An electric vehicle starts from rest and accelerates at a rate of 2.0 m/s2 in a straight line until it reaches a speed of 21 m/s. The vehicle then slows at a constant rate of 1.1 m/s2 until it stops. (a) How much time elapses from start to stop? (b) How far does the vehicle move from start to stop?

Answers

Answer 1

Answer:

total time = 29.59 sec

total distance = 310.70 m

Explanation:

given data

accelerates at a rate = 2.0 m/s²

speed = 21 m/s

slows at a constant rate = 1.1 m/s²

solution

first we take  equation of motion

v = u + at        ............1

21 = 0 + 2 × t

t = 10.5 sec

now in case of deceleration again we take here

0 = 21 - 1.1 × t

t = 19.09 sec

so that total time is

total time = 10.5 + 19.09

total time = 29.59 sec

and

in case of acceleration

v² = u² + 2as           ...................2

21² = 0 + 2 × 2 × s

s = 110.25 m

and when it is in case of deceleration we take here

0 = 21² - 2 × 1.1 × s

s = 200.45 m

so that here total distance is

total distance = 110.25  + 200.45

total distance = 310.70 m


Related Questions

Two muscles in the back of the leg pull upward on the Achilles tendon, as shown in the figure below. (These muscles are called the medial and lateral heads of the gastrocnemius muscle.)F2 = 210 N18°F1 = 210 N 18°Find the magnitude (in N) and direction (in degrees counterclockwise from the dotted line) of the total force on the Achilles tendon.-magnitude -directionWhat type of movement could be caused by this force?

Two muscles in the back of the leg pull upward on the Achilles tendon, as shown in the figure below.

Answers

In order to find the total force, we need to sum the forces F1 and F2.

To do so, let's calculate the horizontal and vertical components of each force.

Before calculating these components, let's use the following angles, considering as reference the positive x-axis:

So we have:

\(\begin{gathered} F_{1x}=F_1\cdot\cos (\theta_1) \\ F_{1x}=210\cdot\cos (72\degree) \\ F_{1x}=210\cdot0.309=64.89\text{ N} \\ \\ F_{1y}=F_1\cdot\sin (\theta_1) \\ F_{1y}=210\cdot\sin (72\degree) \\ F_{1y}=210\cdot0.951=199.71\text{ N} \\ \\ F_{2x}=F_2\cdot\cos (\theta_2) \\ F_{2x}=210\cdot\cos (108\degree) \\ F_{2x}=210\cdot(-0.309)=-64.89\text{ N} \\ \\ F_{2y}=F_2\cdot\sin (\theta_2) \\ F_{2y}=210\cdot\sin (108\degree) \\ F_{2y}=210\cdot0.951=199.71\text{ N} \end{gathered}\)

Now, adding the components of each direction, we have:

\(\begin{gathered} F_x=F_{1x}+F_{2x}=64.89-64.89=0 \\ F_y=F_{1y}+F_{2y}=199.71+199.71=399.42\text{ N} \end{gathered}\)

The resulting force is given by:

\(\begin{gathered} F=\sqrt[]{F^2_x+F^2_y} \\ F=\sqrt[]{0^2+399.42^2} \\ F=399.42\text{ N} \end{gathered}\)

Since the resulting force has only vertical component, its direction is upwards (positive y direction), and the type of movement caused is a vertical movement.

Two muscles in the back of the leg pull upward on the Achilles tendon, as shown in the figure below.

A box with a mass of 30kg accelerates at a rate of 3m/s. If the force of friction on the box is 20N, how much force did you exert in order to move it?

Answers

The force exerted in order to move the box is 404 N.

What is force?

Force is a pull or push effect on a body.

The force on a body is related to the mass and the acceleration of the body.

The acceleration of a body is inversely related to the mass of of the body and directly related to the force acting on it.

Force = mass * acceleration.

Net force = Force applied - (weight of the body + frictional force)

Force applied = Net force + weight of the body  + frictional force

Weight of the body = 30 * 9.8 m/s = 294 N

Net Force = 30 * 3 = 90 N

Force applied = 90 N + 294 N + 20 N

Force applied = 404 N

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Metalloids have __________ and ___________ properties of metals and nonmetals.
5. They act as ______________ .

Answers

According to the research, the correct terms to complete the statements about Metalloids are:

Metalloids have unique and intermediate properties of metals and nonmetals.They act as semiconductors.

What are Metalloids?

They are very varied elements that have three or more electrons in their valence shell ad Boron (B), Silicon (Si) that conduct electricity more effectively than non-metals, being considered as semiconductors.

In this sense, these have intermediate properties between metals and non-metals in terms of bonds and ionization capacity, being unique among themselves in shape, appearance and color.

Therefore, we can conclude that metalloids are electrical semiconductors whose intermediate properties allow them to act as metals in some situations and as non-metals in others.

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A drag racer, starting from rest, speeds up for 402 m with an acceleration of +17.0 m/s2. A parachute then opens, slowing the car down with an acceleration of –6.10 m/s2. How fast is the racer moving 3.50 × 102 m after the parachute opens?

Answers

The racer is running at a speed of approximately 96.943 meters per second at 350 meters after the parachute is opened.

According to this question, the drag race accelerates and later decelerates uniformly and we can determine the final speed of the vehicle by the following kinematic formula:

\(v = \sqrt{v_{o}^{2}+2\cdot a\cdot s}\) (1)

Where:

\(v_{o}\) - Initial speed, in meters per second. \(v\) - Final speed, in meters per second.\(a\) - Acceleration, in meters per square second.\(s\) - Traveled distance, in meters.

Acceleration phase

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(a = 17\,\frac{m}{s^{2}}\) and \(s = 402\,m\), then the final speed of the drag racer is:

\(v = \sqrt{\left(0\,\frac{m}{s} \right)^{2} + 2\cdot \left(17\,\frac{m}{s^{2}} \right)\cdot (402\,m)}\)

\(v \approx 116.910\,\frac{m}{s}\)

Deceleration phase

If we know that \(v_{o} \approx 116.910\,\frac{m}{s}\), \(a = -6.10\,\frac{m}{s^{2}}\) and \(s = 350\,m\), then the final speed of the drag racer is:

\(v = \sqrt{\left(116.910\,\frac{m}{s} \right)^{2} + 2\cdot \left(-6.10\,\frac{m}{s^{2}} \right)\cdot (350\,m)}\)

\(v \approx 96.943\,\frac{m}{s}\)

The racer is running at a speed of approximately 96.943 meters per second at 350 meters after the parachute is opened.

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true or false- When an atom's charge is balanced, the amount of negative charge equals the amount of neutral charge.

Answers

the answer would be true


2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m

Answers

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Whoever can answer this is smart
What is an electrostatic force in a simple definition
What is a magnetic force in simple definition

Answers

An electrostatic force = forces that can push or pull an object without touching it.

A magnetic force = can attract or repel of a force that is exerted between poles (like north and south). It is between electrically charged particles.

Answer:

Hope it helps you

Explanation:

An electrostatic force is an attractive as well as replusive force caused by the electric charge particles.

Magnetic force is a consequence of electromagnetic force and is caused due to the motion of charges.

PLS RATE AS BRAINLIEST ANSWER

HONI A ball is rolling steady on the floor. (a) Draw and label all the forces acting on the ball. (b) Describe the relationships between all the forces acting on the ball ​

Answers

a) The image is attached to this answer

b) The kinetic friction force affects the forward force of the ball.

What is the relationship between the forces that act on a rolling ball?

The force that opposes a rolling ball's motion is called rolling friction. It slows the ball down by acting in the opposite direction to that of the ball's motion. The weight of the ball and the type of the surface are two variables that affect rolling friction.

The force that a surface uses to maintain the weight of an object that is resting on it is known as the normal force. When a ball is rolling, the normal force exerts itself perpendicular to the surface the ball is moving on. It maintains the ball's weight balance and offers the required reaction force for rolling motion.

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2.) What does it mean when you get a negative percent error? Can you give an example?

Answers

A negative percent error occurs when there is a negative change in the measurement.

What is negative percent error?

A negative percent error occurs when taking change in a particular measurement.

For example, let us obtain the change in the following measurement as shown below.

initial measurement = 150 units

final measurement = 100 units

Find the percentage change in the following measurement;

percentage change = ( final measurement - initial measurement ) / ( initial measurement ) x 100%

percentage change = ( 100 - 150 ) / 100 x 100 %

percentage change = -50 %

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Directions: Use the universal law of gravitation to calculate the acceleration due to gravity on different planets
Planet
Mass = KG
Radius = M
Force experienced by 75kg astronaut
Acceleration due to Gravity
Mercury
3.3x1023 kg
2.439x106 m




Venus
4.87x1024 kg
6.052x106 m




Earth
5.972x1024 kg
6.378x106 m




Mars
6.417x1023 kg
3.389x106 m




Jupiter
1.899x1027 kg
6.991x107 m




Saturn
5.685x1026 kg
5.823x107 m




Uranus
8.682x1025 kg
2.536x107 m




Neptune
1.024x1026 kg
2.462x107 m

Answers

Answer:

5gbyb5hn6 kub5yyb6hb5 Hi hi7ki6mh4yutyimimy mjymyjmjyhnttbr

What causes Ep to be converted to Ek? (giving brainliest to right anwser)

Answers

Answer:

Energy is a quantity that can be verticality from one to another,

sum of all the energy of the system remains constant if there is no friction force.

Explanation:

The potential energy of a system is a configuration energy, that is, for a given position the energy has a value with respect to a reference point.

Kinetic energy is an energy related to the movement of bodies, that is, a body must have a speed to have kinetic energy.

Energy is a quantity that can be verticality from one to another, the gravitational potential that a body has at a given height when the body is released accelerates by action of gravity, in this case the potential energy decreases and the scientific energy increases, It is appropriate to clarify that the sum of all the energy of the system remains constant if there is no friction force.

Please show work if possible! Thank you!!
A 2.0 x 103 kg roller coaster travels around a vertical 24-m radius loop. If the coaster has a tangential speed of 18 m/s at the lowest point of the loop, what is the normal force that is exerted on the coaster by the track at this point?
a. 5.3 x 10^4 N
b. 4.7 x 10^4 N
c. 3.0 x 10^4 N
d. 2.7 x 10^4 N

Answers

B. The normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.

Normal force exerted on the coaster at the lowest point

Fₙ = mg + mv²/r

where;

m is mass of the coasterv is speed of the coasterr is radius of the path

Fₙ = (2,000 x 9.8) + (2,000 x 18²)/24

Fₙ = 46,600 N

Fₙ =  4.7 x 10⁴ N

Thus, the normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.

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help pls!!

Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.

A) What is the amplitude of the wave ? Include correct units.
B) Use the graph to determine the time of one wave. Use it to find the frequency.
C) If the speed of the wave is 25 cm/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.

help pls!!Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.A)

Answers

(a) The amplitude of the wave is determined as 8 cm.

(b) The period of the wave motion is  20 s and the frequency of the wave is 0.05 Hz

(c) The wavelength of the wave is 500 cm.

What is the amplitude of the wave ?

(a) The amplitude of the wave is the maximum displacement of the wave.

from the graph, amplitude of the wave = 8 cm

(b) The period of the wave motion is calculated as;

T = 20 s

The frequency of the wave = 1/T = 1/20 s = 0.05 Hz

(c) The wavelength of the wave is calculated by applying the following wave formula.

λ = v / f

λ = 25 cm/s / 0.05 Hz

λ = 500 cm

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A tie-bar has a cross-section area of 125mm² and is subjected to a pull of 10kN. Calculate the stress in Megapascals​

Answers

The stress in Magapascals is 80 Magapascals

This question can be solved by applying Young's modulus.

Young's modulus : Young's modulus states that, stress  is directly proportional to strain.

Where Stress is pressure acting the body. The s.i unit of stress is N/m² or Pascal. And it can be expressed mathematically as,

\(P = F/A\)................. Equation 1Let: P = Stress, F = Force on the tie-bar, A = cross section area of the tie-bar

From the question,

Given\(F = 10 kN\) \(= 10000 N\), \(A = 125 mm^{2}\) \(= (125/10^6)\) \(= 1.25*10^{-6} m^{2}\)Substitute these values into equation 1

\(P = 10000/(125*10^{-6} )\)

\(P =\) \(8*10^{7}\) Pascals

\(P =\) 80 Magapascals

Hence the stress in Magapascals is 80 Magapascals

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The stress experimented by the tie-bar is 80 megapascals.

The tie-bar is under axial load. Under the assumption that force is distributed uniformly in the cross-section area, we can use the following definition of normal stress (\(\sigma\)), in megapascals:

\(\sigma = \frac{F}{A}\) (1)

Where:

\(F\) - Axial force, in meganewtons.

\(A\) - Cross-section area, in square meters.

If we know that \(F = 10\times 10^{-3}\,MN\) and \(A = 125\times 10^{-6}\,m^{2}\), then the stress experimented by the tie-bar is:

\(\sigma = \frac{10\times 10^{-3}\,MN}{125\times 10^{-6}\,m^{2}}\)

\(\sigma = 80\,MPa\)

The stress experimented by the tie-bar is 80 megapascals.

How does solar weather affect Earth’s magnetosphere? Select the two correct answers.

It causes geomagnetic storms.

It generates auroras.

It develops solar wind.

It forms radiation belts.

Answers

A. Geomagnetic storms and B. Auroras.

A geomagnetic storm occurs when the solar wind collides with the electromagnetic field of the earth generating disturbances in the Earth's magnetosphere.
An aurora is a luminescent formation produced by the interaction of charged solar particles and the terrestrial electromagnetic field. The solar wind pushes these particular to the terrestrial electromagnetic field that later transports them to the poles, where they are seen in different colors according to the type of particle.

In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

if you sit on the edge of a very light table, it is likely the table will topple over. explain?​

Answers

Answer:

This question heavily relies on the weight of the table and the weight of the person sitting on it, if a 90 pound person sits on the side of a 40 pound table, it will topple over.

Explanation: Tables are generally have a 50/50 weight distribution ratio so that they are even on the ground and can stay upright, but if a table is too light and the person or object sitting on it is heavier than the side they/it is placed on, it will fall.

50 points!

Light waves of frequency 6 x 10^14 Hz have a wavelength of 3.75 x 10^-7 m in water. What is their speed in water?

Answers

\(\\ \bull\sf Frequency=f=6\times 10^{14}Hz\)

\(\\ \bull\sf Wavelength=\lambda=3.75\times 10^{-7}m\)

Now

. Velocity=v

\(\\ \sf\longmapsto v=f\lambda\)

\(\\ \sf\longmapsto v=6\times 10^{14}s^{-1}\times 3.75\times 10^{-7}m\)

\(\\ \sf\longmapsto v=22.5\times 10^7ms^{-1}\)

Answer:

velocity=v = 22.5 * 10⁷ m s ^ - 1

Explanation:

\(\sf\longmapsto \: Frequency = 6 * 10 ^ {14 } H z\)

\(\sf\longmapsto \: Wavelength = 3.75 \times 10 {}^{-7} m\)

Now let's solve out!!

\(\sf\longmapsto \: velocity = frequency \lambda\)

\(\sf\longmapsto \: velocity=6 \times 10 {}^{14} s {}^{ - 1} \times \ 3.75 \times 10 {}^{ - 7} m\)

\(\sf\longmapsto \: velocity= 22.5 \times 10 ^ 7 m s ^ { - 1}\)

Note:

\(\lambda\) is the Greek letter known as lambda.

can a particle with constant speed be accelarating?
what if it has constant velocity?​

Answers

Explanation:

it can be safely concluded that an object moving in a circle at constant speed is indeed accelerating. It is accelerating because the direction of the velocity vector is changing.

When an object is moving with constant velocity, it does not change direction nor speed and therefore is represented as a straight line when graphed as distance over time.

Martin has hypothesized that the size and types of trees differ between valleys and higher elevations. He sets up a transect line in a wooded valley and randomly creates three 10 x 10 meter plots along the transect line, recording GPS coordinates for the northwest corner of each plot. He identifies and measures (diameter at breast height) every tree within the plots. He repeats this procedure in a wooded area on the ridge above the valley.

Using the scenario above, state the independent and dependent variables.

Answers

Answer: The dependent Variables include: Size and Types of trees.

The independent Variables include:

geographic elevations that is, valleys and the higher elevations.

Explanation:

The dependent variable simply refers to the variable a researcher tests or measures during an experiment. On the other hand, the independent variable simply refers to the variable that's controlled during an experiment.

Based on the definition above, the dependent variables include the size and the types of trees while the independent variables include the

geographic elevations that is, the valleys and the higher elevations.

A lump of lead with mass 0.50 kg is dropped from a height of 20 m onto a hard surface. It does not rebound but remains there at rest for a long period of time.
what are:
a)∆Q,(b)∆W and (c)∆U for the lead during this process?
d) What is the temperature change in the lead immediately aer the impact? [specific heat capacity of lead = 128 kJ/kg K]

Answers

The temperature change in the lead immediately   ∆T=1.56 K.

Temperature is a physical amount that expresses the hotness of a count number or radiation. There are 3 sorts of the temperature scale.

Temperature is a measure of the common kinetic power of the particles in an item. when the temperature will increase, the motion of the debris also increases. Temperature is measured with a thermometer or a calorimeter.

Temperature is a degree of the common kinetic strength of the particles of a substance. The higher the temperature of an item, the better its kinetic strength. Kinetic electricity is a form of electricity related to movement.

a.  ΔQ=mgh

ΔQ=0.5×9.80×20

ΔQ=98 J.

⇒∆U= ∆Q

⇒∆W=0

d. The temperature change is ∆T=1.56 K

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plzzzzzzzzzzzzz help SERIOUSLY ​

plzzzzzzzzzzzzz help SERIOUSLY

Answers

i think the answer is 1 .. probably because at this point the body has only potential energy while the rest positions do possess kinetic energy as well . so 1 would surely be correct

What order does energy flow: sun prodecer consumer?

Answers

Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.

Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.

At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.

The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.

Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.

At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.

It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.

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2. 290 grams of water is to be heated from 24.0% to 100.0°C to make a cup of
tem, how much heat must be added? The specific heat of water is 4.18 J/g•C

Answers

Answer:

92127.2 j

Explanation:

Given that :

Mass of water = 290 g

Specific heat of water (C) = 4.18 j/g.C

Initial Temperature (t1) = 24°C

Final temperature (t2) = 100°C

Using the relation :

Q = mCdt

dt = change in temperature =( 100 - 24)° = 76°C

Q = quantity of heat ; C = specific heat capacity;

m = mass of substance

Q = 290 g * 4.18 j/g.C * 76°C

Q = 92127.2 j

what is the first letter of the alphabet?
A:B B:A


C:Z or D:D

Answers

Answer:

B:A

Explanation:

because the alphabet goes

A B C D E F G

Answer: B.) A

This was a little complicated because of the answer letters LOL

PLS I NEED HELP ASAP
A rollercoaster speeds up from rest to 100mph (45m/s) in 1.2s. (Acceleration=37.5)
The rollercoaster car then travels vertically upwards, and decelerates at 10m/s^2
How much time passes before it is stationary (for a moment)?

Answers

Answer:

5.7s

Explanation:

it is stationary when v = 0 so use the equations of motion to find t. Please see photo attached

PLS I NEED HELP ASAP A rollercoaster speeds up from rest to 100mph (45m/s) in 1.2s. (Acceleration=37.5)The

The time passed before it is stationary (for a moment) will be 5.7s.

What is acceleration?

Acceleration is defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

A rollercoaster speeds up from rest to 100mph (45m/s) in 1.2s. The rollercoaster car then travels vertically upwards, and decelerates at 10m/s^2

Time taken for the change in speed is t.

The acceleration is given by

-10= (45 -0)/ t

t = 4.5

Total time passed = 4.5 +1.2 = 5.7s

Thus, the time passed is  5.7s.

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If the speed of an object in uniform circular motion is constant and the radial distance is doubled, by what factor does the magnitude of the radial acceleration decrease?

Answers

Answer: Half

Explanation:

Given

The object is in uniform circular motion with constant speed.

Radial acceleration of the object is given by

\(\Rightarrow a_r=\dfrac{v^2}{r}\)

Where, \(a_r=\text{Radial acceleration}\)

\(v=\text{speed}\\r=\text{distance from the axis of rotation}\)

If the radial distance \(r\) is doubled, i.e. \(2r\)

Radial acceleration is

\(\Rightarrow a'_r=\dfrac{v^2}{2r}\\\\\Rightarrow a'_r=\dfrac{a_r}{2}\)

Radial acceleration becomes half of the initial value.

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If the speed of an object in uniform circular motion is constant and the radial distance is doubled,

A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?​

Answers

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

Kinematics:Question 2
We are accelerating whenever we are?

Answers

Moving faster is the answer to the question

A rock has a gravitational potential energy 1960 J at 100 meters high. What is the mass of the rock?

Answers

According to the information, the mass of the rock is found to be 2 kg.

What is Potential energy?

Potential energy may be defined as a type of stored energy that depends upon the relative position of various parts of a system. This energy is held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

According to the question, the potential energy is calculated with the help of the following formula:

Potential energy (P.E) = m × g × h.

where, P.E = 1960 J, g = 9.8 m/sec, and height = 100 m, mass = ?

mass = P.E / g × h = 1960/980 = 2 kg.

Therefore, the mass of the rock is found to be 2 kg.

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