a stone of mass 6 kg is released from a height of 30 metre calculate the potential energy​

The velocity of the third piece 2/11. (13 j - 15i)

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The largest atom of period 4 is Potassium (K).

One of the chemical elements in the fourth row (or period) of the periodic table of the elements is known as element of period 4. The periodic table is organized into rows to show recurrent (periodic) tendencies in the chemical behavior of the elements as their atomic number rises.

One element is present in each of the eighteen groups, making up the fourth period's 18 elements, which start with potassium and end with krypton. d-block, which includes transition metals, makes its first appearance in the table.

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The LIGO experiment uses a Michelson interferometer with two 4 km arms in an ultra-high vacuum to detect gravitational waves by measuring changes in the intensity of a laser signal at the detector.

The LIGO experiment aims to detect gravitational waves, which are ripples in the fabric of spacetime caused by the acceleration of massive objects.

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The question is -

The LIGO experiment consists of a Michelson interferometer where the two arms of the interferometer are in an ultra-high vacuum. To a very good approximation the refractive index, n, equals 1 in the arms to begin with. The length of each arm is 4 km and the laser used has a wavelength of 1064 nm.

The LIGO scientists work hard to adjust the mirror positions so that the intensity at the detector is maximal. They measure the intensity of the laser signal at the detector to be 20 Watts/m².

Answer:

h = distance up = 50 sin 10

m g h = 800 * 9.81 * 50 sin 10 Joules

Explanation:

Answer:

natural convection

............

Answer:

- They need oxygen to burn fuel

- Aerodynamics

- Extreme temperatures

- Radiation

- Pressure issues

Explanation:

A airplane is a heavier-than-air aircraft kept aloft by the upward thrust exerted by the passing air on its fixed wings and driven by propellers, jet propulsion, etc.

Aeroplanes cannot travel in space for several reasons:

They need oxygen to burn fuel - Aeroplane engines rely on the oxygen in the atmosphere to burn fuel and generate thrust. In space, there is no atmosphere so there is no oxygen for the engines to work.

Aerodynamics - Aeroplane wings generate lift by interacting with the air. In space, there is no air so wings would be unable to generate any lift. Aeroplanes rely on aerodynamics to fly which does not work in space.

Extreme temperatures - In space, temperatures can range from -150 degrees Celsius to 150 degrees Celsius. Aeroplanes are designed to operate within a much narrower temperature range. The extreme cold and heat of space could damage aeroplane components.

Radiation - In space, there are high levels of radiation from the Sun and cosmic rays. Aeroplane bodies are not designed to shield against this type of radiation and it could damage electronics and affect aeroplane systems.

Pressure issues - Aeroplanes are designed to withstand air pressures at altitudes up to around 12 kilometers. In low-Earth orbit and beyond, the air pressure is essentially zero. This extreme change in pressure could cause structural damage to the aeroplane.

In summary, while aeroplanes are designed to fly through the Earth's atmosphere, they lack the key features needed to operate in the extreme environment of outer space like spaceships. Aeroplanes require things like oxygen, aerodynamics and being able to withstand changes in pressure - all of which do not exist or work the same way in space.

Explanation:

The wing is pushed up by the air under it. Large planes can only fly as high as about 7.5 miles. The air is too thin above that height. It would not hold the plane up.

Answer:

speed of light

Explanation:

the sun's light is 8 mins behind imaging that a billion fold

We have the next expression

9m – 3 – 5m = 3 + 4m – 6

we sum like terms

4m-3=4m-3

As we can see we have the same expression on both sides, which means that we will have infinity solutions for this equation

ANSWER

infinite solutions

Answer:

0,5 m/s²

Explanation:

v = d /t

v = 10 / 20

v = 0,5 m/s²

Hi! Let's see.

Explanation:

Data:

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Use speed formula in URM:

Replace with the data:

It divides:

Answer: The average speed of the soccer ball is 0.5m/s. (meters per seconds)

Cordially Alejanndraax. Greetings!

Answer:

24>0y

Explanation:

The answer is  energy 3 times as much. option A.

To calculate the amount of energy released when a 5 kg object is converted to pure energy, we can use Einstein's famous equation: E = mc². In this equation, E represents energy, m represents mass, and c represents the speed of light.

Given that the mass of the object is 5 kg, we can calculate the energy using the equation:

E = (5 kg) * (c²)

Now, to compare this energy with the amount of energy the Earth receives from the Sun every second, we need to determine the Earth's solar energy input.

The solar constant is the amount of solar radiation received per unit area at the Earth's distance from the Sun. Its average value is approximately 1361 Watts per square meter (W/m²). Multiplying this value by the surface area of the Earth (approximately 510 million square kilometers), we can estimate the total energy received by the Earth from the Sun every second.

Energy from the Sun = (1361 W/m²) * (510,000,000,000 m²)

To compare the energy released from converting a 5 kg object to energy with the energy received from the Sun, we divide the former by the latter:

Energy conversion / Energy from the Sun = [(5 kg) * (c²)] / [(1361 W/m²) * (510,000,000,000 m²)]

Simplifying the equation, we find:

Energy conversion / Energy from the Sun = (5 kg * c²) / (1361 W/m² * 510,000,000,000 m²)

The value of c² is approximately (3x10^8 m/s)² = 9x10^16 m²/s².

Plugging in the values, we get:

Energy conversion / Energy from the Sun = (5 kg * 9x10^16 m²/s²) / (1361 W/m² * 510,000,000,000 m²)

Simplifying further:

Energy conversion / Energy from the Sun ≈ 3.52

Therefore, the amount of energy released when a 5 kg object is converted to pure energy is approximately 3.52 times larger than the amount of energy the Earth receives from the Sun every second.

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Energy transformation, also known as energy conversion, is the process of changing energy from one form to another.

The energy of transformation in a proper way is known as the transformation chain. When we boiled water in the kettle, then the water starts to boil so electrical energy is converted into thermal energy. When we drop the water from the kettle into the cup, then the gravitational potential energy is converted into the kinetic energy because the height is involved in it. Generator is the source of electrical energy in which mechanical energy is converted into electrical energy.

So we can conclude that energy transformation, also known as energy conversion, is the process of changing energy from one form to another.

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Answer:

both experience forces or at least a force

Explanation:

it would go in the direction the other object

(second object, the one that crashed) was going

si if going right then right if left then left

plus or minus

When the current in the wire is decreasing the oppose magnitude of the magnetic flux in the loops is decreasing.

Induced currents in the loops and the forces exerted on them are directed so they oppose this change

Magnetic flux is a size of the entire magnetic subject which passes thru a given region. it's far a useful device for helping describe the outcomes of the magnetic pressure on some thing occupying a given location.

Magnetic flux through a surface is the surface integral of the ordinary element of the magnetic subject B over that floor. it is also denoted Φ or ΦB. The SI unit of magnetic flux is the weber, and the CGS unit is the maxwell.

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The speed you must go over the bump if people in your car are to feel "weightless" is 18.52 m/s.

Weightlessness is the complete or near-complete absence of the sensation of weight. In this situation, the downward acceleration is equal to acceleration due to gravity.

a = g

v²/r = g

v² = rg

v = √rg

where;

v = √(35 x 9.8)

v = 18.52 m/s

Thus, the speed you must go over the bump if people in your car are to feel "weightless" is 18.52 m/s.

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When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Assuming that the speed of sound is 343 m/s at 25 degrees Celsius, we can use the formula:

wavelength = speed of sound/frequency

wavelength = 343 / 666

wavelength = 0.515 meters or 51.5 centimeters

Therefore, the wavelength of a 666 Hz sound wave at 25 degrees Celsius is approximately 51.5 centimeters.

The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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Answer:

i think its 8.2

Explanation:

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.

Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.

The gravitational potential energy is given by:

mgh = (1.9 kg)\((9.8 m/s^2)h\)

The elastic potential energy stored in the spring is given by:

1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.

The kinetic energy of the box just before it makes contact with the spring is given by:

\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.

Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.

mgh = 1/2 \(kx^2\)

Substituting the given values, we have:

\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)

Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.

(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.

At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.

mgh = 1/2 \(kx^2\)

Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.

It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.

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The equivalent resistance of the circuit shown  is 23 ohms.

Option A is correct.

Resistance is  described as the opposition that a substance offers to the flow of electric current.

In a series circuit, all components are connected end-to-end to form a single path for current flow.

In a parallel circuit, all components are connected across each other with exactly two electrically common nodes with the same volt.

We then 1/R = 1/100 + 1/100 + 1 /(50+ 50) +  1 /(50+ 50)

I/R = 0.04

R = 25 ohms.

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\(\implies F_1 < F_2\)

\( \implies F_{net} = F_2 - F1\)

\(\implies F_{net} = 42 -15\)

\(\implies \underline{ \boxed{ F_{net} = 27 \: N}}\)

The net force on the 4.0 kg box is 27 N towards EAST.

Table A agrees with the information in the problem. After 25.0 seconds, the velocity of the plane is 187 m/s.

Based on the given problem, we need to determine the velocity of a plane after 25.0 seconds. The plane is initially flying east at a velocity of 115 m/s, and it experiences an acceleration of 2.88 m/s² in the northwest direction.

Let's analyze each option and calculate the final velocity (Vf) of the plane after 25.0 seconds:

Option A:

Vi = 115 m/s

a = 2.88 m/s²

t = 25.0 s

Using the equation Vf = Vi + at, we can calculate:

Vf = 115 m/s + (2.88 m/s²)(25.0 s) = 115 m/s + 72 m/s = 187 m/s

Option B:

V₁ = 2.04 m/s

a = 2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 2.04 m/s + (2.04 m/s²)(25.0 s) = 2.04 m/s + 51 m/s = 53.04 m/s

Option C:

V₁ = 115 m/s

a = -2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 115 m/s + (-2.04 m/s²)(25.0 s) = 115 m/s - 51 m/s = 64 m/s

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Suppose you are in mission control on the moon, in charge of launching a moon-orbiting communications satellite.

a) 2430 N.

b) 1.84 x 10^6 m.

c) F = m * v^2 / r

d) 2157 m/s

e) 2.87 x 10^4 s

f)1.17 x 10^-3 m/s^2

a. The weight of the satellite near the surface of the moon would be the mass of the satellite multiplied by the acceleration due to gravity on the moon. The acceleration due to gravity on the moon is about 1.62 m/s^2, so the weight of the satellite would be

1500 kg * 1.62 m/s^2 = 2430 N.

b. The radius of the orbit of the satellite would be the distance from the center of the moon to the altitude of the satellite. The radius of the moon is 1.74 x 10^6 m, so the radius of the orbit of the satellite would be

1.74 x 10^6 m + 100 km = 1.84 x 10^6 m.

c. The centripetal force is the force that is required to keep an object in circular motion. It is equal to the mass of the object times its velocity squared, divided by the radius of its orbit. To find the centripetal force on the satellite, we need to know its velocity. We can find this using the equation for the centripetal force, which is:

F = m * v^2 / r

where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the orbit.

d. To find the required orbital velocity for the satellite, we can rearrange the equation for the centripetal force to solve for v:

v = sqrt(F * r / m)

Plugging in the values, we get:

v = sqrt(2430 N * 1.84 x 10^6 m / 1500 kg) = 2157 m/s

e. The orbital period is the time it takes for an object to complete one orbit. It is equal to the circumference of the orbit divided by the velocity of the object. The circumference of the orbit is 2 * pi * r, where r is the radius of the orbit. The velocity of the object is the orbital velocity we calculated above. Plugging these values into the equation, we get:

T = 2 * pi * r / v

Plugging in the values, we get:

T = 2 * pi * 1.84 x 10^6 m / 2157 m/s = 2.87 x 10^4 s

f. Yes, the satellite is accelerating while in orbit. The direction of the acceleration is towards the center of the orbit, and the magnitude of the acceleration is the centripetal acceleration, which can be calculated using the equation:

a = v^2 / r

Plugging in the values, we get:

a = 2157 m/s^2 / 1.84 x 10^6 m = 1.17 x 10^-3 m/s^2

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1. The time taken for the object to reach the ground is 2.47 s

2. The speed with which the object will reach the ground is 26.206 m/s

1. How do I determine the time taken?

We can obtain the time taken for the object to reach the ground as      follow:

h = ½gt²

30 = ½ × 9.8 × t²

30 = 4.9 × t²

Divide both side by 4.905

t² = 30 / 4.9

Take the square root of both side

t = √(30 / 4.9)

t = 2.47 s

Thus, the time taken to reach the ground is 2.47 s

2. How do i determine the speed?

The speed the object will use to reach the ground can be obtained as follow:

v = u + gt

v = 2 + (9.8 × 2.47)

v = 2 + 24.206

v = 26.206 m/s

Thus, the speed is 26.206 m/s

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Answer:

C. 20 cm x 80 cm

Explanation:

The dimensions of the scale model have the same ratio of the original dimensions. The ratio of the original dimenstions is

240/60 = 4

Then, the ratio for each option is

A. 360/90 = 4

B. 3/1 = 3

C. 80/20 = 4

D. 480/120 = 4

Therefore, B is not a correct option.

Additionally, we don't use A because the units for length and width are different

And we don't use D because the measures are too long for a model.

Therefore, the answer is

C. 20 cm x 80 cm