Calculate the horizontal force that must be applied to a 1,300 kg vehicle to give it an acceleration of 2.6 m/s² on a level road.

500 N

3,380 N

1,302.6 N

0.002 N

​

Answer:

It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.

Explanation:

The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.

One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light

Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.  

When the switch is open, there is no current flowing through the wire loop, and therefore, the magnetic flux through the wire loop is zero.

When a current flows through a wire loop, it creates a magnetic field around the wire, which in turn generates a magnetic flux through the wire loop. However, when the switch is open, there is no current flowing through the wire loop, and hence, there is no magnetic field around the wire. As a result, the magnetic flux through the wire loop is zero.

This can be understood using Faraday's law of electromagnetic induction, which states that the induced electromotive force in a closed loop is proportional to the rate of change of the magnetic flux through the loop. Since the magnetic flux through the wire loop is zero when the switch is open, there is no induced electromotive force in the wire loop, and hence, no current flows through the loop.

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Answer: C. Trial 3

Explanation:

Trial 1 and 2 equal 1.5, Trial 3 equals 1 and Trial 4 equals 3. Trial 3 is the smallest current .

The trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.

To know the trial which generates the smallest current, we need to determine the current in each trial.

Since current I = V/R where V = voltage and R = resistance.

For trial 1, V = 1.5 V and R = 200 Ω

So, I = 1.5 V/200 Ω

= 0.0075 A

= 7.5 mA

For trial 2, V = 1.5 V and R = 100 Ω

So, I = 1.5 V/100 Ω

= 0.015 A

= 15 mA

For trial 3, V = 3 V and R = 200 Ω

So, I = 3 V/200 Ω

= 0.015 A

= 15 mA

For trial 4, V = 3 V and R = 100 Ω

So, I = 3 V/100 Ω

= 0.03 A

= 3 mA

Trial 2 and trial 3 both produce a the smallest current of 15 mA.

So, the trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.

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The maximum wavelength (\lambda_{\max }) for the Sun is approximately 5.01 × 10^-7 meters.

To find the maximum wavelength (\lambda_{\max}) for the Sun, we can use Wien's Law. According to Wien's Law, the wavelength at which an object emits the maximum amount of radiation is inversely proportional to its temperature.

The temperature of the Sun can be estimated using the Stefan-Boltzmann Law, which states that the power output of a blackbody is proportional to the fourth power of its temperature. Given that the total power output of the Sun is 3.8510²⁶ W, we can use this information to find the temperature.

By rearranging the Stefan-Boltzmann Law equation, we get:

T = (P/σ)^1/4

where T is the temperature, P is the power output, and σ is the Stefan-Boltzmann constant (5.67 × 10^-8 W m^-2 K^-4).

Plugging in the values, we have:

T = (3.8510²⁶ / 5.67 × 10^-8)^1/4

Simplifying this expression, we find:

T ≈ 5778 K

Now that we have the temperature of the Sun, we can find the maximum wavelength using Wien's Law, which states:

\lambda_{\max } = \frac{b}{T}

where \lambda_{\max } is the maximum wavelength, b is Wien's displacement constant (2.8978 × 10^-3 m K), and T is the temperature.

Plugging in the values, we have:

\lambda_{\max } = \frac{2.8978 × 10^-3}{5778}

Calculating this expression, we find:

\lambda_{\max } ≈ 5.01 × 10^-7 m

Therefore, the maximum wavelength (\lambda_{\max }) for the Sun is approximately 5.01 × 10^-7 meters.

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The production function will have constant returns to scale if 2αβ = 1

Constant returns to scale (CRS) implies that if all inputs increase by a factor of λ, the output increases by λ as well. The requirement for constant returns to scale (CRS) in a Cobb-Douglas production function with a new input factor is given by the sum of exponents on all variables equal to 1.

In this case, Y = AKαLβMγ.

Thus, we have that α + β + γ = 1 for constant returns to scale in K, L, and M, because the sum of the exponents is 1.

If the sum of the exponents is less than 1, it indicates decreasing returns to scale. If the sum of the exponents is greater than 1, it indicates increasing returns to scale. If we take γ = 0, we obtain the production function used in class, which is Y = AKαLβ, thus α + β = 1 for constant returns to scale in K and L.

When γ = 0, the answer we get is consistent with what we learned in class. Now, we consider the constant elasticity of substitution (CES) technology, where Y = [aKα + bLα]β. The production function will have constant returns to scale (CRS) in K and L if the sum of the exponents of K and L is equal to 1.

Therefore, αβ + αβ = 1, implying 2αβ = 1.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

m is the mass

f is the force

From the question we have

\(a = \frac{70}{7} = 10 \\ \)

We have the final answer as

Hope this helps you

Answer:

height=25

velocity=8

force of gravity=10

Answer =2000

Answer = The new distance is 1.5d

The horizontal range of a projectile is given by d = v2(sin2θ)/g

The ball is rolled down from the track from height 'h' above the endf of the track.

Hence, the loss in potential energy of the ball as it leaves the track is P = mgh

This P energy is converted to kinetic energy of the ball K = 0.5mv2

Hence, 0.5mv2 =  mgh  or, 0.5v2 = gh or, v2 = 2gh

Hence, Range d= v2(sin2θ)/g = (2gh)(sin2θ)/g

or, d = 2h(sin2θ)

Now, the track is not changed so θ is constant

So, d is proportional to h

The new height is 50% greater than h.

So, hnew = h + 0.5h = 1.5h

Hence, dnew = 2( 1.5h)sin2θ) = 1.5d

Answer = The new distance is 1.5d

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Answer: you have it correct

Explanation:

Answer:yall dumd dang thought yall know better

Explanation:

hehe

Answer:

earth

sorry I need points but I don’t know the answer again I’m really sorry

The initial velocity of the flea when it leaves the ground is roughly 0.083 m/s.

The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change. The velocity of an object is the rate at which its location changes in relation to a frame of reference and is a function of time. Velocity is similar to a speed and direction of motion specification (e.g., 60 km/hr to the north).

Here,

To calculate the initial velocity of the flea as it leaves the ground, we need to use the equation of motion for vertical motion:

v₀ = √(2gh)

where:

v₀ is the initial velocity

g is acceleration due to gravity (approximately 9.8 m/s²)

h is the maximum height (0.350 mm, or 0.00035 m)

So, the initial velocity would be:

v₀ = √(2 * 9.8 * 0.00035) = √(0.00693) = 0.083 m/s

The flea's initial velocity as it leaves the ground is approximately 0.083 m/s.

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Answer:

300 m/s

Explanation:

The “sum of forces” acting on a cart can be explained as the net force or resultant force acting on it. This term refers to the total amount of force acting on an object, considering both the direction and magnitude. The cart's acceleration is influenced by this force, which is critical in the laws of physics.

The following is a description of the “sum of forces” acting on a cart: The sum of forces can be calculated using the formula F = ma, where F is the force acting on the cart, m is the mass of the cart, and a is the acceleration produced by the force. If there is more than one force acting on the cart, it is necessary to calculate the net force, which is the sum of all the forces acting on the cart.
The sum of forces can be split into two components: internal and external forces. Internal forces are those generated within the object, whereas external forces are exerted by other objects. The frictional force between the wheels of the cart and the surface is an example of an internal force acting on the cart.
The gravitational force exerted by the Earth is an example of an external force acting on the cart. If there are more than two forces acting on the cart, vector addition must be used to determine the net force.
The sum of forces acting on the cart is critical in the laws of physics. If the sum of forces acting on the cart is zero, it implies that there is no net force acting on it, and it is either stationary or moving at a constant velocity. If the sum of forces is nonzero, it implies that there is a net force acting on the cart, and it is either accelerating or decelerating.

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In general, comets are often discovered by amateur or professional astronomers using telescopes or other observation equipment. The type of telescope used can vary depending on the observer's preference and the specific requirements of the observation.

When a comet is first discovered, astronomers typically describe its position, brightness, and any visible features such as a tail or coma. They may also use spectroscopy to analyze the composition of the comet's gases and dust.

Astronomers may have various expectations about what they might see when a comet impacts a planet or other object. Prior to the impacts, some astronomers may have predicted a large explosion or other dramatic effects. However, the actual outcome can be difficult to predict and may depend on many factors such as the comet's size, speed, and angle of impact.

As for lessons for us on Earth, the study of comets can help us understand the history and evolution of our solar system. It can also provide insights into the formation of planets and the origins of life on Earth. Additionally, the study of impacts can help us prepare for potential hazards such as asteroid or comet impacts on Earth.

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2.15 s time  it take the can to hit the floor when a can of bean rolls off a horizontal table with a velocity of 0.44 m/s

velocity=distance/time

time=distance/velocity

time=0.95/0.44

time=2.15 s

A vector number called velocity can be used to express "the speed at which an object changes its location." Imagine someone moving quickly while taking two steps forward and two steps back, all while remaining in the same place. A vector quantity is velocity. As a result, velocity is aware of direction. When calculating an object's velocity, the direction must be taken into consideration. A speed of 55 miles per hour is insufficient detail. The velocity of the item must be properly described in terms of the direction. Simply explained, the velocity vector's direction shows how an item is moving.

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Answer:

v=s/t

s=vt

t=s/v

t=(120×10‐³)/172.8

(the distance meters has been changed to kilometres)

t=1/1440 hrs

Given ,

(a)The pressure at B is 0.1248 atm.

(b)The temperature at C is 727.1 K.

(c)The total work done by the gas in one cycle is -1979J

General calculation:

We can use the First Law of Thermodynamics to analyze the heat engine cycle:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. For a complete cycle, ΔU = 0, so:

Q = W

We can also use the ideal gas law to relate the pressure, volume, and temperature of the gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.

(a)How to find the pressure at B segment?

To find the pressure at B, we can use the fact that the segment AB is an isothermal expansion. This means that the temperature remains constant, so:

PV = nRT

PB = (nRT)/(2V) = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/(2V) = (0.0821 L·atm/mol)(600 K)/V

Since the pressure at A is 5.00 atm, we can use the fact that the temperature is constant to find the volume at A:

PV = nRT

VA = (nRT)/P = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/5.00 atm = 197.76 L

Since the volume at B is twice the volume at A, we have:

VB = 2VA = 395.52 L

Substituting into the expression for PB, we get:

PB = (0.0821 L·atm/mol)(600 K)/395.52 L = 0.1248 atm

Therefore, the pressure at B is 0.1248 atm.

To find the temperature at C, we can use the fact that the segment BC is an adiabatic expansion. This means that no heat is added or removed from the system, so:

\(PV^\gamma\)= constant

where γ is the ratio of specific heats (for a monoatomic gas, γ = 5/3). We can use the fact that the volume at C is equal to the volume at A to find the pressure at C:

\(PAV^\gamma = PCV^\gamma\)

PC =  \(PA(V/A)^\gamma\) = 5.00 atm\((1/2)^(^5^/^3^)\) = 1.556 atm

Since the segment BC is adiabatic, the temperature changes but no heat is added or removed from the system. Using the ideal gas law, we can relate the pressure, volume, and temperature:

PV = nRT

TC = (PCVC)/(nR) = (1.556 atm)(197.76 L)/(2.00 mol)(0.0821 L·atm/mol·K) = 727.1 K

Therefore, the temperature at C is 727.1 K.

The total work done by the gas in one cycle is the sum of the work done in each segment of the cycle:

W = WAB + WBC + WCD + WDA

For segment AB, the work done is:

WAB = -QAB = -∫PdV = -nRT∫(1/V)dV = -nRT ln(VB/VA) = -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2) = -602 J

For segment BC, the work done is:

WBC = -QBC = -∫PdV = -nγRT∫(1/V)dV = -nγRT

We know that VB = 2VA and VC = 2VD, so we can express the ratio VB/VC in terms of VA/VD:

VB/VC = (2VA)/(2VD) = VA/VD

Substituting into the expression for WBC, we get:

WBC = -nγRT ln(VA/VD)

For segment CD, the work done is:

WCD = -QCD + PCDΔV = -nCpΔT + PCDΔV

where Cp is the specific heat at constant pressure, ΔT is the change in temperature, and ΔV is the change in volume. We know that the segment CD is isobaric, so ΔV = VB - VA = (2VA) - VA = VA. We can also use the ideal gas law to relate the pressure, volume, and temperature:

Substituting into the expression for WCD, we get:

WCD = -nCpΔT + (nRT/VD)VA = -nCp(TC - TD) + (nRT/VD)VA

For segment DA, the work done is:

WDA = -QDA + ΔU = -nCvΔT

where Cv is the specific heat at constant volume. We know that the segment DA is isovolumetric, so ΔV = 0. Using the First Law of Thermodynamics, we know that ΔU = 0 for a complete cycle, so:

QDA = -WDA = nCvΔT

Substituting into the expression for WDA, we get:

WDA = -nCvΔT

Adding up the work done in each segment, we get:

W = WAB + WBC + WCD + WDA

= -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(Cp)(TC - TD) + (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(Cv)(TC - TA)

We know that Cp and Cv for a monoatomic gas are related by Cp = Cv + R, so we can express Cp in terms of Cv:

Cp = Cv + R = (3/2)R + R = (5/2)R

Substituting and simplifying, we get:

W = (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(727.1 K)+ (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(600 K)

W = -966.2 J - 4957 J - 7476 J + 5154 J

    = -1979 J

Therefore, the total work done by the gas in one cycle is -1979 J

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Answer:

The five conditions of chemical change: color change, formation of a precipitate, formation of a gas, odor change, temperature change.

Light is radiant energy in the form of a wave of electromagnetic energy.

Light is a form of electromagnetic radiation that is visible to the human eye. It is made up of a stream of energy particles, called photons, that travel in a wave-like pattern. It has various properties, including intensity, color, and direction, which can be used to explain its behavior. It can be described as having both a particle-like nature and a wave-like nature. The particle-like nature of light is exhibited in the way it travels in packets of energy, known as photons. The wave-like nature of light is demonstrated by the way it can be bent, diffracted, and refracted.
The intensity of light is determined by the amount of energy that a photon has. The color of light is determined by the wavelength of the light, with different colors having different wavelengths. Direction is also an important property of light, as it determines how light will be bent when it passes through an obstacle or is reflected off of a surface.
Light plays a critical role in the lives of humans and other organisms. It is used in vision, to help organisms understand the world around them. Light also has numerous applications in science and technology, such as in communications, photography, and solar energy.
In conclusion, light is a form of electromagnetic radiation composed of photons that travel in a wave-like pattern. It has various properties, including intensity, color, and direction, that are used to explain its behavior. Light is important for vision and has various uses in science and technology.

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Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

Answer:

A. quart

B. gram

C. Meter

Explanation:

Answer:

A. meter

B. liter

C. pound

Explanation: First kid is not right at all i am

The quantum theory of energy developed by max planck raised fundamental questions about the nature of matter and energy, challenging the classical view that energy was continuous and could be divided into an infinite number of small amounts.

Planck's theory postulated that energy is emitted or absorbed in discrete packets, or quanta, and that the energy of each quantum is proportional to the frequency of the radiation.

This theory revolutionized the understanding of atomic and subatomic processes and laid the foundation for the development of quantum mechanics, which is now a fundamental part of modern physics.

The theory also helped to explain the behavior of black-body radiation, which was a major problem for classical physics at the time, and paved the way for new technologies like lasers and transistors, which rely on the principles of quantum mechanics.

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a. The particles speed up and spread apart,  in a liquid as it turns into a gas.

Particles in liquids are dispersed randomly across the container and are relatively near to one another. Due to the closer proximity of the particles, collisions between them happen more frequently than in gases even if particles are moving quickly in all directions.

A liquid has a fixed shape and volume as opposed to a gas, which is how they differ from one another. While a liquid keeps a consistent volume, a gas adopts the shape of its container. Additionally, gas is more compressible than liquid. This implies that a gas can be compressed into a smaller area than a liquid.

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The acceleration of a particle is a= (-1.6 v1/2) m/s². The initial velocity of the particle is u = 8 m/s.

Now, let's use the formula: 2as = v² - u², where a = (-1.6v^(1/2)) m/s², u = 8 m/s, and v = 0 m/s 2 × (-1.6v^(1/2)) × s = 0 - 8²s = 64 / (2 × 1.6v^(1/2)) = 20v^(1/2)/4 = 5v^(1/2) meters.

This is the distance travelled by the particle before it stops.

We know that the final velocity of the particle is 0 m/s. The initial velocity of the particle is 8 m/s.

The acceleration of the particle is a = (-1.6v^(1/2)) m/s².

Let's use the formula to calculate the time it takes to stop the particle. It is:v = u + at 0 = 8 + (-1.6v^(1/2)) × t t = 8 / (1.6v^(1/2)) t = 5 / v^(1/2) seconds.

This is the time taken by the particle to come to rest.

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The particle travels approximately 12.5 meters before it comes to a stop. It takes approximately 5 seconds for the particle to reach zero velocity.

To determine the distance traveled before the particle comes to a stop, we need to integrate the velocity function over time. The given deceleration is expressed as a = -1.6√v , where v is the velocity in m/s. Since the initial velocity is 8 m/s, we can write the deceleration as a = -1.6√8. Integrating the acceleration with respect to velocity gives us the equation: ∫dv/(-1.6√v ) = ∫dt. Simplifying the integral and solving for t gives us t = 5 seconds.

To find the distance traveled, we integrate the velocity function with respect to time. The velocity function is given by dv/dt = -1.6√v. Separating variables and integrating, we get ∫dv/√v  = ∫-1.6dt. Evaluating the integral and substituting the limits (from v = 8 m/s to v = 0), we find √v = -1.6t + C. Applying the initial condition v(0) = 8, we can solve for C and obtain C = √8. Plugging in the values for t and C, we get √v = -1.6t + √8. Squaring both sides and solving for v, we find v = \((1.6t - \sqrt{8} )^{2}\). Integrating the velocity function again with respect to time, we get ∫\((1.6t - \sqrt{8} )^{2}\) dt = ∫ds. Evaluating the integral and substituting the limits, we find s = 12.5 meters.

Therefore, the particle travels approximately 12.5 meters before coming to a stop.

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Answer:

The answer is 0 J

Explanation:

Mass=3

Acceleration= 9.8

Height=0

The eqation is \(3(9.8)(0)\) or \(3*9.8*0\)

and if you do the math it adds up to 0 J

The potential energy of your 3 kg puppy that is sitting in the grass in your backyard would be 0 Joules .

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy .

ME = PE + KE

As for the given problem, we have to find out what the potential energy of your 3 kg puppy that is sitting in the grass in your backyard,

The potential energy of the puppy = m × g × h

                                                  = 3 × 9.8 × 0

                                                  = 0

Thus , the potential energy of your 3 kg puppy that is sitting in the grass in your backyard would be 0 Joules .

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Answer:

40 m/s

Explanation:

To solve this problem, we can use the following kinematic equation:

\(\boxed{v = u + at}\),

where:

• v ⇒ final velocity = 0 m/s [as the ball stops moving when it reaches the highest point]

• u ⇒ initial velocity

• a ⇒ acceleration = -10m/s² [The value is negative as acceleration due to gravity is acting downwards but the ball is moving upwards]

• t ⇒ time taken = 4 s

Substituting the data into the equation above, we can calculate the initial velocity:

0 = u - 10 × 4

⇒ u = 40 m/s

Therefore, the ball was travelling at 40 m/s when it left the boy's hand.

Answer:

The answer would be B. Lubricating surfaces.

Explanation:

Mark brainliest pls

You should push the accelerator all the way to the floor and hold for five seconds if your engine is flooded with gasoline.

To find the answer, we need to know about the flooded engine.

Thus, we can conclude that, You should push the accelerator all the way to the floor and hold for five seconds if your engine is flooded with gasoline.

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Answer:

1. Pioneer

2. Primary

Explanation:

Pioneer Species are the first organisms to colonize barren environments.

Primary Succession is the development of an ecosystem of a barren environments!

I hope this helped! :)

Answer:

The first answer is Pioneer and I think the second is Primary

Explanation: