For a conductor in electrostatic equilibrium, which of the following properties are true? Choose all that apply. For a conductor in electrostatic equilibrium, which of the following properties are true? Choose all that apply. The electric field inside is zero. The entire conductor is at the same potential. Any excess charge is uniformly spread throughout the volume of the conductor.

Answer:

m = 115.36 kg = 1.15E2 kg

Explanation:

First we find a conversion between demog (dmgs) and lbs. It is given that the boy weights 86.45 lbs in real world, while he ways 7.4 dmgs in upside down world. Therefore,

7.4 dmgs = 86.45 lbs

1 dmgs = (86.45 lbs)/7.4

1 dmgs =  11.6824 lbs   ------------- equation (1)

Now, we convert the mass of demogorgon baby into lbs:

Mass of demogorgon baby = m = 21.75 dmgs

using conversion factor from equation (1)

m = (21.75 dmgs)(11.6824 lbs/1 dmgs)

m = 254.1 lbs

Now, we convert this mass into kg, by using the conversion factor given in question:

m = (254.1 lbs)(454 g/1 lbs)(1 kg/1000 g)

m = 115.36 kg = 1.15E2 kg

Answer:

250 m/s

Explanation:

Velocity (v) = Frequency (f) × Wavelength (λ)

Velocity (v) = 25 Hz × 10 m

Calculating the multiplication:

Velocity (v) = 250 m/s

The force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is 12.4 N.

Start by calculating the change in velocity (Δv) experienced by the object. This can be done by subtracting the initial velocity v₁ from the final velocity v.

Δv = v - v₁ = ((8î + 3) - 5k) - ((4î - 5) + 3k)

= 8î + 3 - 5k - 4î + 5 - 3k

= 4î - 8k + 8

Next, calculate the acceleration (a) using the formula:

a = Δv / t

where t is the time interval, given as 10 seconds.

a = (4î - 8k + 8) / 10

= (0.4î - 0.8k + 0.8) m/s²

The force (F) required to accelerate the object can be found using Newton's second law:

F = m * a

where m is the mass, given as 40 kg.

F = (40 kg) * (0.4î - 0.8k + 0.8) m/s²

= (16î - 32k + 32) N

Simplify the expression to obtain the final answer:

F = 16î - 32k + 32 N

≈ 12.4 N

Therefore, the force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is approximately 12.4 N.

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The reactive force when a fish swims through water is the force of the water on the fish. This is an example of Newton’s third law of motion which states that for every action, there is an equal and opposite reaction. The active force is the fish pushing against the water, so the reactive force would be the reverse, the equal force of the water pushing back on the fish.

Answer:

Z = 138.5 Ω

Explanation:

In a series RLC circuit the impedance is

          Z = \(\sqrt{R^2 + ( X_L - X_C)^2 }\)

the capacitive impedance is

         X_C = 1 / wC

the inductive impedance is

         X_L = wL

in this exercise indicate that C = 50 10⁻³ F, L = 0.3 H and the frequency is f=60 Hz

angular velocity and frequency are related

         w = 2π f

         w = 2π 60

         w = 376.99 rad / s

let's calculate

        Z = \(\sqrt{80^2 + ( 376.99 \ 0.3 - \frac{1}{376.99 \ 50 \ 10^{-3}} )^2 }\)

        Z = \(\sqrt{6400 + ( 113.1 - 0.053)^2}\)

        Z = √19179.6

        Z = 138.5 Ω

Answer:

C6H12O6 is the final product of Calvin cycle light independent reactions

Explanation:

* steps in Calvin cycle

: carbon fixation

: reduction

: regeneration

for C6H12O6 it requires 2 molecules of PGAL or G3P

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The temperature gradient in the flow of direction is 294525 W.

A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.

Q= T/( L/ KA)

Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)

   = 294525 W

Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.

Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.

Therefore, The temperature gradient in the flow of direction is 294525 W.

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Answer:

What are your options? also i believe the answer may be ecosystem.

Explanation:

There are both biotic and abiotic factors in an ecosystem. Be cause living organisms Are Biotic. While water and rocks are abiotic which are needed to form an ecosystem.

My discussion with the prospective avionics students would provide them with insights into the training required, specialties available and the nature of the work.

I would start my conversation with the potential students by emphasising the education needed to become a licensed avionics mechanic because I am the most seasoned educator of avionics mechanics.

I would then go on to describe the several avionics career specialties. I would mention that avionics mechanics can choose to specialize in things like flight management systems, radar systems, radio communication systems, or aircraft instruments.

I'll now go into detail about the kind of work that avionics mechanics often do. I'd want to clarify that avionics mechanics are in charge of examining, testing, mending, and maintaining avionics systems and parts.

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Answer:

Explanation:

2as=vf^2-Vi^2

vf=30 m/s

vi= 0 m/s

a=g=9.8 m/s^2

s=vf^2-Vi^2/2a

s=(30)²-(0)²/2*9.8

s=900-0/19.6

s=45.9=46 m

The energy released when 10 g of steam is spilled on the hand is approximately 25 kJ

The heat required to raise the temperature of 10 g of water from 33 °C to 100 °C is

Q₁ = m x c x ΔT

= 10 g * 4.2 * (100 °C - 33 °C)

= 2772 J

The heat required to vaporize 10 g of water at 100 °C is given by:

Q₂ = m x L

= 10 * 2.2

= 22,000 J

where L is the specific latent heat of vaporization of water

The total energy released

Q = Q1 + Q2

= 2772 J + 22,000 J

= 24,772 J

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Answer:

yea

Explanation:

Answer:

yeah i think so. but his sheild is kinda wack

The equivalent resistance of the circuit shown  is 23 ohms.

Option A is correct.

Resistance is  described as the opposition that a substance offers to the flow of electric current.

In a series circuit, all components are connected end-to-end to form a single path for current flow.

In a parallel circuit, all components are connected across each other with exactly two electrically common nodes with the same volt.

We then 1/R = 1/100 + 1/100 + 1 /(50+ 50) +  1 /(50+ 50)

I/R = 0.04

R = 25 ohms.

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Answer:

we can conclude that the component of the horizontal force and vertical force are 225.28 N and 1370 N respectively.

Coefficient of static friction = 0.26

Explanation:

Given that:

length of the ladder = 16.0 m

weight of the ladder = 520 N

angle θ = 65.0°

(a) We are to find the horizontal and vertical forces the ground exerts on the base of the ladder when an :

Force = 850 N

distance of the climber from the base of the ladder = 4.20 m

The diagrammatic illustration representing what the given information entails can be seen from the attached file below.

Let consider the Ladder being at point A with the horizontal layer of the ground.

From the whole system; the condition for the equilibrium at the point A can be computed as :

\(N_2 (16 \ Sin\ 65) = 850(4.2 \ \times Cos \ 65 )+ 520 (\dfrac{16}{2}) Cos \ 65\)

\(N_2 (14.50) = 850(1.7749 )+ 520 (8) \times 0.4226\)

\(N_2 (14.50) = 1508.665+1758.016\)

\(N_2 (14.50) = 3266.681\)

\(N_2 =\dfrac{ 3266.681}{14.50}\)

\(N_2 =225.28 \ N\)

\(N_1 = mg+F\\\)

where ;

w =mg

\(N_1 = 520+850\)

\(N_1 = 1370 \ N\)

Therefore; we can conclude that the component of the horizontal force and vertical force are 225.28 N and 1370 N respectively.

(b) If the ladder is just on the verge of slipping when the firefighter is 9.40 m from the bottom, what is the coefficient of static friction between ladder and ground?

the coefficient of static friction between ladder and ground when the firefighter is 9.40 m from the bottom can be calculated as:

\(N_2 (16 \ Sin\ 65) = 850(9.4 \ \times Cos \ 65 )+ 520 (\dfrac{16}{2}) Cos \ 65\)

\(N_2 (14.50) = 850(3.9726 )+ 520 (8) \times 0.4226\)

\(N_2 (14.50) =3376.71+1758.016\)

\(N_2 (14.50) =5134.726\)

\(N_2 =\dfrac{5134.726}{14.50}\)

\(N_2 =354.12 \ N\)

Therefore; the coefficient of the static friction is;

\(\mu = \dfrac{f_s}{N_1}\)

\(\mu = \dfrac{354.12}{1370}\)

\(\mu\)  = 0.26

Coefficient of static friction = 0.26

Answer:

No

Explanation:

because there is no pressure

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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If the resistance of the circuit were halve and the voltage remains constant, the new current in the circuit would be 240 mA.

The current in the circuit is inversely proportional to the resistance of the circuit. This implies that the increase in the resistance of the circuit decreases the current in the circuit.

V = IR

At constant voltage;

I₁R₁ = I₂R₂

when, R₂ = 0.5R₁

I₂ = I₁R₁ /R₂

I₂ = I₁R₁ /0.5R₁

I₂ = 2I₁

I₂ = 2 x 120 mA

I₂ = 240 mA

Thus, if the resistance of the circuit were halve and the voltage remains constant, the new current in the circuit would be 240 mA.

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A) To find the spring constant of the spring, we can use the conservation of energy. The spring constant of the spring is 1378.8 N/m.

B) The equilibrium point is at a height of 0 meters.

C)  The frequency of the oscillation is: f = 1/T ≈ 6.25 Hz

y(t) = 0.05 cos (2 π × 6.25 where y is in meters and t is in seconds.

The positive direction is from the equilibrium point.

a) To find the spring constant of the spring, we can use the conservation of energy. At the maximum height, the ball has no kinetic energy, so all the energy stored in the spring has been transferred to potential energy in the ball. The potential energy stored in a spring is given by:

PE = (1/2) k S^2

where k is the spring constant and S is the distance the spring is compressed. The potential energy stored in the spring must be equal to the potential energy of the ball at its maximum height. Using the given values, we can set up the equation:

(1/2) k S^2 = M g H

where M is the mass of the ball, g is the acceleration due to gravity, and H is the maximum height reached by the ball. Solving for k, we get:

k = 2 M g H / S^2

Substituting the given values, we get:

k = 2 × M × 9.81 m/s^2 × 0.35 m / (0.05 m)^2 = 1378.8 N/m

Therefore, the spring constant of the spring is 1378.8 N/m.

b) The equilibrium point of the ball when it is sitting on the spring with no forces other than gravity and the spring acting on it is the unscratched point of the spring. We can choose this point as the origin of our coordinate system, and take the upward direction as positive. Therefore, the equilibrium point is at a height of 0 meters.

c) When the ball is glued onto the spring and oscillates up and down, its motion can be described by a simple harmonic motion equation:

y(t) = A cos (ω t)

where y is the position of the ball, A is the amplitude of the oscillation, ω is the angular frequency, and t is the time. The amplitude of the oscillation is equal to the initial compression of the spring, which is 0.05 meters. The angular frequency is given by:

ω = 2 π f

where f is the frequency of the oscillation. The frequency of the oscillation is related to the period of the oscillation T by:

T = 1/f

The period of the oscillation can be found using the formula for the period of a simple harmonic motion:

T = 2 π √(m/k)

where m is the mass of the ball and k is the spring constant. Substituting the given values, we get:

T = 2 π √(0.1 kg / 1378.8 N/m) ≈ 0.16 s

Therefore, the frequency of the oscillation is:

f = 1/T ≈ 6.25 Hz

Substituting these values in the equation for the position of the ball, we get:

y(t) = 0.05 cos (2 π × 6.25 t)

where y is in meters and t is in seconds. The positive direction is upward from the equilibrium point.

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The block accelerates down the ramp due to the component of its weight that acts parallel to the ramp; this force has magnitude

(100 kg) g sin(26.6°) ≈ 438 N

(Note that the positive sign here means we take "down the ramp" to be the positive direction.)

Since the ramp is frictionless, this is the only force acting on the block in this direction. By Newton's second law, the block's acceleration is a such that

438 N ≈ (100 kg) a   ⇒   a ≈ 4.38 m/s²

The block accelerates uniformly, so that it attains a speed v as it moves 50 m such that

v² = 2a (50 m)

Solve for v :

v = √(2a (50 m)) ≈ 20.9 m/s

Answer:

B

Explanation:

Water level remains unchanged

The first thing to realize is that the buoyancy force is the same as, or equal to the weight of the wood, this same force is also the same as or equal to the weight of the water displaced by the wood. In the two cases, the weight of the wood will be unaffected nonetheless, and thus the water level will remain the same.

Therefore, the answer is B, the water level remains unchanged.

Answer:A

Explanation:I TOOK THE Test

Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.

Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.

The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.

In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.

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Answer:

24 m/s

Explanation:

V=Vi+at

given initial velocity is 0, acceleration is 2 and time is 12 sec

find final velocity by plugging in the variables into the equation above.

V=0+2x12=24m/s

Answer:

log T = 3.72 to 3.77

Explanation:

Temperature range is

T = 5200 to 5900

Take the log

So,

log T = log 5200 to log 5900

log T = 3.72 to 3.77

The acceleration of the spherical shell is determined as 6.37 m/s².

The friction force is 12.74 N.

The coefficient of friction of the surface is calculated as follows;

Fsinθ = μFncosθ

where;

mg(sin θ) = (μmg) cosθ

(sin θ) = μ cosθ

μ = sinθ/cos θ

where;

μ = tan θ

μ = tan(33)

μ = 0.65

The acceleration of the spherical shell is calculated as;

a = μg

a = 0.65 x 9.8 m/s²

a = 6.37 m/s²

The frictional force is calculated as follows;

Ff = μmg

Ff = 0.65 x 2 x 9.8

Ff = 12.74 N

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The period of the pendulum, given that the pendulum has an angular velocity about the pivot point of 0.66 radians/sec is 9.52 seconds

First, we shall list out the given parameters from the question. This is shown below:

The period and angular velocity are related according to the following formula:

ω = 2π/ T

Inputting the given parameters, we can obtain the period of the pendulum as follow:

0.66 = (2 × 3.14) / T

0.66 = 6.28 / T

Cross multiply

0.66 × T = 6.28

Divide both sides by 0.66

T = 6.28 / 0.66

T = 9.52 seconds

Thus, we can conclude that the period of the pendulum is 9.52 seconds

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