Answer:
ω = 5.5 rad/s
Explanation:
Assuming no external torques present during the instant that the clump of clay is dropped on the turntable, total angular momentum must be conserved.The angular momentum of a rotating rigid body, can be expressed as follows:\(L = I * \omega (1)\)
where I = moment of inertia regarding the axis of rotation, and ω =
angular speed of the rotating body.
Since the angular momentum must keep constant, this means that it must be satisfied the following equality:\(L_{o} = L_{f} (2)\)
where L₀ = I₀ * ω₀, Lf = If * ωf.
I₀ is the moment of inertia of a solid disk rotating around an axis
passing through its center, as follows:
\(I_{o} =\frac{1}{2} * m* r^{2} = \frac{1}{2} * 22 kg*(2.3m)^{2} = 58.2 kgm2 (3)\)
If, is the moment of inertia after dropping the clump of clay, which adds
its own moment of inertia as a point mass, as follows:
\(I_{f} =\frac{1}{2} * m* r^{2} + m_{cl} * r_{cl}^{2} =58.2 kgm2 + (8.7kg)*(1.5m)^{2} \\ = 58.2 kgm + 19.6 kgm2 = 77.8 kgm2 (4)\)
Replacing I₀, If and ω₀ in (2), we can solve for ωf, as follows:\(\omega_{f} = \frac{I_{o} *\omega_{o} }{I_{f}} = \frac{58.2kgm2*7.3rad/s}{77.8kgm2} = 5.5 rad/s (5)\)
When the bells are charged up, the left bell acquires a positive charge, the right bell a negative charge. When this occurs, the nut that is suspended between the two bells experiences a torque (it lines itself up with a line between the two bells) but it doesn't experience a net force. What does this tell us about the charge on the nut
Answer:
Thus simply tells us that The nut has no net charge and so therefore, There will be a negative charge on the left side, and an equal positive charge on the right side
This basically means that the nut has no net charge and thus will have a negative charge on the left side and an equal positive charge on the right side.
What is net charge?When an object has more protons than electrons, its net charge is positive.
If there are more electrons than protons in an object, the net charge is negative. If the object has an equal number of protons and electrons, it is electrically neutral.
The total charge on a body is the algebraic sum of all the charges on it. Every atom is electrically neutral because it contains the same number of electrons as protons.
This basically means that the nut has no net charge and thus has a negative charge on one side and an equal positive charge on the other.
Thus, this can be implied as per the given scenario.
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Describe the setup of the electromagnet. Why does the wire need to be a conductive material?
An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.
An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.For more questions on electromagnet
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How much heat is contained in 100 kg of water at 60.0 °C?
Answer:
so how much heat is there at 0 C? That's zero. But for every degree above that you have 4.184 J. You take it from there. Remember q = mc*delta T.
The moon weighs 7x1022kg and we are about 380,000,000m away from the moon. If you weigh 50kg, how much gravitational force does the moon have on you? (G=6.7x10-¹¹)
The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:
F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².
Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.
The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.
Therefore, we have:
m₁ = 50 kg
m₂ = 7 × 10²² kg
r = 380,000,000 m
G = 6.7 × 10⁻¹¹ N m²/kg²
Substituting these values into the formula, we get:
F = (G × m₁ × m₂) / r²
F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²
F = 1.15 N
Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
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A refrigerator is 1.8m tall, lm wide,and 0.8m deep.The center of mass is lm from the bottom, 0.5m from the side, and 0.6m from the front. it weighs 1300N. When pushing it back into its position in the kitchen, you must push on the front side. If you push horizontally from a height of 1.5m above the bottom, what is the maximum pushing force you can exert to avoid tipping the refrigerator
Answer:
F = 520 N
Explanation:
For this exercise the rotational equilibrium equation should be used
Σ τ = 0
Let's set a reference system with the origin at the back of the refrigerator and the counterclockwise rotation as positive. On the x-axis it is horizontal directed outward, eg the horizontal y-axis directed to the side and the z-axis vertical
Torque is
τ = F x r
the bold indicate vectors, we analyze each force
the applied force is horizontal along the -x axis, the arm (perpendicular distance) is directed in the z axis,
The weight of the body is the vertical direction of the z-axis, so the arm is on the x-axis
-F z + W x = 0
F z = W x
F = \(\frac{x}{z}\) W
The exercise indicates the point of application of the force z = 1.5 m and the weight is placed in the center of mass of the body x = 0.6 m, we are assuming that the force is applied in the wide center of the refrigerator
let's calculate
F = 1300 0.6 / 1.5
F = 520 N
A projectile is fired straight up with an initial velocity of 40.0 m/s . Approximately how high will the projectile ?
Answer:
it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters
Explanation:
hope it helped
:)
The apparent weight of a passenger in an elevator is greater than his true weight. Which one of the following is true? The elevator is either moving upward with an increasing speed or moving downward with a decreasing speed. The elevator is either moving upward with a decreasing speed or moving downward with an increasing speed. The elevator is either moving upward with an increasing speed or moving downward with an increasing speed. The elevator is either moving upward with a decreasing speed or moving downward with a decreasing speed. The elevator is either moving upward with an increasing speed or moving upward with a decreasing speed.
Answer:
D
Explanation:
The elevator is either moving upwards with an increasing speed, or moving downwards with a a decreasing speed.
The statement above is true because the direction at which the elevator accelerates, or decelerates(which is negative acceleration anyway), is of paramount importance. If the acceleration is towards the upside, the apparent weight does becomes greater than the true weight. While on the other hand, if the acceleration points towards the downside, then the apparent weight does becomes less than the true weight.
Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.
To better understand crash dynamics we have to look at "__________."
A. the law of gravity
B. Bernoulli's principle
C. the laws of motion
D. Archimedes' principle
To better understand crash dynamics we have to look at "the laws of motion."
The laws of motion
The laws of motion were introduced by Sir Isaac Newton in 1687 in his book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), which defined the laws of motion, or three fundamental laws that govern the movement of bodies. The laws of motion, according to Newton, govern the motion of an object or a system of objects that interact.
It defines the concepts of force and mass, and the fundamental dynamics of motion.The following are the laws of motion:Every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. The velocity of an object changes proportional to the force applied to it, and the acceleration of an object is proportional to both its force and its mass. For every action, there is an equal and opposite reaction.
Therefore, these laws are necessary to fully grasp crash dynamics because they explain how objects respond to outside forces that cause them to accelerate or decelerate.
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very important!!!
A drilling rig performs 5.15∗105 J of work at an average power output of 3940 W. How long does it take the drill to perform this work?
540 s
916 s
244 s
131 s
Answer:131s
Explanation:
time = 5.15*10^5 J / 3940
7) Three resistors having resistances of 4.0 Ω, 6.0 Ω, and 10.0 Ω are connected in parallel. If the combination is connected in series with an ideal 12-V battery and a 2.0-Ω resistor, what is the current through the 10.0-Ω resistor?
A) 0.59 A
B) 2.7 A
C) 6.4 A
D) 11.2 A
E) 16 A
E) 16 A
Answer:
A, 0.59A
Explanation:
The total resistance in the circuit is the resistances in parallel plus that in series.
Total resistance for those in parallel is;
1/(1/4 +1/6 +1/10) = 1/ (15+10+6 /60)
1/(31/60)= 60/31 ohms
Hence total resistance of the circuit is;
60/31 + 2 = (60+62)/31 = 122/31=3.94 ohms
To calculate the current flowing through the 10ohm resistance we need to know the voltage drop by subtracting the voltage drop in the 2ohm resistance from the total voltage drop.
Voltage drop on the 2 ohm resistance is;
Current on the 2 ohm resistor × 2 ohms
V = I ×R ; I - current
R - resistance
Current drop on the 2ohm resistance is;
Total voltage in the circuit/ total resistance in the circuit
12/3.94= 3.05A
Voltage drop on the 2 ohm resistance;
3.05 × 2 = 6.10volts
Hence voltage drop on the parallel resistance would be ;
12-6.10= 5.90V
Now voltage drop in a parallel circuit is the same hence 5.90v is dropped in each of the parallel resistance.
That said, the current drop on the 10 ohm resistor would be;
5.90/10 = 0.59A
Remember V= I× R so that I = V/R
The current flowing through the 10 ohms resistor is 0.59 A.
The given parameters;
resistors in parallel, = 4.0 Ω, 6.0 Ω, and 10.0 Ωresistor in series = 2 0 Ω,The equivalent resistance of the parallel resistors;
\(\frac{1}{R_e} = \frac{1}{4} + \frac{1}{6}+ \frac{1}{10} \\\\\frac{1}{R_e} = \frac{31}{60} \\\\R_e = \frac{60}{31} = 1.94 \ ohms\)
The overall resistance with series resistor
R = 1.94+ 2 = 3.94 ohms
The current flowing in the entire circuit is calculated as follows;
\(I = \frac{V}{R} \\\\I = \frac{12}{3.94} \\\\I =3.05 \ A\)
The voltage drop due to the 2 ohms resistor is calculated as follows;
V = 12 - 3.05(2)
V = 5.9 V
The current flowing in the 10 ohms resistor is calculated as follows;
\(I = \frac{5.9}{10} \\\\I = 0.59 \ A\)
Thus, the current flowing through the 10 ohms resistor is 0.59 A.
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how do you define teaching?
Answer:
Teaching is the process of attending to people's needs, experiences and feelings, and making specific interventions to help them learn particular things.
Explanation:
Hope it helps✌Answer:
In education, teaching is the concerted sharing of knowledge and experience, which is usually organized within a discipline and, more generally, the provision of stimulus to the psychological and intellectual growth of a person by another person or artifact.
How much heat is required to raise the temperature of 90 g of water from 12C to 88C?
It would require 28618.56 J of heat to raise the temperature of 90 g of water from 12°C to 88°C.
How much heat is required to raise the temperature of 90g of water from 12°C to 88°C?Given that:
Mass of water m = 90g
Initial temperature = 12°C
Final temperature = 88°C,
The amount of heat required to raise the temperature of a substance is given by:
Q = mCΔT
Where Q is the amount of heat, m is the mass of the substance, C is the specific heat capacity of the substance, and ΔT is the change in temperature.
Note that: the specific heat capacity of water is 4.184 J/g°C.
So, for raising the temperature of 90 g of water from 12°C to 88°C, we have:
Q = mCΔT
Q = (90 g) × (4.184 J/g°C) × (88°C - 12°C)
Q = (90 g) × (4.184 J/g°C) × (76°C)
Q = 28618.56 J
Therefore, the required heat is 28618.56 Joules.
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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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Moving sideways on the balls of the feet.
Question 4 options:
galloping
sliding
striding
skipping
Various ways of performing locomotive motion may include walking, running, striding and so on. However, when moving sideways using the balls of feet, with the knees on the ground, it is called sliding.
Galloping movement is also similar to sliding with the body being forward rather than being in a sideways position.
Skipping involves a series of jumps with each feet successively taking up and down in a repeated manner.
Striding involves a fairly long walk with greater distance moved compared to walking.
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What do the spheres in this model represent?
A. Molecules
B.electrons
C. Planets and the sun
D. Atoms
Answer:
Atoms
________________
The spheres in this model represent atoms. The correct option is D.
What is atom?
Atom is the smallest unit of the element. Different elements have different size atoms and same element have same size atoms.
All matter consists of atoms. Atoms of the same element are the same in size and atoms of different elements are different. Atoms combine in whole-number ratios to form compounds.
And in any model, the atoms are represented as a sphere.
Thus, correct option is D.
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One end of a spring is attached to a wall. A 26 N pull on the other end causes the spring to stretch by 3.0 cm . What is the spring constant?
The force constant of the spring is 866.7 N/m.
What is the Hooke's law?In order to fix the question that we have here we have to look at the Hooke's law. From the Hooke's law we have to note that the force that is causing the string to become expanded is proportional to the extension of the spring as long as the elastic limit has not been exceeded.
Now we know that the Hooke's law would refer to the force and the extension and that is what we would need to be able to solve in order to get the force constant as we have been asked in the problem that we have here.
Thus;
F = Ke
F = force
K = force constant
e = extension
Then;
K = F/e
K = 26 N/3 * 10^-2 m
K = 866.7 N/m
From the calculation that we have done in the lines above, we have obtained the force constant to be about 866.7 N/m.
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What unique strengths would you bring to the Grace Scholars Program?
Grace Scholars Program is a scholarship program that selects the best and brightest students for the program.
The Grace Scholars Program is a prestigious scholarship program that aims to identify and support exceptionally talented and promising students. The program seeks to provide opportunities for these students to excel academically, develop their leadership skills, and make a positive impact in their respective fields.The selection process for the Grace Scholars Program is highly competitive, with a rigorous evaluation of applicants' academic achievements, extracurricular activities, personal qualities, and potential for future success. The program typically looks for students who demonstrate outstanding academic performance, intellectual curiosity, leadership abilities, and a commitment to service and community involvement. By offering this scholarship program, institutions aim to attract and retain top talent, foster a culture of excellence, and contribute to the development of future leaders and innovators who can positively impact society.For such more questions on scholarship
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In general, why is it risky to build something whose natural frequency can be matched by external vibrations?
It risky to build something whose natural frequency can be matched by external vibrations because resonance can occur and an increase in the amplitude of a vibration will result causing it to collapse.
Frequency describes the variety of waves that bypass a fixed place in a given quantity of time. So if the time it takes for a wave to bypass is is half 2nd, the frequency is two according to 2d. If it takes 1/one hundred of an hour, the frequency is a hundred according to hour.
Frequency is the cost in numbers that suggests how regularly a particular item takes place inside the given information set. There are varieties of frequency table - Grouped Frequency Distribution and Ungrouped Frequency Distribution.
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Sally puts on wool socks and rubs her feet on a nylon carpet. How does static electricity build up in Sally?
O When electrons from the wool socks move into the carpet, Sally and her socks gain a negative charge.
O The friction causes electrons from the wool socks to move to Sally, giving Sally a negative charge.
O Electrons from the wool socks move into the carpet, giving Sally and her socks a positive charge.
Electrons from the carpet move into the wool socks, giving Sally and her socks a positive charge.
When Sally puts on wool socks and rubs her feet on a nylon carpet, static electricity builds up through a process involving the movement of electrons. The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge.
The correct answer would be the friction causes electrons from the wool socks to move to Sally, giving Sally a negative charge.
The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge. This is due to the phenomenon known as the triboelectric effect.
The triboelectric effect occurs when two materials come into contact and then separate. During the rubbing process, the atoms in the two materials interact, causing the transfer of electrons between them. In this case, the wool socks have a greater affinity for electrons compared to the nylon carpet. As a result, electrons from the socks are transferred to the carpet, leaving the socks with a positive charge and the carpet with a negative charge.
Sally, wearing the wool socks, experiences an accumulation of excess electrons on her feet, giving her a negative charge. This excess negative charge on her body can lead to static electricity-related phenomena, such as experiencing a shock when touching a metal object or seeing her hair stand on end when near certain surfaces.
It's important to note that the movement of electrons determines the charge distribution during the triboelectric effect. In this scenario, electrons move from the wool socks to the nylon carpet, resulting in Sally and her socks gaining a negative charge.
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Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm). This is equal to 0.08 revolutions per second (rps). What is the angular velocity in radians per second? 2π rad = 1 revolution.
The angular velocity in radians per second, given that Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm) is 0.50 radians per second
How do I determine the angular velocity in radians per second?The angular velocity (in radians per second) can be obtained by simply converting 0.08 revolution per second to radians per second. This is obtained as illustrated below:
Angular velocity (in revolution per second) = 0.08 revolution per secondAngular velocity (in radians per second) =?1 revolution per second = 2π radians per second
Therefore,
0.08 revolution per second = 0.08 × 2π
Recall
Pi (π) = 3.14
Thus,
0.08 revolution per second = 0.08 × 2 × 3.14
0.08 revolution per second = 0.50 radians per second
Thus, we can conclude that the angular velocity (in radians per second) is 0.50 radians per second
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Match these items.
1. effect observed when light from an object in cool air passes through warm air
2. line perpendicular to a surface
3. splitting of light into its component colors angle of incidence
4. alignment of light into a single vibrational direction
5. larger angle as light passes from air to water
6. cause of the sky's color
7. bouncing of light rays reflection
8. bending of light between media
9. ratio of speeds of light
10. inability of light to escape a low-velocity medium due to a large angle of approach refraction
a. scattering
b.dispersion
c.angle of incidence
d.index of refraction
e.mirage
f.reflection
g.normal
h.total inertial reflection
i.polarization
j.refraction
Answer:
1. effect observed when light from an object in cool air passes through warm air
→ h. total internal reflection
2. line perpendicular to a surface
→ g. normal.
3. splitting of light into its component colors angle of incidence
→ b. dispersion.
4. alignment of light into a single vibrational direction
→ i. polarization
5. larger angle as light passes from air to water
→ c. angle of incidence
6. cause of the sky's color
→ f. reflection
7. bouncing of light rays reflection
→ f. reflection
8. bending of light between media
→ j. refraction.
9. ratio of speeds of light
→ d. index of refraction.
10. inability of light to escape a low-velocity medium due to a large angle of approach refraction
→ scattering.
Assume the following vehicles are all moving at the Sam speed .it would be harder to change the velocity of which vehicle . What law is it
Answer:what the choices
Explanation:
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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A flying stationary kite is acted on by a force of 9.8 N downward. The wind exerts a force of 45 N at an angle of 50.0 degrees above the horizontal. Find the force that the string exerts on the kite.
The force that the string exerts on the kite is 38.02 N.
What is the force exerted by the string?
The force exerted by the string is calculated by applying the following equation.
R² = F² + W² - 2FW cosθ
where;
F is the force of the windW is the downward force on the kiteθ is the angle between the force of wind and downward forceThe given parameters include the following;
the angle between the two forces , θ = 90 ⁰ - 50 ⁰ = 40 ⁰The force that the string exerts on the kite is calculated as follows;
R² = F² + W² - 2FW cosθ
R² = 45² + 9.8² - 2(45 x 9.8) cos (40)
R² = 1445.39
R = √1445.39
R = 38.02 N
Thus, the force applied by the string on the kite is equal to the resultant force on the kite.
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Which of the statements best describes distance and displacement?
A. distance and displacement both have direction.
B. distance and displacement both have no direction.
C. distance has no direction while displacement has.
D. distance has direction while displacement don't have.
The phrases that best express separation and movement are those. A. Displacement and distance both have a direction. (Select A).
How do people behave when they are displace?Transferring unfavorable emotions from one item or person to another is referred to as displacement and is a defensive tactic. To "take out" their rage on a family member, for instance, a person can yell at them if they are upset with their job.
An alternative term for displacement is...Replace, supersede, and supplant are some frequent alternatives to the word "displace." While all of these phrases refer to "putting out of a normal or suitable position or into the place of another. Thousand had been displaced by fighting.
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Define the term volume and its unit
Volume is the measure of the 3-dimensional space occupied by matter, or enclosed by a surface, measured in cubic units. The SI unit of volume is the cubic meter (m3), which is a derived unit. Liter (L) is a special name for the cubic decimeter (dm3). ... Milliliter (mL) is a special name for the cubic centimeter (cm3).
Answer:
Key Takeaways: Volume Definition
Volume is the three-dimensional space occupied by a substance or enclosed by a surface. The International System of Units (SI) standard unit of volume is the cubic meter (m3). The metric system uses the liter (L) as a volume unit. One liter is the same volume as a 10-centimeter cube.
The picture shows an investigation conducted by Galileo many years ago. He learned that the speed of each ball increased as it fell, and that the balls fell at the same average speed. image Which of these statements is best supported by Galileo’s investigation?
Answer:
Italian astronomer Galileo Galilei provided a number of scientific insights that laid the foundation for future scientists. His investigation of the laws of motion and improvements on the telescope helped further the understanding of the world and universe around him.Nov 14, 2017
Explanation:
Why do some people still believe that Earth is flat if it's disproven?
Answer:
some people failed to realize that the earth is round ligit
Explanation: they failed to do that because of how our eyes see the earth so they was like okay it is flat caused the never saw a person that showed it on the internet
analia loves to rock climb. over thanksgiving break she took some time to head out to enchanted rock to get a good climb in. she puts her 9 kg pack on her back and walks 1200 meters to her climbing spot. she scales the 20 meter tall cliff face and once at the top walks an additional 5 meters to sit and enjoy the view. how much work was done by analia on her pack from the time she left the car until she made it to enjoy the view?
The total work done by Analia on her pack from the time she left the car until she made it to enjoy the view is 105840 J.
How to find the work done by Analia on her pack
Since she carries the pack on her back and walks a distance of 1200 meters, she exerts a force equal to the weight of the pack (which we assume is constant throughout the walk) over this distance:
Work done on the pack during the walk = force x distance
The force on the pack is equal to its weight, which is given by:
force = mass x gravity
where mass is the mass of the pack and gravity is the acceleration due to gravity (9.8 m/s^2). Thus, the force on the pack is:
force = 9 kg x 9.8 m/s^2 = 88.2 N
So the work done on the pack during the walk is:
work = force x distance = 88.2 N x 1200 m = 105840 J
Once Analia reaches the top of the cliff, she walks an additional 5 meters. Since the pack is already on her back, there is no additional work done on the pack during this part of the climb.
Therefore, the total work done by Analia on her pack from the time she left the car until she made it to enjoy the view is 105840 J.
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