A commuter train passes a passenger platform at a constant speed of 39.6 m/s. The train horn is sounded at its characteristic frequency of 346 Hz. (a) What overall change in frequency is detected by a person on the platform as the train moves from approaching to receding

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

For more such questions on equilibrium, click on:

https://brainly.com/question/517289

#SPJ8

Answer:

2 m/s²

Explanation:

To calculate the acceleration of an object, we use the following formula:

\(\boxed{a = \frac{v - u}{t}}\),

where:

• a = acceleration

• v = final speed

• u = initial speed, and

• t = time taken

We are told in the question that the final speed of the helicopter is 40 m/s, its initial speed is 30 m/s, and that the time it took to get from 30 m/s to 40 m/s is 5 seconds.

Therefore, using this information, as well as the formula above, we can evaluate the acceleration of the helicopter:

\(a = \frac{40 - 30}{5}\)

  \(= \frac{10}{5}\)

  \(= \bf 2 \: m/s^2\)

So the acceleration of the helicopter is 2 m/s².

The example provided is most closely related to option C: Performance accomplishments.

Setting a mileage goal each week and becoming more confident about finishing the race indicates that Tina is actively working towards her goal of running a 5k race. By gradually increasing her mileage and gaining confidence, she is achieving performance accomplishments, which involve personal achievements and successful experiences.

Physiological states refer to the influence of one's physical and emotional condition on their confidence and motivation. Verbal persuasion involves receiving encouragement or positive feedback from others. Vicarious experience entails gaining confidence by observing and learning from others' successes.

Learn more about Performance accomplishments, here;

https://brainly.com/question/2065380

#SPJ1

An elastic spring extends by 0.1 m due to the action of a force of 15 N. The elasticity constant of that spring will be 150 Newton/ meters.

Elastic constants are the constants which are used to determine the deformation which is produced by a given stress system acting on the material. There are many types of elastic constants such as Bulk modulus (K). The expression for Bulk modulus for elasticity.

F = kx

where, F is the force applied,

k is Elasticity constant,

x is the extension of the spring

k = F/ x

k = 15/ 0.1

k = 150

Therefore, the elasticity constant of the spring will be 150 Newton/ meters.

Learn more about Elasticity here:

https://brainly.com/question/28790459

#SPJ9

Answer:

The bending moment is 459.16 N.m

Explanation:

From the given information;

Let's assume that the angle is 66°

Then, the free body diagram is draw and attached in the file below.

Now, the calculation of the acceleration from the first part of the free body diagram is:

\(\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a \\ \\ a = \dfrac{347.906}{50} \\ \\ a = 6.96 \ m/s^2\)

Bending moment M:

From the second part of the diagram:

\(\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435 \\ \\ M = 238.435 + 220.725 \\ \\ \mathbf{M = 459.16 \ N.m}\)

Answer:

at the highest point in the trajectory

Explanation:

When the tennis ball is hit, it moves in the air along a curve or an arc. This path is the parabola curve. Such a motion in the two dimension is known as projectile motion. It is constant accelerated motion in the downward direction.

The velocity of the ball is minimum at the highest point of the motion. When we hit the ball, the ball moves up to certain eight and then it gradually fall back to the earth surface along a curve.

The horizontal velocity of the ball is always the same along the curve. Only the vertical velocity varies. As the ball reaches the top of the curve or the maximum height, its vertical velocity becomes zero.

So, speed of the tennis ball is minimum at the highest point of the path.

Explanation:

To determine the force F of interaction between the half ring and the point charge, we can use the principle of superposition, which states that the total force on a point charge due to a collection of other charges is the vector sum of the individual forces that each of those charges would exert on the point charge if it were the only charge present.

First, we need to find the electric field at the center of curvature due to the charged half ring. The electric field at a point on the axis of a uniformly charged ring is given by:

E = kqz / (z^2 + R^2)^(3/2)

where k is Coulomb's constant, q is the linear charge density, z is the distance from the center of the ring to the point on the axis, and R is the radius of the ring.

At the center of curvature of the half ring, z = R, so the electric field is:

E = kq / (2R)

Next, we can use the electric field to find the force on the point charge q:

F = qE

Substituting the given values, we get:

F = (20 x 10^-9 C) x (9 x 10^9 N·m^2/C^2) x (1/20 cm)

F = 9 x 10^-3 N

Therefore, the force of interaction between the half ring and the point charge is 9 x 10^-3 N.

This force can also be interpreted as the force required to hold the point charge at the center of curvature against the electric field due to the charged half ring. It is an attractive force because the point charge is opposite in sign to the charged half ring.

Answer:

5.65N.

Explanation:

Solution Given:

radius of R = 10 cm=10/100=0.1 m

linear density λ = 1 Mikrokulon/m= 10^-6 Coulomb/m

force F=?

q1 = 20nC=20*10^-9 C

we have

Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, this can be expressed as:

F = k*(q1*q2)/r^2

since q1 is located at the center of curvature of the half ring , so the half ring is uniformly charged with a linear density of λ= 1 μC/m.

again

equation becomes.

F=k*(q1*λL)/r^2

Since the half ring is a semicircle,

we have L=πr

F=k*(q1*λ*πr)/r^2

substituting value

F=9 x 10^9 N*m^2/C^2 *(20*10^-9 C* 10^-6 m^3*π*0.1 m)/(0.1m^2)

F=5.65 N

Therefore, the force of interaction between the half ring and the point charge is 5.65N.

Answer:

The statement of the student is correct.

Since B attained a higher velocity in a short amount of time, that is it accelerated faster(having a larger slope).

Slope = dy/dx

That is, Velocity

Time

which is acceleration.

That's my guess.

Hope it's right.

Explanation:

, the net force will be felt on particle approximately 15.39 N to the right.

If the distance between them is tripled, the gravitational force is F2= 36/9=4N. The force of attraction between any two bodies is proportional to the product of their masses and inversely proportional to the square of their distance.

WHAT IS GRAVITATIONAL FORCE?

The formula for Gravitational force:

F=G m1*m2/r² ,

G: gravitational constant = 6.67x10⁻¹¹ N*m²/kg²

m1: is the mass of the first object

m2: is the mass of the second object

r: is the distance between the center of the masses of the objects

F∝1/r²

so F1/F2=( r2/r1)².......(1)

Given F1= 36N F2=?

let r1=r, r2= 3r

putting all this value in equation (1)

36/F2= (3r/r)²

⇒F2= 36/9=4N

To know more about gravitational force refer

brainly.com/question/24783651

#SPJ10

The correct answer is :

Here 100 N force is applied to make the box move with constant velocity from rest. That means 100 N force is applied to overcome the limiting  static friction and as soon as 100 N force is applied it starts moving.

Now,

Constant velocity means acceleration = 0

Net force acting on the box =mass × accelaration = mass × 0 = 0

Conceptually it is zero as it is balanced by kinetic friction which has equal value that of applied force. Because net force =Applied force - friction force and hence here friction force =applied force.

If there was any accelaration then there would exist a net force and then frictional force and applied force will be the same.  

To learn more about accelaration refer the link:

https://brainly.com/question/21509870

#SPJ9

Answer:

1.2703 km

Explanation:

The speed can be calculated using the formula;

Speed (m/s) = distance (m) ÷ time (s)

Based on the information in this question, it took 3.7 seconds for a sound with speed of 1236 km/h to reach John. The distance will be:

Distance = speed × time

However, we need to convert the time in seconds (s) to hour (hr).

1 second = 0.000277778 hour

3.7 seconds = 0.00102778 hours.

Hence,

distance = 1236 × 0.00102778

Distance = 1.2703 km

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

know more about clusters here:

https://brainly.com/question/31390874

#SPJ8

Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

(a) The son pops the helium balloon (unchanged)

(b) The fisherman knocks the tackle box overboard and it sinks to the bottom (rises)

(c) The son finds a cup and bails some water out of the bottom of the boat (falls)

(d) The fisherman lowers himself in the water and floats on his back (unchanged)

(e) The fisherman lowers the anchor and it hangs one foot above the bottom of the pond (rises)

(f) The son gets in the water, looses his grip on the string, letting the balloon escape upwards (rises).

According to Archimedes principle, when a body is partially or completely immersed in a fluid, it experiences an upthrust which is equal to weight of to fluid displaced.

F = ρVg

V = F/ρg

where;

When an object with a significant weight is dropped into the pond, the level of water in the pond will rise and vice versa.

The water level in the pond will be Unchanged, since the weight of the balloon is almost insignificant.

The water level will rise because the weight of the tackle box is significant.

The water level will fall since some volume of water is being removed.

The water level will be unchanged, since nothing new is added into the pond.

The water level will rise because the anchor will displace some volume of water upwards when it is dropped inside the pond.

The water level will rise, because the balloon will displace the water upwards when it escape upwards.

Learn more about upthrust here: https://brainly.com/question/23931817

#SPJ1

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

A person born in the United States is considered a citizen of the country, according to the 14th Amendment's "Citizenship" provision.

Citizens of both the United States and the State in which they live include everyone who was born or naturalised in the country and is subject to its laws. No State may enact or carry out any legislation that restricts the rights or privileges of US citizens; no State may rob anyone of their life, liberty, or property without first providing them with a fair trial; and no State shall deny anyone living under its jurisdiction the equal protection of the law.

Based on the first clause of Section 1,1, the Court has determined that a child born in the United States to Chinese parents who were not qualified for naturalisation themselves is nonetheless a citizen of the United States with all the rights.

Learn more about United states here:

https://brainly.com/question/1315100

#SPJ1

The speed at the top of the loop is √gR.

Let the starting point be A, the lower point of loop be B and the top of loop be C.

So, at A the car is having only potential energy.

PE = mgh

At B, the kinetic energy,

KE = 1/2 mv²

a) At point C,

mv²/R = mg

The velocity at the top point, v(C)

v(top) = √gR

b) According to Conservation of energy, at B and C,

1/2 mv(B)² = 1/2 mv(C)² + mg(2R)

v(B)² = gR + 4gR

Therefore, v(B) = √5gR

To learn more about Conservation of energy, click:

https://brainly.com/question/11264649

#SPJ1

The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm. Option A is correct.

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of the given mechanical machine.

Mechanical advantage is a measure of how much a machine multiplies the input force.

The equation for the mechanical advantage of a lever is;

MA =length of effort arm/length of resistance arm

\(\rm MA=\frac{L_E}{L_R}\)

The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm.

Hence, option A is correct.

To learn more about the mechanical advantage, refer to the link;

https://brainly.com/question/7638820

#SPJ1

The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm. Option A is correct.

What is the mechanical advantage?

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of the given mechanical machine.

Mechanical advantage is a measure of how much a machine multiplies the input force.

The equation for the mechanical advantage of a lever is;

MA =length of effort arm/length of resistance arm

a) The angle θ1 which the righthand cable makes with respect to the ceiling is  sin^(-1)(692 N / 530 N).

b) The angle θ2 which the left-hand cable makes with respect to the ceiling is  sin^(-1)(692 N / 570 N).

We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).

We may apply the ideas of trigonometry and vector addition to address this issue.

a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.

T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).

T1sin(θ1) = 692 N

We may rearrange the equation to find 1:

θ1 = sin^(-1)(692 N / T1)

We can find 1 by substituting the given tension value, T1 = 530 N:

θ1 = sin^(-1)(692 N / 530 N)

b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.

The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).

T2sin(θ2) = 692 N

To find θ2, we can rearrange the equation:

θ2 = sin^(-1)(692 N / T2)

Substituting the given tension value T2 = 570 N, we can solve for θ2:

θ2 = sin^(-1)(692 N / 570 N)

Calculating these angles using the given tension values will provide the answers in degrees.

For more question on tension

https://brainly.com/question/24994188

#SPJ11

Answer:

??????? umm what r u saying??? kinda confusing..............what does question why if you keep dieing in zombies on cold war u think im gunna rev you. i just got the key and the d.i.e remote and am geting the wonder wepon. but soon as that door explode you so quick to grab it you die. played me like a fool. why the heck you keep tryna exfil on round 15 BOI IF YOU DONT WQBFUFHJEWFHFNQC! packapunched knife to tier 1 head aS BOI!!! mean????????

very very very confusing

Explanation:

plz mark brainlyist :()

Answer:

i think it's C thx correct me if wrong

Answer:

A

Explanation:

The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point:

d

→

L

d

t

=

0

or

→

L

=

→

l

1

+

→

l

2

+

⋯

+

→

l

N

=

constant

.

Note that the total angular momentum

→

L

is conserved. Any of the individual angular momenta can change as long as their sum remains constant. This law is analogous to linear momentum being conserved when the external force on a system is zero.

To calculate the mass of the block, we need to use the formula:

mass = density x volume

The density of lead is approximately 11.34 grams per cubic centimeter.

The volume of the block is:

30cm x 80cm x 60cm = 144,000 cubic centimeters

Therefore, the mass of the block of lead is:

11.34 g/cm3 x 144,000 cm3 = 1,632,960 grams

So the mass of the block of lead is 1,632,960 grams.

The mass of the block of lead is 1632.96 kg.

To find the mass of a block of lead with dimensions 30 cm by 80 cm by 60 cm, we need to know the density of lead. The density of lead is 11.34 g/cm³. The formula for mass is

mass = density x volume.

The volume of the lead block is 30 cm x 80 cm x 60 cm = 144000 cm³.

Therefore, mass = 11.34 g/cm³ x 144000 cm³ = 1632960 g.

The mass of the block of lead is 1632.96 kg.The mass of a block of lead is determined by the formula

mass = density x volume.

The density of lead is 11.34 g/cm³. The block of lead has dimensions of 30 cm by 80 cm by 60 cm, therefore its volume can be calculated as 30 cm x 80 cm x 60 cm = 144000 cm³.The formula for the mass of an object is

mass = density x volume.

From the provided values, we can calculate the mass of the block of lead as follows:

mass = 11.34 g/cm³ x 144000 cm³ = 1632960 g.Since 1 kg = 1000 g,

we can convert the mass from grams to kilograms by dividing the answer by 1000:

mass = 1632960 g / 1000 = 1632.96 kg.

For more question block of lead

https://brainly.com/question/2078650

#SPJ8

The resultant velocity of the jacob while crossing chattooga river is found as  6.5 m/s with the direction heading south east.

Due to kayaker and the river, we obtain two perpendicular velocities: 2.5 m/s across the river in an easterly direction, and 6 m/s downstream in a southerly direction.

The Pythagorean Theorem predicts the size of a resultant velocity as follows:

v = √(2.5)² + (6)²

v = √42.25

v = 6.5 m/s

The resultant direction will be south east.

Thus, the resultant velocity of the jacob while crossing chattooga river is found as  6.5 m/s with the direction heading south east.

To know more about the resultant velocity vector, here

https://brainly.com/question/4945130

#SPJ1

Answer:

B. period of the sound wave

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

For more such information on: net force

https://brainly.com/question/14361879

#SPJ8

Answer:

       d = 6 i^   m

Explanation:

This is an exercise in kinematics, where the position vector is the displacement of the body from one point to another.

In this case we are told that for t = 0 the worm is at x₀ = 3m and with velocity starts from zero, after t = 1 s it is at x₁ = 9m and with a velocity of

v₁ = 5 m / s

They ask what is the displacement for the time of 1 s

               d = x₁ - x₀

               d = 9 -3 m

               d = 6 m

Bold indicates vector, displacement vector is

             d = 6 i ^ m

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

To learn more about diameter

https://brainly.com/question/32968193

#SPJ8