A meterstick moves past you at great speed. Its motion relative to you is parallel to its long axis. Part A If you measure the length of the moving meterstick to be 1.00 ft (1 ft 0-3048 m)-for example, by comparing it with a 1-ft ruler that is at rest relative to you- -at what speed is the meterstick moving relative to you? Express your answer with the appropriate units.

Answer:

Power is associated by many people with electricity. Knowing that power is the rate of energy use or energy conversion, what is the expression for electric power? Power transmission lines might come to mind. We also think of lightbulbs in terms of their power ratings in watts. Let us compare a 25-W bulb with a 60-W bulb. (See Figure 1(a).) Since both operate on the same voltage, the 60-W bulb must draw more current to have a greater power rating. Thus the 60-W bulb’s resistance must be lower than that of a 25-W bulb. If we increase voltage, we also increase power. For example, when a 25-W bulb that is designed to operate on 120 V is connected to 240 V, it briefly glows very brightly and then burns out. Precisely how are voltage, current, and resistance related to electric power?

Explanation:

Answer: the answer is d $19.95

Explanation:

chicken dinner: 6.95 x 3 = 20.85

burger: 5.75

20.85 + 5.75 = 26.6

26.6 divided by 4 (bc theres 4 ppl and the bill needs to be split equally)

26.6/4= 6.65

and since 3 friends are paying him back u gotta do 6.65 x 3 = 19.95

The statement that correctly describes the direction of conventional current in the circuit is : ( C ) current is directed from A to B to C to D

conventioanl current is simply the flow of protons from the positive terminal of the voltage source ( battery ) to the negative terminal of the battery. Also conventional current is the charge transferred in a given direction per unit time. for a conventional current the charge carrier is irrelevant.

Hence we can conclude that the direction of conventional current in the circuit is : current is directed from A to B to C to D.

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Attached below is the missing part of the question

If two equal forces are acting in opposite directions on an object, the net force is zero.

The net force when two equal forces are acting in opposite directions on an object is zero. Here's a step-by-step explanation:
1. First, identify the magnitudes and directions of the two forces acting on the object. Let's say force F1 acts in the positive direction, and force \(F_2\) acts in the negative direction.
2. Since the forces are equal in magnitude, we can represent them as \(F_1\) = \(F_2\)
3. Net force is the vector sum of all individual forces acting on the object.

In this case, we only have two forces: \(F_1\) and \(F_2\).

To calculate the net force, we can use the formula:

Net Force = \(F_1\) + \(F_2\)
4. As \(F_1\) and \(F_1\) are acting in opposite directions, we need to take into account their directions when calculating the net force.

As \(F_1\) is in the positive direction and \(F_2\) is in the negative direction, the formula becomes:

Net Force = \(F_1\) - \(F_2\)
5. Now, we can substitute the values of \(F_1\) and \(F_2\).

Since \(F_1\) = \(F_2\), the equation becomes:

Net Force = \(F_1\) - \(F_1\).
6. Finally, when we subtract \(F_1\) from itself, the result is zero.

Therefore, the net force is zero when two equal forces are acting in opposite directions on an object.
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Answer:

Answer: action and reaction

Explanation: Newton's 3rd states that action and reaction are equal and opposite in direction. I hope this helps!

Answer:

Reaction

Explanation:

The law states that every action has an equal and opposite reaction

The minimum coefficient of friction between tires and road that will allow cars to take the turn without sliding off the road is 0.078

tan θ = v² / g R

θ = Banking angle

v = Velocity

g = Acceleration due to gravity

R = Radius is banked surface

v = 60 km / h = 16.66 m / s

g = 9.8 m / s²

R = 200 m

tan θ = 16.66² / ( 9.8 * 200 )

tan θ = 0.1416

θ = 8.14°

∑ \(F_{x}\) = m v² / R

N sin θ - \(f_{s}\) cos θ = m v² / R

m g sin θ - μ m g cos θ = m v² / R

( 9.8 * sin 8.14° ) - ( μ * 9.8 * cos 8.14° ) = 40² / 200

1.387 - 9.7 μ = 0.617

0.77 = 9.7 μ

μ = 0.078

Therefore, the minimum coefficient of friction between tires and road is 0.078

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Answer:

Explanation: It's R/n

Answer:A

Explanation:

If a tuning fork starts to vibrate when a certain note is played on the piano. This is an example of: A. resonance.

Resonance is one of the notable properties of sound waves and it can be defined as a phenomenon in which an object such as a turning fork is forced to vibrate as a result of the vibration of a second object (piano) at the same natural frequency of the first object. Thus, the tuning fork begins to vibrate when a certain note (the same natural frequency of the fork) is played on the piano.  

In this context, the frequency of note played on the piano matches the natural frequency of a turning fork, thereby causing it to vibrate.

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Answer:

easy  how you would die from a plastic bag being over your head is by sufacation the oxegen you breath with soon become carbon dioxide and kill you is it gets to your cellular reperation atory

Explanation:

The answer to the question is 1.125  Newton

Formula for electrostatic force is F = ( K q1 q2 )/ r²

where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.

Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.

Electrostatic force between q1 and q3

r will be 0.500 + 0.500 = 1 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²

F₁₃ = 2.25  × 10⁻¹ N

Electrostatic force between q2 and q3

r will be 0.500 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²

F = (225 × 10⁻³) / (25 × 10⁻²)

F₂₃ = 9 × 10⁻¹ N

Total force on q3 will be F₁₃ + F₂₃

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 11.25  × 10⁻¹ ) N

Total force on q3 =  1.125  N

Thus after solving we got the net force on q3 as 1.125  Newton

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Answer:

C. 2.95 grams/cubic centimeter

Explanation:

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

\(Density = \frac{mass}{volume}\)

The standard unit for the measurement of density of a substance is either kilograms per cubic meters or grams per cubic centimeters.

Hence, 2.95 grams/cubic centimeter is a correct measurement of density

The frequency of the violet light is\(7.5 x 10^14 Hz (Hertz).\)

The frequency of the wave is determined by dividing the velocity of light by its wavelength.

\(v=f/λWhere:v = velocity of light f = frequency λ = wavelength of the light\)

The speed of light is\(3.00 x 10^8\) meters per second (m/s).

To convert 400 cm into meters, divide 400 by 100. 400 cm = 4 m

Therefore,λ = 4 meters

Plugging these values into the formula, \(v = (3.00 x 10^8 m/s) / (4 m) = 7.5 x 10^14 Hz\)

So, the frequency of the violet light with a wavelength of \(400 cm is 7.5 x 10^14 Hz.\)

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Answer:

pressure is equals to F/A tge answer is 5pa

Answer:20watts

Explanation:

Answer:

The solution is given below

Explanation:

The computation is shown below;

We know that

Work done = Fs cosθ

But before that we need to determine the force i.e.  

We know that

Force (F) = mass (m) × Acceleration (a)

= 100 × 5

= 500 N

Now,  work done by the go-cart is  

Work done (W) = Fs cosθ

= 500 × 25 × cos(0°)

=  500 × 25 × 1

= 12,500 J

Small stars have a longer and less dramatic life cycle than large stars. They gradually expand and cool as they run out of fuel, eventually becoming white dwarfs. Large stars, on the other hand, go through a more explosive and shorter life cycle, culminating in a supernova that can create neutron stars or black holes.

Small and large stars have different life cycles because they have different masses, which affects their gravitational forces and the fusion processes that occur in their cores.

Here's a comparison of their life cycles:

Small Stars:

Protostar: A cloud of gas and dust collapses under its own gravity, forming a dense, hot core.

Main Sequence: Nuclear fusion of hydrogen in the core produces energy, which counteracts the force of gravity and keeps the star stable. This phase can last for billions of years.

Large Stars:

Protostar: A cloud of gas and dust collapses under its own gravity, forming a dense, hot core.

Main Sequence: Nuclear fusion of hydrogen in the core produces energy, which counteracts the force of gravity and keeps the star stable. This phase can last for millions of years.

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Answer: I observed that the electric field strength is the same at all points between the plates. The value of the field is 70 volts per meter. This is exactly 100 times the applied voltage. The electric field lines point from the positive plate to the negative plate, as the downward arrow on the detector shows.

Explanation:

the sample answer, don't directly copy it!

Initial temperature (I.T.) is described in 21 CFR 113.3(l) as the average temperature of the contents of the coldest container to be processed at the start of the thermal processing cycle, as determined following thorough stirring or shaking of the filled and sealed container.

To calculate the final heat of your substance, add the temperature change to the starting point. If your water started off at 24 degrees Celsius, for instance, the end temperature would be 24 + 6, or 30 degrees Celsius. Where the velocity is unknown, one uses the equation: KE=12mv2 K E = 1 2 m v 2 to calculate the initial kinetic energy. The final Potential Energy is calculated using the formula: PE=mgh P E = m g h, where h is the height of 50 meters.

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The only way to ensure that power is off in a system, circuit, or equipment is by using a lockout/tag-out (LOTO) procedure.

Lockout/tag-out (LOTO) is a procedure that ensures the safety of the people who operate equipment. In particular, it ensures that no hazardous energy can reach the equipment. In general, hazardous energy refers to electrical, thermal, mechanical, pneumatic, chemical, and hydraulic energy.

Lockout/Tag-out Steps

Step 1: Notify Workers: Before shutting down machinery or equipment, notify workers who will be affected.

Step 2: Prepare for Shutdown: The person who is responsible for shutting down the machinery or equipment must turn off the main switch. All energy isolating devices must be located and activated.

Step 3: Isolate Energy Sources: Isolate all sources of energy, such as electrical, thermal, mechanical, pneumatic, chemical, and hydraulic energy. Make sure to isolate all power sources by disconnecting them.

Step 4: Lockout: All switches, valves, and energy isolation devices must be locked out. Then attach lockout devices, tag-outs, or other safety devices to them. This prevents the accidental start-up of machines or equipment that might occur when workers are not paying attention.

Step 5: Release Stored Energy: Before working on machinery or equipment, make sure to release any stored energy. For example, electrical capacitors, hydraulic systems, and mechanical springs are all energy storage devices.

Step 6: Verify the Isolation: Once all energy sources have been isolated, the last step is to verify that they are isolated. This is done by testing equipment to ensure it cannot be started.

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1. The Schrödinger equation is a fundamental equation in quantum mechanics that describes the behavior of particles. The general solution represents the wave function of a particle and provides information about its position and momentum.

3.Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically.

1. The Schrödinger equation is a partial differential equation that was developed by Erwin Schrödinger in 1925 as a mathematical formulation of quantum mechanics. It describes how the wave function of a particle evolves over time. The equation takes the form:

Ĥψ = Eψ

Where Ĥ is the Hamiltonian operator, ψ is the wave function, E is the energy of the particle, and Ĥψ represents the operation of the Hamiltonian on the wave function.

The general solution to the Schrödinger equation represents the wave function of a particle. The wave function provides information about the probability distribution of the particle's position and momentum. It contains both real and imaginary components and is typically represented as a complex-valued function.

The wave function, ψ, can be written as a product of a spatial part and a temporal part:

ψ(x, t) = Ψ(x) * Φ(t)

The spatial part, Ψ(x), represents the probability amplitude of finding the particle at position x, while the temporal part, Φ(t), describes how the wave function evolves over time.

The Schrödinger equation and its general solution are essential tools in quantum mechanics, as they allow us to predict the behavior of particles on a microscopic scale. By solving the equation, we can determine the wave function of a particle and calculate probabilities associated with its position and momentum.

2.Case 1: Particle in a Box

In the case of a particle confined to a one-dimensional box, the potential energy is zero within the box and infinite outside of it. This situation can be represented by the following potential function:

V(x) = 0,  0 < x < L

V(x) = ∞,  x ≤ 0 or x ≥ L

To solve the Schrödinger equation for this case, we need to find the wave function (Ψ) and the corresponding energy levels (E). The general form of the wave function inside the box is given by:

Ψ(x) = A * sin(kx)

Where A is a normalization constant, and k = (2π/L).

Applying the boundary conditions, we find that the wave function must go to zero at both ends of the box (x = 0 and x = L). This leads to the quantization of the wave vector k:

k = nπ/L,  where n = 1, 2, 3, ...

The corresponding energy levels are given by:

E = (ħ²π²/2mL²) * n²

Where ħ is the reduced Planck's constant and m is the mass of the particle.

Case 2: Harmonic Oscillator

In the case of a particle in a harmonic oscillator potential, the potential energy can be described by:

V(x) = (1/2)kx²

Where k is the spring constant. To solve the Schrödinger equation for this potential, we use the harmonic oscillator equation:

- (ħ²/2m) * (d²Ψ/dx²) + (1/2)kx²Ψ = EΨ

The solutions to this equation are given by Hermite polynomials, and the corresponding energy levels are quantized. The wave function for the harmonic oscillator potential can be expressed as a product of a Gaussian function and a Hermite polynomial:

Ψ(x) = (A/π)\(^{(1/4)\) * exp(-αx²/2) * Hₙ(√αx)

Where A is a normalization constant, α = (√(mk/ħ)), and Hₙ is the Hermite polynomial of degree n.

The energy levels in the harmonic oscillator potential are given by:

E = (n + 1/2)ħω

Where n = 0, 1, 2, ... and ω = (√(k/m)) is the angular frequency of the oscillator.

These solutions provide insights into the behavior of electrons traveling in these potential systems, including the quantization of energy levels and the spatial distribution of the wave functions.

3. Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically. This effect arises from the wave nature of particles, as described by the Schrödinger equation.

Tunneling has important implications in various areas of physics, such as nuclear fusion, quantum computing, and scanning tunneling microscopy. It allows for phenomena such as alpha decay, where alpha particles escape from atomic nuclei, and the operation of tunneling diodes in electronic devices.

Overall, tunneling is a fascinating quantum mechanical phenomenon that challenges our classical intuition and plays a crucial role in understanding the behavior of particles in the presence of potential barriers.

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The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.

According to the definition of vector sum and vectors in rectangular form, we must solve the following vector equation:

(0, 0) = 205 · (cos 23°, - sin 23°) + v · (- cos 75°, sin 75°) + u · (- cos 55°, - sin 55°)

(0, 0) = (188.703, 80.100) + v · (- 0.259, 0.966) + u · (- 0.574, 0.819)

(- 188.703, - 80.100) =  v · (- 0.259, 0.966) + u · (- 0.574, 0.819)

Then, we must solve the following system of linear equations:

- 0.259 · v - 0.574 · u = - 188.703

0.966 · v + 0.819 · u = - 80.100

The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.

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The atmosphere supports a column of mercury with a height of 760 mm. Supports a 32 m high water column. And, of course, that's why we fill the barometer with mercury instead of water or alcohol.

The vapor pressure of mercury is also minimal. Therefore, the pressure at the exit point is equal to atmospheric pressure. This pressure is therefore equal to 10 to the power of 5 times 1.1. The base area of ​​this water cube is 12" x 12" = 144 square inches. So, the pressure at the bottom of the water cube is 62.4 pounds / 144 square inches = 0.433 pounds per square inch (psi). The RCC column minimum size is 9" x 9" and incorporates four 12mm bars steel stiffeners and cleats of 8mm steel rings spaced 150mm center to center.

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Answer:

12N

Explanation:

By Newton second law force is the product of the mass of the object times it's acceleration. That makes it \(2\cdot 6 kg \cdot m/s^2 = 12 N\)

i. The gravitational force between the earth and sun can be obtained as follow:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 5.987×10²⁴ × 1.989×10³⁰) / (1.5×10¹¹)²

F = 3.53×10²² N

Thus, the gravitational force between the earth and sun is 3.53×10²² N

ii. The gravitational force between the earth and moon can be obtained as follow:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 5.987×10²⁴ × 7.347×10²²) / (3.844×10⁸)²

F = 1.99×10²⁰ N

Thus, the gravitational force between the earth and moon is 1.99×10²⁰ N

Comparison = G₁ / G₂

G₁ / G₂ = 3.53×10²² / 1.99×10²⁰

G₁ / G₂ = 177

Cross multiply

G₁ = G₂ × 177

Thus, we can say that the gravitational force between the earth and sun is 177 times bigger than the gravitational force between the earth and moon

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Answer:

The equivalent resistance of the combination is R/100

Explanation:

Parallel Connection of Resistances

If resistances R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:

\(\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}\)

The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.

It's known the 10 parts or resistance R/10 were connected in parallel, thus the electric resistance is:

\(\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}+...+\frac{1}{R/10}\)

Note the sum consists of 10 equal terms. Operating on each term:

\(\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}\)

The sum of 10 identical fractions yields 10 times each fraction:

\(\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}\)

Solving for Re needs to take the reciprocal of both sides of the equation:

\(R_e=R/100\)

The equivalent resistance of the combination is R/100

To determine the amount of energy lost as respiration by an insect population, we need to consider several factors, including the metabolic rate and respiration efficiency of the insects, as well as the population size and activity level.

Respiration in insects involves the conversion of stored chemical energy (e.g., from food) into usable energy in the form of adenosine triphosphate (ATP) through the process of cellular respiration. However, not all energy obtained from food is converted into ATP. Some energy is lost as heat during the metabolic processes.

The energy lost as respiration can be estimated using the concept of respiratory quotient (RQ), which is the ratio of carbon dioxide produced to oxygen consumed during respiration. Different food sources have different RQ values, and the metabolic rate of insects can vary based on factors such as temperature, activity level, and physiological state.

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123.61KV difference is the electric potential 20 cm from a charge of 5.5 c compared to 40 cm from the same charge.

electric force F=\(\frac{KQq}{r^2}\)

electric potential V=\(\frac{Fr}{Q}\)  

                             V=\(\frac{Fq}{r}\)

this equation we know that \(V\propto \frac{1}{r}\)

the point closer to the charge is higher than the point farther away.

B)   for 20cm

V=\(\frac{kq}{r}\)

V=\(\frac{8.99*10^9*5.5*10^{-6}}{0.2}\)

V=247.25KV

for 40cm

V=\(\frac{8.99*10^9*5.5*10^{-6}}{0.4}\)

V=123.61KV

∴ the difference is 247.25-123.61= 123.61KV

the electric capability (additionally known as the electric discipline capability, potential drop, the electrostatic capacity) is defined as the amount of work strength had to move a unit of electric fee from a reference point to the specific factor in an electric-powered field.

the electric-powered potential is the work done consistent with a unit fee to deliver the rate from infinity to a degree in an electric discipline. the capacity distinction is the distinction between the potentials between two factors within the electric-powered discipline. electric powered ability is described as a factor. In an electrical circuit, the capability between factors (E) is defined as the quantity of labor carried out (W) by using an external agent in shifting a unit fee (Q) from one point to another. Mathematically we will say that E = W/Q.electric-powered capability is a scalar, and electric-powered discipline is a vector. The addition of voltages as numbers offers the voltage due to a combination of point costs, whereas the addition of man or woman fields as vectors offers the full electric-powered subject.

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