The average intensity of an electromagnetic wave with a peak electric field of 1800 V/m is approximately 4.295 W/m². To find the average intensity of an electromagnetic wave with a peak electric field of 1800 V/m, you can use the following formula:
Average Intensity (I) = (1/2) × ε₀ × c × E₀²
where ε₀ is the vacuum permittivity (8.854 x 10^(-12) F/m), c is the speed of light (3 x 10^8 m/s), and E₀ is the peak electric field (1800 V/m).
Step 1: Square the peak electric field value.
E₀² = (1800 V/m)² = 3,240,000 (V²/m²)
Step 2: Multiply ε₀, c, and E₀².
(1/2) × ε₀ × c × E₀² = (1/2) × (8.854 x 10^(-12) F/m) × (3 x 10^8 m/s) × (3,240,000 V²/m²)
Step 3: Calculate the average intensity.
I = (1/2) × (8.854 x 10^(-12) F/m) × (3 x 10^8 m/s) × (3,240,000 V²/m²) ≈ 4.295 W/m²
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Why does 10 gram bigger cooper than 10 gold
Answer: A gram of gold is worth about $25, so 2 grams or better would be viewed as high-grade for bulk tonnage mining.
Explanation:
i looked it up.
Objects 1 and 2
attract each other with
a electrostatic force
of 72.0 units. If the charge of Object
is one-third the
original value AND the charge of object 2 is doubled AND
the distance separating Objects 1 and 2 is doubled, then the
new electrostatic force will be
units.
Answer:
12 units
Explanation:
Original F = C q1q2/r^2 now change the parameters
New F = C 1/3 q1 2 q2 / (2r)^2
= 2/12 C q1q2/r^2 <=======the new force is 1/6 of original
1/6 * 72 = 12 units
With friction turned on, let the skater do one back-and-forth on the half pipe. Use
the grid. Does he reach the same height as when he started?
The skater does indeed reach the same height on either side of the track With friction turned on.
The only thing that will change is how long it takes for the skater to come to a rest during the scenario. Only the skater's initial height when placed onto the track affects the overall energy, which remains constant.Potential energy is transformed into kinetic energy as the skateboarder descends the ramp. Some of the system's energy is changed into heat energy by friction. The energy cannot be returned to the system's potential or kinetic energy once the kinetic energy has been transformed into heat.For more information on friction kindly visit to
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par 1/2
In a volcanic eruption, 3.8 km of mountain
with a density of 1739 kg/m” was lifted an
average height of 403 m.
The acceleration of gravity is 9.81 m/s2.
How much energy was released in this eruption?
Answer in units of J.
part 2/2
The energy released by thermonuclear bombs is measured in megatons of TNT, where 1 megaton of sqrt(T) is 4.2 * 10 ^ 15 * J Convert this energy release into megatons of TNT. Answer in units of Mton TNT.
part 1
mass = ρ x V
mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg
PE (potential energy)= mgh
PE = 6608.2 kg x 9.81 x 403
PE = 2.61 x 10⁷ J
part 2
megaton of TNT (Mt) =4.2 x 10¹⁵ J
convert PE to Mt:
2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt
A backpack has a mass of 8 kg. it is lifted and given 54.9 J of gravitational potential energy. how high is it lifted? Acceleration due to gravity is g = 9.8 m/s^2. A) 3.2 m B) 0.15 m C) 6.9 m D) 0.7 m
Answer:
0.7 mOption D is the correct option.
solution,
Potential Energy(PE)=54.9 J
Mass(m)=8 kg
Acceleration due to gravity (g)=9.8 m/s^2
Height (h)=?
Now,
\(p.e = m \times g \times h \\ or \: 54.9 = 8 \times 9.8 \times h \\ or \: 54.9 = 78.4 \times h \\ or \: h = \frac{54 .9}{78.4} \\ h = 0.7 \: m\)
Hope this helps...
Good luck on your assignment..
a ball of mass m falls vertically, hits the floor with a speed i u , and rebounds with a speed f u . what is the magnitude of the impulse exerted on the ball by the floor?
So, the magnitude of the impulse exerted on the ball by the floor is m(fu + iu).
To calculate the magnitude of the impulse exerted on the ball by the floor, we need to use the impulse-momentum theorem, which states that the impulse experienced by an object is equal to the change in momentum of that object.
The momentum of the ball just before it hits the floor can be calculated as p = m * i, where m is the mass of the ball and i is its initial velocity. Similarly, the momentum of the ball just after it rebounds can be calculated as p' = m * f, where f is its final velocity.
The change in momentum of the ball is then given by the equation Δp = p' - p, which can be simplified to Δp = m * (f - i). This represents the momentum that the ball gains or loses as a result of its collision with the floor.
According to the impulse-momentum theorem, the impulse experienced by the ball is equal to the change in momentum, so we can write:
J = Δp = m * (f - i)
Therefore, the magnitude of the impulse exerted on the ball by the floor is equal to m * |f - i|, where |f - i| represents the absolute value of the difference between the final and initial velocities.
In other words, the impulse exerted on the ball depends on the mass of the ball and the difference between its initial and final velocities. The magnitude of the impulse will be greater if the ball bounces back with a higher speed, and will be lower if it rebounds with a lower speed.
The magnitude of the impulse exerted on the ball by the floor can be calculated using the impulse-momentum theorem, which states that impulse equals the change in momentum.
Impulse = Δmomentum = m(final velocity) - m(initial velocity)
In this case, the initial velocity is -iu (downward direction) and the final velocity is +fu (upward direction). Therefore,
Impulse = m(fu) - m(-iu) = m(fu + iu)
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a box is being pushed across the floor by a constant force the coeficient of kinetic friction is at time what is the new velocity and position
The velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction are determined by Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration.
In this scenario, the applied force, friction force, and mass of the box all play a role in determining its velocity and position.
The applied force is the force being applied to the box to move it across the floor. The frictional force, which acts in the opposite direction to the applied force, is proportional to the normal force and the coefficient of kinetic friction. The normal force is the force exerted by the floor on the box, perpendicular to the floor.As the box is pushed, it will eventually reach a velocity at which the frictional force is equal in magnitude to the applied force, and the net force on the box will be zero. At this point, the box will move at a constant velocity, as it is no longer accelerating. The position of the box will be dependent on the initial velocity, the applied force, and the time elapsed.
Overall, the velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction are interrelated and determined by the balance of forces acting on the object.
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What is the relationship between the velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction?
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which is not true about geothermal energy? it is only available in limited areas. it cannot be used for cooling. it can be locally depleted due to heavy use. ground source heat pumps require an additional source of energy.
The statement which is not correct regarding geothermal energy is that it can be locally depleted due to heavy use.
Geothermal energy is the energy in the form of heat, which is generated inside the earth. Temperature inside the earth increases at the rate of 25°C/km. When temperature reaches 700-1300°C, the rock becomes magma. This magma comes in the mantle or upper core layer.
Due to the high temperature magma heats up the attached rock and thereby water inside the permeable layers of the Earth. This warm water is utilized to run the turbine and generate electricity. It is a renewable source of energy which cannot be depleted by anyone. So the statement C is not true.
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which method is commonly used for improving cattle breeds and why?
Answer: Cross-breeding method is commonly used for improving cattle breeds. Cross-breeding between two good varieties of cattle will produce a new improved variety. Cross breeding is defined as the process or the act of producing offspring particularly through mating two pure bred individuals but come from different breeds, varieties, or even species. Crossbreeding is undertaken to: Utilise the desired attributes of two or more breeds. Produce progeny better suited to target markets while maintaining environmental adaption. Improve productivity quicker in traits which are slow to change within a breed i.e. environmental adaption, fertility and carcass traits.
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An aluminum wire 1.291 mm in diameter (16-gauge) carries a current of 1.5 amps. Overall Hint a. What is the number density of charge carriers (electrons) in the wire? Hint for (a) 1 The number density of electrons in the wire is 6.02E28 (Use "E" notation to enter your answer in scientific notation. For example, to enter 3.14 x 1012, enter "3.14E12".) mº b. What is the magnitude of the drift velocity of the electrons? Hint for (b) The drift velocity of the electrons is vd = m/s. c. What would be the drift velocity if the same gauge copper were used instead of aluminum? Hint for (c) For the same gauge copper wire, the drift velocity would be vd = m/s. There is a disconnect between how small drift velocities are and how quickly electrical signals travel through wires (nearly at the speed of light). For the moment, treat the two as completely unrelated to each other.
If an aluminum wire 1.291 mm in diameter (16-gauge) carries a current of 1.5 amps then:
(a) The density of charge carriers in the aluminum wire is 6.02E²⁸ electrons/m³.
(b) The magnitude of the drift velocity is 1.18E⁻⁴ m/s.
(c) Drift velocity in the same gauge copper wire is 8.4E⁻⁵ m/s.
a. To find the number density of charge carriers (electrons) in the aluminum wire, we can use the given information: number density = 6.02E²⁸ electrons/m³.
b. To find the drift velocity of the electrons, we need to use the formula:
Drift velocity (v_d) = Current (I) / (Charge of electron (e) * Number density (n) * Cross-sectional area (A))
First, we need to find the cross-sectional area of the wire:
A = π * (diameter / 2)²
A = π * (1.291E⁻³ m / 2)²
A = 1.309E⁻⁶ m²
Next, we can plug the values into the formula:
v_d = 1.5 A / (1.6E⁻¹⁹ C × 6.02E28 electrons/m³ × 1.309E-6 m²)
v_d = 1.18E⁻⁴ m/s
So the drift velocity of the electrons is approximately 1.18E⁻⁴ m/s.
c. To find the drift velocity in the same gauge copper wire, we need to know the number density of electrons in copper. The number density of electrons in copper is approximately 8.5E²⁸ electrons/m³. We can then use the same formula as before:
v_d (copper) = 1.5 A / (1.6E⁻¹⁹ C × 8.5E²⁸ electrons/m³ × 1.309E⁻⁶ m²)
v_d (copper) = 8.4E⁻⁵ m/s
The drift velocity of the electrons in the same gauge copper wire would be approximately 8.4E⁻⁵ m/s.
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a 0.40 kg mass is attached to a 0.5 m string and displaced an angle of 12 degrees before it is released. 1. what is the initial potential energy of the pendulum? 2. what is the angular frequency of the pendulum? 3. what is the velocity of the pendulum at the lowest point in its swing? 4. what is the height of its displacement?
A pendulum is a weight released from a starting point so that it can swing freely. When a pendulum is displaced sideways it restores a force due to gravity that will accelerate it back toward the equilibrium position from the resting position.
How to find initial potential energy, angular frequency, velocity and height of displacement of a pendulum?
We know, m= 0.40kg
L=0.5m
Angle = 12°
i) Main answer is : initial potential energy = PE = mgh (1-cos∅)
= 0.9×9.81×0.5×(1-cos12°)
= 0.0429 J
ii)Main answer is: Angular frequency= W= √g/l
=4.43 rad/s
= 0.7 rev/s
iii) Main answer is : velocity of pendulum = V=√2gl(1-cos∅)
=0.46m/s
iv) Main answer is : height of displacement= h=L (1-cos∅)
=0.01m
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The pendulum's angular frequency is 4.42 rad/s, and its potential energy is 0.04 J. the pendulum's lowest in its swings has a speed of 0.44 m/s, a motion time of 0.010905 m, and a lateral distance of 0.1039 m.
What is potential energy, exactly?Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is squeezed or strained, its energy increases. If a steel ball is lifted above the ground as contrasted to falling to the ground, it has higher potential energy.
Briefing:Given data:
The associated mass is m=0.40kg.
The string measures L=0.5m in length.
Angle misplaced is equal to 12°.
(1). Calculate the potential energy of pendulum:
PE=mg[L−Lcosθ]
PE=0.40kg×9.8m/s[0.5m−0.5m×cos12°]
PE=0.04J
Consequently, the pendulum's potential energy is 0.04 J.
(2). Determine the pendulum's angular frequency:
\(\omega=\sqrt{\frac{g}{L}}\)
Changing every variable in the aforementioned equation:
\(\omega=\sqrt{\frac{9.8 \mathrm{~m} / \mathrm{s}^2}{0.5 \mathrm{~m}}}\)
ω = 4.42 rad/s
Consequently, the pendulum's angular frequency is 4.42 rad/s.
(4). Do the vertical displacement calculation:
\(x_V=L-L \cos \theta\)
\(\begin{aligned}& x_V=0.5 \mathrm{~m}-0.6 \mathrm{~m} \cos 12^{\circ} \\& x_V=0.010905 \mathrm{~m}\end{aligned}\)
Do the horizontal displacement calculation:
\(\begin{aligned}& x_H=L \sin \theta \\& x_H=L \sin 12^{\circ} \\& x_H=0.1039 \mathrm{~m}\end{aligned}\)
The height of the horizontal displacement is therefore 0.1039 m, while the height of the deformation is 0.010905 m.
(3).Calculate the pendulum's rock bottom in its swing by using energy balance to determine its velocity.
KE = PE
\(\frac{1}{2} 0.40 \mathrm{~kg} \times v^2=0.04 \mathrm{~J}\)
v = 0.44 m/s
Calculate the pendulum's velocity at its rock bottom in its swing, which is 0.44 m/s.
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True or false Momentum is sometimes not conserved in collisions
False.
The momentum is always conserved in a collision.
From the law of conservation of momentum, the total momentum of a system before the collision is equal to the total momentum of the system after the collision.
Thus, the given statement is false.
15. What is velocity, and how is it useful for describing an object's motion?
Velocity describes motion by indicating how fastan object moves and in what direction. Speed is a magnitude of velocity, which indicates only how fast an object moves. Speed shows how much distance is traversed in a given interval of time: In a general case of motion,.
If you add 20g of ice at 0 degree celciu to 180g of water at 20 degree celciu, what i the final temperature of the water a all of the ice melt?
The combined water and melted ice temperature is 31.15°C.
We can use the following formula:
q = m c T is used to calculate the final temperature of the water and melted ice, where:
q = added or lost heat
m = the substance's mass
c = the substance's specific heat capacity
T = temperature change
Finding the heat that the ice has taken away:
(20g) x (2.1 J/g°C) x (0 - (-20))°C = q
q = 8400 J
Identifying the heat gained by water:
(180g) x (4.18 J/g°C) x (T) = q
Taking the heat lost by ice and converting it to the heat gained by water
(180g) x (4.18 J/g°C) x (T) = 8400 J
Trying to find T
T = 8400 J/(180g x 4.18 J/g°C).
ΔT = (8400/756)°C = 11.15°C
We get the final temperature by adding the initial temperature of the water to the temperature change.
T(f) = 20°C + 11.15°C = 31.15°C
As a result, the combined temperature of the water and melted ice is 31.15°C.
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9. A bicyclist is moving down a hill. Her position on the hill gives her 720 J of potential energy, and her
movement gives her 680 J of kinetic energy. What is her total mechanical energy?
A. 260 J
B. 1400 J
C. 2648 J
D. 2.86×105 J
The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.
The total mechanical energy of a moving object is the sum of its kinetic energy and potential energy. Kinetic energy is defined as the energy an object has due to its motion, whereas potential energy is the energy an object has due to its position or configuration.Therefore, the total mechanical energy of the bicyclist is calculated by adding her kinetic energy and potential energy. According to the question, the bicyclist has 720 J of potential energy and 680 J of kinetic energy.Total mechanical energy = Potential energy + Kinetic energy = 720 J + 680 J = 1400 JTherefore, the total mechanical energy of the bicyclist is 1400 J. Therefore, the correct answer is option B.For more questions on mechanical energy
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A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.
Answer:
True
Explanation:
The main differences between a physical property and a chemical property are mentioned below:
A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points.
While A chemical property describes the ability of a substance to undergo a specific chemical change.
How much power is used by a washing machine if it does 7,200 joules of work in 3 minutes?
So, the power that used by the washing machine is 400 Watt.
IntroductionHi ! Here, I will help you to calculate the power generated. Power is work done per unit time. If a person or machine can do a large amount of work in the shortest possible time, it will produce or require a large amount of power. The relationship between power, work, and time is expressed in the equation:
\( \boxed{\sf{\bold{P = \frac{W}{t}}}} \)
With the following condition :
P = power that produce or require (Watt)W = work that had done (J)t = interval of the time (s)Problem SolvingWe know that :
W = work that had done = 7,200 Jt = interval of the time = 3 minutes = 3 × 60 = 180 sWhat was asked :
P = power that used = ... WattStep by step :
\( \sf{P = \frac{W}{t}} \)
\( \sf{P = \frac{7,200}{18}} \)
\( \boxed{\sf{P = 400 \: Watt}} \)
Conclusion :So, the power that used by the washing machine is 400 Watt.
Match the description of an object's motion with the position-time graph that represents at A. slowing down B. moving with constant speed C. not moving D. speeding up
The descriptions of object's motion with the position-time graph that represents at:
D. speeding up - Graph 1
C. not moving - Graph 2
B. moving with constant speed - Graph 2
A. slowing down - Graph 3
What is motion?Motion is the conceptual notion in which an object moves from its position with respect to time. Motion is acceptable to be described in terms of displacement, distance, velocity, acceleration, speed.
Furthermore, Motion is a change in an object's position over time. It is the result of forces acting upon an object, and can be described in terms of distance, speed, and direction.
Therefore, it is a change of position or orientation of a body with the change of time. looking at the attached graph, it can then be concluded that the correct answers are as given above
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If you dip hand in cold water after having dipped in warm water wii you feel the water colder than actually is?
Your hand feels colder when it transitions from warm to "colder" (room temperature) water.
What happens when you put your hand from warm water to cold water?Your hand feels colder when you move it from the warm water to the "colder" (room temperature) water. Skin surface temperature will decrease in a constant ambient environment as a result of sympathetic nerve activity increasing and blood flow decreasing as a result of cutaneous receptors triggered by ice-water immersion of one hand in the palm skin of the non-immersed opposite hand.
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A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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An overhead East-West transmission line carries a current of 250. A in each of two parallel wires. The two wires are separated by 1.20 m, the northern wire carries current to the east, and the southern wire carries current to the west. (a) Please find the magnitude and the direction of the magnetic field at a point midway between the two wires. (Ignore the carth's magnetic field.) (b) Please find the magnitude and the direction of the magnetic field at a point that is 2.00 m below the point of part (a). (lgnore the earth's magnetic field.)
Answer: (a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page.
(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.
(a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page. Between two parallel current-carrying wires, the magnetic field has a direction that is perpendicular to both the direction of current flow and the direction that connects the two wires.
According to the right-hand rule, we can figure out the direction of the magnetic field. The right-hand rule says that if you point your thumb in the direction of the current and curl your fingers, your fingers point in the direction of the magnetic field. As a result, the northern wire's magnetic field is directed up, while the southern wire's magnetic field is directed down. Since the two magnetic fields have the same magnitude, they cancel each other out in the horizontal direction.
The magnetic field at the midpoint is therefore perpendicular to the plane formed by the two wires, and the magnitude is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × 0.600 m) = 1.20 × 10⁻⁵ T.
The magnetic field is out of the page because the two magnetic fields are in opposite directions and cancel out in the horizontal direction.
(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.
The magnetic field at a point that is 2.00 m below the midpoint is required. The magnetic field is inversely proportional to the square of the distance from the wires.
Therefore, the magnetic field at this point is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × √(1.20² + 2²) m) = 2.93 × 10⁻⁷ T. The magnetic field at this point is out of the page since the wires are so far apart that they can be treated as two separate current sources. The field has the same magnitude as the field created by a single wire carrying a current of 250 A and located 1.20 m away.
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A bicyclist pedaling up a hill is this a form of kinetic energy or potential energy?
Answer:
Kinetic
Explanation:
Its a moving action
When a bicyclist is pedaling up a hill, it is a form of potential energy. The correct option is option potential energy.
An object's position or configuration in relation to other things might provide it potential energy. The potential energy in this situation is gravitational potential energy.
Because they are being lifted against gravity as they ascend the hill, the cyclist gains gravitational potential energy. The potential energy of the cyclist increases as they ascend.
The potential energy will be transformed into kinetic energy once the cyclist begins pedaling or moving downward.
As a result of their increased height above the ground, cyclists are building up potential energy as they bike up a hill. They gain speed as they cycle downhill, transforming that potential energy into kinetic energy.
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A 5.1 kg
cat and a 2.2 kg
bowl of tuna fish are at opposite ends of the 4.0-m
-long seesaw.
The minimum distance the 2.2 kg bowl of tuna fish can be from the other end of the seesaw so that the seesaw remains balanced is 1.85 meters.
Let's call the distance that the 2.2 kg bowl of tuna fish is from the center of the seesaw "x." The moment of the cat is equal to its weight times its distance from the center of the seesaw, which is (5.1 kg)(0.8 m) = 4.08 Nm.
For the seesaw to remain balanced, the sum of the moments on one side of the seesaw must be equal to the sum of the moments on the other side. Therefore, we can write:
4.08 Nm = (2.2 kg)x
Solving for x, we get:
x = 1.85 m
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--The complete Question is, If the 5.1 kg cat moves 0.8 meters away from the seesaw's center, what is the minimum distance the 2.2 kg bowl of tuna fish can be from the other end of the seesaw so that the seesaw remains balanced? --
A student is holding a stone at a certain height. The stone has 50 joules of potential energy and 0 joules of kinetic energy. The stone is released from that height. How much energy does the stone have right before it hits the ground
A student is holding a stone at a certain height. The stone has 50 joules of potential energy and 0 joules of kinetic energy. The stone is released from that height. the stone has 50 joules of kinetic energy right before it hits the ground, with no remaining potential energy. This energy is responsible for the stone's motion and will be dissipated upon impact with the ground.
When the stone is released from a certain height, it begins to fall under the influence of gravity. As it falls, its potential energy is converted into kinetic energy. At the same time, the total mechanical energy of the stone remains constant, assuming there is no significant loss of energy due to factors such as air resistance or friction. Initially, the stone has 50 joules of potential energy, which gradually decreases as it falls. At the same time, its kinetic energy increases, as it gains speed during its descent. This is due to the principle of conservation of energy, which states that energy cannot be created or destroyed, but only transferred or transformed.
Right before the stone hits the ground, all of its potential energy is converted into kinetic energy. This means that the stone has 50 joules of kinetic energy at that moment. The potential energy has been completely transformed into the energy of motion. Therefore, the stone has 50 joules of kinetic energy right before it hits the ground, with no remaining potential energy. This energy is responsible for the stone's motion and will be dissipated upon impact with the ground.
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a boy of mass 40kg and a girl of mass 30kg play on the seesaw of negligible weight. if the boy sits 270cm from the pivot of the seesaw, where must the girl sit to make it balance
Answer:
The answer is 360
Explanation:
Follow me!!!
3. Riddle:
I am black when you buy me, red when you use me and grey when you throw me away.
What am I?
Answer:
The answer is charcoal
Answer:
Charcoal
Explanation:
In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is the most ideal state for that system?
Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.
Thermal energy is the energy possesed by a system due to its temperature.
In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.
Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy
ANSWER:
A. Entropy
Independent practice
1.
a.
2.
Calculate the density p (in kg/m) for each of the following:
m = 10 kg and V=10 m3
b. m = 160 kg and V = 0.1 m3
C. m = 220 kg and V = 0.02 m3
A wooden post has a volume of 0.025 m' and a mass of 20 kg. Calculate its
density in kg/m
Challenge. A rectangular concrete slab is 0.80 m long, 0.60 m wide and 0.04
m thick. |
Calculate its volume in m?,
b. The mass of the concrete slab is 180 kg. Calculate its density in kg/m.
3.
a.
Explanation:
formula: Mass
Density x volume
2a) m=10kg v=0.3m³
10÷0.3=33.3 kg/m
2b) m = 160 kg V=0.1m³
160÷0.1=1600 kg/m
2c) m = 220 kg V = 0.02m³
220÷0.02=11000 kg/m
A wooden post has a volume of 0.025m³ and a mass of 20kg. Calculate its density in kg/m.
density = volume ÷ mass
20÷ 0.025=800 kg/m
Challenge: A rectangular concrete slab is 0.80m long, 0.60 m wide and 0.04m thick. Calculate its volume in m³.
Formula : Length x width x height = Volume
0.80 x 0.60 x 0.04 = 0.0192m³
B) The mass of the concrete slab is 180 kg. Calculate its density in kg/m.
density = volume ÷ mass
180 ÷ 0.0192 = 9375 kg/m
Beyond the shallow-water zone of ponds and lakes is the __________ zone. This is the open-water zone that extends down to the depth of light penetration.
Beyond the shallow-water zone of ponds and lakes is the pelagic zone. The pelagic zone is the open-water region that extends beyond the shallow areas and reaches down to the depth of light penetration. It is also known as the limnetic zone in freshwater environments.
In the pelagic zone, sunlight can penetrate to a certain depth, allowing photosynthesis to occur. This depth varies depending on factors such as water clarity and the presence of suspended particles. The upper layer of the pelagic zone, where sufficient sunlight reaches, is called the euphotic zone. This is where primary production, carried out by phytoplankton and other photosynthetic organisms, takes place.
The pelagic zone is characterized by its vast expanse of open water and is home to a diverse array of organisms. Zooplankton, small fish, and other aquatic organisms inhabit this zone and form the basis of the food web. Predatory fish, such as trout and bass, are often found in the pelagic zone, preying on the smaller organisms.
Overall, the pelagic zone plays a crucial role in the ecology and productivity of aquatic ecosystems, supporting a wide range of organisms and contributing to the overall biodiversity of lakes and ponds.
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Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?
O solid
O liquid
solid or gas
liquid or gas
the answer is solid
solid
Explanation:
because it has a definite shape and volume