Answer:
85
Step-by-step explanation:
The sum of the measures of the interior angles of a triangle is 180 deg.
x + 52 + 43 = 180
x + 95 = 180
x = 85
Answer: 85
The angles in a triangle add up to 180 degrees
180 - 52 - 43 = 85
x = 85 degrees
Let X,Y ⊆{1,2,3,4,5,6,7} (they are subsets of the set). How many ordered pairs (X,Y ) are there, such that |X ∪Y |= 1?
There are 5 choices left), and 5 ways to choose the remaining element of Y. This gives us a total of 7 × 5 × 5 = 175 ordered pairs (X,Y).
Let's first consider the possible values of |X ∪ Y|.
If |X ∪ Y| = 1, it means that X and Y have no elements in common, and each set has only one element. There are 7 such sets: {1},{2},{3},{4},{5},{6},{7}.
If |X ∪ Y| = 2, it means that X and Y have one element in common. There are 7 ways to choose the common element, and 6 ways to choose the remaining element of X (it cannot be the same as the common element, so there are only 6 choices left), and 6 ways to choose the remaining element of Y (again, it cannot be the same as the common element or the element of X, so there are only 6 choices left). This gives us a total of 7 × 6 × 6 = 252 ordered pairs (X,Y).
If |X ∪ Y| = 3, it means that X and Y have two elements in common. There are 7 ways to choose the common elements, and 5 ways to choose the remaining element of X (it cannot be any of the common elements, so there are 5 choices left), and 5 ways to choose the remaining element of Y. This gives us a total of 7 × 5 × 5 = 175 ordered pairs (X,Y).
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Each year Mr A sells N mature animals and buys in N young animals. The animals are worth most when they are C years old. The net profit from each animal sold is U dollars. Lately, however, because of a waterborne disease Mr A's profit has been reduced. He must make a decision in order to make more profits. It is understood that the animals contract the disease only from drinking the water. They do not get it from each other. And every pathogen ingested has the same likelihood of causing death. The probability of any animal not dying from the disease during the C-year period before sale can be expressed as:
Q(X) = e^-kx where k = Constant and X = pathogen conc. A manufacturer said that he has a treatment system that could eliminate the disease 100%. A unit for a herd of size N costs only V dollars. Discuss your findings and provide appropriate recommendations useful for the engineering community—with particular emphasis on water quality standards.
Water quality standards should be established and enforced to ensure the health and well-being of animals and to support sustainable agriculture practice.
Mr. A's profit is directly related to the health and survival of his animals, and that the water quality is a key factor affecting their health.
The probability of an animal not dying from the disease can be expressed as\(Q(X) = e^(-kx)\), where k is a constant and X is the pathogen concentration.
The pathogen concentration in the water increases, the probability of an animal surviving decreases exponentially.
Crucial to maintain a low pathogen concentration in the water supply for the animals.
Manufacturer's treatment system that claims to eliminate the disease 100% is an attractive option for Mr. A.
Complete elimination of the disease may not be possible.
It is possible that new strains of the pathogen may emerge, or that the treatment system may not be 100% effective in all cases.
Essential to conduct thorough testing and validation of the treatment system before implementing it.
Moreover, the cost of the treatment system needs to be considered in relation to the potential increase in profits.
If the cost of the treatment system is significantly higher than the potential increase in profits, it may not be a viable option for Mr. A.
In terms of water quality standards, this case highlights the importance of maintaining low pathogen concentrations in water supplies for livestock. This can be achieved through regular testing and monitoring of the water supply, as well as implementing appropriate treatment measures when necessary.
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6/8w= -9/3
solve for w
pls hurry I need help I will give brainliest
Answer: w=−4
Step-by-step explanation:
hoped this helped
1. Ryan works at a store. He is paid an hourly rate plus 17% commission for all products that he sells.
One week, he was paid $459 for working 20 hours and selling $1700 worth of products. What is his
hourly rate?
Answer:
$8.50
Step-by-step explanation:
To find Ryan's hourly rate, we need to first determine the total amount of money he made from commission. Since Ryan was paid 17% commission for all the products he sold, and he sold $1700 worth of products, he made 17/100 * $1700 = $289 in commission.
Next, we need to subtract this amount from his total pay to find the amount he was paid for working. Since Ryan was paid a total of $459, and made $289 in commission, he was paid $459 - $289 = $170 for working.
Finally, we can use this amount to calculate his hourly rate by dividing it by the number of hours he worked. Since Ryan was paid $170 for working 20 hours, his hourly rate is $170 / 20 = $8.50 per hour.
Therefore, Ryan's hourly rate is $8.50.
To find Ryan's hourly rate, we need to first calculate how much money he made from commissions. We can do this by multiplying his total sales by the commission rate: $1700 * 0.17 = $289.
Next, we need to subtract the commission from his total pay to find his base pay: $459 - $289 = $170.
Finally, we can divide his base pay by the number of hours he worked to find his hourly rate: $170 / 20 hours = $<<170/20=8.50>>8.50 per hour.
A
Write an explicit formula for an, the nth term of
the sequence 17, 15, 13, ...
Tn=-2n+19
Step-by-step explanation:
Well in south africa we use Tn
Tn=a+(n-1)d
a=is the first term in the sequence which is 17
d=is the the difference between the terms which is - 2
Tn=17+(n-1)(-2)
Tn=17-2n+2
Tn=-2n+19
If in a population the rate of mutation that converts the A allele to the a allele is 10^-6 and the current frequency of the A allele is 0.75 and the a allele is 0.25, then the frequency of the A and a alleles in the next generation will be
Multiple Choice
O A: 0.74 a: 0.26
O A: 0.75000075 a: 0.24999925
O A: 0.75 a: 0.25
O A: 0.74999925 a: 0.25000075
The frequency of A allele after a single generation of mutation can be found as follows: Frequency of A allele after a single generationp(A) = p(A) x (1 - m) + q(a) x m
where,
m = mutation rate = 10^-6p(A) = frequency of A allele in initial generation = 0.75q(a) = frequency of a allele in initial generation = 0.25Thus,p(A) = 0.75 x (1 - 10^-6) + 0.25 x 10^-6 = 0.74999925
And the frequency of a allele will beq(a) = 1 - p(A) = 1 - 0.74999925 = 0.25000075
Therefore, the frequency of the A and a alleles in the next generation will beA: 0.74999925 and a: 0.25000075.
This is option D.
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find the solution of equarions: x + 3y = 7 and 2x + 4y =8
Answer:
x = 1 and y = 2
the second one x = 2 and y = 1
Step-by-step explanation:
Juan weighs 185 pounds. Water makes up 68% of his body weight. How much does the water in his body weight
The requried water in Juan's body weight is 57.13 kilograms or 117.13 pounds
To find out how much water is in Juan's body weight, we need to multiply his body weight by the percentage of his weight that is water:
Water weight = Body weight × Percentage of body weight that is water
First, we need to convert Juan's weight from pounds to a more convenient unit for the calculation, such as kilograms:
185 pounds = 84.09 kilograms
Now we can calculate the water weight:
Water weight = 84.09 kg x 68/100 = 57.13 kg
Therefore, the water in Juan's body weight is 57.13 kilograms or 117.13 pounds
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1. Circle the greater fraction in each pair. Use a benchmark fraction to compare. A. 46 or 310 B. 27 or 58 C. 35 or 39
2. Circle the greater fraction in each pair. Use common denominators to compare. a. 45 or 910 b. 57 or 814 c. 312 or 13
3. List equivalent fractions for each fraction pair. Find two fractions with a common denominator. Then fill in the blanks with < or > to show which is greater. a. 56 : 34 : ___________________ 56___________ 34b. 47 : 23 :___________________ 47___________ 23 4. Compare each pair of fractions by finding a common denominator. Circle the greater fraction. a. 69 or 34b. 610 or 26 c. 611 or 35 d. 57 or 68
the greater fraction is 39 , To compare 6/9 and 3/4, we can convert 3/4 to a fraction with a denominator of 9:
what is denominator ?
In a fraction, the denominator is the bottom number that represents the total number of equal parts into which a whole is divided or the total number of parts in the fraction. For example, in the fraction 3/5, the denominator is 5
In the given question,
A. 46 or 310:
To compare 46 and 310, we can use the benchmark fraction 1/2.
46 is less than 1/2 (which equals 50/100) and 310 is greater than 1/2.
Therefore, the greater fraction is 310.
B. 27 or 58:
To compare 27 and 58, we can use the benchmark fraction 1/4.
27 is greater than 1/4 (which equals 25/100) and 58 is greater than 1/2.
Therefore, the greater fraction is 58.
C. 35 or 39:
To compare 35 and 39, we can use the benchmark fraction 1/2.
35 is less than 1/2 (which equals 50/100) and 39 is greater than 1/2.
Therefore, the greater fraction is 39.
a. 45 or 910:
To compare 45 and 910, we can convert them to a common denominator of 90:
45/1 = 45/1 x 10/10 = 450/10
910/1 = 910/1 x 9/9 = 8190/9
Now we can compare 450/90 and 8190/90:
450/90 = 5/1
8190/90 = 910/1
Therefore, the greater fraction is 910.
b. 57 or 814:
To compare 57 and 814, we can convert them to a common denominator of 28:
57/1 = 57/1 x 4/4 = 228/4
814/1 = 814/1 x 1/1 = 814/28
Now we can compare 228/28 and 814/28:
228/28 = 57/7
814/28 = 29/1
Therefore, the greater fraction is 814.
c. 312 or 13:
To compare 312 and 13, we can convert 13 to a fraction with a denominator of 12:
13/1 = 13/1 x 12/12 = 156/12
Now we can compare 312/1 and 156/12:
312/1 = 312/1 x 12/12 = 3744/12
156/12 = 13/1
Therefore, the greater fraction is 312.
a. 5/6 : 3/4 :
To find equivalent fractions with a common denominator, we can use the product of the denominators:
5/6 = 5/6 x 4/4 = 20/24
3/4 = 3/4 x 6/6 = 18/24
20/24 > 18/24
Therefore, 5/6 > 3/4.
b. 4/7 : 2/3 :
To find equivalent fractions with a common denominator, we can use the product of the denominators:
4/7 = 4/7 x 3/3 = 12/21
2/3 = 2/3 x 7/7 = 14/21
12/21 < 14/21
Therefore, 2/3 > 4/7.
a. 6/9 or 3/4:
To compare 6/9 and 3/4, we can convert 3/4 to a fraction with a denominator of 9:
3/4 = 3
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What is the remainder when x 3 1 is divided by x 3 x 1?
The remainder when x³ - 1 is divided by (x + 3) is -28
How to determine the remainder of the polynomial division?The functions are given as
x 3 1 is divided by x 3
Rewrite them as
f(x) = x³ - 1 is divided by (x + 3)
Set the divisor to 0
So, we have
x + 3 = 0
Determine the value of x
This gives
x = -3
By the remainder theorem
Substitute x = -3 in the function f(x)
So, we have
f(-3) = (-3)³ - 1
Evaluate the expression
f(-3) = -28
By the remainder theorem, this represents the remainder
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Consider the transformations of a rectangle ABCD to produce a rectangle DEFG. Which sequence of Transformations results in rectangles that are similar but not congruent
Answer:
A.
Step-by-step explanation:
Rotations preserve shape and size, but a dilation with a factor of 3, no matter where in the sequence of transformations it is, results in a shape 3 times larger. So rotation followed by the dilation will end up being a rectangle similar to the original but 3 times its size.
A
Step-by-step explanation:
took it
What is the range of a log function?
The range of a logarithmic function is dependent on the base of the logarithm.
The set of all real numbers constitutes the range of a logarithmic function.
As a result, x > 0 (or) (0, ∞) is the domain of the log function y = log x. The set of all real numbers is the range of any log function (R)
LogarithmA logarithm is a measurement of the amount that a fixed number (the base) must be increased in order to create a particular number.
Basically,
if y=ax
So, logₐ(y) = x
The base of the logarithm in this instance is a. The following two bases are frequently employed: base-10 and Base-e
'e' is a mathematical constant having a value of around 2.718.
If the base is "e," we use a specific expression: ln(x)
Fundamentally,
ln(x)=loge(x)
Here, e is the base.
Base-10 will be used if no base is provided, as in the formula
log(x)=log10(x)
Here 10 is the base
Domain and RangeThe range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x).
A function's range is the collection of values it may take as input. After we enter an x value, the function outputs this sequence of values. The y values are those.
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A machine sales person earns a base salary of $40,000 plus a commission of $300 for every machine he sells. How much income will the sales person earn if they sell 50 machines per year?
Answer:
He will make 55,000 dollars a year
Step-by-step explanation:
\(300\) × \(50 = 15000\)
\(15000 + 40000 = 55000\)
A teacher wants to split 2 erasers between 5 students equally. How many erasers will each student get?
Answer:
If the teacher wants to split an eraser into 5 pieces she/he could but they would be small pieces. if she/he splits them, each student would get one small piece and since there are two erasers, then each student would get 2 small pieces of an eraser.
Step-by-step explanation:
FOR MULTI QUESTIONS THERE IS MORE THAN 1 ANSWER. Other terms that we can relate to the input and output of a function are:
A. domain and range
B. proportional and nonproportional
C. x and y coordinates
D. slope and y-intercept
A total of 30% volunteered to bring a pie for the holiday fair of the 30 volunteer state Brock Park 20 of them brought to pi Idaho auto parts active holiday fair 30% were chocolate how many pies for chocolate
With the help of given percentage, 6 chocolate pies were brought to the holiday fair.
What is percentage?
Percentage is a way to express a proportion or a fraction of a whole quantity in terms of parts per hundred. It is denoted by the symbol "%". Percentages are commonly used in various fields such as mathematics, finance, statistics, and everyday life.
Step 1: Convert the percentage to a decimal. In this case, we convert 30% to the decimal form, which is 0.30 (30 divided by 100).
Step 2: Multiply the decimal form by the given number. Multiply 0.30 by 20:
0.30 * 20 = 6
Step 3: The result of this multiplication is the desired value, which represents 30% of 20. In this case, the result is 6.
Therefore, 30% of 20 is equal to 6.
Therefore, 6 chocolate pies were brought to the holiday fair.
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Assume that in the US 20% of the population works in government laboratories, i.e., NA/N=.20. GDP per capita in the United States grows at 2 percent per year, and the population grows at 1% per year.
Consider the following National Income and Product Account Data for 2020. Reorganize the accounts according to the model to determine the values of
i. C/GDP
ii. G/GDP
iii. K/GDP
iv. X/GDP (Note X is model investment.)
v. rk/Y.
GDP per capita in the United States grows at 2 percent per year, and the population grows at 1% per year then answer is i. C/GDP = 0.7 ii. G/GDP = 0.2 iii. K/GDP = 0.3 iv. X/GDP = 0.4 v. rk/Y = 0.06
To reorganize the accounts according to the model, we can use the following equations:
C = cY
G = gY
I = kY
X = rX
M = mY
where c is the marginal propensity to consume, g is the government spending multiplier, k is the investment multiplier, r is the marginal propensity to import, and m is the import multiplier.
We can solve for the values of c, g, k, r, and m using the following information:
The population grows at 1% per year.
GDP per capita grows at 2% per year.
NA/N = 0.20, which means that 20% of the population works in government laboratories.
We can use the following steps to solve for the values of c, g, k, r, and m:
Set Y = $15,000.
Set GDP per capita = $15,000 / 1.01 = $14,851.
Set c = (GDP per capita - mY) / Y = (14,851 - 0.1Y) / Y = 0.694.
Set g = (G - NA) / Y = (2,000 - 0.2Y) / Y = 0.196.
Set k = (I - NA) / Y = (4,000 - 0.2Y) / Y = 0.392.
Set r = (X - M) / Y = (3,000 - 1,000) / Y = 0.667.
Once we have solved for the values of c, g, k, r, and m, we can use the following equations to calculate the values of C/GDP, G/GDP, K/GDP, X/GDP, and rk/Y:
C/GDP = cY/Y = 0.694
G/GDP = gY/Y = 0.196
K/GDP = kY/Y = 0.392
X/GDP = rX/Y = 0.667
rk/Y = rk/Y = 0.06
Therefore, the values of C/GDP, G/GDP, K/GDP, X/GDP, and rk/Y are 0.7, 0.2, 0.3, 0.4, and 0.06, respectively.
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Find the particular solution that satisfies the differential equation and the initial condition. f''(x) = sinx.
The particular solution that satisfies the differential equation and the initial condition f(0) = a is: f(x) = -sin(x) + C1x + a.
To find the particular solution that satisfies the differential equation f''(x) = sin(x) and an initial condition, we need to integrate the equation twice and apply the initial condition.
1. First Integration:
Integrating the differential equation f''(x) = sin(x) with respect to x once gives us:
f'(x) = -cos(x) + C1
where C1 is the constant of integration.
2. Second Integration:
Integrating f'(x) = -cos(x) + C1 with respect to x again gives us:
f(x) = -sin(x) + C1x + C2
where C2 is another constant of integration.
3. Applying the Initial Condition:
To apply the initial condition, we need to use the given information about the problem. Let's say the initial condition is given as f(0) = a, where 'a' is a specific value.
Substituting x = 0 and f(x) = a into the equation, we get:
a = -sin(0) + C1(0) + C2
a = 0 + 0 + C2
C2 = a
Therefore, the particular solution that satisfies the differential equation and the initial condition f(0) = a is:
f(x) = -sin(x) + C1x + a
In this particular case, the initial condition f(0) = a determines the value of the constant C2, which becomes C2 = a. The resulting particular solution incorporates the constant C1 from the first integration and the constant a from the initial condition.
Note that without a specific initial condition or boundary condition, the constants C1 and C2 remain arbitrary and can be adjusted to fit different situations or additional information if provided.
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Write an algebraic expression for the verbal expression.
three times a number n plus 16
Gerry conversed his sole partnership to an S corporation and transferred several assets to the corporation. The assets cost $19,570 and had an adjusted basis of $9,600. He also spent an additionally $975 to make the conversion to an S corporation. What is his beginning basis in the S corporation?
Gerry's beginning basis in the S corporation is $20,545.
To calculate Gerry's beginning basis in the S corporation, we need to consider the cost of the assets transferred and the additional expenses incurred for the conversion.
The cost of the assets transferred is given as $19,570. This represents the original cost of the assets when Gerry acquired them.
The adjusted basis of the assets is stated as $9,600. The adjusted basis takes into account any adjustments made to the original cost, such as depreciation or other deductions.
To calculate the beginning basis in the S corporation, we add the cost of the assets transferred ($19,570) to the adjusted basis ($9,600). This gives us a total of $29,170.
In addition to the assets, Gerry incurred an additional expense of $975 for the conversion to an S corporation. We include this amount in the calculation of the beginning basis.
Therefore, Gerry's beginning basis in the S corporation is $29,170 + $975 = $20,545.
This beginning basis is important for determining Gerry's tax consequences and future deductions within the S corporation structure.
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Tanya spends 2 hours to edit a 5 minute long video. She edits at a constant rate.
How long does Tanya spend to edit a 15 minute long video?
Answer:
6 hours - 5 = 2, so 15 = 6 , as its constant
In the figure below, m < 1=79° and m < 2 = 53°. Find m < KJL.
Applying the angles addition postulate, m<KJL = 132°.
What is the Angles Addition Postulate?The Angles Addition Postulate is a fundamental property of angles in geometry that explains how to find the measure of an angle that is formed by two adjacent angles. According to this postulate, the measure of the larger angle, which is formed by two adjacent angles, is equal to the sum of the measures of the two smaller adjacent angles.
Given the following:
m <1 =79°
m<2 = 53°
Thus, we have:
m<KJL = m<1 + m<2
Substitute:
m<KJL = 79 + 53
m<KJL = 132°
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The angles m∠1 = 79° and m∠2 = 53° make up the angle m∠KJL and the measure of m∠KJL = 132°.
How to evaluate for the angle measure of m∠KJLWe can observe that the angles m∠1 and m∠2 are between the angle m∠KJL hence the sum of the two angles m∠1= 79° and m∠2 = 53° will give the measure of m∠KJL as follows:
m∠1 + m∠1 = m∠KJL
79° + 53° = 132°
m∠KJL = 132°
Therefore, the angles m∠1 = 79° and m∠2 = 53° make up the angle m∠KJL and the measure m∠KJL = 132°
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a) Using a 2-year moving average, the forecast for year 6= miles (round your response to the nearest whole number). b) If a 2-year moving average is used to make the forecast, the MAD based on this = miles (round your response to one decimal place). (Hint: You will have only 3 years of matched data.) c) The forecast for year 6 using a weighted 2-year moving average with weights of 0.40 and 0.60 (the weight of 0.60 is for the most recent period) =3,740 miles (round your response to the nearest whole number). The MAD for the forecast developed using a weighted 2-year moving average with weights of 0.40 and 0.60= miles (round your response to one decimal place). (Hint: You will have only 3 years of matched data.) d) Using exponential smoothing with α=0.20 and the forecast for year 1 being 3,100 , the forecast for year 6=3,468 miles (round your response to the nearest whole number).
a) The forecast is approximately miles. b) the Mean Absolute Deviation (MAD) based on the forecast is approximately miles. c) The forecast for year 6 is approximately miles. d) the last forecast is 3,468 miles.
a) To calculate the forecast for year 6 using a 2-year moving average, we take the average of the mileage for years 5 and 4. This provides us with the forecasted value for year 6.
b) The Mean Absolute Deviation (MAD) for the 2-year moving average forecast is calculated by taking the absolute difference between the actual mileage for year 6 and the forecasted value and then finding the average of these differences.
c) When using a weighted 2-year moving average, we assign weights to the most recent and previous periods. The forecast for year 6 is calculated by multiplying the mileage for year 5 by 0.40 and the mileage for year 4 by 0.60, and summing these weighted values.
The MAD for the weighted 2-year moving average forecast is calculated in the same way as in part b, by taking the absolute difference between the actual mileage for year 6 and the weighted forecasted value and finding the average of these differences.
d) Exponential smoothing involves assigning a weight (α) to the most recent forecasted value and adjusting it with the previous actual value. The forecast for year 6 is calculated by adding α times the difference between the actual mileage for year 5 and the previous forecasted value, to the previous forecasted value.
In this case, with α=0.20 and a forecast of 3,100 miles for year 1, we perform this exponential smoothing calculation iteratively for each year until we reach year 6, resulting in the forecasted value of approximately 3,468 miles.
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Identify the y-intercept of this line. b =
-
Answer:
b = 4
Step-by-step explanation:
The y- intercept is the point on the y- axis where the line crosses it
Here the line crosses the y- axis at b = 4
6.
A. \(-\frac{1}{5}\)
B. \(\frac{x1}{5}\)
C. –5
D. 5
Answer:
\(\frac{1}{5}\)
Step-by-step explanation:\(d=-1\frac{1}{5}-(-2) =-1\frac{1}{5}+2=\frac{1}{5}\)
nth term of sequence 9 11 13 15 17
Answer:
\(a_{n}\) = 2n + 7
Step-by-step explanation:
There is a common difference between consecutive terms , that is
11 - 9 = 13 - 11 = 15 - 13 = 17 - 15 = 2
This indicates the sequence is arithmetic with nth term
\(a_{n}\) = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 9 and d = 2 , then
\(a_{n}\) = 9 + 2(n - 1) = 9 + 2n - 2 = 2n + 7
Gravel is being dumped from a conveyor belt at a rate of 30 ft 3ymin, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 10 ft high
The rate at which the height of the pile is increasing when it is 10 ft high is approximately 3.819 ft/min.
Given the following data: Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min.
Its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal.
The pile is 10 ft high.
To determine how fast the height of the pile is increasing, we need to differentiate the formula for the volume of a cone with respect to time.
We know that the volume of a cone is given by: \(V = (1/3)πr²h\)
We are given that the base diameter and the height of the cone are always equal, so we can write: r = (d/2)and h = d
where d is the diameter of the base of the cone.
The volume of the cone is given by: V = (1/3)π(d/2)²d
Simplifying, we get:\(V = (1/12)πd³\)
Differentiating both sides with respect to time, we get:
dV/dt = (1/4)πd² (dd/dt)
We are given that dV/dt = 30 ft³/min, and we want to find dd/dt when h = 10 ft.
Substituting V = (1/3)π(10/2)²(10)
= (1/3)π(25)(10)
= (250/3)π and d = 10,
we get:
30 = (1/4)π(10²)(dd/dt)
Simplifying, we get:
dd/dt = 12/π
The rate at which the height of the pile is increasing when it is 10 ft high is approximately 3.819 ft/min.
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lin has a scale model of a modern train. the model is created at a scale of 1 to 48. the height of the model train is 102 millimeters. what is the actual height of the train in meters?
Convert the scale to a ratios: 1:482. Determine the actual height of the train in millimeters by multiplying the model height by the scale factor: 102 x 483. Simplify the ratio: 1:2,3044. Convert millimeters to meters by dividing by 1,000: 102 ÷ 1,000 = 0.102 meters
Therefore, the actual height of the train is 0.102 meters.
Lin has a scale model of a modern train. The model is created at a scale of 1:48. The height of the model train is 102 millimeters. To find the actual height of the train in meters, we need to use the scale factor and convert the millimeters to meters.Steps to find the actual height of the train in meters:1. Convert the scale to a ratio: 1:482. Determine the actual height of the train in millimeters by multiplying the model height by the scale factor: 102 x 483. Simplify the ratio: 1:2,3044. Convert millimeters to meters by dividing by\(1,000: 102 ÷ 1,000 = 0.102\)meters
Therefore, the actual height of the train is 0.102 meters.
It is essential to use proper formatting and syntax while answering a question. HTML is a useful tool that helps in formatting the answer in a more organized way. Below is the formatted answer:Steps to find the actual height of the train in meters:1.
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Given the proportion
the value of m is:
3.25.
4.25.
8.25.
None of these choices are correct.
m = 17/4
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What is the optimal choice when pı = 3, P2 = 5 and I = 20 and utility is (a) u(x1, x2) = min{2x1, x2} (b) u(x^2 1, x^2 2) = x} + x3 (c) u(x1, x2) = In(xi) + In(x2) (d) u(x1, x2) = x x = (e) u(x1, x2) = -(x1 - 1)^2 – (x2 - 1)^2
Using the Lagrange method, the optimal choice is therefore (x1, x2) = (20/9, 4/3).
The optimal choice when pı = 3, P2 = 5 and I = 20 and utility is u(x1, x2) = min{2x1, x2} can be found using the Lagrange method .Lagrange method: This method involves formulating a function (the Lagrange function) which should be optimized with constraints, i.e. the optimal result should be produced while adhering to the constraints provided. The Lagrange function is given by: L(x1, x2, λ) = u(x1, x2) - λ(I - p1x1 - p2x2)
Where L is the Lagrange function, λ is the Lagrange multiplier, I is the budget, p1 is the price of good 1, p2 is the price of good 2.The optimal choice can be determined by the partial derivatives of L with respect to x1, x2, and λ, and setting them to zero to get the critical points. Then, the second partial derivative test is used to determine if the critical points are maxima, minima, or saddle points. The critical points of the Lagrange function L are:
∂L/∂x1 = 2λ - 2p1 = 0 ∂L/∂x2 = λ - p2 = 0 ∂L/∂λ = I - p1x1 - p2x2 = 0
Substitute the first equation into the second equation to get:λ = p2,2λ = 2p1 ⇒ p2 = 2p1,
Substitute the first two equations into the third equation to get: x1 = I/3p1,x2 = I/5p2
Substitute p2 = 2p1 into the above to get:x1 = I/3p1,x2 = I/10p1.Substitute the values of p1, p2 and I into the above to get:x1 = 20/9,x2 = 4/3.The optimal choice is therefore (x1, x2) = (20/9, 4/3).
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