a manometer is attached to a sample of gas that occupies a volume of 2.34 liters. the mercury level in arm of the manometer attached to the gas sample is 24.3 torr lower than that of the arm open to the atmosphere. atmospheric pressure is measured to be 1.23 atm. what is the pressure of the sample of gas?group of answer choices23.1 torr25.5 torr911 torr935 torr959 torr

Considering the atomic masses of each of the elements in (NH₄)₂SO₄, its molecular mass is: 132.17 g/mol.

To calculate the molecular mass of (NH₄)₂SO₄, we need to consider the atomic masses of each element in the compound and multiply them by their respective subscripts.

The atomic masses are:

N (Nitrogen) = 14.01 g/mol

H (Hydrogen) = 1.01 g/mol

S (Sulfur) = 32.07 g/mol

O (Oxygen) = 16.00 g/mol

For (NH₄)₂SO₄, we have:

2 Nitrogen atoms (N) = 2 * 14.01 g/mol = 28.02 g/mol

8 Hydrogen atoms (H) = 8 * 1.01 g/mol = 8.08 g/mol

1 Sulfur atom (S) = 1 * 32.07 g/mol = 32.07 g/mol

4 Oxygen atoms (O) = 4 * 16.00 g/mol = 64.00 g/mol

Adding these values together, the molecular mass of (NH₄)₂SO₄ is:

28.02 g/mol + 8.08 g/mol + 32.07 g/mol + 64.00 g/mol = 132.17 g/mol.

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The strength of intermolecular attractions in a pure sample of a compound is determined by several factors, including the size, electronegativity, and polarity of the molecules.

The strongest type of intermolecular attraction is usually hydrogen bonding, followed by dipole-dipole interactions and London dispersion forces.

In order to determine the strongest intermolecular attraction for a specific compound, it is necessary to have information about the chemical structure and properties of the molecules. For example, if the compound contains polar bonds or highly electronegative elements such as nitrogen and oxygen, then hydrogen bonding may be the strongest intermolecular attraction. On the other hand, if the compound contains non-polar bonds or non-polar elements such as carbon and hydrogen, then London dispersion forces may be the strongest intermolecular attraction.

It is important to note that the strength of intermolecular attractions can affect a variety of physical properties, including boiling point, surface tension, and viscosity, among others. Understanding the strength and type of intermolecular attractions in a compound is important for predicting its behavior and properties.

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Answer:

Those photos are a chemical change

The cell potential is 0.94 V.

To find the cell potential of the given cell, we can use the standard reduction potentials from a table.

The half-reactions are:

\(Ag^+ + e^- → Ag E° = +0.80 V\)

\(Sn^2^+ + 2e^- → Sn E° = -0.14 V\)

The overall cell potential (Ecell) can be calculated as sown below.

Ecell = E°cathode - E°anode

Ecell = (+0.80 V) - (-0.14 V)

Ecell = +0.94 V

Therefore, the cell potential of the given cell is +0.94 V.

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Answer:

b)

Explanation:

\(pH = - log[H {}^{ + } ] \\ 2.36 = - log[H {}^{ + } ] \\ [H {}^{ + } ] = {10}^{ - 2.36} \\ [H {}^{ + } ] = 4.37 \times {10}^{ - 3} \: M\)

Answer:

Explanation:

Alexander Fleming's hypothesis was that the juice that was produced by the mold that appeared in the petri dishes was killing the bacteria growing there (streptococcus, meningococcus and the diphtheria bacillus).

Answer:

He thought the mold had released a chemical that prevented the bacteria’s growth.

Explanation:

Gradpoint

Answer:

f = frequency = 590,000 Hz ===> 59×10^4 Hz

λ = Wavelength = ?

c = Speed of light in a vacuum = 3 × 10^8 m/s

** Hz = 1/sec

___o___o___

\(f = \frac{c}{λ} \\ \\ λ = \frac{c}{f} \\ \\ λ = \frac{3 \times {10}^{8} }{590000} \\ \\ λ = \frac{3 \times {10}^{8} }{59 \times {10}^{4} } \\ \\ λ =0.0508 \times {10}^{4} \: m \\ \\ λ = 508 \times {10}^{ - 4} \times {10}^{4} \: m \\ \\ λ = 508 \: m\)

I hope I helped you^_^

Answer: 2.9

Explanation:

Molar mass of Cu(NO3)2 = 187.5 g/mol

Molar mass of water = 18.0 g/mol

%H2O = (5.0 g - 3.9 g) / 5.0 g X 100 (100 is to get percent) = (1.1 g) / 5.0 g X 100

= 22.0 %

% H2O = ( mass of H20 alone) / (mass of total hydrate)

0.22 = 18.0n / (18.0n + 187.5)

n = 2.9 = (about) 3

When a 5.0g sample of Cu(NO₃)₂ . nH₂O is heated, and 3.9g of the anhydrous salt remains. The value of n is 3.

Water mass = Hydrate mass - Anhydrous mass

                    = 5.0 - 3.9

                    = 1.1 g water

Number of moles = \(\frac{\text{Given mass}}{\text{Molar mass}}\)

Now find the moles of H₂O and moles of Cu(NO₃)₂.

Moles of H₂O = \(\frac{\text{Mass of water}}{\text{Molar mass of water}}\)

                       =  \(\frac{1.1\ g}{18\ g/mol}\)

                       = 0.061 moles

Moles of Cu(NO₃)₂ = \(\frac{\text{Mass of}\ Cu(NO_{3})_{2}}{\text{Molar mass of}\ Cu(NO_{3})_{2}}\)

                               = \(\frac{3.9\ g}{187.5\ g/mol}\)

                               = 0.0208 moles

Ratio of moles of H₂O and moles of Cu(NO₃)₂.

= \(\frac{0.061}{0.0208}\)

= 2.9

≈ 3

The value of n is 3. So the formula will be Cu(NO₃)₂ . 3H₂O.

Thus, from above conclusion we can say that when a 5.0g sample of Cu(NO₃)₂ . nH₂O is heated, and 3.9 g of the anhydrous salt remains. The value of n is 3.

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Answer: Mg is a cation and Cl is an anion

Explanation: In more detail, if you look at the periodic table, the group number (or columns) of the elements, describe how many valence electrons, or how many electrons the element has available to have a complete an electron shell. Magnesium being in group 2, it has one 2 electrons that will be "donated" to an anion that it bonds with. However, Chlorine being in group 17, (look at the single digit number for double digit groups), it has 7 valence electrons. Knowing that a full electron shell is usually 8 electrons, it needs only one. Since Magnesium has 2 valence electrons to give away, two atoms of Chlorine gas will then bind to the Magnesium, where the 2 Chlorine atoms will take the electrons to fill their shells. Magnesium Chloride, in terms of charges when in ions, [Mg]2+ and 2 [Cl]-1

Magnesium chloride is formed when magnesium ion formed from the loss of two electrons and two chloride ions formed by accepting one electron each are held together by electrostatic attractive forces.

Magnesium chloride is an ionic compound which consists of magnesium ions and chloride ions.

Therefore, magnesium chloride is formed when magnesium ion formed from the loss of two electrons and two chloride ions formed by accepting one electron each are held together by electrostatic attractive forces.

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The temperature would have to be raised to approximately 8.64 * n Kelvin.

The temperature to which the volume of oxygen must be raised to give a 2atm pressure can be calculated using the Ideal Gas Law:

PV = nRT

where:

P is the pressure (in atm),

V is the volume (in liters),

n is the number of moles of gas,

R is the gas constant (0.0821 Latm/molK),

T is the temperature (in Kelvin).

Given the initial pressure of 760 mmHg, we can convert it to atmospheres:

760 mmHg * 1 atm / 760 mmHg = 1 atm

And given the initial temperature of 15 degrees Celsius, we can convert it to Kelvin:

15°C + 273.15 = 288.15 K

Rearranging the Ideal Gas Law equation for T and solving for the temperature at 2atm:

T = (PV / nR)

T = (2 atm * 356 cm³) / (n * 0.0821 L * atm / mol * K)

T = (2 atm * 356 cm³ * 1 L / 1000 cm³) / (n * 0.0821 L * atm / mol * K)

T = (2 atm * 0.356 L) / (n * 0.0821 L * atm / mol * K)

T = (0.712 L * atm) / (n * 0.0821 L * atm / mol * K)

T = 8.64 * n K

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Answer:

cooling a liquid

Explanation:

Temperature is lowered and the energy of molecules, and therefore number of available configuration , is lowered

The thermal energy present in the system for the product formation is entropy. Cooling a liquid can decrease the entropy of the thermodynamic system. Thus, option C is correct.

Entropy is the energy and the heat present in the reactant of the thermodynamic system that is associated with the randomness and disorder of the particle matter in the reaction system.

Entropy is dependent on factors like dissolution, temperature, randomness, kinetic energy, etc. The entropy increases with an increase in the dissolution and tempearture.

The process of cooling liquid lowers the temperature which in turn decreases the kinetic energy and randomness of the molecules and at last, the entropy decreases.

Therefore, the cooling of the liquid decreases the entropy.

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Answer:

0.25

Explanation:

From the given information:

The dominant trait R = red color; &

The recessive trait r = white

If a heterozygous traits Rr  crosses with a dominant trait RR;

The Punnet square will be as follows:

              R               r

R            RR             Rr

R            RR             Rr

Thus all the flowers are red and there is 50% dominant red rose flowers (RR) and 50% heterozygous red rose flowers (Rr).

Let assume that two heterozygous traits (Rr) cross together; Then the punnet square is:

          R         r

R        RR        Rr

r          Rr        rr

From the above punet square, we have:

0.25 dominant red rose flowers

0.5 heterozygous red rose flowers;

0.25 recessive white rose flowers.

Answer:

Explanation:

Mide 2mL de etanol, añadelo a un matraz aforado, pon agua hasta llegar a 100mL

Answer:2. Mitosis would produce identical daughter cells with the same number as the parent cell. Meiosis would product sex cells with one-half the amount of genetic material as the parent cells.

Explanation:

If a cell has 4 chromosomes at the beginning of meiosis then the daughter cell will have TWO chromosomes at the end of meiosis.

In conclusion, if a cell has 4 chromosomes at the beginning of meiosis then the daughter cell will have TWO chromosomes at the end of meiosis.

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Explanation:

Acidic radical

Acid radical is the ion formed after the removal of Hydrogen ion (H+) from an acid. Example: When H2SO4 loses H+ ion, it forms HSO4− which is an acid radical.

Basic radical

The ion formed after the removal of hydroxide ion (OH−) from a base is known as basic radical.

Answer:

The solubility of gases in a liquid or another gas is a measure of the extent to which the gas can dissolve in the liquid or gas. It is usually expressed as the amount of gas that can dissolve in a given volume of liquid or gas at a specific temperature and pressure. The solubility of gases in a mixture, such as the air in your classroom, can vary depending on the specific gases present and their relative proportions.

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Explanation:

HFO-1234yf has been tested and found compatible with  PAG oil.
The correct answer is option A. PAG oil

PAG oil, or Polyalkylene Glycol, is a fully synthetic hygroscopic oil specifically designed for automotive air conditioner compressors. It is used in R-134a air conditioning systems to lubricate the compressor. When looking at PAG oil you will notice various numbers such as PAG46 or PAG100. These numbers refer to the viscosity of the oil, similar to 10W30 oil. In order to determine the correct PAG viscosity for your vehicle you will need to look up the specifications of your make and model of your vehicle either online or in the instruction manual.

Hence, HFO-1234yf is compatible with PAG oil. It is not compatible with mineral oil, hydraulic oil, or all of the items listed.

The correct answer is option A. PAG oil.
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Shortest wavelength of light that can be emitted by a hydrogen atom is 95.0 nm

Emission is the transfer of electron from higher energy level to lower energy level.

Shortest wavelength is the transition with higher energy.

So,

The electron emits from \($n=5$\) to \($n=1$\) level.

The lowest state is:

\(n_1=1$\\\mathrm{n}_2=5$$\)

The Balmer-Rydberg equation is

\($$\begin{aligned}& \frac{1}{\lambda}=R_{\infty}\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right] \\& \mathrm{n}_2=5 \text { and } \mathrm{n}_1=1 \\& \mathrm{R}=1.097 \times 10^7 \mathrm{~m}^{-1}\end{aligned}$$\)

\(\frac{1}{\lambda}=R_{\infty}\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]$\\\\$\Rightarrow \frac{1}{\lambda}=1.097 \times 10^7 \mathrm{~m}^{-1}\left[\frac{1}{1^2}-\frac{1}{5^2}\right]$\\\\$\Rightarrow \frac{1}{\lambda}=1.097 \times 10^7 \mathrm{~m}^{-1} \times 0.96=10531200 \mathrm{~m}^{-1}$$\lambda\\\\=\frac{1}{10531200 \mathrm{~m}^{-1}}\\\\=9.50 \times 10^{-8} \mathrm{~m}$$\lambda\\\\=95.0 \times 10^{-9} \mathrm{~m}\\\\=\mathbf{9 5 . 0} \mathbf{n m}$\)

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What is the shortest wavelength of light that can be emitted by a hydrogen atom, if the electron is initially in the n=5 level? Give your answer accurate to three significant figures.

We can see that the ion that has a noble gas electron configuration is:

C. \(C^{2-}\)

An ion is an atom or a group of atoms that carries an electric charge. It is formed when an atom gains or loses electrons, resulting in an imbalance between the number of protons (positively charged particles) and electrons (negatively charged particles) in the atom.

When an atom gains one or more electrons, it becomes negatively charged and forms a negative ion, also known as an anion. This occurs because the atom now has more electrons than protons. Anions are represented by a negative sign (-) after the atomic or molecular symbol.

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There are 7.253 x 10^24 H atoms in 17.5 g (NH4)2C2O4.

Avogadro's number is the number of atoms, molecules, or particles in one mole of a substance, which is approximately 6.022 x 10^23.

To determine the number of H atoms in 17.5 g (NH4)2C2O4, we need to first calculate the number of moles of (NH4)2C2O4 using its molar mass and then use the mole ratio between H atoms and (NH4)2C2O4.

The molar mass of (NH4)2C2O4 can be calculated as follows:

Molar mass of NH4 = 14.01 g/mol

Molar mass of C2O4 = 2 * 12.01 g/mol + 4 * 16.00 g/mol = 88.04 g/mol

Molar mass of (NH4)2C2O4 = 2 * molar mass of NH4 + molar mass of C2O4

= 2 * 14.01 g/mol + 88.04 g/mol

= 116.06 g/mol

Number of moles of (NH4)2C2O4 = mass / molar mass

= 17.5 g / 116.06 g/mol

= 0.1507 mol

The mole ratio between H atoms and (NH4)2C2O4 is 8:2, which means that there are 8 H atoms for every 2 (NH4)2C2O4 units. Therefore, we can calculate the number of H atoms as follows:

Number of H atoms = 8 * Avogadro's number * number of moles of (NH4)2C2O4

= 8 * 6.022 x 10^23 * 0.1507

= 7.253 x 10^24 H atoms

Therefore, there are approximately 7.253 x 10^24 H atoms in 17.5 g (NH4)2C2O4.

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In the above intermediate chemical equation, oxygen will appear as follows: O₂(g) as a reactant (option B).

A chemical equation in chemistry is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

According to this question, an intermediate chemical equation is presented as follows:

As observed in the above chemical equation, oxygen will react in its gaseous form i.e. as a reactant.

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Answer:The hydrogen bond is responsible for many of the anomalous physical and chemical properties of compounds of N, O, and F. In particular, intermolecular hydrogen bonding is responsible for the high boiling point of water (100 °C) compared to the other group 16 hydrides that have much weakerhydrogen bonds

Hydrogen bonding is primarily responsible for the high ______ of water.

Answer: About 43 billion tons

Explanation:

This is gonna be quite hard to explain.

Answer:

The element that is the reaction is Pt

Explanation:

Answer:

The answer is pt on edge

Explanation:

The variable part of an amino acid is the e. side chain.

The variable part of an amino acid is known as the side chain or R-group. Amino acids are the building blocks of proteins, and each amino acid consists of a central carbon atom (alpha carbon) bonded to four groups: an amino group (NH2), a carboxyl group (COOH), a hydrogen atom (H), and the side chain.

The side chain is responsible for the unique properties of each amino acid and determines its chemical behavior and interactions within a protein structure.

The side chain plays a crucial role in determining the protein's structure, function, and interactions with other molecules. It can be hydrophilic (water-loving), hydrophobic (water-repellent), or charged, and these characteristics influence how the amino acid interacts with its environment. The side chain's size, shape, and chemical properties dictate the folding and stability of the protein, as well as its ability to interact with other proteins, nucleic acids, or small molecules. Therefore, understanding the side chain's nature is fundamental to comprehending the complex structures and functions of proteins.

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