The fourth-degree polynomial equation with real coefficients that has 2i and -3+i as roots is x^4 + 14x^2 + 40 . Since 2i is a root, its conjugate, -2i, is also a root.
To find a fourth-degree polynomial equation with real coefficients that has 2i and -3+i as roots, we can use the conjugate root theorem. Since 2i is a root, its conjugate, -2i, is also a root.
Thus, the polynomial equation can be written as (x - 2i)(x + 2i) = (x^2 + 4). To include -3+i as a root, we subtract it from x: (x - (-3+i)) = (x + 3 - i). Taking the conjugate of -3+i, we also get (x + 3 + i).
Therefore, the polynomial equation can be written as (x^2 + 4)(x + 3 - i)(x + 3 + i) = (x^2 + 4)(x^2 + 6x + 10). Expanding the equation, we get x^4 + 6x^3 + 10x^2 + 4x^2 + 24x + 40 = x^4 + 6x^3 + 14x^2 + 24x + 40.
Simplifying further, the fourth-degree polynomial equation with real coefficients that has 2i and -3+i as roots is x^4 + 14x^2 + 40.
Therefore , the fourth-degree polynomial equation with real coefficients that has 2i and -3+i as roots is x^4 + 14x^2 + 40
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What is the slope of the line in the graph?
5452-
Answer:
(0,5452) that every thing
A Simple Maximization Problem
Consider the following linear programming problem
a. List all the extreme points of the feasible region. b. Find the optimal solution and the objective function value.
c. List the values of all the slack variables.
a. (0,0),(5,0),(3.75,3.75),(3.5,4.5),(0,8); b. x=3.5,y=4.5,OFV=59.5;c.s1=0,s2=2,s3=0
a. (0,0),(5,0),(3.5,4.5),(0,8); b. x=3.5,y=4.5,OFV=59.5;c.s1=0,s2=2,s3=0.
a. (0,0),(5,0),(3.75,3.75),(6,4),(0,8); b. x=6,y=4,OFV=76;c1.s1=5,s2=0,s3=2.
a. (0,0),(5,0),(8,0),(3.5,4.5),(0,8); b. x=8,y=0,OFV=64;c.s1=45,s2=20,s3=0.
a. (0,0),(5,0),(3.75,3.75),(4,6),(0,8); b. x=4,y=6, OFV =74;c1.s1=0,s2=0, s3=2.
a. (0,0),(5,0),(8,0),(3.5,4.5),(0,8),(0,10); b. x=0,y=10,OFV=70;c.s1=25,s2=0,s3=2
a. (0,0),(3,0),(3.75,3.75),(3,5),(0,4); b. x=3,y=5, OFV =59;c1.s1=5,s2=0,s3=0
a. (0,0),(5,0),(3.75, 3.75),(3.5),(0,8); b. x=3, y=5, OFV=59; c1.s1=5, s2=0, s3=0
a. (0,0), (5,0), (3.75, 3.75), (3.5,4.5), (0,8);
b. x = 3.5, y = 4.5, OFV = 59.5;
c. s1 = 0, s2 = 2, s3 = 0.
a. The extreme points of the feasible region are the vertices of the polygon formed by the intersection of the constraint lines. In this case, the extreme points are (0,0), (5,0), (3.75, 3.75), (3.5,4.5), and (0,8).
b. To find the optimal solution and the objective function value, we evaluate the objective function at each extreme point and choose the point that maximizes the objective function. In this case, the point (3.5, 4.5) maximizes the objective function with a value of 59.5. Therefore, the optimal solution is x = 3.5 and y = 4.5, and the objective function value is 59.5.
c. The slack variables represent the surplus or slack in each constraint. We calculate the slack variables by subtracting the actual value of the left-hand side of each constraint from the right-hand side. In this case, the values of the slack variables are s1 = 0 (indicating no slack in the first constraint), s2 = 2 (indicating a surplus of 2 in the second constraint), and s3 = 0 (indicating no slack in the third constraint).
Therefore, the correct option is:
a. (0,0), (5,0), (3.75, 3.75), (3.5,4.5), (0,8);
b. x = 3.5, y = 4.5, OFV = 59.5;
c. s1 = 0, s2 = 2, s3 = 0.
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find the exact value of the expression by using appropriate identities. do not use a calculator. sin78cos33
To find the exact value of the expression sin(78°)cos(33°), we can use the trigonometric identity:
sin(A + B) = sin(A)cos(B) + cos(A)sin(B)
We can rewrite the expression as:
sin(78°)cos(33°) = sin(45° + 33°)cos(33°)
Using the identity sin(A + B) = sin(A)cos(B) + cos(A)sin(B), we have:
sin(78°)cos(33°) = [sin(45°)cos(33°) + cos(45°)sin(33°)]cos(33°)
Now, we can use the known values of sin(45°) = cos(45°) = √2/2 and sin(33°) to evaluate the expression:
sin(78°)cos(33°) = [(√2/2)(cos(33°)) + (√2/2)(sin(33°))]cos(33°)
= (√2/2)(cos(33°)cos(33°)) + (√2/2)(sin(33°)cos(33°))
= (√2/2)(cos^2(33°) + sin(33°)cos(33°))
Now, we can simplify further using the identity cos^2(A) + sin^2(A) = 1:
sin(78°)cos(33°) = (√2/2)(1 - sin^2(33°) + sin(33°)cos(33°))
= (√2/2)(1 - sin^2(33°)) + (√2/2)(sin(33°)cos(33°))
= (√2/2)(1 - sin^2(33°)) + (√2/2)(sin(66°)/2)
= (√2/2)(1 - sin^2(33°) + sin(66°)/2)
This is the exact value of the expression sin(78°)cos(33°).
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When 8 is added to a certain number and the
sum is multiplied by 3, the result is 57.
Find the number.
Answer:
11
Step-by-step explanation:
11+8=19
19x3=57
what is the equation of line a
Step-by-step explanation:
The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables and c is the constant term. The other different forms to find and represent the equation of a line are slope-intercept form, point-slope form, two-point form, intercept form, and normal form.
Discuss the downsizing process in your own words and provide an
example.
Downsizing refers to the process of reducing the size and workforce of a company to cut costs, increase efficiency, or adapt to changing market conditions. It involves eliminating positions, reducing staff numbers, or even closing down certain business units or branches.
Downsizing can occur for various reasons, such as financial difficulties, mergers and acquisitions, technological advancements, or strategic reorganization. Companies often assess their operational costs and decide to downsize to improve their financial performance.
During the downsizing process, companies may calculate the potential cost savings by considering factors such as salaries, benefits, severance packages, and operational expenses. For example, if a company decides to eliminate 100 positions with an average salary of $50,000 per year, it could result in annual savings of $5 million.
While downsizing can help companies achieve short-term cost reductions, it often has significant implications for the affected employees, including layoffs, reduced morale, and increased workload for remaining staff. It is crucial for organizations to handle the downsizing process with sensitivity and transparency, providing support to affected employees and communicating the rationale behind the decisions.
It is important to note that downsizing should not be seen as a long-term solution, but rather as a strategic measure to address specific challenges. Companies should also explore alternatives to downsizing, such as retraining and redeploying employees, implementing productivity improvements, or seeking new business opportunities, to ensure sustainable growth and success in the long run.
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The sale price of an item is $160 after a 20% off discount. What was the original price of the item?
Answer:
200
Step-by-step explanation:
160/80 is 2. 2 times 100 is 200
Help plz I need the answer real quick???
Answer:
Distance between mall and library is 6.32 miles.
Step-by-step explanation:
Coordinates of the door to the library is at (2, 4) and door to the mall is at (8, 4).
Since, distance between two points \((x_1,y_1)\) and \((x_2,y_2)\) is given by,
Distance = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)
By this formula,
Distance between (2, 4) and (8, 4) will be,
Distance = \(\sqrt{(8-2)^2+(2-4)^2}\)
= \(\sqrt{36+4}\)
= \(\sqrt{40}\)
= 6.32 miles
Find the measure of ∠H
Group of answer choices
106°
116°
96°
74°
Answer: 106
Step-by-step explanation: See attached images
Elimination Method2x+ 4y=10X+ y=15
1) Let's pick the 2nd equation and to eliminate the x variable, multiply by -2 then add both equations like this
2x+ 4y=10
-2X+ -2y=-30
---------------------------------
2y = -20
y = -10
2) Now let's plug that y=-10 into one equation, usually the simpler one.
x +y = 15
x -10 = 15 add 10 to both sides
X = 15 +10
x=25
3) So the solution is S ={25, -10}
on Tuesday at lunchtime, it was 29 degrees Celsius, by sunset, the temperature had dropped by 16
The equation for temperature change is T = -1.5t + 29 and the number line is plotted.
What is a number line?
A picture of numbers on a straight line is called a number line. It serves as a guide for contrasting and arranging numbers. Any real number, including all whole numbers and natural numbers, can be represented by it.
Let T represent the temperature in degrees Celsius, and let t represent the time in hours after lunchtime.
Then write an expression for the situation as follows:
T = -1.5t + 29
Here, -1.5t represents the decrease in temperature per hour, since the temperature is dropping at a rate of 1.5 degrees Celsius per hour.
Adding 29 to -1.5t gives the initial temperature of 29 degrees Celsius at lunchtime.
To illustrate this situation on a number line diagram, we can plot the temperature T as a function of time t.
The diagram would have time t on the horizontal axis and temperature T on the vertical axis.
Label the point (0, 29) on the diagram to represent the temperature at lunchtime, and the point (x, 16) to represent the temperature at sunset, where x is the number of hours after lunchtime.
Then draw a straight line connecting these two points to represent the linear relationship between temperature and time.
The line slopes downward from left to right, indicating that the temperature is decreasing over time.
Therefore, the number line diagram is plotted.
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On Tuesday at lunchtime, it was 29 degrees Celsius. By sunset, the temperature had dropped to 16 degrees Celsius. Please write an expression for the situation, and draw a number line diagram.
solve the problem attached in the image
Answer:
no te entiendo
yo también la busco
Answer:
1) 4 hours 2) 144 miles 3) 12 miles
Step-by-step explanation:
60/5=12
72/6=12
120/10=12
180/15= 12
1) 48 miles / 12 miles = 4 hours
2) 12 hours x 12 miles = 144 miles
3) 1 hour x 12 miles = 12 miles
If the experiment called for the temperature of the liquid to change by -3\4°c each hour, what would the temperature be at noon? Explain.
The temperature of the liquid at noon would be of:
-2.25ºC.
What is the linear function?The linear function in this problem is defined in the slope-intercept format, as follows
y = mx + b.
In which the coefficients of the function are given as follows:
m is the slope, representing the rate of change of the temperature.b is the y-intercept, representing the initial temperature.The values of these coefficients are given as follows:
m = -3/4, b = 0.
Then the function that gives the temperature in x hours after 9 A.M. is of:
y = -3/4x.
Noon is three hours after 9 A.M., hence the estimate is given as follows:
y = -3/4(3) = -9/4 = -2.25ºC.
Missing InformationThe problem states that the initial temperature is of 0ºC at 9 A.M.
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What is the relationship between DG and FG?
Math
If the length of the rectangle is (7x − 6) and the width is (5x + 6). Find the area of the rectangle
The area of a rectangle is 35x^2 + 12x - 36
What is Algebra?A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.
To determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.
Given that the length of the rectangle is (7x − 6) and the width is (5x + 6).
Thus the width be (5x + 6).
So, the length = (7x − 6)
So,
Area of rectangle = (7x − 6) (5x + 6).
= 35x^2 + 42x -30x - 36
= 35x^2 + 12x - 36
So, The area is 35x^2 + 12x - 36
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1. A researcher measures fear as the time it takes to walk across a presumably scary portion of campus. The times (in seconds) that it took a sample of 12 participants were 8, 12, 15, 13, 12, 10, 6, 10, 9, 15, 50, and 52. ___________________________________
The appropriate nonparametric test for the given research is; One sample Wilcoxon signed rank test.
What is the Non Parametric Test?A non-parametric test is also called a distribution-free test and it unlike the parametric test, it is usually based on fewer assumptions. Thus, there is typically no need for key parameters like median, mean deviation, mean e.t.c.
Now, the types of Non parametric tests are;
Wilcoxon Rank Sum TestMann Whitney U-testSpearman CorrelationKruskal Wallis TestIn this question, we do not know the distribution of X.
where;
X is the time it takes to walk across a presumably scary portion of campus.
However, we know that X is continuous and so we will use the One sample Wilcoxon signed rank test.
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a b and c are positive intergers a:b = 3:8 and b:c= 6:11 work out the smallest possible value of a b and c
Answer:
We can use ratios to set up a system of equations and solve for a, b, and c. Since a:b = 3:8, we can write:
a = 3x
b = 8x
Similarly, since b:c = 6:11, we can write:
b = 6y
c = 11y
Now we have two expressions for b, so we can set them equal to each other and solve for y:
8x = 6y
y = 4x/3
Substituting y back into the expression for c, we get:
c = 11y = 44x/3
To find the smallest possible values of a, b, and c, we want to choose values of x that are as small as possible while still being positive integers. Since x must be a multiple of 3 (because a = 3x is a multiple of 3), let's try x = 3. Then we get:
a = 3x = 9
b = 8x = 24
c = 44x/3 = 44
So the smallest possible values of a, b, and c are 9, 24, and 44, respectively.
Step-by-step explanation:
I’m so stuck please help
Answer: it is d
Step-by-step explanation:
What is an equation of the line that passes through the points (-1, 4) and (1, -6)?
Answer: y=-5x-1
Step-by-step explanation:
The two given points are (-1,4) and (1.-6)
We can then use the slope formula (Y2-Y1)/(X2-X1) to find the slope
4-(-6)/ -1-1 = 10/-2 = -5
Slope is -5
We then plug the slope in a set of points to find the y intercept
-5*-1+x = 4
5+x=4
x=-1
Then just add these two together to form the equation of y=mx+b
y=-5x-1
To start with, there were 2t + 1 daffodils and 14 roses in a flowerbed. 5 more daffodils were then added to the flowerbed, and the ratio of daffodils to roses is now 11 : 7. Calculate the value of t.
Help
The value of t is 16 where 14 roses are in a flowerbed.
What is ratio?A ratio is a relationship between two quantities or values that shows how many times one value is contained within the other. It is a way of comparing two or more numbers or measurements.
According to question:Let's first write an equation for the initial number of daffodils and roses in terms of t:
Number of daffodils = 2t + 1
Number of roses = 14
After adding 5 daffodils, the total number of daffodils becomes 2t + 1 + 5 = 2t + 6.
Now we can set up the ratio of daffodils to roses and solve for t:
(2t + 6)/14 = 11/7
Multiplying both sides by 147 gives:
2t + 6 = 222
Simplifying and solving for t gives:
2t = 38 - 6
2t = 32
t = 16
Therefore, the value of t is 16.
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A store gives away gift bags during a sale. Of these gift bags, 50% are green, 20% are yellow, and 30% are blue. The average number of items in each green bag is 8. The average number of items in each yellow bag is 5. The average number of items in each blue bag is 8. What is the average number of items in all the gift bags? PLS, HELP WILL GIVE YOU 95 PTS!!!!!!!!
Answer:
7
Step-by-step explanation:
So I started with an equation (g for green variable, y for yellow variable, b for blue variable)
8g + 5y + 8b = ??
Because of the lack of variables, I'm not really sure how to tie in the 50%, 20%, and 30%. (It could be unnecessary information)
But going off the average number of items, you have 8 green, 5 yellow, and 8 blue. So you can add them together for 21. From here, you divide 21 by 3 to get your average, 7.
Answer:hmm
Step-by-step explanation:
help asap if you can pls an thank u!!!!!!!
The value of angle S is 53°
What is exterior angle theorem?Exterior angle theorem states that the measure of an exterior angle of a triangle is equal to the sum of two remote interior angles.
With this theorem we can say that
7x+2 = 4x+13+19
collecting like terms
7x -4x = 13+19-2
3x = 30
divide both sides by 3
x = 30/3
x = 10
Since x = 10
angle S = 4x+13
angle S = 4(10) +13
= 40+13
= 53°
Therefore the measure of angle S is 53°
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A ______ graph is best suited for showing changes in statistics over time or space. a. pie b. line c. distributive d. parallel e. ratio.
A line graph is best suited for showing changes in statistics over time or space.
Line graphs are commonly used to visualize trends, patterns, and fluctuations in data over a continuous or discrete period. The x-axis represents time or space, while the y-axis represents the corresponding statistic being measured. The line graph connects the data points, allowing for a clear representation of how the statistic changes over the given time or space interval.
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Use the graph to write a linear function that relates y to x
PLEASE HELP
Answer:
\(y = \frac{1}{3} x + 3\)
Step-by-step explanation:
Start at the point (-3, 2). Go up 1 unit, then right 3 units, to the point (0, 3). The slope of the line is 1/3, and the y-intercept is 3, so we have
\( y = \frac{1}{3} x + 3\)
what is the potential energy of the water in a lake of surface area 10 square miles, average depth 40 ft, and elevation above the electrical generator of 600 ft?
The potential energy of the water in a lake is 57 trillion N × m, which is 57 trillion joules (J).
Gravitational potential energy applies in this situation. G P E = m g h is the formula for gravitational potential energy, where: mg stands for weight or mass times gravity (w). The height to which an object can fall before kinetic energy replaces potential energy is denoted by the symbol h. In the example of the lake, we first determine the amount of water using the equation for the volume of a typical cylinder in order to determine the weight of the cylinder: V cy l = π r²L , The weight density of the water per cubic foot, which is about 62 lb, can then be multiplied by this volume: W(water) = (Volume) (Density)
W (water) = (28,000,000 ft² ⋅ 40ft) ( 62 lb ÷ ft³ )
W (water) = 69,440,000,000 lb
To calculate the potential energy, multiply this weight by the height. GPE=mgh
GPE=Wh=(69,440,000,000lb)(600ft)
GPE=41,644,000,000,000ft⋅lb
matching the level of precision by rounding the response to two significant digits. 4.2X10¹³ft⋅lb , or 42 trillion ft-lb.
Because joules are measured in N × m units, multiply the result by fractional equivalencies. 42trillionft × lb × (4.45N ÷ lb) × (m ÷ 3.28ft)
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please help ASAP I don't know what to do
Answer:
AB = √(20^2 + 21^2) = √841 = 29
sin A = 21/29, cos A = 20/29, tan A = 21/20
F and g are functions such that
F(x)=3/x2 and g(x)=2x3
A) find f(-4)
B) find fg(1)
a. The value of f(-4) is \(3 \div -8\)
b. The value of fg(1) is \(3\div 4\)
Calculation of the value of f(-4) and fg(1):Since \(F(x)=3\div x\times 2\ and\ g(x)=2\times x\times 3\)
So,
a. The value of f(-4) is
\(= 3\div (-4)(2)\\\\= 3\div -8\)
And,
b. The value of fg(1) is
\(= 3\div (2(1)^3)(2)\\\\= 3\div (2)(2)\\\\= 3\div 4\)
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5. Divide 1148 into two parts which
are in the ratio 11: 3.
How do you get the answer
Add the two parts of the ratio together: 11 + 3 = 14
Divide the original number by 14:
1148/14 = 82
Now multiply 82 by each part of the ratio:
82 x 11 = 902
82 x 3 = 246
Answer: 902: 246
The body and head of a fox measure 19 ⅘ inches, and its tail measures 10 ⅘ inches. Whatis the total length of the fox?
Answer:
The total length of the fox is 30 3/5 inches
Step-by-step explanation:
Here, we are interested in calculating the total length of a fox, given the length of its head and body and also the length of its tail.
Mathematically, the total length of the fox = length of its head and body + length of its tail
length of the head and body = 19 4/5
length of its tail = 10 4/5
Plugging these values into the equation, we have;
19 4/5 + 10 4/5
99/5 + 54/5 = (99 + 54)/5 = 153/5 = 30 3/5 inches
The strength, S, of a wooden beam depends on the width and depth of the rectangular cross-section of the beam, but not on the length of the beam. For a particular type of wood, the value of S of a beam is proportional to the product of the width and the square of the depth of its cross-section. Suppose the strength of an oak beam is 69 , when the beam is 7 inches wide and 3 inches deep. Determine the strength, S, of the largest rectangular beam that can be cut from a 28 -inch-diameter oak tree, given that the beam must be 14 inches wide. Remember y is proportional to x if there is a constant k such that y=kx. The constant k is known as the constant of proportionality. a) S=9016 b) S=2231 c) S=8232 d) S=392
The real root of the equation is x = 40 - 39√2, which gives a value of S = 2231 approximately.
Given,The strength, S, of a wooden beam depends on the width and depth of the rectangular cross-section of the beam, but not on the length of the beam.
For a particular type of wood, the value of S of a beam is proportional to the product of the width and the square of the depth of its cross-section.
The strength of an oak beam is 69, when the beam is 7 inches wide and 3 inches deep.Thus, we can conclude that k, a constant of proportionality exists, such that: S=k(W x D²), where W is the width, D is the depth of the rectangular cross-section and S is the strength of the beam.
Let's use this to calculate k: When the beam is 7 inches wide and 3 inches deep, S=69. Thus, we get:k = S/W x D²=69/(7 x 3²)=1.
Thus, the equation for S becomes:S = W x D²The radius of the oak tree is 28/2 = 14 inches and the beam must be 14 inches wide.
This implies that the rectangular cross-section of the beam must be square (or the largest rectangular cross-section is a square). Let the side of the square cross-section be x.
Thus, we can write:S = x²Diameter, d = 28 inches => radius, r = 14 inchesWe need to determine the depth of the beam. The depth of the beam is half the height of the cylindrical log from which the beam is cut. The cylindrical log has a diameter of 28 inches. The beam has a width of 14 inches.
The largest rectangular cross-section is a square with sides of length x. This cross-section can be obtained by cutting the log at a height of x/2 from its center.Since the diameter is 28 inches, the radius is 14 inches. The height at which the beam is cut is h = 14 - x/2.
Thus, the depth of the rectangular beam cut from the cylindrical log is given by: D = 2(h) = 2(14 - x/2) = 28 - x.Using the relationship S = W x D² with S = 69, W = 14 and k = 1, we can write:x² (28 - x)² = 69Simplifying the above equation,x⁴ - 56x³ + 784x² - 69 = 0.
Using polynomial long division, we get:(x² + 16x - 69)(x² - 40x + 1) = 0The real root of the equation is x = 40 - 39√2, which gives a value of S = 2231 approximately.Therefore, the answer is (b) S = 2231.
The strength, S, of a wooden beam depends on the width and depth of the rectangular cross-section of the beam, but not on the length of the beam. Let the side of the square cross-section be x. Thus, we can write:S = x²Diameter, d = 28 inches => radius, r = 14 inches. Using the relationship S = W x D² with S = 69, W = 14 and k = 1, we can write:x² (28 - x)² = 69.The real root of the equation is x = 40 - 39√2, which gives a value of S = 2231 approximately.
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