can you apply kinematics with constant acceleration equations for an object undergoing circular motion?
Answers
No, we can not apply kinematics with constant acceleration equations for an object undergoing circular motion because acceleration of the particle in circular motion is constantly changing.
Why kinematics can not be applied for an object undergoing circular motion?Since the kinematic formulas are accurate only if the acceleration is constant during the time interval , therefore we have to be careful to not use them when the acceleration is changing.
The kinematics equations can be utilized for any motion that is described as being either a constant velocity motion or a constant acceleration motion. They can not be used over any time period during which the acceleration is changing.
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Related Questions
Whenever energy is changed from one form to another is some energy lost as heat
Answers
Answer:
That is very true, there can never be 100% energy conversion.
Which of the following is a subatomic particle?
Particle
Atom
Neutron
Element
Answers
Answer:
neutron.
Explanation:
subatomic particles include,
neutron.
proton.
electron.
hope it helps. :)
an astronaut is said to be weightless when he/she travels in a satellite.does it mean that the earth does not attract him/her?
Answers
Answer:
No, gravitational force is a force having infinite range. It only reduces to an extent that astronauts cannot feel it.
Explanation:
sound caused by an explosion on the oceans surface travels vertically downward to an underwater mountain and is reflected back to a microphone at the surface. if this takes 11.6 s to occur and the sound travels 1450 m/s in water what is the depth to this mountain
Answers
The depth to this underwater mountain is 8410 m.
What is an echo?An echo is the sound heard after the reflection of the initial sound from a reflecting surface.
The echo time or the time taken for an echo to be heard is used to calculate the distance from the reflecting surface.
The Distance is of a place from the time taken to hear an echo is calculated as follows:
Distance = Speed * Time/2
Distance = 1450 * 11.6/2
Distance = 8410 m
Therefore, the depth to this underwater mountain is 8410 m.
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You are driving a metric car that has a speedometer that displays in meters per second. When you look down at your speedometer, you see that it reads 23 m/s, then 7.4 s later you look down and it reads 13 m/s. What is your average acceleration over those 7.4 s?
Answers
mention four physical properties of physics
Answers
density (intensive)
volume (extensive)
mass (extensive)
2. Color
3. Volume
4. Mass
a boy throws a ball straight up into the air. it reaches its highest point after 4 seconds.how fast was the ball going when it left the boy's hand
Answers
Answer:
Explanation:
The most important thing to remember about parabolic motion in physics is that when an object reaches its max height, the velocity right there at the highest point is 0. Use this one-dimensional motion equation to solve this problem:
v = v₀ + at and filling in:
0 = v₀ + (-9.8)(4.0) **I put in 4.0 for time so we have more than just 1 sig fig here**
0 = v₀ - 39 and
-v₀ = -39 so
v₀ = 39 m/s
4 properties of light
Answers
-dispersion of light
-absorption of light
-polarization of light
Why are solar storms a concern to Earth?
Answers
Sc 1.1 Two forces act on an object. The first is a horizontal 50 N force. The second is a 40 N force acting at an angle to the horizontal. Use a graphical method drawn to a scale of 1 mm : 1 N to find the resultant if the 40 N force is inclined at: 1.1.1 30° to the horizontal 1.1.2 60° to the horizontal.
Answers
1.1.1: The force, which is 61.4 N and inclined at a 34.4° angle to the horizontal,
1.1.2: The resultant force is 30.8° inclined to the horizontal and is 66.9 N in magnitude.
How does vector addition work?
The process of adding vectors together to determine the resulting force is known as vector addition.
Vector addition is the theory that was applied in this question
The steps involved in adding vectors are as follows:
First, use the two provided vectors and the resulting vector to scale up a vector diagram.
Step 2: Apply the Pythagorean theorem to determine the magnitude of each vector.
Calculate each vector's angle with respect to the horizontal in step three.
4th step: Apply the Use the law of cosines to find the magnitude of the resultant vector
Step 5: Use the law of sines to find the angle of the resultant vector with respect to the horizontal.
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How much of Dalton's atomic model is still considered accurate
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Dalton's atomic theory is still mostly true, and it forms the framework of modern chemistry.
Key Points:
Dalton's atomic theory was the first complete attempt to describe all matter in terms of atoms and their properties.Dalton based his theory on the law of conservation of mass and the law of constant composition.The first part of his theory states that all matter is made of indivisible atoms.The second part of the theory says all atoms of a given element are identical in mass and properties.The third part says compounds are combinations of two or more different types of atoms.The fourth part of the theory states that a chemical reaction is a rearrangement of atoms.Parts of the theory had to be modified based on the discovery of subatomic particles and isotopes.
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If there is 3.4 m3 of methane gas in a container with a pressure of 18.9 atm and the container expands until the methane has a pressure of 2.2 atm, what is the final volume of the methane? Temperature is constant at 305 K. A. 12.23 m3 B. 141.37 m3 C. 29.21 m3 OD. 2.53 m3
Answers
Answer:
C. 29.21 m³
Explanation:
Given the following data;
Initial volume, V1 = 3.4 m³Initial pressure, P1 = 18.9 atmFinal pressure, P2 = 2.2 atmTo find the final volume, we would use Boyle's law;
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
PV = K
\( P_{1}V_{1} = P_{2}V_{2} \)
Making V2 the subject of formula, we have;
\( V_{2} = \frac {P_{1}V_{1}}{P_{2}} \)
Substituting the values into the formula, we have;
\( V_{2} = \frac {18.9 * 3.4}{2.2} \)
\( V_{2} = \frac {64.26}{2.2} \)
Final volume, V2 = 29.21 m³
Objects A and B have equal amounts volumes and are both traveling at 25 miles per hour. Object A is much denser than Object B. Which object has a greater amount of force and why
Answers
Answer:
Object A
Explanation:
Mass of an object= Volume × denstiy
Object having higher density will have greater mass
Next,
According to second law of Newton
Force= mass× acceleration
Force= mass× change is velocity/ time
For an equal amount of time, if change in velocity is equal then object with higher mass will have higher force. Hence, greater density, greater is mass and larger is the force.
As a particle moves from the center to the edge of a spinning platform: ___________
a. its angular speed increases.
b. its center of mass increases.
c. its angular acceleration increases.
d. its tangential speed increases.
Answers
As a particle moves from the center to the edge of a spinning platform, its tangential speed increases. The correct option is D
As a particle moves from the center to the edge of a spinning platform, its tangential speed increases.What is tangential speed?Tangential speed is defined as the speed of a point traveling along a circular path. It's a scalar quantity that's determined by the path's radius and the point's angular velocity.
What is spinning? Spinning is the process of rotating an object about an axis that passes through the object's center of mass. The movement of particles in a spinning system is characterized by their angular velocity and speed. Hence, as a particle moves from the center to the edge of a spinning platform, its tangential speed increases. The correct option is D
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At one instant a bicyclist is 46.0 m due east of a park's flagpole, going due south with a speed of 10.0 m/s. Then 34.0 s later, the cyclist is 46.0 m due north of the flagpole, going due east with a speed of 10.0 m/s. For the cyclist in this 34.0 s interval, what are the (a) magnitude and (b) direction of the displacement, the (c) magnitude and (d) direction of the average velocity, and the (e) magnitude and (f) direction of the average acceleration
Answers
Magnitude of the displacement is 64.1 m. b) Direction of displacement is 142.6°. c) Magnitude of average velocity is 1.89 m/s. d) Direction of average velocity is 50.7° east of south.
Magnitude of average acceleration is 0 m/s². f) Direction of average acceleration is undefinedGiven data:Initial distance of bicyclist from the park's flagpole = 46.0 mInitial velocity of bicyclist = 10.0 m/sSouth direction is considered as negative x-axis and east direction is considered as positive y-axis.Solution:a) Magnitude of the displacement is given by magnitude of difference between final and initial position of the bicyclist.Magnitude of displacement = sqrt[(46.0 + 46.0)² + (0)²]Magnitude of displacement = 64.1 mb) Direction of the displacement is given by the direction of line joining initial and final position of the bicyclist and is measured from the negative x-axis.Direction of displacement = tan⁻¹ (0/92.1)Direction of displacement = 0° + 142.6° = 142.6°c) Magnitude of average velocity is given by the magnitude of displacement divided by the time taken.Magnitude of average velocity = Magnitude of displacement / Time takenMagnitude of average velocity = 64.1 m / 34.0 sMagnitude of average velocity = 1.89 m/sd) Direction of average velocity is the direction of line joining initial and final position of the bicyclist and is measured from the negative x-axis.Direction of average velocity = tan⁻¹ 46.0/46.0Direction of average velocity = 45.0° + 5.7° = 50.7° east of southe)
As there is no change in velocity of the bicyclist, magnitude of average acceleration is zero.Magnitude of average acceleration = 0 m/s²f) As the acceleration of the bicyclist is zero, direction of average acceleration is undefined.
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Einstein’s theory of general relativity is currently the best explanation of gravity . What is likely to happen to this theory in the future
Answers
Answer:
2.00
Explanation:
Answersdff:
Explanation:
what is the magnitude of the angular momentum of the bar?
Answers
Answer:
The magnitude of the angular momentum:
M × v × r
M = the mass of the ballv = the magnitude of its velocityr = the radius of the ballthe diagram shows a basic hydraulic system which has a small piston and a large piston with cross-sectional areas of 0.005m² and 0.1m² respectively. A force of 20 N is applied to the small piston. Determine (a) the pressure transmitted in the hydraulic fluid (b) the mass of the load
Answers
The pressure transmitted in the hydraulic fluid is 4000 Pa and the mass of the load is 40.82 kg.
To determine the pressure transmitted in the hydraulic fluid, we can use the formula:
Pressure = Force / Area
Given that a force of 20 N is applied to the small piston and the cross-sectional area of the small piston is 0.005 m², we can calculate the pressure as follows:
Pressure = 20 N / 0.005 m²
Pressure = 4000 Pa
Therefore, the pressure transmitted in the hydraulic fluid is 4000 Pa.
To determine the mass of the load, we need to consider the equilibrium of forces in the hydraulic system. The force applied to the small piston is transmitted to the larger piston. Since the system is in equilibrium, the force exerted by the larger piston must balance the force applied to the small piston.
Using the formula:
Force = Pressure × Area
The force exerted by the larger piston can be calculated as follows:
Force = Pressure × Area (large piston)
Force = 4000 Pa × 0.1 m²
Force = 400 N
Therefore, the force exerted by the larger piston is 400 N.
Since force is equal to mass multiplied by acceleration (F = m × a), and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the mass of the load:
400 N = mass × 9.8 m/s²
Solving for the mass:
mass = 400 N / 9.8 m/s²
mass ≈ 40.82 kg
Therefore, the mass of the load is approximately 40.82 kg.
The question was incomplete. find the full content below:
The diagram shows a basic hydraulic system which has a small piston and a large piston with cross-sectional areas of 0.005m² and 0.1m² respectively. A force of 20 N is applied to the small piston. Determine (a) the pressure transmitted in the hydraulic fluid (b) the mass of the load
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Ingrid lives in a cold country that sometimes gets lots of snow. When that happens , people can enjoy the sport of skiing. Ingrid goes outside to see if the snow is fit for skiing. She sinks into the snow , but when she puts her skis in,she can move over the snow without skiing. Why?
Answers
Ingrid uses a technique called "skate-skiing" where she holds one ski in a V-shape in the opposite direction while pushing the other.
What is technique?A technique is a way to accomplish a task or solve a problem. This may involve a specific step-by-step process or a more general approach, drawing on your individual knowledge and skills.
Techniques include physical acts, mental processes, or both. Examples of techniques include using a hammer to hammer nails, using certain equations to solve math problems, and using certain types of meditation to relax.
The goal of any technique is to make the task easier, faster, or more accurate. This allows skiers to move over the snow without actually skiing in the traditional way. This technique is often used in areas of deep, soft snow that are not suitable for traditional skiing.
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Determine the speed at which the kinetic energy of an electron is equal to 0.5 times its rest energy.
Answers
The speed at which the kinetic energy of an electron is equal to 0.5 times its rest energy is the speed of light, which is approximately 3 x 10^8 meters per second.
To determine the speed at which the kinetic energy of an electron is equal to 0.5 times its rest energy, we can use the equation for kinetic energy:
\(KE = (1/2)mv^2,\)
where KE is the kinetic energy, m is the mass of the electron, and v is its velocity. The rest energy of an electron is given by the equation:
\(E0 = mc^2\),
where E0 is the rest energy, m is the mass of the electron, and c is the speed of light.
We can set up the equation KE = 0.5E0 and substitute the expressions for KE and E0 to solve for v. Rearranging the equation, we get
\((1/2)mv^2 = 0.5mc^2.\)
Canceling out the mass terms, we have
\(v^2 = c^2.\)
Taking the square root of both sides, we find
v = c.
Therefore, the speed at which the kinetic energy of an electron is equal to 0.5 times its rest energy is equal to the speed of light, c.
In conclusion, the speed at which the kinetic energy of an electron is equal to 0.5 times its rest energy is the speed of light, which is approximately 3 x 10^8 meters per second.
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Why do we need to convert mass to moles in stoichiometry problems.
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The 800 kg physics dragster is traveling at 35 km/h east when it hits the gas and accelerates at 12.5 m/s^2 for 3.25 s. what is its change in momentum during the time
Answers
The change in momentum during the 3.25s acceleration is 28,280 kg m/s.
What is the change in momentum?The change in momentum of an object is given by the product of its mass and its change in velocity, which can be calculated using the equation:
Δp = m * Δv
Where Δp is the change in momentum, m is the mass of the object, and Δv is the change in velocity.
To find the change in velocity, we can use the equation:
v = v0 + at
Where v is the final velocity, v0 is the initial velocity, a is the acceleration, and t is the time interval.
Since the dragster is initially traveling at 35 km/h = 35 * 1000 / 3600 m/s = 9.72 m/s, we can plug in the values to find the final velocity:
v = 9.72 + (12.5)(3.25) = 45.07 m/s
Δv = v - v0 = 45.07 - 9.72 = 35.35 m/s
Now that we have the change in velocity, we can find the change in momentum:
Δp = m * Δv = 800 kg * 35.35 m/s = 28,280 kg m/s
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Emanuel Zacchini, the famous human cannonball of the Ringling Bros. and Barnum &
Bailey Circus, was fired out of a cannon with a speed of 30.0 m/s at an angle of 37° to
the horizontal.
What is his vertical velocity?
O 18.05 m/s
O 23.96 m/s
O 30 m/s
Other questions:
What is the maximum height?
What is the horizontal velocity
If it landed at net 88.279m away at the same height from which he was fired, how long was he in the air?
Please i need help. Its a test.
Answers
Answer:
We have that Assuming No air resistance,the initial horizontal velocity of the cannonball is
From the question we are told that
A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s
Generally the equation for the horizontal velocity is mathematically given as
Therefore
Therefore Assuming No air resistance,the initial horizontal velocity of the cannonball is For more information on this visit
Explanation:
A 1.0 kg weight suspended from a spring is pulled to 0.25 m below its equilibrium point.
If the spring has a spring constant (k) of 50.0 N/m, at what rate will the mass accelerate when it is released?
O 200 m/s²
O 12.5 m/s²
○ 2.7 m/s²
O 6.5 m/s²
Answers
Answer:
B.12.5m/s²Explanation:
Greetings!!!
Given values :-weight= 1.0kg
Extension (x)= 0.25m
spring constant (k)= 50.0N/m
Required value :-Acceleration= ?
Solution:-\(firstly.recall \: the \: hooks \: law\)
F=Kx\(substitute \: known \: varabiles \: into \: the \: equation\)
F= (50)(0.25)\(solve \: for \: force\)
F= 12.5N\(secondly \: reall \: the \: newtons \: second \: law\)
F= ma\(substitute \: known \: variables \: into \: the \: equation \: \)
(12.5)= (1.0)a\(solve \: for \: acceleration \: \)
a= 12.m/s²Hope it helps!!!
Estimate the magnitude of the magnetic field at ground level generated by an overhead AC power line service drop connecting a single home to a utility pole.
Answers
Answer:
Explanation:
Magnetic field due to current carrying wire at a distance r from the wire is
\(B=\frac{\mu_0I}{2r}---(1)\)
In our case
\(I=\frac{I_0}{2}\)
where,
I₀ = max current or peak current
and r = h (where h is the height of power line)
\(\therefore B=\frac{\mu (I_0/2)}{2h} \\\\=\frac{\mu_0 I_0}{4h} ----(2)\)
put
h ≈ 370m
I₀ ≈ 3KA
\(B= \frac{(1.26*10^-^6)(3*10^3)}{4*(370)} \\\\=2.5*10^-^6 T\)
What is happening when an oxygen molecule is formed from two separate oxygen atoms?
Answers
Two from each oxygen atom. For examples of covalent bonding are water (H2O), and carbon dioxide (CO2). Covalent compounds are mostly gases or liquids with low melting points.
How many millimeters of water can dissolve 5g of lead nitrate
Answers
The solubility of lead nitrate is 52 grams per 100 milliliters of water at 0°C. Since the question does not specify the temperature, we will assume it is 0°C.To calculate the number of millimeters of water required to dissolve 5 g of lead nitrate,
we must first calculate the number of milliliters of water required to dissolve 5 g of lead nitrate.52 grams of lead nitrate can dissolve in 100 milliliters of water. So,5 g of lead nitrate can dissolve in x milliliters of water.= (5 g / 52 g) × 100 mL= 9.6 mLTherefore, 5 g of lead nitrate can dissolve in 9.6 mL of water. However, the question is asking for the number of millimeters of water, not milliliters. Since 1 milliliter of water weighs 1 gram,9.6 milliliters of water will weigh 9.6 grams.Thus, 5 g of lead nitrate can dissolve in 9.6 millimeters of water.
main answer:5 g of lead nitrate can dissolve in 9.6 millimeters of water. :52 grams of lead nitrate can dissolve in 100 milliliters of water. So, 5 g of lead nitrate can dissolve in x milliliters of water.= (5 g / 52 g) × 100 mL= 9.6 mLTherefore, 5 g of lead nitrate can dissolve in 9.6 mL of water. However, the question is asking for the number of millimeters of water, not milliliters. Since 1 milliliter of water weighs 1 gram,9.6 milliliters of water will weigh 9.6 grams.Thus, 5 g of lead nitrate can dissolve in 9.6 millimeters of water.
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The standard metric unit of volume is the _____.
cubic centimeter
liter
milliliter
cubic meter
Answers
Answer:
. The SI unit of volume is the cubic meter (m3), which is a derived unit.
Liter (L) is a special name for the cubic decimeter (dm3).
The cooling system of an automobile motor contains 20. 0 kg of water. What is the t of the water if the engine operates until 836,000 J of heat have been added to the water?
Answers
the temperature of the water in the cooling system will increase by 9.99°C if the engine operates until 836,000 J of heat have been added to the water.
To solve this problem, we need to use the specific heat capacity equation:
Q = mcΔT
where Q is the amount of heat transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
We know that the engine has added 836,000 J of heat to the water, and that the mass of the water is 20.0 kg. The specific heat capacity of water is 4.18 J/g°C.
First, we need to convert the mass of water from kg to g:
20.0 kg = 20,000 g
Now we can plug in the values:
836,000 J = (20,000 g)(4.18 J/g°C)(ΔT)
Solving for ΔT:
ΔT = 836,000 J / (20,000 g x 4.18 J/g°C)
ΔT = 9.99°C
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for the am waveform s(t) shown, the carrier signal has a peak amplitude of 0.8 v. what is the modulating index?
Answers
The modulating index for this AM waveform is 1.25.
How to calculate the modulating index in amplitude?The modulating index (m) in amplitude modulation (AM) is a dimensionless quantity that represents the ratio of the amplitude of the modulating signal to the amplitude of the carrier signal. It is given by the formula:
m = (A_m/A_c)
where A_m is the amplitude of the modulating signal, and A_c is the amplitude of the carrier signal.
Assuming that the modulating waveform is a sinusoidal signal with a peak amplitude of 1 V, the modulating index can be calculated as follows:
m = (A_m/A_c) = (1 V)/(0.8 V) = 1.25
Therefore, the modulating index for this AM waveform is 1.25.
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