find the radius of convergence, r, of the series. [infinity] (−1)n n2xn 7n n = 1

The mass of the second box car from the calculation is  22317 Kg.

We have to note that we can be able to obtain the momentum as the product of the mass and the velocity of the object that is to be studied. In the case of the cars that we have here;

The momentum before Collison = Momentum after collision

We would then have from the question;

(10300 * 19) + (M * 0) = (10300 + M) * 6

Let the mass of the second box car be M

Then;

195700 = 61800 + 6M

M = 22317 Kg

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A Hall voltage of approximately 0.021 mV is produced when a 0.160 T magnetic field is applied across a 2.60 cm diameter aorta with a blood velocity of 64.0 cm/s.

The Hall effect refers to the phenomenon of a voltage being generated perpendicular to both the direction of current flow and an applied magnetic field. In this case, the blood flowing through the aorta acts as the current-carrying conductor, and the applied magnetic field causes a Hall voltage to be generated.

To calculate the Hall voltage, we can use the formula:

\(V_{Hall} = B * v * d\)

Where:

V_Hall is the Hall voltage,

B is the magnetic field strength,

v is the blood velocity, and

d is the diameter of the aorta.

Plugging in the given values:

B = 0.160 T

v = 64.0 cm/s

d = 2.60 cm

Converting the diameter and velocity to meters:

d = 0.0260 m

v = 0.640 m/s

Substituting the values into the formula, we get:

V_Hall = (0.160 T) * (0.640 m/s) * (0.0260 m) = 0.021 mV

Therefore, a Hall voltage of approximately 0.021 mV is produced in this scenario.

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To determine the pressure at point (0.5 m, 0) when the pressure at point B is atmospheric, we will use the hydrostatic pressure formula.

Here's the step-by-step explanation:

Step 1: Identify the given information.
- Pressure at point B (P_B) = atmospheric pressure
- Point A coordinates: (0.5 m, 0)

Step 2: Use the hydrostatic pressure formula.
The hydrostatic pressure formula is: P_A = P_B + ρgh
Where:
- P_A is the pressure at point A
- P_B is the pressure at point B
- ρ (rho) is the fluid density
- g is the acceleration due to gravity (approximately 9.81 m/s²)
- h is the height difference between point A and point B

Step 3: Determine the height difference (h) between points A and B.
Since the point A is at a horizontal position (0.5 m, 0), there is no height difference between point A and point B. Thus, h = 0.

Step 4: Substitute the values into the formula.
P_A = P_B + ρgh
P_A = atmospheric pressure + ρ × 9.81 m/s² × 0
Since h = 0, the second term becomes zero.\

Step 5: Solve for the pressure at point A.
P_A = atmospheric pressure

Therefore, the pressure at point (0.5 m, 0) is equal to the atmospheric pressure since there is no height difference between the two points.

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The measure you are referring to is called "mass."

Mass is a fundamental property of matter and is determined by the number and type of particles present in an object. It is a measure of the amount of matter an object contains. Mass is different from weight, which is the force exerted on an object due to gravity. Weight is dependent on the mass of an object and the gravitational force acting on it. The equation that relates mass and weight is W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity. On Earth, the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of an object can change depending on the gravitational pull it experiences. However, the mass of an object remains constant regardless of its location in the universe.

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The distance is 7m while the displacement is 1m. Option A

We know that the displacement is defined as the distance that is covered in a specified direction. We must note that there are two kinds of quantities that we have in physics and these are the vectors and the scalars. The vectors are the quantities that have both magnitude and direction while the scalars are the quantities that have magnitude but do not have direction.

Now we know that when we are dealing with the vectors that we must be able to consider the direction of the vector in question. This is not important when we are dealing with a scalar.

Now, distance is a vector and displacement is a scalar hence we must be able to consider the direction as we deal with the displacement of the ball.

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Answer:   PbBr4 is covalent

Answer:

Average speed = 541.67 mph

Explanation:

The value of voltage V₁ is determined as 22 V and Voltage V₃ is determined as 10 V.

To find V₁ and V₃, we need to apply Kirchhoff's laws to the circuit.

Firstly, we apply Kirchhoff's current law (KCL) at the node between the 1.1 Ω resistor and V₁. The current entering this node is I₁, and the current leaving this node is I₂.

Therefore, we have:

I₁ = I₂ = 2 A

Next, we apply KCL at the node between the 0.15 Ω resistor and V₃. The current entering this node is I₃, and the current leaving this node is 6A.

Therefore, we have:

I₃ = 6A

Now, we need to apply Kirchhoff's voltage law (KVL) to find V₁ and V₃. Starting from the top left corner of the circuit and going clockwise, we have:

-12V + 1.1Ω I₁ + V₁ - 11Ω (2A) = 0

1.1I₁ + V₁ - 34V = 0     (recall I₁ = 2A)

1.1 (2) +  V₁ - 34V = 0

22V +  V₁ - 34V = 0

V₁  =  22 V

-1.8Ω (6A) - V₃ + 0.15Ω I₃ = 0   (recall I₃ = 6A)

-9.9V - V₃  = 0

V₃ ≈ -10 V

Note that the negative sign for V₃ indicates that the voltage drop across the 1.8Ω resistor is greater than the voltage drop across the 0.15Ω resistor, resulting in a negative voltage at V₃.

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The speed in miles per hour is approximately 288.6 mph, and the speed in feet per second is approximately 678.2 ft/s.

To convert the speed from kilometers per hour to miles per hour, you can use the conversion factor of 0.6214 miles per kilometer. Multiplying the given speed of 464.5 km/hr by this conversion factor gives approximately 288.6 mph.

To convert the speed from kilometers per hour to feet per second, you need to go through two conversion steps.

First, convert kilometers per hour to meters per second by dividing by 3.6 (since there are 3.6 seconds in an hour).

Then, convert meters per second to feet per second by multiplying by 3.281 (since there are 3.281 feet in a meter).

By applying these conversion factors, the speed of 464.5 km/hr is approximately 678.2 ft/s.

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Explanation:

Δy = v₀ t + ½ at²

Δy = (0 m/s) (7.0 s) + ½ (-9.8 m/s²)(7.0s)²

= -34.3

The electric flux through the square sheet is \(4.4 * 10^4 Nm^2/C\), when a uniform electric field of magnitude \(1.1 * 10^4 N/C\) is perpendicular to a square sheet with sides 2.0 m long.

The electric flux through a closed surface is given by the formula:

\(\[ \Phi = \mathbf{E} \cdot \mathbf{A} \]\)

where \(\(\Phi\)\) is the electric flux, \(\(\mathbf{E}\)\) is the electric field, and \(\(\mathbf{A}\)\) is the area vector of the surface. In this case, the electric field \(\(\mathbf{E}\)\) is perpendicular to the square sheet, and the magnitude of the electric field is given as \(1.1 * 10^4 N/C\).

The area of the square sheet is \(\(A = (2.0 \, \text{m})^2 = 4.0 \, \text{m}^2\)). Since the electric field is perpendicular to the surface, the angle between the electric field and the area vector is 0 degrees.

Substituting the values into the formula, we have:

\(\[ \Phi = (1.1 \times 10^4 \, \text{N/C}) \cdot (4.0 \, \text{m}^2) = 4.4 \times 10^4 \, \text{N} \cdot \text{m}^2/\text{C} \]\)

Therefore, the electric flux through the square sheet is \(4.4 * 10^4 Nm^2/C\).

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Answer:

heat energy is the form of energy produced by heat

when we burn heat a type of enery is came

Answer: The 6 kg rock sitting on a 3.2 m cliff.

Explanation:

The potential energy of an object of mass M that is at a height H above the ground us:

U = M*H*g

where g is the gravitational acceleration:

g = 9.8m/s^2

Then:

"An 8 kg rock sitting on a 2.2 m cliff"

M = 8kg

H = 2.2m

U = 8kg*2.2m*9.8 m/s^2 = 172.48 J

"a 6 kg rock sitting on a 3.2 m cliff"

M = 6kg

H = 3.2m

U = 6kg*3.2m*9.8m/s^2 = 188.16 J

You can see that the 6kg rock on a 3.2m cliff has a larger potential energy.

i think the answer is 4.6 meters per second

At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.

Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:

a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.

b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.

c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.

To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.

Vertical Stress:

The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.

Vertical Stress = Unit Weight of Rock × Depth

Vertical Stress = 27 kN/m³ × 500 m

Vertical Stress = 13,500 kN/m² or 13.5 MPa

Horizontal Stress:

The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:

Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)

Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)

Horizontal Stress = 13.5 MPa × 0.6 / 0.7

Horizontal Stress = 11.57 MPa

Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.

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Answer:

θi = 47.7°

Explanation:

The formula for the refractive index is as follows:

\(n = \frac{Sin\theta_i}{Sin\theta_r}\)

where,

n = refractive index = 1.75

θi = angle of incidence = ?

θr = angle of refraction = 25°

Therefore,

\(1.75 = \frac{Sin\ \theta_i}{Sin\ 25^o} \\\\(1.75)(Sin\ \ 25^o) = Sin\ \theta_i\\\\\theta_i = Sin^{-1}(0.739)\)

θi = 47.7°

(a) Flowchart: A condenser process flowchart is provided, illustrating the inputs and outputs of the humid air stream, O₂, N₂, and the condensed liquid water. (b) Total flow rate: The total flow rate of the feed stream entering the condenser is 5.296F mol/s, considering the flow rates of water vapor, O₂, and N₂. (c) Enthalpy and heat transfer: The enthalpy changes for water vapor and O₂ are calculated, resulting in a heat transfer of -0.072 kF kW, indicating heat removal by the condenser. the heat transferred by the condenser is -0.072 kF kW.

(a) Flowchart:

(b) Total flow rate of the feed stream:

The flow rate of N2 leaving the condenser is given as 5.18 mol/s.

The flow rate of water vapor entering the condenser is 58.0 mol% of F.

80% of the above water vapor is condensed and removed, leaving 20% remaining.

So, 20% of the above water vapor remaining in the humid air after condensation is 0.116F mol/s.

The flow rate of O2 is given as 8.8 mol% of F.

The total flow rate of the feed stream is the sum of the flow rates of water vapor, O2, and N2:

Total flow rate = Flow rate of water vapor + Flow rate of O2 + Flow rate of N2

              = 0.116F + 0.088F + 5.18

              = 5.296F mol/s

(c) Inlet-Outlet Enthalpy Table:

To calculate the heat transferred by the condenser, we need to determine the enthalpy changes for water vapor (H3 to H4) and O2 (H5).

The enthalpy change for water vapor can be calculated as:

ΔH_vap = Enthalpy of water vapor at 30°C - Enthalpy of water vapor at 150°C

      = [40.657 + 0.119 × (30 - 0)] - [40.657 + 0.119 × (150 - 0)]

      = -13.607 kJ/kmol

Enthalpy of water leaving the condenser (H4) can be calculated as:

H4 = Enthalpy of water vapor at 30°C = 40.657 kJ/kmol

Enthalpy of O2 leaving the condenser (H5) can be taken as:

H5 = Enthalpy of O2 at 30°C = 0.102 kJ/kmol

The heat transferred by the condenser (q) can be calculated as:

q = Total flow rate × ΔH

 = (5.296F mol/s) × (-13.607 kJ/kmol) × 10⁻³ kW/J

 = -0.072 kF kW (where kF is the constant conversion factor 10⁶)

Therefore, the heat transferred by the condenser is -0.072 kF kW.

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Precise cutting power.

The ratio between the power used to cut the material and the rate at which metal is removed from the material

If we assume that the force needed to cut the material is F and that the cutting tool's velocity is V, then the cutting power is the product of the force and the velocity.

F times V = Power P

Let's use MRR, or metal removal rate.

F×V/MRR

If the rate of metal removal and the speed of the cutting tool are assumed to be constants, then an increase in cutting force will result in an increase in specific energy.

The particular energy will then be.

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The wavenumber and (b) the wavelength of the radiation used by an fm radio transmitter broadcasting at 92. 0 mhz will be  31.25 * \(10^{2}\) \(m^{-1}\) and 0.032 * \(10^{2}\) m respectively

Forms of electromagnetic radiation like radio waves, light waves or infrared (heat) waves make characteristic patterns as they travel through space. Each wave has a certain shape and length. The distance between peaks (high points) is called wavelength.

Wavenumber, also called wave number, a unit of frequency, often used in atomic, molecular, and nuclear spectroscopy, equal to the true frequency divided by the speed of the wave and thus equal to the number of waves in a unit distance.

wavelength = ?

frequency = 92 m Hz = 92 * \(10^{6}\) Hz

speed of light = 3 * \(10^{8}\) m/s

speed of light = frequency * wavelength

wavelength = speed of light  / frequency

                     = 3 * \(10^{8}\)  / 92 * \(10^{6}\)

                     = 0.032 * \(10^{2}\) m

wavenumber = 1 / wavelength

                      = 1 / 0.032 * \(10^{2}\) m

                      = 31.25 * \(10^{2}\) \(m^{-1}\)

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The doppler shift of a star occurs when there is a change in its frequency due to its motion. This can occur when a planet orbits a star, and its gravitational pull causes the star to wobble back and forth, resulting in a doppler shift.

The correct answer is d

Now, to answer the question at hand, which of the following will increase the doppler shift of a star? The correct answer is d) two of the above. Increasing the mass of the planet will result in a stronger gravitational pull on the star, causing it to wobble more and thus, increasing the doppler shift. Similarly, increasing the mass of the star will also result in a greater wobbling effect and hence an increased doppler shift.

On the other hand, moving the planet farther from the star (c) will have the opposite effect and decrease the doppler shift. This is because the gravitational pull between the planet and the star will be weaker, resulting in a smaller wobbling effect on the star. Therefore, option c) is not correct.

In conclusion, to increase the doppler shift of a star, one would need to increase the mass of the planet or the star, and not move the planet farther from the star.

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The coefficient of kinetic friction between a 10-kg box initially moving at 5. 31 m/s slides 4. 87 m across the floor before coming to rest is 0.418.

The Work-Kinetic energy theorem states that the work done on an object is equal to the change in its kinetic energy. In this case, the work done on the box is due to the friction between the box and the floor. The kinetic energy of the box initially is given by

KE₁ = (1/2)mv²

where m is the mass of the box and v is its velocity. The kinetic energy of the box at rest is zero, so the change in kinetic energy is -KE₁.

The work done on the box by friction is given by W = Fd, where F is the force of friction and d is the distance the box slides. Since the box comes to rest, the force of friction is equal in magnitude to the force pushing the box, which is given by F = ma, where a is the acceleration of the box and is equal to -v₂/(2d).

Therefore,

F = -ma

= -(m/2d)v₂

Substituting this expression for F into the equation for work, we get

W = -(m/2d)v²

d = -(1/2)mv²

Equating this to the change in kinetic energy, we get:

-(1/2)mv² = -(1/2)mv₂ × mu

where mu is the coefficient of kinetic friction.

Solving for mu, we get:

mu = (d/v)²

= (4.87/5.31)²

= 0.418.

Therefore, the coefficient of kinetic friction between the floor and the box is 0.418.

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Answer:false

Explanation:because it means you're pushing yourself too much and you need to use smaller weights

Answer:

86.1125 meters

Explanation:

Here is what we are given:

Initial Velocity - 0 m/s

Acceleration - 2.5 \(m/s^2\)

Time - 8.3 s

We can use this motion equation. This equation is derived from one of the common kinematics equations. It may not look familiar.

\(x=0.5t^{2}a\)

We can now substitute our values into the equation.

\(x=0.5*8.3^{2}*2.5\)

\(x=0.5*68.89*2.5\)

\(x=86.1125\)

Over time, hominin legs lengthened relative to trunk lengths which allowed for more efficient bipedal locomotion.

As hominins evolved, their legs gradually became longer compared to their trunks. This change allowed for a more efficient form of bipedal locomotion. Walking on two legs became easier and more energy-efficient, as the longer legs allowed for a longer stride length and more efficient use of muscles.

In conclusion, the lengthening of hominin legs relative to their trunks was an important adaptation that allowed for the evolution of bipedal locomotion, which was crucial for the survival and success of early human ancestors.

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Answer:

Hello! your answer is C. I did this. got 100%. Have a nice day!

Explanation:

Answer:

D Predicting the volume of a gas by its Temp and preasure

Explanation:

1: not C, took the Plato test and it was wrong

C DOES seem like the answer, but determining if an element is a metal or non-metal deals with the molecular structure of said element as well as the different components meaning its more of a chemistry based task

2: the answer choice D refers to the measurement of volume and temp, these are tied to physical traits and therefore, is a task based on the understanding of physics

*SIDENOTE* a good way to tell in this case is process of elimination, we know that option A involves a more chemical style task, referring to the measurement of the acidity of said substance, same goes for option C for it deals with the molecular structure of a solution

Answer:

The weight and the mass of an object are related because the weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. w=mg

The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.

The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.

Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:

E/B = (NC^(-1))/(NA^(-1) m^(-1))

To simplify this expression, we can cancel out the common units in the numerator and denominator:

E/B = (N/C)/(N/(A m))

Now, let's simplify further by dividing the numerator and denominator:

E/B = (N/C) * (A m/N)

Canceling out the common units:

E/B = (A m)/(C)

Therefore, the unit of E/B is A m/C (ampere meter per coulomb).

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Answer:

the skateboard pushes up

Explanation:

newton's 3rd law says for every action, there's an equal and opposite reaction, so when his feet push on the skateboard, the skateboard pushes back up.

Answer:

the skateboard pushes up

Explanation:

Answer:

sq root 2 sec.... same as initial speed