at what speed relative to a laboratory does a clock tick at one quarter the rate of an identical clock at rest in the laboratory? give your answer as a fraction of c .

Answers

Answer 1

The clock ticks at approximately 0.866 c relative to the laboratory.

Let's assume the laboratory is at rest and the clock is moving relative to it. We need to find the velocity at which the clock ticks at one quarter the rate of an identical clock at rest.

According to time dilation in special relativity, the time experienced by a moving object relative to an observer at rest is given by:

t' = t / sqrt(1 - v^2/c^2),

where t' is the time experienced by the moving clock, t is the time experienced by the clock at rest, v is the velocity of the moving clock, and c is the speed of light.

In this case, we want the moving clock to tick at one quarter the rate of the clock at rest. So we have:

t' = 1/4 * t.

Substituting this into the time dilation equation, we get:

1/4 * t = t / sqrt(1 - v^2/c^2).

Simplifying this equation, we find:

1/4 = 1 / sqrt(1 - v^2/c^2).

Taking the reciprocal of both sides, we have:

4 = sqrt(1 - v^2/c^2).

Squaring both sides, we get:

16 = 1 - v^2/c^2.

Rearranging the equation, we find:

v^2/c^2 = 1 - 16.

v^2/c^2 = -15.

Taking the square root of both sides, we have:

v/c = sqrt(-15).

However, the square root of a negative number is not physically meaningful in this context, so there is no real solution. This implies that there is no velocity at which the clock will tick at one quarter the rate of an identical clock at rest in the laboratory.

There is no velocity at which a clock will tick at one quarter the rate of an identical clock at rest in the laboratory. This result is consistent with the principles of special relativity, which indicate that time dilation can only result in time slowing down, not speeding up.

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Related Questions

the total amount of friction used for acceleration, braking, and turning cannot exceed the limit of friction or skidding will occur. true false

Answers

The statement "the total amount of friction used for acceleration, braking, and turning must not exceed the limit of friction or skidding" is true because it prevents skidding.

True. When a vehicle accelerates, brakes, or turns, it relies on the friction between its tires and the road to perform these actions. However, there is a limit to the amount of friction available, and if this limit is exceeded, the tires will lose traction and skidding can occur. Skidding is dangerous as it reduces the driver's control over the vehicle.To prevent skidding, it is important to understand the concept of the coefficient of friction, which is the ratio between the force of friction and the force pressing the objects together. During acceleration, the friction between the tires and the road helps propel the vehicle forward. When braking, the friction between the tires and the road helps to slow down the vehicle. During turning, the friction assists in changing the direction of the vehicle.To ensure safe driving, it is crucial to not exceed the limit of friction. This can be achieved by adjusting driving techniques, maintaining proper tire pressure, and using appropriate tires for road conditions. It is also essential to drive at a reasonable speed and maintain a safe following distance to allow for proper braking and turning without exceeding the limit of friction.

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what statement on convection is wrong? select an answer and submit. for keyboard navigation, use the up/down arrow keys to select an answer. a cooler, denser, heavier air sinks downward. b ascending warm air expands, cooling until it becomes denser than surrounding air and sinks back to the ground. c cooler air, now in contact with the ground, is warmer and rises, having been displayed by cooler, dense air. d warm air usually goes down and cooler air goes up.

Answers

The statement that is wrong is option d: "warm air usually goes down and cooler air goes up.

What is Convection?

Convection is the process of heat transfer that occurs in fluids such as gases and liquids. This process involves the transfer of heat by the movement of fluids from one place to another.

In this process, hot air rises while cooler air sinks. This movement of air is due to the differences in air density caused by temperature changes. A cooler, denser, heavier air sinks downward because it is denser than the surrounding air. As it sinks, it displaces the warmer air, which rises to the top.

This movement of air creates convection currents that transfer heat from one place to another. Ascending warm air expands, cooling until it becomes denser than the surrounding air and sinks back to the ground.

Therefore, statement (d) is incorrect.

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did voyager 2 pass closer to the northern or southern magnetic pole of uranus?

Answers

Voyager 2 passed closer to the southern magnetic pole of Uranus.

During its flyby of Uranus in 1986. This was determined by the measurements taken by the spacecraft's instruments, which detected the magnetic field of Uranus and allowed scientists to map its magnetic structure.

The spacecraft's trajectory and the data collected indicated that Voyager 2 passed nearer to the southern magnetic pole than the northern one. This encounter provided valuable insights into the magnetic field and overall magnetosphere of Uranus, contributing to our understanding of the planet's unique characteristics and the dynamics of its magnetic environment.

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what are the two correct answers to this question

what are the two correct answers to this question

Answers

Answer:

Most probably mass and volume

Explanation:

i dont think you can really measure it from its color i dont think measurements work that way lol. temperature cant be the option because all of them are likely to be in the same condition and time is just an absurd way to measure a object

For the solar cooker project, the two measurements that students should make to determine the dependent variable are: temperature and time.

What are the  measurement that student should make to determine the dependent variable?

Two measurements that students should make to determine the dependent variable are :

Temperature: The students should measure the temperature of the food being cooked at different times of day and under different conditions, such as with or without insulation, with or without reflective materials, and so on. The temperature would be dependent variable because it is directly related to the rate of cooking. The higher the temperature, then faster the food will cook.

Time: The students should measure the time it takes to cook the food under different conditions. The time would be a secondary dependent variable because it is also directly related to rate of cooking. The faster the food cooks, the shorter the cooking time will be.

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To strike or hit something with great force

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Answer:

To strike or crash into with resounding impact. To collide or strike with great force. Used to indicate the sound of a forceful blow or collision.

Answer:

To strike or crash into with resounding impact. To collide or strike with great force. Used to indicate the sound of a forceful blow or collision.

Explanation:

Explain why ""human error"" is a poor explanation for error.

Answers

Human error is a poor explanation for error because it is too general. Human error is not a root cause, but a symptom of underlying causes.

It does not provide any real explanation of what happened, how it happened, or why it happened.

Furthermore, it can be viewed as blaming the individual who made the error rather than focusing on the larger organizational or systemic issues that led to the error.

Instead of attributing errors to human error, it is essential to look for root causes. Root cause analysis is a structured approach that aims to identify the underlying causes of problems, including errors.

Root cause analysis helps identify the factors that contributed to the error and identify corrective actions that can prevent similar errors from occurring in the future.

Rather than blaming individuals, root cause analysis focuses on identifying systemic problems and implementing solutions to address them.

By identifying and addressing root causes, organizations can improve their processes, increase safety, and reduce errors.

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After a certain pesticide compound is applied to crops, its decomposition is a first-order reaction with a half-life of 32. 5 days. What is the rate constant, k, for the decomposition reaction?.

Answers

The rate constant, k, for the decomposition reaction will be 0.0214/day. The half-life of a first-order reaction is the amount of time it takes for the concentration of a reactant to decrease by half.

A first-order reaction is a type of chemical reaction in which the rate of the reaction is directly proportional to the concentration of one of the reactants. The rate constant, k, is a measure of the speed of the reaction and is specific to the reaction conditions (temperature, pressure, etc.).

It is a useful concept because it is a constant for a given reaction, regardless of the starting concentration of the reactant.

The half-life, t1/2, of a first-order reaction is given by the equation: t1/2 = 0.693/k

So, in this case, since the half-life is 32.5 days, we can find k by rearranging the equation to:

k = 0.693/32.5 days = 0.0214/day

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In a lab experiment, 7.14 g of mg reacts with sulfur to form 16.56 g of magnesium sulfide. how much magnesium sulfide would be formed if 7.14 g of mg were reacted with 18.40 g of s?

Answers

If 7.14 g of Mg were reacted with 18.40 g of S, approximately 16.51 g of MgS would be formed.

To determine how much magnesium sulfide would be formed when 7.14 g of Mg reacts with 18.40 g of S, we can use the concept of stoichiometry and the given ratio of Mg to MgS from the first reaction.

From the first reaction, we know that 7.14 g of Mg reacts to form 16.56 g of MgS. This gives us the ratio:

7.14 g Mg : 16.56 g MgS

Now, we need to determine the amount of MgS that would be formed when 7.14 g of Mg reacts with 18.40 g of S.

First, we need to determine the limiting reactant. To do this, we compare the moles of Mg and S:

Moles of Mg = 7.14 g / molar mass of Mg

          = 7.14 g / 24.31 g/mol (molar mass of Mg)

          ≈ 0.294 mol

Moles of S = 18.40 g / molar mass of S

          = 18.40 g / 32.07 g/mol (molar mass of S)

          ≈ 0.574 mol

Since we have fewer moles of Mg (0.294 mol) compared to S (0.574 mol), Mg is the limiting reactant. This means that Mg will be completely consumed in the reaction, and S will be in excess.

Next, we can calculate the amount of MgS formed using the ratio from the first reaction:

Moles of MgS = Moles of Mg * (Moles of MgS / Moles of Mg)

           = 0.294 mol * (1 mol MgS / 1 mol Mg)

           = 0.294 mol MgS

Finally, we can calculate the mass of MgS formed:

Mass of MgS = Moles of MgS * molar mass of MgS

           = 0.294 mol * 56.32 g/mol (molar mass of MgS)

           ≈ 16.51 g

Therefore, 18.40 g of S and 7.14 g of Mg would combine to generate roughly 16.51 g of MgS.

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how much work is done by the field along the parabolic path given by as goes from to ? (remember: how you parametrize the path is up to you and will not change your answer...)

Answers

The work done by the field along the parabolic path given by y = x as x goes from -1 to 1 is 19/3 Joules.

We can parametrize the parabolic path as follows:

x(t) = t, where t goes from -1 to 1

y(t) = t

Substituting these into the expression for the field F, we get:

F = \((3t^2 + 2t)i + (4t + 2t)j\)

F = \((3t^2 + 6t)i + (6t)j\)

To find the work done by the field along this path, we need to integrate the dot product of F and the path differential vector dr, evaluated along the path:

W = ∫ F · dr

dr = dx i + dy j

dr = dt i + dt j

dr = (i + j) dt

Substituting F and dr, we get:

W = ∫ F · dr

W = \(∫[(3t^2 + 6t)i + (6t)j] · (i + j) dt\)

W = \(∫(3t^2 + 9t) dt\)

Evaluating the integral from t = -1 to t = 1, we get:

W = \([t^3/3 + 9t^2/2] from -1 to 1\)

W =\([(1/3 + 9/2) - (-1/3 + 9/2)]\)

W = \([19/3] Joules\)

Therefore, the work done by the field along the parabolic path given by y = x as x goes from -1 to 1 is 19/3 Joules.

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Full Question: How much work is done by the field F = (3x2 + 2y)i + (4y + 2x)ị along the parabolic path given by y = x? as x goes from –1 to +1? (Remember: how you parametrize the path is up to you and will not change your answer...)

tia phản xạ trên gương phẳng nằm trong cùng mặt phẳng với:

Answers

Answer:

can anyone translate

Explanation:

because i cant read this

Pressure of 76cm of mercury column is pa

Answers

The pressure of 76 cm of mercury column is 10132.5 Pa.

Pressure, in the physical sciences, the perpendicular force per unit area, or the stress at a point within a confined fluid.

The pressure of 76 cm of mercury column can be converted to Pascals (Pa) using the following conversion factor:

1 atm = 101325 Pa

760 mmHg = 1 atm

Therefore,

76 cm Hg = (76/760) atm = 0.1 atm

Now, we can convert this pressure in atm to Pascals using the following conversion factor:

1 atm = 101325 Pa

Therefore,

0.1 atm = 0.1 * 101325 Pa = 10132.5 Pa

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--The complete question is, Pressure of 76cm of mercury column is ______ pa.--

planimeters have a counter that registers the number of times the wheel revolves as c is traversed. explain how the number of revolutions is converted to the area of r

Answers

Planimeters are devices used to measure the area of irregular shapes on a surface. The number of revolutions is converted to the area of r

Area (A) = (C x R^2) / (2π)

The conversion of the number of wheel revolutions to the area of the shape measured by a planimeter is based on the concept of the polar planimeter. A polar planimeter consists of a wheel that rotates as it moves along the boundary of the shape being measured. The wheel's radius is known as R.

When the wheel rotates, it traces a spiral path, and the area of the shape enclosed by this spiral path can be determined using the formula:

Area (A) = (C x R^2) / (2π)

Here, C represents the number of wheel revolutions recorded by the planimeter counter. The formula derives from the concept that the area of a sector of a circle is equal to (1/2) x (radius)^2 x angle (in radians). By integrating the contributions of each sector covered by the wheel revolutions, the total area of the shape can be calculated.

Therefore, by multiplying the number of revolutions (C) by the square of the wheel radius (R^2) and dividing by 2π, the planimeter can accurately convert the rotations into the area of the irregular shape being measured.

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what is it called when two mirrors facing each other

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When two mirrors are placed facing each other, it creates a phenomenon known as "mirror reflection" or "infinite reflection." This occurs as the light reflects back and forth between the mirrors, creating multiple reflections that appear to stretch infinitely into the distance.

The reflection continues on and on until it becomes too small to see. In this way, a person sees many reflections of themselves, and each reflection is smaller than the previous one. This is called an infinity mirror or a mirror tunnel.An infinity mirror is a visual illusion that looks like the mirror has no end. It is accomplished by placing a mirror in front of another and allowing a small amount of space between the two. Then, light is reflected back and forth in the space between the mirrors, generating an infinite loop of images.

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The airport has a new plane that can go from 0 miles per hour to 100 miles per hour in 10 seconds. What is being described about the new plane?

Answers

Acceleration :

Acceleration is a vector quantity that is defined as ❝ rate of change in velocity ❞

And as per the question, the plane can go from 0 miles to 100 miles/hour in 10 seconds that shows rate of change in its velocity. that is :

from 0 miles/hour to 100 miles/hour. hence Acceleration is the quantity being described about the new plane.

\(\qquad \sf  \dashrightarrow \: a = \dfrac{v - u}{t} \)

[ v = final velocity, u = initial velocity, t = time ]

\(\qquad \sf  \dashrightarrow \: a = \dfrac{100 - 0}{10} \)

\(\qquad \sf  \dashrightarrow \: a = \dfrac{100}{10} \)

\(\qquad \sf  \dashrightarrow \: a = 10 \: \)

So, the Acceleration of the new plane is 10 miles/hour²

For your senior project you want to build a cyclotron that will accelerate protons to 10% of the speed of light. The largest vacuum chamber you can find is 50 cm in diameter. What field strength do you need? If your electric field is 100V between the D's, how many revolutions does it make?

Answers

For your senior project cyclotron, to accelerate protons to 10% of the speed of light within a 50 cm diameter vacuum chamber, you need a magnetic field strength of approximately 1.64 T (tesla).

The protons will make about 11,207 revolutions with a 100V electric field between the D's.

1. Calculate the required final velocity: v = 0.1 * c (speed of light), v ≈ 3 * 10⁷ m/s


2. Determine the radius of the cyclotron: r = diameter / 2, r = 0.5 / 2 = 0.25 m


3. Use the cyclotron equation: B = (2 * pi * m * v) / (q * r), where m is the proton mass (1.67 * 10⁻²⁷ kg), q is the proton charge (1.6 * 10⁻¹⁹ C), and B is the magnetic field strength.


4. Calculate the field strength: B ≈ 1.64 T


5. Find the time for one revolution: T = (2 * pi * m) / (q * B)


6. Calculate the number of revolutions: N = (final velocity * time for one revolution) / (2 * pi * radius * electric field)
7. N ≈ 11,207 revolutions

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Using the results from your post-fitness assessment, write a three-paragraph reflection addressing the following questions. Be sure to address all portions of the prompt in your reflection.

Journal prompt to be answered in 3 fully developed paragraphs citing specific examples from the pre-assessment.

In paragraph 1, summarize your results for each part of the assessment. Were there areas that surprised you about your results(able to complete more or less than you thought)?
In paragraphs 2 and 3, respond to the following: What is the purpose of completing a post-assessment? How can you analyze the data and use it to create a plan? What areas of the assessment would like to improve upon? How have you improved from your pre-assessment?

Answers

In reflecting on the assessment results I found that I was generally able to complete most parts successfully

The areas covered in the assessment

However I was surprised by my performance in the section that required complex problem-solving skills as I struggled more than expected On the other hand I was pleased with my ability to communicate effectively in the written portion

The purpose of completing a post-assessment is to evaluate progress and identify areas for improvement By analyzing the data from the assessment I can identify strengths and weaknesses which helps in creating a development plan For instance if time management was an issue during the assessment strategies can be implemented to improve efficiency and task prioritization Analyzing the data allows for a focused approach to skill enhancement

One area I would like to improve upon is critical thinking I noticed that I sometimes struggled to analyze complex information and draw logical conclusions To address this I plan to practice critical thinking exercises engage in analytical discussions and seek out relevant resources On a positive note I have improved my time management skills since the pre-assessment becoming more conscious of time constraints and allocating my time more efficiently across different sections

In conclusion the post-assessment provides an opportunity for self-reflection and growth Analyzing the data identifying areas for improvement and implementing targeted strategies are key steps towards enhancing skills and performance

The progress made since the pre-assessment highlights the effectiveness of intentional practice and focused effort Continuous self-assessment and improvement will contribute to further strengthening of abilities and the achievement of personal goals

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A ball is thrown upwards.
> What effect does the force of gravity have on the ball ??
A. It produces a constant acceleration downwards.
B. It produces a constant acceleration upwards.
C. It produces a decreasing acceleration upwards.
D. It produces an increasing acceleration downwards.
Plz plz plz help me
I will mark brainliest

A ball is thrown upwards. > What effect does the force of gravity have on the ball ?? A. It produces

Answers

Answer: A

Explanation:

the acceleration is constant and gravity causes the ball to fall downwards.

hope this helps

a) During a thermodynamic cycle gas undergoes three different processes beginning at an initial state where p1-1.5 bar, V₁ =2.5 m³ and U₁ =61 kJ. The processes are as follows: (i) Process 1-2: Compression with pV= constant to p2 = 3 bar, U₂ = 710 kJ 3 (ii) Process 2-3: W2-3 = 0, Q2-3= -200 kJ, and (iii) Process 3-1: W3-1 +100 kJ. Determine the heat interactions for processes 1-2 and 3-1 i.e. Q1-2 and Q3-1.\

Answers

The heat interactions for processes 1-2 and 3-1 are 0 kJ and 100 kJ

A thermodynamic cycle is a process where there is a conversion of thermal energy into mechanical work. It is a series of processes through which a thermodynamic system goes to produce useful work. The heat interactions for processes 1-2 and 3-1 can be determined as follows:

During process 1-2, gas undergoes compression with pV= constant to p2 = 3 bar. This process is isobaric and hence the heat interactions can be determined using the formula Q=ΔH - W where ΔH is the change in enthalpy and W is the work done.

Since the gas undergoes compression, the work done is negative (W1-2 = - ΔU = U2 - U1 = 710 - 61 = 649 kJ).

Therefore, the heat interaction for process 1-2 can be calculated as follows: Q1-2 = ΔH - W = U2 - U1 - W1-2 = 710 - 61 - 649 = 0 kJ

During process 3-1, gas undergoes expansion with heat being added.

This process is isobaric and hence the heat interactions can be determined using the formula Q=ΔH - W where ΔH is the change in enthalpy and W is the work done.

Since the gas undergoes expansion, the work done is positive (W3-1 = ΔU + Q3-1 = U1 - U3 + 100 = 61 - 405 + 100 = -244 kJ).

Therefore, the heat interaction for process 3-1 can be calculated as follows: Q3-1 = ΔH - W = U1 - U3 - W3-1 = 61 - 405 - (-244) = 100 kJ

In short, the heat interactions for processes 1-2 and 3-1 are 0 kJ and 100 kJ, respectively.

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A gardener uses 2700 J of work to push a wheelbarrow for 60 seconds. How much power does she use?

A gardener uses 2700 J of work to push a wheelbarrow for 60 seconds. How much power does she use?

Answers

Answer:

I think 90 w I am not sure but I think it is right

I hope it is helpful for u

Answer:

45 W

Solution,

Work(W)=2700 Joule

Time(t)=60 Seconds

Power=?

Now,

\(power = \frac{work \: done}{time \: taken} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2700}{60} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 45 \: \: watt\)

hope this helps..

Good luck on your assignment..

How does the Coriolis effect impact the Gulf Stream and the Brazil Current?

Answers

Answer: The Coriolis effect results in bending the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere. The Coriolis effect causes winds and currents to form the circular patterns. The direction in which they spin depends upon the hemisphere in which they are present.Coriolis Effect is named after the French mathematician and physicist Gaspard-Gustave de Coriolis. It affects the weather patterns of an area, it affects the ocean currents, and it also affects air quality.

An electric iron is Marg 20 words 500 w the units consumed by it in using it for 24 hours will be

Answers

The electric iron with a power rating of 500 watts will consume 12 kilowatt-hours (kWh) of electricity when used continuously for 24 hours.

To calculate the units consumed, we need to consider the power rating and the duration of usage. The power rating of the electric iron is given as 500 watts, which is equivalent to 0.5 kilowatts (kW). By multiplying the power rating by the time used (24 hours), we obtain the total energy consumed, which is 12 kilowatt-hours (kWh). This value represents the units of electricity consumed by the electric iron during the 24-hour period.

Therefore, the electric iron will consume 12 kilowatt-hours (kWh) of electricity when used for 24 hours continuously with a power rating of 500 watts.

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places of hot climate it is advised that outer walls of houses be painted white. Why?​

Answers

Answer: In places of hot climate it is advised that the outer wall of houses be painted white because white color reflects heat and the houses do not heat up too much.

A Ferris wheel with a diameter
of 40 m makes one revolution
every 20 minutes. What is its
average speed in meter/min?

Answers

Answer:

6.3 m/min

Explanation:

Circumference of a circle = 2πr

r = D/2 = 40m/2 = 20m

C = 2π(20m) = 125.7 m

speed = distance/time = (125.7 m) / (20  min)  = 6.3 m/min

Poisoner's Handbook Video
Questions

1. What are some symptoms of cyanide poisoning?

2. Describe the state of death investigation in the New York Medical Examiner's office/police department prior to the
hiring of Dr. Norris?

3. What famous hospital became the home of Norris lab?
Bellevue Hospital

4. In what ways did the local government officials (mayor, etc.) try to discourage Norris?

5. Morris believed that Prohibition had become a plague? Why did he refer to Prohibition as a "national experiment in
extermination'?

6. Why was the Standard Oil manufacturing plant referred to as the looney bin?

7. What is illuminating gas? Why was it responsible for more deaths in New York than measles and tuberculosis?

8. Radium was used in painting clock and watch faces because it glowed and make the numbers and hands illuminate
at night. These were worn by servicemen during the war. Women worked in the factories painting these time
pieces during war time. They were known as the radium girls. What effects did these girls experience as a results of
their exposure to radium?

9. What mineral does radium mimic? What effect does this have on the body?

10. Describe New York when the depression hit?

11. What did Prohibition promise that did not happen?

12. Who is Mike the Durable? How did he get this nickname?

Answers

Dizziness, Headache, Nausea, vomiting, rapid breathing, rapid heart rate, Restlessness and Weakness are the symptoms that shows poisoning of cyanide.

What are some symptoms of cyanide poisoning?

Dizziness, Headache, Nausea and vomiting, Rapid breathing, Rapid heart rate, Restlessness and Weakness are the some of the symptoms of cyanide poisoning. Cynaide is a very dangerous and fast acting poison that leads to death if not treated on time.

So we can conclude that all above are the symptoms caused by cyanide poisoning.

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when a rifle fires at a distant target, where should the barrel be pointing?

Answers

When a rifle fires at a distant target, the barrel should be pointing straight towards the target.

This is because the barrel is the part of the rifle that the bullet travels through to reach the target. If the barrel is not pointing directly at the target, the bullet may not hit it.

Therefore, it is important to aim the barrel accurately when shooting a rifle at a distant target.

A rifle is a long gun designed to be fired from the shoulder, with a barrel that has spiral grooves (rifling) cut into the inside of the barrel wall that forces the bullet to rotate as it moves out of the barrel.

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Name the two poles of a magnet
What is meant by magnetism?​

Answers

North & South Pole, one is Iron and the other is electric

A man pulls a refrigerator using 48 N of force. The refrigerator accelerates 0.35 m/s<2. What is the mass of the refrigerator

Answers

Answer: 137.14 kg

Explanation: F=ma (Force = mass x acceleration)

So, 48N (newtons) = m×0.35m/s²

N = kg (m/s²)

      (48 kg m/s²)÷0.35m/s² = m

      137.14 kg

 note: answer is to the nearest hundredth because of the .035 m/s²

what is the direction of f3f3 for the ring to be in equilibrium?

Answers

In order for a ring to be in equilibrium, the net force acting on it must be zero.

Assuming that "ff3" refers to a force acting on the ring, we need to determine the direction that this force must act in order to balance out the other forces acting on the ring.

Without additional information about the other forces acting on the ring, it is difficult to determine the direction of "f3" required to achieve equilibrium.

However, in general, if the ring is already in equilibrium and we add an external force "f3", the direction of "f3" required to maintain equilibrium will depend on the direction and magnitude of the other forces acting on the ring.

For example, if the other forces are all pointing clockwise, then "f3" would need to be pointing counterclockwise with an appropriate magnitude to balance out the other forces and maintain equilibrium. On the other hand, if the other forces are all pointing counterclockwise, then "f3" would need to be pointing clockwise to maintain equilibrium.

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If you rub a ballon against some cloth and try to attract sand will it attract?

Answers

The wall is positively charged, whereas it is negatively charged. If a woollen fabric is not used to massage it, it will not do so. When the sand was drawn inside the balloon, the same thing occurred.

Why are balloons attracted to each other?

Positive charges pull away from negative charges. The balloon will attract the wool fabric if it is not touched since it contains an equal balance of negative and positive charges. Both balloons will reject one another when they are brushed with the wool cloth because they both receive negative charges.

Why does a charged balloon attract water?

Positive and negative particles make up the water. Because positive and negative ions are attracted to one another, when you bring the balloon near the water, the positively charged water molecules will pull the water in the direction of the negatively charged balloon.

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Answer:

b is the equivalent

do u want explanation

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