a transformer with an input emf of 240volts and output of 960volts has 720 turns in the secondary coil. what is the number of coil in the primary coil?​

Answer: Negative

Explanation: The acceleration along the y-axis for any projectile motion will always be -9.8m/s^2.

The external structure of a solid  refers to the overall structure of the solid due to the arrangement of its particles..

The internal structure of a solid is the the arrangement of unit particles in the internal space of the solid.

A solid is a substance which has a definite shape and volume.

Solids are one of the three states of matter.

The particles in a solid are arrange in regular repeating patterns due to the strong intermolecular forces of attraction between the particles in the solid.

The external structure of a solid refers to the overall structure of the solid due to the arrangement of its particles.

The external structure of a solid may be a crystal or amorphous in shape.

The internal structure of a solid is the the arrangement of unit particles in the internal space of the solid.

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Complete Question

Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 32.75 m/s at an angle θ = 32° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.

Randomized Variables

vo 32.75 m/s

theta 32 degrees

What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?

Answer:

The  horizontal distance is  \(R =  590.2 \ m \)  

Explanation:

From the question we are told that

 The initial  velocity is  \(v_o =  32.75 \  m/s\)

  The angle is  \(\theta =  26^o\)

  The gravitational acceleration of the moon is \(g_m  =  \frac{1}{6}  *  9.8   = 1.633 m/s^2\)

 Generally the distance traveled is mathematically represented as

    \(R =  \frac{v_o^2 sin 2(\theta)}{g_m}\)

=> \(R =  \frac{32.75^2 sin 2(32)}{1.633}\)

=> \(R =  590.2 \ m \)  

Answer:

the period of oscillation of the given object is 0.14 s

Explanation:

Given;

mass of the object, m = 3 kg

extension of the spring, x = 0.085 m

The spring constant is calculated as follows;

\(F = mg = \frac{1}{2} ke^2\\\\2mg = ke^2\\\\k = \frac{2mg}{e^2} \\\\k = \frac{2\times 3 \times 9.8}{(0.085)^2} \\\\k = 8,138.41 \ N/m\)

The angular speed of a 4 kg object is calculated as follows;

\(\omega = \sqrt{\frac{k}{m} } \\\\\frac{2\pi }{T} = \sqrt{\frac{k}{m} } \\\\T= 2\pi \sqrt{\frac{m}{k} } \\\\T = 2\pi \sqrt{\frac{4}{8138.41} }\\\\T = 0.14 \ s\)

Therefore, the period of oscillation of the given object is 0.14 s

Hope this answer helps you

If the light spring is stretched with a spring constant of 102 N/m then, the elongated length of the spring will be 0.48 meters.

Spring constant is the force which is needed to stretch or press a spring, divided by the distance that the spring gets longer or shorter.

Given,

Spring constant of light spring k = 102.0N/m

mass of balloon m = 1.75g = 1.75 × 10⁻³ Kg

Density of helium (He) = 0.179 kg/m

Density of air = 1.204 kg/m³

Volume of balloon/helium V = 4.92 m³

We have 3 forces acting on the spring, two directed downward, one upward. Downward forces are the weight of the balloon and weight gas inside it. of the helium

Upward force is the buoyant force. helium is of lesser density. air.

Now, Fnet = mg + e(He) vg - Ve(air)g

Fnet = g[m + v(e(He)-e(air))]

Fnet = 9.8 (1.75 × 10⁻³+ 4.92(0.179-1.204))

Fnet = 9.8(0.00175 + (-5.04125))

Fnet = 9.8 × -5.04125

Fnet = -49.40 N

The elongation of the spring = IFnetI/ K

Length = 49.40/ 102

Length of spring = 0.48 meters

Therefore, the elongated length of the spring will be 0.48 meters.

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The mass of the soccer ball with a kinetic energy of 500J and traveling with 50m/s is 0.2 kg.

Kinetic energy is simply a form of energy an object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given the data in the question;

Plug the given values into the above formula and solve for m.

K = (1/2)mv²

2K = mv²

m = 2K / v²

m = 500kgm²/s² / (50m/s)²

m = 500kgm²/s² / 2500m²/s²

m = 0.2kg

Therefore, the mass of the ball is 0.2 kg.

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Answer:

B. add more loops of wire between the magnets

Explanation:

this would increase the magnetic force acting on the rod therefore increasing

By adding more loops of wire between the magnets the motor is changed to be able to lift a heavier box.

An electric motor is a mechanism that turns electricity into mechanical energy.

The interaction between the motor's magnetic field and electric current in a wire winding generates force in the form of torque imparted to the motor's shaft in most electric motors.

An electric generator is physically equivalent to an electric motor, but it converts mechanical energy into electrical energy using a reversed flow of power.

The load capacity in the motor can be increased by increasing the no of loops. So by adding more loops of wire between the magnets the motor is changed to be able to lift a heavier box.

Hence option B is correct.

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Given data:

The value of the spring constant is,

The value of the mass of the cart is,

The distance moved by the cart from the equilibrium is,

The acceleration acquired by the cart is,

The initial velocity of the cart is,

The velocity of the cart when it passes the equilibrium is,

Thus, the velocity of the cart is 18 meter per second.

Answer:

1.40 m/s^2

Explanation:

Given data

Velocity= 17.4 m/s

time= 12.4 seconds

We want to find the acceleration of the rock

We know that

acceleration = velocity/time

Substitute

acceleration= 17.4/12.4

acceleration=1.40 m/s^2

Hence the acceleration is 1.40 m/s^2

The difference is (80 dB - 40 dB) = 40 dB.

The sound is 40 dB louder outside.

Each 10 dB means 10 times more sound power.

40 dB louder means 10x10x10x10 times more sound power.

That's 10,000 times more sound power outside than inside.

The correct answer is a. x-rays is produced by the sudden deceleration of high speed electrons.

What is x-rays?

When high-speed electrons are suddenly decelerated or slowed down, they release energy in the form of electromagnetic radiation. This process is known as bremsstrahlung or "braking radiation". The energy of the emitted radiation depends on the initial speed of the electrons and the degree of deceleration.

In the case of bremsstrahlung, the emitted radiation can range from radio waves to gamma rays, but the highest energy radiation produced by bremsstrahlung is x-rays. Therefore, the sudden deceleration of high-speed electrons produces x-rays.

X-rays are ionizing radiation, meaning that they have enough energy to remove electrons from atoms or molecules, which can cause damage to living tissue. Therefore, exposure to X-rays should be limited and controlled to minimize health risks.

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Complete question is: x-rays is produced by the sudden deceleration of high speed electrons.

Answer:

196 megajoules

Explanation:

Since you are talking about the gravitational potential I am assuming 10km is the height of the object in free fall.

PEg = mgh    2000kg×9.8m/s²×10000m = 196 megajoules

Answer:

copper

Explanation:

wires use copper to conduct electrictiy

Answer:

Explanation:

Copper is the answer; as it is metal and metals are famous for conducting electricity, but plastic,rubber and glass  are  nonmetals.

We need the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other to find the instantaneous velocity but not the average velocity.

We need to take a moment to be able to explain to ourselves again the meaning of the term velocity. Let us recall that the term velocity would have to do with the change in the position of an object with time.

We know that the velocity is a vector quantity and as such we must have to look at the direction in which the distance that has been covered has passed through and this is something that we must keep in  mind as we work through this question.

Now, we know that the velocity is the change in position as such we need the two positions of the object and the approximate time taken to make the change.

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(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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The child's speed at the lowest point is 5.42 m/s.

At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.

Using the conservation of mechanical energy, we can write:

Potential energy at highest point = Kinetic energy at lowest point

mgh = (1/2)mv²

where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.

First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:

h = (1/2)3.00 m = 1.50 m

Next, we can solve for the child's speed at the lowest point:

mgh = (1/2)mv²

40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²

588 J = 20.0 kg * v²

v² = 29.4 m²/s²

v = 5.42 m/s

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Answer:

Explanation:

To verify the hypothesis that the Earth has a liquid outer core and a solid inner core, we can use seismographs to study seismic waves that pass through the Earth's interior. The experiment can be set up as follows:

1. Select multiple seismograph stations around the globe to record seismic waves.

2. Choose a location for an earthquake to occur. The earthquake should be large enough to generate seismic waves that travel through the Earth's interior and be located far away from the selected seismograph stations.

3. Record the seismic waves generated by the earthquake at the various seismograph stations.

4. Analyze the seismic waves to determine how they interact with the Earth's interior. Specifically, we will study how the seismic waves pass through the Earth's outer and inner core.

5. Repeat the experiment using earthquakes of different magnitudes and at different locations, and record the resulting seismic waves.

Equipment needed for the experiment include seismographs, computers for data analysis, and earthquake monitoring systems. Seismographs can be installed in various locations around the globe to record the seismic waves generated by the earthquake. Data from these seismographs can be collected and analyzed using computer software to determine how the seismic waves interact with the Earth's interior.

Evidence that proves the outer core is liquid includes the observation of seismic waves that cannot travel through the liquid outer core, resulting in a shadow zone on the opposite side of the Earth from the earthquake. This shadow zone indicates that the seismic waves are refracted or absorbed by the liquid outer core. In contrast, evidence that proves the inner core is not liquid includes the observation of seismic waves that are reflected and refracted by the inner core boundary. This is due to the fact that the inner core is solid and has a different density and composition than the outer core.

To use repeatability to show whether the hypothesis is valid or not, we can repeat the experiment using earthquakes of different magnitudes and at different locations, and record the resulting seismic waves. If the results from multiple experiments are consistent with the hypothesis, then we can have greater confidence that the hypothesis is valid. If the results from multiple experiments are inconsistent, then we would need to investigate further to determine the cause of the inconsistency and revise the hypothesis accordingly.

There is not enough information to determine the work done. Option iv

Let us note that we say that there is work done when the force that has been applied moves a distance in the direction of the force. In this case, we have been told that there is the combination of the works that is done by the object.

Now, we also have to note that we do not have other information to determine the work done such as the magnetic feild and the mass of the electron. All these are lacking in the question.

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So looking at the magnet given,

we know S attracts N

Given the situation in the given, when the magnets come together, the north end still be in the north side (as shown in the given) and same thing for the south

So the correct answer is D.

The electrons are usually at a constant distance from the nucleus of an atom in precious shells. The flow of charges to the per unit of time helps the conductor to conduct electricity. The mathematic representation of the electric current is given in the terms of charges as

*Here 'q' is the charge

*Here 't' is the time

The movement of electrons

The flow of charges inside the metal (conductor) is known as the electric current.

Given:

The lamp draws the current is

The voltage supplied by the generator is

The time for which energy converted is

Explanation:

(a)

The power delivered by the generator is given by

Plugging all the values in the above equation, we get

The power delivered by the generator is

(b)

Energy is converted by the electric lamp is given by

Plugging all the values in the above relation, we get

Thus, the electric energy convert by the lamp is

Answer:

6.29 μC/m³

Explanation:

Volume charge density is the quantity of charge per unit volume.

The direction of the electric field was not specified, therefore the volume charge density (ρ) is given by:

2πRLE = ρπR²L/ε₀

ρ = 2Eε₀ / R

Where E = electric field strength = 16 kN/C = 16 * 10³ N/C, R = radius of rod = 4.5 cm = 0.045 m, ε₀ = relative permittivity of free space = 8.85 * 10⁻¹² C² / Nm²

Therefore:

ρ = 2(16 * 10³ N/C)(8.85 * 10⁻¹² C²/Nm²) / 0.045 m = 6.29 * 10⁻⁶ C/m³

ρ = 6.29 μC/m³

At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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Answer: 7.7Hz

Explanation:

The frequency of a sound wave produced by a wind instrument depends on the speed of sound in the medium, which in turn depends on the temperature of the medium. The speed of sound in air at room temperature (23°C) is approximately 343 meters per second. At body temperature (37.0°C), the speed of sound in air is approximately 349 meters per second.

To calculate the expected maximum change in frequency of a wind instrument when warmed up from room temperature to body temperature, we can use the following formula:

Δf/f = Δv/v,

where Δf is the change in frequency, f is the initial frequency (in Hz), Δv is the change in speed of sound, and v is the initial speed of sound (in meters per second).

Substituting the values, we get:

Δf/440 = (349 - 343)/343

Δf/440 = 6/343

Δf = (6/343) × 440

Δf ≈ 7.7 Hz

Answer:

100

Explanation:

F = m * a

Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):

F = 0.02 kg * 5 m/s^2 = 0.1 N

So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.