Answer:
C. 100 J
Explanation:
If the 60 you wrote is the degree (60°)
Work done = forcexcos x distance
W= 100x cos 60 x2
W= 100 J
Answer:
100 J
Explanation:
Work done is the product of force and distance. The distance here is easy; it's just 2 m because it was pulled horizontally. The force, on the other hand, requires some more work, no puns intended!
We know the applied force is at an angle. Since work is parallel to the distance, the force used to calculate work must be parallel to the distance as well. This means we must use the horizontal component of the force. This, consequently, calls for the horizontal component of the angle.
Here, that horizontal component is the cosine of theta, cos θ, because the horizontal component must be adjacent to the angle. We know the angle in this case; θ is 60°. So, to find the component of the force parallel to the floor, we must multiply the total force by cos θ.
Here, θ = 60°, and the total force is 100 N. Therefore, the horizontal force equals 100 N × cos 60°. As for cos 60°, its value is 0.5. This means the horizontal force equals 100 N × cos 60° = 50 N.
From here, the work is that force, those 50 N, times the distance the box was pulled, 2 m. Therefore, work equals 50 N × 2 m = 50 N × m = 50 J.
In summary, the total work done is 50 J.
I hope you understand my explanation! Please have a great day!
Which of the following lines exists in a p-V diagram for water? O all of the mentioned O saturated liquid lines O saturated vapor line saturated solid line
In a p-V (pressure-volume) diagram for water, the line that exists is the saturated liquid line. This line represents the boundary between the liquid and vapor phases of water at equilibrium. It indicates the conditions at which water exists as a saturated liquid.
The saturated vapor line, on the other hand, represents the boundary between the liquid and vapor phases of water when it exists as a saturated vapor. The saturated solid line is not applicable in a p-V diagram for water, as water does not have a stable solid phase at standard atmospheric conditions.
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HELP HAVING BAD DAY NEED ANSWER QUICK!!!!
Jan can run at 7.5 m/s and Mary at 8.0 m/s. On a race track Jan is given
a 25 m head start, and the race ends in a tie. How long is the track?
Let's call the length of the race track as "x".
To solve for "x", we can use the formula:
\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)
Since the race ends in a tie, we know that Jan and Mary both took the same amount of time to run the race. Let's call this time "t".
For Jan:\(\implies \text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)
\(\implies t = \dfrac{x - 25}{7.5}\)
For Mary:\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)
\(\implies t = \dfrac{x}{8.0}\)
Since both expressions represent the same time, we can set them equal to each other and solve for "x":
\(\implies \dfrac{x - 25}{7.5} = \dfrac{x}{8.0}\)
Multiplying both sides by 60 (the least common multiple of 7.5 and 8.0) to get rid of the decimals:
\(\implies 8(x - 25) = 7.5x\)
\(\implies 8x - 200 = 7.5x\)
\(\implies 0.5x = 200\)
\(\implies x = 400\)
\(\therefore\) The length of the race track is 400 meters.
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A metal spoon is put in a cup of hot tea and then put it into the mouth. The spoon is not very hot, but the tea is much hotter. Why?
camel have humps why
Answer:
camels have humps to store fat which is then converted to energy when food is scarce ( the humps are not used for storing water )
Answer: camels have humps to store fat which is then converted to energy when food is scarce ( the humps are not used for storing water )
A 50.0 kg lead block initially at 15 °C is released from rest at the top of an inclined plane with a 10° angle above the horizontal. The inclined plane is 5.00 m long. The block reaches the bottom of the inclined with a speed of 2.20 m/s. How much work is done the friction force on the block? What is the change of temperature of the block? Assume that work done by the friction force equals by magnitude the amount of heat going into the block. CL = 130 J/kg °C
Given data:
* The mass of the lead is m = 50 kg.
* The angle of the inclined plane with the horizontal is,
\(\theta=10^{\circ}\)* The length of the inclined plane is L = 5 m.
* The speed of the lead at the bottom of the plane is v = 2.2 m/s.
* The initial temperature of the lead is,
\(T_i=15^{\circ}\text{ C}\)* The specific heat of lead is,
\(c_L=130J/kg^{\circ}C\)Solution:
(a). The kinetic energy of the lead at the bottom of the inclined plane is,
\(\begin{gathered} K=\frac{1}{2}mv^2 \\ K=\frac{1}{2}\times50\times2.2^2 \\ K=121\text{ J} \end{gathered}\)The diagrammatic representation of the given case is,
From the diagram, the initial height of the block is,
\(\begin{gathered} \sin (\theta)=\frac{h}{L} \\ h=L\sin (\theta) \end{gathered}\)Substituting the known values,
\(\begin{gathered} h=5\times\sin (10^{\circ}) \\ h=0.87\text{ m} \end{gathered}\)The potential energy at the top of the inclined plane is,
\(U=\text{mgh}\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} U=50\times9.8\times0.87 \\ U=426.3\text{ J} \end{gathered}\)The lead block is initially at rest at the top of the inclined plane, thus, the kinetic energy at the top of the inclined plane is zero.
The net energy at the top of the inclined plane is,
\(\begin{gathered} E_i=U+K_i \\ E_i=U+0 \\ E_i=426.3\text{ J} \end{gathered}\)The height of the lead block at the bottom of the inclined plane is zero, thus, the potential energy at the bottom of the inclined plane is zero.
The net energy at the bottom of the inclined plane is,
\(\begin{gathered} E_f=U_f+K \\ E_f=0+121 \\ E_f=121\text{ J} \end{gathered}\)Thus, the energy loss due to the friction is,
\(\begin{gathered} E_f-E_i=121-426.3 \\ E=-305.3\text{ J} \end{gathered}\)Here, the negative sign indicates the loss of energy,
The work done by the frictional force is equal to the amount of energy loss during the motion of the lead block down the inclined plane.
Thus, the work done by the friction force on the lead is 305.3 J.
(b). The energy loss takes place in the form of heat.
The amount of heat produced in terms of the mass, temperature, and specific heat is,
\(Q=mc_L(T_f-T_i)\)where Q is the amount of heat produced, T_f is the final temperature and T_i is the initial temperature,
Substituting the known values,
\(\begin{gathered} 305.3=50\times130\times(T_f-15) \\ 305.3=6500T_f-97500 \\ 6500T_f=305.3+97500 \\ 6500T_f=97805.3 \end{gathered}\)By simplifying,
\(\begin{gathered} T_f=\frac{97805.3}{6500} \\ T_f=15.05^{\circ}\text{C} \end{gathered}\)Thus, the final temperature of the lead block is 15.05 degrees celsius.
What is the magnitude of the force provided by the third rope (A to F), in terms of theta? F_AB cos(θ) 2F_AB cos(θ) 2F_AD sin(θ) F_AB sin(θ)
The magnitude of the force provided by the third rope (A to F), in terms of theta 2FABSin(θ).
What is magnitude example?Magnitude is the size of something. For example, in the case of speed, a car is moving faster than a bike. In this instance, the magnitude of the speed of the car is higher than that of the bike. It tells the direction or size that is absolute or relative in which an object travels in the sense of motion.
What is magnitude in physics?In physics, magnitude is defined simply as “distance or quantity.” It depicts the absolute or relative direction or size in which an object moves in the sense of motion. It is used to express the size or scope of something.
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if the earht rotates at roughly 1,000 miles per hour why do we not land 1000 miles away when we jump up
While the Earth rotation is substantial in terms of speed, the effects of gravity and our own inertia dominate the motion when we jump, we do not land 1000 miles away due to our inertia and the gravitational force acting on us.
The Earth's rotation does indeed cause the surface to move at a high speed, approximately 1000 miles per hour at the equator. However, when we jump up, we are already in motion with the Earth and possess the same rotational speed. According to the principle of inertia, an object in motion tends to stay in motion unless acted upon by an external force.
When we jump, the only significant external force acting on us is gravity. Gravity pulls us back towards the Earth's surface, causing us to fall back down. As we jump, our horizontal motion due to the Earth's rotation remains relatively unchanged, and we maintain our position relative to the Earth's surface. The gravitational force acts downward and alters our vertical motion, bringing us back to the ground close to our starting point.
While the Earth's rotation is substantial in terms of speed, the effects of gravity and our own inertia dominate the motion when we jump, preventing us from landing significantly displaced from our original position.
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An electrical current has a low voltage and a low amperage. What does the amperage represent in the electrical current?
The amperage represents the rate at which electric charge flows through a conductor.
What is amperage?
Amperage is a measure of electrical current, or the rate at which electrical charge flows through a circuit. It is measured in units of amps (A). Amperage is related to voltage and resistance in an electrical circuit, and can be calculated using Ohm's law. Amperage is important to consider when sizing electrical components and wiring for a circuit, as too much amperage can cause damage to the components.
The amperage, also known as current, represents the rate at which electric charge flows through a conductor. It is measured in amperes (A) and is a measure of the quantity of electric charge that passes through a given point in a circuit per unit of time. In other words, amperage is a measure of how many electrons are flowing through a wire at a given moment. A low amperage means that there is a small amount of electric charge flowing through the conductor. This could be because the resistance of the conductor is high, or because the voltage of the power source is low. A low voltage, on the other hand, means that there is a small potential difference between two points in a circuit, which means that the electric charge is not being pushed as hard and may not be flowing as quickly.
Therefore, it represents the rate at which electric charge flows through a conductor.
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a ball player catches a ball 3.40 ss after throwing it vertically upward. part a with what speed did he throw it?
The speed of the ball that the ball player throw is 16.66 m/s.
The ball player throws a ball vertically upward and then catches the ball. It means, the ball doing vertical motion travel upward to the highest point and then goes down until the ball player catches it. The trajectory of the ball as it goes up is symmetrical to the trajectory of the ball as it goes down.
The time to travel upward is equal to the time to travel downwardtravel time = travel time upward + travel time downward
t = t₁ + t₂
3.40 = t₁ + t₁
3.40 = 2t₁
t₁ = 3.40 ÷ 2
t₁ = 1.70 s
When the ball travels upward, non-uniform motion applies
v₂ = v₁ + at
a = the accelerationv₂ = v₁ + at₁
0 = v₁ + (- 9.8 × 1.70)
0 = v₁ - 16.66
v₁ = 16.66 m/s
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IWhat is a hypothesis?
Answer:
a hypothesis is a explanation made on the basis of limited evidence
Explanation:
Answer:
an hypothesis is an educated guess based on what you already know
Explanation:
hope this helps
The application of 16 Newtons of force to an egg results in the egg accelerating at 68.6 m/s^2 what is the mass of the egg? Round to the nearest hundredths
The mass of the egg = 0.23 kg
Explanation:The force, F = 16 N
The acceleration, a = 68.6 m/s²
The relationship between the force (F), acceleration (a), and mass (m) is:
F = ma
Substitute F = 16, a = 68.6, and solve for m
16 = 68.6m
m = 16/68.6
m = 0.23 kg
A bell hanging at the top of a tower has 8,550 J of gravitational potential energy. It has a mass of 20 kg. If the bell falls to the ground so that all of its potential energy gets converted to kinetic energy, what will it's final velocity be?
The gravitational potential energy (PE) of an object is given by the formula:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point.
In this case, the bell has a PE of 8,550 J and a mass of 20 kg. We can rearrange the above formula to solve for the height h:
h = PE/(mg)
Substituting the given values, we get:
h = 8,550 J / (20 kg x 9.81 m/s^2) ≈ 43.4 meters
This is the height from which the bell falls. When the bell falls to the ground, all of its PE is converted to kinetic energy (KE). The formula for KE is:
KE = (1/2)mv^2
where m is the mass of the object and v is its velocity.
Setting the PE equal to the KE, we get:
PE = KE
mgh = (1/2)mv^2
Simplifying and solving for v, we get:
v = √(2gh)
Substituting the values for g and h, we get:
v = √(2 x 9.81 m/s^2 x 43.4 m) ≈ 29.4 m/s
Therefore, the final velocity of the bell when it hits the ground is approximately 29.4 m/s.
The net force on a moving object suddenly becomes zero and remains zero. the object will:_________-
If the net force on an object becomes zero and remains zero, the object will continue to move at constant velocity.
The net force acting on a body is the addition or the resultant of all the forces acting on the body. When the net force acting on a body is more than zero, it causes motion, but when it is zero, the object will remain at rest or will continue moving with uniform velocity.
This is in line with Newton's first law of motion which states that "a body will continue in its state of rest or will continue to move with uniform velocity unless it is acted upon by a force".
Thus, when the net force on a moving body becomes zero, it will not slow down or speed up, it will continue to move at the same speed. An example of this is when the passengers of a moving car fall forward when the car suddenly comes to a stop.
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what is latent heat energy's definiton
7. Two carts are sitting on a frictionless track with a compressed spring between them. The sum of the masses of carts A and B is 1.5 kg. After the spring releases, Cart B has twice the speed of Cart A. What is the mass of each cart?
Answer:
Explanation:
Let mass of cart be m₁ and m₂
m₁ + m₂ = 1.5 kg
At the time of release , their momentum will be conserved
m₁ v ₁ = m₂ v₂
m₁ v ₁ = (1.5 - m₁ ) x 2 v₁
m₁ = 3 - 2m₁
3m₁ = 3
m₁ = 1 kg
m₂ = .5 kg
the amplitude of the electric field of an electromagnetic wave traveling in a vacuum is measured to be 4.8 ✕ 102 v/m. what is the amplitude of the magnetic field in this wave? t
To summarize, the amplitude of the magnetic field in the electromagnetic wave with an amplitude of 4.8 × 10^2 V/m is approximately 1.6 × 10^-6 T.
The amplitude of the magnetic field in an electromagnetic wave can be calculated using the relationship between the electric and magnetic fields in a vacuum. The amplitude of the magnetic field can be determined by dividing the amplitude of the electric field by the speed of light. In a vacuum, the speed of light is approximately 3.0 × 10^8 meters per second.
So, in this case, the amplitude of the electric field is given as 4.8 × 10^2 V/m. Dividing this value by the speed of light, we get:
Amplitude of magnetic field = (4.8 × 10^2 V/m) / (3.0 × 10^8 m/s)
Calculating this, we find that the amplitude of the magnetic field in this wave is approximately 1.6 × 10^-6 T (tesla).
To summarize, the amplitude of the magnetic field in the electromagnetic wave with an amplitude of 4.8 × 10^2 V/m is approximately 1.6 × 10^-6 T.
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How do you rationalize the tension being used in Tennis Racket strings using the concept of impulse and momentum?
Answer:
The momentum, ΔP, and therefore, kinetic energy given to the ball in a serve is the result of the product of the tension force, 'F', in the string and the time of contact, Δt, between the ball and the string
ΔP = F × Δt
Explanation:
The impulse, ΔP, is the produce of the force, 'F', applied to a body for a given period of time, Δt', that gives motion to the body, and it is equal to the change of momentum of the body
ΔP = F × Δt
The momentum, 'P', of a body is the product of the mass, 'm', of the body and its velocity, 'v'
P = m × v
Tension is the axial pulling force of a string
T = Axial Force, F\(_{axial}\)
The tension used in Tennis Racket strings is between 40 to 65 lbs.
When high tension is used in the string, the string is taut, and the contact duration between the Racket string and the ball is minimal, and the player needs to use more force to obtain a high momentum, and therefore, energy in the ball, which reduces control, and increase stress, as force is more emphasized
When low tension is used in the string, the Tennis Racket strings are more elastic. During a serve, the ball pushes the strings further back into the racket, such that the ball spends more time in contact with the string, (Δt is larger), and therefore, the impulse, F·Δt = ΔP, given to the ball is larger, therefore, the ball has a larger change in momentum, and therefore more energy in the intended direction.
However, a very slackened string will increase the increase area and time (large Δt) of contact of the ball and the racket such that the force given to the ball, F = ΔP/(large Δt) is reduced and therefore reduce the likelihood of gaining points from a serve against an opponent with a much forceful return of a serve.
how much would a 55 kg person weigh on phobos? express your answer in newtons.
The weight on Phobos will be 0.3135 N
How much would a 55 kg person weigh on phobos?We know that weight is defined as:
W = mass*gravitational acceleration.
Here we know that the mass of the person is 55 kilograms, and we also know that the gravitational acceleration on phobos is:
g = 0.0057 m/s²
Then the weight will be
W = 55kg*0.0057 m/s² = 0.3135 N
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Guys if you see this please help me
7. Why are cooking pans made of aluminum? {Explain using the specific heat value of
aluminum} it conducts heat well high thermal energy
can a chemical change be undone?
Answer:
no
Explanation:
because it will bind together in the molecular level
Will give correct answer brainliest please help
Two cars are involved in a head-on collision in an alley. The driver of a car with mass,
ma = 1,200 kg claims to have been traveling west at via = 7 m/s. The driver of the
other car with mass, mb = 1,000 kg claims to have been traveling east at vib - 10
m/s. The investigating officer found that both cars were stuck together and traveled
with a common final velocity of 3 m/s, eastward, after the collision.
Assuming that at least one driver is correct, what does an application of the law of
conservation of momentum allow the officer to conclude about the accident?
The driver of the westbound car was moving significantly faster than reported.
Both drivers correctly reported their velocities at the time of the collision.
Either the driver of the westbound car overestimated his velocity or the driver of
the eastbound car underestimated his velocity,
KID Either the driver of the westbound car underestimated his velocity, or the driver
of the eastbound car overestimated his velocity.
Answer:
it is the 3rd answer choice
The correct assumption of the given situation is required.
The correct option is
Either the driver of the westbound car overestimated his velocity or the driver of the eastbound car underestimated his velocity,
\(m_a\) = Mass of west moving car = 1200 kg
\(m_b\) = Mass of east moving car = 1000 kg
\(v_{ia}\) = Velocity of west moving car = -7 m/s
\(v_{ib}\) = Velocity of east moving car = 10 m/s
v = Combined velocity of the cars = 3 m/s
From the conservation of momentum we get
\(m_av_{ia}+m_bv_{ib}=(m_a+m_b)v\\\Rightarrow 1200\times -7+1000\times10=(1000+1200)\times 3\\\Rightarrow 1600\neq 6600\)
So, either westward ( \(1000\times10\) ) moving car needs to have more velocity or eastward (\(1200\times -7\)) moving car needs to have less velocity.
Since, mass is constant only the velocity can be different.
The correct option is
Either the driver of the westbound car overestimated his velocity or the driver of the eastbound car underestimated his velocity.
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Which of the following statements regarding lightning strikes is correct?
Select one:
A. Victims who are struck by lightning often experience severe full-thickness burns.
B. Cervical spine fractures are the most common cause of lightning-related deaths.
C. The tissue damage pathway caused by lightning usually occurs through the skin. Incorrect
D. Lightning often results in a brief period of asystole that resolves spontaneously.
The correct statement regarding lightning is as follows: Victims who are struck by lightning often experience severe full-thickness burns (option A).
What is lightning?Lightning is an electrical discharge caused by imbalances between storm clouds and the ground, or within the clouds themselves.
Lightning strike is a lightning bolt, stroke of lightning, one of the events during an electrical storm when lightning strikes (an object on) the ground or an aircraft in flight.
Most deaths after lightning strikes occur either because of primary cardiac arrest or hypoxia-induced secondary cardiac arrest, however, survivors have experienced debilitating injuries, burns and ongoing disability, including symptoms like seizures and memory loss.
Therefore, severe full-thickness burns are the symptoms or signs of lightning strike.
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Normally, the air in the center of a Low-Pressure system would be warm.
A. Squeeze
C. Reverse direction
B. Evaporate into a liquid D. rise and form clouds
The air in the center of a Low-Pressure system: rises and forms clouds. The correct option is D.
In a low-pressure system, also known as a cyclone, the air in the center rises and forms clouds. Low-pressure systems are characterized by air that is less dense than the surrounding air, causing it to ascend. As the air rises, it expands and cools, leading to the condensation of water vapor and the formation of clouds.
The rising air in a low-pressure system creates an area of low atmospheric pressure at the surface. Air from surrounding areas with higher pressure flows towards the center to fill the void left by the rising air. This results in the convergence of air towards the center of the low-pressure system.
The rising motion and cloud formation in low-pressure systems are associated with unstable atmospheric conditions. These systems are often associated with weather phenomena such as rain, thunderstorms, and cyclones. The warm air rising in the center of a low-pressure system contributes to the development and intensification of these weather events. The correct option is D.
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solved the question belowCalculate the force of attraction between a cation with a valence of +3 and an anion with a valence of -2, the centers of which are separated by a distance of 2.8 nm.
F= _____Calculate the force of attraction between a cation( eV , N , J , nm ) Choose One
the attraction between a +3 valence cation and a -2 valence anion, whose centres are separated by a distance of 2.8 nm. The attraction between two cations is 1.76×10⁻¹⁰ forces.
given,
number of cations,n₁=3
number of anions,n₂=2
center distance between cation and anion,r=2.8 nm=2.8×10⁻⁹m
write the equation force of attraction:
\(F=\dfrac{kq_1q_2}{r^2}.\)..............(1)
Here,K is coulombs constant ,K=9×10⁹ Nm²/C²,q =n×e ,e is electronic charge,e=1.60×10⁻¹⁹ coulombs. the attraction between a +3 valence cation.
calculate the value of cation charge q₁
q₁=n₁×e
q₁=3×1.60×10⁻¹⁹
calculate the value of cation charge q₂
q₂=n₂×e
q₂=2×1.60×10⁻¹⁹
substitute the values in equation 1
\(F=\frac{(9*10^{9})*(3*1.602*10^{-19}) *(2*1.602*10^{-19} )}{(2.8*10^{-9})^{2} }\)
F=1.76×10⁻¹⁰
The force of attraction between cation is 1.76×10⁻¹⁰.
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Is this statement true or false?
Line spacing refers to the amount of space between each line in a paragraph.
true
false
Answer:
True
Explanation:
I just took the test and got 100
Felipe drives his car at a velocity of 28 m/s. He applies the brake, which slows the vehicle down at a rate of 6. 4 m/s2 and causes it to slow to a stop. How long does it take for the car to stop? Round your answer to the nearest tenth.
Hi there!
We can use the kinematic equation:
\(v_f = v_i + at\)
vf = final velocity (0 m/s, breaking to a stop)
vi = initial velocity (28 m/s)
a = acceleration (-6.4 m/s², breaking)
time (sec)
Plug in the given values and solve.
\(0 = 28 - 6.4t\\\\-28 = 6.4t\\\\\large\boxed{t = 4.375 s}\)
Why does the Sun appear white at noon?
In experiment 1, a student places a ball on a tee and hits the ball with the bat as hard as they can. In a second test, the same student hits the ball half as hard. Both times, the student measures how far the ball travels. In experiment 2, a student places 3 33 books on a rolling chair and gives the chair a push. They then place 10 1010 books on the chair, and the student gives the chair a push with the same force. Both times, the student measures how far the chair rolls. Which experiment is the better test of how force affects an object’s motion?
Experiment 2 is the better test of how force affects an object's motion.
Experiment 2 is the better test of how force affects an object's motion because it involves testing the effect of force on the motion of a heavier object, whereas in experiment 1, the force applied to the ball was only changed by half.
In experiment 2, the same force was applied to two different masses, allowing the student to compare the effect of force on different objects.
This is important because the mass of an object affects its motion.
Therefore, the results from experiment 2 will provide a better understanding of the relationship between force and motion, which is the goal of the experiment.
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The relationship between the equilibrant and the resultant vector is *
the equilibrant is equal in magnitude and in diredction
the equilibrant is equal in magnitude but opposite in direction
the equilibrant is different in magnitude and in direction
the equilibrant is different in magnitude but opposite in direction
Answer:
the equilibrant is equal in magnitude but opposite in direction.
Explanation:
In vector algebra, a resultant vector is a single vector that have the same effect as the effect of the net or algebraic sum of two or more vectors.
A resultant vector arises from finding the adding multiple vectors together.
When a group of vectors is replaced by a resultant vector, in order to keep the system of vectors at equilibrium, there is another vector which has the same magnitude as the resultant vector but acting in opposite direction to the resultant vector. This vector is called the equilibrant.