Complete the following calculations. Include units in your answers. Report your answer to 1 decimal place.

1. (100m) / (26 s)
2. (8.1 kg) / (0.45 cm x 0.55 cm)
3. (5.1 m) (4.5 m)

Please help! And please explain how you solved it! Thank you!!!!

Answers

Answer 1

The complete calculation and corresponding units of the problems in one decimal place is determined as 3.9 m/s, 32.7 kg/cm² and 23.0 m².

Compete calculation

The complete calculation and corresponding units of the problems in one decimal place is calculated as follows;

For problem 1

1. (100m) / (26 s) = 3.9 m/s

For problem 2

2. (8.1 kg) / (0.45 cm x 0.55 cm) = (8.1 kg) / (0.2475 cm²) = 32.7 kg/cm²

For problem 3

3.  (5.1 m) (4.5 m) = 5.1 m x 4.5 m = 23.0 m²

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Related Questions

g The gas molecules in the internal combustion engine chamber are in a high state of random motion. When the molecules are expelled through an exhaust pipe in a more ordered state, what will their temperature be as their temperature in the chamber before being exhausted

Answers

Answer:

Explanation:

Entropy is the measure of randomness of a system . When heat is added to a gas , gas molecules become more random and therefore , their entropy increases . Hence at higher temperature , entropy increases and randomness increases due to addition of heat .

Hence when a gas molecules become more ordered that means entropy decreases . Hence heat is withdrawn from the system . Hence temperature of the system is decreases .

In the given case , gas molecules are made more ordered that means their temperature is decreased to lower the  entropy before they are exhausted .

45. Assume that 0.504 g of H₂ gas at STP reacts with
excess CuO according to the following equation:
Cuo(s) + H₂(g) → Cu(s) + H₂O(g)
Make sure the equation is balanced before beginning
your calculations.
a. How many liters of H₂ react?
b. How many moles of Cu are produced?
C. How many grams of Cu are produced?

Answers

The balanced equation for the reaction is:

CuO(s) + H2(g) → Cu(s) + H2O(g)

a. To find the volume of H2 gas at STP, we can use the ideal gas law:

PV = nRT

At STP, the pressure (P) is 1 atm and the temperature (T) is 273 K. The volume (V) of 1 mole of gas at STP is 22.4 L. So, the number of moles (n) of H2 gas is:

n = PV/RT = (1 atm) x V/(0.0821 L·atm/mol·K x 273 K) = V/22.4

We know that 0.504 g of H2 gas reacts. The molar mass of H2 is 2 g/mol. So, the number of moles of H2 gas is:

n = m/M = 0.504 g/2 g/mol = 0.252 mol

Now we can find the volume of H2 gas:

V = n x 22.4 L/mol = 0.252 mol x 22.4 L/mol = 5.65 L

Therefore, 5.65 liters of H2 gas react.

b. From the balanced equation, we can see that the mole ratio of CuO to Cu is 1:1. So, the number of moles of Cu produced is also 0.252 mol.

c. To find the mass of Cu produced, we can use the molar mass of Cu, which is 63.5 g/mol:

mass of Cu = number of moles of Cu x molar mass of Cu
= 0.252 mol x 63.5 g/mol
= 16.02 g

Therefore, 16.02 grams of Cu are produced.

intermolecular forces between particles are​

Answers

Explanation:

Intermolecular forces hold multiple molecules together and determine many of a substance's properties. All of the attractive forces between neutral atoms and molecules are known as van der Waals forces, although they are usually referred to more informally as intermolecular attraction.

Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules, or ions ). These forces are weak compared to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.

Which of the following is not a derived unit?

A) g/ml

B) liter

C) kg

D) All of these are derived.

Answers

B. Liter is the answer

You pour some hot water into a metal cup. After a minute,
you notice that the handle of the cup has become hot.
Explain, using your knowledge of heat transfer, why the
handle of the cup heats up. How would you design the cup so
that the handle does not heat up?

Answers

Heat transfer is the movement of thermal energy from a temperature that is higher to one that is lower.

Thermoenergy: What is it?

The energy that exists in a system and controls its temperature is known as thermal energy. Heat is thermal energy in motion. Thermodynamics is a comprehensive field of physics that examines how heat and work are transferred between diverse systems.

Energy of what kind is thermal energy?

The energy that results from atoms and molecules moving around within a substance is known as thermal energy, often known as heat. When these particles move more quickly, heat is produced. Geothermal energy is the earth's heat energy. Energy held within motion is referred to as motion energy.

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6. What is the limiting reagent when 0.50 mol of Cr and 1.0 mol of H3PO4 react according to the following chemical equation?
2Cr + 2H3PO4 → 2CrPO4 + 3H2

If 0.20 mol of CrPO4 is recovered from the reaction described above, what is the percent yield?

Answers

I did it in two different ways hope it is clear :)
6. What is the limiting reagent when 0.50 mol of Cr and 1.0 mol of H3PO4 react according to the following

The pressure of a 1.7379 mol sample of Ne in a 92.202 L container is measured to be 1.4948 atm. What is the temperature of this gas in kelvins?

Answers

The temperature of a 1.7379 mole of a gas with a pressure of 1.4948 atm and volume of 92.202 L is 965.69K .

How to calculate temperature?

The temperature of a given gas can be calculated using the ideal gas law equation:

PV = nRT

Where;

P = pressure = 1.4948atmV = volume = 92.202LR = gas law constant = 0.0821 Latm/molKn = number of moles = 1.7379molT = temperature

1.4948 × 92.202 = 1.7379 × 0.0821 × T

137.82 = 0.142T

T = 137.82 ÷ 0.142

T = 965.69K

Therefore, the temperature of a 1.7379 mole of a gas with a pressure of 1.4948 atm and volume of 92.202 L is 965.69K.

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As you move from left to right in the third period of the periodic table…
A. Each group loses an outer electron
B. Each group gains an outer electron
C. Each group gains a neutron
D. The number of outer electrons remains constant across the period

Answers

Answer:

B

Explanation:

2.8.1 Na

2.8.2 Mg

and so on and so forth

The atomic number tells the number of

Answers

The atomic number refers to tell if the number has the amount of protons for a nucleus in an atom. This is shown that the chemical effects of an element has in its singular form in the periodic table

What volume of a 0.124 M KOH solution neutralizes 23.4 mL of 0.206 M HCl solution?
A) 15.9 mL
B) 38.9 mL
C) 31.8 mL
D) 1.00 × 104 mL
E) 5.00 × 102 mL

Answers

A) 15.9 mL I hope it is if not I’m sorry

The volume of KOH required for the neutralization of acid has been 38.9 ml. Thus, option B is correct.

Neutralization reaction has resulted in the formation of salt and water with the reaction of acid and base.

In the neutralization reaction, the strength of the acid and base can be given by:

Molarity of acid \(\times\) Volume of acid = Molarity of base \(\times\) Volume of base

Given, the molarity of KOH base = 0.124 M

The volume of acid (HCl) = 23.4 ml

Molarity of acid (HCl) = 0.206 M.

Substituting the values:

0.206 \(\times\) 23.4 = 0.124 × Volume of base (KOH)

Volume of base (KOH) = 38.874 ml.

Volume of KOH = 38.9 ml

The volume of KOH required for the neutralization of acid has been 38.9 ml. Thus, option B is correct.

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can u pls help me with this question ​

can u pls help me with this question

Answers

i think its volume but im not 100% sure

Answer:

D.

Explanation:

cuz liter is volume

Identify the acid, base, conjugate acid and conjugate base in the following reactions:
a. NH_3(aq) + CH_3COOH(aq) NH_4^+ (aq) + CH_3COO^-(aq)
b. HClO_4(aq) + NH_4(aq) ClO_4^- (aq) + NH_4^+ (aq)

Answers

Answer:

a. NH₃ : base

CH₃COOH (acetic acid) : acid

NH₄⁺ : conjugate acid

CH₃COO⁻ : conjugate base

b. HClO₄ (perchloric acid) : acid

NH₃ : base

ClO₄⁻ : conjugate base

NH₄⁺ : conjugate acid

Hope this helps.

In each of the following equations identify the acid and base for the reactants

In each of the following equations identify the acid and base for the reactants

Answers

Answer:The oxygen is coming from the atmosphere.

Explanation:

Which statement comparing ionic bonds and covalent bonds is correct?

Answers

Covalent bonds tend to be less polar than ionic bonds, which is an accurate way to compare the two types of bonds.

How are ionic and covalent bonding compared?

An atom can participate in covalent and ionic bonds, which are the two main types of bonds. By sharing electrons, two or more atoms can form covalent bonds. When two or more ions come together, their opposing charges hold them together to form ionic bonds.

What is true regarding covalent bonding according to the following statements?

Response and Justification: The right answer is (a). Covalent bonds are formed when the orbitals of two atoms overlap. Because the sharing of electrons creates covalent bonds.

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Which of the following statements is correct about covalent bonding?

The typical dosage of statin drugs for the treatment of high cholesterol is 10 mg. Assuming a total blood volume of 4.5 L, calculate the concentration of drug in the blood in units of % (w/v)

Answers

Answer:

1.904 ppm

Explanation:

Concentration of drug in units of ppm = mass of solute / (mass of solution ) × 1000000

mass of blood = density of blood × volume = 1.05 g / ml × 5000 ml = 5250  g

mass of solution = mass of blood + mass of solute ( statin) = 5250 + 0.01 g  = 5250.01 g

Concentration of drug in units of ppm = (0.01 g / 5250.01 g) × 1000000 = 1.904 ppm

I hope this helps!!

Write the balanced equation showing the decomposition of carbonic acid and sulfurous acid.

Answers

Explanation:

here's the answer to your question

Write the balanced equation showing the decomposition of carbonic acid and sulfurous acid.

Decomposition of Sulfurous Acid (H₂SO₃):

H₂SO₃ → H₂O + SO₂

In this reaction, sulfurous acid decomposes into water (H₂O) and sulfur dioxide (SO₂).

The decomposition of carbonic acid (H₂CO₃) and sulfurous acid (H₂SO₃) can be represented by the following balanced chemical equations:

Decomposition of Carbonic Acid (H₂CO₃):

H₂CO₃ → H₂O + CO₂

In this reaction, carbonic acid decomposes into water (H₂O) and carbon dioxide (CO₂).

Decomposition of Sulfurous Acid (H₂SO₃):

H₂SO₃ → H₂O + SO₂

In this reaction, sulfurous acid decomposes into water (H₂O) and sulfur dioxide (SO₂).

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: Tell me about the best science experience you've ever had in your entire life in any science class

Answers

Answer:

Well, considering it's asking about a personal experience you should answer it but ill answer using one of mine.

Explanation:

TW: I AM TALKING ABOUT HUMAN ORGANS AND SEX

During my 7th-grade science class, we were talking/learning about male and female reproductive systems. One day going into class my teacher was standing over a big black bag and something was in it. Everyone was confused but we all sat down, my teacher explained that she has canceled our test. Everyone was happy including me, but she explained that if everyone could say what everything was called and where it was located we would get an A. At that moment she pulled the Black trash bag away and what was under the bag was 2 reproductive organs a Male and a Female one. Most of the girls started gagging and hid under the table (scared it was going to chase them or something) all the guys seemed so amazed. Anyways the weirdest part was when we were touching and saying what is what and what each thing does (with gloves on) one of the dudes thought it would be an amazing idea if he took the penis and put it inside of the uterus. (representing sex)  Everyone was disgusted but my teacher said that in most situations that would be disrespectful but in this case she allowed it, and for the rest of the lesson she talked about how the baby forms and why we should have sex until we are 18.

That is my weird/ best science experience ive ever had.

Physical methods of monitoring the rate of a chemical reaction

Answers

There are several physical methods that can be used to monitor the rate of a chemical reaction are; Spectrophotometry, Conductometry, and Turbidity measurement

Spectrophotometry involves measuring the changes in the intensity of light absorbed or transmitted by a solution during a chemical reaction. Spectrophotometers are used to measure the amount of light absorbed or transmitted by a sample at different wavelengths.

Conductometry  involves measuring the changes in electrical conductivity of a solution during a chemical reaction. Conductivity meters are used to measure the electrical conductivity of a solution, which can change as the concentration of ions in the solution changes during a chemical reaction.

Turbidity measurement involves measuring the changes in the clarity or turbidity of a solution during a chemical reaction. Turbidimeters or nephelometers can be used to measure the amount of light scattered by a sample, which can change as particles form or dissolve during a reaction.

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--The given question is incomplete, the complete question is

"What are the physical methods of monitoring the rate of a chemical reaction?"--

All alkali metals react with water to produce hydrogen gas and the corresponding alkali metal hydroxide. A typical reaction is that between lithium and water: 2Li(s) + 2H2O(1) 2LiOH(aq) + H2(g) How many grams of Li are needed to produce 9.89 g of H₂ ?

Answers

Answer:

69.23g

Explanation:

Find out how many moles is in 9.89g of H2.

number of moles = mass(g) / molar mass

1 is the molar mass of hydrogen (to the nearest whole)

relative molecular mass of H2: 2*1 = 2

number of moles of H2 = 9.89/2 = 4.945

1 mol of H2 is produced from 2 mol of Li

so

4.945 mol of H2 produces 9.89 mol of Li

mass(g) = number of moles * molar mass

7 is the molar mass of Lithium (to the nearest whole)

mass = 9.89 * 7 = 69.23

69.23 grams of Li are needed to produce 9.89 of H2

if 0.75 g of gas at 40 atm of pressure dissolves in 1.25 l of water at 25°c, how much will dissolve in 2.0 l of water at 3.0 atm of pressure and the same temperature

Answers

This is a problem about the solubility of a gas in a liquid, which is affected by pressure, temperature, and other factors. The solubility of a gas in a liquid is usually measured in terms of its mole fraction, which is the ratio of the number of moles of gas to the total number of moles (gas plus liquid).

In this case, we can use Henry's law, which states that the mole fraction of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. Mathematically, we can write:

x = k * P

where x is the mole fraction of the gas in the liquid, P is the partial pressure of the gas above the liquid, and k is the proportionality constant, which depends on the gas and the liquid.

To solve this problem, we need to use the given information to find the value of k, and then use Henry's law to find the mole fraction of gas in the second solution.

First, we can use the given information to find the value of k:

x = k * P

0.75 g of gas at 40 atm of pressure dissolves in 1.25 l of water, which has a density of about 1 g/cm^3 at 25°C. The molar mass of the gas is not given, but we can assume that it is a simple gas such as nitrogen, oxygen, or carbon dioxide, which have molar masses of about 28 g/mol, 32 g/mol, and 44 g/mol, respectively. Let's assume that the gas is nitrogen, which has a molar mass of 28 g/mol. Then, the number of moles of gas dissolved in the water is:

n = m / M = 0.75 g / 28 g/mol ≈ 0.0268 mol

The total number of moles in the solution is equal to the number of moles of gas plus the number of moles of water:

n_total = n_gas + n_water

n_total = n_gas + V_water / M_water

where V_water is the volume of water and M_water is the molar mass of water (18 g/mol).

Since the density of water is about 1 g/cm^3, we can convert the volume of water from liters to cubic centimeters:

1.25 l = 1250 cm^3

Then, we can calculate the total number of moles in the solution:

n_total = 0.0268 mol + 1250 cm^3 / 1000 cm^3/mol

n_total ≈ 0.048 mol

The mole fraction of the gas in the solution is equal to the number of moles of gas divided by the total number of moles:

x = n_gas / n_total

x = 0.0268 mol / 0.048 mol

x ≈ 0.558

Now we can use Henry's law to find the mole fraction of gas in the second solution:

x = k * P

We want to find x when P = 3.0 atm and V_water = 2.0 L. Since the temperature is the same as in the first solution, we can assume that k has the same value as before.

k = x / P

k = 0.558 / 40 atm

k ≈ 0.014

x = k * P

x = 0.014 * 3.0 atm

x = 0.042

Therefore, the mole fraction of gas in the second solution is about 0.042. To find the number of moles of gas in the second solution, we can use the same formula as before:

n_gas = x * n_total

n_gas = 0.042 * 0.048 mol

n_gas ≈ 0.002 mol

Finally, we can convert the number of moles of gas to mass using the molar mass of nitrogen:

m_gas = n_gas * M_gas

m_gas = 0.002 mol * 28 g/mol

m_gas = 0.056 g

Therefore, approximately 0.056 g of gas will dissolve in 2.0 L of water at 3.0 atm of pressure and the same temperature.

Which of the following can form hydrogen-bonds?A. Acetic acidB. EthaneC. Formyl chloride, CHClO

Answers

The following molecule that can form hydrogen bonds is acetic acid (A)

Because it is a polar molecule, acetic acid is capable of forming hydrogen bonds with the water molecules in the environment. The hydrogen bonding (H-bonding) that exists between the molecules of acetic acid and water is the most powerful force that is responsible for determining the chemical and physical characteristics of the mixture. In its structure, acetic acid exhibits both a double oxygen-carbon bond as well as a hydrogen atom that is connected to an oxygen atom.

The oxygen atom that is part of the double bond in the acetic acid molecule has the potential to form a hydrogen bond with one of the hydrogen atoms in the water molecule. Two equivalent hydrogen bonds are known to cause acetic acid to form a cyclic dimer. Because of how stable the dimer is, it can even stay in the gas phase.

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Stamples of heterogeneous equilibria. FeO(s) + CO(g) = Fe(s) + CO₂(g) II. H₂(g) L₂(g) = 2HI(g) III. CO₂(g) + C(s) = 2CO(g) IV. N₂(g) 3H₂(g) + 2NH3(g) Identify I.​

Answers

An example of heterogeneous equilibrium is:

I. FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g)

What is heterogeneous equilibrium?

Heterogeneous equilibrium refers to an equilibrium state in a chemical reaction where the reactants and products exist in different physical states or phases. It occurs when substances in different phases, such as solids, liquids, and gases, are involved in a chemical reaction.

Considering the given equations:

The equation I: FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g) represents a heterogeneous equilibrium.

This is because the reactants and products involve different phases (solid and gas). FeO is a solid (s), CO is a gas (g), Fe is a solid (s), and CO₂ is a gas (g). The reaction involves the conversion of a solid and a gas to another solid and a gas, and the equilibrium is established between these different phases.

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calculate the amount of heat needed to melt 190 of solid octane (c8h18) and bring it to a temperature of 99.3. Be sure your answer has a unit symbol and the correct number of significant digits.

Answers

The amount of heat needed to melt 190 of solid octane  1,320,467 J

What is heat?

Generally, When two water molecules bond together, energy is released in the form of a hydrophobic interaction.

This energy is released because the oxygen atom of one molecule is attracted to the hydrogen atoms of the other molecule, forming a strong hydrogen bond between the two molecules.

This attraction releases energy, which can be used to power biochemical reactions.

To calculate the amount of heat needed to melt 190g of solid octane (C8H18) and bring it to a temperature of 99.3°C, I used the following equation:

Q = m x ΔT x Cp.

Q is the amount of heat needed, m is the mass, ΔT is the change in temperature, and Cp is the specific heat capacity of the material.

Using these values, the equation was solved as follows:

Q = 190g x (99.3°C - 0°C) x 1,096 J/g°C.

This gave a result of 1,320,467 J.

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A sample of ammonia, NH3, has a mass of 78.25 g. Calculate the number of ammonia molecules in the sample.
number of molecules:

Answers

There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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5 gallons to ? L
1gal = 3.785 L

Answers

A gallon is a common volume measurement unit for measuring liquids and occasionally dry things. 5 gallon is equal to 18.925 L.

Thus, The US liquid gallon, US dry gallon, and Imperial gallon are the three different sorts of gallons. To measure and store commodities like fuel, oil, milk, paint, and many other things, these three types are frequently employed.

The English Parliament created the gallon in 1696 to be used for measuring dry goods. After gaining independence, the US adopted the Winchester gallon, which is now known as the US dry gallon.

Both are now referred to as US liquid gallon and US dry gallon, respectively. On the other hand, the Imperial gallon was adopted by the British Empire in 1834.

Thus, A gallon is a common volume measurement unit for measuring liquids and occasionally dry things. 5 gallon is equal to 18.925 L.

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2 examples of metal’s catalytic reaction

Answers

Answer:

Example 1

palladium(II) nitrate,

Example 2

Metal catalysts such as Fe, Ni, Mo, and Co are routinely used in the manufacture of CNMs.

Explanation

The three metals used in catalytic converters — rhodium, platinum and palladium — are part of a category known as platinum group metals, or PGMs, which are known for their catalytic properties.

a 4mL sample of lead has a mass of 45.2 g/mL what is its density?

Answers

Answer:

11.3 g/cc

Explanation:

To determine the density of a 4 mL sample of lead, we need to divide its mass by its volume.

The mass of the sample is given as 45.2 g/mL, which means that the sample has a mass of 45.2 grams. The volume of the sample is given as 4 mL, which is equivalent to 4 cubic centimeters (cc).

We can use the formula for density, D = M/V, to calculate the density of the sample. Plugging in the values we have for mass (M) and volume (V), we get: D = 45.2 g / 4 cc = 11.3 g/cc.

Therefore, the density of the 4 mL sample of lead is 11.3 g/cc.

the density is 11.3 g

Draw structural formulas for the two primary amines with molecular formula C3H9N
-Draw one structure per sketcher. Add additional sketchers using the dropdown menu in the bottom right corner.
-Separate structures with + signs from the dropdown menu.

Answers

Draw the substituted ring structure in which the chlorine is attached to the ring.

The benzene structure contains only 6 carbons and 6 hydrogens. The ring is replaced where the chlorine is attached to the ring. Therefore, the hydrogen-1 on the benzene ring is replaced by an ethyl group, and another hydrogen on the benzene ring is replaced by a chlorine group. Concerning the chlorine bond, there are 3 possible structures grouped called ortho, meta, and para.

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Draw structural formulas for the two primary amines with molecular formula C3H9N-Draw one structure per

An empty container with a volume of 150.0 cm3 is weighed and found to have a mass of 72.5 g. The container is filled with a liquid and reweighed. The mass of the container and the liquid is 194.37 g. Determine the density of the liquid to the appropriate number of significant figures. (1 cm3 = 1 mL)

Answers

The density of the liquid is 0.8125 g/mL.

What is density?

Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density. For instance, while Earth has a density of 5.51 grams per cubic centimeter, water has a density of 1 gram per cubic centimeter. Another way to state density is in kilograms per cubic meter (in meter-kilogram-second or SI units). For instance, air weighs 1.2 pounds per cubic meter. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated. The mass of a body can easily be determined from its volume or vice versa using a density.

mass of liquid = (mass of container and liquid) - (mass of empty container)

mass of liquid = 194.37 g - 72.5 g = 121.87 g

The volume of the liquid is equal to the volume of the container, which is 150.0 ml. (1 cm3 = 1 mL)

The density of the liquid is the mass of the liquid divided by the volume of the liquid:

density = mass/volume

density = 121.87 g / 150.0 ml

density = 0.81 g/ml

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Balance the equation
Ca(s) + H3PO4(aq) ---->Ca3(PO4)2(s) + H2(g)

Answers

Answer: CO2x+O4H I don’t know if this is the right answer
Other Questions
Hallco runs a day shift and a night shift. No matter how many units are produced, the only production cost during a shift is a setup cost. It costs $8,000 to run the day shift and $4,500 to run the night shift. Demand for the next two days is as follows: day 1, 2,000; night 1, 3,000; day 2, 2,000; night 2, 3,000. It costs $1 per unit to hold a unit in inventory for a shift.Please formulate (do not solve) an IP that can be used by Hallco to determine a production schedule that minimizes the sum of setup and inventory costs. All demand must be met on time. Problem Description and Given InfoComplete a Java program that takes two numbers as the inputs, and computes and outputs the product of the two inputs.Here is an example of what the user should see when the program runs.Enter first number : 9Enter second number : 5The product is : 45Be sure to read and understand the code that you are given for this assignment below. You will be adding only three lines of code to complete this Java program. Add the required lines where indicated by the comments in the code you are given.The first line you will add will declare a variable named product of data type int.The second line you will add will compute the product of the two values that the user inputs, and then store this value in the variable named product.The third line you will add will print out the product for the user.Make no other changes to the code you are given for this assignment.When you are finished adding the required lines of code, be sure to Run and test your program before you Submit your program for the auto-grader to score. If the auto-grader does not give you all 100 points, then be sure to carefully read the auto-grader feedback. You can correct your code and re-run and test and re-submit as many times as you like before the due date. The score for your last submission will be recorded in the grade book.For the given inputs of 9 and 5, make sure that your program output looks exactly like the example above (including spelling, capitalization, punctuation, and spaces).import java.util.Scanner;public class ComputeProduct {public static void main(String[] args) {// declare and instantiate a Scanner object to collect user inputScanner scnr = new Scanner(System.in);// Collect the first number from the user.System.out.print("Enter first number : ");int firstNumber = scnr.nextInt();// Collect the second number from the user.System.out.print("Enter second number : ");int secondNumber = scnr.nextInt();// Below this comment: write a single Java statement to declare a variable named product of data type int.// Below this comment: write a single Java statement to compute the product of the two numbers inputted above,// and store the result in a variable named product.// Below this comment: write a single Java statement to display the product of the two input values.}} Below are the jersey numbers of 11 players randomly selected from a football team. Find the range, variance, and standard deviation for the given sample data. What do the results tell us?21 72 69 20 58 86 61 13 29 75 83Range-? (Round to one decimal place as needed.)Sample standard deviation(Round to one decimal place as needed.)Sample variance-?(Round to one decimal place as needed.)What do the results tell us?OA Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.B. The sample standard deviation is too large in comparison to the range.OC. Jersey numbers on a football team vary much more than expected.OD. Jersey numbers on a football team do not vary as much as expected. Radius R. Central Angle 027 meters. 2/3 radiansFind the length of the arc on a circle of radius r intercepted by a central 0. 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Industries had the following balances: Accounts Receivable, $5,000; Accounts Payable, $6,000; Inventory, $3,000; and Unexpired Insurance, $2,000. The corporation reported net income of $79,000 for the year, including depreciation expense of $5,000, and uses the indirect method of computing net cash flow from operating activities. Based on this information, net cash flow from operating activities is a. $78,000 b. $77,000 c. $70,000 d. $82,000