How is the çhocolate shell on the outside of the bar different from the ice cream on the inside?

Answer:

Explanation:

Σf=m*a

Σf=40*1,2

Σf=48N

Answer: 134 = 143 = 151 = 166 = 176

Hope this helps!!

Sorry if it's incorrect!!

:'(

Answer:

I think it's A

Explanation:

he shouldn't have changed the amount of sugar, because the whole point is to see which temperature dissolves sugar more quickly.

Answer: The forces of gravity

Explanation:  The consequence of this phenomenon is that every mass exerts a so-called "force of mutual attraction" on every other mass. The attractive force that the celestial bodies exert on other masses by virtue of their total mass is called the force of gravity.

Hope this helps

Using a Social Institution of our society as a guide, Yes,  changes in inequality can be accomplished when policies are put in place to address them and they are also enforce properly.

Long-term social and economic development is under danger due to inequality, which also harms property reduction and undermines people's sense of fulfillment and self-worth. Crime, sickness, and environmental destruction can all result from this.

In addition to other sorts of policy, governments can lessen inequality through lowering taxes and providing income support or transfers (such as welfare, free healthcare, and food stamps).

Therefore, the reduction of poverty and the creation of opportunity for disadvantaged populations can be greatly impacted by improving access to markets, communications, and roadways. Additionally, by minimizing localized pockets of poverty, decentralization of public services, offices, and industry can foster shared wealth among areas.

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Answer:

Bicycle

Explanation:

The Bicycle uses the reflection from the sun or moon to cast light off of its red rear. does not produce own radiant energy

The vector characteristics of the electric field allow to find the result for the electric field at the point of interest is;

Given parameters.

    1) Electric charges:

    2)Charge positions

   3) Points of interest r = (0,0,1) = 1 \(\hat k\)  

To find.

the electric field at point r.

The intensity of the electric field is given by the ratio of the electric force to the positive test charge at the point of interest.

          \(E= k \frac{q}{r^2 }\)  

where E is the electric field, k the constant of Coulomb, q the charge and r the distance.

In the attached we see a diagram of the test charges and the distance to the point of interest on the z axis.

The total field is the vector addition of the fields created by each charge

          \(E_{total} = E_1 +E_2\)

Let's look for the components of each electric field.

Field created by charge q₁

          tan θ = \(\frac{z}{x}\)  

          tan θ = 1/1 = 1

          tea = 45º

x-axis

          cos 45 = \(\frac{E_{1x}}{E_1}\)

z axis

          sin 45=  \(\frac{E_{1z}}{E_1}\)  

          E₁ₓ = E₁ cos 45

          \(E_{1z}\)  = E₁ sin 45

Field created by load 2

y-axis

        cos 45 = \(\frac{E_{2y}}{E_2}\)  

z- axis

        sin 45 = \(\frac{E_{2z}}{E_2}\)  

        \(E_{2y}\) = E2 cos 45

        \(E_{2z}\) = E2 sin 45

We look for the components of the total electric field, where the signs are taken from the direction of the vectors in the attached.

    \(E_{total} = - E_{1x} \hat i + E_{2y} \hat j + ( E_{1z} - E_{2z} ) \hat k\)

Let's substitute.

         \(E_{total } = - E_1 cos 45 \hat i + E_2 cos 45 \hat j + (E_1 sin 45 - E_2 sin 45) \hat k\)

Let's find the distance for each charge to the test point using the Pythagorean Theorem.

         r₁₃² = x² + z²

         r₁₃² = 1 + 1

         r₁₃² = 2

         r₂₃² = y² + z²

         r₂₃² = 1² + 1²

         r₂₃² = 2

Let's look for the magnitud of the electric fields.

Charge q₁

        \(E_1 = k \frac{q_1}{r_{13}^2}\)  

        E₁ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₁ = 20 N / m

Charge q₂

        \(E_2 = k \frac{q_2}{r_{23}^2}\)  

        E₂ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₂ = 20 C / N

Let's substitute in the expression of the total eletric field.

         \(E_{total} = -20 \ cos45 \ \hat i + 20 \ cos 45\ \hat j + ( 20 -20) sin 45 \ \hat k\)

         \(E_{total} = 14.1 ( - \hat i + \hat j) \ \frac{N}{C}\)  

In conclusion using the vector characteristics of the electric field we can find the result for the electric field at the point of interest is;

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the Given

*The number of mol of neon is n = 1 mol.

*The temperature of the neon gas is T = 288 K.

*The mass of the neon gas is m = 0.01 kg.

*The gas constant R is R = 8.31 J/(mol.K).

To find: The average velocity of atoms of neon (v).

According to the given equation,

Substitute the known values.

The average velocity of atoms of neon is 847.33 m/s. Thus, option (A) is the correct answer.

Answer:

protons: 6

electrons: 6

neutrons: 8

Explanation:

atomic number -> number of protons -> 6

mass number -> number of protons + number of neutrons

    so 14-6 = 8. 8 neutrons

this atom is neutral (net charge is 0), so the number of electrons is the same as the number of protons, which is 6

In physics, a system is a group of related objects that interact with each other and form a complex whole.

In sciences (i.e., physics, chemistry and biology) a system can be defined as an interrelated group of different elements or parts that work together to perform a given function.

In conclusion, in physics and science disciplines in general, a group of related objects that interact in order to form a complex whole is commonly referred as a system.

Complete question:

Fill in the blank. In physics, a ____ is a group of related objects that interact with each other and form a complex whole.

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Answer:

200 km/hr

Explanation:

Since he goes 80km per hour, multiply this by 2.5 or two and a half hours.

80 x 2.5 = 200 km/hr.

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

First option, third option, fourth option, and the fifth option.

Explanation:

Kinetic energy is energy an object has when it's motion, the greater the speed the greater the kinetic energy. For example, a car moving and increasing in speed is kinetic energy since the object is in motion. If the car stops and parks in a parking lot that is potential energy. Potential energy is the amount of energy an object has when it's at rest or not in motion.

So, the answer for this question is as followed first option or "energy can be stored in the position of an object." Third option or "Energy can be stored in the position of the particles that make up a substance." Fourth option or "Energy exists as movement of the particles of a substance." The last answer will be the fifth option or "Energy is greater in faster-moving particles than in slower-moving particles."

Hope this helps.

Answer:

( About ) 6.8nC

Explanation:

We are given the equation |Q2| = mgd^2 / kQ1. Let us substitute known values into this equation, but first list the given,

Charge Q2 = +45nC = (45 × 10⁻⁹) C

mass of charge Q2 = 4.5 μg, force of gravity = 4.5 μg × 9.8 m/s² = ( 4.41 × 10^-5 ) N,

Distance between charges = 25 cm = 0.25 m,

k = Coulomb's constant = 9 × 10^9

_______________________________________________________

And of course, we have to solve for the magnitude of Q2, represented by the charge magnitude of the charge on Q2 -

(4.41 × 10^-5) = [(9.0 × 10⁹) × (45 × 10⁻⁹) × Q₂] / 0.25²

_______________________________________________________

Solution = ( About ) 6.8nC

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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Elastic potential energy of spring is twice the gravitational potential energy of the object.

Height of the object, h = 0.5 m

Displacement of the spring, x = 0.5 m

Given that,

Potential energy of the object = Elastic potential energy of spring

mgh = 1/2 kx² = E

When the distance and height are doubled,

GPE = 2 mgh = 2E

Elastic PE = 1/2 k(2x)²

Elastic PE = 4 x 1/2 kx² = 4E

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On the rollercoaster:

To solve this problem, apply the principles of conservation of energy. Use the following equations:

a) The Total Mechanical Energy (TME) at any point can be calculated using the formula: TME = Potential Energy + Kinetic Energy.

b) The velocity of the coaster can be calculated using the equation: Kinetic Energy = (1/2)mv², where m = mass of the rollercoaster.

c) The velocity of the coaster at point B can be calculated using the conservation of energy principle. So, equate the Potential Energy + Kinetic Energy at point A to the Potential Energy + Kinetic Energy at point B and solve for velocity at point B.

d) Calculate the height of point A using the formula: Potential Energy = mgh, where m is the mass of the rollercoaster, g is the acceleration due to gravity, and h is the height.

Given:

Mass of rollercoaster (m) = 1000 kg

Braking force (F) = 8780 N

Let's calculate each part of the problem:

a) The Total Mechanical Energy at Point A:

TME = Potential Energy + Kinetic Energy

Since the rollercoaster is at the highest point (A) and it's not moving, the Kinetic Energy is zero.

Potential Energy = mgh

Potential Energy at Point A = (1000 kg)(9.8 m/s²)(h) = TME

TME = 591,100 J

b) The velocity of the coaster at Point A:

Using the Total Mechanical Energy calculated in part a, calculate the velocity using the formula:

TME = (1/2)mv²

591,100 J = (1/2)(1000 kg)(v²)

v² = (2 × 591,100 J) / (1000 kg)

v² = 1182.2 m²/s²

v = √(1182.2) ≈ 34.4 m/s

c) The velocity of the coaster at Point B:

Using the conservation of energy principle, equate the TME at Point A to the TME at Point B:

Potential Energy at Point A + Kinetic Energy at Point A = Potential Energy at Point B + Kinetic Energy at Point B

mgh + (1/2)mv² = mgh' + (1/2)mv'²

Since the coaster starts from rest at Point A, the Kinetic Energy is zero.

mgh = mgh' + 0

gh = gh'

34.4 m/s = √(2 × 9.8 m/s² × h')

h' = (34.4 m/s)² / (2 × 9.8 m/s²) ≈ 60.3 m

d) The highest hill the coaster could have gotten over before Point A with no additional mechanical energy is the height at Point A, is calculated to be approximately 60.3 meters.

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Answer:

Explanation:

Conservation of momentum

Initial momentum is zero as both gun and bullet are motionless in the frame of reference before firing.

0 = 0.012(1500.0) + 4.0v

v = - 4.5 m/s

Must be a rail gun as the fastest powder driven bullets are moving at roughly half the speed described.

When a typical comet in the Oort cloud is only 1 km in diameter, then the mass of the Oort cloud is changes to  4.18×10⁹ kg.

The mass of each comet int he Oort cloud is,

mass = density × Volume

volume of sphere = 4/3(π×r²) where, r = radius of the sphere

From the given,

diameter = 1 km

radius = Diameter / 2 = 1/2(D)

Volume of the comet = 4/3 (π×r²) = 4/3 (π× (1/2 (10)³)²)

                                   = 4/3×(π) ×(1/8×10⁶)

Mass = density  × volume, where density = 1000 kg/m³

         = 1000  × 4/3×(π) ×(1/8×10⁶)

        = 4.18 ×10⁹ kg

When the typical comet in the Oort cloud is only 12 km in diameter the mass of Oort cloud is 4.18×10⁹ kg.

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the answer for the speed of the roller coaster at the top of the loop is v = 14.8 m/s

the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

(a) To find the speed of the roller coaster at the top of the loop, we can use the equation for centripetal acceleration: a = v^2/r. We know that the radius of curvature is 13.0 m and the downward acceleration of the car is 1.50 g (where g is the acceleration due to gravity, approximately 9.8 m/s^2).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(1.5g * 13m)

v = sqrt(22.5 * 9.8)

v = sqrt(219.5)

v = 14.8 m/s

(b) To find the minimum speed necessary for the coaster to complete the loop without falling off the track, we can use the same equation for centripetal acceleration, but this time we will use the minimum value of a that will keep the car on the track, which is equal to the acceleration due to gravity (g).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(g * 13m)

v = sqrt(9.8 * 13m)

v = sqrt(127.4)

v = 11.3 m/s

So the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

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Answer:    Vf = Vi + A(t)

Vf= -2+ (-9.8)(5)

Vf = -51 m/s

Explanation:

The final velocity is equal to the initial velocity plus the acceleration multiplied by the time

(-9.8) is used for the acceleration for this question because that is the speed at which things in free fall accelerate when they are on earth

-2 is used as the initial velocity because the ball was thrown in the negative direction which is down.

The time of 5 was given in the question so you can plug it in for time

Answer:

Explanation:

Given:

V₀ = 2 m/s

g = 9.8 m/s²

t = 5 s

____________

V - ?

Axis OX direct vertically down. Then:

V = Vₓ = V₀ₓ + g·t

V = 2 + 9.8*5 = 51 m

The point through which this ray will pass, after refraction by the lens is point D.

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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The velocity of the car is 5.5 m/s. Then the centripetal acceleration of the car will be 0.6 m/s².

Acceleration is a physical quantity measuring the rate of change in velocity. It has both magnitude and direction.

Centripetal acceleration is the acceleration of an  object moving through a circular path. Thus its measures the rate of change in velocity of the body moving in the curvature path.

The centripetal acceleration = V²/R.

Where R is the radius of the curvature path.

The car moves 50 m in 9 seconds. Its velocity is 50/9 = 5.5 m/s.

Thus, centripetal acceleration = (5.5 × 5.5) m/s/ 50 m = 0.6 m/s².

Therefore, the centripetal acceleration of the car moving at a speed of 9 m/s through curvature path is 0.6 m/s².

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Two point charges designated A and B are connected by electric field lines. Because charge A is directly north of charge B, we can infer that charge A is positive and charge B is negative.

A great approach to see electric fields is with electric field lines. They had their beginnings with Michael Faraday himself. At one point, a field line is drawn perpendicular to the net.

A straight line drawn in an electric field is known as an electric line of force. The direction of the electric field at any given position on the curve is indicated by the tangent at that location.

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The value of 3993 BTUs in Joules is 4212838.0195 Joules.

Answer:

d

Explanation:The other types of low-level radioactive waste are the tools, protective clothing, wiping cloths, and other disposable items that become contaminated with small amounts of radioactive dust

Answer:

C. Industrialization. Nuclear energy can be used to power industries and factories, providing a reliable, clean and cost-effective form of power. Nuclear energy also has potential applications in desalination, medical isotope production, and even space exploration.

Answer:

1 )effect of the force

2) producing the force

3) receiving the force

As the book fell through the air and eventually hit the ground, the energies  of the system were converted from one form to another.

Option D is correct.

Energy is described as  the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.

The forms of energy includes:

Chemical energy.

Electrical Energy.

Mechanical Energy.

Thermal energy.

Nuclear energy.

Gravitational Energy.

In conclusion, When the book fell through the air and hit the ground, the potential energy it possessed due to its position above the ground was converted into kinetic energy as it accelerated towards the ground.

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