Answers
Answer:
Mass = 89.97 g
Explanation:
Given data:
Number of moles of chloride ions = 1.98 mol
Mass in grams of MgCl₂ present = ?
Solution:
we can see that 1 mole of MgCl₂ contain 2 moles of chloride ions. Thus 1.89 moles of chloride ions contain moles of MgCl₂ are,
Cl₂ : MgCl₂
2 : 1
1.89 : 1/2×1.89 = 0.945
Thus, 1.89 moles of chloride ions are provided by 0.945 moles of MgCl₂.
Mass of MgCl₂:
Mass = number of moles × molar mass
Mass = 0.945 mol × 95.211 g/mol
Mass = 89.97 g
Related Questions
5 Describe how seawater forms layers
Answers
Answer:The ocean forms layers because the water has different density throughout. 2. Water with higher density sinks to the bottom while water with lower density sits on the top. ... Low-density water tends to be warmer and less saline, while high-density water is generally cooler and more saline.
Explanation:
A student went to the cafeteria and bought iced tea. He then proceeded to add more sugar to his iced tea. In this solution, the iced tea was the __________ and the sugar was the ____________.
Answers
A student enters the canteen and buys iced tea. He then goes on to add more sugar to his iced tea. In this solution, iced tea is the solvent and sugar is the solute.
2. A 0.2719 g sample containing CaCO3 reacted with 20.00 mL of 0.2254 M HCl. Given that HCI was excess. The excess HCl required exactly 20.00 mL of 0.1041 M NaOH to reach the end-point using phenolphthalein indicator. Determine percentage purity of CaCO3 in the sample. The reraction involved is CaCO3(s) + 2HCl(aq) → CaCl₂(aq) + 2H₂O(l) The titration reaction is HC(aq) + NaOH(aq) NaCl(aq) + H₂O(1)
Answers
The percentage purity of the calcium carbonate is 44%. The percentage purity gives the amount of pure CaCO3 in the sample.
What is excess titration?In excess titration or back titration, we neutralize the excess titrand left in a system.
We have the reaction;
CaCO3 + 2HCl ----> CaCl2 + H2O + CO2
Number of moles of HCl = 0.2254 M * 20/1000 L = 0.0045 moles
The reaction of the excess acid is according to the reaction;
HCl + NaOH ----> NaCl + H2O
Number of moles of NaOH = 0.1041 M * 20/1000 = 0.0021 moles
Since the reaction is 1:1, 0.0021 moles of HCl reacted also
Number of moles of HCl that reacted with CaCO3 = 0.0045 moles - 0.0021 moles = 0.0024 moles
If 2 moles of HCl reacts with 1 mole of CaCO3
0.0024 moles of HCl reacts with 0.0024 moles * 1/2
= 0.0012 moles
Mass of pure CaCO3 present = 0.0012 moles * 100 g/mol = 0.12g
Percent purity of the sample = 0.12g/0.2719 g * 100/1
= 44%
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Is 14 rightThe mg mass are 0.33 and after is 0.49
Answers
Answer:
0.55g of MgO will be formed.
Explanation:
1st) From the balanced equation we know that with 2 moles of Mg, 2 moles of MgO are formed. It is necessary to use the molar mass of Mg and MgO to convert moles to grams:
- Mg molar mass: 24.3g/mol
- Mg conversion:
\(2moles\frac{24.3g}{1mole}=48.6g\)- MgO molar mass: 40.3g/mol
- MgO conversion:
\(2moles*\frac{40.3g}{1mole}=80.6g\)Now we know that with 48.6g og Mg, 80.6g of MgO are formed.
2nd) Finally, with the calculated grams from the stoichiometry of the reaction, and the starting mass of Mg (0.33g) we can calculate the grams of MgO that will be formed:
\(\begin{gathered} 48.6gMg-80.6gMgO \\ 0.33gMg-x=\frac{0.33gMg*80.6gMgO}{48.6gMg} \\ x=0.55gMgO \end{gathered}\)So, 0.55g of MgO will be formed.
4. A solid is 5 cm tall, 3 cm wide and 2 cm thick. It has a mass of 129 g. What is its density?
Answers
4.3 g/cm³ or 4.3g/cc
Explanation:
Volume(V) = Height × Length × Width
= 5cm × 3cm × 2cm
= 30cm³
Mass(m) = 129gram
So,
Density = m/V
= 129g/30cm³
= 4.3g/cc or 4.3g/cm³
What is the mass (in grams) of 2.04 x 1024 methane (CH4) molecules?
Answers
The mass of the methane is 54.4 g.
How does mass and moles relate?Mass and moles are related through the concept of molar mass. The molar mass of a substance is the mass of one mole of the substance, which is numerically equal to its atomic or molecular weight.
The relationship between mass and moles can be expressed using the following equation:
number of moles (n) = mass (m) / molar mass (M)
We know that;
1 mole of the methane would contain 6.02 * 10^23 molecules
x moles would contain 2.04 x 10^ 24 molecules
x = 3.4 moles
Then we have the mass as;
= 3.4 moles * 16 g/mol
= 54.4 g
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moles of each product that would form as a result of the decomposition of aspirin
Answers
The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).
The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:
\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)
From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.
Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.
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5.5 moles of Mg(OH)2 is
Question Blank 1 of 1
type your answer...
x 10^24 molecules of Mg(OH)2
Answers
Avogadro's number is used to determine the small entity like the atoms and the molecules. 5.5 moles of magnesium hydroxide contain 3.31 × 10²⁴ molecules.
What are molecules?Molecules are the small entity that makes up the compound. It is made up of similar or different atoms.
If 1 mole of magnesium hydroxide = 6.02 ×10²³ molecules
Then 5.5 moles = 33.11 × 10²³ molecules.
Therefore, 3.31 × 10²⁴ molecules of magnesium hydroxide are present in 5.5 moles.
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A buffer solution is prepared by dissolving 0.2 mol of CH3NH2 (KB=3.7×10−4) and 0.1 mol of CH3NH3Cl in enough water to make 1.00 L of solution. Determine the pH of the buffer
Answers
The pH of acid is between 0-7 on pH scale while for base pH range is from 7-14. Therefore, the pH of buffer is 10.5. pH is a unitless quantity.
What is pH?pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic.
On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7.
CH\(_3\)NH\(_2\) + H\(_2\)O(aq) \(\rightarrow\) CH\(_3\)NH\(_3\) ⁺(aq) + OH⁻(aq)
Kb = [CH\(_3\)NH\(_3\) ⁺] x[OH⁻] =3.7x 10⁻⁴
[CH\(_3\)NH\(_2\)]= 0.2 / 1.00 =0.2M
Kb = (0.2M) x [OH⁻] = 3.7x 10⁻⁴
[OH-] = 3.15 x 10⁻⁴
pOH=-log[OH-]
= -log[3.15 x 10⁻⁴]
pOH=3.5
pH+pOH=14
pH = 10.5
Therefore, the pH of buffer is 10.5.
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1. (1pt for each) Mark O if the statement is true, X if wrong. For the wrong statements, correct
them.
(a) Since electrons are required, all electrochemical depositions are electrolytic. ()
(b) Increasing metal ion concentration has the same effect with the decreasing deposition current density on the electrodeposited structures. ( )
(c) The standard reaction Gibbs energy change for water electrolysis is positive, thus
generates 1.23V during electrolysis. ( )
(d) When the system is under charge transport limitation, the electrodeposited structures
are normally dense and uniform. ( )
(e) If you deposit metal A on metal 8 with huge lattice misfit between them, the deposition
process follows layer by-layer growth mechanism. ( )
(f) If the standard reduction potentials of metal A and B are 1.0V and -1.0V with respect to hydrogen electrode, you need to apply potential negative than -1.0V for making AxBy alloy. ( )
(g) When you make metal nanowire using AAO templated electrodeposition, the length of
wire can be controlled by the acid strength and voltage in anodization step. ( )
(h) The membrane electrolyte for PEMFC should be paths for both electronic and ionic movements. ( )
(i) The fuel cell electric vehicle generates no CO2, during operation. ( )
(j) The organic leveler used in the electrodeposition process interact with the substrate or
growing deposits normally through van der Waals interaction. ()
Answers
(a) Electroless deposition is a type of electrochemical deposition that does not require electrons - X.
(b) Increasing metal ion concentration increases the deposition current density on the electrodeposited structures - X.
(c) The standard reaction Gibbs energy change for water electrolysis is negative, not positive, and generates 1.23V during electrolysis under standard conditions - X.
(d) When the system is under mass transport limitation, the electrodeposited structures are normally dense and uniform - O.
(e) If you deposit metal A on metal B with a huge lattice misfit between them, the deposition process follows the island growth mechanism rather than the layer-by-layer growth mechanism - O.
(f) To make an AxBy alloy from metals A and B with standard reduction potentials of 1.0V and -1.0V, respectively, you need to apply a potential between -1.0V and 1.0V, depending on the desired stoichiometry - O.
(g) The length of metal nanowires made using AAO templated electrodeposition can be controlled by the anodization time and the thickness of the AAO template - O.
(h) The membrane electrolyte for PEMFC should only allow for ionic movement, not electronic movement - O.
(i) The fuel cell electric vehicle generates less CO2 than traditional vehicles but still produces some CO2 during operation - O.
(j) The organic leveler used in the electrodeposition process interacts with the substrate or growing deposits through chemical bonding rather than van der Waals interaction - O.
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Question 14(Multiple Choice Worth 2 points)
(03.01 LC)
Which of the following is an example of non-matter?
O Atom
O Energy
O Gas
O Liquid
Answers
Answer:
I think the answer is b. gas and liquid is a state of matter.
List the 2 pKa's for H2SO4
Answers
what is meant by the structural isomers
Answers
Answer: idk
Explanation:
38.5 mL of HCl of unknown concentration is neutralized by 16.8 mL of 0.50M NaOH. Calculate the concentration of the HCl.
Answers
A neutralizing reaction takes place when the acid and base are let to interact. The concentration of HCl is 218.12 M.
What do you mean by Neutralized ?Determine how much 0.100 M HCI solution is required to neutralize 25.0 mL of 0.350 M NaOH. (Response: 87.5 mL) In order to neutralize 124 mL of 0.250 M NaOH solution, determine the volume of 0.100 M HzSO4 solution required. An acid and base process known as neutralization produces only salt and water. The OH- from the base totally neutralizes the H+ from the acid in this reaction. Therefore, we can define a neutralization reaction as a reaction that creates water by removing the H+ and OH- from the reactant. Here is an example to help you.
HCl + NaOH = NaCl + H₂OOH⁻ + H⁺
mol of solution = molarity × Liter solution
mol HCL = 16.8 ml × 0.50 M
= 8.4 mol HCl
Concentration of HCl = 8.4/0.0385
= 218.12 M
From the foregoing, it is obvious that the reaction converted the OH- and H+ from the base into water.
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If you dilute 175 ml of a 1.6 M solution of LiCl to 1.0 L , determine the new concentration of the solution
Answers
1) List the known quantities
Initial conditions
Concentration 1: 1.6 M
Volume 1: 175 mL
Final conditions
Volume 2: 1 L
Concentration 2: unknown
2) Set the equation
\(C1*V1=C2*V2\)3) Convert units
Volume
1 L = 1000 mL
\(mL=1\text{ }L*\frac{1000\text{ }mL}{1\text{ }L}=1000\text{ }mL\)4) Plug in the known quantities and solve for C2
\((1.6\text{ }M)*(175\text{ }mL)=C2*(1000\text{ }mL)\)\(C2=\frac{(1.6\text{ }M)*(175\text{ }mL)}{(1000\text{ }mL)}\)\(C2=0.28\text{ }M\)
The new concentration is 0.28 M.
.
Does this chemical reaction describe water hydrogen plus oxygen
Answers
Answer: Formation of water from hydrogen and oxygen is a combination reactionbecause hydrogen and oxygen are combining to form single product. The reaction occurs as follows: 2H2(g)+O2(g)→2H2O(l)
Explanation:
Examine the substances listed. Identify the substance(s) that represents a single element.
SUBSTANCE: soil, copper pipe, water. CO2*
soil
copper pipe
water
CO2
Answers
Answer:
the answer is copper pipe
What is the conjugate base of CO3-2
Answers
The conjugate base of CO3-2 is hydrogen carbonate.
Meaning of Conjugate baseA conjugate base can be defined as a base that can be derived from another base by the reason of it loosing or gaining an electron.
Conjugate base are very similar because they both posses the same elements.
In conclusion, The conjugate base of CO3-2 is hydrogen carbonate.
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1. A balloon is inflated to a pressure of 2.55 atm at a temperature of 25 °C. What temperature
(in °C) is required to maintain the same volume if the pressure decreases to 1.39 atm?
Answers
Answer :
-111°C
Hope it helps
The final temperature of the gas in the balloon is equal to -110.6°C.
What is Gay Lussac's law?Gay-Lussac's law can be described as when the volume of the gas is kept constant then the pressure (P) is directly proportional to the absolute temperature (T in kelvin) of the gas.
The mathematical representation of Gay Lussca's law can be written as follows:
P/T = k
The pressure (P) of a gas is always directly proportional to the temperature (T) of the gas.
P ∝ T (where volume is constant)
\(\frac{P_1}{T_1} =\frac{P_2}{T_2}\)
Where P₁, T₁, P₂, and T₂ are the initial and final pressure and temperature.
The initial temperature of the balloon, T₁ = 25 °C = 25 + 273 = 298 K
The initial pressure of the balloon, P₁ = 2.55 atm
The final pressure of the balloon, P₂ = 1.39 atm
Substituting temperatures and pressures of the gas in the balloon in the above equation:
2.55/298 = 1.39/T₂
T₂ = 162.4 K
T(K) = 273 + T(°C)
T(°C) = 162.4 - 273 = - 110.6°C
Therefore, the final temperature of the gas inside the balloon is -110.6°C.
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An insulated container is used to hold 47.5 g of water at 19.3 °C. A sample of copper weighing 14.7 g is placed in a dry test tube and heated for 30 minutes in a boiling water bath at 100.0°C. The heated test tube is carefully removed from the water bath with laboratory tongs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper is 0.385 J/(g·°C), calculate the maximum temperature of the water in the insulated container after the copper metal is added.
Answers
The maximum temperature of the water in the insulated container after the copper metal is added is 40.7 °C.
The problem can be solved using the principle of conservation of energy, which states that the heat lost by the copper metal is equal to the heat gained by the water.
To calculate the heat lost by the copper, the formula
q = m * c * delta T
is used, where q is the heat lost, m is the mass of copper, c is the specific heat of copper, and delta T is the change in temperature of the copper.
Given that the copper is heated from 19.3 °C to 100.0 °C, the heat lost by the copper is calculated to be 450.5 J.
To calculate the heat gained by the water, the same formula is used, where m is the mass of water, c is the specific heat of water, and delta T is the change in temperature of the water.
We are given that the initial temperature of the water is 19.3 °C and the mass of water is 47.5 g. Assuming the final temperature of the water to be T °C, the expression for the heat gained is
47.5 g * 4.184 J/(g·°C) * (T - 19.3) °C.
Equating the expressions for the heat lost and gained, we get
450.5 J = 47.5 g * 4.184 J/(g·°C) * (T - 19.3) °C.
Simplifying and solving for T, we get
T = 40.7 °C,
which is the final temperature of the water after the copper is added.
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The pOH of a solution is 6.0. Which statement is correct?
Use pOH = -log[OH-] and PH+pOH = 14.
The pH of the solution is 20.0.
O The concentration of OH ions is 1.0 x 108 M.
The concentration of OH ions is 1.0 x 106 M.
O The pH of the solution is 8.0.
A
Answers
At pOH value of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)
In this question we will apply the formula
pH +pOH = 14 . . . . . . . . . . . . .(1)
where pH = concentration of [\(H^{+}\) ] ion
pOH = concentration of [\(OH^{-}\) ] ion
As per the question
pOH =6.0
Putting the value of pOH in equation (1) we get the value of pH
pH + 6.0 =14
pH = 14 -6.0
pH = 8.0
The value of pH if the pOH value is 6.0 is 8.0
To find the concentration of \(H^{+}\) ion we will use the following formula
This is calculated by the formula
[\(H^{+}\)} = \(10^{-pH}\)
where we will write the values of pH
Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)
Therefore at pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)
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The complete question is -
What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?
(01.01 LC)What is the body of scientific knowledge based on?
Guesses
Mysteries
Observations
Opinions
Answers
The body of scientific knowledge is based on different Observations (Option C).
What does observations mean in the scientific method?Observations in the scientific method are fundamental because it is the first step to raising scientific questions that may be explained through plausible hypotheses. Subsequently, hypotheses must be tested by experimental procedures.
In conclusion, the body of scientific knowledge is based on different Observations (Option C).
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Which is stronger, the strong force (SF) or the electromagnetic force (EMF)? Describe how they battle each other in the nucleus. What would happen if their strengths were reversed?
Answers
Answer:uclear Force that holds together the nucleus of an atom. electromagnetic force. ... They are unstable because the Strong Force that would hold them together if the protons and neutrons were closer is weakened because the protons and neutrons get too far apart.
Explanation:
The strongest intermolecular interactions between propanol (CH3CH2CH2OH) molecules arise from hydrogen bonding
a. True
b. False
Answers
The claim that the strongest intermolecular interactions between propanol molecules arises from hydrogen bonding is True.
Intermolecular forces are weaker attraction forces that are utilized to define physical characteristics of molecules such as:
boiling point temperature densitymelting pointsHydrogen bonding is an type of intermolecular forces.
It is a type of dipole-dipole interaction that only happens when a hydrogen atom is connected to the atomic element of oxygen, nitrogen, or fluorine.
From the question given, in the propanol (CH3CH2CH2OH) molecule, the hydrogen usually has a partially positive charge which attracts the partially negative charge of the oxygen.
Therefore, we can conclude that the claim is True.
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which force helps keep earth in its orbit around the sun
Answers
The force that helps keep the Earth in its orbit around the Sun is the gravitational force.
The Sun has a massive gravitational pull due to its large mass, which causes the Earth to be attracted towards it. This force of attraction is what keeps the Earth in its stable orbit around the Sun.
The gravitational force between the Sun and the Earth is balanced by the Earth's velocity and centrifugal force, which allows it to maintain a stable orbit around the Sun.
The gravitational force is the attractive force that exists between any two objects with mass. The magnitude of the gravitational force between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them.
This means that the larger the mass of the objects and the closer they are to each other, the stronger the gravitational force between them.
In the case of the Earth and the Sun, the Sun is much more massive than the Earth, which means it exerts a much stronger gravitational force on the Earth. The Earth is constantly falling towards the Sun due to the force of gravity.
However, the Earth also has a tangential velocity that keeps it moving in a circular orbit around the Sun. This is known as centrifugal force, which is the force that acts on an object moving in a circular path, pulling it away from the center of the circle.
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Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g of sodium and 3.93 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample
Answers
Answer:
4.71 g of sodium and 7.25 g of chlorine
Explanation:
Note: The question is incomplete. the complete question is given below:
Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g of sodium and 3.93 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?
4.71 g of sodium and 3.30 g of chlorine
4.71 g of sodium and 7.25 g of chlorine
4.71 g of sodium and 1.31 g of chlorine
4.71 g of sodium and 13.7 g of chlorine
The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.
This means that irrespective of the source of any sample of a pure chemical compound, the constituents elements are always combined in the same mass ratio.
In the first sample, the mass ratio of Sodium to chlorine is given below:
mass of sodium = 2.55 g
mass of chlorine = 3.93 g
mass ratio; sodium to chlorine = 2.55 / 3.93 = 0.65
From the set of masses give above, we can determine the result of the decomposition of the second sample.
4.71 g of sodium and 3.30 g of chlorine
mass ratio; sodium to chlorine = 4.71 / 3.30 = 1.43
4.71 g of sodium and 7.25 g of chlorine
mass ratio; sodium to chlorine = 4.71 / 7.25 = 0.65
4.71 g of sodium and 1.31 g of chlorine
mass ratio; sodium to chlorine = 4.71 / 1.31 = 3.59
4.71 g of sodium and 13.7 g of chlorine
mass ratio; sodium to chlorine = 4.71 / 13.7 = 0.34
From the results above, the correct set of masses for the second sample is 4.71 g of sodium and 7.25 g of chlorine
which properties represent a metal ( select all that apply )
a. malleable
b. shiny
c. dull
d. brittle
e. good conductors
Answers
Malleable, shiny and good conductors
A B E
An oxide of copper is decomposed forming copper metal and oxygen gas. A 0.500 g sample of this oxide is decomposed, forming 0.444 g of copper metal. What is the empirical formula of the copper oxide
Answers
Answer:
Explanation:
.5 g of copper oxide contains .444 g of copper .
its oxygen content = .5 - .444 = .056 g
moles of copper = .444 / 63.5 = 7 x 10⁻³ moles
moles of oxygen atom = .056 / 16 = 3.5 x 10⁻³ moles
ratio of copper and oxygen = 2 : 1
empirical formula of copper oxide = Cu₂O.
Given the following equilibrium constants:
Na2O(s) ⇌ 2 Na(l) + 1/2 O2(g) K1= 2 x 10^–25
NaO(g) ⇌ Na(l) + 1/2 O2(g) K2= 2 x 10^–5
Na2O2(s) ⇌ 2 Na(l) + O2(g) K3= 5 x 10^–29
NaO2(s) ⇌ Na(l) + O2(g) K4= 3 x 10^–14
Determine the value for the equilibrium constants for the following reaction:
2 NaO(g) ⇌ Na2O2(s)
Answers
Answer:
K = 8x10¹⁸
Explanation:
When you sum a reaction, the result of this sum has a K equal to the multiplication of the K's of the reactions involved in the sum
The sum of two times the reaction:
NaO(g) ⇌ Na(l) + 1/2 O₂(g) K₂ = 2x10⁻⁵
2 NaO(g) ⇌ 2 Na(l) + O₂(g) K = K₂ₓK₂ = (2x10⁻⁵)² = 4x10⁻¹⁰
The result of the inverse reaction:
Na₂O₂(s) ⇌ 2 Na(l) + O₂(g) K₃= 5x10⁻²⁹
2 Na(l) + O₂(g) ⇌ Na₂O₂(s) K = 1/K₃ = 2x10²⁸
And the sum of the two bolded reactions:
2 NaO(g) + 2 Na(l) + O₂(g) ⇌ 2 Na(l) + O₂(g) + Na₂O₂(s)
2 NaO(g) ⇌ Na₂O₂(s) K = 4x10⁻¹⁰× 2x10²⁸
K = 8x10¹⁸
6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100