Find a function of the form y = A cos B(x - C) with the given properties. Amplitude: 1; Period: 3pi/4; Phase Shift: 3pi/4 units to the right.

To evaluate ∫fac cos(√x + 3) dx:Let u = √x + 3.Then du/dx = 1/(2√x), and therefore, dx = 2u du.Substituting in the integral,∫fac cos(√x + 3) dx = ∫fac cos u * 2u du.

The given integral can be solved by using the integration technique known as substitution. In order to solve the integral, we need to substitute a value of x with u. This is because the integral of the given form cannot be evaluated as it is directly. When we substitute, we get a simpler integral that can be evaluated easily.

The substitution is given by u = √x + 3.

By doing this, we can simplify the integral to get,

∫fac cos(√x + 3) dx = ∫fac cos u * 2u du = 2u sin u |fc - ac - 2√3sin(√x + 3)/3 + C,

where C is the constant of integration.

In conclusion, the integral ∫fac cos(√x + 3) dx can be evaluated by using the substitution method. By using the substitution u = √x + 3, we can simplify the integral to get a form that can be easily evaluated. After simplification, the integral becomes ∫fac cos u * 2u du. Then, by integrating by parts, we obtain the solution to the integral as 2u sin u |fc - ac - 2√3sin(√x + 3)/3 + C, where C is the constant of integration.

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Using a test statistic of 2.0 in a two-sided hypothesis test for the population proportion with a sample of 50, you can reject the null hypothesis at the 5% significance level. This is because the test statistic (2.0) is greater than the z-value for a 5% significance level (1.96).

Based on the given test statistic of 2.0 and the sample size of 50, we can use a normal distribution to conduct the hypothesis test for the population proportion. The null hypothesis, in this case, would be that the population proportion is equal to a certain value, while the alternative hypothesis would be that it is not.

Using the given significance levels and critical values, we can determine whether we can reject or fail to reject the null hypothesis. Since this is a two-sided test, we will use the critical values for both the upper and lower tails of the distribution.

Looking at the critical values provided, we see that zo.1 is -1.282, zo.025 is -1.96, and zo.01 is -2.33 for a two-tailed test at the 10%, 5%, and 1% significance levels, respectively. Based on these values, we can see that a test statistic of 2.0 falls outside of the rejection region at the 10% and 5% levels, but not at the 1% level.

Therefore, the correct answer is that we can reject the null hypothesis at the 5% significance level, but not at the 10% level.

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When designing a 3x3 factorial study design with a within-subjects design and when 10 participants are assigned for each cell, the number of participants we require in total is 10.

Therefore, the answer is 10.

In a n×m factorial study design, the number of factors is the number of numbers, that is here 2 and the first factor is of n levels and second factor is of m levels.

So in 3x3 factorial study we have two factors each with 3 levels and the number of groups is 3 × 3 = 9.

In a within-subject design, all the participants take part in every group. So if there are 10 participants in a cell, these 10 participants are part of all groups. So we require only 10 participants in total for this study.

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The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model. The optimal number of notebooks to make in each order is 590 units. The annual ordering cost (AOC) is approximately $892.20. The Annual Holding Cost (AHC) is $3540. The annual product cost (APC) is $233,460. The annual total cost of managing inventory (ATC) is approximately $237,892.20. The total number of orders in the year (N) is 33. The estimated time between each order (T) is approximately 7.58 days. The daily demand is approximately 77.82 units. The reorder point (ROP) is approximately 311 units.

The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model.

To find the optimal number of notebooks to make in each order, we can use the EOQ formula:

EOQ = √[(2 * Demand * Ordering Cost) / Holding Cost]

EOQ = √[(2 * 19455 * 27) / 6]

EOQ ≈ 589.96

Since the number of notebooks must be a whole number, the optimal number to order would be 590 notebooks.

The annual ordering cost (AOC) can be calculated by dividing the annual demand by the EOQ and multiplying it by the ordering cost:

AOC = (Demand / EOQ) * Ordering Cost

AOC = (19455 / 590) * 27

AOC ≈ $892.20

The Annual Holding Cost (AHC) is calculated by multiplying the EOQ by the holding cost per unit:

AHC = EOQ * Holding Cost

AHC = 590 * 6

AHC = $3540

The annual product cost (APC) is calculated by multiplying the annual demand by the cost per unit:

APC = Demand * Cost per unit

APC = 19455 * 12

APC = $233,460

The annual total cost of managing inventory (ATC) is the sum of the annual ordering cost, annual holding cost, and annual product cost:

ATC = AOC + AHC + APC

ATC = 892.20 + 3540 + 233460

ATC ≈ $237,892.20

The total number of orders in the year (N) can be calculated by dividing the annual demand by the EOQ:

N = Demand / EOQ

N = 19455 / 590

N ≈ 33

The estimated time between each order (T) can be calculated by dividing the number of working days in a year by the total number of orders:

T = Number of working days / N

T = 250 / 33

T ≈ 7.58 days

The daily demand is calculated by dividing the annual demand by the number of working days in a year:

Daily Demand = Demand / Number of working days

Daily Demand = 19455 / 250

Daily Demand ≈ 77.82 units/day

The reorder point (ROP) is the number of units at which a new order should be placed. It can be calculated by multiplying the daily demand by the lead time (time taken for the supplier to deliver the order):

ROP = Daily Demand * Lead Time

ROP = 77.82 * 4

ROP ≈ 311.28 units

Therefore, the reorder point would be approximately 311 units.

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Answer: 7 x 10 + 2 x 1 + 6 x 1/10+ 3 x 1/1000

Step-by-step explanation: just had this question on the test

Answer:

NO=15

Step-by-step explanation:

Two Congruent Angles→Isosceles Triangle

Opposite sides must be congruent.

MO=15 so NO=15

The length of NO is 15 units.

A type of triangle known as an isosceles triangle has any two sides that are both the same length. The theorem that describes the isosceles triangle states that "if the two sides of a triangle are congruent, then the angle opposite to them are also congruent." This means that the two angles of an isosceles triangle opposite to equal sides are equal in measure. For example, in the triangle ΔABC, if sides AB and AC are equal, then ABC is an isosceles triangle where ∠B = ∠C.

Given ΔMNO,

∠M = ∠N

and MN=12 and OM=15

the angles are equal then triangle is isosceles and for given triangles the two sides are equal,

sides opposite to angles are

OM and NO

OM = NO = 15 units

Hence the length of third side is 15 units.

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Answer:

3

Step-by-step explanation:

12x-4x+8x = 16+x

The absolute value inequality represents the difference between the rope lengths cut and the specifications are | x - 10 | ≤ 0.5.

Modulus value always outputs a positive value irrespective of the input value sign.

Julian needed to cut ropes for her school project and their length should be 10 inches long with a difference of 0.5 inches.

∴ The maximum allowable length of the rope should be (10 + 0.5) = 10.5 inches and the minimum allowable length of the rope should be

(10 -0.5) = 9.5 inches.

The absolute value of inequality that represents this condition is,

| x - 10 | ≤ 0.5.

x - 10 ≤ 0.5.

x ≤ 10.5, And

- ( x - 10) ≤ 0.5.

-x + 10 ≤ 0.5.

- x ≤ - 9.5.    ( think of moving the terms on either side to make x positive).

x ≥ 9.5.

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Answer:

see explanation

Step-by-step explanation:

1

substitute t = - 6 into h(t)

h(- 6) = 3(- 6) - 2 = - 18 - 2 = - 20

2

substitute a = 6 into g(a)

g(6) = - 4(6) - 2 = - 24 - 2 = - 26

3

substitute a = - 3 into w(a)

w(- 3) = (- 3)² + 5(- 3) = 9 - 15 = - 6

4

substitute n = - x into h(n)

h(- x) = 2(- x) - 4 = - 2x + 4

5

substitute a = a - 3 into k(a)

k(a - 3) = 3(a - 3) - 2 = 3a - 9 - 2 = 3a - 11

!! for 2 and 3 these values are rounded

1) 693.5/18,250 = .038 x 100% = 3.8% commission

2) ~118.5%  --- divide tip/meal then x 100%

3) ~21.33%   divide sale price/over org., then subtract by 100%

Answer:

\(4\sqrt[3]{307}\) o 26.98398684 en forma decimal

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

To determine the number of rolls, take the number of packs and multiply by the number of rolls per pack.

10 *4 = 40

40 rolls total.

Answer:

40 rolls

Step-by-step explanation:

10 packs * 4 rolls per pack

Answer:

DC = 10 cm

Step-by-step explanation:

given a tangent and a secant drawn to the circle from an external point, then the square of the measure of the tangent is equal to the product of the secant's external part and the entire secant , that is

AC × AD = AB²

8(8 + x) = 12² = 144 ( divide both sides by 8 )

8 + x = 18 ( subtract 8 from both sides )

x = 10

that is DC is 10 cm

The value of x for GT is 6.5 .

What is the congruence of triangles?
If all three corresponding sides and all three corresponding angles are equal in size, two triangles are said to be congruent. Slide, twist, flip, and turn these triangles to create an identical appearance. They are in alignment with one another when moved.

Given, ΔGET ≅ ΔABS
Following the statement that corresponding sides of congruent triangles are congruent, we have:
GE = AB, ET = BS and GT = AS -(i)
AB = 10, BS = 13, AS = 18, GT = 4x - 8 -(ii)
Comparing (i) and (ii) we have, 4x - 8 = 18 ⇒ 4x = 26 ⇒ x = 26/4 = 6.5
Thus, the value of x for GT is 6.5 .

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the integral ∫e^(4θ)sin(5θ)dθ evaluates to (-9/41)e^(4θ)cos(5θ) + C.

To evaluate the integral ∫e^(4θ)sin(5θ)dθ, we can use integration by parts.

Let u = sin(5θ) and dv = e^(4θ)dθ.

Then, we have du = 5cos(5θ)dθ and v = (1/4)e^(4θ).

Using the formula for integration by parts:

∫u dv = uv - ∫v du,

we can apply it to our integral:

∫e^(4θ)sin(5θ)dθ = (-1/4)e^(4θ)cos(5θ) - ∫(1/4)e^(4θ)(5cos(5θ))dθ.

Simplifying the expression, we get:

∫e^(4θ)sin(5θ)dθ = (-1/4)e^(4θ)cos(5θ) - (5/4)∫e^(4θ)cos(5θ)dθ.

Now, we need to evaluate the remaining integral: ∫e^(4θ)cos(5θ)dθ.

For this integral, we can again use integration by parts.

Let u = cos(5θ) and dv = e^(4θ)dθ.

Then, we have du = -5sin(5θ)dθ and v = (1/4)e^(4θ).

Applying the integration by parts formula, we get:

∫e^(4θ)cos(5θ)dθ = (1/4)e^(4θ)cos(5θ) + (5/4)∫e^(4θ)sin(5θ)dθ.

We can substitute this result back into the previous expression:

∫e^(4θ)sin(5θ)dθ = (-1/4)e^(4θ)cos(5θ) - (5/4)[(1/4)e^(4θ)cos(5θ) + (5/4)∫e^(4θ)sin(5θ)dθ].

Now, we have an equation involving the integral we are trying to evaluate. Let's isolate it:

∫e^(4θ)sin(5θ)dθ = (-1/4)e^(4θ)cos(5θ) - (5/4)(1/4)e^(4θ)cos(5θ) - (25/16)∫e^(4θ)sin(5θ)dθ.

Combining like terms, we get:

(41/16)∫e^(4θ)sin(5θ)dθ = (-9/16)e^(4θ)cos(5θ).

Finally, dividing both sides by (41/16), we obtain:

∫e^(4θ)sin(5θ)dθ = (-9/41)e^(4θ)cos(5θ) + C,

where C is the constant of integration.

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a) The equation be \($$(3 x+y)^4$$\) then the binomial expression be \($$81 x^4+108 x^3 y+54 x^2 y^2+12 x y^3+y^4$$\).

b) The equation be \($$(x-2 y)^6$$\) then the binomial expression be\($$x^6-12 x^5 y+60 x^4 y^2-160 x^3 y^3+240 x^2 y^4-192 x y^5+64 y^6$$\)

The algebraic terms of the form (x + y)n are expanded using the binomial theorem. \((x + y)^n = ^nC_0 x_ny_0 +^ nC_1 x_{n-1}y_1,... + ^nC_{n-1} x_1y_{n-1} + ^nC_n x_0y_n\).

In this case, there are n + 1 terms in the binomial expansion with an exponent of n. In a progressive way, the second term's exponent is gradually rising while the first term's exponent in the expansion is steadily declining. The Pascals triangle or the combination formula

\(^nC_r\) = n! / [r! (n - r)!]! can be used to determine the coefficients of the binomial expansion.

a) Let the given equation be \($$(3 x+y)^4$$\)

Apply binomial theorem, we get

\($(a+b)^n=\sum_{i=0}^n\left(\begin{array}{l}n \\ i\end{array}\right) a^{(n-i)} b^i$\).

\($a=3 x, b=y$\)

\(=\sum_{i=0}^4\left(\begin{array}{l}4 \\i\end{array}\right)(3 x)^{(4-i)} y^i\)

simplifying the equation, we get

\($\frac{4 !}{0 !(4-0) !}(3 x)^4 y^0+\frac{4 !}{1 !(4-1) !}(3 x)^3 y^1+\frac{4 !}{2 !(4-2) !}(3 x)^2 y^2+\frac{4 !}{3 !(4-3) !}(3 x)^1 y^3+\frac{4 !}{4 !(4-4) !}(3 x)^0 y^4$\)

Simplifying the above equation, we get

\($\frac{4 !}{0 !(4-0) !}(3 x)^4 y^0= 81 x^4$\)

\($\frac{4 !}{1 !(4-1) !}(3 x)^3 y^1= 108 x^3 y$\)

\($\frac{4 !}{2 !(4-2) !}(3 x)^2 y^2=54 x^2 y^2$\)

\($\frac{4 !}{3 !(4-3) !}(3 x)^1 y^3= 12 x y^3$\)

\($\frac{4 !}{4 !(4-4) !}(3 x)^0 y^4= y^4$\)

\($$=81 x^4+108 x^3 y+54 x^2 y^2+12 x y^3+y^4$$\)

b) Let the given equation be \($$(x-2 y)^6$$\)

Apply binomial theorem: \($(a+b)^n=\sum_{i=0}^n\left(\begin{array}{l}n \\ i\end{array}\right) a^{(n-i)} b^i$\)

a = x, b = -2y

simplifying the equation, we get

\($$=\sum_{i=0}^6\left(\begin{array}{l}6 \\i\end{array}\right) x^{(6-i)}(-2 y)^i$$\)

\($=\frac{6 !}{0 !(6-0) !} x^6(-2 y)^0+\frac{6 !}{1 !(6-1) !} x^5(-2 y)^1+\frac{6 !}{2 !(6-2) !} x^4(-2 y)^2+\frac{6 !}{3 !(6-3) !} x^3(-2 y)^3+\)\($\frac{6 !}{4 !(6-4) !} x^2(-2 y)^4+\frac{6 !}{5 !(6-5) !} x^1(-2 y)^5+\frac{6 !}{6 !(6-6) !} x^0(-2 y)^6$\)

simplifying the equation, we get

\($\frac{6 !}{0 !(6-0) !} x^6(-2 y)^0= x^6$\)

\($\frac{6 !}{1 !(6-1) !} x^5(-2 y)^1=-12 x^5 y$\)

\($\frac{6 !}{2 !(6-2) !} x^4(-2 y)^2= 60 x^4 y^2$\)

\($\frac{6 !}{3 !(6-3) !} x^3(-2 y)^3=-160 x^3 y^3$\)

\($\frac{6 !}{4 !(6-4) !} x^2(-2 y)^4= 240 x^2 y^4$\)

\($\frac{6 !}{5 !(6-5) !} x^1(-2 y)^5 = -192 x y^5$\)

\($\frac{6 !}{6 !(6-6) !} x^0(-2 y)^6= 64 y^6$\)

\($$=x^6-12 x^5 y+60 x^4 y^2-160 x^3 y^3+240 x^2 y^4-192 x y^5+64 y^6$$\)

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\(\huge\text{Hey there!}\)

\(\large\text{Solve the inequalities: } \mathsf{3y + 4 < 14}\)

\(\mathsf{3y + 4 < 14}\)

\(\large\text{SUBTRACT 4 to BOTH SIDES}\)

\(\mathsf{3y + 4 -4< 14-4}\)

\(\large\text{CANCEL out: }\mathsf{4 - 4}\large\text{ because it gives you 0}\)

\(\large\text{Keep: }\mathsf{14 - 4}\large\text{ because it gives you 10 (which helps you solve for y)}\)

\(\large\text{New equation: }\mathsf{3y < 10}\)

\(\large\text{DIVIDE 3 to BOTH SIDES}\)

\(\mathsf{\dfrac{3y}{3}<\dfrac{10}{3}}\)

\(\large\text{Cancel out: }\mathsf{\dfrac{3}{3}}\large\text{ because it gives you 1}\)

\(\large\text{Keep: }\mathsf{\dfrac{10}{3}}\large\text{ because it helps solve for y....or compare to y}\)

\(\boxed{\boxed{\huge\text{Answer: }\mathsf{\bf y<\dfrac{10}{3}}}}\huge\checkmark\)

\(\text{Good luck on your assignment and enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

The value of x coordinate for point E is,

⇒ x = 6

A pair of numbers which describe the exact position of a point on a cartesian plane by using the horizontal and vertical lines is called the coordinates.

Given that;

Grace has a segment with endpoints C (3, 4) and D (11, 3)

And, It is divided by a point E such that CE and DE form a 3:5 ratio.

Hence, We get;

The coordinates of E is,

E = [ ( 3× 11  + 5 × 3)/(3 + 5) , (3×3  + 5 × 4)/(3 + 5) ]

   = [ (33 + 15)/8 , (9 + 20)/8 ]

    = *(48/8  ,  29/8)

    =  (6 , 3.625)

Thus, The value of x coordinate for point E is,

⇒ x = 6

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Answer:gamble that,on average,will leave a person with the same amount of money.

Step-by-step explanation:

Answer:

(x + 6)(x + 7)

Step-by-step explanation:

To factor the trinomial x^2 + 13x + 42, we need to find two numbers that multiply to 42 and add up to 13.

One way to do this is to list all the pairs of factors of 42 and see which pair adds up to 13:

1, 42 -> 1 + 42 = 43

2, 21 -> 2 + 21 = 23

3, 14 -> 3 + 14 = 17

6, 7 -> 6 + 7 = 13

So the pair of factors that we want is 6 and 7. We can use these numbers to rewrite the middle term of the trinomial:

x^2 + 13x + 42 = x^2 + 6x + 7x + 42

Next, we can group the first two terms and the last two terms:

x^2 + 6x + 7x + 42 = (x^2 + 6x) + (7x + 42)

Now, we can factor out the greatest common factor from each group:

x(x + 6) + 7(x + 6)

Notice that we have a common factor of (x + 6) in both terms. We can factor this out:

(x + 6)(x + 7)

Answer:

In the PDF. All the answers should be there. Let me know if I'm missing any.

Answer:

Answers are below

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given

Solving for x

Answer:

Step-by-step explanation:

The Answer is 29 degrees

The table is

x = 0            5         8            10           30.

y = 300       250    220        200         0

The height of the airplane decreases with time. Thus airplane landed in the time interval.

What is an equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two expressions 3x + 5 and 14, which are separated by the 'equal' sign.

Given equation is y = -10x + 300.

Putting x = 0 in the equation:

y = -10×0 + 300

y = 300

Putting x = 5 in the equation:

y = -10×5 + 300

y = -50 + 300

y = 250

Putting x = 8 in the equation:

y = -10×8 + 300

y = -80 + 300

y = 220

Putting x = 10 in the equation:

y = -10×10 + 300

y = -100 + 300

y = 200

Putting x = 30 in the equation:

y = -10×30 + 300

y = -300 + 300

y = 0

The height of the airplane after 5 minutes is 250 feet.

The height of the airplane after 30 minutes is 0 feet.

The altitude of the airplane decreases with time. The altitude of the airplane decreases with time. The airplane is landing in the time interval.

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Answer:

i think ur rise over run is up 1 over to the right 2

Step-by-step explanation:

i

A score on a test that can be standardized with respect to the mean and standard deviation of the data referred to as z-score.

A z-score (also known as a standard score) is a standardized form of measurement that reflects the number of standard deviations a raw score is above or below the mean of its distribution. In simple terms, a z-score represents the distance between a score and the mean in units of standard deviation.

For example, a z-score of +1.5 indicates that a score is 1.5 standard deviations above the mean, whereas a z-score of -2.0 indicates that a score is 2.0 standard deviations below the mean. The z-score transformation allows scores from different distributions to be compared and evaluated on the same scale.

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Life in the neighborhood depicted in the film "Los Olvidados" is characterized by challenging economic and social conditions.

The neighborhood in "Los Olvidados" is portrayed as a poverty-stricken area where the residents struggle to make ends meet. The film explores the lives of marginalized individuals most particularly young boys, who are caught in a cycle of poverty, violence, and neglect.

The economic conditions in the neighborhood are harsh, with limited opportunities for employment and a lack of access to basic necessities. As a result, the residents are often forced into criminal activities to survive leading to a high level of violence and crime within the community.

Moreover, the social conditions exacerbate the challenges faced by the neighborhood. There is a sense of abandonment and neglect from the government and wider society with little support or resources available to address the issues faced by the residents.

Full question:

Describes life in the neighborhood that takes place in the film Los Olvidados by Luis Buñuel, taking into account their economic and social conditions through the different activities carried out by the neighborhoods.

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Answer:

1684.8 cubic units

Step-by-step explanation:

In oblique cylinder the height (altitude) is measured from the opposite base to the base of the cylinder, but it lies outside. We can find the height using Pythagoras theorem.

       h + 7² = 13²

              h²= 169 - 49

              h² = 120

               h = √120

                h = 10.95 units

radius = r = 7 units

\(\boxed{\text{\bf Volume of oblique cylinder = $\bf\pi r^2h$} }\)

                                                    = 3.14 * 7 * 7 * 10.95

                                                    = 1684.8 cubic units

Answer:

Each of the n tests must have two success p or failure q results, they are mutually exclusive. The probability of success p of an event is fixed or constant, likewise for the probability of failure q. The tests are independent.

Step-by-step explanation: