audible limit of the sound wave

Newton's universal law of gravitation

F = (G * m1* m2)/d^3

Where:

F = force

G= universal gravitation constant

M1= mass 1

M2 = mass2

d = distance

The force of attraction is directly proportional to the product of their masses.

40 x 2 = 80 N

If the mass of one object is doubled, then the force is doubled.

Answer:

identify who they are as a person

Explanation:

The size of the largest asteroid is option (b) 1,000 km.

Rock-filled spacecraft called asteroids orbit the sun but are too tiny to be referred to as planets. They are sometimes known as tiny planets or planetoids.

Asteroids are in the millions and range in size from hundreds of miles to a few feet. The combined mass of all asteroids is less than that of the moon of Earth.

Despite their size, asteroids can be dangerous. There have already been many, and there will be more in the future. That is one of the reasons why asteroids are studied by scientists, who are keen to understand more about their composition, orbits, and physical attributes. We want to be informed if an asteroid is heading in our direction.

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Answer:

The definition of a fulcrum is a pivot point around which a lever turns, or something that plays a central role in or is in the center of a situation or activity.

The refraction of a sound wave occurs when the sound wave bends as it passes through the boundary between media. Refraction occurs when there is a difference in the speed of sound waves in two different media.

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Answer:

You didn't put any options but there are water droplets on the window due to dew-condensation.

Explanation:

I learned this in class.

Answer:

its C or D

Explanation:

The energy from the sun caused water to heat up and evaporate.

Drawing (d) best represents the system after the stopcocks are opened and the system is allowed to come to equilibrium, as it shows equal pressure in all three bulbs.

Since the two bulbs contain different gases, the pressures in each bulb will be different. When the stopcocks are opened, the gases will flow into the empty bulb until the pressures are equalized. The final state will have equal pressure in all three bulbs.

What is an equilibrium?

An equilibrium is a state of balance or stability achieved in a chemical reaction when the forward reaction rate is equal to the reverse reaction rate. In other words, it is the point at which the concentrations of reactants and products no longer change with time, because the rates of the forward and reverse reactions are equal.

At equilibrium, the amounts of reactants and products are governed by the equilibrium constant (K), which is a measure of the relative concentrations of the reactants and products at equilibrium.

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The charge on each particle is 3.3×10⁻⁵ C.

Charge is the product of current and time.

To calculate the charge on each particle, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the charge on each particle is 3.3×10⁻⁵ C.

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This question is incomplete, the complete question is;

What is the magnitude of the electric field at the point (8.70i - 9.10j + 7.20k ) m if the electric potential is given by V = 4.30xyz², where V is in volts and x, y  and z are in meters.

Answer:

the magnitude of the electric field is 5648.67 N/C

Explanation:

Given the data in the question;

Suppose electric field at this point is;

E = Exi + Eyj + Ezk

Now, electric field is given by;

E = -dV/dr

so,

Ex = -d( 4.30xyz² )/dx = -4.30yz²

Ey = -d( 4.30xyz² )/dy = -4.30xz²

Ez = -d( 4.30xyz² )/dz = -8.60xyz

so

E = -4.30yz² i  - 4.30xz² j - 8.60xyz k

now, at the point (8.70i - 9.10j + 7.20k )  

E = (-4.30(-9.10)(7.20)²) i  + (-4.30(8.70)(7.20)²) j + (-8.60(8.70)(-9.10)(7.20) k

E =  2028.499 i - 1939.334 j + 4902.206 k

so, Magnitude of electric field will be;

|E| = √( Ex² +  Ey² + Ez² )

we substitute

|E| = √( (2028.499)² +  (-1939.334)² + (4902.206)² )

|E| = √( 31907448.222993 )

|E| = 5648.67 N/C

Therefore, the magnitude of the electric field is 5648.67 N/C

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:V(t)=20t^2-100t+50t

as we know accl means derivatives of velocity.

a/q,

dv/dt =0

dv/dt=20t^2-100t+50t=0

dv/dt=4t-100+50=0

=>40t-50=0

=>40t=50

=>t=1.25

therfore Vs= 20t^2-100t+50t

Vs=20(1.25625)-125+62.5

Vs=31.25-125+62.5

Vs=-31.25

Answer:

the particle is at coordinates (18,15/2)

Explanation:

To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:

a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j

So the acceleration of the particle is a = 2i + 3j m/s².

To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:

r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j

We can use the kinematic equations of motion to solve this problem.

Let the acceleration of the particle be a = axî + ayj.

(a) Using the equation of motion v = u + at, where u is the initial velocity:

f = v = u + at

Substituting the given values, we get:

(91+7j) = (3î-2j) + a(3î + 3j)

Equating the real and imaginary parts, we get:

91 = 3a + 3a (coefficients of î are equated)

7 = -2a + 3a (coefficients of j are equated)

Solving these equations simultaneously, we get:

a = î(23/6) + j(1/2)

So the acceleration of the particle is a = (23/6)î + (1/2)j.

(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:

At t = 3s, the displacement of the particle is:

s = ut + (1/2)at^2

Substituting the given values, we get:

s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2

Simplifying, we get:

s = 9î + (17/2)j

So the coordinates of the particle at t=3s are (9, 17/2).

Answer:

hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.

It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.

To find the time it takes for the catcher to stop the ball, you can use the equation:

time = distance / velocity

In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:

time = 0 / 21.80

time = 0 s

So, it takes 0 seconds for the catcher to stop the ball.

To find the distance the ball travels before stopping, you can use the equation:

distance = 1/2 * acceleration * time^2

In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:

distance = 1/2 * (-2000 m/s^2) * (0 s)^2

distance = 0 m

So, the ball travels 0 meters before stopping.

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The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg

Applying the principle of energy conservation

Heat lost by the hot body = heat absorbed by the cold water + calorimeter

= m * 4200 * ( 100 - 70  ) = 0.50 * 4200 * ( 70 -20 ) + 105 * ( 70 -20 )

= m * 126000 = 110250

therefore ;

m = 110250 / 126000

  = 0.875 kg

Hence we can conclude that The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg

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\(\\ \sf\longmapsto v=u+at\)

\(\\ \sf\longmapsto v=40+(16)(9)\)

\(\\ \sf\longmapsto v=40+144\)

\(\\ \sf\longmapsto v=184m/s\)

Explanation:

Answer:

4.44 ohms

Explanation:

To find the resistance of a circuit, you can use Ohm's law, which states that the resistance of a circuit is equal to the voltage across the circuit divided by the current through the circuit. So in this case, the resistance would be 12 volts / 2.7 amps = 4.44 ohms.

The astronaut would have to exert an upward force of approximately 108 N to catch the package.

Acceleration due to gravity, denoted by the symbol g, is the acceleration that an object experiences when it is in free fall near the surface of a massive body, such as a planet or a moon. In simpler terms, it is the acceleration that an object would experience if it were allowed to fall freely under the influence of gravity.

The value of acceleration due to gravity varies depending on the mass and radius of the celestial body, and it decreases with increasing altitude or distance from the surface. On Earth, the standard value of acceleration due to gravity is approximately 9.81 m/s² at sea level, which means that an object in free fall near the surface of the Earth would accelerate at a rate of 9.81 meters per second squared.

a) To find the acceleration of gravity on Vulcan, we can use the formula:

g = G * M / r²

where g is the acceleration of gravity, G is the gravitational constant, M is the mass of the planet, and r is the radius of the planet. Substituting the given values, we get:

g = (6.67 x 10⁻¹¹ N m² / kg²) × (5.78 x 10²³ kg) / (4.37 x 10⁶ m)²

g ≈ 22.5 m/s²

Therefore, the acceleration of gravity on Vulcan is approximately 22.5 m/s².

b) To find the time it takes for the package to reach the astronauts, we can use the formula:

y = vit + 1/2g × t²

where y is the distance the package falls (55 m), vi is the initial vertical velocity (12 m/s downwards), g is the acceleration of gravity on Vulcan (22.5 m/s²), and t is the time we want to find. Resetting this equation and substituting the given values, we get:

t = √(2 × y/g)

t = √(2 × 55 m / 22.5 m/s²)

t ≈ 2.21 s

Therefore, it takes approximately 2.21 seconds for the package to reach the astronauts.

c) To find the amount of force the astronaut would have to exert to catch the package, we can use the change in kinetic energy of an object is equal to the work done by a force. We can assume that the package has zero initial velocity when the astronaut catches it. The work done by the astronaut's force is equal to the change in kinetic energy of the package:

work = (1/2)mvf² - (1/2)mvi²

where m is the mass of the package, vf is the final velocity of the package (zero), and vi is the initial velocity of the package (12 m/s downwards). Substituting the given values, we get:

work = (1/2) × 1.8 kg × (0 m/s)² - (1/2) × 1.8 kg × (12 m/s)²

work ≈ -129.6 J

The negative sign indicates that the astronaut's force is acting opposite to the direction of motion of the package. The distance the astronaut's force acts over is 1.2 m, so the force required to bring the package to rest is:

force = work / distance

force = -129.6 J / 1.2 m

force ≈ -108 N

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Answer:

the greater the height of an object the *greater* its gravitational potential energy

greater

Answer:

the distance in meters traveled by a point outside the rim is 157.1 m

Explanation:

Given;

radius of the disk, r = 50 cm = 0.5 m

angular speed of the disk, ω = 100 rpm

time of motion, t = 30 s

The distance in meters traveled by a point outside the rim is calculated as follows;

\(\theta = \omega t\\\\\theta = (100 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m\)

Therefore, the distance in meters traveled by a point outside the rim is 157.1 m

Answer: B

Explanation: I think its B or A but mostly B

Answer:

The enthalpy of a reaction does not depend on the reactant path taken

Explanation:

i just took the test on a pex :)

C. The average acceleration is positive and smaller in magnitude than the initial acceleration.

Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.

a = Δv/Δt

where;

a = (250 - 248) / (70 - 40)

a = 0.067 m/s²

Thus, we can conclude that the average acceleration is positive and smaller in magnitude than the initial acceleration.

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Potatoes mostly consist of starch, a complex carbohydrate produced by plants as a means of storing energy.

As starch accounts for the majority of potatoes' calories, they are categorised as a carbohydrate vegetable rather than a lipid. Potatoes, like the majority of foods, are a balance of fat, protein, and carbohydrates.

The most prevalent biomolecules on earth are carbohydrates, which include cellulose, starch, creatine, glucose, fructose, and others. Through the process of photosynthesis, carbohydrates are created by reducing the carbon dioxide in the atmosphere with the aid of light energy.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

The distance of the object from the concave mirror determines if it is a virtual or real image

Explanation:

Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.

An axon is a long, tubelike structure extending from a neuron's cell body.

option A is the correct answer.

An axon is a long, tubelike structure extending from a neuron's cell body.

An axon is respnsible for transmitting nerve impulses, or action potentials, away from the cell body to other neurons, muscles, or glands.

Thus, an axon is a long, tubelike structure of a neuron that carries nerve impulses away from the cell body and towards other neurons, muscles, or glands. It is the primary means by which neurons transmit information throughout the nervous system.

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The equivalent resistance is described as the location in a parallel or series circuit where the total resistance is measured.

A single resistance is referred to as the equivalent resistance if it can replace a group of resistances while maintaining the same current flow in the circuit. Where the total resistance connected in parallel or series is determined is called the equivalent resistance. The circuit is essentially built in either series or parallel. Electrical resistance demonstrates how much power is required to pass charges or current through your gadgets. Electrochemical cells, thermoelectric devices, solar cells, photodiodes, electrical generators, inductors, transformers, and even Van de Graaff generators are examples of equipment that can produce emf. When magnetic field variations pass through a surface in nature, EMF is produced.

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PHYSICS

*not sure about the answer but here we go*

Mass = 425 kg

distance = 614.4 m

acceleration = 1.8 m/s²

Answer :

Count Force first.

\(f \: = m \: \times a\)

F = 425 × 1,8

F = 765 N ✅

Now let's count Work.

\(w \: = \: f \: \times s\)

W = 765 × 614.4

W = 470016 J ✅

Answer:

D 30 minutes per day, 5 days a week