A prismatic bar AB of length L and solid circular cross section (diameter d) is loaded by a distributed torque of constant intensity t per unit distance .
(a) Determine the maximum shear stress tmax in the bar
(b) Determine the angle of twist between the ends of the bar.

Answer:

Since a sound wave consists of a repeating pattern of high pressure moving through a medium it is sometimes referred to as a pressure wave

Explanation:

Since a sound wave consists of a repeating pattern of high pressure moving through a medium it is sometimes referred to as a pressure wave

Answer:

A sound wave is a pattern of disturbance caused by the movement of energy.

Pressure Waves may refer to one of the two main types of elastic body waves , called seismic waves in seismology.

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Answer:

B = 2.19*10^-7 T

u = 1.92*10^-18 J/m^3

P = (4pi r^2)cεo E^2

Explanation:

In order to find the magnetic field strength of the electromagnetic wave you use the following formula:

\(B=\frac{E}{c}\)     (1)

B: magnitude of the magnetic field

E: magnitude of the electric field = 65.9V/m

c: speed of light = 3*10^8m/s

\(B=\frac{65.9V/m}{3*10^8m/s}=2.19*10^{-7}T\)

The magnitude of the magnetic field 2.19*10^-7 T

The energy density of the electromagnetic wave is:

\(u=\frac{1}{2}\epsilon_oE^2\)       (2)

εo: dielectric permittivity = 8.85*10^-12C^2/Nm^2

\(u=\frac{1}{2}(8.85*10^{-12}C^2/Nm^2)(65.9V/m)^2=1.92*10^{-8}\frac{J}{m^3}\)

The energy density of the electromagnetic wave is 1.92*10^-8J/m^3

The power is given by:

\(P=IA=c\epsilon_oE^2(4\pi r^2)\)

The final velocity after 6.0 s is

1304.2 .

What is velocity?

velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.

Solution -

As per the given-

Mass of runner m = 74kg

initial velocity of runner u=4.8 m/s

final velocity of runner v =0

Coefficient of friction ¥=0.7

Let's d be the distance moved by runner till the stop.

a- mechanical energy lost due to friction

As friction does negetive work causing the runner to stop.

As we know,

Mechanical energy lost= Kinetic energy of runner

Mechanical energy lost =

1/2 mv^2 = 1/2 ×74×4.8^2=852.2

Distance move by runner-

Work done by friction = mechanical energy lost

-¥×mg×d =852.2 j

-0.7×74×9.8×d = -491.2

Solving the equation we get

1304.2.

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Answer:

un café y a seguir pensando porque no se la respuesta xd

Answer:

microwave

Explanation:

Answer: 3

Explanation:

khan academy

Answer:

Acidity

Explanation:

pH measures how acidic or basic a substance is.

Answer:

a) Acidity

Answer:

change on velocity..........

Answer:

change in velocity

Explanation:

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When the thistle funnel is moved upwards towards the surface of the liquids, the height (h) decrease.

What happens when the thistle funnel is moved upward?

An important principle outlined by Pascal's law states that any fluid (in this instance, liquids) experiences equal transmission of force in every direction within it. Hence, there is an intimate relationship between the height of a liquid column and its pressure.

Raising a thistle funnel reduces this height causing loss of weight from above this point thus decreasing its pressure.

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See complete question in the attached image.

Answer:

18.9s

Explanation:

Using the formula;

ω = v/r

Where;

ω = angular velocity (rad/s)

v = linear velocity (m/s)

r = radius of the circular track (m)

According to the given information, v = 30m/s, r = 90m

ω = v/r

ω = 30/90

ω = 3/9

ω = 0.3333 radians/seconds.

Since ω = 2π/T

Where;

π = 3.142

T = period (s)

ω = angular velocity

0.333 = 2 × 3.142/T

T = 2 × 3.142/0.333

T = 6.284/0.333

T = 18.87s

T = 18.9s

The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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The true statement is that the acceleration in the first two seconds is 6 m/s^2.

The term acceleration is defined as the rate of change of velocity with time. The graph as shown is a velocity time graph. The graph shows the changes that occur in the velocity over a given time interval.

Now  we have;

Initial velocity = 0 m/s

Final velocity = 12 m/s

Time taken = 2s

Acceleration = 12 - 0/2

= 6 m/s^2

Thus the true statement is that the acceleration in the first two seconds is 6 m/s^2.

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Answer:

Ice and Rock

Explanation:

There's also dust and sand mixed up

The vehicle has a 2000kg mass.

Take a mass's acceleration into account. Use the formula F = m a to determine the force's value. Kilogram-meter/second-squared will be used as the unit of force. The short name for this unit, which is made up of the three basic SI units, is newton.

F= ma

m= F/a

m= 50000/25

m= 2000 kg

According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force acts on a mass (object). This law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. The force that propels you forward on your bicycle comes from your leg muscles.

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Answer:

A high EQ (emotional intelligence)

In today's transitioning workplace, having a high EQ is the most important trait of a good boss. Bosses must be able to discern between their own personal beliefs and the thoughts and beliefs of others, and other generations (boomers, Gen X, xennials, millennials and now Gen Z).

Explanation:

hope it helps you

Answer:

To derive the expression for electric field due to an electric dipole, consider AB is an electric dipole of two point charges – q and + q separated by small distance 2d and then consider that P is a point along the axial line of the dipole at a distance r from the midpoint O of the electric dipole.

Formula used: E=1/4π∈∘.q/x²

Electronegativity, symbol χ, measures the tendency of an atom to attract a shared pair of electrons (or electron density). An atom's electronegativity is affected by both its atomic number and the distance at which its valence electrons reside from the charged nucleus.

Answer:

\(3.6\times10^{23} N\)

Explanation:

\(F=\frac{GmM}{r^2}=4\times10^{22} N\)

\(F'=\frac{GmM}{(r/3)^2}=9\frac{GmM}{r^2}=9\times4\times10^{22}=3.6\times10^{23} N\)

if the planet were 3 times closer to the star, the magnitude of the force on the star due to the planet would be \(\( 3.6 \times 10^{23} \, \text{N} \).\)

The gravitational force between two objects is given by Newton's law of universal gravitation:

\(\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \]\)

where:

F is the gravitational force between the two objects,

G is the gravitational constant \((\( G \approx 6.67430 \times 10^{-11} \, \text{m}^3/\text{kg}\cdot\text{s}^2 \)),\)

\(\( m_1 \)\) and \(\( m_2 \)\) are the masses of the two objects, and

r is the distance between the centers of the two objects.

Let's assume the planet is \(\( m_1 \)\) and the star is \(\( m_2 \).\)

Given that the original force is \(\( 4 \times 10^{22} \, \text{N} \)\), we have:

\(\[ F_{\text{original}} = 4 \times 10^{22} \, \text{N} \]\)

Let's denote the original distance between the planet and the star as \(\( r_{\text{original}} \).\)

Now, when the planet is 3 times closer to the star, the new distance \((\( r_{\text{new}} \))\) will be \(\( \frac{1}{3} \)\) of the original distance:

\(\[ r_{\text{new}} = \frac{1}{3} \cdot r_{\text{original}} \]\)

To find the new magnitude of the force \((\( F_{\text{new}} \))\) on the star due to the planet, we use the same formula with the new distance:

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{r_{\text{new}}^2} \]\)

Substitute \(\( r_{\text{new}} \)\) with \(\( \frac{1}{3} \cdot r_{\text{original}} \):\)

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{\left( \frac{1}{3} \cdot r_{\text{original}} \right)^2} \]\)

Simplify the expression:

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{\frac{1}{9} \cdot r_{\text{original}}^2} \]\)

Multiply both the numerator and denominator by 9 to get rid of the fraction:

\(\[ F_{\text{new}} = \frac{9 \cdot G \cdot m_1 \cdot m_2}{r_{\text{original}}^2} \]\)

Now, we can see that \(\( F_{\text{new}} \)\) is simply 9 times the original force \(\( F_{\text{original}} \):\)

\(\[ F_{\text{new}} = 9 \times F_{\text{original}} \]\)

Substitute the value of \(\( F_{\text{original}} \):\)

\(\[ F_{\text{new}} = 9 \times 4 \times 10^{22} \, \text{N} \]\[ F_{\text{new}} = 36 \times 10^{22} \, \text{N} \]\[ F_{\text{new}} = 3.6 \times 10^{23} \, \text{N} \]\)

So, if the planet were 3 times closer to the star, the magnitude of the force on the star due to the planet would be \(\( 3.6 \times 10^{23} \, \text{N} \).\)

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Answer:

measurement of mass means a measure of mass in an object and measurement of length is the distance from one point to another.

Explanation:

i think so lol

Answer:

line graph. A line graph is the best way to show changes in data over time. The geographer can plot the economic growth of one country as a line going up over the 10 years, and the economic decline of the other country as a line going down slightly over the same period. This will allow for a clear visual comparison of the changes in the economies of the two countries over time.

Answer:

fhddmvxmvydlyghclhchc

The current and potential difference in the lumped element model of electrical circuits are dealt with by Kirchhoff's circuit laws, which are two equalities. German scientist Gustav Kirchhoff published the first account of them in 1845. This was done before James Clerk Maxwell and generalized Georg Ohm's work.

Because the sum of the currents entering and leaving the junction is equal, Kirchhoff's first law is based on the conservation of charge. The algebraic sum of potential drops in a closed circuit must equal zero, according to Kirchhoff's second law. Therefore, it is based on energy conservation.

A stream of charged particles—such as electrons or ions—moving through a conductor for electricity or into empty space is known as an electric current. It is determined by measuring the net rate of electric charge flow through a surface or into a control volume.

The amount of resistance in an electrical circuit represents the resistance to current flow. The Greek letter omega (Ω), which stands for resistance, represents ohms.

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In a circular motion the normal force is also called centripetal force. The centripetal force is given by:

where m is the mass, v is the velocity and r is the radius.

Plugging the values given we have:

Answer:

Velocity is a vector whose magnitude is called speed. Collision study needs to analyse the transfer of momentum, which is another vector quantity associated with the velocity vector of each object

Explanation:

The important concept to recall is that velocity is a vector quantity, which has direction apart from just magnitude (as speed is). So in the transfer of momentum (another vector quantity) that takes place in a collision, it is extremely important to know the direction of the velocity vector, since there is much larger transfer of momentum if the cars collide heads on, than if the cars collide from behind while going in the same direction.

Answer:

5

Explanation:

We have that for the Question, it can be said that With respect to this axis, the magnitude of the torque due to the weight and ,the thrust is

From the question we are told

The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 14900 N and acts as shown in the figure. In flight the engine produces a thrust of 61500 N that is parallel to the ground. The rotational axis in the figure is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to (a) the weight and (b) the thrust.

a)

Generally the equation for the Torque due to weight  is mathematically given as

\(TW=Engine weight*2.50*sin32\\\\TW=14900*2.50*sin32\)

TW=19740N-m

b)

Generally the equation for the Torque due to thrust  is mathematically given as

\(TT=Engine thrust*2.50*cos32\\\\TT=61500*2.50*cos32\\\\\)

TT=130387.39N-m

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