how do i find s??? I'm legit crying help.

Answer:

B

Step-by-step explanation:

The steps to bring equation to standard form is Distribute the 3x and then subtract 9 from both sides of the equation

The standard form for linear equations in two variables is Ax+By=C.

For example, 2x+3y=5 is a linear equation in standard form.

According to the question

3x (2x - 7) = 9

Now,

Step1: Multiply 3x to the braces part

6\(x^{2}\) - 21 = 9

Step 2 : Subtract 9 both side

6\(x^{2}\) - 30 = 0

Its standard form

Hence, The steps to bring equation to standard form is Distribute the 3x and then subtract 9 from both sides of the equation

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Answer:

Option C

Step-by-step explanation:

2 pentagons and 5 rectangles are needed to build this pentagonal prism!

The two-dimensional shapes needed to build the pentagonal prism are 2 pentagons and 5 rectangles.

It has 2 congruent cross-sections that are pentagons, the other 5 faces are rectangles.

Answer:264.32

Step-by-step explanation:    multiply 4.72 x 56 to get the answer of 264.32

Answer:

hdhdieidjdjjdjdjdufufifuififif

Answer:

18

Step-by-step explanation:

Let the number of employees with both cell and car be b. Using a Venn diagram shown above,

19 + 22 - b + 2 = 25

43 - b = 25

b = 18

The maximum value of z is 0, and the values of the decision variables are x1 = 0, x2 = 10, x3 = 0, x4 = 0.

maximize: z = c1x1 + c2x2 + ... + cnxn

subject to

a11x1 + a12x2 + ... + a1nxn ≤ b1

a21x1 + a22x2 + ... + a2nxn ≤ b2

am1x1 + am2x2 + ... + amnxn ≤ bmxi ≥ 0 for all i

In our case,

the given LP is:maximize: z = 36x1 + 30x2 - 3x3 - 4x

subject to:

x1 + x2 - x3 ≤ 5

6x1 + 5x2 - x4 ≤ 10

xi ≥ 0 for all i

We can rewrite the constraints as follows:

x1 + x2 - x3 + x5 = 5  (adding slack variable x5)

6x1 + 5x2 - x4 + x6 = 10  (adding slack variable x6)

Now, we introduce the non-negative variables x7, x8, x9, and x10 for the four decision variables:

x1 = x7

x2 = x8

x3 = x9

x4 = x10

The objective function becomes:

z = 36x7 + 30x8 - 3x9 - 4x10

Now we have the problem in standard form as:

maximize: z = 36x7 + 30x8 - 3x9 - 4x10

subject to:

x7 + x8 - x9 + x5 = 5

6x7 + 5x8 - x10 + x6 = 10

xi ≥ 0 for all i

To apply the simplex algorithm, we initialize the simplex tableau as follows:

  |  Cj   |   x5   |   x6   |   x7   |   x8   |   x9   |   x10  |    RHS  |

---------------------------------------------------------------------------

z |  0    |   0    |   0    |  36    |   30   |   -3   |   -4   |    0    |

---------------------------------------------------------------------------

x5|   0   |   1    |   0    |   1    |   1    |   -1   |   0    |    5    |

---------------------------------------------------------------------------

x6|   0   |   0    |   1    |   6    |   5    |   0    |   -1   |   10    |

---------------------------------------------------------------------------

Now, we can proceed with the simplex algorithm to find the optimal solution. I'll perform the iterations step by step:

Iteration 1:

1. Choose the most negative coefficient in the 'z' row, which is -4.

2. Choose the pivot column as 'x10' (corresponding to the most negative coefficient).

3. Calculate the ratios (RHS / pivot column coefficient) to find the pivot row. We select the row with the smallest non-negative ratio.

Ratios: 5/0 = undefined, 10/(-4) = -2.5

4. Pivot at the intersection of the pivot row and column. Divide the pivot row by the pivot element to make the pivot element 1.

5. Perform row operations to

make all other elements in the pivot column zero.

After performing these steps, we get the updated simplex tableau:

  |  Cj   |   x5   |   x6   |   x7   |   x8   |   x9   |   x10  |    RHS  |

---------------------------------------------------------------------------

z |  0    |   0    |  0.4   |  36    |   30   |   -3   |   0    |   12    |

---------------------------------------------------------------------------

x5|   0   |   1    |  -0.2  |   1    |   1    |   -1   |   0    |   5     |

---------------------------------------------------------------------------

x10|   0  |   0    |   0.2  |   1.2  |   1   |   0    |   1    |   2.5   |

---------------------------------------------------------------------------

Iteration 2:

1. Choose the most negative coefficient in the 'z' row, which is -3.

2. Choose the pivot column as 'x9' (corresponding to the most negative coefficient).

3. Calculate the ratios (RHS / pivot column coefficient) to find the pivot row. We select the row with the smallest non-negative ratio.

Ratios: 12/(-3) = -4, 5/(-0.2) = -25, 2.5/0.2 = 12.5

4. Pivot at the intersection of the pivot row and column. Divide the pivot row by the pivot element to make the pivot element 1.

5. Perform row operations to make all other elements in the pivot column zero.

After performing these steps, we get the updated simplex tableau:

  |  Cj   |   x5   |   x6   |   x7   |   x8   |   x9   |   x10  |    RHS  |

---------------------------------------------------------------------------

z |  0    |   0    |  0.8   |  34    |   30   |   0    |   4    |   0     |

---------------------------------------------------------------------------

x5|   0   |   1    |  -0.4  |   0.6  |   1    |   5   |   -2   |   10    |

---------------------------------------------------------------------------

x9|   0   |   0    |   1    |   6    |   5    |   0   |   -5   |   12.5  |

---------------------------------------------------------------------------

Iteration 3:

No negative coefficients in the 'z' row, so the optimal solution has been reached.The optimal solution is:

z = 0

x1 = x7 = 0

x2 = x8 = 10

x3 = x9 = 0

x4 = x10 = 0

x5 = 10

x6 = 0

Therefore, the maximum value of z is 0, and the values of the decision variables are x1 = 0, x2 = 10, x3 = 0, x4 = 0.

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The volume of the parallelepiped with sides given by vectors A, B and C is 13 cubic cm, which is the final answer.

The given vectors are:

A = [-4, 3, 2] cm, B = [2,1,3] cm and C= [1, 1, 4] cm

In order to calculate the volume of parallelepiped, we will use vector triple product equation:

Volume = A . (BXC)|, where BXC represents the cross product of vectors B and C.

Step-by-step solution:

We have, A = [-4, 3, 2] cm

B = [2,1,3] cm

C = [1, 1, 4] cm

Now, let's find BXC, using the cross product of vectors B and C.

BXC = | i    j     k|                    2      1     3                            1      1     4        | i    j     k |  = -i + 5j - 3k

Where, i, j, and k are the unit vectors along the x, y, and z-axes, respectively.

The volume of the parallelepiped is given by:

Volume = A . (BXC)|

Therefore, we have: Volume = A . (BXC)

\(Volume = [-4, 3, 2] . (-1, 5, -3)\\Volume = (-4 \times -1) + (3 \times 5) + (2 \times -3)\\Volume = 4 + 15 - 6\\Volume = 13\)

Therefore, the volume of the parallelepiped with sides given by vectors A, B and C is 13 cubic cm, which is the final answer.

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Step-by-step explanation:

9 *(3 + 5) = (9 x 3)+ (9x 5)

the formula for distributive property is a×(b+c) = (a×b) + (a×c)

The extreme points (x, y) along the curve are (-1, -1) and (0, 0).

The given function f(I, y) = e² x² + xy + y² = 1 represents a quadratic equation in two variables, x and y. To find the extreme points, we need to determine the values of x and y that satisfy the equation and minimize or maximize the function.

a) The function defined by f(x, y) = e² x² + xy + \(y^2\) - 1 takes on a minimum and a maximum value along the curve.

To find the extreme points, we need to find the critical points of the function where the gradient is zero.

Step 1: Calculate the partial derivatives of f with respect to x and y:

∂f/∂x = 2\(e^2^x\) + y

∂f/∂y = x + 2y

Step 2: Set the partial derivatives equal to zero and solve for x and y:

2\(e^2^x\) + y = 0

x + 2y = 0

Step 3: Solve the system of equations to find the values of x and y:

Using the second equation, we can solve for x: x = -2y

Substitute x = -2y into the first equation: 2(-2y) + y = 0

Simplify the equation: -4e² y + y = 0

Factor out y: y(-4e^2 + 1) = 0

From this, we have two possibilities:

1) y = 0

2) -4e²  + 1 = 0

Case 1: If y = 0, substitute y = 0 into x + 2y = 0:

x + 2(0) = 0

x = 0

Therefore, one extreme point is (x, y) = (0, 0).

Case 2: If -4e^2 + 1 = 0, solve for e:

-4e²  = -1

e²  = 1/4

e = ±1/2

Substitute e = 1/2 into x + 2y = 0:

x + 2y = 0

x + 2(-1/2)x = 0

x - x = 0

0 = 0

Substitute e = -1/2 into x + 2y = 0:

x + 2y = 0

x + 2(-1/2)x = 0

x - x = 0

0 = 0

Therefore, the second extreme point is (x, y) = (0, 0) when e = ±1/2.

b) The equation (1+x)e = (1+y)e* is satisfied along the line y = x.

To find a critical point on this line where the equation is neither locally uniquely solvable for x nor y, we need to find a point where the equation has multiple solutions.

Substitute y = x into the equation:

(1+x)e = (1+x)e*

Here, we see that for any value of x, the equation is satisfied as long as e = e*.

Therefore, the equation is not locally uniquely solvable for x or y along the line y = x.

c) Taylor expansion up to degree 2:

To understand the solution set of the equation in the vicinity of the critical point, we can use Taylor expansion up to degree 2.

2. Expand the function f(x, y) = e²x²  + xy + \(y^2\) - 1 using Taylor expansion up to degree 2:

f(x, y) = f(a, b) + ∂f/∂x(a, b)(x-a) + ∂f/∂y(a, b)(y-b) + 1/2(∂²f/∂x²(a, b)(x-a)^2 + 2∂²f/∂x∂y(a, b)(x-a)(y-b) + ∂²f/∂y²(a, b)(y-b)^2)

The critical point we found earlier was (a, b) = (0, 0).

Substitute the values into the Taylor expansion equation and simplify the terms:

f(x, y) = 0 + (2e²x + y)(x-0) + (x + 2y)(y-0) + 1/2(2e²x² + 2(x-0)(y-0) + 2(\(y^2\))

Simplify the equation:

f(x, y) = (2e² x² + xy) + ( x² + 2xy + 2\(y^2\)) + e² x² + xy + \(y^2\)

Combine like terms:

f(x, y) = (3e² + 1)x² + (3x + 4y + 1)xy + (3 x² + 4xy + 3 \(y^2\))

In the vicinity of the critical point (0, 0), the solution set of the equation, given by f(x, y) = 0, looks like a second-degree polynomial with terms involving  x² , xy, and  \(y^2\).

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Answer:

Dimensions of the rectangle are:

Wedth= 6

Length= 8

Answer:

A

Step-by-step explanation:

z, duehdhdhd 2747 36veuend

Answer:

1. 2430 feet

2. 1.8 m/s^2

Step-by-step explanation:

See the attached worksheet.

A time versus speed graph contains a small treasure of mathematical rewards. The area under the graph is equal to the distance travelled. The slope of the line segments represents acceleration.

For total distance: If we break the graph into three sections (2 triangles and a rectangle) we can calculate the areas for each. Each area is the distance travelled for that segment. As shown on the workseet, the total area is 2430 miles, the distance travelled by the train for this question.

The slope of the line in the first 10 seconds is 1.8 meters/sec^2, the acceleration of the train over that period.

Answer:

For the first one it is 5x+2

Step-by-step explanation:

(9x+5) - (4x+3) = ?

First you minus the x's together so,

9x-4x which would equal 5x

then you minus the 5 and 3 together so,

5-3 which would equal 2

then you put the 5x and the 2 together and you get

5x+2 :-)

For the rest of the problems, use this as an example!

16250 many different three-letter words—including nonsense words—have different letters in the next position.

Given that,

We have to find how many different three-letter words—including nonsense words—have different letters in the next position.

We know that,

The number of alphabets are 26

First letter has 26 choices.

Second letter can not be same has first letter so 25 choices.

Third letter can not be same has second letter so 25 choices.

So,

Total words = 26×25×25=16250

Therefore, 16250 many different three-letter words—including nonsense words—have different letters in the next position.

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The area of the sector OAB of the circle is 9 square meters

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

Sector area = central angle/360 * Circle area

Substitute the known values in the above equation, so, we have the following representation

Sector area = 45/360 * 72

Evaluate

Sector area = 9

Hence, the area of the sector is 9 square meters

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Answer:

Rewriting the expression \((3^\frac{2}{3})^\frac{1}{6}\) with a rational exponent as a radical expression we get \(\mathbf{\sqrt[9]{3} }\)

Step-by-step explanation:

We need to rewrite the expression \((3^\frac{2}{3})^\frac{1}{6}\) with a rational exponent as a radical expression.

The expression given is:

\((3^\frac{2}{3})^\frac{1}{6}\)

First we will simply the expression using exponent rule \((a^m)^n=a^{mn}\)

\((3^\frac{2}{3})^\frac{1}{6}\\=(3^\frac{2}{18})\)

As we know 2 and 18 are both divisible by 2, we can write

\(=(3^\frac{1}{9})\)

Now we know that \(a^\frac{1}{9}=\sqrt[9]{a}\)

Using this we get

\(=\sqrt[9]{3}\)

So, rewriting the expression \((3^\frac{2}{3})^\frac{1}{6}\) with a rational exponent as a radical expression we get \(\mathbf{\sqrt[9]{3} }\)

To find the work done by a force vector f = (3, 5) of 36 pounds in moving an object 10 feet from (0, 0) to (10, 0), we can use the formula for work done: work = force dot product displacement.

The dot product of two vectors is given by the sum of the products of their corresponding components. In this case, we have the force vector f = (3, 5) and the displacement vector d = (10, 0).

The dot product of f and d is calculated as follows: f · d = (3 * 10) + (5 * 0) = 30.

The work done by the force f is given by the formula: work = force dot product displacement.

Since the magnitude of the force is given as 36 pounds, the work done can be calculated as: work = 36 * (f · d) = 36 * 30 = 1080 foot-pounds.

Therefore, the work done by the force f of 36 pounds in moving the object 10 feet from (0, 0) to (10, 0) is 1080 foot-pounds.

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The time-series model that assumes that demand in the next period will be equal to the most recent period's demand is A) Naive approach.

This model is based on the simplest assumption of all, that the next period's demand will be equal to the current period's demand. It is called the naive approach because it assumes no underlying pattern in the data and provides a baseline prediction. The formula for the naive approach is as follows:

y(t) = y(t-1) where y(t) represents the demand in period t and y(t-1) represents the demand in the previous period.

Although this model is simple, it is often used as a benchmark for comparison with more complex models and can provide reasonable results for stable demand patterns.

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Answer:Sand and gravel are combined with other materials to create a cement mixture. The relationship between sand and gravel is represented by s = 3g in terms of g. Rewrite the equation in terms of s.

aterials to create a cement mixture. The relationship between sand and gravel is represented by s = 3g in terms of g. Rewrite the equation in terms of s.

Step-by-step explanation:

reate a cement mixture. The relationship between sand and gravel is represented by s = 3g in terms of g. Rewrite the equation in termsSand and gravel are combined with other materials to create a cement mixture. The relationship between sand and gravel is represented by s = 3g in terms of g. Rewrite the equation in terms of s.

Take into account that the scale of the drawing realted to the actual size is

2 cm = 2.5m

Conisder that the width and length of the living space is 16.8 cm and 4.8 cm respectivley.

Convert the height and length to the actual lengths by using the given scale, as follow:

length = 16.8 cm => 16.8 (2.5 m) = 42 m

height = 4.8 cm => 4.8 (2.5 m) = 12 m

Hence, the actual length of the living space is 42 m

Answer:

Yes, Triangle CAB is congruent to triangle DAB by the SAS Congruence Theorem, so line segment BC is congruent to line segment BD. This means that line segment AB is a perpendicular bisector of line segment CD.

Answer:

1st option

Yes, Triangle CAB is congruent to triangle DAB by the SAS Congruence Theorem, so line segment BC is congruent to line segment BD. This means that line segment AB is a perpendicular bisector of line segment CD.

Using it's concepts, the domain and the range of the function are given as follows:

a) Domain: [0, 7].

b) Range: [0, 300].

The domain of a function is composed by the set of all possible input values of the function. Hence, on the graph, the domain is composed by the values of x.

In the context of this problem, the input of the function is the number of days. A week has 7 days, hence the domain of the function is given by:

[0, 7].

The range of a function is composed by the set of all possible output values of the function. Hence, on the graph, the range is composed by the values of y.

In the context of this problem, the output of the function is the balance of the bank account after each day. Supposing that the smallest balance of the account is of $0, and considering the greatest balance of $300 stated in the problem, the range of the function is given by:

[0, 300].

The graph of the function is incomplete, hence we suppose that the minimum balance is of $0.

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Answer:

W=x/7+ 8z/7 + 4/7

Step-by-step explanation:

Smaller sample size results in smaller sampling variation of the OLS estimator for the slope coefficient in the sample regression model due to the fact that it reduces the amount of variability in the data. Smaller error variance also reduces sampling variation as it reduces the amount of overall variation in the data.

The sampling variation of the OLS estimator for the slope coefficient in the sample regression model is affected by a variety of factors. A smaller sample size will result in smaller sampling variation because it reduces the amount of variability in the data. This is due to the fact that a smaller sample size will contain less variation in the independent variable, and therefore the estimated slope coefficient will have less variation. Additionally, a smaller error variance will also reduce the sampling variation as it reduces the amount of overall variation in the data. Finally, smaller variation in the independent variable in the sample will also lead to smaller sampling variation of the OLS estimator. This is because the slope coefficient is estimated by minimizing the sum of squared residuals, which is a function of the variation in the independent variable. Thus, if the variation in the independent variable is reduced, the slope coefficient will have less variation. In conclusion, all three factors can lead to reduction in the sampling variation of the OLS estimator for the slope coefficient in the sample regression model.

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The ratios of (a) square kens to square meters (1 ken² / 1 m²) is 3.88

For given question,

We have been given the unit conversion.

A traditional unit of length in Japan is the ken

and 1 ken = 1.97 m

We need to find the the ratios of (a) square kens to square meters.

First we find the square of 1 ken.

⇒ 1 square kens = (1.97 m)²

⇒ 1 square kens = 1.97 × 1.97 m²

⇒ 1 square kens = 3.88 m²                  ..................(1)

And 1 square meters = 1 m²                 ................. (2)

Now we take the ratio of square kens to square meters.

From (1) and (2),

⇒ 1 ken² / 1 m² = 3.88 / 1

⇒ 1 ken² / 1 m² = 3.88

Therefore, the ratios of (a) square kens to square meters (1 ken² / 1 m²) is 3.88

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Inferential statistics is one of the three basic ways of explaining the results of a research investigation. Group of answer choices Comparing variable quantities Graphing relationships between variables Comparing group percentages Making precise statements about data by correlating the scores of individuals on two variables.

Making precise statements about data by correlating the scores of individuals on two variables is one of the three basic ways of explaining the results of a research investigation.

This is also known as inferential statistics, which involves making predictions or generalizations about a larger population based on sample data.

The other two basic ways of explaining research results are descriptive statistics, which involves summarizing and describing the characteristics of a sample, and graphical representation, which involves using visual aids to display data and relationships between variables.

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Based on the given data from the crossover trial comparing two pain relievers (drugs A and B), we can conclude that there is evidence to suggest that the mean pain level is higher with drug B.

The appropriate null and alternate hypotheses are:

Null hypothesis (H0): μ1 = μ2 (There is no difference in the mean pain level between drug A and drug B)

Alternate hypothesis (H1): μ1 < μ2 (The mean pain level is higher with drug B)

To compute the P-value using the TI-84 Plus calculator, we need to perform a paired t-test on the data. By calculating the t-statistic for the paired differences and degrees of freedom, we can obtain the P-value associated with the observed difference. Using the P-value method, the obtained P-value is compared to the significance level (α = 0.10) to make a decision.

If the computed P-value is less than the significance level (0.10), we reject the null hypothesis. This indicates that there is sufficient evidence to support the alternative hypothesis, suggesting that the mean pain level is indeed higher with drug B.

Based on the results of the analysis, we can conclude that there is evidence to suggest that the mean pain level is more with drug B compared to drug A. However, it's important to note that this conclusion is based on the given data and the assumptions made during the analysis. Further studies with larger sample sizes and rigorous experimental designs may be needed to confirm these findings.

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μx = 4.6

σx = 0.2

Given:

μ = 4.6

σ = 0.4

n = 4

To calculate μx, the mean of the sample, we can simply use the population mean:

μx = μ = 4.6

To calculate σx, the standard deviation of the sample mean, we use the formula:

σx = σ / sqrt(n)

Substituting the given values:

σx = 0.4 / sqrt(4) = 0.4 / 2 = 0.2

Therefore, the values are:

μx = 4.6

σx = 0.2

The mean, denoted by μ (pronounced "mu"), is a statistical measure that represents the average value of a set of numbers. It is calculated by summing up all the values in the set and dividing the sum by the total number of values.

In other words, the mean is the central value that represents the typical or average value in a data set. It provides a measure of the central tendency of the data and is commonly used as a summary statistic in statistical analysis.

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