ANYONE CAN HELP WITH THIS QUESTION ?!! ;)​

ANYONE CAN HELP WITH THIS QUESTION ?!! ;)

Answers

Answer 1

Answer:

32.50

Step-by-step explanation:


Related Questions

Which inequality is true when x = 4?

Answers

Answer:

x + 5 < 3

Step-by-step explanation:

One inequality could be x > 3. So when x = 4 this is true because 4 is greater than 3.

first to get it right gets brainliest

What kind of room has no doors or windows

Answers

a room with no doors or windows is a mushroom

A barrel contained 50 Gallons of oil.Oil leaked out of the barrel at a rate of 5 gallons every 2 days.How many days did it take for all 50 gallons of oil to leak out of the barrel?

Answers

Answer:

20 days

Step-by-step explanation:

50 divided by 5 = 10

10 times 2 = 20

Let 0 be an acute angle of a right triangle. Evaluate the other five trigonometric functions of 0.

Let 0 be an acute angle of a right triangle. Evaluate the other five trigonometric functions of 0.

Answers

Answer:

1. Cos θ = 6√2 / 11

2. Tan θ = 7 / 6√2

3. Cosec θ = 11 / 7

4. Sec θ = 11 / 6√2

5. Cot θ = 6√2 / 7

Step-by-step explanation:

From the question given above, the following data were obtained:

Sine θ = 7 / 11

Next, we shall determine the adjacent of the right triangle. This can be obtained as follow:

Sine θ = 7 / 11

Sine θ = Opposite / Hypothenus

Opp = 7

Hypo = 11

Adj =?

Hypo² = Opp² + Adj²

11² = 7² + Adj²

121 = 49 + Adj²

Collect like terms

Adj² = 121 – 49

Adj² = 72

Take the square root of both side

Adj = √72

Adjacent = 6√2

1. Determination of Cos θ

Adjacent = 6√2

Hypothenus = 11

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = 6√2 / 11

2. Determination of Tan θ

Opposite = 7

Adjacent = 6√2

Tan θ =?

Tan θ = Opposite / Adjacent

Tan θ = 7 / 6√2

3. Determination of Cosec θ

Sine θ = 7 / 11

Cosec θ =?

Cosec θ = 1 ÷ Sine θ

Cosec θ = 1 ÷ 7 / 11

Cosec θ = 1 × 11/7

Cosec θ = 11/7

4. Determination of Sec θ

Cos θ = 6√2 / 11

Sec θ =?

Sec θ = 1 ÷ Cos θ

Sec θ = 1 ÷ 6√2 / 11

Sec θ = 1 × 11 / 6√2

Sec θ = 11 / 6√2

5. Determination of Cot θ

Tan θ = 7 / 6√2

Cot θ =?

Cot θ = 1 ÷ Tan θ

Cot θ = 1 ÷ 7 / 6√2

Cot θ = 1 × 6√2 / 7

Cot θ = 6√2 / 7

Which graph below represents an inequality that begins with y < . . . .

Which graph below represents an inequality that begins with y &lt; . . . .

Answers

The graph which could represent an inequality which begins with y < .... is; Choice C; C.

Which of the answer choices represents an inequality: y < ...?

It follows from the task content that the graph which could represent an inequality that begins with y < ..is required to be determined.

Since the inequality symbol is less; it follows that the boundary line for the inequality would be a broken line and the region shaded is the region below the line.

Ultimately, the graph that could represent the inequality is; Choice C; C.

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Mr. and mrs. smith plan to roof the cabin on 2 consecutive days. Assuming that the chance of rain is independent of the day, what is the probability that it will rain both days?

Answers

The probability that it will rain both days is \(\frac{1}{4}\).

According to the question

Mr. and mrs. smith plan to roof the cabin on 2 consecutive days.

Assuming that the chance of rain is independent of the day

Probability is the chance that some event will happen.

It is the ratio of the number of ways a certain event can occur to the number of possible outcomes.

Probability = Number of ways it can occur/Total number of outcomes

Probability of rain on first day = 1/2

Probability of rain on second day = 1/2

Then

Probability of rain on both days = \(\frac{1}{2}\) × \(\frac{1}{2}\) = 1/4

Hence,

The probability that it will rain both days is \(\frac{1}{4}\).

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Arwen rolls a number cube (with sides labeled 1 through 6) twice. What is the
probability that the first or second result is the number 5?

The answer is 11/36.
Just how??

Arwen rolls a number cube (with sides labeled 1 through 6) twice. What is theprobability that the first

Answers

Answer: 1/36
1-6 to choose from
Only one 5
Rolling a 5 twice would mean
1/6 x 1/6 = 1/36

Find the common difference of the arithmetic sequence 2, 4, 6, ... ​

Answers

the answer to this question is 2

those answers ar all wrong!!= Discrete Random Variables Instructor created question points O Points: 0 of 1 Save Suppose that you buy two S1 Lotto Texas tickets What is the probability that both are winning? (Round to six decima

Answers

A discrete random variable represents a finite number of outcomes, and in the context of your question, we'll be looking at the probability of both Lotto Texas tickets winning.

Let's denote the probability of a single ticket winning as "p". Since you have two tickets, you want to find the probability of both winning, which can be calculated by multiplying the individual probabilities: P(both winning) = p * p = p^2.

To determine the exact probability (p), we would need to know the total number of possible ticket combinations and the number of winning combinations. However, you can substitute the specific probability values provided for the Lotto Texas game to calculate the final answer, rounding to six decimal places as requested.

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Torrance is shopping for a school party. His donation to the party is snack bags and juice boxes. Snack bags come in packages of 12, and juice boxes come in a package of 10. What is the fewest number of packages of each product Torrance must purchase so that he has the same number of snack bags and juice boxes? Use paper to show what you know about the least common multiple to support your answer. Enter your answers in the boxes. Torrance must purchase packages of snack bags and packages of juice boxes to have the same number of each

Answers

Answer:

Torrance must purchase 5 packages of snack bags and 6 packages of juice boxes.

Step-by-step explanation:

Given that:

Snack bags come in packages of 12.

Juice bags come in packages of 10.

To find:

Fewest number of packages of each product so that there are same number of snack bags and juice boxes.

Solution:

Number of snack bags when 1 package is bought = 12

Number of snack bags when 2 package is bought = 24

Number of snack bags when 3 package is bought = 36

Number of snack bags when 4 package is bought = 48

Number of snack bags when 5 package is bought = 60

Number of snack bags when 6 package is bought = 72

Number of juice bags when 1 package is bought = 10

Number of juice bags when 2 package is bought = 20

Number of juice bags when 3 package is bought = 30

Number of juice bags when 4 package is bought = 40

Number of juice bags when 5 package is bought = 50

Number of juice bags when 6 package is bought = 60

Number of juice bags when 7 package is bought = 70

We can see that when 5 packages of snack bags are bought and 6 packages of juice bags are bought, 60 bags of each are bought.

This can be found by finding the LCM as well.

LCM of 10 and 12 is 60.

It means we need to buy 60 bags of each item.

And we can easily find the number of packages for each.

Number of packages of snack bags to be bought = \(\frac{60}{12} =5\)

Number of packages of juice bags to be bought = \(\frac{60}{10} = 6\)

Torrance must purchase 5 packages of snack bags and 6 packages of juice boxes.

Find the positive numbers such that the sum of and its reciprocal is as small as possible.Does this problem require optimization over an open interval or a closed interval

Answers

Answer:

Yes and closed interval

Step-by-step explanation:

The computation is shown below:

For the sum and the reciprocal as small as the possible equation is as follows

\(\(\frac{d}{dx}\left(x+\frac{1}{x}\right)=0.\)\)

Now take out the derivates,

So,

\(\(1-\frac{1}{x^2}=0,\)\)

or we can say that

\(\(x^2-1=0\rightarrow x=\pm1.\)\)

As the only positive number is to be determined i.e

x = 1

So this problem needed the optimization over a closed interval and the same is to be considered.

Let f(x)= x. a. Using the definition of the derivative, compute the derivative at x=4 and x=9. b. Let a be a real number. Compute the derivative at x=a. c. This gives you a function of the input a we will call g(a). Evaluate this function at a=4 and a=9. d. Graph g and f on the same axes (you should attempt this by hand, but may use an online grapher like DESMOS to assist).. e. Examine the groph of f. Estimate what happens to the slope of the tangent line to this graph as x gets larger and larger? What happens to the volues of g as the x gets larger and larger?

Answers

a) f'(4) = 1/4, f'(9) = 1/6.

b) = lim(h->0) [(√(a + h) - √a) / h]

c) g(4) = f'(4) = 1 / 4, g(9) = f'(9) = 1 / 6

d) graph attached

e) The graph of f(x) = √x is a curve that starts at the origin (0, 0) and gradually increases as x becomes larger.

f) The rate at which the function is increasing slows down as x increases.

a. To compute the derivative of the function f(x) = √x using the definition of the derivative, we need to find the limit of the difference quotient as it approaches 0.

For x = 4:

f'(4) = lim(h->0) [(f(4 + h) - f(4)) / h]

= lim(h->0) [(√(4 + h) - √4) / h]

To simplify this expression, we can use the conjugate pair:

f'(4) = lim(h->0) [(√(4 + h) - √4) / h] × [(√(4 + h) + √4) / (√(4 + h) + √4)]

= lim(h->0) [(4 + h - 4) / (h(√(4 + h) + √4))]

= lim(h->0) [h / (h(√(4 + h) + √4))]

= lim(h->0) [1 / (√(4 + h) + √4)]

= 1 / (2√4)

= 1 / 4

Similarly, for x = 9:

f'(9) = lim(h->0) [(f(9 + h) - f(9)) / h]

= lim(h->0) [(√(9 + h) - √9) / h]

= lim(h->0) [(9 + h - 9) / (h(√(9 + h) + √9))]

= lim(h->0) [1 / (√(9 + h) + √9)]

= 1 / (2√9)

= 1 / (2 × 3)

= 1 / 6

b. To compute the derivative at x = a, we can follow the same process:

f'(a) = lim(h->0) [(f(a + h) - f(a)) / h]

= lim(h->0) [(√(a + h) - √a) / h]

c. To find g(a), we need to substitute the derivative expressions for each value of a:

For a = 4:

g(4) = f'(4) = 1 / 4

For a = 9:

g(9) = f'(9) = 1 / 6

d. To graph g and f on the same axes, we will use desmos [attached].

e. The graph of f(x) = √x is a curve that starts at the origin (0, 0) and gradually increases as x becomes larger.

f. As x gets larger and larger, the slope of the tangent line to the graph of f(x) decreases. This means that the rate at which the function is increasing slows down as x increases.

For g(a), as x (or a) gets larger and larger, the values of g(a) approach 0. This is because the derivative of √x is inversely proportional to the square root of x. Therefore, as x becomes larger, the derivative (the slope of the tangent line) approaches 0, indicating that the rate of change becomes smaller and smaller.

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Let f(x)= x. a. Using the definition of the derivative, compute the derivative at x=4 and x=9. b. Let


29. My grandson makes wall hangings by stitching
together 16 square patches of fabric into a 4 x 4
grid. I asked him to use patches of red, blue,
green and yellow, but to ensure that no patch
touches another of the same colour, not even di-
agonally.
The picture shows an attempt which fails only
because two yellow patches touch diagonally.
In how many different ways can my grandson
choose to arrange the coloured patches correctly?

29. My grandson makes wall hangings by stitchingtogether 16 square patches of fabric into a 4 x 4grid.

Answers

9514 1404 393

Answer:

  168

Step-by-step explanation:

Below are shown the 7 different kinds of arrangements that can be made. Each of these can be permuted into 24 different arrangements by assigning colors in a different order than the one used here:

  {1, 2, 3, 4} ⇒ {green, blue, red, yellow}

Then the total number of possible correct colorings is 7·24 = 168.

__

These colorings were found using a computer program that identified all 168 viable colorings, then eliminated permutations. It started by identifying ways to color 2 rows, then adding rows based on that.

_____

You'll notice that the last on the attached list most closely matches the one in the problem statement.

29. My grandson makes wall hangings by stitchingtogether 16 square patches of fabric into a 4 x 4grid.

According to LIMRA, 77% of husband-wife families with kids under 18 years old have life insurance. A random sample of six husband-wife families was selected. What is the probability that less than two families have life insurance?

Answers

The probability that less than two families out of the random sample of six husband-wife families have life insurance is approximately 0.23.

In this case, the probability of success (a family having life insurance) is 77%, which corresponds to a probability of 0.77. The probability of failure (a family not having life insurance) is the complement of the success probability, which is 1 - 0.77 = 0.23.

To calculate the probability that less than two families have life insurance, we need to find the probability of 0 or 1 success in a sample of six, using the binomial distribution formula. This can be calculated as the sum of the probabilities of these two outcomes.

The calculation involves evaluating the binomial probability function for each outcome and summing them up. The formula for calculating the probability of k successes in a sample of size n is given by: P(X = k) = C(n, k)  p^k  (1 - p)^(n - k), where C(n, k) represents the number of combinations of n items taken k at a time.

In this case, we need to calculate P(X < 2) = P(X = 0) + P(X = 1) = C(6, 0) 0.77^0 x 0.23^6 + C(6, 1)  0.77^1 x 0.23^5. Evaluating this expression will give us the desired probability.

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If fx=-4x2-3 please evaluate for f(8), listing the steps you take in order with their result. Find the inverse function f-1(x)

Answers

Answer:

A. -259

B. inverse function is 1/2 √(-x-3)

Step-by-step explanation:

Here, we want to find f(8)

Simply substitute x = 8 in the equation.

The equation is

f(x) = -4x^2 -3

So f(8) = -4(8)^2-3

f(8) = -256-3

f(8) = -259

Inverse of f(x) = -4x^2 -3

Simply equate this to m

m = -4x^2-3

-4x^2 = m + 3

x^2 = (m + 3)/-4

x^2 = -m/4 -3/4

x = √(-m-3)/4

x = 1/2√(-m-3)

Put back the value of x for m

x = 1/2 √(-x-3)

Work out the size of angle x.

Work out the size of angle x.

Answers

Answer:

x = 46°

Step-by-step explanation:

Angles on a straight line sum to 180°.

Therefore, the interior angle of the triangle that forms a linear pair with the exterior angle marked 130° is:

⇒ 180° - 130° = 50°

The interior angle of the triangle that forms a linear pair with the exterior angle marked 96° is:

⇒ 180° - 96° = 84°

The interior angles of a triangle sum to 180°. Therefore:

⇒ 50° + 84° + x = 180°

⇒ 134° + x = 180°

⇒ 134° + x - 134° = 180° - 134°

⇒ x = 46°

Therefore, the size of angle x is 46°.

Work out the size of angle x.

1 question Plus brainliest help fast and I will add you too please please help

1 question Plus brainliest help fast and I will add you too please please help

Answers

Answer:

its C

Step-by-step explanation:

Answer: C is the correct answer

Step-by-step explanation:

A guidance counselor wants to determine if there is a relationship between a student's number of absences, x, and
their grade point average (GPA), y. The given data list the number of absences and GPAs for 15 randomly selected
students.
15 1
0 6 9
12
3
3
1
2 7 0 4 9 10
Number of
Absences
GPA
2.1 4.3 4.5 3.2 4.0
1.7
3.8
2.9
3.6
3.4 2.6 3.1 2.8 2.8 4.1
Using technology, what is the value of r²?
O-0.56
O-0.32
O 0.32
O 0.56

Answers

The fraction by which the variance of the dependent variable is greater than the variance of the errors is known as R-squared. The correct option is C, 0.32.

What is R- Squared?

The fraction by which the variance of the dependent variable is greater than the variance of the errors is known as R-squared.

It is called so because it is the square of the correlation between the dependent and independent variables, which is commonly denoted by “r” in a simple regression model.

fraction of the variability in data values = (coefficient of correlation)² = r²

For the given data, the correlation can be found as shown below. Therefore, the value of r is -0.56. Since we need the value of  r², the value of is,

r² = (-0.56)²

r² = 0.3136 ≈ 0.32

Hence, the correct option is C, 0.32.

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A guidance counselor wants to determine if there is a relationship between a student's number of absences,
A guidance counselor wants to determine if there is a relationship between a student's number of absences,

three points t, u, and v on the number line have coordinates t, u, and v, respectively. is point t between points u and v ?

Answers

We can determine coordinates if point t is between points u and v by checking if u < t < v or v < t < u.

To determine if point t is between points u and v, we need to compare their coordinates. If u < v, then point t is between points u and v if and only if u < t < v. On the other hand, if v < u, then point t is between points u and v if and only if v < t < u.

Whether or not point t is between points u and v depends on the relationship between the coordinates of u and v. If u < v, t must fall between them, and if v < u, t must also fall between them.

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A 46 gram sample of a substance that's a by product of fireworks has a k-value of 0.1394. Find the substance's half-life in days. Round your answer to the nearest tenth.

N=N0e^-kt

Answers

The half life obtained to the nearest tenth is 5.0 days.

What is the half life?

The half life is the time taken for only half of the initial amount of the radioactive substance to remain. We know that we have to use the formula;

N=N0e^-kt

N = amount present at time t

No = Amount initially present

k = The constant

t = The half life

We now have that;

HALF LIFE = O.693/k

We have to recall that the term k is the decay constant for the process as shown.

Half life = O.693/0.1394

Half life = 5.0 days

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To get from one term to the next in a sequence, we multiply by 2 and then
add 4.
The third term in the sequence is 48.
What is the first term in the sequence?

Answers

Answer: the first term in the sequence is 9.

Step-by-step explanation:

Let the primary term be x.

At that point the moment term is 2x + 4.

And the third term is 2(2x + 4) + 4 = 4x + 12.

Since the third term is given as 48, we will set up an condition and unravel for x:

4x + 12 = 48

4x = 36

x = 9

4x2 – 15 = 85
I don’t understand this

Answers

Answer:

1.) x = 5

2.) x = -5

Step-by-step explanation:

(22x2 -  15) -  85  = 0  

4x2 - 100  =   4 • (x2 - 25)  

(x + 5)  •  (x - 5)    

4 • (x + 5) • (x - 5)  = 0  

 x+5 = 0              

x = -5

x-5 = 0  

I need both answers now please and don answer if u don’t know

I need both answers now please and don answer if u dont know

Answers

Answer:3048.7804878

Step-by-step explanation:

I took the same test p.s. you may need to round.

signment Submission r this assignment, you submit answers by question parts. The number of submissions remaining for each question part onily changes if you submit or change the answer. ssignment Scoring our best submission for each question part is used for your score. [-14 Points] SERCP11 2.1.P.011. The cheetah can reach a top speed of 114 km/h(71mih). While chasing its prev in a short sprint; a cheetan starts from rest and runs 50 m in a straight line, reaching a final speed of 95 krym (b) Deteemine the theetah's average aceleration during the short sprine. ms​s2 (b) Find its displacement at t=3.0 t. (Assume the cheetah maintains a conuant acceleration throughout the sprint.) m

Answers

(a) The cheetah's average acceleration during the short sprint is approximately 6.940 m/s².

(b) The cheetah's displacement at t = 3.0 s is approximately 31.23 meters.

(a) To determine the cheetah's average acceleration during the short sprint, we can use the following formula:

Average acceleration = (Final velocity - Initial velocity) / Time

The initial velocity of the cheetah is 0 km/h since it starts from rest, and the final velocity is 95 km/h. The time is not given in the question, so we'll need to use the displacement and final velocity to find the time first.

Given:

Initial velocity (u) = 0 km/h

Final velocity (v) = 95 km/h

Displacement (s) = 50 m

We know that:

Final velocity (v) = Initial velocity (u) + Acceleration (a) * Time (t)

Since the initial velocity is 0 km/h, the equation simplifies to:

Final velocity (v) = Acceleration (a) * Time (t)

We can convert the velocities to m/s for consistency:

Final velocity (v) = 95 km/h = 95 * (1000 m / 3600 s) = 26.39 m/s

So we have:

26.39 m/s = a * t

Now we need to find the time (t) using the displacement and final velocity. We can use the equation of motion:

s = u * t + (1/2) * a * t²

Since the initial velocity (u) is 0, the equation simplifies to:

s = (1/2) * a * t²

Plugging in the values:

50 m = (1/2) * a * t²

Now we have two equations:

26.39 m/s = a * t

50 m = (1/2) * a * t²

To solve for the average acceleration, we need to eliminate the time (t). Rearrange the first equation to solve for t:

t = 26.39 m/s / a

Substitute this expression for t in the second equation:

50 m = (1/2) * a * (26.39 m/s / a)²

Simplifying:

50 m = (1/2) * a * (26.39 m/s)² / a²

50 m = (1/2) * (26.39 m/s)² / a

Now we can solve for the average acceleration (a):

a = (1/2) * (26.39 m/s)² / (50 m)

a = 6.940 m/s²

Therefore, the cheetah's average acceleration during the short sprint is approximately 6.940 m/s².

(b) To find the displacement at t = 3.0 s, we can use the equation of motion:

s = u * t + (1/2) * a * t²

Given:

Initial velocity (u) = 0 km/h (0 m/s)

Time (t) = 3.0 s

Acceleration (a) = 6.940 m/s² (from part a)

Substituting the values:

s = 0 m/s * 3.0 s + (1/2) * 6.940 m/s² * (3.0 s)²

s = 0 m + (1/2) * 6.940 m/s² * 9.0 s²

s = 0 m + 31.23 m²/s²

s = 31.23 m²/s²

Therefore, the cheetah's displacement at t = 3.0 s is approximately 31.23 meters.

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if y = 0.5x + 5

and y = 30,

what will x=

Answers

x=35

Step-by-step explanation:

y=30

y=0.5x+5

you would take 30÷0.5=60

0.5x60+5

30+5=35

x=35

I think this is right, don't come at me if it's not lol

The function y=5.45+1.05(x+7)

Answers

Y= 1.05+ 12.8, hope this helps

I need help once again :(

I need help once again :(

Answers

1 is a
2 is x = 5
3 is no solution
4 is s=6
5 is infinite solutions
6 x=-1
I don't know if u need the work or just the answers but I hope I helped :)

A fifteen-year bond, which was purchased at a premium, has semiannual coupons. The amount for amortization of the premium in the second coupon is $982.42 and the amount for amortization in the fourth coupon is $1052.02. Find the amount of the premium. Round your answer to the nearest cent. Answer in units of dollars. Your answer 0.0% must be within

Answers

The amount of the premium is $1844.19.

Let's assume that the face value of the bond is $1000 and the premium is x dollars.

It is known that the bond has a semi-annual coupon and it is 15-year bond, meaning that it has 30 coupons.

Then the premium per coupon is `(x/30)/2 = x/60`.

The first coupon has the premium amortization of `x/60`.

The second coupon has the premium amortization of $982.42.

The third coupon has the premium amortization of `x/60`.

The fourth coupon has the premium amortization of $1052.02.And so on.

The sum of the premium amortizations is equal to the premium x: `(x/60) + 982.42 + (x/60) + 1052.02 + ... = x`.

This can be rewritten as: `(2/60)x + (982.42 + 1052.02 + ...) = x`

Notice that the sum of the premium amortizations from the 4th coupon is missing.

The sum of these values can be written as `x - (x/60) - 982.42 - (x/60) - 1052.02 = (28/60)x - 2034.44`.

Therefore, the equation can be written as: `(2/60)x + 2034.44 = x`.Solving for x, we get: `x = $1844.19`.

Therefore, the amount of the premium is $1844.19.

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A rectangular piece of paper has an area of 117 square inches and a perimeter of 44 inches. What are the dimensions of the paper?

Answers

Answer:

13x9

Step-by-step explanation:

half of perimeret of  rectangle L+W

half of perimeter of  rectangle = 44/2 = 22

L+W=22

LxW=117

  Think of 2 numbers that added =22 and multiplied =117

       13+9 =22

    13x9 =117

orange squash diluted 1 part squash to 7 parts water. Making 2 litres of diluted squash. How much water is needed?

Answers

We need 1.75 litres of water to make 2 litres of diluted squash with a ratio of 1 part squash to 7 parts water

The number of water

To make 2 litres of diluted squash with a ratio of 1 part squash to 7 parts water, we need to calculate how much water is needed.

We can do this by using the following formula:

Water = Diluted Squash - Squash First, we need to find out how much squash is in 2 litres of diluted squash.

Since the ratio is 1:7, we can divide 2 litres by the total number of parts (1 + 7 = 8) to find out how much squash is in 2 litres of diluted squash: Squash = 2 litres / 8 = 0.25 litres

Now we can use the formula to find out how much water is needed:

Water = 2 litres - 0.25 litres = 1.75 litres

Therefore, we need 1.75 litres of water to make 2 litres of diluted squash with a ratio of 1 part squash to 7 parts water.

Learn more about dilution at https://brainly.com/question/28548168

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