Answer:
A hydraulic press works on the principle of Pascal's law, which states that when pressure is applied to a confined fluid, the pressure change occurs throughout the entire fluid. Within the hydraulic press, there is a piston that works as a pump, that provides a modest mechanical force to a small area of the sample.
Explanation:
Two horses have hooves of about the same area. Horse A has a much bigger mass than horse B. How would the pressure that they produce on the ground be different?
The pressure will be different because of the difference in the masses of horse A and horse B.
Horse A will have greater pressure due to much bigger mass.
Who do horses have hooves?In order for a horse to survive and operate, its hooves are necessary. Throughout a horse's lifetime, its hooves expand. Each foot of a horse has a single, solid hoof. The size of this might vary according on the breed, size, and running and jumping prowess of the horse.
Scholars have long disagreed on how animals—whose predecessors were dog-sized creatures with three or four toes—came to have only one hoof. According to a recent research, when horses grew bigger, one big toe was shown to be more resistant to bone stress than several smaller toes.
Thus, horse A will have greater pressure due to much bigger mass.
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9. A driver, driving a Bugatti Veyron, accelerates at 26.7 m/s² for 2.4 seconds. What change in
velocity did the driver experience?
The change in velocity experience by a driver, driving a Bugatti Veyron, accelerating at 26.7 m/s² for 2.4 seconds is 64.08 m/s.
What is chnage in velocity?Change in velocity is the difference between the final and the initial velocity of a body.
To calculate the change in velocity experienced by the driver, we use the formula below.
Formula:
Δv = at........... Equation 1Where:
Δv = Change in velocitya = Accelerationt = Time.From the question,
Given:
a = 26.7 m/s²t = 2.4 secondsSubstitute these values above into equation 1
Δv = 26.7×2.4Δv = 64.08 m/s.Hence, the change in velocity experienced by the driver is 64.08 m/s.
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if a piece of steel and a piece of aluminum of the same volume are dropped into water, what can be said about the buoyant force acting on each of them?
Water is incompressible, thus its density, stickiness, and other qualities essentially stay the same as you go deeper. As a result, the buoyant force also doesn't change.
What is buoyant force?Buoyant force is defined as the upward force applied to an object that is partially or completely submerged in liquids. The fluid's pressure on the object is what creates the buoyant force.
The object will rise to the surface and float if the buoyant force is greater than its weight. If the buoyant force is less than the object's weight, the object will sink. The object will remain hung at that depth if the buoyant force is equal to the weight of the object.
Thus, water is incompressible, thus as you travel deeper, its density, stickiness, and other characteristics essentially remain the same. Consequently, the buoyant force also remains constant.
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what is velocity ratio?
Explanation:
⚡⚡WHO WANTED TO PLAY⚡⚡
__❎ NO SEX ❎ NO FLIRT❎__
⬇️⬇️⬇️⬇️Z000MM⬇️⬇️⬇️⬇️
373 629 9840
444000
Answer:
the ratio of a distance through which any part of a machine moves to that which the driving part moves during the same time.
Explanation:
Both a 50-kg sack is lifted 2 meters from the ground and a 25-kg sack is lifted 4 meters in the same time. The power expended in raising the 50-kg sack is
The same.
for 50 kg sack
P1 = mgh / t = 50 * 2 g /t = 100 g/t
for 25 kg sack
P2 = 25 * 4 g/t = 100 g/t
11. PE = mg h = 8* 9.8* 12 = 940.8 J
12. Workdone = Fd = 45 * 2 = 90 J
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The power expended in raising the 50-kg sack is 90 J when both a 50-kg sack is lifted 2 meters from the ground and a 25-kg sack is lifted 4 meters in the same time.
How to calculate power?for 50 kg sack
P1 = mgh / t
= 50 * 2 g /t
= 100 g/t
for 25 kg sack
P2 = 25 * 4 g/t
= 100 g/t
PE = mg h
= 8* 9.8* 12
= 940.8 J
Workdone = Fd
= 45 * 2
= 90 J
What is power?Power is the quantity of energy that is transported or transformed per unit of time in physics. The watt, which is equal to one joule per second in the International System of Units, is the unit of power. Power may also be referred to as activity in earlier writings. A scalar concept is power.To know more about power visit:
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Cómo están relacionadas la energía y materia en la química?
Answer:
La materia y energía interactúa entre sí de forma continua. De hecho, la materia estaría en un estado estático de forma estable si no fuera por la energía. De esta forma, materia y energía están interactuando entre sí constantemente, donde la materia sería el sujeto pasivo que padece la acción de la energía, mientras que la energía sería el sujeto activo que modificaría el estado de reposo o movimiento de la materia.
Explanation:
An astronaut in training is seated at the end of a horizontal arm 8 meters long. How many revolutions per second must the arm make for the astronaut to experience a horizontal acceleration of 4.0g
Answer:
a = v^2 / R where a is the centripetal acceleration and R the radius
v = 2 π R N / t where (N / t) is the revolutions / sec giving distance / time
a = 4 g horizontal acceleration
4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2
(N / t)^2 = g / (π^2 * R)
N / t = 1 / π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2 = .352 / sec
The magnitude of the resultant of two vectors of magnitude 3 units and 4 units is 5 units. What is the angle between two vectors?
Explanation:
Using Cosine rule, we have 5² = 3² + 4² - 2(3)(4)(cosx).
=> cosx = 0, x = 90°.
(7\%) Problem 12: Although the transmission of light, and electromagnetic radiation generally, is correctly described by wave (physical) optics, there are situations for which ray (geometric) optics gives a sufficiently good approximation. For each of the situations described in the following, determine whether ray optics may be used or wave optics must be used. A
50%
Part (a) Green laser light of wavelength
560 nm
is incident on a 31 -cm diameter mirror. a
50%
Part (b) Red laser light of wavelength
702 nm
is incident on a molecule of size
102 nm
For part (a), ray optics may be used to analyze the reflection of green laser light of wavelength 560 nm incident on a 31-cm diameter mirror and for part (b), wave optics must be used to analyze the interaction of red laser light of wavelength 702 nm with a molecule of size 102 nm.
The situation described in part (a) can be analyzed using ray (geometric) optics because the mirror is much larger than the wavelength of the incident light. When the mirror diameter is much larger than the wavelength of light, then ray optics can be used to describe the reflection of light. The situation described in part (b) requires the use of wave (physical) optics because the size of the molecule is much smaller than the wavelength of the incident light.
When the size of the object is smaller than the wavelength of the incident light, then wave optics must be used to analyze the interaction of light with the object. In this case, the mirror's diameter is significantly larger than the wavelength of the light (31 cm vs. 560 nm). This means that the light can be treated as a ray, and ray optics can be used as a sufficiently good approximation.
Red laser light of wavelength 702 nm is incident on a molecule of size 102 nm. In this situation, the size of the molecule is comparable to the wavelength of the light (102 nm vs. 702 nm). In such cases, wave effects become significant, and we must use wave optics to accurately describe the interaction between the light and the molecule.
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Question 21 of 25
Barry slides across an icy pond. The coefficient of kinetic friction between his
shoes and the ice is 0.15. If his mass is 83 kg, what is the force of friction
acting on him
O A 352 N
O B. 122 N
C. 1150 N
O D. 813N
Answer:
B. 122N
Explanation:
f = 0.15 x 83 x 9.8 = 122.01
f = 122N
Assuming the Pressure Gradient Force is the same in both a trough and a ridge, the trough will have the faster winds. True False
False
The Pressure Gradient Force (PGF) is the force that drives air from areas of high pressure to areas of low pressure. In both a trough and a ridge, the PGF is the same.
However, the winds will not be the same in both features.
In a trough, the winds tend to move towards the center of the trough, where the air is rising, and this causes convergence and lifting. This upward motion causes a decrease in pressure, leading to a steeper pressure gradient, which means stronger winds. On the other hand, in a ridge, the winds move away from the center of the ridge, where the air is sinking, and this causes divergence and sinking. This sinking motion causes an increase in pressure, leading to a weaker pressure gradient and lighter winds.
Therefore, assuming the same PGF, the trough will have the faster winds compared to the ridge.
Which one is electrolyte - salt or sugar? Give reasons.
Answer:
Sugar ofc.
Explanation:
Have you seen energy drinks such as gatorade? Electrolytes
Answer:
An electrolyte solution contains water, salt, potassium and sugar in the proper concentration. The salt and sugar also have an added benefit of helping the body absorb the water - it turns out we absorb water with a little salt and sugar much better than we do plain water.
Explanation:
The density of an object can be found using
(A) Pascal's Law
(B)Hooke's Law
(C)Archimedes' Principle
(D)Principle of floatation
when the lobes of two p orbitals are in the same phase and overlap side-by-side, the orbital that is formed has a _____ dissociation energy compared to the σ∗ molecular orbital formed from the out-of-phase direct overlap of the two p orbitals.
when the lobes of two p orbitals are in the same phase and overlap side-by-side, the orbital that is formed has a bonding dissociation energy compared to the σ∗ molecular orbital formed from the out-of-phase direct overlap of the two p orbitals.
What scientific theory describes how covalent bonds develop when specific elements' valence orbitals overlap?Bonding arise when two unique atomic orbitals on different atoms cross across, generating an area where the two atoms share one pair of electrons, according to the theory of valence bonds. When orbitals intersect over an axis containing nuclei, a bond is formed.
A covalent bond is formed by two atoms that share a pair of electrons. The atoms are held together because the electron pair is pulled to both nuclei.
When two atoms exchange one or more pairs of electrons, a covalent connection is established.
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Help meeee
Cody is riding the Super Duper Drop at Six Flags. The ride drops him and he free falls
for 2.6 seconds.
a) What will be his final velocity at the end of the 2.6 seconds?
His final velocity at the end of the 2.6 seconds will be 25.48 m/s
given
time = 2.6 seconds
initial velocity = u = 0
acceleration = acceleration due to gravity = 9.8 \(m/s^{2}\) (since , it is a free fall )
final velocity = ?
using kinematics equation
v = u + at
v = u - g*t
v = - 9.8 * 2.6 = - 25.48 m/s
His final velocity at the end of the 2.6 seconds will be 25.48 m/s in downward direction
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If the car speeds up at a steady 1. 7 m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?.
The centripetal acceleration is equal to the tangential acceleration after: t = time taken by the car to reach 10.29 m/s = v / a = 10.29 / 1.7 ≈ 6.05 sec. Answer: 6.05 sec
The centripetal acceleration is given as,ac = v²/r .........(1)
And the tangential acceleration is given as,
at = a .............(2)Given that, ac = at
We know that at = a .............(2)ac = v²/r
Putting the value of ac and at, we getv²/r = a
Solving for v, we get
v = sqrt(ar)Now, we know that acceleration a = 1.7 m/s², and r = 70 m (given in the previous question)
So, putting the values of a and r in the above equation, we get
v = sqrt(1.7 x 70) = 10.29 m/s
We can find the time t from the first equation using the value of v.We know that ac = v²/r, and putting the values, we get
ac = (10.29)²/70ac = 1.4989 m/s²
The tangential acceleration is given as at = 1.7 m/s² (from equation 2)
Therefore, the centripetal acceleration is equal to the tangential acceleration after:t = time is taken by the car to reach 10.29 m/s = v / a = 10.29 / 1.7 ≈ 6.05 sec. Answer: 6.05 sec
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The density of radiation in the very early universe is more sensitive to the scale factor, R, than the density of matter. Write down the dependence for the density of radiation with R, and explain why it differs from that of matter.
The density of radiation in the early universe is inversely proportional to the fourth power of the scale factor, R. This means that as R increases, the density of radiation decreases rapidly. On the other hand, the density of matter is proportional to the cube of the scale factor, R.
The reason for this difference lies in the nature of radiation and matter. Radiation is made up of particles that travel at the speed of light and have high energy levels. As the universe expands, the wavelength of radiation also increases, which means that its energy decreases. Therefore, the number of photons in a given volume of space decreases as the universe expands, leading to a decrease in the density of radiation.
In contrast, matter particles do not travel at the speed of light and are not affected by the expansion of the universe in the same way as radiation. As the universe expands, the volume of space increases, leading to a decrease in the density of matter. However, the decrease is not as rapid as in the case of radiation because matter particles do not lose energy due to expansion.
In summary, the density of radiation in the early universe is more sensitive to the scale factor, R, than the density of matter because of the nature of radiation and its high energy levels.
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Choose a sport you like, such as football or gymnastics. Describe how a high level of flexibility would affect your performance in that sport. Consider the benefits in many aspects of the sport.
The level of flexibility will affect my performances in football. Football
requires some level of flexibility to do certain things.
Flexibility will enable me change speed and direction easily when there is a
counter attack by the opponents. It will also assist in using some techniques
such as adding more curve on the football with the feet in order to score
goals.
Flexibility will also ensure that there will be lesser injury concerns because there will be less sprains or other muscle related injuries.
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how much force is needed to accelerate a 48 kg object to 3 m/s²
Answer:
144 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 48 × 3
We have the final answer as
144 NHope this helps you
Calculate the current through the resistor in the circuit shown below.
Answer:
0.6amp or I= 0.6
Explanation:
V=IR
12V=I(20)
12/20=I
0.6=I
Answer:
0.6amp
Explanation:
can somebody helppp me pls thank you:)))))
HEY HEY HEY HEY
Explanation:
HEY HEY HEY HEY HEY
FILL THE BLANK. the ________________ cortex receives most of its input from the thalamic relay nuclei of a given sensory system.
The term you're looking for is "primary sensory cortex." The primary sensory cortex receives most of its input from the thalamic relay nuclei of a given sensory system.
The primary sensory cortex, often referred to as the primary somatosensory cortex or primary visual/auditory cortex, is a portion of the brain that collects and interprets sensory data from numerous body regions. For somatosensory processing, it is situated in the parietal lobe, for visual processing in the occipital lobe, and for auditory processing in the temporal lobe. The perception and interpretation of sensory stimuli like touch, pressure, pain, visual input, and aural signals are fundamentally influenced by the primary sensory cortex. It is in charge of encoding and organising sensory data, which enables us to experience and comprehend the outside world.
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How is Heat Transfer different from Thermal Energy Transfer
Answer:
ExplaHeat can travel from one place to another in three ways: Conduction, Convection and Radiation. ... Thermal energy is transferred from hot places to cold places by convection. Convection occurs when warmer areas of a liquid or gas rise to cooler areas in the liquid or gas.nation:
11. the square of the speed of an object undergoing a uniform acceleration a is some function of a and the displacement s, according to the expression given by
v^2 = k am sn,
where k is a dimensionless constant.
we have to tell the whether it is dimensional or dimensionless
v = m/sec dimesions
a = m/sec^2 dimesion, m = m
v^2 = m^2 / sec^2 = k m/sec^2 * m
k = dimesionless constant.
Dimension is a measurable extent, such as the three principal dimensions of an object of width, height, and depthdimension is of many types radial, angular, linear etc.Reference Dimensions is a Dimension without a tolerance, used for information purposes only. A reference is a repeat of a given dimension or established from other values one dimension is practically not found.To know more about Dimension visit : https://brainly.com/question/1374629
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A certain first order reaction between two gases
occurs at 389 K with a half-life of 24 hours. How
much time is required to drop the pressure of one of
the gases from 2.0 atm to 0.25 atm at 389 K?
A) 8 hours B) 72 hours
C) 192 hours D) 288 hours
The time required to drop the pressure of one of the gases from 2.0 atm to 0.25 atm at 389 K is 288 hours, or Option (D).
For a first order reaction, the change in pressure of a gas is proportional to its initial concentration and to the rate constant of the reaction. The half-life of a first order reaction is defined as the time required for the concentration of a reactant to decrease to half its initial value.
The rate constant (k) of a first order reaction can be related to its half-life (t1/2) as follows:
k = 0.693 / t1/2
We can use this relationship to find the rate constant for our reaction:
k = 0.693 / 24 hours = 0.0289 h^-1
Next, we can use the rate constant to find the time required for the pressure of one of the gases to decrease from 2.0 atm to 0.25 atm:
P = P0 * e^(-kt)
ln(P/P0) = -kt
-t = ln(P/P0) / k
where P0 is the initial pressure, P is the final pressure, t is the time, and e is the base of natural logarithms.
Plugging in the values, we get:
-t = ln(0.25/2.0) / 0.0289 h^-1
t = 288 hours
Therefore, the time required to drop the pressure of one of the gases from 2.0 atm to 0.25 atm at 389 K is 288 hours, or Option D).
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momentum: a rubber ball and a lump of clay have equal mass. they are thrown with equal speed against a wall. the ball bounces back with nearly the same speed with which it hit. the clay sticks to the wall. which one of these objects experiences the greater momentum change? momentum: a rubber ball and a lump of clay have equal mass. they are thrown with equal speed against a wall. the ball bounces back with nearly the same speed with which it hit. the clay sticks to the wall. which one of these objects experiences the greater momentum change? the clay the ball both of them experience the same non-zero momentum change. both of them experience zero momentum change.
The ball has more momentum compared to clay because of its better movement.
The momentum change of every item is given through:
Δp=mΔv=m(v - u)
Each items have equal mass m and identical initial speed u. So we've got:
- For the ball, the very last pace is
v = -u
since it bounces lower back (so, opposite direction --> negative signal) with same speed (so, the magnitude of the final pace remains u). So the trade in momentum is
Δp = m(v - u) = m((-u) - u) = -2mu
The final velocity is
v = 0
Since it sticks to the wall. So, the change in momentum is
Δp = m(v - u) = m(0 - u) = -mu
So we see that the extra momentum change (in importance) is experienced with the aid of the ball.
Momentum refers to the property of an object that determines the amount of force required to change its motion. The law of conservation of momentum states that the total momentum of a closed system remains constant, provided there are no external forces acting on it.
An object with a higher momentum will be harder to stop or change direction than an object with a lower momentum. This is because a larger amount of force is required to overcome its existing motion. Momentum plays a crucial role in many aspects of physics, including mechanics, electromagnetism, and quantum mechanics. It is also important in everyday life, such as in sports, where the momentum of a ball can determine its trajectory and impact.
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Complete Question: -
A rubber ball and a lump of clay have equal mass. They are thrown with equal speed against a wall. The ball bounces back with nearly the same speed with which it hit. The clay sticks to the wall. Which one of these objects experiences the greater momentum change?
How will the force of friction affect a wood block being pushed over a table?
A. Friction acts in the direction of motion, speeding the block up.
B. Friction acts in the direction of motion and is included in the moving force.
C. Friction acts in the opposite direction of motion but does not affect the motion of the object.
D.Friction acts in the opposite direction of motion, slowing the block down.
Answer:
D
friction acts in the opposite direction of motion but does not affect the motion of the object
Answer:D.Friction acts in the opposite direction of motion, slowing the block down.
Explanation:
3. a). Using Newton's second law of motion, set up a model or ODE for the velocity as a function of time, v(t), for a falling body that is acted on by the force of gravity and air resistance. Determine the expression for v(t) assuming the air resistance is proportional to the square of the velocity, the ratio of the proportionality constant and the mass of the body is unity, and an initial velocity of 12 m/s when dropped. What would be the limiting velocity? b). The temperature of the cake from your oven was 300 ∘ F. Five minutes later, it was 200 ∘ F. Although you are hungry and cannot wait, you do not want to end up in the hospital with mouth burns. How long will it take the cake to cool off to a manageable warm temperature of 75 ∘ F for you to enjoy it if the room temperature is 70 ∘ F ?
a) The model for the velocity of a falling body with air resistance can be described using Newton's second law of motion. The equation can be written as:
m * dv/dt = mg - k * v^2
where m is the mass of the body, g is the acceleration due to gravity, k is the proportionality constant for air resistance, and v is the velocity of the body.
Assuming the ratio of k to m is unity, we can rewrite the equation as:
dv/dt = g - v^2
To solve this first-order ordinary differential equation, we can separate variables and integrate:
∫ 1/(g - v^2) dv = ∫ dt
After integration, we obtain:
atan(v/sqrt(g)) = t + C
Solving for v, we have:
v(t) = sqrt(g) * tan(t + C)
Given an initial velocity of 12 m/s, we can determine the value of C. Plugging in the values, we have:
12 = sqrt(g) * tan(C)
Now, we can solve for C using the given information.
b) To determine how long it will take for the cake to cool off to 75 °F, we can use Newton's law of cooling, which states that the rate of temperature change of an object is proportional to the difference between its temperature and the surrounding temperature. The equation can be written as:
dT/dt = -k(T - T_room)
where dT/dt is the rate of temperature change, T is the temperature of the cake, T_room is the room temperature, and k is the proportionality constant.
Separating variables and integrating, we get:
∫ 1/(T - T_room) dT = -k ∫ dt
After integration, we have:
ln|T - T_room| = -kt + C
Solving for T, we obtain:
T(t) = T_room + Ce^(-kt)
Given that the initial temperature is 300 °F and the desired temperature is 75 °F, we can determine the value of C. Plugging in the values, we have:
300 = 75 + Ce^0
Solving for C, we find:
C = 225
Now, we can determine the time it takes for the cake to cool to 75 °F by solving for t when T = 75 and plugging in the values.
Please note that the specific values of the proportionality constants and units are not provided in the question, so the final numerical results will depend on those values.
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A grinding wheel, initially at rest, is ro-tated with constant angular acceleration of2.52 rad/s2for 7.03 s. The wheel is thenbrought to rest with uniform deceleration in11.9 rev.Find the angular acceleration required tobring the wheel to rest. Note that an in-crease in angular velocity is consistent with apositive angular acceleration.Answer in units of rad/s2.
Starting from rest, the wheel accelerates to an angular velocity of
ω = (2.52 rad/s²) (7.03 s) ≈ 17.7 rad/s
then undergoes a new acceleration α until it comes to a rest. It does so in 11.9 revolutions, or with an angular displacement of (11.9 rev) • (2π rad/rev) = 23.8π rad. So α satisfies
0² - ω² = 2 α (23.8π rad)
α = - ω² / (47.6π rad)
α ≈ -2.10 rad/s²
How many ohms is the resistance of the electric heater connected to 220 V voltage
Answer:
44 ohms.
Explanation:
R for V (according to Ohm's law). This second formula is more frequently used in practice to calculate resistive heating, whereas the first formula has other, more general applications. As we might infer from the equation, the units of watts also correspond to amperes2 x ohms (A2 x Ω).