Answer:
A color of a star that has a surface temperature of 3000 K is red.
Explanation:
This color results from the star emitting more red light than blue light.
What is a star?
A star is a celestial body of hot plasma that emits light in the form of electromagnetic radiation. It is held together by its gravity and usually generates energy through nuclear fusion of hydrogen into helium. Stars vary in color, size, and luminosity as well as in their lifetime, activity, and composition.
Stars are classified according to their spectral type, luminosity class, and chemical composition. They are also grouped into clusters, galaxies, and other astronomical structures based on their spatial distribution, kinematics, and evolution.
What is the color of a star that has a surface temperature of 3000 K?
A star that has a surface temperature of 3000 K appears red. This color is due to the star emitting more red light than blue light. The color of a star is determined by its surface temperature, which is related to its spectral type. Hotter stars have higher surface temperatures and emit more blue and ultraviolet light, while cooler stars have lower surface temperatures and emit more red and infrared light.
The exact color of a star depends on its composition, age, and distance from Earth. In addition, the atmosphere of Earth and the interstellar medium can affect the apparent color of stars seen from our perspective.
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The image behind a convex mirror (radius of curvature = 68 cm) is located 22 cm from the mirror.(a) Where is the object located and(b) what is the magnification of the mirror? Determine whether the image is(c) upright or inverted and(d) larger or smaller than the object
(a) The object is located 44 cm from the convex mirror.
(b) The magnification of the mirror is -0.647.
(c) The image formed by the convex mirror is virtual and upright.
(d) The image formed by the convex mirror is smaller than the object.
Find the image is upright or inverted?To determine the location of the object and the characteristics of the image formed by a convex mirror, we can use the mirror formula and magnification formula.
(a) The mirror formula states that 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance. For a convex mirror, the focal length is half the radius of curvature, so f = 34 cm. We are given v = -22 cm (negative sign indicates a virtual image).
Plugging in these values, we can solve for u to find that the object is located 44 cm from the convex mirror.
(b) The magnification formula is given by m = -v/u, where m is the magnification. Substituting the known values, we find that the magnification is -0.647.
(c) Since the image distance is negative, the image formed by the convex mirror is virtual. The upright orientation means that the image is not inverted or flipped.
(d) The negative magnification indicates that the image is smaller than the object.
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What caused the need for topographic maps to be updated?
There is the need for topographic maps to be updated because it makes resources and environment monitoring more significant
What is a Topographic map?This is referred to as a type of map which shows the shape of the Earth's surface through the use of contour lines. The geographical representation is also important in the socio-economic development of a country or place.
In developing countries , there is the need to monitor the resources and environment due to different changes occurring as a result of high human activity influence such as mining, pollution etc in which the government has to discover methods to control it and avoid resources depletion.
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a resistor is made of a material that has a resistivity that is proportional to the current going through it. if the voltage across the resistor is doubled, what happens to the power dissipated by it?
If the voltage across the resistor is doubled, the power dissipated by it It increases by a factor of \(2^\frac{3}{2}\) .
The relationship between the material's resistivity and the current flowing through the resistor is linear.
ρ ∝ I
ρ=kI
Here,
Here, I is the current,
k is the constant, and
ρ is the material's resistivity.
Ohm's law states that a resistor's resistance and resistivity are directly inversely related.
So,
R∝ρ
R=kI
The initial power dissipated by the resistor is,
P=VI
Find the voltage across the resistor.
R=V/I
kI=V/I
V=kI²
V′=k(I′)² [V′=2V]
2V=k(I′)²
2kI²=k(I′)² [V=kI²]
√2I=I
I′ is the final current and
V′ is the final voltage.
Find the final power dissipated by the resistor.
P′=V′I′
P′=2V√2I
P′=2³⁺2VI [P=VI]
P′=2³⁺²P
Therefore, If the voltage across the resistor is doubled, the power dissipated by it It increases by a factor of \(2^\frac{3}{2}\) .
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1. In a discussion, outline elaboratively 5 of the 10 major external forces that affect organizations: economic, social, cultural, demographic, environmental, political, governmental, legal, technological, and competitive. (You may choose any 5 ) 2. I want you to tell me CONVINCINGLY, the importance of gathering competitive intelligence. 3. In business we are aware that economic factors have tremendous impacts in the various strategy applications. Name a few economic variables that we need to monitor. 4. Social, cultural, demographic, and environmental changes have a major impact on virtually all products, services, markets, and customers, that's a given, in your own opinionated words why is this so. 5. List 5 key external factors of your choice including both opportunities and threats you believe affect the firm and its industry. List the opportunities first and then the threats. 6. Explain your opinion on how to prioritize and determine a firm's internal weaknesses and strengths. 7. What do you understand about financial ratio analysis, what is it, and why is it so important in business. 8. A major responsibility of strategists is to ensure development of an effective external audit system. Why do you think this is so? Explain your opinion in this.
1. Five major external forces that affect organizations are economic, social, cultural, demographic, and technological. Economic factors such as inflation and interest rates can impact a company's profitability and purchasing power. Social factors like changing consumer preferences and lifestyles can influence demand for products and services.
Cultural factors like values and beliefs can shape consumer behavior and market trends. Demographic factors such as population size and age distribution can affect target markets.
Technological factors like advancements in automation or digitalization can disrupt industries and create new opportunities. These external forces shape the business environment and organizations must monitor and adapt to them to stay competitive.
2. Gathering competitive intelligence is crucial for businesses because it provides valuable insights about their competitors' strategies, strengths, weaknesses, and market position.
By understanding the competitive landscape, businesses can identify opportunities and threats, make informed decisions, and develop effective strategies.
Competitive intelligence helps businesses stay ahead of their competitors, anticipate market trends, identify emerging technologies, and improve their own products or services. It allows businesses to benchmark their performance, evaluate their competitive advantage, and identify areas for improvement.
Ultimately, gathering competitive intelligence empowers businesses to make proactive and strategic decisions that can lead to sustainable growth and competitive advantage.
3. In business, various economic variables need to be monitored as they have significant impacts on strategy applications. Some important economic variables include GDP (Gross Domestic Product), inflation rate, exchange rates, interest rates, consumer spending, unemployment rate, and industry-specific factors like raw material prices or energy costs.
Monitoring these variables helps businesses understand the overall economic conditions, identify market opportunities, and assess potential risks. For example, a high inflation rate may impact pricing strategies, while a favorable exchange rate can benefit export-oriented businesses.
By monitoring economic variables, businesses can adapt their strategies accordingly and make informed decisions to navigate the dynamic business environment.
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If I do 100 Joules of work to lift my backpack, then half of everything falls out so that I can lift it using half the force, how much work will I do to lift it the same distance?
50J work will do to lift it the same distance
How much energy is wasted during a fall?
When an object is falling freely, its velocity rises because of the acceleration caused by gravity. In the instance of a body that is falling freely, the kinetic energy thus rises while the potential energy falls as the height of the object decreases.
When an object is descending at its terminal velocity, the force of gravity and air resistance are equal, and the object no longer accelerates. The amount of labor done is equal to the sum of the object's displacement and the gravitational force. The modification of the object's potential energy brought on by gravity can also be used to calculate it.
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A swimming pool has a volume of 50 m’. A mass C (in kg) of chlorine is dissolved in the pool water. Starting at a time t = 0, water containing a con- centration of 0.1 C/V chlorine is pumped into the swimming pool at a rate of 0.02 m3/min, and the water flows out at the same rate. a) Present the differential equation for the chlorine mass Q(t). b) Find the solution Q(t) to this equation. 7.7 Exercises 289 c) What is the amount of the chlorine mass Q(t) after 2 hours? d) At which time is the chlorine mass in the pool 50% of the initial mass?
The differential equation for the chlorine mass Q(t) in the swimming pool is dQ/dt = (0.1C/V) - (Q/V)(0.02).
How can we express the chlorine mass Q(t) in the swimming pool over time?To determine the differential equation for the chlorine mass Q(t), we consider the rate at which chlorine is being pumped into and out of the swimming pool. The concentration of chlorine in the pool water is represented by C, and the volume of the pool is given as V = 50 m³. At a rate of 0.02 m³/min, water containing chlorine concentration 0.1 C/V is pumped into the pool, while water flows out at the same rate. This results in a differential equation where the rate of change of Q(t) with respect to time is equal to the inflow rate minus the outflow rate.
To solve this differential equation, we integrate both sides and apply the initial condition Q(0) = 0, since there is no initial chlorine mass in the pool. The solution to the equation is Q(t) = (0.02C/V)(1 - e^(-0.02t)), which gives us the expression for the chlorine mass Q(t) in terms of time t.
Now, to find the amount of chlorine mass Q(t) after 2 hours, we substitute t = 120 minutes into the solution equation and evaluate Q(t). Similarly, to determine the time at which the chlorine mass in the pool is 50% of the initial mass, we set Q(t) equal to 0.5C and solve for t. These calculations will provide the specific values requested in parts c) and d) of the question.
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what is photosynthesis ?
Answer:
Photosynthesis is the process by which plants use sunlight, water, and carbon dioxide to create oxygen and energy in the form of sugar.
Explanation:
Answer: Photosynthesis is something that a plant goes through. It takes the sunlight from the sun and turns it into oxygen, emitting it out into the atmosphere and giving us air to breathe.
Explanation:
Which of the following choices is an example of an allele?
a) blue eye-color gene
b) hair length
c) height and weight ratio
d) All of these choices are correct.
Answer:
Blue eye-color gene
1) A plane whose airspeed is 220 km/h heads due
north. It suddenly encounters a 150 km/h cross wind
blowing due east. What is the resulting velocity of
the plane with respect to the ground?
Answer:
=(220^2 +150^2)
/
put this on a square root
for you to get 266.2705391
round it to a whole number =266km/h
Explanation:
p
Joule is equal to:
Awatt x metre
B.watt x second
C. Newton x Metre
D. Both b and c
Answer:
The answer is ( D) i. e both b and c.
A man can use a snowblower to move snow in 5 minutes. If he moves it with a shovel, will take 20 minutes. He will use more power with which process?
Answer:
the second process of using the the shovel to move the snow as it takes a longer time meaning more power is expended
a 0.105-kg hockey puck moving at 30 m/s is caught and held by a 61-kg goalie at rest. with what speed does the goalie slide on the ice?
A 0.105-kg hockey puck moving at 30 m/s is caught and held by a 61-kg goalie at rest. The Speed at which the goalie slide on the ice is 0.0517 m/s.
A 0.105-kg hockey puck moving at 30 m/s is caught and held by a 61-kg goalie at rest.
The velocity of the goalie is given. In the problem, the momentum of the hockey puck is defined as 0.105 kg x 30 m/s = 3.15 kg*m/s.
The law of conservation of momentum claims that the sum of the momenta of two objects is conserved throughout the collision.
Momentum is always conserved, but the total energy in the system is not (since some energy is lost as sound, heat, and deformation of the objects during a collision).
This is given as the initial momentum of the puck, and since the total momentum of the system is conserved, the momentum of the puck after the collision is zero since the goalie is at rest.
The total momentum of the system is calculated using conservation of momentum principles.
Using the conservation of momentum law, the velocity of the goalie can be calculated, which is given by:
\($$\begin{aligned} 0.105 \text{ kg}\times 30 \text{ m/s} &= (0.105 \text{ kg}+61 \text{ kg}) \times v \\ 3.15 \text{ kg}\cdot \text{m/s} &= 61.105 \text{ kg}\times v \\ \frac{3.15 \text{ kg}\cdot \text{m/s}}{61.105 \text{ kg}} &= v \approx 0.0517 \text{ m/s} \end{aligned}$$.\)
The goalie's velocity is 0.0517 m/s, which is a very modest speed.
Thus, the answer to the given problem is 0.0517 m/s, which is the velocity of the goalie.
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a small hockey puck slides without friction over the icy hill shown in the figure and lands 7 m from the foot of the cliff with no air resistance. what was its speed v0 at the bottom of the hill?
Using conservation of energy, the initial velocity of the puck at the bottom of the hill is 19.6 m/s.
Expecting the slope is a smooth bend, we can utilize preservation of energy to track down the underlying speed of the puck. Since there is no grating or air obstruction, the main powers following up on the puck are gravity and the typical power. Thusly, the absolute mechanical energy of the puck is saved.At the highest point of the slope, the puck has gravitational possible energy, which is changed over into active energy as it slides down the slope. At the lower part of the slope, the gravitational potential energy has been all changed over into motor energy, so we can compose:
mgh = (1/2)mv0^2
where m is the mass of the puck, g is the speed increase because of gravity, h is the level of the slope, and v0 is the underlying speed of the puck at the lower part of the slope.
Tackling for v0, we get:
v0 = sqrt(2gh)
Where sqrt addresses the square root capability.We can utilize the given distance of 7 m to track down the level of the slope:d = sqrt(h^2 + 49)
where d is the distance the puck lands from the foot of the bluff. Settling for h, we get:
h = sqrt(d^2 - 49)
Subbing this articulation for h into the situation for v0, we get:
v0 = sqrt(2g(sqrt(d^2 - 49)))
Where g is the speed increase because of gravity.Connecting the upsides of g = 9.8 m/s^2 and d = 7 m, we get:
v0 = sqrt(2 x 9.8 x sqrt(7^2 - 49)) = 19.6 m/s
In this way, the underlying speed of the puck at the lower part of the slope was 19.6 m/s.
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Help me please
Which line shows the LOWEST frequency?
a 45,000-kg airplane experiences a force from its engines of 110,000 n. what is the acceleration of the airplane?
Each of a jumbo jet's four engines produces 50,000 N of thrust at 100,000 kg during takeoff, and the plane accelerates at a speed of There are engines, therefore the acceleration is equal to 50,000/100,000 * 4 or 2 m/s.
What will happen to the acceleration if the net force increases?Newton discovered that if you raise the net force by, say, a factor of two, then the acceleration also increases by that same factor, which helps to explain the relationship between force and acceleration. This implies that the relationship between force and acceleration is linear.
Net force divided by mass results in acceleration. An object accelerates at a rate equal to its net force multiplied by two. The acceleration will decrease by half if the mass is doubled. The formula a = v/t denotes acceleration (a), which is the product of the change in velocity (v) and the change in time (t). Using meters per second squared \((m/s^{2} )\), you can gauge how quickly velocity varies.
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Having landed on a newly discovered planet,
an astronaut sets up a simple pendulum of
length 1.04 m and finds that it makes 475
complete oscillations in 1320 s. The amplitude of the oscillations is very small compared
to the pendulum’s length.
What is the gravitational acceleration on
the surface of this planet?
Answer in units of m/s^2.
Answer:
17.215 m/s^2
Explanation:
L = 0.825 m
It completes 397 oscillations in 546 s.
Time period is defined as the time taken to complete one oscillation.
So, Time period, T = 546 / 397 = 1.375 s
Let g be the gravitational acceleration at that planet.
Use the formula for the time period
g = 17.215 m/s^2
When using the max out method to determine muscular strength, you must first do a warm-up set and a complete set before attempting your one rep max.
Answer:
True
Explanation:
I took the quiz and got it right.
TRUST
The "max out" method, also known as the "1RM" (One Repetition Maximum) method, is commonly used in strength training to determine the maximum amount of weight an individual can lift for a particular exercise.
The purpose of this method is to assess muscular strength accurately. While it is essential to perform warm-up sets to prepare the body for intense lifting, the process of determining the 1RM involves a specific protocol:
Warm-up Sets: Before attempting the 1RM, it is crucial to warm up the muscles and joints properly. Warm-up sets are typically performed with lighter weights and higher repetitions to gradually prepare the body for the heavier load.
Complete Sets: After the warm-up sets, the individual performs one or more "complete sets" with progressively heavier weights, but not at maximal effort. These sets help acclimate the body to heavier loads and prepare the nervous system for the upcoming maximal lift.
1RM Attempt: Once adequately warmed up and prepared, the individual makes an attempt to lift the heaviest weight possible for one repetition. It is essential to have a spotter or a qualified trainer to ensure safety during this maximal effort lift.
Rest: After the 1RM attempt, it is essential to allow sufficient rest and recovery, as attempting maximal lifts can be physically and mentally demanding.
It's important to note that determining 1RM carries a higher risk of injury compared to typical strength training. It's best to perform 1RM assessments under the guidance of a qualified trainer or coach who can provide proper instruction and ensure safety throughout the process. Additionally, the 1RM should be assessed periodically, as it can change over time with training and adaptation.
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A projectile is shot horizontally from the edge of a cliff, 400 m above the ground. The projectile is traveling horizontally at 65 m/s the moment it leaves the cannon.
What is the initial vertical velocity of the projectile?
Determine the time taken by the projectile to hit the ground.
How far does the projectile land from the base of cliff?
Find the vertical component of the velocity just before the projectile hits the ground.
What is the magnitude of the final vector velocity the instant before it hits the ground?
What is the direction of the final vector velocity the instant before it hits the ground?
Answer:
a) \(v_{oy}\) = 0, b) t = 9.035 s, c) x = 587.275 m, d) v_y = -88.54 m / s,
e) v = 109.84 m / s, f) θ = -53.7º
Explanation:
This exercise is a projectile launch
a) as the projectile is launched horizontally, its initial vertical velocity is zero
\(v_{oy}\) = 0
b) let's use the relation
y = y₀ + v_{oy} t - ½ g t²
when reaching the ground y = 0 and the initial vertical velocity is v_{oy}=0
0 = y₀ + 0 - ½ g t²
t = \(\sqrt{ \frac{2 v_o}{g} }\)
t = \(\sqrt{ \frac{ 2 \ 400 }{ 9.8} }\)
t = 9.035 s
c) the horizontal distance is
x = v₀ₓ t
x = 65 9.035
x = 587.275 m
d) the vertical speed when touching the ground
v_y = \(v_{oy}\) -gt
v_y = 0 - 9.8 9.035
v_y = -88.54 m / s
the negative sign indicates that the velocity is directed downwards
e) the velocity at this point
v = \(\sqrt{ v_x^2 + v_y^2}\)
v = \(\sqrt{65^2 + 88.54^2}\)
v = 109.84 m / s
f) the direction of the velocity
let's use trigonometry
tan θ = v_y / vₓ
θ = tan⁻¹1 v_y / vₓ
θ = tan⁻¹ (-88.54 / 65)
θ = -53.7º
this angle is measured clockwise
A charge gains 2.77 J of energy when it moves between the terminals of a battery with a potential difference of 9.00 V What is the amount of the charge? (Unit = C)
Answer: 0.308
Explanation:
acellus
explain why the magnetic field in solenoid is Greater if the solenoid has an iron core?
Answer:
he magnetic field is greater because the magnetization of the material is added
Explanation:
The magnetic field in a solenoid is given by the relation
B₀o = μ₀ n I
where n is the density of turns and I the current
When we put a magnetic material inside solenoid
the magnetic field is
B = B₀ + μ₀ M
where M is called the magnetization of the material and corresponds to the alignment of the magnetic moments of the atoms with the field, therefore the total field is much greater, it should be noted that the part of Bo increases with the current, but the magnetization has a maximum value.
Consequently the magnetic field is greater because the magnetization of the material is added
how do you imagine you can increase the magnetic field from a magnet?
1). Wind more turns of wire in the coil around the core.
2). Increase the electrical current flowing in the wire.
(You can do that by using a battery or power supply with a little more voltage.)
3). If the core of the electromagnet is anything else but pure iron,
take it out, throw it away, and replace it with a core of pure iron.
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Explain how radioactive decay works for measuring the absolute age of ancient objects.
Answer: Radioactive decay is the breakdown of a material into stable isotopes which are used for determining the age of the ancient material.
Explanation:
The radioactive decay is a natural process in which an ancient or old material whether in the form of rock, object or fossil break down into elements. Carbon 14 is an unstable isotope which decays to produce stable elements, the dating procedure uses these stable elements and the rate of decay of the isotopes to determine the age of absolute ancient of the objects but exact age cannot be determined just an approximation can be accepted.
A fault in the switch caused a householder to receive a mild electric shock before a safety device switched the circuit off.
The mean power transfer to the person was 5.75 W.
The potential difference across the person was 230 V.
Calculate the resistance of the person
The resistance of the person is 9200 Ω if a fault in the switch is caused by a householder to receive a mild electric shock with the mean power transfer to the person as 5.75 W and potential difference across the person as 230 V.
The resistance of the person can be calculated using Ohm’s law.
Ohm’s law states that the potential difference across a conductor is directly proportional to the current flowing through it, provided that its temperature and other physical conditions remain constant.
It can be expressed as: V = IR,
where V is the potential difference, I is the current, and R is the resistance of the conductor.
Rearranging the equation, we get: R = V/ I.
Given that the mean power transfer to the person was 5.75 W and the potential difference across the person was 230 V, the current flowing through the person can be calculated using the formula:
P = IV
where P is the power ,V is the potential difference and I is the current flowing through the person
Rearranging the equation, we get: I = P/V
Substituting the given values, we get:
I = 5.75/230 = 0.025 A
Therefore, the resistance of the person can be calculated as:
R = V/I = 230/0.025 = 9200 Ω
Hence, the resistance of the person is 9200 Ω.
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A marble has a volume of 1 mL. How much water will it displace in a graduated cyclinder
A.
1 mm
B.
more than 1 mL
C.
less than 1 mL
D.
1mL
The upward force on an object falling through the air is ___
Answer:
the answer is air resistancetwo children, A and B, fire identical 10.0g all bearings from a catapult. the elastic band of each catapult extended by 0.10m and then released to fire the ball bearings. Child A's elastic band has a spring constant of 144N/m. calculate the energy transferred to the kinetic energy store of the child A's ball bearing.
thanks soo much (:
WORTH 50 PTS
The energy transferred to the kinetic energy store of the child A's ball bearing is 0.72 J.
Energy transferred to the kinetic energy
The energy transferred to the kinetic energy store of the child A's ball bearing is determined from the principle of conservation of energy as shown below;
K.E = Ux = ¹/₂kx²
K.E = ¹/₂ x 144 x 0.1²
K.E = 0.72 J
Thus, the energy transferred to the kinetic energy store of the child A's ball bearing is 0.72 J.
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need some help please.
Answer:
The x - component of vector B is determined as -18.3 m.
What is x-component of a vector?
The x-component or horizontal component of a vector is the value of the vector acting or pointing x direction or in a horizontal direction.
The x-component or horizontal component of a vector on a given plane calculated as follows;
Bx = B cos(θ)
where;
B is the magnitude of the vectorθ is the angle of inclination of the vectorThe given parameters include the following;
the angle of inclination of the vector from the horizontal direction, θ = 170⁰the magnitude of vector B = 18.6 mSubstitute the given parameters into the above equation and for the x-component of vector b.
Bx = 18.6 x cos(170)
Bx = -18.3 m
Thus, from the magnitude of vector B in the image, the value of vector B in x - direction is -18.3 m.
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A particular roller coaster has a mass of 3500 kg, a height of 4.0, and a velocity of 12m/s. What is the potential energy? If needed, use g=10.m/s^2
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
Gravitational Potential Energy of an object is calculated by formula ~
\( \large\boxed{\sf P = mgh}\)
where,
m = mass of the object = 3500 kgg = Acceleration due to gravity = 12 m/s²h = height attained by the object = 4 mNow, let's calculate its potential energy ~
\(3500 \times 10 \times 4\)\(140000 \: \: joules\)\(140 \: \: kj\)Answer:
Potential Energy of an object is calculated by formula:
Potential Energy (P.E)=m×g×hWhere,
m=mass of bodyg=acceleration due to gravityh=height from the earth surfaceNow, let's solve the question.
Given,
mass(m)=3500 kgheight (h)=4mvelocity (v)=10m/s²Now,
We know that,
Potential Energy (P.E)=mgh
\( = 3500 \times 10 \times 4\)
\( = 3500 0\times 4\)
\( =140000 joules \)
\(\mathfrak{\blue{DisneyPrincess29}}\)
A rod 14.0 cm long is uniformly charged and has a total charge of - 22.0 μC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 36.0 cm from its center.
Answer:
\(E=1.58*10^6N/C\)
The direction is toward the negative x axis i.e the Rod
Explanation:
From the question we are told that:
Length \(L=14.0cm\)
Total charge \(q=-22.0\muC\)
Distance \(d=36cm=>0.36m\)
Generally the equation for Electric Field is mathematically given by
\(E=\frac{kq}{d^2}\)
Since Magnitude of E is at 36cm away from center
\(E=\frac{kq}{d^2-(L/2)^2}\)
\(E=\frac{9*10^9*(22*10^6)}{0.36^2-(0.14m/2)^2}\)
\(E=1.58*10^6N/C\)
Therefore with Charge Bearing the Negative sign the direction is toward the negative x axis i.e the Rod
1)A 25 kg air compressor is dragged up a rough incline from r⃗ 1=(1.3ı^+1.3ȷ^)m to r⃗ 2=(8.3ı^+2.6ȷ^)m, where the y-axis is vertical. How much work does gravity do on the compressor during this displacement?
2)A 25 kg box sliding to the left across a horizontal surface is brought to a halt in a distance of 55 cm by a horizontal rope pulling to the right with 16 N tension.How much work is done by tension?How much work is done by gravity?
As for the work done by gravity, in this case, it is zero because the box is sliding horizontally on a horizontal surface, and gravity does not do any work in this direction. Therefore, the total work done by tension is 8.8 Joules.
What is the work done by gravity?To calculate the work done by gravity on the air compressor during its displacement up the incline, we need to determine the change in gravitational potential energy.
The gravitational potential energy (PE) of an object is given by the equation \(PE = mgh\), where m is the mass of the object, g is the acceleration due to gravity, and h is the change in height.
Given:
Mass of the air compressor, \(m = 25 kg\)
Acceleration due to gravity, \(g = 9.8 m/s^2\) (assuming Earth's gravity)
Initial position, \(r⃗ = (1.3ı^ + 1.3ȷ^) m\)
Final position, r⃗\(2 = (8.3ı^ + 2.6ȷ^) m\)
Change in height, h = Final y-coordinate - Initial y-coordinate \(= y2 - y1 = 2.6 m - 1.3 m = 1.3 m\)
Therefore, the work done by gravity on the air compressor is:
\(W = \Delta PE = mgΔh = 25 kg * 9.8 m/s^2 * 1.3 m = 318.5 J\) (rounded to one decimal place)
So, the work done by gravity on the air compressor during its displacement up the incline is approximately 318.5 Joules.
The work done by tension can be calculated using the equation \(W = Fd\), where F is the force applied and d is the displacement.
Given:
Tension force, \(F = 16 N\) (in the opposite direction of displacement)
Displacement, \(d = 55 cm = 0.55 m\)
Therefore, the work done by tension is:
\(W = Fd = 16 N \times 0.55 m = 8.8 J\)
Therefore, As for the work done by gravity, in this case, it is zero because the box is sliding horizontally on a horizontal surface, and gravity does not do any work in this direction. the work done by tension is \(8.8\) Joules.
Learn more about gravity here:
brainly.com/question/30319398
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