a solution contains 0.020 m ca2 and 0.010 m ag . a) can 99% of ca2 be precipitated by sulfate without precipitating ag ?

Answer:

4200

Explanation:

4,000 * .8 + 5,000 * .2

The weighted average of lemonas with 80% GX model and 20 % GXL model is calculated using their mass percent and it is 4200.

What is  weighted average?

The weighted average is different from the normal average we use in maths. Let's X and Y be two number and their average be x+ y/2. That is the arithmetic mean.

The weighted average of lemonas is similar to the atomic weight of an element calculated from ist two isotopes where, the percentage abundance in earth and the mass of isotopes if given the weighted average is calculated as follows:

weighted average =  % abundance / 100 × mass of isotope 1 + % abundance / 100 × mass of isotope 2

In a similar way, the weighted average of lemonas of GX and GXL model is calculated as follows:

weighted average = ( 4000 lbs ×80/100 ) + ( 5000 lbs ×20/100)

                               = 4200 lbs.

Hence, the weighted average of lemonas if 80% are the GX model (4,000 lbs) and 20% are the GXL model is 4200 lbs.

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There are 7.253 x 10^24 H atoms in 17.5 g (NH4)2C2O4.

Avogadro's number is the number of atoms, molecules, or particles in one mole of a substance, which is approximately 6.022 x 10^23.

To determine the number of H atoms in 17.5 g (NH4)2C2O4, we need to first calculate the number of moles of (NH4)2C2O4 using its molar mass and then use the mole ratio between H atoms and (NH4)2C2O4.

The molar mass of (NH4)2C2O4 can be calculated as follows:

Molar mass of NH4 = 14.01 g/mol

Molar mass of C2O4 = 2 * 12.01 g/mol + 4 * 16.00 g/mol = 88.04 g/mol

Molar mass of (NH4)2C2O4 = 2 * molar mass of NH4 + molar mass of C2O4

= 2 * 14.01 g/mol + 88.04 g/mol

= 116.06 g/mol

Number of moles of (NH4)2C2O4 = mass / molar mass

= 17.5 g / 116.06 g/mol

= 0.1507 mol

The mole ratio between H atoms and (NH4)2C2O4 is 8:2, which means that there are 8 H atoms for every 2 (NH4)2C2O4 units. Therefore, we can calculate the number of H atoms as follows:

Number of H atoms = 8 * Avogadro's number * number of moles of (NH4)2C2O4

= 8 * 6.022 x 10^23 * 0.1507

= 7.253 x 10^24 H atoms

Therefore, there are approximately 7.253 x 10^24 H atoms in 17.5 g (NH4)2C2O4.

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Control Experiment: Those experiment where a control is taken as a reference to notice the changes in same reaction in the presence of external stress.

Need for a control in a experiment: The control is required to analyse the effect of stress applied to reaction. For e.g. If there are two compounds AB and XY & they are undergoing displacement reaction to form AX & BY, But all sudden another salt let MN is added into the reaction then there are possibilities of formation of different products depending upon the reactivity of initial reactants and external compound. The product can be same as our Control i.e. AB & XY if MN remains inert in the reaction. That's why control is important to compare the results.

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Answer:

A-Ideas

Explanation:

31.25 °C is the temperature at which a 0.291 m solution of magnesium sulfate in water exhibit an osmotic pressure of 14.0 atm.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points and thermometric substances. The most popular scales are the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), and the Kelvin scale (K), with the latter being mostly used for scientific purposes. One of the International System of Units' (SI) seven base units is the kelvin.

π = MRT

14.0 atm = M(0.08206 L·atm/K·mol)T

M = 214.5/T

0.291 L = moles of solute / 1 L

moles of solute = 0.291 M

moles of \(Mg^2+\) = 2 x moles of MgSO\(_4\)= 2 x 0.291 M = 0.582 M

Π = iMRT

Π = 3 x 0.582 M x (0.08206 L·atm/K·mol) x T

14.0 atm = 0.448 Atm·K·mol/L x T

T = 31.25 °C

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Answer:

Answer above is incorrect

Explanation:

The true answers are B and E on Edge 2020

Hope this helps :)

Answer:

B and E

Explanation:

on edge hope this helps

The name of the compound made of magnesium and fluorine is magnesium fluoride and its formula is MgF2. Magnesium fluoride is a white crystalline solid that has a bitter taste and is insoluble in water. Magnesium fluoride is a stable ionic compound with a high melting point.

This compound is the primary source of magnesium and fluoride ions in many industrial and chemical processes. Magnesium fluoride is produced by the reaction between magnesium oxide and hydrogen fluoride.

MgO + 2HF → MgF2 + H2O

In the laboratory, magnesium fluoride is produced by dissolving magnesium hydroxide in hydrofluoric acid.

Mg(OH)2 + 2HF → MgF2 + 2H2O

Magnesium fluoride is used in the production of ceramics and glass as a flux and to increase the resistance of the glass to attack by acids. Magnesium fluoride is also used as an optical coating on lenses and other optical components as it has a low refractive index.

Magnesium fluoride is a white crystalline solid with a bitter taste that is insoluble in water. It is the primary source of magnesium and fluoride ions in many industrial and chemical processes. The formula of magnesium fluoride is MgF2. It is used in the production of ceramics and glass as a flux and to increase the resistance of the glass to attack by acids. Magnesium fluoride is also used as an optical coating on lenses and other optical components as it has a low refractive index.

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Answer:

hydrogen is a non-metal and it has 1 valence electron

Explanation:

You can find the valence electrons on the bottom left of your periodic table, it is under the atomic number. Hydrogen is a non-metal because hydrogen conducts heat and electricity poorly.

Answer:

1. 0.3457g

2. 7650mL

3. 216000 seconds

4. 10080minutes

5. 2400 seconds

6. 173.99cm

7. 70283.2g

8. 137.16metres

9. 4.968miles

10. 3.105miles

Explanation:

1. 1000mg = 1g

345.7 mg = 345.7/1000

= 0.3457g

2. 1kL = 1000000mL

0.00765 kL = 0.00765 × 1000000

= 7650mL

3. 1 day = 86400s

2.5 days = 2.5 × 86400

= 216000 seconds

4. 1 week = 10080minutes

1.000weeks is equivalent to 1 week, hence there are 10080minutes in 1.000week.

5. 1minute = 60seconds

40.0minutes = 40 × 60

= 2400seconds.

6. 1 inch = 2.54cm

68.5inches = 68.5 × 2.54

= 173.99cm

7. 1Ib = 16oz

155Ibs = 155 × 16

= 2480 oz

1 oz = 28.34 g

2480oz = 2480 × 28.34

= 70283.2g

8. 1 foot = 12 inches

450 feet = 450 × 12

= 5400inches

1 inch = 0.0254metres

5400 inches = 5400 × 0.0254

137.16metres

9. 1 metre = 0.000621 mile

8000 metres = 8000 × 0.000621

= 4.968miles

10. 1 kilometers = 1000 metres

5km = 5 × 1000

= 5000metres

1 metre = 0.000621 mile

5000metres = 5000 × 0.000621

= 3.105miles

Answer:

1 mol

Explanation:

It's about balacing the equation. 2 parts "b" can form 1 part "a". So take 2 mol and divide by 2.

The reaction that occur at the anode of an electrochemical cell is Zn(s) Zn²+ (aq) + 2e. The correct option is B.

An electrochemical cell has two eletcrodes present in an solution. The one electrode is anode where oxidation occurs and second is cathode hwere reduction occurs.

The reaction Zn(s) = Zn²+ (aq) + 2e due to oxidation chrage is added here.

Thus, the correct option is B. Zn(s) = Zn²+ (aq) + 2e.

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The 5s orbital has zero spherical (radial) nodes.

The number of spherical (radial) nodes in an orbital is determined by its principal quantum number (n). The 5s orbital corresponds to the principal quantum number n = 5.

To determine the number of spherical nodes, we subtract 1 from the principal quantum number (n - 1). In this case, since n = 5, we have (5 - 1) = 4. Therefore, the 5s orbital has four spherical nodes.

However, it's important to note that the 5s orbital is unique among the s orbitals because it does not have any spherical (radial) nodes. The term "spherical nodes" refers to regions of zero electron density. In the case of the 5s orbital, the electron density is concentrated towards the center of the atom and decreases radially as we move away from the nucleus, but there are no regions of zero electron density.

The absence of spherical nodes in the 5s orbital is due to its shape, which is spherically symmetric. It is characterized by a single lobe extending from the nucleus, without any nodal planes. This makes the 5s orbital different from the higher energy orbitals with additional radial nodes, such as the 4d or 5p orbitals, which have distinct regions of zero electron density along the radial direction.

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Glucose 6-phosphate → Phosphohexose isomerase binds to glucose 6-phosphate → Isomerization reaction occurs → Fructose 6-phosphate is formed → Fructose 6-phosphate is released.

The correct order of events in the conversion of glucose 6-phosphate to fructose 6-phosphate catalyzed by phosphohexose isomerase is as follows:

1. Glucose 6-phosphate binds to the active site of phosphohexose isomerase.
2. The enzyme catalyzes the isomerization reaction, causing a rearrangement of the carbon skeleton.
3. The resulting product is fructose 6-phosphate.
4. Fructose 6-phosphate is released from the active site of phosphohexose isomerase.

Therefore, the correct order of events is:
Glucose 6-phosphate → Phosphohexose isomerase binds to glucose 6-phosphate → Isomerization reaction occurs → Fructose 6-phosphate is formed → Fructose 6-phosphate is released.

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The skeletal equation for the reaction involving the decomposition of lead (IV) oxide on heating would be; \(2PbO_2 -- > 2PbO + O_2\)

Skeletal equations of reactions are equations showing the chemical formula of the various components of the reactions. In other words, they are equations that show the chemical symbols of all the atoms in the components participating in reactions.

The skeletal equation for lead (IV) oxide is \(PbO_2\)

The skeletal equation for lead (II) oxide is PbO

The skeletal equation for oxygen gas is \(O_2\)

Thus, the skeletal equation for the reaction involving the decomposition of lead (IV) oxide to leave (II) oxide and oxygen gas would be:

\(2PbO_2 -- > 2PbO + O_2\)

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Answer:

c) how sedimentary rock forms

Answer:

3.5 milligram

Explanation:

From;

N/No = (1/2)^t/t1/2

Where;

N = amount of Po-210 that remains unchanged after 414 days

No = 28.0 milligram of Po-210 originally present

t = 414 days

t1/2 = half life of Po-210 = 138 days

Substituting values;

N/28 = (1/2)^414/138

N/28 = (1/2)^3

N/28 = 1/8

8N = 28

N = 28/8

N = 3.5 milligram

C₂H₆, compound has a C-H bond with the lowest bond dissociation energy, hence option A is correct.

Toluene has the lowest bond dissociation energy because it undergoes hyper conjugation with the C-H protons.

The energy needed to break a bond and create two atomic or molecular fragments, each containing one of the original shared pair of electrons, is known as the bond dissociation energy.

As a result, an extremely stable bond has a high bond dissociation energy, meaning additional energy is required to break the binding.

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Answer:

Empirical formula is Na₂CO₃

Molecular formula is Na₂CO₃

Explanation:

Percentage compositions of the elements;

Sodium = 46%

Carbon = 12 %

Oxygen = 42%

To determine empirical formula, we calculate the mole ratio first.

mole ratio =  % mass/atomic mass; where the atomic masses of the elements are :  Na = 23 u, C = 12 u and O = 16 u.

mole ratio: Na = 46/23; C = 12/12; O = 42/16

mole ratio (Na : C : O) = 2 : 1 : 2.6

approximate mole ratio = 2 : 1 :3

Therefore, empirical formula of compound is Na₂CO₃

To determine the molecular formula;

molecular formula or mass = n(empirical formula or mass)

n = molecular mass/empirical mass

molecular mass = 106 u,

empirical mass = 23*2 + 12 + 16*3 = 106 u

then, n = 106/106 = 1

therefore, molecular formula = 1 * (Na₂CO₃) = Na₂CO₃

The limiting reactant is Sulphur,  according to the chemical reaction given in the question.

Let's take the balanced chemical reaction in the question

2S + 3O₂ + 4NaOH → 2Na₂SO₄ + 2H₂O

Here,

We have to identify the limiting reactant when 2.0 g of sulfur reacts with 3.0 g of oxygen and 4.0 g of sodium hydroxide.

First, we need to calculate the moles of each substance, and then we can find out the limiting reactant.

Let's do it one by one.

Mole of sulphur (S) = 2 g/32 g/mol = 0.0625 moles

Moles of Oxygen (O2) = 3 g/32 g/mol = 0.09375 moles

Moles of Sodium Hydroxide(NaOH) = 4g/40g/mol = 0.1 moles

Now, we have to compare the number of moles of each substance to find out the limiting reactant.

Here we can see that the number of moles of sulphur (S) is the least among all the reactants, i.e., 0.0625 moles.

Hence, the limiting reactant is sulfur (S).

Therefore, the correct answer is "sulphur."

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Fluorine accounts for 70.37% of the mass.

To find the percent of the mass that is from fluorine, we need to first find the mass of fluorine in the sample.

Mass of fluorine = Total mass of the sample - Mass of oxygen in the sample

⇒       Mass of fluorine = 0.432 g - 0.128 g = 0.304 g

Now, we can calculate the percent of the mass that is from fluorine using the formula:

% mass of fluorine = (Mass of fluorine / Total mass of the sample) x 100%

⇒      % mass of fluorine = (0.304 g / 0.432 g) x 100% = 70.37%

Therefore, approximately 70.37% of the mass in the sample is from fluorine.

The problem requires us to determine the percentage of the mass that is from fluorine in a sample containing only oxygen and fluorine. To do so, we first need to calculate the mass of fluorine in the sample by subtracting the mass of oxygen from the total mass of the sample. Once we know the mass of fluorine, we can use the formula for percent composition to calculate the percentage of the mass that is from fluorine. This problem emphasizes the importance of knowing how to calculate the percent composition of elements in a given compound or mixture.

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Answer:

Neutrons,Electrons and Protons I think.

Answer:

the basic unit of an ionic compound is called a formula unit and the basic unit of a covalent compound is a molecule.

Answer:

we know that it was the vinegar and baking soda because gas had been created, the gas was held within the bubbles. the gas that was created was called Carbon Dioxide or CO2

For water: q = cmΔT = 4.18 ∙ 150 (32.6 – 22.4) = 6395.4J

For brass: c = q / mΔT = 6395 / 127.68 (163 – 32.6) = 0.384 J / gC

What is water?

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Answer:

Mass and speed

Explanation:

Mass and speed determine the amount of kinetic energy an object has. Mass is an intrinsic property of a body.

Mass refers to an intrinsic property of a body. It was traditionally believed to be related to the quantity of matter in a physical body, until the discovery of the atom and particle physics. It was found that different atoms and different elementary particles, theoretically with the same amount of matter, have nonetheless different masses.

Mass in modern physics has multiple definitions which are conceptually distinct, but physically equivalent. Mass can be experimentally defined as a measure of the body's inertia, meaning the resistance to acceleration when a net force is applied. The object's mass also determines the strength of its gravitational attraction to other bodies. The SI base unit of mass is the kilogram.

In physics, mass is not the same as weight, even though mass is often determined by measuring the object's weight using a spring scale.

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