hello
let the output be represented by y and the input be represented by x
"the output is 4 greater than twice the input" can be written as
\(2y=x+4\)the statement can be written as 2y = x + 4
please help 3/4 divided by 1/8
Answer:
6
Step-by-step explanation:
please help 3/4 divided by 1/8
3/4 : 1/8 =
3/4 x 8 =
24/4 =
6
Find the recursive rule:
420, 84, 16.8, 3.36, …
Answer:
It would be times 5 so 3.36×5=16.8 then 16.8×5=84 then 84×5=420
The function F is given in 3 equivalent forms.
Which form most quickly reveals the y intercept?
Look at image below
Part 2: what is the y intercept?
The form that most quickly reveals the y intercept is
B f(x) = 1/2 x² - 5x + 21/2The y intercept is (0, 21/2)
What is y-intercept?The y-intercept is the point where a function or a curve intersects the y-axis. In other words, it is the value of the dependent variable (y) when the independent variable (x) is equal to zero.
In the form, f(x) = 1/2 x² - 5x + 21/2 it is easier to see that eliminating x by plugging in 0 leaves 21/2 which is the y intercept
hence we can easily say that the y intercept is (0, 21/2)
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Solve the compound inequality.
2(x - 2) + 7> -1 and 5 – 4x > 9
Decide which of the two given prices is the better deal and explain why. You can fill a 12-gallon tank of gas for $39.43 or buy gas for $3.20/gallon.
Answer:
$3.20/gallon
Step-by-step explanation:
to fill up your tank at $3.20/gallon only costs $38.40
Please i need the answer fast k12
(A) The range and IQR for boxplot 1 is 10 and 6 respectively.
(B) The range and IQR for boxplot 2 is 12 and 7 respectively.
What is the IQR?The interquartile range defines the difference between the third and the first quartile.
The formula for the interquartile range is given below.
Interquartile range = Upper Quartile – Lower Quartile = Q3 – Q1
What is the range?The range is the difference between the lowest and highest values.
The formula for the interquartile range is given below.
Range = Maximum – Minimum
(A) For boxplot 1, we need to find the range and IQR from the given data set.
So, let 34 be the maximum and 24 be the minimum.
\(\text{Range}=\sf 34-24\)
\(\text{Range}=\sf10\)
Therefore, the range is 10.
Now time to find the IQR.
So, let 33 be Q3 and 27 be Q1.
\(\text{IQR}=\sf 33-27\)
\(\text{IQR}=\sf 6\)
Therefore, the IQR is 6.
(B) Now for boxplot 2, we will do the same thing as from part A.
Let's find the range.
So, let 24 be the maximum and 12 be the minimum.
\(\text{Range}=\sf 24-12\)
\(\text{Range}=\sf12\)
Hence, the range is 12.
Now for the IQR.
So, let 22 be Q3 and 15 be Q1.
\(\text{IQR}=\sf 22-15\)
\(\text{IQR}=\sf 7\)
Hence, the IQR is 7.
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Help me with 15 :)plz
find the square root of 7
The value of the square root of 7 is,
⇒ √7 = 2.645
What is mean by Function?A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).
WE have to given that;
To find the value of the square root of 7 .
Since, the square root of 7 is,
⇒ √ 7
⇒ 2.645
Thus, The value of the square root of 7 is,
⇒ √7 = 2.645
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30 POINTS FOR JUST ONE QUESTION!
Answer:
The answer would be D. $19.33
For the quadratic function f(x) = x2 + 6x +11:
a. Use the idea of completing the square to write it in graphing form.
Step-by-step explanation:
Make f(x) = 0
\( {x}^{2} + 6x + 11 = 0\)
First, we move the constant term to the right hand side of the equality sign.\( {x}^{2} + 6x = - 11\)
Then, we half the coefficient of x and square our result.\(( \frac{6}{2} ) ^{2} = 3 ^{2} = 9\)
Now, we add the result to the both sides of the equation.\( {x}^{2} + 6x + 9 = - 11 + 9\)
We can see that x²+6x+9 = (x+3)² {Try factorizing}Therefore,(x+3)²= -2
(x+3)²+2= 0
f(x)= (x+3)²+2
Which is the f(x) in graphing form.
Lesson 1.17
Quadrilateral ABCD is congruent to quadrilateral
A'B'C'D'. Describe a sequence of rigid motions that
takes A to A', B to B', C to C', and D.
please im begging you please help!!!
Answer:
You will translate A up until it is equal with A', then you will reflect the figure over the line of symmetry that will be half way between line segments CD and C'D'
Step-by-step explanation:
I am not sure if the polygon is drawn on a coordinate plane. I cannot see any horizontal or vertical lines to tell you exactly how many units to move up.
b) Graph the probability distribution using a histogram and describe its shape
c) Find the probability that a randomly selected student is less than 20 years old.
d) Find the probability that a randomly selected student's age is more than 18 years
old but no more than 21 years old.
LOOK AT SCREENSHOT FOR FULL QUESTION
The peak of the histogram appears at age 19, and its shape is approximately symmetric. This indicates that the students' ages are evenly distributed, with a mean age of around 19.
What is probability?Probability is a gauge of how likely an occurrence is to take place. It is expressed as a number between 0 and 1, with 0 designating an impossibility and 1 designating a certainty for the occurrence.
For instance, if you flip an impartial coin, you could get either heads or tails. Because there is an equal possibility that the coin will land on its head or tails, the probability of getting heads on a single toss is \(0.5\) , or 50%.
Given
c) To determine the likelihood that a pupil chosen at random is under 20 years old, we must add the probabilities of the top two bars in the histogram. Following are the results: P(age 20) = P(age = 17) + P(age = 18) \(= 0.05 + 0.15 = 0.2\)
The likelihood that a pupil chosen at random is under \(20\) years old is therefore \(0.2, or 20%\) .
d) We must add the probabilities of the bars between the ages of 19 and 21, inclusive, in order to determine the likelihood that an arbitrarily chosen student is older than 18 but not older than 21. P(18 age 21) equals P(age = 19) + P(age = 20) + P(age = 21) \(= 0.35 + 0.25 + 0.1 = 0.7\) .
Therefore, \(0.7, or 70%\) , of an arbitrarily chosen student having an age that is greater than 18 but not greater than \(21\) .
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The height of a right triangular prism is 1 5/6 inches each side of the triangular base measures 10 inches and the height of the bases eight2 over 3 inches the triangular prism is place to top of cube whose side measures 10 inches so that one of the triangular prisms bases lies completely on one side of the cube what is the surface area of the solid formed
The surface area of the solid formed is approximately, 598.3 in².
What is the Surface Area of a Right Triangular Prism?Surface area of the solid is the area covered by the solid all round.
The given parameters are:
Height of the prism (L) = 1 5/6 = 1.83 in.Side of base (s1) = 10 in.Side of base (s2) = 10 in.Side of base (s3) = 8 2/3 = 8.67 in.base (b) = 10Height (h) = 8.67 in.a = 10 in.Surface area of the solid formed = 5(10×10) + (0.5×10×8.67) + 3(10×1.83) = 598.3 in²
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Polygon A is similar to Polygon B.
Find the perimeter of Polygon B.
24
A
PA = 128
15
B
PB = [?]
Answer:
\(P_{B}\) = 80
Step-by-step explanation:
given 2 similar figures with ratio of sides = a : b
then ratio of perimeters is also a : b
here ratio of sides = 24 : 15 = 8 : 5
the ratio of perimeters is also 8 : 5
then by proportion
\(\frac{ratioA}{P_{A} }\) = \(\frac{ratioB}{P_{B} }\) , that is
\(\frac{8}{128}\) = \(\frac{5}{P_{B} }\) ( cross- multiply )
8 \(P_{B}\) = 5 × 128 = 640 ( divide both sides by 8 )
\(P_{B}\) = 80
Ms. Gallegos burns 236 calories riding her bike each hour. She wants to burn more than 590 calories riding her bike at the same rate.
Which inequlity represents all possible values for t, the number of hours Ms. Gallegos must ride her bike to burn more than 590 calories?
A.
t > 2.5
B.
t < 2.5
C.
t > 0.4
D.
t < 0.4
Answer:
Bro the answer is A
Step-by-step explanation:
trust me straight 100% brain dead person
In the triangle below, with right angle , suppose that and .
Find the degree measure of each angle in the triangle.
Answer:
G= 60.5
E= 70.9
F= 90
........
.......
Last year, Manuel deposited $7000 into an account that paid 11% interest per year and $1000 into an account that paid 5% interest per year. No withdrawals were made from the accounts. Answer the questions below. Do not do any rounding. (a) What was the total interest earned at the end of year? (b) What was the percent interest for the total deposited?
Answer:
The total interest earned at the end of the year was $ 820, and the interest generated by the total deposited was 10.25%.
Step-by-step explanation:
Given that last year, Manuel deposited $ 7000 into an account that paid 11% interest per year and $ 1000 into an account that paid 5% interest per year, and no withdrawals were made from the accounts, to determine what was the total interest earned at the end of year and what was the percent interest for the total deposited, the following calculations must be performed:
7000 x 0.11 + 1000 x 0.05 = X
770 + 50 = X
820 = X
8000 = 100
820 = X
820 x 100/8000 = X
82,000 / 8,000 = X
10.25 = X
Therefore, the total interest earned at the end of the year was $ 820, and the interest generated by the total deposited was 10.25%.
4x^3 +5x+10 divided by 2x+3 equals
Step-by-step explanation:
step 1. what is the question? simplify the following expression (4x^3 + 5x + 10)/(2x + 3)? let's simplify with division.
2x^2 + 3x - 2
_________________
step 2. 2x + 3. / 4x^3 + 5x + 10
4x^3 + 6x^2
6x^2 + 9x
-4x + 10
-4x - 6.
R16
step 3. the answer is 2x^2 + 3x -2 R16 or 2x^2 + 3x -2 + 16/(2x + 3).
Answer:
Step-by-step explanation:
___2x²_- 3x_+ 7____________
2x + 3 I 4x³ + 0x² + 5x + 10 1) 4x³ ÷ 2x = 2x²
4x³ + 6x² (2x + 3)*2x² = 2x * 2x² + 3*2x²
- - = 4x³ + 6x²
-6x² + 5x 2) -6x²÷ 2x = -3x
-6x² -9x (2x + 3)*(-3x) =2x*(-3x) +3*(-3x)
+ + = -6x² - 9x
14x + 10 3) 14x ÷ 2x = 7
14x + 21 (2x + 3) *7 = 14x + 21
- -
-11
Quotient = 2x² - 3x + 7
Remainder = -11
Frank and Carl do some fundraising for their scout group. Together they raised 237 dollars. If Frank raised m dollars, and Carl raised
137 dollars:
Write an equation that represents the relationship between the amounts each contributed. (Note that we are not looking to solve for m yet.)
Answer:
237 = m + 137
this is the equation showing the relationship
5×100+4×10+6×1+2×(
10
1
)+8×(
1000
1
)
Answer:
5×100+4×10+6×1+2×(101)+8×(10001) =
80756
7k-k+19 Combine like terms
Step-by-step explanation:
7k-k+19
6k+19 should be fine
Steps to solve:
7k - k + 19
~Combine like terms
6k + 19
Best of Luck!
100 POINTS!!!!!!!!!!!!!!1 PLEASE SOLVE THESE PROBLEMS QUICKLY WITH AN EXPLANATION
In triangle ABC, if m∠B = 90°, BH = AH, and the ratio of m∠A to m∠C is 1:2, then m∠BHA = 120° (C).
In the next given equilateral triangle ABC, y = 70°.
Finding m∠BHA:
In triangle ABC, it is given that,
∠B = 90°
And m∠A : m∠C = 1:2
Let us assume m∠A is x. Then, m∠C = 2x
According to the angle sum property of a triangle,
∠A + ∠B + ∠C = 180°
90° + x + 2x = 180°
90° + 3x = 180°
3x = 90°
x = 30°
⇒ In triangle ABC, ∠A = 30° and ∠C = 60°
Now, in triangle AHB, it is also given that,
BH = AH
⇒ ∠ABH = ∠A = 30°
Thus, according to the angle sum property of a triangle,
∠ABH + ∠A + ∠BHA = 180°
30° + 30° + ∠BHA = 180°
∠BHA = 180° - 60°
∠BHA = 120°
Finding y in the Second Triangle:
Since triangle ABC is equilateral,
∠A = ∠B = ∠C = 60°
∴ x + 2x + 3x = 60°
6x = 60°
x = 10°
In triangle ABD, using angle sum property of triangle,
x + ∠B + ∠BDA = 180°
10° + 60° + ∠BDA = 180°
∠BDA = 180° - 70°
∠BDA = 110°
Now, since, ∠BDA and y are linearly adjacent angles,
∠BDA + y = 180°
110° + y = 180°
y = 180° - 110°
y = 70°
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Candace bought 14 sacks of dog food to share equally among three dog shelters. How much dog food does each shelter get?
Answer:
4 sacks
Step-by-step explanation:
Solve for 8. 0.5s +1 = 7 + 4.5s
Answer:
s=-1.5
Step-by-step explanation:
We need to isolate the variable.
1. Subtract 4.5s from both sides
2. We now have the equation -4s+1=7
3. Subtract 1 from both sides
4. -4s=6
5. Divide both sides by -4
6. The answer would be s=-1.5
Each side length of a triangle is 4 cm. What type of triangle is it?
☐ right
□acute
Equilateral
Isosceles
Answer: Equilateral
Step-by-step explanation:
It's equilateral because it says that each side of the triangle is 4cm. In simple words, all the sides of triangle are equal. Such a triangle is called an equilateral triangle.
Hope you understood.
The area of a parallelogram is 315 square inches. If the parallelogram has a base length of 21 inches, what is the height of the parallelogram?
Answer:
Area of parallelogram is =base *height
Given area of parallogram is 315square inches
Therefore, area of parallogram =b*h
Therefore area of parallogram =21*h
Therefore, 315=21*h
Therefore 315/21=h
Therefore, 15 =height
Height of parallogram is 15 inches
If you are helped with my answer pls tag me brianliest
THANK YOU...........
Question 1 of 10
Which expressions are equivalent to the one below? Check all that apply.
log 2-log 4
A. log(¹)
B. log 1
C. log(2) + log(¹)
D. log 2
"The correct option is C." The only expression that is equivalent to log 2 - log 4 is option C: log(2) + log(¹).
The expression "log 2 - log 4" can be simplified using logarithmic properties. Specifically, the property states that "log(a) - log(b) = log(a/b)." Applying this property to the given expression, we have "log 2 - log 4 = log(2/4) = log(1/2) = -log(2)."
The expression log 2 - log 4 can be simplified using logarithmic properties. Let's analyze each option:
A. log(¹): This expression is not equivalent to log 2 - log 4. The logarithm of 1 is 0, but it does not cancel out the terms log 2 and log 4.
B. log 1: This expression is equivalent to 0, but it does not cancel out the terms log 2 and log 4.
C. log(2) + log(¹): This expression is equivalent to log 2 + 0, which simplifies to just log 2. It is not equivalent to log 2 - log 4.
D. log 2: This expression is not equivalent to log 2 - log 4. It represents the logarithm of 2, but it does not account for the subtraction of log 4.
Option C, "log(2) + log(¹)," again uses an exponentiation notation without an exponent and is not a valid mathematical expression.
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what is 14 divided by 3
Answer:
4.666667
or round it to 4.67
los tornillos vienen en bolsa de 100. cada 10 bolsas se empaqueta una caja. las cajas se embalan de a 10 en cajones y los cajones se guardan de a 10 en un contenedor para ser transportados. ¿ cuantos tornillos lleva un contenedor?
Answer:
lleva 10 000 tornillos un contenedor
Step-by-step explanation:
PLEASE HELP ASAP!!!
Makaila would like to walk at least 70 blocks over the next five days. She would like to increase the number of blocks she walks by two per day for each of the second and third days. Then, she wishes to level off so that the fourth and fifth days she walks only as far as she did on the third day.
a. If the amount that Makaila walks the first day is represented by x, then write expressions for each distance she walks the other four days.
Day 1= x Day 2 = Day 3 = Day 4 = Day 5 =
b. Find all possible values that Makaila could walk on the first day to reach her goal.
c. Assuming that Makaila walks a whole number of blocks on Day 1, what is the fewest number of blocks she could walk on this day and still meet her goal.
A) First day = x blocks
Second day = x + 2 blocks
Third day = x + 4 blocks
Fourth day = x + 4 blocks
Fifth day = x + 4 blocks
B) All possible values that Makaila could walk on the first day to reach her goal are; x ≥ 11.2
C) The fewest number of blocks she could walk on this day and still meet her goal is; 70 blocks
How to solve arithmetic sequences?A) We are told that the first day, she walks x blocks
Thus;
Second day = x + 2 blocks
Third day = x + 4 blocks
Fourth day = x + 4 blocks
Fifth day = x + 4 blocks
B) Total blocks = x + x + 2 + x + 4 + x + 4 = 5x + 14
Makaila would like to walk at least 70 blocks over the next five days. Thus, the equation is;
5x + 14 ≥ 70
Subtract 14 from both sides of this equation to get:
5x ≥ 56
Divide both sides of this equation by 5 to get:
x ≥ 11.2
C) She must walk greater than or equal to 11.2 blocks the first day to reach her goal.
assume she walks exactly 11.2 blocks the first day.
then her total walking based on the formula would be:
first day 11.2
second day 13.2
third day 15.2
fourth day 15.2
fifth day 15.2
total walked is 11.2 + 13.2 + (3 * 15.2)
this equals 24.4 + 45.6 which equals 70.0
Any number of blocks over 11.2 on the first day will result in a total greater than 70 blocks.
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