Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the two cars stick together What is the total momentum of the system after the collision? O 800 kg . m/s m, = 600 kg V,= 4 m/s m = 400 kg v2 = 0 m/s 1,600 kg. m/s 0 2,400 kg • m/s 0 4,000 kg . m/s After Collision ​

Answer:

1885.2 ohms

Explanation:

Step one:

given data

L=5H

f=60Hz

Required

The inductive reactance of the inductor

Step two:

Applying the expression

XL= 2πfL

substitute

XL=2*3.142*60*5

XL=1885.2 ohms

Answer:

  19 cm³

Explanation:

The coefficient of thermal expansion is the ratio of the change in volume to the reference volume for each degree change in temperature. Hence the change in volume is found by multiplying by the reference volume and the change in temperature.

  (1000 cm³)(0.950·10⁻³/K)(50-30)K = 19 cm³ . . . volume increase

The ball's height \(y\) at time \(t\) is given by

\(y = 29.2\,\mathrm m - \left(8.30\dfrac{\rm m}{\rm s}\right) t - \dfrac12 gt^2\)

where \(g=9.80\frac{\rm m}{\mathrm s^2}\).

Solve for \(t\) when \(y=0\). Omitting the units, we have

\(29.2 - 8.30t - \dfrac g2 t^2 = 0\)

I'll solve by completing the square.

\(29.2 - \dfrac g2 \left(t^2 + \dfrac{16.6}g t\right) = 0\)

\(29.2 - \dfrac g2 \left(t^2 + \dfrac{16.6}g t + \dfrac{8.3^2}{g^2}\right) = -\dfracg2 \times \dfrac{8.3^2}{g^2}\)

\(29.2 - \dfrac g2 \left(t + \dfrac{8.3}g\right)^2 = -\dfrac{8.3^2}{2g}\)

\(\dfrac g2 \left(t + \dfrac{8.3}g\right)^2 = 29.2 + \dfrac{8.3^2}{2g}\)

\(\left(t + \dfrac{8.3}g\right)^2 = \dfrac{58.4}g + \dfrac{8.3^2}{g^2}\)

\(t + \dfrac{8.3}g = \pm \sqrt{\dfrac{58.4}g + \dfrac{8.3^2}{g^2}}\)

\(t = -\dfrac{8.3}g \pm \sqrt{\dfrac{58.4}g + \dfrac{8.3^2}{g^2}}\)

\(\implies t \approx -3.43 \text{ or } t \approx 1.74\)

Ignore the negative solution; the ball hits the ground about 1.74 s after being thrown.

The abnormalities in the genetic code must be found and corrected on time as it could lead to inherited disorders which could be life-threatening.

Genetic abnormalities are the conditions which are caused by changes to the genes or chromosomes. Genetic disorders are also known as inherited disorders which are caused by mutations in the genetic code. Genetic disorders include disorders such as cystic fibrosis, sickle cell disease, and Tay-Sachs disease.

Cells become diseased because certain genes work incorrectly or does not work at all. Replacing the defective genes in the diseased organisms may help treat certain diseases. For instance, a gene called p53 prevents tumor growth. Several types of cancer which have been linked to problems with the p53 gene.

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The time the wheel would take for the disk with twice the radius and twice the mass to come to a stop would be 480 seconds.

This is because the moment of inertia, which is the measure of an object's resistance to changes in its rotation rate, depends on both the mass and the radius of the disk. Specifically, the moment of inertia of a solid disk is given by

I = 1/2 * mass * radius^2.

Since the disk in question has twice the mass and twice the radius, its moment of inertia will be 8 times greater than the original disk. This means that it will take 8 times longer for the disk to come to a stop under the same frictional force.

Therefore, the time it would take for the disk with twice the radius and twice the mass to come to a stop is 8 * 60 seconds = 480 seconds.

Therefore, the time the wheel would take to come to a stop from the same initial rotational speed If the disk had twice the radius and twice the mass is 480 seconds.

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The Specific Heat Capacity of the liquid is 43.846 KJ/(Kg K).

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The expression for the tension in the spring A is T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]

The tension in spring A can be determined by resolving the forces into x and y components as shown below.

The angle spring A makes with horizontal is calculated as;

A = 90⁰ - θ

The horizontal component of the tension on spring A;

T(Aₓ) = -W cos(A)

T(Aₓ) = -W cos(90 - θ)

The vertical component of the tension of spring A is calculated as;

T(Ay) = W sin(A)

T(Ay) = W sin(90 - θ)

The expression for the tension in spring A is calculated as;

T(A) = √[(T(Aₓ)² + T(Ay)²]

T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]

Thus, the expression for the tension in the spring A is determined through resolution of vector components.

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Given data:

* The mass of the book is m = 2 kg.

* The height of book A is h_A = 1 m.

* The height of book B is h_B = 1.5 m.

* The height of book C is h_C = 2 m.

Solution:

(a). The gravitational potential energy of book A is,

where g is the acceleration due to gravity,

Substituting the known values,

Thus, the gravitational potential energy of book A is 19.6 J.

(b). The gravitational potential energy of book B is,

Thus, the gravitational potential energy of book B is 29.4 J.

(c). The gravitational potential energy of book C is,

Thus, the gravitational potential energy of book C is 39.2 J.

The scale will register less than 190N if the aluminum is hanging in fresh water. The weight of the piece of aluminum is reduced as it is submerged in water due to the buoyant force that opposes the force of gravity, so the scale's reading will be less than 190N.

When a piece of aluminum is attached to a string that is fastened to a hanging scale, the scale will show 190N when the aluminum is hanging in the air. The hanging aluminum has a weight of 190N because the force of gravity acts on it. The buoyant force of water, on the other hand, opposes the force of gravity on an object immersed in it.

The buoyant force is equal to the weight of the water displaced by the aluminum's volume. Therefore, the aluminum's weight decreases when it is submerged in water. The scale will read less than 190N because it is determined by the sum of the force of gravity and the buoyant force. Since the buoyant force counteracts the force of gravity, the scale's reading is less than when the aluminum is hanging in air. The scale's reading is determined by the aluminum's weight plus the buoyant force in water.

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ANSWER:

The average speed is 6.67 yards/s

The average velocity is 1.18 yards/s

STEP-BY-STEP EXPLANATION:

Given:

We assume the full field is 100 yards

Total distance traveled = full field + full field - 30 yards = 100 + 100 - 30 = 170 yards

Total displacment = 30 yards

Time taken = 25.5 s

For the calculation of the speed, the total distance traveled is taken into account, while in the velocity, the total displacement is taken into account.

Therefore, we calculate in each case, like this:

B. A chemical change

Explanation:

I'm guessing ?

The stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.

This problem can be solved using the laws of kinematics and conservation of energy. The potential energy of the stone at the top of the cliff is converted to kinetic energy as it falls. We can equate the potential energy at the top of the cliff to the kinetic energy just before hitting the ground.

Potential energy = mgh,

Where

Kinetic energy = (1/2)mv^2,

Where

Equating these two expressions and solving for v, we get:

mgh = (1/2)mv^2

v^2 = 2gh

v = sqrt(2gh)

Plugging in the given values, we get:

v = sqrt(2 x 9.8 m/s^2 x 360 m) = 84.4 m/s

Therefore, the stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.

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To solve the given problems, we'll use the principles of work-energy and conservation of energy. Let's address each question one by one:

(1) What is the work done by Chris on the box when the speed of the box reaches 2.1 m/s?

The work done by Chris on the box is equal to the change in the box's kinetic energy. Since the box starts from rest, the initial kinetic energy is zero. The final kinetic energy can be calculated using the formula:

Kinetic energy = (1/2) * mass * velocity^2

Plugging in the values:

Mass of the box (m) = 53 kg

Final velocity (v) = 2.1 m/s

Kinetic energy = (1/2) * 53 kg * (2.1 m/s)^2

Calculate the value of the kinetic energy, which represents the work done by Chris on the box.

(2) What is the speed of the box when it reaches the bottom of the slope (Point B in the diagram)?

To determine the speed at the bottom of the slope, we'll use the principle of conservation of energy. The total mechanical energy of the box is conserved as it moves from the top to the bottom of the slope.

The initial potential energy at the top of the slope is converted into kinetic energy at the bottom of the slope, neglecting any energy losses due to friction.

Potential energy at the top = m * g * h1

Where:

Mass of the box (m) = 53 kg

Acceleration due to gravity (g) = 10 m/s^2

Height difference between floors (h1) = 3.2 m

Calculate the initial potential energy.

The final kinetic energy at the bottom is given by:

Kinetic energy at the bottom = (1/2) * m * v^2

Where:

Mass of the box (m) = 53 kg

Velocity at the bottom (v) = ?

Equating the initial potential energy to the final kinetic energy, solve for v to find the speed of the box at the bottom of the slope.

(3) To what speed does the box slow down when it reaches the bottom of the ramp to the pickup truck?

Since the ramp connecting the first floor to the bed of the pickup truck is frictionless, there is no external force doing work on the box. Thus, the mechanical energy of the box is conserved as it moves from the bottom of the slope to the bottom of the ramp.

Using the same principle of conservation of energy, equate the final kinetic energy at the bottom of the slope to the initial potential energy at the bottom of the ramp.

Potential energy at the bottom of the ramp = m * g * h2

Where:

Mass of the box (m) = 53 kg

Acceleration due to gravity (g) = 10 m/s^2

Height difference between the first floor and the truck bed (h2) = 0.90 m

Calculate the potential energy at the bottom of the ramp.

Equating the potential energy at the bottom of the ramp to the final kinetic energy, solve for the speed of the box at the bottom of the ramp.

(4) What is the speed of the box when it reaches the bed of the pickup truck?

Since the ramp connecting the first floor to the truck bed is frictionless, there is no external force doing work on the box. The mechanical energy of the box is conserved as it moves from the bottom of the ramp to the truck bed.

Using the same principle of conservation of energy, equate the final potential energy at the bottom of the ramp to the final kinetic energy at the truck bed.

Potential energy at the truck bed = m * g * h

Answer:

liquid, solid, and gas. A heating curve shows how the temperature changes as a substance is heated up at a constant rate.

Explanation:

liquid is often the bridge between solid and gas

not always, but most times.

For water, liquid water would probably be at temperature Y= 32- 212 degrees F, or Y= 0-100 degrees C.

Apologies, I hope this helps.

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

\(15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm\)

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

Originally there must been

1,4775E6 + 2.25E4 = 147.75E4 + 2.25E4 = 150E4 present at start

% = 2.25 / 150 = 1.5 %      of 235 U left

The energy that it needs to reach the maximum speed is 7583.4 Cal

In Physics, we know that the work done is the product of the force and the distance moved. However, work can be converted to energy since the both have the same dimensions. We define energy in physics as the ability or the capacity to do work.

Given these information, we know that the work done in moving the cheetah as it accelerates from the bottom to the top of the mountain is equal to the kinetic energy of the cheetah thus we can write;

W = KE = 1/2 mv^2

W= 0.5 * 62.0-kg * ( 32.0 m/s)^2

W = 31744 J

Given that;

1 calories = 4.186 J

x calories = 31744 J

x = 7583.4 Cal

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Let A and B are the starting and end point of field respectively.

The velocity of man going from point A to point B is,

The velocity of man going from point B to point A is,

The time is given as,

Therefore, time taken by man going from point A to point B is given as,

The time taken by man going from point B to point A is given as,

The average speed is given as,

Simplifying the above equation;

Substituting all known values,

Therefore, the average speed of the man is 4.44 m/s.

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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Answer: the average acceleration of the car is 3.33 mph/s.

Explanation:

To find the average acceleration of the car, we can use the formula:

average acceleration = (final velocity - initial velocity) / time

In this case, the initial velocity of the car is 45 mph, the final velocity is 65 mph, and the time taken to reach the final velocity is 6 seconds.

Substituting these values in the formula, we get:

average acceleration = (65 mph - 45 mph) / 6 s

average acceleration = 20 mph / 6 s

average acceleration = 3.33 mph/s (rounded to two decimal places)

Therefore, the average acceleration of the car is 3.33 mph/s.

Answer:

110

Explanation:

45+65=110

The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.

The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is calculated as follows;

Fn = Fc + mg

Fn = mω²r + mg

where;

Fn = 10(0.21²) 10  + 10(9.8)

Fn = 102.41 N

Thus, the normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.

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Answer:

C

Explanation:

The thermal energy from her hand will go up into the smoothie.

Answer:

C bois

Explanation:

Answer:

From the initial height h

Explanation:

When a material or substance is drop from a height h, it possesses potential energy, immediately it is dropped from that height, the potential energy is gradually converted to kinetic energy, it gets to a point where the potential energy equals the kinetic energy, as the material touches the ground, all potential energy has been converted to kinetic energy already

Answer:

t=8

Explanation:

u have solution I give solution also

don't mark plzz follow y

Answer:

The mass in grams of a red blood cell is about 7.85 ×  10⁻¹¹ grams

Explanation:

To find the mass in grams of a red blood cell,

From,

\(Density = \frac{Mass}{Volume}\)

Then,

\(Mass = Density \times Volume\)

From the question,

Density of a red blood cell is similar to that of water

Density of water = 1 g/mL = 1 g/ cm³

Then, Density of a red blood cell = 1 g/cm³

Now, we will find the volume a red blood cell.

From the question,  

Since the shape is like that of a thick disc, we can determine the volume by using the formula for volume of a cylinder.

Hence,

Volume of a red blood cell = \(\pi r^{2}h\)

Where \(\pi\) Is a constant (Take \(\pi\) = 3.14)

\(r\) is the radius

and \(h\) is the thickness

Diameter of a red blood cell = 10 micrometers

Then, radius of a red blood cell = 10/2 micrometers = 5 micrometers

\(r\) = 5 micrometers = 5 × 10⁻⁶ meters

and \(h\) = 1 micrometer = 1 × 10⁻⁶ meters

Hence,

Volume of a red blood cell = 3.14 × (5 × 10⁻⁶)² × 1 × 10⁻⁶

∴ Volume of a red blood cell = 7.85 × 10⁻¹⁷ cubic meter (m³)

Convert this to cubic centimeter

(NOTE: 1 cubic meter = 1000000 cubic centimeter)

Hence,

Volume of a red blood cell = 7.85 ×  10⁻¹¹ cubic centimeter (cm³)

Now, for the mass

\(Mass = Density \times Volume\)

Density of a red blood cell = 1 g/cm³

Volume of a red blood cell = 7.85 ×  10⁻¹¹ cubic centimeter (cm³)

Then,

Mass = 1 g/cm³ ×  7.85 ×  10⁻¹¹ cm³

Mass = 7.85 ×  10⁻¹¹ g

Hence, the mass in grams of a red blood cell is about 7.85 ×  10⁻¹¹ grams

Answer:

Explanation:

Here,

P=Pressure

V=Volume

Subscript meanings: 1 is before, 2 is after. So P1 is starting pressure, P2 is ending pressure.

In the P1V1 = P2V2 equation, P and V are inversely proportional.

It means that when a quantity will increase then another will decrease.

The pressure of a gas is directly proportional to the. The temperature when volume and amount of substance are constant. P1/T1 = P2/T2. Combined gas law: P1V1/T1 = P2V2/T2 Use the gas laws for pressure, volume, and temperature calculations. Avagadro's law and the Ideal gas law.

The compression of the spring of spring constant 384 N/m is 2.41 m.

Compression springs work by resisting and pushing back against any downward or inward force that tries to squash and hold them in a compressed state.

To calculate the compression of the spring, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the compression of the spring is 2.41 m.

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The force on each of the particles F = 998.89N.

To find force force,

Given,

K = 8.99 x 10⁹

I = 2.5x10-5 C

r = 15 cm

So, Using formula,

F = k x I / r²

F is force

K is kinetic energy

I is charge

r is distance

F = 8.99 x 10⁹ x 2.5x10-5 C / 15²cm

F = 998.89N

A particle or an object that is in motion has a form of energy called kinetic energy. An object gains kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.

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