How to write the molecular equation of the following reaction. Also, identify the net ionic equation, the total ionic ecuation and the species that gets reduced and oxidized.

NaHCO3(ac) + HCl(ac)

The mass of hexane, C₆H₁₄ that would be needed to produce 562 grams of carbon dioxide, CO2 is 183 g

We'll begin by writing the balanced equation for the reaction.

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

From the balanced equation above,

528 g CO₂ were produced from 172 g of C₆H₁₄

With the above information, we shall determine the mass of hexane, C₆H₁₄ needed to produce 562 g CO₂. Details below:

From the balanced equation above,

528 g CO₂ were produced from 172 g of C₆H₁₄

Therefore,

562 g of CO₂ will react to produce = (562 × 172) / 528 = 183 g of C₆H₁₄

Thus, the mass of hexane, C₆H₁₄ needed is 183 g

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Answer:

4 millllllermeeters jb

Answer:

4.42x10⁻⁶ m³

Explanation:

Primero convertimos 100 gramos a kilogramos:

Ahora se puede calcular el volumen que ocuparán 0.100 kg de osmio, usando la densidad dada por el problema:

La respuesta es 4.42x10⁻⁶ m³.

If a sample transmits 75% of the incident light, its absorbance would be 0.125 Au.

The absorbance of a sample is calculated from the percentage of incident light transmitted using the following formula:

Absorbance = 2 – log(%T), where %T = percentage of incident light transmitted.

In this case, %T = 75, the formula becomes:

Absorbance = 2 - log 75

                         = 2 - 1.875

                               = 0.125 Au

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Answer

Explanation

Given

number of moles = 4.00 moles

Volume = 3.00 L

Required: Molarity

Solution

C = n/V C is the molarity/concentration, n is the moles and V is the volume

C

The pressure of the environment affects the liquid's boiling point. The boiling point of the liquid is higher when it is under high pressure than when it is under normal atmospheric pressure. For a given pressure, various liquids have different boiling points.

The temperature at which a liquid's vapour pressure equals the surrounding atmosphere is known as the boiling point of the liquid. This temperature causes the liquid to become a vapour.

The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapour all affect its boiling point.

We know that change in temperature of a system is given by the following formula:

Initial boiling point (T₁) = 80.1 °C

ΔT = T₂ - T₁

2.25 = T₂ - 80.1

T₂ = 82.35  °C

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Answer:

82.35

Explanation:

acellus

Answer:

conservation of mass

Answer:

Answer: 3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms . Explanation: The relationship between atoms and moles is:. 1 mole atom. =6.022

Answer:

\(\boxed {\sf 5.63 \times 10^{24} \ atoms \ Li}}\)

Explanation:

We are asked to find how many atoms are in 9.35 moles of lithium (Li)

Moles are converted to atoms using Avogadro's Number or 6.022×10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of lithium.

We convert using dimensional analysis, so we set up a conversion factor using Avogadro's Number.

\(\frac {6.022 \times 10^{23} \ atoms \ Li}{1 \ mol \ Li}\)

We are converting 9.35 moles of lithium to atoms, so we multiply the conversion factor by this value.

\(9.35 \ mol \ Li *\frac {6.022 \times 10^{23} \ atoms \ Li}{1 \ mol \ Li}\)

The units of moles of lithium cancel.

\(9.35 *\frac {6.022 \times 10^{23} \ atoms \ Li}{1 }\)

\(9.35 *{6.022 \times 10^{23} \ atoms \ Li}\)

\(5.63057\times10^{24} \ atoms \ Li\)

The original value of moles (9.35) has 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 0 in the thousandth place tells us to leave the 3 in the hundredth place.

\(5.63 \times 10^[24} \ atoms \ Li\)

9.35 moles of lithium contains approximately 5.63×10²⁴ atoms of lithium.

The pressure of the gas using the ideal gas equation is 14.93 atm.

The pressure of the gas using the van der Waals equation is 3.82 atm.

The pressure of the gas using the ideal gas equation is calculated as follows;

PV = nRT

where;

P = nRT/V

P = (3.9 x 0.08205 x 294)/(6.3)

P = 14.93 atm

P = (RT/Vm - b) - a/Vm²

P = (0.08205 x 294) / (6.3 - 0.03183) - (1.36)/(6.3²)

P = 3.85 - 0.034

P = 3.82 atm

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Hey dear,

Benzene is a 6-C cyclic structure with alternate double bonds.

● Reactions -

1) Benzene to cyclohexane -

Benzene can be reduced to cyclohexane with

the help of Ni/H2. C6H6 + 3H2 --> C6H12

All 3 double bonds in ring are reduced here.

2) Benzene to benzoquinone - Benzene can be oxidized to benzoquinone with

the help of acidic K2Cr207. C6H6 +3[O] --> C6H4O2 + H2O

Only 1 double bond is lost in this reaction.

Hope this helps you.

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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Answer:

The correct answer is (C)

Which is "1-fluorobutane"

Explanation:

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The name of the hydrocarbon CH3CH2CH2CH2F is 1-fluorobutane.

In naming organic hydrocarbons, we count the number of the parent chain family. Here, we have an alkane with 4 carbons, which means that the parent chain is a family of alkane. The fourth compound in the family of an alkane is butane.

Afterwards, we will determine if there is any substituent attached to any of the carbon atoms in the chain and rank them in a way such that we have the lowest possible number.

Here, the fluorine is attached to the first carbon atom. So, it becomes 1-fluorobutane.

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In 15.0 mL of a 2.5 molar magnesium chloride solution, there are approximately 4.51 × 10^{22} chloride ions.

An inorganic compound composed of one magnesium ion and two chloride ions.

We must first determine the number of moles of MgCl_2 in the solution,

moles of solute = concentration × volume (in liters)

Converting the solution's volume from milliliters to liters,

15.0 mL = 15.0 × 10^{-3} L

moles of MgCl_2 = 2.5 mol/L × 15.0 × 10^{-3} L = 0.0375 moles

The solution contains the following number of chloride ions:

number of Cl^{-} ions = 2 × moles of MgCl_2

Substitute the value of moles of MgCl_2,

number of Cl^{-} ions = 2 × 0.0375 moles = 0.075 moles

by using Avogadro's number:

number of Cl^{-} ions = 0.075 moles × 6.02 × 10^{23} ions/mol ≈ 4.51 × 10^{22} ions

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Answer: At very low temperatures, gases expand less for a given pressure change than they do at high temperatures.

Explanation:

Answer:

above me is righttttttt

Question 1 : the empirical formula for the compound is CBr₄.

Question 2 : the molecular formula for the compound is CBr₄.

To determine the empirical formula and molecular formula of the compound, we need to analyze the given percentage composition and molecular weight. Let's go through the process step by step:

Empirical Formula:

The percentage composition by mass states that the compound contains 3.622% carbon and 96.38% bromine. We can assume a 100g sample of the compound to simplify the calculations.

Mass of carbon = (3.622/100) * 100g = 3.622g

Mass of bromine = (96.38/100) * 100g = 96.38g

Next, we need to find the moles of each element. We can use their atomic masses to convert the masses to moles.

Atomic mass of carbon (C) = 12.01 g/mol

Atomic mass of bromine (Br) = 79.90 g/mol

Moles of carbon = Mass of carbon / Atomic mass of carbon = 3.622g / 12.01 g/mol ≈ 0.3017 mol

Moles of bromine = Mass of bromine / Atomic mass of bromine = 96.38g / 79.90 g/mol ≈ 1.205 mol

To find the simplest whole-number ratio between the elements, we divide both moles by the smallest number of moles (0.3017 mol in this case):

Moles of carbon (C) = 0.3017 mol / 0.3017 mol = 1

Moles of bromine (Br) = 1.205 mol / 0.3017 mol ≈ 4

Therefore, the empirical formula for the compound is CBr₄.

Molecular Formula:

Given that the molecular weight (molar mass) of the compound is 331.6 amu, we need to compare it with the empirical formula weight.

Empirical formula weight = (Atomic mass of carbon × Number of carbon atoms) + (Atomic mass of bromine × Number of bromine atoms)

= (12.01 amu × 1) + (79.90 amu × 4) = 12.01 amu + 319.6 amu = 331.61 amu

The molecular weight is very close to the empirical formula weight, indicating that the empirical formula represents the molecular formula as well. Therefore, the molecular formula for the compound is also CBr₄.

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Answer:

Answer: e) A pH = 10.00 buffer solution

Answer:

Ok:

Explanation:

a) 2-fluoropropane

b) 2,3 dichlorobutane

c) pent-2-ene or 2 pentene (I assume the semicolon was a typo)

d) Same as c (I assume Z is a typo too)

e) non-1-ene or 1-nonene (I assume the B is a 2)

There is no reaction between zinc II sulfate and magnesium sulfate.

We know that a reaction is said to occur when two species are combined and there are new products that appear in the system. This implies that if there are no new substances that appear in the system we can not say that a chemical reaction has taken place.

In this case, we can see that we can not be able to observe any change when wee mix a solution of magnesium sulfate and zinc II sulfate since the both of them have the same anion.

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Explanation:

Because both forces are in one direction.

Answer:

0.8853 mL

Explanation:

First we convert 13 lb to kg, keeping in mind that 1 lb = 0.454 kg:

Then we calculate how many mg of acetaminophen should be given, using the recommended dose and infant mass:

Finally we calculate the required mL of suspension, using its concentration:

The maximum distance between the two white balls is 2R, and the maximum angle between them is 180 degrees (or π radians).

Maximum distance between the balls:

The maximum distance between the two white balls will be achieved when they are placed at opposite ends of a diameter of the circular region.

In this case, the distance between them will be equal to the diameter of the circle, which is 2R.

Maximum angle between the balls:

To find the maximum angle between the two balls, imagine the center of the circle as the vertex of the angle, and the positions of the two balls as the endpoints of the angle's two sides.

Since the balls are located at opposite ends of a diameter, the angle formed will be a straight angle, which is 180 degrees (or π radians).

So, the maximum distance between the two white balls is 2R, and the maximum angle between them is 180 degrees (or π radians).

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Two white balls, A and B, are placed on a flat surface inside a circular region of radius R. What is the maximum distance and maximum angle between the balls that can be achieved

When you see  or visit grasslands you know that :

Grasslands are a type of vegetation found mostly in areas with favourable weather conditions such as mild summers and right amount of precipitation which provides the grasslands with enough water for proper growth.

Other types of vegetation include :

Desert vegetation expreciences very hot summers and little precipitation which leads to the scarcity of green vegetation, while forest vegetation expreciences a very high level of precipitation.

Hence we can conclude that When you see  or visit grasslands you know that :They have mild to hot summers ,They have a lot of precipitation  

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Answer:

They have little precipitation.

They have cold winters.

They have mild to hot summers.

Answer:

2CH4(g)+3O2(g)→2CO(g)+4H2O(g)

Explanation:

Start with methane (CH4) and the gas product CO. It is safe to assume that the remaining products and reactants are O2 and H2O. There we have an unbalanced equation CH4+O2->CO+H2O after which it can be balanced as above.

1)The earth is made up of three different layers: the crust, the mantle and the core.

2) I think an earthquake is when the tectonic plates form together and progress movement which cause floor shakiness and everything falls.

3) Earth's interior layers are ordered by density. The densest layer is the solid metal inner core, the mantle is of intermediate density, and the least dense layer is the lithosphere, particularly the continental lithosphere.

4) Earth's crust is divided into two types: oceanic crust and continental crust.

5)Surface waves travel along the surface. There are two types of body waves: P-waves travel fastest and through solids, liquids, and gases; S-waves only travel through solids. Surface waves are the slowest, but they do the most damage in an earthquake.

6)Indirect observation involves the analysis of textual material generated either indirectly from transcriptions of audio recordings of verbal behavior in natural settings or directly from narratives.

7)The mantle is divided into several layers: the upper mantle, the transition zone, the lower mantle, and D” , the strange region where the mantle meets the outer core.

8)The outer core is not under enough pressure to be solid, so it is liquid even though it has a composition similar to the inner core. Sulfur and oxygen could be present in the outer core.

Answer:

D . They are found in moist environments.

Explanation:

Nonvascular plants do not have a xylem or phloem, roots, stems, or leaves. Because these plants lack water-conducting tissues, they fail to achieve the structural complexity and size of most vascular plants and have evolved in habitats which allow their survival and reproduction.

The plant body that is most obvious in non-vascular plants are the the gametophyte generation. The gametophte gemeration is haploid.

The non-vascular plants grow in moist environments. It is due to lack of vascular tissue that requires to maintain close contact with water to prevent desiccation. Nonvascular plants are plants that do not have any special internal pipelines or channels to carry water and nutrients. Instead, nonvascular plants absorb water and minerals directly through their leaflike scales. Nonvascular plants are usually found growing close to the ground in damp, moist places. Non-vascular plants thrive in damp conditions since they don't need to rely on roots to acquire enough water.