Giving brainlist SO PLZ HELP

Shawn owns a lemonade stand and is trying to calculate his earnings. The problem is that his little brother keeps giving away cups of lemonade to his friends. Every time he does this, Shawn loses money. Each cup of lemonade costs Shawn $0.30 to make, and he sells them for $1.25 each. Last week, Shawn’s brother gave away 12 cups of lemonade.

Last week Shawn sold 26 cups of lemonade. What was his total profit based on how many cups he sold and his brother gave away?

A. $40.30

B. $13.40

C. $1.55

D. $0.95

Answer:

-8

Step-by-step explanation:

8x-5y and -5y+8x is the same equation just with the terms ordered differently so both equations equal -8.

I'd enjoy a Brainliest if you think this answer is good enough for one.

Answer:

-5y+8x

Step-by-step explanation:

Nothing would change as this question isnt like 8x−5y=−8

variables y = 1.5, x = 5, hence, the value of y is 9 when x is 30

Two variables, such as x and y, are proportional to one another and their ratio is constant when they vary directly. In other words, if y and x vary directly, their relationship can be written as y = kx, where k is the proportionality constant. With the knowledge that y = 1.5 when x = 5 as provided, we can utilise this information to find the value of y when x equals 30:

1.5 = k(5) \sk = 1.5/5 \sk = 0.3

We can use the equation y = kx to get the value of y for x = 30 now that we know the value of k:

y = 0.3(30) \sy = 9

Hence, the value of y is 9 when x is 30.

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Answer:

\(b + n = 18\)

\(6b + 5n = 101\)

The level of confidence for the given confidence interval is 95% and z-score is 1.96.The calculation involves using the formula for the confidence interval and the given sample proportion and size.

We can use the formula for the confidence interval for a population proportion:

p-hat ± z*(sqrt(p-hat*(1-p-hat)/n))

Where p-hat is the sample proportion, z is the z-score for the desired level of confidence, and n is the sample size.

We're given that p-hat = 0.3 and n = 50. We're also given that the confidence interval is (.1323, .4677), which means that:

p-hat ± z*(sqrt(p-hat*(1-p-hat)/n)) = (.1323, .4677)

We can use the midpoint of the confidence interval as the point estimate for p-hat, which is (0.1323 + 0.4677) / 2 = 0.3.

Substituting the values we have into the equation, we get:

0.3 ± z*(sqrt(0.3*(1-0.3)/50)) = (.1323, .4677)

Simplifying the equation, we get:

z = 1.96

Therefore, the level of confidence for this interval is 95%, since the z-score for a 95% confidence level is 1.96.

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T he joint moment generating function of x and y is M(t1, t2) = (1/36)Σx=1^6Σz=1^6 e^(t1x + t2z)

Let X be the value of the first die, which takes on values {1, 2, 3, 4, 5, 6} with equal probability of 1/6 each. Let Y be the sum of the values of two dice, so Y takes on values {2, 3, ..., 12}.

The joint moment generating function of X and Y is given by:

M(t1, t2) = E[e^(t1X + t2Y)]

To compute this, we can use the law of total probability and conditioning on the value of X:

M(t1, t2) = E[e^(t1X + t2Y)]

= Σx P(X=x) E[e^(t1X + t2Y) | X=x]

= (1/6)Σx=1^6 E[e^(t1x + t2Y) | X=x]

Now we need to compute E[e^(t1x + t2Y) | X=x]. We can use the fact that the sum of two dice is the sum of two independent uniform random variables on {1, 2, 3, 4, 5, 6}:

E[e^(t1x + t2Y) | X=x] = E[e^(t1x + t2(x+Z))]

= E[e^(tx) e^(t2Z)]

= MZ(t2) e^(tx)

where Z is a uniform random variable on {1, 2, 3, 4, 5, 6} and MZ(t2) is its moment generating function, which is:

MZ(t2) = E[e^(t2Z)]

= (1/6)Σz=1^6 e^(t2z)

Substituting this back into the expression for M(t1, t2), we get:

M(t1, t2) = (1/6)Σx=1^6 E[e^(t1x + t2Y) | X=x]

= (1/6)Σx=1^6 MZ(t2) e^(tx)

= (1/6)Σx=1^6 [(1/6)Σz=1^6 e^(t2z)] e^(tx)

Simplifying the expression, we get:

M(t1, t2) = (1/36)Σx=1^6Σz=1^6 e^(t1x + t2z)

This is the joint moment generating function of X and Y.

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The first term of the arithmetic sequence is 27.

Arithmetic sequence is a sequence of numbers where the numbers are arranged ion a definite order such that the difference of two consecutive numbers is a constant. This constant of difference is called common difference which is commonly denoted by the letter 'd'.

Given that,

Second term of arithmetic sequence, a₂ = 24

Common difference, d = -3

Now, common difference is the difference of the two consecutive terms.

a₂ - a₁ = d

24 - a₁ = -3

-a₁ = -3 - 24

-a₁ = -27

a₁ = 27

Hence the first term is 27 for the sequence.

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Answer:  the future value of $7,000, given that it will be invested for five years at an annual interest rate of 6 percent, would be approximately:

a. $8,677.10 when compounded annually.
b. $8,774.04 when compounded semiannually.
c. $8,802.77 when compounded bimonthly.

To calculate the future value of $7,000, we need to use the formula for compound interest:

Future Value = Principal * (1 + Rate/Compounding Period)^(Compounding Period * Time)

a. For the first part of the question, we need to calculate the future value of $7,000 when invested for five years at an annual interest rate of 6 percent. Since the interest is compounded annually, the compounding period is 1 year.

Using the formula, we have:

Future Value = $7,000 * (1 + 0.06/1)^(1 * 5)

Simplifying this calculation:

Future Value = $7,000 * (1 + 0.06)^5

Future Value = $7,000 * (1.06)^5

Future Value ≈ $8,677.10

b. For the second part, we need to recalculate the future value using different compounding periods:

1) Semiannually:
In this case, the compounding period is 0.5 years. Using the formula:

Future Value = $7,000 * (1 + 0.06/0.5)^(0.5 * 5)

Simplifying this calculation:

Future Value = $7,000 * (1 + 0.12)^2.5

Future Value ≈ $8,774.04

2) Bimonthly:
In this case, the compounding period is 1/6 years (since there are 12 months in a year and 2 months in each compounding period). Using the formula:

Future Value = $7,000 * (1 + 0.06/1/6)^(1/6 * 5)

Simplifying this calculation:

Future Value = $7,000 * (1 + 0.36)^5/6

Future Value ≈ $8,802.77

So, the future value of $7,000, given that it will be invested for five years at an annual interest rate of 6 percent, would be approximately:

a. $8,677.10 when compounded annually.
b. $8,774.04 when compounded semiannually.
c. $8,802.77 when compounded bimonthly.

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Answer:

8

Step-by-step explanation:

2x = 16

2x/2 = 16/2

x = 8

Answer:

2 time 4 gives you 16

plz check

Answer:

Area = x^2 + 4x

Step-by-step explanation:

Width: x

Length x + 4

Area = x (x + 4)

The price at which they will sell the car is $34.30.

A discount reduces the carrying value of the model car. If the price of the car is discounted by 5% everyday, it means that the car decreases at an exponential rate. When there is an exponential decrease, the value of the car falls faster with the passage of time.

Exponential functions have this form \(e^{x}\)

Where:

The formula that can be used to determine the price at which they will sell the car is:

Selling price = initial value x (1 - discount rate)^number of days

$40 x (1 - 0.05)^3

$40 x 0.95^3 = $34.30

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Answer:

B. 4 - 2√10

Step-by-step explanation:

This is the value of x when you plug it into the equation.
Hope this helped!

The future value of the loan is approximately $10,070.29.

To find the interest on the loan, we can use the formula:Interest = Principal × Rate × Time

Given:

Principal (P) = $6000

Rate (R) = 8% per year (0.08 as a decimal)

Time (T) = 6 months (0.5 years)

Plugging in the values into the formula:

Interest = $6000 × 0.08 × 0.5 = $240

Therefore, the interest on the loan is $240.

To find the future value of the loan, we can use the formula for simple interest:

Future Value = Principal + Interest

Given:

Principal (P) = $6000

Interest = $240

Plugging in the values into the formula:

Future Value = $6000 + $240 = $6240

Therefore, the future value of the loan is $6240.

For the second scenario:

Given:

Principal (P) = $9275

Rate (R) = 7.57% per year (0.0757 as a decimal)

Time (T) = 13 months (13/12 years)

To find the interest, we can use the same formula:

Interest = Principal × Rate × Time

Plugging in the values into the formula:

Interest = $9275 × 0.0757 × (13/12) = $795.29

Therefore, the interest on the loan is approximately $795.29.

To find the future value of the loan, we can use the same formula as before:

Future Value = Principal + Interest

Plugging in the values into the formula:

Future Value = $9275 + $795.29 = $10,070.29

Therefore, the future value of the loan is approximately $10,070.29.

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The simplified form of 4\(\sqrt[4]{6a}\) - 3\(\sqrt[4]{6a}\) is \(\sqrt[4]{6a}\)

Surds are the square roots of irrational numbers.

They usually have the square roots signs in them. Examples of surds are the square roots of prime numbers.

\(4\sqrt[4]{6a} - 3\sqrt[4]{6a}\)

Since the surds are the same, we factorize

\(\sqrt[4]{6a}(4 - 3)\)

= \(\sqrt[4]{6a}(1)\)

= \(\sqrt[4]{6a}\)

In conclusion, the simplified form of the surd is \(\sqrt[4]{6a}\)

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The probability that the sample mean will be within plus minus 2 of the population mean if the sample size is n = 100 between z-scores of 0 and 2.5 using a z-table.

The standard deviation of the sample distribution, commonly known as the standard error, can be computed using the formula given that the population mean is 100 and the standard deviation is 16:

Standard Error = Standard Deviation / sqrt(sample size)

Let's determine the likelihoods for sample sizes of n = 100 and n = 400:

For n = 100:

Standard Error = 16 / sqrt(100) = 16 / 10 = 1.6

We can determine the z-scores for the upper and lower boundaries to establish the likelihood that the sample mean will be within plus or minus 2 of the population mean:

Lower Bound z-score = (Sample Mean - Population Mean) / Standard Error

Lower Bound z-score = (100 - 100) / 1.6

Lower Bound z-score = 0

Upper Bound z-score = (Sample Mean - Population Mean) / Standard Error

Upper Bound z-score = (104 - 100) / 1.6

Upper Bound z-score = 4 / 1.6

Upper Bound z-score = 2.5

We can calculate the region under the normal distribution curve between z-scores of 0 and 2.5 using a z-table or statistical software. This shows the likelihood that the sample mean will be within +/- 2 standard deviations of the population mean.

For n = 400:

Standard Error = 16/√400

Standard Error = 16/20

Standard Error = 0.8

We determine the z-scores by following the same procedure as above:

Lower Bound z-score = (Sample Mean - Population Mean) / Standard Error

Lower Bound z-score = (100 - 100) / 0.8

Lower Bound z-score = 0

Upper Bound z-score = (Sample Mean - Population Mean) / Standard Error

Upper Bound z-score = (104 - 100) / 0.8

Upper Bound z-score = 4 / 0.8

Upper Bound z-score = 5

Once more, we may determine the region under the normal distribution curve between z-scores of 0 and 5 using a z-table or statistical software.

A larger sample size, like n = 400, has the benefit of a lower standard error. The sampling distribution of the sample mean will be more constrained and more closely resemble the population mean if the standard error is less.

As a result, there is a larger likelihood that the sample mean will be within +/- 2 of the population mean. In other words, the estimate of the population mean gets more accurate and dependable as the sample size grows.

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Answer:

BC=AB

Step-by-step explanation:

This triangle is isosceles that it means has two equal ribs. BC=AB so BC= 4x-14. I think it is in the right form. It depends on how you named the triangle. The important thing is that two equal ribs are those ribs that are in front not the base.

9514 1404 393

Answer:

  3

Step-by-step explanation:

The common difference of an arithmetic sequence is the slope of the equation that describes it. The slope formula is useful in this case:

  m = (y2 -y1)/(x2 -x1)

  m = (219 -213)/(4 -2) = 6/2 = 3

The common difference of the corresponding arithmetic sequence is 3.

The gravitational potential energy of the stone-Earth system can be calculated before the stone is released, after it reaches the bottom of the well, and the change in gravitational potential energy during the process.

Gravitational potential energy is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

(a) Before the stone is released, it is held 11 m above the top edge of the well. The mass of the stone is 0.25 kg, and the acceleration due to gravity is approximately 9.8 m/s². Using the formula, the gravitational potential energy is calculated as PE = (0.25 kg)(9.8 m/s²)(11 m).

(b) After the stone reaches the bottom of the well, its height is 7.3 m. Using the same formula, the gravitational potential energy at this point is given by PE = (0.25 kg)(9.8 m/s²)(7.3 m).

(c) The change in gravitational potential energy can be determined by subtracting the initial potential energy from the final potential energy. The change in gravitational potential energy is equal to the gravitational potential energy after reaching the bottom of the well minus the gravitational potential energy before the stone was released.

By calculating these values, we can determine the specific numerical values for (a), (b), and (c) based on the given data.

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Answer: m∠CBD = 98°

Step-by-step explanation:

Solution:

Note that:

Looking at the notes, we can conclude that ∠K measures 150° because of the equation (∠L = ∠K).

Hoped this helped!

Alternative angles have sum 180°

\(\\ \rm\hookrightarrow 150+x=180\)

\(\\ \rm\hookrightarrow x=180-150\)

\(\\ \rm\hookrightarrow x=30\)

The total area of the figure in this problem is given as follows:

41.3 ft².

The area of the composite figure is given by the sum of the areas of all the parts that compose the figure.

The figure in this problem is composed as follows:

Then the area of the triangle is given as follows:

At = 0.5 x 6 x 3 = 9 ft².

The area of the semicircle is given as follows:

Ac = π x 3² = 28.3 ft².

The area of the square is given as follows:

As = 2² = 4 ft².

Then the total area of the figure is given as follows:

9 + 28.3 + 4 = 41.3 ft².

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Answer:

(3,8)

Step-by-step explanation:

First, you need to graph a triangle using the points given.

Then reflect across y = x

R is (3,0) which when reflected across y = x is (0,3)

S is (3,3) which when reflected across y = x is (3,3)

R is (4,0) which when reflected across y = x is (0,4)

Answer:

C

Step-by-step explanation:

Answer:

The answer is A

Step-by-step explanation: took it on times4learning math assignment

Answer:

144

Step-by-step explanation:

Hope this helps! God bless you!

Answer:

The farmer can achieve a maximum area of 50 square yards with 20 yards of fencing.

Step-by-step explanation:

Given that farmer shall construct a rectangular fenced-in area and a side of the barn is one side of such area, the needed length of fencing is represent by the following perimeter equation (\(p\)), measured in square yards:

\(p = 2\cdot l + w\)

Where:

\(l\) - Length of the rectangle, measured in yards.

\(w\) - Width of the rectangule (side of the barn), measured in yards.

In addition, the equation of the fenced-in area (\(A\)) is:

\(A = w\cdot l\)

If \(p = 20\,yd\), equation of area is now simplified as follows:

\(A = (20\,yd - 2\cdot l)\cdot l\)

\(A = 20\cdot l - 2\cdot l^{2}\)

The value of \(l\) associated with the maximum area is obtained with the help of First and Second Derivative Tests. Firstly, first and second derivatives of the area function are determined:

\(A' = 20 - 4\cdot l\)

\(A'' = -4\)

Let equalize first equation to zero, second derivative indicates that critical value follows to an absolute maximum. Hence:

\(20-4\cdot l = 0\)

\(l = 5\,yd\)

The width of the rectangle is: (\(p = 20\,yd\) and \(l = 5\,yd\))

\(w = p - 2\cdot l\)

\(w = 20\,yd - 2\cdot (5\,yd)\)

\(w = 10\,yd\)

And finally, the maximum area she can achieve is:

\(A = (5\,yd)\cdot (10\,yd)\)

\(A = 50\,yd^{2}\)

The farmer can achieve a maximum area of 50 square yards with 20 yards of fencing.

Two steps that will complete the list correctly are:

4. The original measurement should be multiplied by the conversion factors.

5. Verify that it makes sense.

A conversion factor can be used to switch from one set of units to another by multiplying or dividing a number. When a conversion is necessary, the appropriate conversion factor to an equivalent value must be applied.

Let's use an example of converting from inches to centimeters to address this query.

10 inches should be converted to cm.

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Answer:

d

Step-by-step explanation:

The length of the QR is 16 cm when PQR ~MNO

In the given question, it is given that two similar triangles as PQR ~MNO

Then, the corresponding sides will be in equal proportion to each other as follows

PQ / MN = PR / MO = QR / NO

We need to find the length of the side QR

As above relations are given,

\(\frac{PQ}{MN}\) = \(\frac{PR}{MO}\) = \(\frac{QR}{NO}\)

\(\frac{30}{10}\) = \(\frac{5x + 7}{x+5}\) = \(\frac{4x}{\frac{16}{3} }\)

Equating all the fractions, equal to each we'll find

\(\frac{5x + 7}{x+5}\) = \(\frac{30}{10}\)

5x + 7 = 3(x +5)

5x + 7 = 3x + 15

2x = 8

x = 4

We know that, the length of the QR = 4x cm = 4 x 4 cm = 16 cm

Therefore, the length of the QR is 16 cm when PQR ~MNO

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The following equation based on the tangent function tan(60.5°) = (36 + x) / 1.4. the tangent function tan(60.75°) = w / 30   and   tan(30.43°) = w / 30.  If the height of the chimney is less than 100 m, it does not meet the pollution control norms. the height of the building:

height of the building = tan(θ) * d

Q1. To find the distance the boy walked towards the building, we can use trigonometric concepts. Let's denote the distance the boy walked as 'x'.

From the given information, we can form a right triangle where the boy's height (1.4 m) is the opposite side, the height of the building (36 m) is the adjacent side, and the angle of elevation changes from 30.3° to 60.5°.

Using trigonometry, we can set up the following equation based on the tangent function:

tan(60.5°) = (36 + x) / 1.4

Solving this equation for 'x', we can find the distance the boy walked towards the building.

Q2. To find the width of the river, we can use the concept of angles of depression and trigonometry. Let's denote the width of the river as 'w'.

Based on the given information, we have two right triangles. The height of the man on the tree (30 m) is the opposite side, and the angles of depression (60.75° and 30.43°) represent the angles between the line of sight from the man to the feet of the poles and the horizontal line.

Using trigonometry, we can set up the following equation based on the tangent function:

tan(60.75°) = w / 30   and   tan(30.43°) = w / 30

By solving this system of equations, we can determine the width of the river.

Q3. To find the height of the chimney, we can use the concept of angles of elevation and depression. Let's denote the height of the chimney as 'h'.

Based on the given information, we have a right triangle. The height of the tower (45 m) is the opposite side, the angle of elevation (56°) is the angle between the line of sight from the top of the tower to the top of the chimney and the horizontal line, and the angle of depression (33°) is the angle between the line of sight from the top of the tower to the foot of the chimney and the horizontal line.

Using trigonometry, we can set up the following equation based on the tangent function:

tan(56°) = h / 45   and   tan(33°) = h / 45

By solving this system of equations, we can determine the height of the chimney. If the height of the chimney is less than 100 m, it does not meet the pollution control norms.

Q4. The practical problem chosen is determining the height of a building using the concept of angle of elevation.

Solution: To determine the height of the building, we need a baseline distance and the angle of elevation from a specific point of observation. Let's assume we have the baseline distance 'd' and the angle of elevation 'θ' from the observer's eye to the top of the building.

Using trigonometry, we can set up the following equation based on the tangent function:

tan(θ) = height of the building / d

By rearranging the equation, we can solve for the height of the building:

height of the building = tan(θ) * d

To solve the practical problem, we need to measure the baseline distance accurately and measure the angle of elevation from a suitable location. By plugging in the values into the equation, we can determine the height of the building.

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The quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

The time taken by substance to reduce to its half of its initial concentration is called half life period.

We will use the half- life equation N(t)

N e^{(-0.693t) /t½}

Where,

N is the initial sample

t½ is the half life time period of the substance

t2 is the time in years.

N(t) is the reminder quantity after t years .

Given

N = 13g

t = 350 years

t½ = 1599 years

By substituting all the value, we get

N(t) = 13e^(0.693 × 50) / (1599)

= 13e^(- 0.368386)

= 13 × 0.691

= 8.98

Thus, we calculated that the quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

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Answer:

that's fake right?

Step-by-step explanation:

¯\_(ツ)_/¯