Felipe wants
to have a mean score of 20 points per
game. He has scored 17, 21, 16, 18, and
19 points in his first five games. How
many points does Felipe need in his
sixth game to have a mean score of
20 points?

Hello Hi I think it is Option D

All the other Options are false

Hope it helps

-Rosie (Jewels)

Hello.

In order to find out which option is true, let's simplify all these fractions:

\(\displaystyle\frac{3}{4}\)

This fraction is already in its simplest form.

Let's simplify the following fraction:

\(\displaystyle\frac{9}{16}\)

This fraction is also in its simplest form.

Thus, Option A is false.

\(\displaystyle\frac{6}{8}\)

Divide both the top and bottom by 2:

\(\displaystyle\frac{3}{4}\)

Is it equivalent (equal) to \(\displaystyle\frac{4}3}\)? No, these fractions are reciprocals.

Thus, Option B is false as well; we have two remaining options.

We can see right off the bat that 3 is on no account equal to 8, so we cross out Option C.

Thus, Option D is the correct option.

I hope it helps.

Have a nice day!

\(\boxed{imperturbability\::-))}\)

(A) The number of possible selections for playing a round at a silver or gold course is 16. (B) The number of combined selections possible if the golfer plays one round per week for 3 weeks, starting with a bronze course, then silver, then gold, is 96.

(A) To determine the number of possible selections for playing a round at a silver or gold course, we need to find the total number of silver and gold courses. Given that there are three times as many bronze courses as silver courses, let's assume there are x silver courses.

This means there are 3x bronze courses. Adding the four gold courses, the total number of courses would be x (silver) + 3x (bronze) + 4 (gold) = 4x + 4. Since the golfer can choose either a silver or a gold course, the total number of possible selections is 4x + 4.

(B) If the golfer plays one round per week for 3 weeks, starting with a bronze course, then silver, and finally gold, we need to calculate the combined number of selections. From part (A), we know that the total number of possible selections for silver or gold courses is 4x + 4.

Since the golfer plays one round each week for 3 weeks, the combined number of selections would be (4x + 4) * (3) = 12x + 12. Therefore, the golfer has 12 times the number of possible selections for silver or gold courses when playing one round per week for 3 weeks.

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The correct answer is A. line. A line is a straight path that extends infinitely in both directions. It has no endpoints and continues indefinitely.

A line is a basic geometric object that is defined by two points or can be represented by a single equation. It is characterized by its straightness and infinite length, extending in both directions without any boundaries or endpoints. A line can be represented by a straight line segment with two distinct points or by an equation such as y = mx + b in a coordinate system.

On the other hand, a plane refers to a two-dimensional flat surface that extends infinitely in all directions. It is not a straight path but rather a flat, continuous surface. A ray, is a part of a line that has one endpoint and extends infinitely in one direction. It is not a straight path that continues indefinitely in both directions like a line.

A triangle is a closed geometric shape with three sides and three angles. It is not a straight path but rather a closed figure formed by connecting three non-collinear points.Therefore ,the correct answer is A.

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Answer:

Each undershirt costs $2.99 when purchased individually.

Step-by-step explanation:

The problem says that $13.98 is $3.96 less than the cost of buying 6 individual shirts which means that the total cost of buying 6 individual shirts is $17.94.

To find the price of 1 individual shirt, you divide 17.94 by 6. When you do this, you get $2.99. $2.99 is the cost of each undershirt when purchased individually.

Hope this helps!

Unsigned whole numbers in binary are represented by a sequence of 1s, with the number of 1s equal to the value of the number itself.

In binary representation, numbers are expressed using only 0s and 1s. When dealing with unsigned whole numbers, the value of the number determines the length of the sequence of 1s used for its representation. For example, the decimal number 5 would be represented in binary as "11111" since it consists of five consecutive 1s. Similarly, the decimal number 10 would be represented as "1111111111" since it consists of ten consecutive 1s. This encoding scheme allows for a simple and efficient representation of positive whole numbers in binary.

Binary representation provides a concise and efficient way to represent numbers in computing systems. It is the foundation of digital communication and storage, enabling the manipulation and processing of numerical data. Understanding how numbers are encoded in binary is essential for working with computer systems, algorithms, and programming languages.

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The number of surfer view page is 18.7 views out of 100 webpage views

In this example, we have three webpages, W₁, W₂, and W₃, and an adjacency matrix C. The matrix C represents the links between the webpages.

C =

0 1 1

1 0 0

0 0 0

To calculate the PageRank of each webpage, we start with an initial vector v that represents the surfer's probability of being on each webpage. Initially, the surfer is equally likely to be on any of the webpages, so v = [1/3, 1/3, 1/3].

To answer the question, we need to calculate the PageRank of webpage W3 after 100 iterations of the formula above.

After one iteration, we have:

v = d x Cv + (1 - d) x u

v = 0.7 * [0, 0, 1/3] + 0.3 * [1/3, 1/3, 1/3]

v = [0.1, 0.1, 0.2333]

After 100 iterations, we have:

v = d x Cv + (1 - d) x u

v = 0.7 * [0.1, 0.1, 0.2333] + 0.3 * [1/3, 1/3, 1/3]

v = [0.068, 0.045, 0.187]

Therefore, the surfer will view webpage W3 approximately 18.7% of the time after 100 iterations.

This corresponds to 18.7 views out of 100 webpage views.

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Answer:

5,8

Step-by-step explanation:

since C is on y coordinate 8 if its a reflection C' will be as well and C is on x coordinate -5 so if its a reflection then C' will be 5 so 5,8

Answer:

(5,8)

Step-by-step explanation:

one way I like to do it is a) count how many squares C is away from the axis, which is 5, and then staring at the Y-axis count five spaces to the right, or b) which might be a little more time consuming, do where the original D is and see how many spaces up and across C is from D, which is up two and right 5. So then go to the new one, and go up two and instead of going right five, count five to the left because it's reflected. Hope that made sense and helped! If not please let me know and i'll try to explain further.

Answer:

have a great day

god bless you

Step-by-step explanation:

ghofuikgcjjivbiucbkhfkhcuvijnochm

Answer:

C: 16.4 miles

Explanation/

Answer:

Step-by-step explanation:

By the Pythagorean Theorem

\(d^2=x^2+y^2\\ \\ d^2=10^2+13^2\\ \\ d^2=100+169\\ \\ d^2=269\\ \\ d=\sqrt{269}\\ \\ d\approx 16.4\ miles\)

In a paired t-test, we use the D) Difference. of two observations for each subject.

A paired t-test is a statistical test used to compare the means of two related groups. In this test, we use the difference of two observations for each subject.

For example, if we are comparing the effectiveness of two different drugs, we would measure the response of each patient to both drugs and then calculate the difference between the two responses.

This gives us a single value for each subject that represents the change in response between the two drugs. We then use these differences to calculate the t-statistic.

The formula for the t-statistic in a paired t-test is:

t = (mean difference / (standard deviation of differences / √n))

Where n is the number of pairs of observations. This formula uses the mean difference (i.e., the average of the differences between the two groups), which is calculated by subtracting the second observation from the first observation for each subject.

Therefore, the correct answer to the given question is D. Difference.

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Answer:

1st Q: C. Algebraic Expression; it consists of numbers and a variable.

2nd Q: D. The number of times Chris washes the car.

Step-by-step explanation:

1st Question:

Numerical Expression: Contains numbers and operations. Numerical expressions are your typical 2 + 2 equations. The ones you start learning in Kindergarten with just numbers and different operations such as addition, subtraction, division, and multiplication.

EX: 108 - 24 = ?

? = 84

Algebraic Expression: Contains numbers, operations, and variables. They are the same as normal, numerical expressions with the exception that it also has letters, or variables.

EX: 2x + 3 = 7

x = 2

__________________________________

2nd Question:

Amount Chris earns per wash: $10.00

# of times Chris washes the car: x

So 10x means what...?

10 = earns per wash

x = times washed the car

Multiply 10 by x to find the total Chris earns for the number of times he washes the car, x.

(Just as a reference, this would be counted as an Algebraic Expression).

Hope this helps! :)

(Lmk if you don't understand the explanation for the 2nd Q)

Overall, the horizontal analysis of Blanchet Corporation's balance sheet for 2019 suggests positive growth and financial stability.

There has been a significant increase in total assets from the previous year. This indicates potential growth and expansion in the company's operations.

The liabilities have also increased, but not at the same rate as the assets. This suggests that the company may have taken on additional debt or financing to support its growth.

The retained earnings have shown a positive trend, indicating that the company has been profitable and able to retain a portion of its earnings for reinvestment or future use.

The equity section has also grown, which can be attributed to the increase in retained earnings and potentially additional capital investments.

The increase in assets and retained earnings indicates the company's ability to generate profits and reinvest in its operations. However, the increase in liabilities should be carefully monitored to ensure it is manageable and sustainable in the long term.

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Answer:

153 185-32 is 153 so there's your answer

The claim that "a context level data flow diagram includes many detailed processes representing the computer programmes within the system" is false.

A context level data flow diagram (DFD) is a particular kind of diagram that shows how various system components interact with one another. The main objective of building a DFD is to visually depict the data flow and system activities.

The highest-level diagram that shows the system's overall operation without going into specifics about particular processes or data stores is a context level DFD, also referred to as a Level 0 DFD.

The statement that "a context level data flow diagram includes many detailed processes representing the computer programmes within the system" is untrue. This is so because the context level DFD reflects the total functionality of the system.

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Answer:

C. 19,005

Step-by-step explanation:

multipy 2,715 by 7

Refer to the image for the graph of the lines.

The common form of the equation of a line is y = mx + c, where m is the slope of the line and c is a constant.

We need to draw any line with a slope m = 2, and

another line with a slope m = -2.

Disclaimer: Let us assume that the constant c = 0.

Then the equation to the line with a slope of "positive" 2 is given by

y = 2x

Then the equation to the line with a slope of "negative" 2 is given by

y = -2x

Refer to the attached image for the graph of the lines with the slope of "positive" 2 and "negative" 2.

f: green line indicates a line with a slope of "positive" 2.

g: blue line indicates a line with a slope of "negative" 2.

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The equivalent effective bi-weekly rate is approximately 0.01456%.

To find the equivalent effective bi-weekly rate, we need to convert the given nominal rate \(i^{(2)} =1.45000\%\) to the effective rate for a bi-weekly period.

The formula to convert a nominal rate to an effective rate is \(i^{(m)} =(1+r/m)^{m}-1\), where \(i^{(m)}\) is the effective rate, r is the nominal rate, and m is the number of compounding periods per year.

In this case, we have a nominal rate \(i^{(2)}\) that corresponds to a semi-annual compounding (2 periods per year). We can plug the values into the formula and calculate the effective rate \(i^{(bi-weekly)}\) for a bi-weekly period.

\(i^{(bi-weekly)}=(1+1.45000/2/100)^{2}-1\)

Calculating the expression:

\(i^{bi-weekly}=(1+0.00725)^{2} -1\\i^{bi-weekly}= 1.0145640625-1\\i^{bi-weekly}= 0.0145640625\)

The equivalent effective bi-weekly rate is approximately 0.01456%.

Among the given options, none of them match the calculated value exactly.

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Given the curve $r(t) = (5 cos(3t), 5 sin(3t), t)$ and we need to find its curvature at the point $t = 0$.

Curvature is the measure of how quickly a curve changes its direction as compared to a unit tangent vector. A curve has curvature $\kappa$ at a point if its tangent vector is rotating at a rate of $\kappa$ about that point.The formula for the curvature $\kappa$ of a curve $r(t)$ is$$\kappa = \frac{\|r'(t) \times r''(t)\|}{\|r'(t)\|^3}$$Now, let's find the tangent and normal vectors and the radius of curvature.

The tangent vector to the curve is given by$$\mathbf{T}(t) = \frac{r'(t)}{\|r'(t)\|}$$Substitute $r(t) = (5 \cos 3t, 5 \sin 3t, t)$ and simplify to find the unit tangent vector,$$\mathbf{T}(t) = \frac{r'(t)}{\|r'(t)\|} = \frac{(-15 \sin 3t, 15 \cos 3t, 1)}{\sqrt{225 \sin^2 3t + 225 \cos^2 3t + 1}} = (-3 \sin 3t, 3 \cos 3t, 1/\sqrt{225})$$

The normal vector to the curve is given by$$\mathbf{N}(t) = \frac{\mathbf{T}'(t)}{\|\mathbf{T}'(t)\|}$$Differentiate the tangent vector and simplify,$$\mathbf{T}'(t) = (-9 \cos 3t, -9 \sin 3t, 0)$$Substitute $\mathbf{T}'(t)$ and simplify to find the unit normal vector,$$\mathbf{N}(t) = \frac{\mathbf{T}'(t)}{\|\mathbf{T}'(t)\|} = (-\cos 3t, -\sin 3t, 0)$$

The binormal vector is given by$$\mathbf{B}(t) = \mathbf{T}(t) \times \mathbf{N}(t)$$Substitute $\mathbf{T}(t)$ and $\mathbf{N}(t)$ and simplify to find the unit binormal vector,$$\mathbf{B}(t) = \mathbf{T}(t) \times \mathbf{N}(t) = (-1/\sqrt{225}, 0, -3/\sqrt{225})$$The radius of curvature is given by$$\rho = \frac{1}{\kappa} = \left\|\frac{d\mathbf{T}/dt}{\kappa}\right\| = \left\|\frac{\mathbf{N}'(t)}{\kappa}\right\|$$

Differentiate the normal vector and substitute it to find the radius of curvature,$$\mathbf{N}'(t) = (-3 \sin 3t, 3 \cos 3t, 0)$$$$\left\|\frac{\mathbf{N}'(t)}{\kappa}\right\| = \left\|\frac{(-3 \sin 3t, 3 \cos 3t, 0)}{\frac{\|r'(t) \times r''(t)\|}{\|r'(t)\|^3}}\right\| = \frac{225}{14}$$Finally, we get the curvature at $t=0$,$$\kappa = \frac{\|r'(0) \times r''(0)\|}{\|r'(0)\|^3} = \frac{\|(-15, 0, 1)\times(-45, -45, 0)\|}{\|(-15, 0, 1)\|^3} = \frac{15}{\sqrt{226}}$$

Thus, the curvature of the curve $r(t) = (5 cos(3t), 5 sin(3t), t)$ at the point $t=0$ is approximately 1.18 (rounded to two decimal places).

Here, the given curve is $r(t) = (5 cos(3t), 5 sin(3t), t)$. To find the curvature of the curve, first we have to find the unit tangent vector to the curve. From the definition, we have $\mathbf{T}(t) = \frac{r'(t)}{\|r'(t)\|}$. We have to differentiate the unit tangent vector and the derivative of $\mathbf{T}(t)$ is called the principal normal vector $\mathbf{N}(t)$, which is given by $\mathbf{N}(t) = \frac{\mathbf{T}'(t)}{\|\mathbf{T}'(t)\|}$.

Finally, the curvature of the curve is given by $\kappa = \frac{\|r'(t) \times r''(t)\|}{\|r'(t)\|^3}$ and the radius of curvature is $\rho = \frac{1}{\kappa} = \left\|\frac{d\mathbf{T}/dt}{\kappa}\right\| = \left\|\frac{\mathbf{N}'(t)}{\kappa}\right\|$.

By substituting the value $t=0$ in the formula for curvature we get, $\kappa = \frac{\|r'(0) \times r''(0)\|}{\|r'(0)\|^3} = \frac{\|(-15, 0, 1)\times(-45, -45, 0)\|}{\|(-15, 0, 1)\|^3} = \frac{15}{\sqrt{226}}$. Thus, the curvature of the curve $r(t) = (5 cos(3t), 5 sin(3t), t)$ at the point $t=0$ is approximately 1.18 (rounded to two decimal places).

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The answers that describe the quadrilateral DEFG area rectangle and parallelogram.

The correct answer choice is option A and B.

A quadrilateral is a parallelogram, which has opposite sides that are congruent and parallel.

Quadrilateral DEFG

if line DE || FG,

line EF // GD,

DF = EG and

diagonals DF and EG are perpendicular,

then, the quadrilateral is a parallelogram

Hence, the quadrilateral DEFG is a rectangle and parallelogram.

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Answer:

Option 2

 x     y

−3     0

−1      3

 0     4

 3     0

4 3

Step-by-step explanation:

For a relation x →  y to be a function, there can be one and only one value of y for a value of x

Looking at the tables we see that option 1 is out since all x values are 2 andthere are multiple values of y

The last option is out because for x = 0 there are two values of y=-2 and y = 2

Correct choice is the second option which has a unique y value for each value of x

Answer:

option 2 im doing it rn

Step-by-step explanation:

The period of time between treatments in which no treatment is given so that the effects of a previous treatment are eliminated before introducing a new treatment is called a washout period.

The period of time between treatments in which no treatment is given so that the effects of a previous treatment are eliminated before introducing a new treatment is called a washout period.

This period allows the body to return to its baseline state before starting a new treatment. The duration of the washout period depends on the specific treatment and its effects on the body.

The washout period allows for the evaluation of the effects of the new treatment without interference from the previous medication or treatment. The goal of a washout period is to reduce the potential for confounding variables that could impact the accuracy and reliability of the study results.

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Answer:

498,173.26

Step-by-step explanation:

Answer:

The linear equation of the graphed line:

Step-by-step explanation:

Given the points from the graph

Finding the slope between the points

\(\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\)

\(\left(x_1,\:y_1\right)=\left(1,\:0\right),\:\left(x_2,\:y_2\right)=\left(3,\:7\right)\)

\(m=\frac{7-0}{3-1}\)

\(m=\frac{7}{2}\)

We know the slope-intercept form of the line equation

\(y=mx+b\)

Where m is the slope and b is the y-intercept

substituting m = 7/2 and the point (1, 0) to find the y-intercept 'b'

y=mx+b

0 = 7/2(1) + b

0 = 7/2 + b

b = -7/2

b = -3.5

Thus, y-intercept 'b' = -3.5

substituting m = 7/2 and the y-intercept 'b' = -3.5 in the slope-intercept form

\(y=mx+b\)

y=7/2x + (-3.5)

y = 7/2x - 3.5

Thus, the linear equation of the graphed line:

There are two distinct congruence classes modulo x^3 + x + 1 in Z_2[x]. The congruence classes are [0] and [1].

To determine the distinct congruence classes modulo x^3 + x + 1 in Z_2[x], we consider polynomials in Z_2[x] and examine their remainders when divided by x^3 + x + 1.

In Z_2[x], the coefficients of polynomials are either 0 or 1, representing the binary field. When we divide polynomials by x^3 + x + 1, the remainder can only have coefficients of 0 or 1.

After performing polynomial division, we find that there are two distinct congruence classes. The congruence class [0] consists of polynomials that are divisible by x^3 + x + 1, resulting in a remainder of 0. The congruence class [1] consists of polynomials with a remainder of 1 when divided by x^3 + x + 1.

These two congruence classes represent the distinct equivalence classes modulo x^3 + x + 1 in Z_2[x].

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We have constructed an example of a quasi-increasing sequence that is neither monotone nor eventually monotone.

Sure, let's construct an example of a quasi-increasing sequence that is not monotone or eventually monotone. Consider the sequence defined as follows:

a_n = 1 + 1/n for n = 1, 2, 3, ...

Now, let's see if this sequence is quasi-increasing. For any ε > 0, we can choose an n such that n > 1/ε. Now, if m ≥ n, then:

a_m = 1 + 1/m ≤ 1 + 1/n < 1 + ε = a_n + ε

This shows that for any ε > 0, there exists an n such that whenever n > m ≥ n, it follows that a_m < a_n + ε. Hence, the sequence (a_n) is quasi-increasing.

Now, let's check if it is monotone or eventually monotone. The sequence (a_n) starts with a_1 = 2, a_2 = 3/2, a_3 = 4/3, and so on. It is clear that the sequence is not strictly increasing, as a_2 = 3/2 < a_1 = 2. Also, the sequence is not strictly decreasing, as a_3 = 4/3 > a_2 = 3/2.

Moreover, the sequence does not become eventually monotone. For any value of N, we can always find a larger index equation n > N such that a_n = 1 + 1/n < a_N = 1 + 1/N. Therefore, the sequence (a_n) is not eventually monotone.

Thus, we have constructed an example of a quasi-increasing sequence that is neither monotone nor eventually monotone.

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Answer:

30

Step-by-step explanation:

Substitute and multiply :))

f(3)=10(3)

f(3)=30

To find the probability of the event "the first die is 6 or the sum is 8," we need to count the number of outcomes that satisfy this event and divide it by the total number of possible outcomes.

To find the probability of the event "the first die is 6 or the sum is 8," we need to consider the total possible outcomes when rolling two dice and the favorable outcomes for this event.

Total possible outcomes: 6 sides on each die, so there are 6 x 6 = 36 possible outcomes.

Favorable outcomes:
1. First die is 6: There are 6 possible outcomes (6,1), (6,2), (6,3), (6,4), (6,5), and (6,6).
2. Sum is 8: There are 5 possible outcomes (2,6), (3,5), (4,4), (5,3), and (6,2).

However, (6,2) is counted twice, so we should subtract 1 from the total favorable outcomes: 6 + 5 - 1 = 10.

Probability = Favorable outcomes / Total possible outcomes = 10/36. Simplifying the fraction gives 5/18.

So, the probability of the event "the first die is 6 or the sum is 8" is 5/18.

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