Find the equivalent resistance between points A and B
shown in Figure 31.

Answer:

Answer is as follow:

Explanation:

With a distance of just 6,792 km, Mars is even smaller. And again, Venus would be almost Earth's double in terms of scale. It has 81 percent of the earth 's volume, while Mars has just 10 percent of the earth 's mass. Mars and Venus have very different ecosystems, and they are both very separate from Earth.

Answer:

The organisms in a population may be distributed in a uniform, random, or clumped pattern. Uniform means that the population is evenly spaced, random indicates random spacing, and clumped means that the population is distributed in clusters.

Explanation:

Answer:

4161 J/kg·°C

Explanation:

We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.

Let's first calculate the heat lost by the tea:

Q(tea) = mcΔT

Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)

Q(tea) = 6555 J

where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.

Next, let's calculate the heat gained by the milk:

Q(milk) = mcΔT

Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)

Now we can equate the two expressions:

Q(tea) = Q(milk)

6555 J = (0.02 kg)(c)(79.0°C)

Solving for c, we get:

c = 4161 J/kg·°C

Therefore, the specific heat of milk is approximately 4161 J/kg·°C.

Frequency = (number of waves) / (time)

(52waves) / (1.2 sec) = 43.333 Hz.

Answer:

a) The work done by the force is 136.400 joules.

b) The speed of the mass at the end of the 3.5 meters is approximately 11.679 meters per second.

Explanation:

The correct statement is shown below:

A 2-kg mass is initially at reat on a frictionless surface. A 45 N force acts at an angle of 30º to the horizontal for a distance of 3.5 meters:

a) Find the work done by the force.

b) Find the speed of the mass at the end of the 3.5 meters.

a) Given that a external constant force is acting on the mass on a frictionless surface, the work done by the force (\(W_{F}\)), measured in joules, is:

\(W_{F} = F\cdot \Delta s \cdot \cos \theta\) (1)

Where:

\(F\) - External constant force exerted on the mass, measured in newtons.

\(\Delta s\) - Horizontal travelled distance, measured in meters.

\(\theta\) - Direction of the external force regarding the horizontal, measured in sexagesimal degrees.

If we know that \(F = 45\,N\), \(\Delta s = 3.5\,m\) and \(\theta = 30^{\circ}\), then the work done by the force is:

\(W_{F} = (45\,N)\cdot (3.5\,m)\cdot \cos 30^{\circ}\)

\(W_{F} = 136.400\,J\)

The work done by the force is 136.400 joules.

b) The final speed of the mass at the end ot the 3.5 meter is calculated by means of the Work-Energy Theorem, which means that the work done on the mass is transformed into a translational kinetic energy. That is:

\(W_{F} = \frac{1}{2}\cdot m \cdot (v_{2}^{2}-v_{1}^{2})\) (2)

Where:

\(m\) - Mass, measured in kilograms.

\(v_{1}\), \(v_{2}\) - Initial and final speeds of the mass, measured in meters per second.

If we know that \(W_{F} = 136.400\,J\), \(m = 2\,kg\) and \(v_{1} = 0\,\frac{m}{s}\), then the final speed of the mass is:

\(\frac{2\cdot W_{F}}{m} = v_{2}^{2}-v_{1}^{2}\)

\(v_{2}^{2} =v_{1}^{2}+\frac{2\cdot W_{F}}{m}\)

\(v_{2} =\sqrt{v_{1}^{2}+\frac{2\cdot W_{F}}{m} }\)

\(v_{2} =\sqrt{\left(0\,\frac{m}{s} \right)^{2}+\frac{2\cdot (136.400\,J)}{2\,kg} }\)

\(v_{2} \approx 11.679\,\frac{m}{s}\)

The speed of the mass at the end of the 3.5 meters is approximately 11.679 meters per second.

a)K₁ = 125 J b)Speed of bullet-block system after collision is 0.1249 m/s. c) Kinetic energy of bullet-block system after collision is 0.0093 J. d)Maximum elastic potential energy stored in spring is 125 J. e)Maximum compression of spring is 0.93 m.

Energy stored as a result of applying force to deform elastic object is called elastic potential energy.

a)As we know, K₁ = (1/2)mv₁²

m is mass of the bullet and v₁ is velocity.

K₁ = (1/2)(0.001 kg)(500 m/s)² = 125 J

Therefore, the initial kinetic energy of the bullet is 125 J.

b) m₁v₁+ m₂v₂ = (m₁ + m₂)vf

(0.001 kg)(500 m/s) + (2 kg)(0 m/s) = (0.001 kg + 2 kg)vf

vf = (0.001 kg)(500 m/s)/(2.001 kg) = 0.1249 m/s

Therefore, the speed of the bullet-block system after collision is 0.1249 m/s.

c) K₂ = (1/2)(m₁ + m₂)(vf)²

K₂ = (1/2)(0.001 kg + 2 kg)(0.1249 m/s)² = 0.0093 J

Therefore,  kinetic energy of bullet-block system after collision is 0.0093 J.

d) Elastic potential energy stored in the spring is PE = (1/2)kx²

k is the spring constant and x is displacement of the block from its equilibrium position.

K₁ = PE_max

K₁ is the initial kinetic energy of the bullet.

K₁ = (1/2)m1v1² = (1/2)(0.001 kg)(500 m/s)² = 125 J

PE_max = K₁ = 125 J

Therefore, the maximum elastic potential energy stored in the spring is 125 J.

e) PE_max = (1/2)kx²

125 J = (1/2)(120 N/m)x²

x = √(125 J/(60 N/m)) = 0.93 m

Therefore, the maximum compression of the spring is 0.93 m.

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Answer:

One idea is how, on an astronomical level, the planets can be observed to spread apart continuously.

Explanation:

Throughout various studies, many have observed that the planets continuously grow distant from each other. In fact, it is observed through our technological advances that the very galaxies are slowly drifting apart. Thus, indicating there must have been some big bang to set these galaxies and planets in motion.

Answer:

Explanation:

The sentence that identifies this message as a persuasive claim is: "I propose that we meet next Monday for a demonstration. I'm sure you will be able to see the difference."

This sentence is attempting to persuade the recipient to meet with the sender for a demonstration of the speedometer's performance, which implies that the sender is making a claim about the speedometer not functioning properly.

Answer:

The woman is walking at a speed of 0.08 m/s relative to the man on the walkway.

Explanation:

Notice that for the observer, the woman is walking at 0.38 m/s, and the man (who stands still in the walkway) has a speed of 0.3 m/s.

those 0.38 m/s reported from a stationary observer are in fact the addition of two velocities: that of the walkway (0.3 m/s), and that of the woman relative to the walkway (our unknown velocity "v"):

0.38 m/s = 0.3 m/s + v

0.38 m/s - 0.3 m/s = v

v = 0.08 m/s

Answer:

F_{total}= 8.25 \(\frac{G m^2}{L^2}\),      θ’= 194º

Explanation:

To solve this problem we must use the law of universal gravitation and vectorly add the forces

         F = \(G \frac{m_{1} m_{2} }{r^{2} }\)

Let us call the mass m with the subscript 1, the mass 3m with the subscript 3 and the mass 5m with the subscript 5, the total force on particle 1 is

          F_total = F₁₅ + F₁₃

The bold are vectors, in the attachment we can see a diagram of the angles and the forces, the distance between the masses is

           r = L

let's find the force between m1 and m5

           F₁₅ = G m₁ m₅ / r²

           F₁₅ = G m 5m / L²

           F₁₅ = G 5m² / L²

this force is on the line that joins the two masses, let's use trigonometry to decompose this force

           cos 30 = F₁₅ₓ / F₁₅

           sin 30 = \(\frac{Fx_{15y} }{F_{15} }\)

           F₁₅ₓ = F₁₅ cos 30

           \(F_{15y}\) = F₁₅ sin 30

equally with the force between mass 1 and mass 3

            F₁₃ = -G 3 m² / L²

            F₁₃ₓ = F₁₃ cos 30

            F_{13y} = F₁₃ sin 30

to find the total force we can add each component independently, see attached

X axis

           F_total x = -F₁₅ₓ + F₁₃ₓ

           F_total x = -G 5m2 / L² + G 3m² / L²

           F_total x = - G 2m² / L²

Y axis  

           F_total y = - F_{15y} - F_{13y}

           F_total y = - G 5m² / L² - G 3 m² / L²

           F_toal y = - G 8 m² / L²

We can give the result in two ways

1) F_total = - G m ^ 2 / L² (2 i ^ + 8 j ^)

2) in the form of module and angle.

Let's use the Pythagorean theorem

       \(F_{total}^{2} = F_{total x}^{2} + F_{total y}^2\)

       \(F_{total}\) = \(\frac{G m^{2} }{L^2} \sqrt{(2^2 + 8^2)}\)

       F_{total}= 8.25 \(\frac{G m^2}{L^2}\)

with trigonometry

        tan θ = \(\frac{F_{total y} }{F_{total x} }\)

        tan θ = 8/2

        θ = tan⁻¹ 4

        θ = 76º

if we measure this angle from the positive side of the x axis in a counterclockwise direction

       θ’= 270 -76

       θ’= 194º

In order to calculate the resistance, we can divide the voltage and the current, according to the formula below:

Where R is the resistance (in ohm), V is the voltage (in Volt) and I is the current (in Ampere).

So, using V = 120 V and I = 60 A, we have:

Therefore the resistance is 2 ohms.

Answer:

14.7 m

Explanation:

It would fall 14.7 m in 3 s . You multiply 4.9 by 3.

- The resistance of the first resistor (R₁) is 12 Ω.

- The electromotive force (EMF) of the battery is 18 V.

- The internal resistance of the battery is 12 Ω.

To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.

Let's start by calculating the resistance of the first resistor (R₁):

1. Apply Ohm's law to find the voltage drop across the external circuit:

  V = I * R

  V = 1 A * 6 Ω

  V = 6 V

2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:

  V = E - Ir

  6 V = E - (1 A * r)   (where r is the internal resistance of the battery)

3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:

  E = 6 cells * 3 V/cell

  E = 18 V

4. Substitute the value of E in the equation from step 2:

  6 V = 18 V - r

  r = 12 Ω

Therefore, the resistance of the first resistor (R₁) is 12 Ω.

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The speed of the electron when it is 10.0 cm from the +3.00 nC charge is 30×\(10^{-2}\) meters per second.

Given :

q=3.00 nC

r=distance=10 c.m

we apply formula

Velocity of electron =qd

=10×\(10^{-2}\)×3=30×\(10^{-2}\) m/sec

The speed of electricity is determined by what you mean by the term "electricity." This is a broad term that essentially means "all things relating to electric charge." I'll presume we're talking about an electrical charge current moving through a metal wire, like the power cord of a light. Electrical currents passing through metal wires have three different velocities, all of which are physically significant:

The velocity of electron drift.

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The charge of the particle on the aluminum rod is 9.26 x 10^-6 C.

When a charged particle moves through a magnetic field, it experiences a force known as the Lorentz force. The Lorentz force is given by the equation F = qvBsinθ, where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.

In this scenario, an aluminum rod with a mass of 0.946 g is passed between the poles of a 0.41-T permanent magnet at a speed of 4.05 m/s at a 90o angle. Since aluminum is a conductor, it is expected that electrons in the metal will be free to move, allowing for a current to flow through the rod.

We can calculate the charge of the particle by using the equation F = ma, where F is the Lorentz force, m is the mass of the particle, and a is the acceleration of the particle.

The acceleration of the aluminum rod can be calculated using the equation a = F/m. Since the rod is moving at a constant velocity, the force due to air resistance can be ignored. Therefore, the force acting on the rod is solely due to the Lorentz force. Thus, we can write: a = F/m = qvBsinθ/m, Solving for q, we get: q = ma/vBsinθ = (0.946 x 10^-3 kg x 4.05 m/s)/(0.41 T x sin90o) = 9.26 x 10^-6 C.

Therefore, the charge of the particle on the aluminum rod is 9.26 x 10^-6 C.

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The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Answer:

silverware and tupperware?

Given,

The length of the string, L=0.85 m

The diameter of the string, d=6×10⁻⁴ m

The radius of the string, r=3×10⁻⁴ m

The Young's Modulus of the string, Y=190 GPa

The tension, F=66 N

a)

The Young's Modulus is given by,

Where A is the area of cross-section of the string and l is the extension produced in the string.

On rearranging the above equation,

On substituting the known values,

Thus the extension of the wire that is needed to be produced is 1.04×10⁻³ m

b)

The work done in producing the extension is given by,

On substituting the known values,

Thus the work done in producing the extension is 0.034 J

ANSWER:
C

Explanation:

Answer:

Which feature is created when a block of rock dropped down in relation to the block of rock beside it?

Explanation:

Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.

Answer: Plates shifting

Explanation: After years and years of plates colliding into solid rock, they slowly become closer together. As recent studies have shown, Africa is currently moving closer to Europe one centimeter every year (one inch every 2.5 years).

Answer:

nvudbwasivnjlscv bwbfvsz

Explanation:

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

The remaining battery capacity would be 76%, which is still above the 25% limit on discharge depth.

If the electric bicycle can go 100 miles on a full charge, and the owner wants to limit the discharge depth to 25%, then they can only use up to 25 miles of the battery's capacity before needing to recharge.

Since the owner's commute is 12 miles round trip, they can make one round trip without depleting the battery more than 25% of its capacity.

Therefore, the owner can make 2 round trips (2 x 12 = 24 miles) before needing to recharge, but they will still have some battery capacity left.

The remaining battery capacity would be (100 - 24)/100 x 100% = 76%, which is still above the 25% limit on discharge depth. So the owner could make a few more round trips before needing to fully recharge the battery.

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All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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In the Roman soldier model for refraction, the first soldier who hits the muddy stream would slow down and turn slightly. Option B is correct.

The Roman soldier model is a simplified model used to explain the behavior of light when it passes from one medium to another. In this model, a group of Roman soldiers is marching across a field towards a muddy stream. The soldiers represent light rays, and the muddy stream represents the boundary between two media with different refractive indices.

When the first soldier hits the muddy stream, they slow down because the speed of light decreases when it passes from a medium with a lower refractive index to a medium with a higher refractive index. Additionally, the soldier turns slightly because the direction of the light ray changes as it passes through the boundary between the two media. This change in direction is called refraction, and it occurs because the speed of light changes when it passes through a medium with a different refractive index.

The amount of refraction that occurs depends on the angle at which the light ray hits the boundary between the two media and the difference in refractive indices between the two media. The Roman soldier model is a useful tool for understanding the basics of refraction, but it has limitations and cannot fully explain all aspects of the phenomenon. Option B is correct.

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Answer:

1.8 ms to the left

Explanation:

Answer:1.8 ms to the left

Explanation:

(a)  the horizontal distance between the saddle and limb when the man makes his move is approximately 11.386 meters.

(b)  the man is in the air for approximately 0.843 seconds.

To determine the horizontal distance between the saddle and limb when the man makes his move, we need to consider the horizontal velocity of the man when he drops from the tree limb.

Given:

Speed of the horse (constant velocity), v = 13.5 m/s

Vertical distance between the limb and saddle, h = 3.55 m

a) To find the horizontal distance, we can use the formula:

horizontal distance = horizontal velocity × time

Since the man drops vertically, his initial horizontal velocity is zero. The only horizontal velocity he will have is due to the motion of the horse.

The time taken by the man to fall can be determined using the equation for free fall:

h = (1/2) × g × t²

Where g is the acceleration due to gravity (approximately 9.8 m/s²) and t is the time.

Rearranging the equation, we get:

t = √(2h / g)

Substituting the given values:

t = √(2 × 3.55 / 9.8) ≈ 0.843 s

Now, we can find the horizontal distance:

horizontal distance = v × t

horizontal distance = 13.5 × 0.843 ≈ 11.386 m

Therefore, the horizontal distance between the saddle and limb when the man makes his move is approximately 11.386 meters.

b) The time the man is in the air can be calculated using the same equation for free fall:

t = √(2h / g)

Substituting the given value of h:

t = √(2 × 3.55 / 9.8) ≈ 0.843 s

Thus, the man is in the air for approximately 0.843 seconds.

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