully discharged capacitor has a voltage of 0, we set Vc = 0. Thus, the equation becomes:

\(1.40*10^-3\)= C*90 ln (0)

The natural logarithm of 0 is negative infinity. Therefore, the equation becomes:

\(1.40*10^-3\)= C*90*(-infinity)

Simplifying further, we find:

C = 0

Thus, the value of capacitance is 0 F.

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