Answer:
We can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.
Position vectors are used to determine the starting position of a line with reference to the origin or starting point of the coordinate system
Position vectors start at the origin and terminate at any arbitrary point.
In terms of position of a line, position vectors depict the exact position of a line from the starting point of the coordinate system.
In terms of direction of the line, the direction of the position vector points from the starting point of the coordinate system towards the given point.
Thus, we can conclude that position vectors are used to determine the starting position of a line with reference to the origin or starting point of the coordinate system.
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1) Determine the magnitude of energy for each of the blanks on the diagram. Give the correct values for 1A, 1B, and 1C.
2)Explain how the energy transformations follow the Law of Conservation of energy throughout the skier's path. Must answer in complete sentences.
3)Explain how the situation shown above would be different if the skier experiences friction while traveling downhill. Include the terms kinetic energy, heat energy, mechanical energy, total energy and friction. Must answer in complete sentences.
Answer:
Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789
The total energy at each point in the path of the skier is constant as the
skier travels down the slope.
1) 1A P.E. = 15,000 J, 1B K.E. = 19,000 J, 1C, P.E. = 0 J2) The mechanical energy of the system is constant3) Energy is given off as heat due to friction such that the total energy of the system is not conserved if friction is experiencedReasons:
1) Given that the total mechanical energy, M.E. is constant, we have;
M.E. = Kinetic Energy, K.E. + Potential Energy, P.E. = Constant
M.E. = K.E. + P.E.
At the start, we have;
P.E. = 25,000 J
K.E. = 0 J
Therefore;
M.E. = 25,000 J + 0 J = 25,000 J
At point 1A, we have, K.E = 10,000 J
P.E. = M.E. - K.E.
Therefore;
P.E. = 25,000 - 10,000 = 15,000
The potential energy at point 1A, P.E. = 15,000 J
At point 1B, we have; PE = 6000 J
K.E. = M.E. - P.E.
Therefore;
K.E. = 25,000 J - 6,000 J = 19,000 J
At 1B, K.E. = 19,000 J
At point 1C, we have; K.E. = 25,000 J
Therefore;
P.E. = 25,000 J - 25,000 J = 0 J
At 1C P.E. = 0 J
2) The Law of Conservation of Energy states that the energy in a closed
system is constant.
The energy transformation follows the Law of Conservation of energy
given that the total mechanical energy is constant at all points along the
path.
3) The energy of a system is not conserved when a external force is
applied.
If the skier experiences friction, the force of friction does work to reduce
the speed of the skier, thereby reducing the kinetic energy at a point
downslope, where the potential energy has already been reduced,
resulting in an reduction in the mechanical energy of the system.
Therefore, if the skier experiences friction, the total energy of the system is
not conserved, as energy will be consumed in the work done by friction
which is converted to heat and sound energies.
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If you weigh 982 N on Earth, what would your weight be on the surface of Jupiter?
g = 9.8 m/s^2 on Earth's surface
g = 26.0 m/s^2 on Jupiter's surface
mass of the Earth is 6 x 1024 kg
mass of Jupiter is 1.9 x 1027 kg
radius of Earth is 6.4 x 106 m
radius of Jupiter is 7 x 107 m
Round your answer to the nearest whole number.
Mass is always the same. The magnitude of weight on the surface of Jupiter is 2605.3 N
What is Weight ?Weight can simply be defined as a gravitational pull on an object in space. It is the product of mass and acceleration due to gravity.
Given that;
g = 9.8 m/s^2 on Earth's surface
g = 26.0 m/s^2 on Jupiter's surface
mass of the Earth is 6 x 1024 kg
mass of Jupiter is 1.9 x 1027 kg
radius of Earth is 6.4 x 106 m
radius of Jupiter is 7 x 107 m
If you weigh 982 N on Earth, your mass can be calculated by using weight formula. That is,
W = mg
982 = 9.8m
m = 982/9.8
m = 100.2 Kg
The mass is always constant. Your weight on the surface of Jupiter can be calculated in the same way where g = 26.0 m/s^2 on Jupiter's surface
W = mg
W = 100.2 × 26
W = 2605.3 N
Therefore, your weight will be 2605.3 N on the surface of Jupiter.
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The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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Select all the correct locations on the image.
Which hot spots identify features in the image that can help lower the effects of urbanization?
Answer:
its the top 3 can confirm on plato
Explanation:
Answer:
plato
Explanation:
A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air. The potential at the outer conductor is 1.5 kV relative to the inner conductor. What is line charge density on the positively charged conductor
Answer:
The value is \(\rho_s = 4.026 *10^{-6} \ C/m^2\)
Explanation:
From the question we are told that
The radius of the inner conductor is \(r_1 = 1 \ mm = 0.001 \ m\)
The radius of the outer conductor is \(r_2 = 3 \ mm = 0.003 \ m\)
The potential at the outer conductor is \(V = 1.5 kV = 1.5 *10^{3} \ V\)
Generally the capacitance per length of the capacitor like set up of the two conductors is
\(C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}\)
Here \(\epsilon_o\) is the permitivity of free space with value \(\epsilon_o = 8.85*10^{-12} C/(V \cdot m)\)
=> \(C= \frac{2 * 3.142 * 8.85*10^{-12} }{ ln [\frac{0.003}{0.001} ]}\)
=> \(C= 50.6 *10^{-12} \ F/m\)
Generally given that the potential of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge
Generally the line charge density of the outer conductor is mathematically represented as
\(\rho_l = C * V\)
=> \(\rho_d = 50.6*10^{-12} * 1.5*10^{3}\)
=> \(\rho_d = 7.59*10^{-8} \ C/m\)
Generally the surface charge density is mathematically represented as
\(\rho_s = \frac{\rho_l }{2 \pi * r_2 }\) here \(2 \pi r = (circumference \ of \ outer \ conductor )\)
=> \(\rho_s = \frac{7.59 *10^{-8} }{2* 3.142 * 0.003 }\)
=> \(\rho_s = 4.026 *10^{-6} \ C/m^2\)
PLEASE HELP and show work, thank you !!
-The top speed of a Utahraptor is about 9 m/s. How long would it take a Utahraptor to run 1500 m if it accelerates from rest to 9 m/s? Assume acceleration is constant and it reaches its top speed at exactly 1500 m from its starting point.
Answer:
2.94 s
Explanation:
v = u + at
where:
v = final velocity = 9 m/s
u = initial velocity = 0 m/s (rest)
a = acceleration
t = time taken to reach final velocity
We can rearrange the equation to solve for time:
t = (v - u) / a
Substituting the given values, we get:
t = (9 m/s - 0 m/s) / a
Now, we need to find the acceleration. We can use another kinematic equation:
s = ut + (1/2)at^2
where:
s = displacement = 1500 m
u = initial velocity = 0 m/s
a = acceleration
t = time taken to cover the displacement
We can rearrange the equation to solve for acceleration:
a = 2(s - ut) / t^2
Substituting the given values, we get:
a = 2(1500 m - 0 m) / (1500 m / 9 m/s)^2
Simplifying, we get:
a = 3.06 m/s^2
Now, we can substitute this value of acceleration in the earlier equation to find the time taken:
t = (9 m/s - 0 m/s) / 3.06 m/s^2
Simplifying, we get:
t = 2.94 s
After coming down a slope, a 60-kg skier is coasting northward on a level, snowy surface at a constant 15 m>s. Her 5.0-kg cat, initially running southward at 3.8 m>s, leaps into her arms, and she catches it. (a) Determine the amount of kinetic energy converted to internal energy in the Earth reference frame. (b) What is the velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat’s kinetic energy does not change?
The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.
What is law of conservation of momentum?According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.
The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.
The amount of kinetic energy converted to internal energy can be calculated as follows:
m1*v1 = (m1 + m2)*vf
vf = (m1*v1)/(m1 + m2)
KE = (1/2)*m2*v2²
KE converted = KE initial - KE final
KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²
KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²
KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)
KE converted = 28.8 - 22.15
KE converted = 6.65 J
The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.
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Which of the following is NOT a human blood type?
a.
O
c.
B
b.
AB
d.
R
Answer:
d. R
Explanation:
There are 4 main types of blood – A, B, AB and O.
Blood is the most important component of our life. It is a fluid connective tissue which consists of plasma, blood cells and platelets. It circulates throughout the body and delivers oxygen. Among the given options R is not a blood type. The correct option is D.
What are blood types?It was Karl Landsteiner who discovered the ABO blood group system. There are 4 main blood groups, they are A, B, AB and O. Your blood group is determined by the genes you inherit from your parents. Each blood group may be either RhD positive or RhD negative.
Blood group A has antigens on the red blood cells with anti-B antibodies in the plasma. Blood group B has B antigens with anti-A antibodies in the plasma. The blood group O has no antigens but both antibodies are present whereas AB has no antibodies.
Group O is the universal donor and AB is universal recepient.
Thus the correct option is D.
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Which of the following describes glass?
Answer:
is there any choice? in this question?
Two balls are rolled off a tabletop that is 0.85 m above the floor. Ball A has a
horizontal velocity of 3.5 m/s and that of ball B is 5.3 m/s.
A) How long does it take each ball to reach the floor after it rolls off the edge?
B) How far does each ball travel horizontally before hitting the floor?
Hi there!
A)
Since the ball's velocity is initially only in the HORIZONTAL direction, there is NO vertical component of its velocity. Therefore, we can treat this like a free-fall scenario. (Dropped from rest).
We can rearrange the following kinematic equation to make solving for the time taken for the balls to hit the ground easier.
\(d_y = v_yt + \frac{1}{2}at^2\)
dy = vertical displacement (height of table, 0.85 m)
vy = initial vertical velocity (0 m/s, only horizontal)
a = acceleration (due to gravity in this situation, 9.8 m/s²)
t = time (? sec)
Simplify and rearrange the variables for 't'.
\(d_y = 0(t) + \frac{1}{2}at^2\\\\d_y = \frac{1}{2}at^2\\\\t^2 = \frac{2d_y}{a}\\\\t = \sqrt{\frac{2d_y}{a}}}\)
Plug in the given values.
\(t = \sqrt{\frac{2(0.85)}{9.8}} = \boxed{0.4165 s}\)
B)
Now, remember that the ball's acceleration in the vertical direction due to gravity does NOT impact its horizontal velocity. Its vertical and horizontal velocities are COMPLETELY independent. Thus, we can simply use the time solved for above and each ball's respective velocities in the following kinematic equation:
\(d_x = v_xt\)
dₓ= horizontal displacement (? m)
vₓ = horizontal component of velocity (3.5 and 5.3 m/s for A and B respectively)
t = time (0.4165 s)
Solve for the distance traveled by each ball:
Ball A:
\(d_x = 3.5 * 0.4165 = \boxed{1.458 m}\)
Ball B:
\(d_x = 5.3* 0.4165 = \boxed{2.207 m}\)
Secondary succession can happen after primary succession or independently of primary succession. Please select the best answer from the choices provided T F
Answer: ok
Explanation: “In primary succession, newly exposed or newly formed rock is colonized by living things for the first time. In secondary succession, an area that was previously occupied by living things is disturbed, then re-colonized following the disturbance.”-Khanacademy
I think basically, it is saying that you need primary succession in order to colonize and then you have secondary succession which re-colonizeses the area. It could be like a natural disaster, but secondary succession will rebuild back the ecosystem and may even bring good alterations in some scenarios.
I just took the test.
I put True.
I got it right.
Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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PLEASE ANSWER QUICK!!!!!!!!!!!!!!!!!!!!!!!!!!!
Like magnetic fields, electric fields are invisible. How did the experiment allow you to gather evidence that electric fields exist?
Answer: while electric fields aren’t visible or tangible, they are mensurable.
Explanation: you might want to attach the experiment notes to your question***
Answer: 13 miles.
Explanation:
Vector C is 6.28 m long in a105° direction. Vector D is3.09 m long in a 233º direction.Find the direction of theirvector sum.
Answer:
\(\theta_S=\tan ^{-1}(1.85)=61.6069\text{ Deg}\)Explanation: We need to find the resultant vector S that is the sum of the two vectors:
\(\begin{gathered} C=C_x+C_y\Rightarrow\lvert C\rvert=\sqrt[]{(C_x)^2+(C_y)^2}=6.28m \\ \theta_c=\tan ^{-1}(\frac{C_y}{C_x})=105^{\circ} \\ \text{ Likewise} \\ D=D_x+D_y\Rightarrow\lvert D\rvert=\sqrt[]{(D_x)^2+(D_y)^2}=3.09m \\ \theta_D=\tan ^{-1}(\frac{D_y}{D_x})=233^{\circ} \\ \text{ We need to find: } \\ \theta_S=\tan ^{-1}(\frac{S_y}{S_x})\rightarrow\text{ ?} \\ S_y\text{ }\rightarrow\text{?} \\ S_z\rightarrow? \\ \end{gathered}\)Next step is fairly easy, we just need to solve simultaneous equations, which will give us components of C D vectors, then finding the direction of vector sum would be the last step
\(\begin{gathered} C=C_x+C_y\Rightarrow\lvert C\rvert=\sqrt[]{(C_x)^2+(C_y)^2}=6.28m \\ \theta_c=\tan ^{-1}(\frac{C_y}{C_x})=105^{\circ}\rightarrow\frac{C_y}{C_x}=\tan (105^{\circ})\rightarrow C_y=C_x\tan (105^{\circ})=C_x4.03 \\ \therefore\rightarrow C_y=C_x4.03 \\ \text{ Now we can solve for the vector components from the above equation as:} \\ \sqrt[]{(C_x)^2+(C_y)^2}=6.28m\rightarrow\mleft(C_x\mright)^2+\mleft(C_y\mright)^2=(6.28m)^2 \\ (C_x)^2+(C_y)^2=(6.28m)^2\Rightarrow(C_x)^2(4.03)^2+(C_x)^2=(6.28m)^2 \\ (C_x)^2\lbrack(4.03)^2+1\rbrack=(6.28m)^2\rightarrow17.22(C_x)^2=39.44\rightarrow(C_x)^2=\frac{39.44}{17.22} \\ \therefore\rightarrow \\ C_x=\sqrt[]{\frac{39.44}{17.22}}=1.51m\rightarrow(1) \\ \therefore\rightarrow \\ (C_y)^2=(6.28m)^2-(C_x)^2=39.44m-1.51m=37.93m \\ C_y=\sqrt[]{37.93m}=6.16m\rightarrow(2) \\ \end{gathered}\)Similarly for D same thing as above is done, as shown next:
\(\begin{gathered} D=D_x+D_y\Rightarrow\lvert D\rvert=\sqrt[]{(D_x)^2+(D_y)^2}=3.09m \\ \theta_D=\tan ^{-1}(\frac{D_y}{D_x})=233^{\circ}\rightarrow\frac{D_y}{D_x}=\tan (233^{\circ}^{})\rightarrow D_y=D_x\tan (233^{\circ})=D_x0.58 \\ \therefore\rightarrow\text{ }D_y=D_x0.5 \\ \text{Now we can solve for the vector components from the above equation as:} \\ \sqrt[]{(D_x)^2+(D_y)^2}=3.09m\rightarrow(D_x)^2+(D_y)^2=(3.09m)^2 \\ (C_x)^2+(C_y)^2=(3.09m)^2\Rightarrow(D_x)^2(0.58)^2+(D_x)^2=(3.09m)^2 \\ \therefore\rightarrow \\ (D_x)^2\lbrack(0.58)^2+1\rbrack=(3.09m)^2\rightarrow1.34(D_x)^2=9.54\rightarrow(D_x)^2=\frac{9.54}{1.34} \\ \therefore\rightarrow \\ D_x=\sqrt[]{\frac{9.54}{1.34}}=2.67m\Rightarrow(3) \\ (D_y)^2=(3.09m)^2-(D_x)^2=9.55m-7.12m=2.43m \\ D_y=\sqrt[]{2.43m}=1.56m\Rightarrow(4) \end{gathered}\)Now the direction simply is:
\(\begin{gathered} \theta_S=\tan ^{-1}(\frac{S_y\text{ }}{S_x_{}})=\tan ^{-1}(\frac{D_y+C_y}{D_x+C_x})=\tan ^{-1}(\frac{1.56m_{}+6.16m_{}}{2.67_{}m+1.51m_{}})=\tan ^{-1}(\frac{7.72_{}}{4.18_{}})=\tan ^{-1}(1.85) \\ \theta_S=\tan ^{-1}(1.85) \end{gathered}\)The gravity tractor, is a proposed spacecraft that will fly close to an asteroid whose trajectory threatens to impact the Earth. Due to the gravitational attraction between the two objects and a prolonged period of time over which it acts (several years), the asteroid's trajectory is changed slightly, thus hopefully diverting it from impacting the Earth. If the gravity tractor's weight on Earth is 20,000 lbs and it flies with a center of gravity 160ft from the surface of the asteroid, and the asteroid is homogenous pure iron with 1290 ft diameter spherical shape, detirmine the force of mutual attraction. Idealize the gravity tractor to be a particle.
Answer:
\(F_g=461lb_f\)
Explanation:
First calculate the mass of the asteroid. To do so, you need to find the volume and know the density of iron.
If r = d/2 = 645ft, then:
\(V = \frac{4}{3} \pi r^3\)
\(V = \frac{4}{3} \pi r^3\\V = 1.124\times10^{9}ft^3\delta_{iron}=m/V=491lb/ft^3m=V\times\delta=5.519\times10^{11}lb\)
In order to find force, use Newton's universal law of gravitation:
\(F_g=G\frac{m_1m_2}{d^2}\)
Where,
G= the gravitational constant:
\(G= 1.068846 \times10^{-9} ft^3 lb^{-1} s^{-2}\)
\(F_g=461lb_f\)
A magazine rack has a center of gravity 16 cm above the floor, as shown in the figure below (Figure 1). Through what maximum angle, in degrees, can the rack be tilted without falling over?
The maximum angle that the magazine rack can be tilted without falling over depends on its centre of gravity, base width, and the surface it is resting on.
To determine the maximum angle, you can use the formula:
tan(angle) = (centre of gravity height) / (base width/2)
Plugging in the values given, we get:
tan(angle) = 16cm / (5cm/2) = 16cm / 2.5cm = 6.4
The inverse tangent function (tan^-1) can be used to find the angle in degrees:
angle = tan^-1(6.4) = 72.9 degrees
So the maximum angle that the magazine rack can be tilted without falling over is about 73 degrees.
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A proton moves north with a speed of 3 x 10^6 m/s. A 5 Tesla magnetic field is directed west. Determine the magnitude and direction of the magnetic field on the proton.
The magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.
Magnitude of magnetic force on the protonThe magnitude of magnitude force on the proton is calculated as follows;
F = qvB sinθ
where;
q is the charge of the protonv is the speed of the protonB is the magnitude of the magnetic filed θ is the angle between the field and speedSubstitute the given parameters and solve for the magnetic force.
F = (1.6 x 10⁻¹⁹) x (3 x 10⁶) x (5) X(sin90)
F = 2.4 x 10⁻¹² N
Thus, the magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.
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Which of the following diagrams shows the greatest magnitude net torque with a zero net force? All the rods, of length 2r, rotate about an axis that is perpendicular to the rod and fixed in the center of the rod. All the forces are of magnitude F or 2F and all distances from the axis are r or r/2.
The diagram that shows the greatest magnitude net torque with a zero net force is the diagram in second option.
option B is the correct answer.
What is net torque?
The net torque is the sum of the individual torques. The torque itself is obtained from the product of applied force and the perpendicular distance of the force.
In rotational equilibrium, there is no net torque on the object. There may be individual torques, but they add up to zero and cancel each other out.
Mathematically, the formula for torque is given as;
τ = Fr
where;
F is the applied forcer is the perpendicular distanceThe torque applied to an object increases with increase in the perpendicular distance.
To obtain a zero net force, sum of all the opposite forces applied to an object must be equal to zero.
The forces must be equal in magnitude but opposite in direction, and the diagram that meets this specification is the last graph.
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Three loads are applied attached at B and D. Neglecting the weight of the beam, determine the range of values of Q for which neither cable becomes slack when P = 0. as shown to a light beam supported by cables 7.5 kN Q P С E А В 1.5 m- 0.75 m 0.5 m 0.75 m Fig. P4.9
When\(P = 0, Q\)must be in the range between \(4.3 kN and 12.9 kN\) to prevent either cable from becoming slack.
We may examine the forces operating on the beam to find the range of values for Q. The sum of the vertical forces must be zero when \(P = 0,\)which indicates that the beam is in equilibrium. Our result is the equation:
\(Q + 7.5 - 3 - 4 = 0\)
When Q is solved for, we obtain \(Q = 0.5 kN to 12.9 kN.\) To prevent either wire from going slack, we must also ensure that both cables are under positive stress. We can accomplish this by searching for the extreme values of Q in each cable's tensions.
\(Q = 0.5 kN\)results in a positive 7.5 kN tension in cable AB. However, cable DE's tension is negative\((-2.5 kN)\), indicating that cable DE is under tension. is loose.
\(Q = 12.9 kN\) results in a positive \(3.4 kN\) tension in cable DE. Cable AB, however, has negative tension \((-5.4 kN),\) indicating that it is slack.
The range of Q values that satisfy the requirement that neither cable sags when \(P = 0 is 4.3 kN to 12.9 kN.\)
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You are a musician and want to know the frequency of a guitar string. You measure the length of the string to be 0.6 meters and the tension in the string to be 60 Newtons. If the mass of the string is 0.01 kg, what is the frequency of the string? (Units: frequency -hertz (Hz), length -meters (m), tension -newtons (N), mass -kilograms (kg))
Answer:
Explanation:
I frequency = 278 Hz
An electric iron is Mark 120 volts and 500 Watts to units consumed by it in using it for 24 hours will be
An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I
Using the above formula, we can find the current drawn by the electric iron as follows:I = P/VI = 500/120I = 4.17 ATherefore, the power consumed by the electric iron in 24 hours is:P = VI x tP = 120 x 4.17 x 24P = 120 x 100.08P = 12010.56 watt-hoursTo convert watt-hours to kilowatt-hours, we divide by 1000: Energy consumed = 12010.56 / 1000Energy consumed = 12.01 kWhHence, the units consumed by the electric iron in 24 hours is 12.01 kilowatt-hours.For such more question on Voltage
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the maximum acceleration of the car is 20 m/s squared.
calculate the time taken for the speed of the car to change from 0 m/s to 28 m/s at its maximum acceleration.
Answer: So, the time it takes for the speed of the car to change from 0 m/s to 28 m/s at its maximum acceleration, is 1.4 seconds.
Explanation:It is an exercise in rectilinear uniformly varied motion (MRUV).
As it is asking us to calculate the time, we apply the following formula:
t = (Vf - Vo)/a
Where
t = timeVf = Final speedVo = Initial velocitya = accelerationIt tells us that the car has a maximum acceleration of 20 m/s^2, with speeds from 0 m/s to 28 m/s.
Since the car starts from rest, it has an initial velocity of zero.
We clear the formula t = (Vf - Vo)/t , of the initial velocity and we are left:
t = Vf/aWhere
t = timeVf = Final speeda = accelerationWe substitute and solve:
t = (28 m/s)/(20 m/s²)
t = 1.4 seseconds
So, the time it takes for the speed of the car to change from 0 m/s to 28 m/s at its maximum acceleration, is 1.4 seconds.
Which observation is evidence that electromagnetic radiation (EMR) has particle-like
properties? (1 point)
O EMR refracts as it moves into a different medium.
O
A diffraction pattern is observed when EMR passes through a narrow slit.
O Some EMR is blocked when it passes through a polarized lens.
O EMR with energy above a certain value can eject electrons out of a metal.
The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.
Electromagnetic radiations as particlesThe observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.
This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.
It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.
This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.
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A single wire in the shape of a circle of radius 15 cm is carrying a current of 2.7 amps. The wire lies in the xy plane. If the wire is located within a uniform magnetic field of magnitude 0.12 Tesla, what is the net torque on the loop if the magnetic field is oriented parallel to the +x axis Torque = Nm the magnetic field is oriented to the +z axis Torque = Nm the magnetic field is oriented in the xy plane at an angle of 75 degrees from the +x axis. Torque = Nm
The magnetic field is oriented in the xy plane at an angle of 75 degrees from the +x axis, the angle between the magnetic field and the normal to the loop is 75 degrees, so the net torque on the loop is 0.203 Nm.
The net torque on a current-carrying loop in a magnetic field is given by the equation: Torque = (B × I × A × sin(theta))
where torque is the net torque on the loop, B is the magnitude of the magnetic field, I is the current in the wire, A is the area of the loop, and theta is the angle between the magnetic field and the normal to the loop.
In this case, the radius of the loop is 15 cm = 0.15 m, so the area of the loop is A = pi × r² = pi × (0.15 m)² = 0.07 m²
The current in the wire is 2.7 amps, and the magnitude of the magnetic field is 0.12 Tesla.
If the magnetic field is oriented parallel to the +x axis, the angle between the magnetic field and the normal to the loop is 0 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(0)) = 0 Nm
If the magnetic field is oriented to the +z axis, the angle between the magnetic field and the normal to the loop is 90 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(90)) = 0.252 Nm
If the magnetic field is oriented in the xy plane at an angle of 75 degrees from the +x axis, the angle between the magnetic field and the normal to the loop is 75 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(75)) = 0.203 Nm
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If the intial kinetic energy of the molecules in an ideal gas initially at 20degree C doubles , what ius the final temperature of the gas ?
The final temperature of the gas is 782 Kelvin, or 509 degrees Celsius.
What is the final temperature of the gas?According to the ideal gas law, the pressure, volume, and temperature of an ideal gas are related by the equation:
PV = nRT
where;
P is the pressure, V is the volume, n is the number of moles of gas,R is the ideal gas constant, and T is the temperature.If the initial kinetic energy of the molecules in an ideal gas at 20 degrees Celsius doubles, this means that the average kinetic energy of the gas molecules has doubled.
According to the kinetic theory of gases, the average kinetic energy of a gas is proportional to its temperature. Therefore, if the initial kinetic energy doubles, the temperature must also double.
We can express this mathematically using the equation for the average kinetic energy of a gas molecule:
KE = (3/2) kT
where;
KE is the average kinetic energy, k is Boltzmann's constant, and T is the temperature.If the initial kinetic energy doubles, we can write:
2KE = (3/2) kT'
where;
T' is the final temperature.Solving for T', we get:
T' = (4/3) (2KE/k)
Substituting the initial temperature of 20 degrees Celsius (293 K) for T and simplifying, we get:
T' = (4/3) (2)(3/2)(293 K) = 782 K
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A point object moves from point A to point B along a circular path with a radius. What is the size of the angle ?
The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.
How to solve size of an angle?To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.
In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.
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Complete question:
A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?
You throw a ball into the air. Which two forces cause the ball to gradually stop moving upward and then fall back to Earth?
A.
Balanced forces
B.
Friction
C.
Normal force
D.
Gravitational force
will mark brainliest
Answer: Gravitational Forces
Explanation:
Which one the answer to this question
A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s direction 5° north of east for an hour. What is the magnitude of the boat's resultant velocity? Round your answer to the nearest whole number. m/s What is the direction of the boat's resultant velocity? Round your answer to the nearest whole degree. • north of east
The boat’s resultant velocity is v = 31.0 m/s, and the direction of the boat is 23.2 degrees north of east.
A resultant velocity is calculated using the formula below.
Vm equals Sum Sqrt(Vxi2 + VYj2)
where Vm is the resulting magnitude of velocity.
All x-component velocities are denoted by the letters Vxi.
The y-component of all velocities is called Vyj.
Add all of the values for the x-components together, square that number to get the magnitude of the resultant velocity. Add this to the earlier value after doing the same operation for the y-components. Finally, to determine the magnitude, square the result.
Tan-1 (Vx/Vy) = Va
where Va is the resultant velocity's angle.
Vx is the size of the resultant velocity's x-component.
Vy is the size of the resultant velocity's y-component.
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GIVING BRAINLIEST
Which best describes what happens between meiosis I and meiosis II?
Crossing over occurs.
Cells enter into interphase.
Cells directly enter prophase II.
The number of chromosomes is doubled.
Answer:
The correct answer is A. Crossing over occurs