A _________ is a sample containing all components except analyte, and it is taken through all steps of the analytical procedure. a. method blank b. reagent blank c. field blank d. spike blank e. matrix blank

Answer:

a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Explanation:

simpler definition: It's just a thing that you're willing to define before your experiment begins. You're predicting what'll happen, or what you'll earn through your experiment.

Let's say that you're doing an experiment based on using fertilizer on your plant. Your hypothesis can end up like this, "If I add fertilizer to my garden, then my plants will grow faster."

Please correct me if I'm wrong.

Answer:

Normal cells are either repaired or die (undergo apoptosis) when they are damaged or get old. Cancer cells are either not repaired or do not undergo apoptosis.

Explanation:

The relationship between the calculated/theoretical number of ions/particles in solution and the actual number of particles in solution depends on several factors, such as the accuracy and precision of the analytical method used to determine the number of particles.

In reality, the actual number of ions or particles in a solution can vary from the calculated number due to a number of factors. For example, ions can interact with each other and form complexes, or they can be adsorbed onto the surface of solids or other surfaces in the solution. Additionally, ions can be lost from solution due to precipitation, and they can be present in the solution in different forms (such as free ions, ion pairs, or hydrated ions).

Therefore, while the calculated number of ions or particles in solution provides a useful starting point for understanding the behavior of a solution, it is important to keep in mind that the actual number of ions or particles in solution can differ from the calculated number, and that other factors can influence the behavior of the solution.

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• given that volume = 230ml ,therefore mass of water = 230g

• ∆T = Tfinal-Tinitial =30.5-22.9 = 7.6°C

• Specific heat capacity of water , C= 4.184J/°C*g

• Therefore , q = mass* C * ∆T

= 230 * 4.184 * 7.6

=7313.6 J /1000

q= 7.314KJ

• given : mass of methanol burned = Mass F-Mass initial

=(2.51-1.65) = 0.86 g

• So ,moles of methanol , n = mass methanol/Mol. mass methanol

= 0.86g/32.04g/mol

=0.027 moles

• Finally , ∆H = q/n

= 7.314KJ / 0.027mol

=270.85KJ/mol

• However, this is an exorthemic reaction, heat is lost through combustion, our molar enthalpy should be negative.

Answer:

Amplitude is measured from the center line to the highest point in the waves.

Wavelength is the distance between one wave to the other from the highest point.

Frequency is the rate of the waves.

Gene Vincent and Eddie Cochran were particularly popular with teenagers and young adults during the 1950s.

Gene Vincent and Eddie Cochran were American rock and roll musicians who gained popularity in the 1950s. They were part of the rockabilly movement, which combined elements of country music with rhythm and blues.

Gene Vincent was known for his hit song 'Be-Bop-A-Lula,' which became a rock and roll classic. Eddie Cochran was known for his energetic performances and songs like 'Summertime Blues' and 'C'mon Everybody.'

Both artists had a significant impact on the development of rock and roll music and were particularly popular with teenagers and young adults during their time.

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Gene Vincent and Eddie Cochran were particularly popular with the youth and rock and roll enthusiasts of the late 1950s and early 1960s.

Gene Vincent and Eddie Cochran were particularly popular with the youth and rock and roll music enthusiasts of the late 1950s and early 1960s. Their energetic performances and rebellious image resonated with the emerging teenage audience at the time.

They were influential figures in the rockabilly and rock and roll genres, known for their hits such as "Be-Bop-A-Lula" by Gene Vincent and "Summertime Blues" by Eddie Cochran. Their music and style captured the spirit of youthful rebellion and played a significant role in shaping the early rock and roll era.

Gene Vincent and Eddie Cochran were influential figures in the rock and roll music scene of the late 1950s and early 1960s. They were particularly popular with the teenage audience of the time, as their music and persona embodied the rebellious and energetic spirit of the youth culture.

Gene Vincent, born Vincent Eugene Craddock, rose to fame with his hit song "Be-Bop-A-Lula" in 1956. Known for his distinctive vocal style and wild stage presence, Vincent became a rockabilly icon. His music blended elements of rock and roll, rhythm and blues, and country, creating a unique sound that resonated with young listeners. Songs like "Bluejean Bop" and "Race with the Devil" further solidified his popularity.

Eddie Cochran, on the other hand, was a multi-talented musician, singer, and songwriter. He gained fame with his upbeat and catchy songs, such as "Summertime Blues" and "C'mon Everybody." Cochran's music was characterized by his skillful guitar playing, heartfelt lyrics, and a distinctive rock and roll sound. His contributions to the genre and his early death at the age of 21 in a tragic car accident solidified his status as a rock and roll legend.

Both Gene Vincent and Eddie Cochran were known for their electrifying live performances and their impact on the rock and roll genre. Their music resonated with young audiences who were seeking an outlet for their rebellious spirit and love for energetic, guitar-driven music. Their influence can still be felt in the development of rock music and the inspiration they provided to subsequent generations of musicians.

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The original mass of Rn-222 was 0.2 grams.

The quantity of substance in an item or system is measured by its mass, which is a fundamental physical attribute of matter. It is a measurement of an object's resistance to changes in motion and is often expressed in kilogram (kg) or gram (g) units. It's common to conflate weight—the force of gravity acting on an object—with mass. However, weight varies according to the strength of the gravitational field, whereas mass is constant no matter what gravitational field it is in.

The decay of Rn-222 can be modeled using the following equation:

N(t) = N₀ ×  \(\frac{1}{2} ^\frac{t}{T}\)

where N(t) is the amount of Rn-222 remaining at time t, N₀ is the initial amount of Rn-222, T is the half-life of Rn-222, and  \(\frac{1}{2} ^\frac{t}{T}\) is the fraction of  Rn-222 remaining after time t.

We are given that the half-life of Rn-222 is 3.823 days and that 0.05 grams remain after 7.646 days. Using the equation above, we can set up the following equation:

0.05 grams = N₀ × \(\frac{1}{2} ^ \frac{7.646}{3.823}\)

Solving for N₀, we get:

N₀ = 0.05 grams /  \(\frac{1}{2} ^ \frac{7.646}{3.823}\)

N₀ = 0.05 grams / 0.5²

N₀ = 0.05 grams / 0.25

N₀ = 0.2 grams

Therefore, the original mass of Rn-222 was 0.2 grams.

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Answer:

88.20%

Explanation:

% yields =( experimental yield /theoretical yield )x100%

           = ( 56.8 ÷ 64.4 ) x100%

            = 88.20%

The percent yield for the given reaction where in the product obtained is 56.8 g is 88.19%.

Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.

In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.This condition arises when there are other simultaneous reactions taking place leading to the formation of product. It can also arise if there is incomplete removal of impurities from the sample .In the given example , percent yield=56.8/64.4×100=88.19%.

Thus, the percent yield of reaction is 88.19 %.

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Answer:

frequency because it moves up and down faster.

Explanation:

Answer: current and pull making quicker wave and smaller

Explanation:

Answer:

Anatomy of the Immune System

.The immune system is a mobile, circulatingsystem. However, there are some fixed anatomical structures which are important to its function:

immune cells are made within the bone marrow during haematopoiesis

the thymus gland is situated just in front of the heart in the mediastinum. It is active throughout life, but is at its largest in childhood and decreases in size after puberty. It is where lymphocytes mature and receive their immunological “education” before being released into the bloodstream.

mature lymphocytes migrate to lymph nodes, which are small bean-like structures situated along the lymphatic vasculature throughout the body. These filter lymph and provide a site for antigen presentation to the adaptive immune system. Lymph is then returned to the systemic circulation via the thoracic duct, which joins with the left subclavian vein.

the spleen is basically a massive lymph node and is, therefore, another site of antigen presentation to mature lymphocytes. It is part of the reticulo-endothelial system which filters blood and removes old cells, tissue debris, pathogens and immune complexes. It also stores red blood cells and immature monocytes.

finally, the liver is also a site of antigen presentation and contains its own cohort of phagocytes and lymphocytes. This is a vital role, as the liver filters large volumes of potentially contaminated venous blood from the gastrointestinal (GI) tract. It also synthesises acute phase proteins such as CRP in response to infection.

The theoretical yield of Fe₂O₃ is 0.0059 moles and the percent Yield is 44.2%

Using stoichiometry to calculate the theoretical yield of Fe₂O₃:

From the balanced chemical equation, 4 moles of Fe react with 3 moles of O₂ to produce 2 moles of Fe₂O₃. Therefore, set up the following proportion:

3.4 g O₂ / 32 g/mol O₂ = x mol Fe₂O₃ / (2 mol Fe / 4 mol O₂ x 55.85 g/mol Fe)

Solving for x:

x = 3.4/32 x 4/3 x 1/55.85 x 2 = 0.0059 moles Fe₂O₃

Therefore, the theoretical yield of Fe₂O₃ is 0.0059 moles.

From the balanced chemical equation, 4 moles of Fe react with 3 moles of O₂ to produce 2 moles of Fe₂O₃. Therefore, for every 4 moles of Fe that react, expect to produce 2 moles of Fe₂O₃.

Using this information, set up the following proportion:

4 mol Fe / 55.85 g/mol Fe = 0.0059 mol Fe₂O₃ / x

Solving for x:

x = 55.85 x 0.0059 / 4 = 0.082 g Fe

Therefore, the theoretical yield of Fe is 0.082 g.

To calculate the percent yield, use the following formula:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%

Substituting the values calculated:

Percent Yield = (0.0059 mol Fe₂O₃ / 0.082 g Fe) x 100% x (1.5 moles H₂O / 2 moles Fe₂O₃)

Percent Yield = 44.2%

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Gasoline, which is composed of a variety of different liquid hydrocarbons that do not separate as time passes is an example of compound.

A compound is a substance formed by chemical union of two or more ingredients in definite proportions by weight.

A compound is a type of pure substance that does not separate easily via chemical or physical means.

According to this question, gasoline is composed of a variety of different liquid hydrocarbons, which do not separate as time passes.

Gasoline is specifically a liquid consisting of a mixture of refined petroleum hydrocarbons and is mainly used as a motor fuel e.g. petrol.

This suggests that gasoline is an example of a compound because it is made up of several other substances that do not separate readily.

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Answer:

The answer is A.

Explanation:

Universe was smaller and galaxies were closer together in past, galaxy collisions were common in past (distorted galaxies were common in early universe).

The four advantages of die casting over sand casting are: (a) better surface finish, (b) closer tolerances, (d) higher production rates, and (f) mold can be reused.

Die casting provides a better surface finish because the process involves injecting molten metal into a reusable metal mold, which results in a smoother and more uniform surface. In contrast, sand casting uses sand molds, which can create a rougher surface texture.  Closer tolerances are achieved in die casting due to the precision of the metal molds, allowing for more accurate and consistent dimensions in the final product. Sand casting, however, is limited by the less precise nature of the sand molds.

Higher production rates are possible with die casting since the metal molds can be reused multiple times, speeding up the manufacturing process. Sand casting requires the creation of a new sand mold for each casting, which can slow down production. Finally, the reusability of the metal molds in die casting also provides an advantage, as it reduces material waste and lowers overall production costs. Sand casting, on the other hand, requires new molds for each casting, leading to higher material consumption and costs. So therefore (a) better surface finish, (b) closer tolerances, (d) higher production rates, and (f) mold can be reused are Tthe four advantages of die casting over sand casting..

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Answer:

The process in which trace amounts of other elements are added to a material to make it a semiconductor is called doping.

Doping is the process of adding impurities, called dopants, to a semiconductor material in order to create a controlled number of free electrons or holes. The dopants are typically elements that have one more or one less electron than the semiconductor atoms, so they can be easily incorporated into the crystal lattice. The dopants create a region within the semiconductor called a p-type or n-type region, depending on the type of dopant used, which can be used to control the flow of electrical current through the material.

Explanation:

The molarity of the first solution is 0.1698 M, and the molarity of the second solution is 0.291 M.

To calculate the molarity of a solution, we use the formula:

Molarity (M) = moles of solute / liters of solution

Let's calculate the molarity for each solution step-by-step:

1. First solution:
Given: moles of NaOH = 0.450 mol
Volume of solution = 2.65 L

Using the formula, we have:
Molarity = 0.450 mol / 2.65 L
Molarity = 0.1698 M

Therefore, the molarity of the first solution is 0.1698 M.

2. Second solution:
Given: mass of NaCl = 13.9 g
Volume of solution = 817 mL = 0.817 L (convert mL to L)

First, we need to convert mass of NaCl to moles:
Moles = mass / molar mass
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol (Na = 22.99 g/mol, Cl = 35.45 g/mol)
Moles = 13.9 g / 58.44 g/mol
Moles = 0.238 mol

Now, we can calculate the molarity using the formula:
Molarity = 0.238 mol / 0.817 L
Molarity = 0.291 M

Therefore, the molarity of the second solution is 0.291 M.

In summary, the molarity of the first solution is 0.1698 M, and the molarity of the second solution is 0.291 M.

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Answer:

it have more more mass, gravitational potential energy

Explanation:

The molecular geometry based on the description of bonding and lone pairs are as follows:

- Three double bonds and no lone pairs of electrons: linear

- Four single bonds and no lone pairs of electrons: tetrahedral

- Two double bonds and no lone pairs of electrons: bent/angular

- Three single bonds and one lone pair of electrons: trigonal pyramidal

- Five single bonds and no lone pairs of electrons: trigonal bipyramidal

- Six single bonds and no lone pairs of electrons: octahedral

- Two single bonds and two lone pairs of electrons: bent/angular

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Answer:

No because if there was an attraction hydrogen would not do it's function

Answer:

Electrons occupy the regions around the nucleus(energy levels) while protons and neutrons are found in the nucleus

The balanced redox reaction in basic solution is:

3(C2O42-) + 5H2O + 2(ClO3-) → 6CO2 + 2ClO2 + 4OH-

To balance the redox reaction in basic solution, we need to follow the steps of balancing half-reactions and then balancing the overall reaction.

First, let's balance the oxidation half-reaction, which involves the conversion of C2O42- to CO2:

C2O42- → 2CO2

To balance the carbon atoms, we need a coefficient of 2 in front of CO2:

C2O42- → 2CO2 + 2e-

Next, let's balance the reduction half-reaction, which involves the conversion of ClO3- to ClO2:

ClO3- → ClO2

To balance the oxygen atoms, we need to add H2O to the left side:

ClO3- + H2O → ClO2

To balance the charge, we add electrons (e-) to the left side:

ClO3- + H2O + 2e- → ClO2

Now, let's balance the overall reaction by multiplying each half-reaction by appropriate coefficients to make the number of electrons equal:

3(C2O42-) + 3H2O → 6CO2 + 6e-

2(ClO3-) + 2H2O + 4e- → 2ClO2

Now, we can combine the two half-reactions:

3(C2O42-) + 3H2O + 2(ClO3-) + 2H2O + 4e- → 6CO2 + 6e- + 2ClO2

Simplifying the equation:

3(C2O42-) + 5H2O + 2(ClO3-) → 6CO2 + 2ClO2 + 4OH-

Finally, in basic solution, we need to add OH- ions to balance the hydrogen atoms.

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Answer:

Overall charge of the helium atom is zero

Explanation:

this is because we know the charge of an electron is -1 and the charge of a proton is +1.

there is 2 electrons and 2 protons therefore the charges cancel out.

Therefore the charge of a helium atom is zero

( u can also visualize this as -2+2=0 )

Answer:

Human climate drivers include heat-trapping emissions from burning coal, gas and oil in power plants and cars; cutting down and burning forests; tiny pollution particles (aerosols); black carbon pollution more commonly referred to as soot; and changes in land use that also affects Earth's albedo.

Explanation:

The burning of fossil fuels or even driving a car can lead to global warming. This is due to the greenhouse gases released in the air from these activities. This is even primarily why electric cars were invented. Deforestation can also lead to global warming due to less plants absorbing carbon dioxide.

Answer:

262.8577 g/mol

Explanation:

The molar mass and molecular weight of Mg3O8P2 is 262.858.

Answer:

The molar mass and molecular weight of Mg3O8P2 is 262.858.

Explanation:

Answer:

\(m_{undissolved}=27g\)

Explanation:

Hello,

In this case, we first define the solubility as the maximum amount of a solute that is completely dissolved in an specific amount of solvent and it is temperature-dependent. Thus for potassium iodide, its solubility at 30°C is 153 g per 100 cm3 of water, therefore, with the given amount, the undissolved amount results:

\(m_{undissolved}=180g-153g=27g\)

Best regards.