a large volume of 0.1750 m h2so3(aq)0.1750 m h2so3(aq) is treated with enough naoh(s)naoh(s) to adjust the ph of the solution to 5.495.49 . assuming that the addition of naoh(s)naoh(s) does not significantly affect the volume of the solution, calculate the final molar concentrations of h2so3(aq)h2so3(aq) , hso−3(aq)hso3−(aq) , and so2−3(aq)so32−(aq) in solution given that the Ka1ka1 and Ka2ka2 values are 1.50×10−21.50×10−2 and 1.20×10−71.20×10−7 , respectively.

The mole fraction of gas b is 0.457, which corresponds to answer choice (c).

To find the mole fraction of gas b, we need to first calculate the total pressure inside the vessel. This can be done by adding the partial pressures of gas a and gas b:

Total pressure = Partial pressure of gas a + Partial pressure of gas b
Total pressure = 7.00 atm + 5.89 atm
Total pressure = 12.89 atm

Next, we can use the mole fraction formula to calculate the mole fraction of gas b:

At 25.0°C, a 10.00 L vessel is filled with 7.00 atm of gas A and 5.89 atm of gas B. To find the mole fraction of gas B, you'll need to use the formula:

Mole fraction of gas b = (Partial pressure of gas b) / (Total pressure)
Mole fraction of gas b = 5.89 atm / 12.89 atm
Mole fraction of gas b = 0.457

So, the mole fraction of gas B is 0.457.

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To prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.The ratio of benzoic acid to sodium benzoate in the buffer solution using the Henderson-Hasselbalch equation.

To prepare a pH 4.00 buffer solution using benzoic acid and sodium benzoate, we need to calculate the appropriate volumes of the 0.100 M benzoic acid and 0.240 M sodium benzoate solutions.

First, we need to determine the ratio of benzoic acid to sodium benzoate in the buffer solution. The Henderson-Hasselbalch equation can help us with this calculation:

pH = pKa + log([A-]/[HA])

Given that the pH is 4.00 and pKa is 4.20, we can rearrange the equation:

log([A-]/[HA]) = pH - pKa

log([A-]/[HA]) = 4.00 - 4.20

log([A-]/[HA]) = -0.20

Next, we take the antilog of -0.20 to find the ratio of [A-] to [HA]:

[A-]/[HA] = antilog(-0.20)

[A-]/[HA] = 0.63

The ratio of [A-] to [HA] is 0.63.

Now, let's calculate the volumes of each solution needed. Let's assume x represents the volume (in mL) of the 0.100 M benzoic acid solution and y represents the volume (in mL) of the 0.240 M sodium benzoate solution.

Since the total volume is 100.0 mL, we have the equation: x + y = 100

Considering the ratio of [A-] to [HA] as 0.63, we can write the equation: y/x = 0.63

Solving these two equations simultaneously will give us the volumes of each solution:

x + y = 100

y/x = 0.63

By substituting y = 0.63x from the second equation into the first equation, we get:

x + 0.63x = 100

1.63x = 100

x = 61.35 mL (rounded to two decimal places)

Substituting this value back into the equation x + y = 100, we find:

61.35 + y = 100

y = 38.65 mL (rounded to two decimal places)

Therefore, to prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.

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Explanation:

False, gray whales average 75 miles per day at a speed of 5 mph and is the longest annual migration of any mammal.

Answer:

That would be speed.

Explanation:

So, the concentration of [OH⁻] is approximately 3.77 × 10⁻¹¹ M. To find [oh¯],

we can use the equation for the ion product constant of water (Kw): Kw = [H3O+][OH¯], At 25°C, Kw is equal to 1.0 × 10^-14. So, if [H3O+] = 2.65 × 10^-4 M,

we can rearrange the equation to solve for [OH¯]: [OH¯] = Kw/[H3O+]
[OH¯] = 1.0 × 10^-14/2.65 × 10^-4
[OH¯] = 3.77 × 10^-11 M

Therefore, [OH¯] is 3.77 × 10^-11 M.

To find the concentration of [OH⁻] when given the concentration of [H₃O⁺], we can use the ion product constant of water (Kw) formula. The Kw formula is: Kw = [H₃O⁺] × [OH⁻]

Kw is always equal to 1.0 × 10⁻¹⁴ at 25°C. We are given [H₃O⁺] = 2.65 × 10⁻⁴ M. Now, we can solve for [OH⁻]: 1.0 × 10⁻¹⁴ = (2.65 × 10⁻⁴) × [OH⁻]
To find [OH⁻], divide both sides by (2.65 × 10⁻⁴): [OH⁻] = (1.0 × 10⁻¹⁴) / (2.65 × 10⁻⁴), [OH⁻] ≈ 3.77 × 10⁻¹¹ M

So, the concentration of [OH⁻] is approximately 3.77 × 10⁻¹¹ M.

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Answer: False

Explanation:

Answer:

Bro,it's  number A

+3

Explanation:

The oxidation number for chlorine in HClO2 is plus three because oxygen is more electronegative than chlorine and is assigned negative two for each oxygen and hydrogen had a plus one. The sum of oxidation numbers is equal to the charge on the molecule, in this case zero.

The conditions of temperature and pressure in which a sample of CO₂ (g) would behave least like an ideal gas are high temperature and high pressure; 150°C and 300 kPa, option C

An ideal gas is any gas whose molecules obey the gas law and whose behavior follows the ideal gas behavior.

The behavior of ideal gases is as follows:

For a given gas to behave as an ideal gas, it must be under conditions of extremely high temperatures and low pressure.

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Answer:

2 in front of the H and O for number 21

2 in vfront of the Ag as the left aside of the equation

1 in front of everything for 23

1 in front of everything for 24

Explanation:

Answer:

32

Explanation:

0.80 x 40= 32

density = mass/volume

mass= density x volume

Answer:

dont get it wet or it wont work at all

Answer:

False

Explanation:

Given:

Temperature (T1) = 22°C

Pressure (P1) = 0.98

Volume (V1) = 5.8 ml

New Temperature (T2) = 45°C

New Pressure (P2) = 0.613

New Volume (V2) = 10 ml

Computation:

P1V1 / T1 = P2V2/ T2

(0.98)(5.8) / (22) = (0.613)(10) / (45)

0.258 = 0.136

So,

False

The complete, balanced chemical reaction for the reaction between gold (Au) and selenic acid (H2SeO4) is: 4Au + 3H2SeO4 → 2Au2(SeO4)3 + H2SO3 + H2O. The coefficients for the reactants and products are as follows: 4 for Au, 3 for H2SeO4, 2 for Au2(SeO4)3, 1 for H2SO3, and 1 for H2O. The type of chemical reaction is a single displacement reaction.

The balanced chemical equation for the reaction between gold (Au) and selenic acid (H2SeO4) is:

4Au + 3H2SeO4 → 2Au2(SeO4)3 + H2SO3 + H2O

In this equation, the coefficient in front of Au is 4, indicating that 4 moles of gold are involved in the reaction. The coefficient in front of H2SeO4 is 3, indicating that 3 moles of selenic acid are present.

On the product side, the coefficient in front of Au2(SeO4)3 is 2, indicating the formation of 2 moles of gold selenate. The coefficient in front of H2SO3 is 1, representing the formation of 1 mole of sulfurous acid. The coefficient in front of H2O is also 1, indicating the production of 1 mole of water.

Based on the reactants and products involved, the type of chemical reaction is a single displacement reaction, as gold displaces hydrogen in selenic acid to form gold selenate.

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The maximum energy of the UV photons generated by this plasma pencil is approximately\(9.945 x 10^-19 Joules\).

To find the maximum energy of the UV photons generated by this plasma pencil, you need to use the given wavelength range (lambda = 200-300 nm) and the provided constants (speed of light, c = 3.0 x 10^8 m/s and Planck's constant, \(h = 6.63 x 10^-34 J.s\)).

Step 1: Convert the wavelength range to meters by multiplying with 10^-9 (since 1 nm = 10^-9 m). This gives you a range of \(200 x 10^-9 m to 300 x 10^-9 m.\)
Step 2: To find the maximum energy, use the minimum wavelength (200 x 10^-9 m), since energy is inversely proportional to the wavelength.

Step 3: Use the energy formula:\(E = h * c / lambda\).

In this case, E =\((6.63 x 10^-34 J.s) * (3.0 x 10^8 m/s) / (200 x 10^-9 m)\).

Step 4: Calculate the energy:\(E ≈ 9.945 x 10^-19 J\).

The maximum energy of the UV photons generated by this plasma pencil is approximately 9.945 x 10^-19 Joules.

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Answer:

D. 5 frogs/sq meter

Explanation:

Answer:

a) Hydrogen and Fluorine

b) Lithium and Oxygen

c) Potassium and Phosphorus

d) Nickel and Oxygen

e) Mercury and Chlorine

Explanation:

The capital letters in the compounds represent a single element, while some elements have one capital letter and one small letter after it.

a) H & F

b) Li & O

c) K & P

d) Ni & O

e) Hg & Cl

a) The better solvent for NaCl solute is H₂O.

b) The better solvent for HOCH₂CH₂OH solute is CH₃CH₂OH.

c) The better solvent for HOCOCH₂COCH₂OH solute is CH₃COCH(CH₃)₂.

The solubility of a substance means maximum solute dissolved properly in specific amount of solvent. "Like dissolves like" is an important pharse used by chemists to remember the solubility of solute in solvents. depends on the fact that it "dissolves". This means that polar solvents dissolve polar substances and non-polar solvents dissolve non-polar substances. Since benzene is a non-polar solvent, it is a polar compound that dissolves in polar solvents such as water. The way to check solubility of solute in solvent is present in above figure. Now, first solute is sodium chloride, NaCl which is polar in nature due to presence of lone pairs on chlorine atom. So, it is soluble in polar solvent. Thus, H₂O is right. In case of second solute, HOCH₂ CH₂OH , polar molecule is soluble in polar i.e., CH₃CH₂OH. The last solute is HOCOCH₂ COCH₂OH is non-polar molecule so it is soluble in non-polar i.e., CH₃COCH(CH₃)₂.

Hence, we got all required solvents for solutes.

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Complete question:

For each solute click the button under the better solvent: Which is the better solvent? solute NaCl --> CH₃(CH₂)₄OH ; H₂O

b)HOCH₂CH₂OH --> CH₃CH₂OH ; CH₃(CH₂)₅OH

c) HOCOCH₂COCH₂OH --> CH₃COCH(CH₃)₂; CH₃OH

Answer:

second one... maybe

hope it helps :-)

Answer:

Carrying capacity is the number of organisms that an ecosystem can sustainably support. To determine it on a graph you need to locate the point on the graph where the population line is horizontal.

Explanation:

Answer:

This strand contains nucleotides that are complementary to those in the template sequence. Base pairing ensures that the sequence of nucleotides in the existing template strand is exactly matched to a complementary sequence in the new strand, also known as the anti-sequence of the template strand

Answer:

Generally the internal filling volume needs to be a higher volume level than the external volume level of the sample while the probe is submerged at all times.

Explanation:

Hope this helps you!

1.567 g of solute is needed to make 3450 ml of a 2.25 M solution of Ca(NO3)2.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.

Molarity (M), which is determined by dividing the solute's mass in moles by the volume of the solution in liters, is the most widely used unit to express solution concentration: liters of solution/moles of solute equals M. One liter of a solution with a 1.00 molar concentration (1.00 M) contains 1.00 moles of solute.

No. of moles of NO₃⁻ = (0.1528 mol/L) × (125.00/1000 L) = 0.0191 mol

Each mole of Ca(NO₃)₂ contains 2 moles of NO₃⁻.

No. of moles of Ca(NO₃)₂ = (0.0191 mol) × (1/2) = 0.00955 mol

Molar mass of Ca(NO₃)₂ = (40.078 + 14.007×2 + 15.999×6) g/mol = 164.086 g/mol

Mass of Ca(NO₃)₂ required = (0.00955 mol) × (164.086 g/mol) = 1.567 g

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Humidity refers to the amount of water vapor in the air accurately describes it.

This can be defined as the gaseous phase of water as a result of heating in the atmosphere.

The amount of the water vapor in air is what is referred to as humidity which makes option D the most appropriate choice.

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Formulate an argument for or against nuclear power it should be well thought-out and a minimum of seven complete sentences and they are water intensive and environmental impact

Nuclear power is the clean and efficient way of boiling water to make stream and which turn turbined to produce electricity and the nuclear power plant use enriched uranium fuel to produce electricity through process called fission

And the argument against nuclear power is

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10g is the mass (in grams) of KCl needed to prepare 200.0 mL of a 5.000% (m/v) solution of KCl in water.

A body's mass is an inherent quality. Prior to the discoveries of the atom or particle physics, it was widely considered to be tied to the amount of matter within a physical body.

It was discovered that, despite having the same quantity of matter in theory, different atoms and elementary particles have varied masses. There are various conceptions of mass in contemporary physics that are theoretically different but physically equivalent.

mass/volume×100 = 5.000

mass/ 200.0×100 = 5.000

mass =5.000×200.0/100

          = 10g

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The different chemicals emit different colors of light because it will depends on the energy of the photons emitted.

The color of the light emitted will depends on the energy of the photons that is emitted. The emission of the photons take place when the electron jump from the higher energy state to the lower energy state. When the electrons comes to the lower energy state it will emits photons in form of the light.

The light emitted by the photons are different for the different chemicals because no two elements will have the same set of the energy levels.

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The pH of the solution is obtained is basic pH, hence the solution is a base and it will change the color of Bromocresol from  yellow to blue. Phenolphthalein is colorless in neutral and acidic solution but it gives basic pink color in basic solution.

pH of a solution is the measure of the H+ ion concentration. Mathematically it is negative logarithm of H+ ion or hydronium ion concentration. It measures how acidic or basic the solution is.

The pH of the solution is obtained as 12.2 and hence the solution is basic since pH above 7 is basic solutions.  Bromocresol blue shows the color change from yellow to blue in the pH range of 3 - 5.4. Hence above a pH of 5.4 it shows blue color.

Phenolphthalein shows a color change from 8 - 9.5 pH range from colorless to pink. Hence, it gives pink color for the given solution.

Let AOH be the solution and when it dissociates in water it gives OH- ions as per the Arrhenius theory. Based on this theory we cannot say that it is monoprotic or diprotic ,however it flourish all the OH- ions to water.

\(\rm AOH \rightarrow A^{+} +OH^{-}\)

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B) 1 and 3

it's the right answer

Answer:

For 3rd question, the answer is option D

According to the experiment, the snack provides approximately 50.16 J of energy per gram.

The calorimeter absorbs 2508 J of energy from the snack. To calculate the amount of energy provided by the snack per gram (J/g), we need to know the mass of the snack. Let's say the mass of the snack is m grams.

The formula to calculate energy per gram is:

Energy per gram (J/g) = Total energy absorbed (J) / Mass of the snack (g)

In this case, the total energy absorbed is 2508 J.

So, the equation becomes:

Energy per gram (J/g) = 2508 J / m g

To find the energy per gram, we need to know the mass of the snack in grams. Once we have the mass, we can plug it into the equation to calculate the energy per gram.

For example, if the mass of the snack is 50 grams:

Energy per gram (J/g) = 2508 J / 50 g
Energy per gram (J/g) = 50.16 J/g

So, according to the experiment, the snack provides approximately 50.16 J of energy per gram.

It's important to note that the energy provided by the snack per gram may vary depending on the composition of the snack and the specific calorimeter used in the experiment. The experiment provides a way to measure the energy content of the snack and determine its nutritional value.

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Answer:

compound

Explanation:

A compound is a substance that consists of atoms of two or more various elements such that the atoms are chemically joined together.

For example, water is a compound made up of hydrogen and oxygen.

A material being examined is the same throughout such that the material contains carbon and oxygen that are chemically combined. This material is compound.

Answer:

a

Explanation:

I'll explain along side with potassium (k) and Calcium (Ca). the unit for scandium is SC

Sc = 21

Ca = 20

K =19

k = 1s²,2s²,2p⁶,3s²,3p⁶,3d⁰,4s¹

Ca = 1s²,2s²,2p⁶,3s²,3p⁶,3d⁰,4s²

Sc = 1s²,2s²,2p⁶,3s²,3p⁶,3d¹,4s²

if you notice above Sc has 3d¹ while Ca has 3d⁰. This is because Sc is a transition metal

Transition metals are metals whose d-orbital aré partially filled with electron