A complete circuit is left on for several minutes causing the connecting copper wire to become hot
As the temperature of wire increases, the electrical resistance of wire increases. The correct option is B.
What is resistance?The resistance is the property of material which opposes the current through the wire to pass.
A complete circuit is left on for several minutes causing the connecting copper wire to become hot.
The resistance is directly proportional to the temperature. So, when temperature is increased, the resistance of a wire also increases. The current will have more opposition to flow.
Thus, the correct option is B.
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A horizontal turbine takes in steam with an enthalpy of h = 2.80 MJ/kg at 45 m/s. A steam-water mixture exits the turbine with an enthalpy of h = 1.55 MJ/kg at 20 m/s. If the heat loss to the surroundings from the turbine is 300 J/s, determine the power the fluid supplies to the turbine. The mass flow rate is 0.85 kg/s.
Answer:
The power that fluid supplies to the turbine is 1752.825 kilowatts.
Explanation:
A turbine is a device that works usually at steady state. Given that heat losses exists and changes in kinetic energy are not negligible, the following expression allows us to determine the power supplied by the fluid to the turbine by the First Law of Thermodynamics:
\(-\dot Q_{loss} - \dot W_{out} + \dot m \cdot \left[(h_{in}-h_{out}) + \frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) \right] = 0\)
Output power is cleared:
\(\dot W_{out} = -\dot Q_{loss} + \dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) \right]\)
If \(\dot Q_{loss} = 0.3\,kW\), \(\dot m = 0.85\,\frac{kg}{s}\), \(h_{in} = 2800\,\frac{kJ}{kg}\), \(h_{out} = 1550\,\frac{kJ}{kg}\), \(v_{in} = 45\,\frac{m}{s}\) and \(v_{out} = 20\,\frac{m}{s}\), then:
\(\dot W_{out} = -0.3\,kW + \left(0.85\,\frac{kg}{s} \right)\cdot \left\{\left(2800\,\frac{kJ}{kg}-1550\,\frac{kJ}{kg} \right)+\frac{1}{2}\cdot \left[\left(45\,\frac{m}{s} \right)^{2}-\left(20\,\frac{m}{s} \right)^{2}\right] \right\}\)
\(\dot W_{out} = 1752.825\,kW\)
The power that fluid supplies to the turbine is 1752.825 kilowatts.
A(n) _____ test is performed by end-users and checks the new system to ensure that it works with actual data.
a. integration
b. systems
c. unit
d. acceptance
An acceptance test is performed by end-users to verify that the new system functions properly with actual data.
The correct answer is d. acceptance test. An acceptance test is performed by end-users to verify that the new system functions properly with actual data.
This type of test is crucial to ensure that the system is ready for deployment. It is designed to evaluate whether the system meets the specified requirements and is acceptable for use. During an acceptance test, end-users assess the system's performance, functionality, and usability.
This test is typically conducted after other types of testing, such as unit testing, integration testing, and system testing, have been completed. It is an essential step in the software development life cycle to ensure that the system is ready for production.
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While entering an angled parking spot, when you can see down the ______ of the parking space line closest to your vehicle, turn your wheels and slowly enter the space.
When entering an angled parking spot, it is important to take caution and make sure that you are able to safely enter the spot.
One helpful tip is to look down the line closest to your vehicle to make sure that there are no obstructions or hazards in the way. If you are able to see down the line, you can then turn your wheels and slowly enter the space. This allows for more control and precision when parking your vehicle.
Additionally, it is important to make sure that you are parking within the lines of the spot and leaving enough room for other vehicles to park nearby. By following these guidelines, you can ensure that you are safely and effectively parking in angled parking spots.
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explain the relationship between the concrete compressive strength and its flexural strength and splitting tensile strength.
The relationship between the concrete compressive strength and its flexural strength and splitting tensile strength is that; these strengths are interrelated and their values are dependent on one another.
The compressive strength of concrete is defined as the maximum compressive load that can be applied on a test specimen, to fail in compression. It is expressed in MPa or psi. It is one of the most important properties of concrete and is essential in designing a structure because it defines the concrete’s ability to resist compressive stresses.
A flexural strength test is performed on concrete to determine the strength of concrete in resisting bending stresses. In other words, the test determines the ability of the concrete to withstand bending stresses without cracking. A flexural strength test is important in the design of structural elements like beams, slabs, and other such components that are subjected to bending forces.
The splitting tensile strength of concrete is determined by applying a load on a cylindrical or cubical test specimen of concrete. It is the ability of the concrete to withstand tensile forces that tend to split or rupture the test specimen. It is an important property of concrete because it defines the concrete’s ability to resist tension and shear forces.
The relationship between these three strengths of concrete is that they are interrelated and their values are dependent on one another. In general, the compressive strength of concrete is higher than its flexural strength and splitting tensile strength. However, flexural strength and splitting tensile strength are important in determining the overall strength of concrete, and they are used in the design of structural elements like beams, slabs, and other such components.
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the memory organization of a plc can be divided into two broad categories:
The memory organization of a PLC can be divided into two broad categories:
Program Memory: This category includes the storage of the user-programmed instructions, also known as ladder logic or function block diagrams, which define the behavior of the PLC. Program memory is typically non-volatile, meaning that the program remains stored even if the PLC loses power. This memory is usually divided into different sections, such as the main program, subroutines, and function blocks.
Data Memory: This category encompasses the storage of data used by the PLC during program execution. It includes variables, timers, counters, and other data structures required for the program's operation. Data memory can be further divided into input memory, output memory, and internal memory. Input memory stores the status of input signals, output memory stores the status of output signals, and internal memory stores intermediate values and results generated during program execution.
The division of memory into program memory and data memory allows for efficient and organized execution of the PLC program. The program memory holds the instructions that define the logic and sequence of operations, while the data memory stores the data manipulated by the program. This separation facilitates ease of programming, troubleshooting, and maintenance of the PLC system.
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The field winding of a d. C. Motor is connected directly across a 440 V supply. When the winding is at the room temperature of 17 °C, the current is 2. 3 A. After the machine has been running for some hours, the current has fallen to 1. 9 A, the voltage remaining unaltered. Calculate the average temperature throughout the winding, assuming the temperature coefficient of resistance of copper to be 0. 00426/°C at 0 °C
The average temperature throughout the winding is approximately 137.5°C.
To solve this problem, we need to use the formula for the resistance-temperature relationship of copper:
R2 = R1 [1 + α(T2 - T1)]
where R1 is the resistance of the winding at the initial temperature T1, R2 is the resistance of the winding at the final temperature T2, and α is the temperature coefficient of resistance of copper.
We can rearrange the formula to solve for the final temperature T2:
T2 = (R2/R1 - 1) / α + T1
First, we need to calculate the resistance of the winding at the initial temperature T1 = 17°C:
R1 = V1 / I1 = 440 V / 2.3 A = 191 Ω
Next, we need to calculate the resistance of the winding at the final temperature, which we can do using Ohm's law:
R2 = V1 / I2 = 440 V / 1.9 A = 231.6 Ω
Now we can plug in these values into the formula for T2:
T2 = (231.6/191 - 1) / 0.00426 + 17 = 137.5°C
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A 32x10^-6 F capacitor is connected to a 60V AC supply in series with a 56 ohm resistor. The current flowing in the circuit is 0.16 A.
Calculate the frequency of the AC supply.
The frequency of the AC supply is 0.036 Hz.
What is the frequency?We know that an alternating current circuit is the kind of circuit in which we do have the resistor in addition to the to the capacitor or the inductor or both as the case may be.
Here we are told that; A 32x10^-6 F capacitor is connected to a 60V AC supply in series with a 56 ohm resistor. The current flowing in the circuit is 0.16 A.
We can tell that the impedance of the circuit can be obtained by the use of the formula;
V = IZ
V = voltage
I = current
Z = impedance
Z = V/I
Z = 60 V/0.16 A
Z = 375 ohms
Then we have;
Z = √R^2 - XC^2
375 = √(56)^2 - (1/2 * 3.142 * f * 32x10^-6)^ 2
140625 = 3136 - (1/2 * 3.142 * f * 32x10^-6)^ 2
140625 - 3136 = (1/2 * 3.142 * f * 32x10^-6)^ 2
137489 = 1/2 * 10^-4 f
137489 * 2 * 10^-4 f = 1
f = 1/137489 * 2 * 10^-4
f = 0.036 Hz
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Before a rotameter can be used to measure an unknown flow rate, a calibration curve of flow rate versus rotameter reading must be prepared.
a. True
b. False
Which of the following statements about line balancing is TRUE? A process can be balanced without involving the bottleneck resource. Process capacity can be increased by balancing a process. The average labor utilization cannot be increased by balancing a process.
Process capacity can be increased by balancing a process.
Line balancing is a technique used in production and manufacturing to optimize the allocation of work among different workstations or processes. The main goal of line balancing is to minimize idle time and maximize productivity by distributing work evenly across the available resources. In this context, the statement that process capacity can be increased by balancing a process is true.
When a process is balanced, the workload is evenly distributed among the workstations, ensuring that each station operates at its maximum efficiency. By eliminating bottlenecks and reducing idle time, line balancing helps to increase the overall throughput and productivity of the process.
Balancing a process involves analyzing the tasks required and the time it takes to complete each task. By rearranging the sequence of tasks or adjusting the allocation of resources, it is possible to create a more efficient workflow. This optimization not only reduces the overall processing time but also increases the capacity of the process to handle a higher volume of work.
It's important to note that while line balancing can increase process capacity, it may not necessarily involve the bottleneck resource. The bottleneck resource is the part of the process that limits the overall throughput. While it is crucial to identify and address bottlenecks, line balancing focuses on optimizing the entire process rather than solely focusing on the bottleneck.
In summary, line balancing can increase process capacity by optimizing the allocation of work among different workstations or processes. By evenly distributing the workload and minimizing idle time, line balancing improves productivity and enables the process to handle a higher volume of work.
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A 6-in diameter cylinder falls at the rate of 3 ft/s in an 8 in diameter tube containing an incompressible liquid. What is the mean velocity of the liquid (with respect to the tube) in the space between the cylinder and the tube wall? (Hint: Use continuity)
The mean velocity of the incompressible liquid in the space between the cylinder and the tube wall is approximately 46.29 inches per second.
To find the mean velocity of the incompressible liquid in the space between the cylinder and the tube wall, we'll use the principle of continuity.
Calculate the cross-sectional area of the tube and the cylinder.
Area of the tube A (tube) = π * (Diameter(tube) / 2)² = π * (8 in / 2)² = 16π in²
Area of the cylinder A (cylinder) = π * (Diameter(cylinder) / 2)² = π * (6 in / 2)² = 9π in²
Calculate the area of the space between the cylinder and the tube wall.
Area of space A (space) = A (tube) - A (cylinder) = 16π in² - 9π in² = 7π in²
Apply the principle of continuity.
The volume flow rate through the tube must be equal to the volume flow rate through the space between the cylinder and the tube wall.
Q = A (cylinder) * V (cylinder) = A (space) * V (space)
Plug in the known values and solve for V (space).
V (cylinder) = 3 ft/s = 36 in/s (since 1 ft = 12 in)
Q = 9π in² * 36 in/s = 7π in² * Vspace
Solve for V (space).
V (space) = (9π * 36) / 7π = 324 / 7 ≈ 46.29 in/s
The mean velocity of the incompressible liquid in the space between the cylinder and the tube wall is approximately 46.29 inches per second.
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Which of the following is not a characteristic of an external combustion engine?
A. External pistons are used.
B. Fuel is sent directly to the engine.
C. Boiler burns fuel to produce steam.
D. Steam is sent to the engine to produce power.
Your grandmother is concerned about reducing her winter heating bills. Her strategy is to loosely fit rigid polystyrene sheets of insulation over her double-pane windows right after the first freezing weather arrives in the autumn. Identify the relevant heat transfer processes on a cold winter night when the foamed insulation sheet is placed
a. on the inner surface
b. on the outer surface of her window
c. when no insulation is used.
Sketch a temperature profile through each layer for each case, including for the case with no thermal insulation. For simplicity, assume a linear temperature profile through the air gap.To avoid condensation damage, which configuration is preferred
What does abbreviation vom stand for
Answer:
vom = Volt Ohm Meter
Explanation:
In a short paragraph, discuss the kinds of jobs that Americans can aspire to.
The kinds of jobs that Americans can aspire to include a wide range of professions such as retail salespersons, registered nurses and customer service representatives.
What are some examples of jobs Americans can aspire to?There are numerous career opportunities available for Americans to pursue. For instance, retail salespersons play a crucial role in the retail industry by assisting customers, showcasing products and completing sales transactions.
Registered nurses are in high demand, providing essential healthcare services and tending to the needs of patients. Customer service representatives play a vital role in ensuring positive interactions between companies and their clients, resolving issues and providing support.
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Jamal is demonstrating howto build a game in scratch to several of his friends. for the purpose of his demonstration, he wants the backdrop to continuously keep changing. what type of loop will he need to create in order to do this?
a control loop
b master loop
c forever loop
d motion loop
A type of loop which Jamal will need to create in order to make the backdrop to continuously keep changing is: C. forever loop.
What is a forever loop?A forever loop can be defined as a type of loop which comprises a sequence of instructions that are written to run continuously or endlessly, until the simulation is quitted by an end user.
This ultimately implies that, a forever loop should be created by Jamal to make the backdrop to continuously keep changing.
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Answer: C
Explanation:
To any of you who are also taking Game Design, I have respect for you.
The current at resonance in a series L-C-R circuit is 0.2mA. If the applied voltage is 250mV at a frequency of 100 kHz and the circuit capacitance is 0.04 microfrad . Find the circuit resistance and inductance
Answer:
The resistance of the circuit is 1250 ohmsThe inductance of the circuit is 0.063 mH.Explanation:
Given;
current at resonance, I = 0.2 mA
applied voltage, V = 250 mV
resonance frequency, f₀ = 100 kHz
capacitance of the circuit, C = 0.04 μF
At resonance, capacitive reactance (\(X_c\)) is equal to inductive reactance (\(X_l\)),
\(Z = \sqrt{R^2 + (X_ l - X_c)^2} \\\\But \ X_l= X_c\\\\Z = R\)
Where;
R is the resistance of the circuit, calculated as;
\(R = \frac{V}{I} \\\\R = \frac{250 \ \times \ 10^{-3}}{0.2 \ \times \ 10^{-3}} \\\\R = 1250 \ ohms\)
The inductive reactance is calculated as;
\(X_l = X_c = \frac{1}{\omega C} = \frac{1}{2\pi f_o C} = \frac{1}{2\pi (100\times 10^3)(0.04\times 10^{-6} ) } = 39.789 \ ohms\\\)
The inductance is calculated as;
\(X_l = \omega L = 2\pi f_o L\\\\L = \frac{X_l}{2\pi f_o}\\\\L = \frac{39.789}{2\pi (100 \times 10^3)} \\\\L= 6.3 \ \times \ 10^{-5} \ H\\\\L = 0.063 \times \ 10^{-3} \ H\\\\L = 0.063 \ mH\)
Use the ________________ property to configure rounded corners with CSS?
Answer: border-radius
Explanation:
explain why brittle materials crack when exposed to large stress concentrations that does not fracture ductile materials.
A crack in a brittle material adds a lot of stress to its tip. one way to prevent such a crack from progressing is to drill a hole. at the end of the crack to increase its radius and thus reduce the stress. fracture occurs in a brittle material when the stress concentration exceeds the reduction in strength of the material.
What is brittle material?Brittle materials are characterized by low deformation, poor resistance to impact and load-vibration, high compressive strength and low tensile strength. Most inorganic non-metallic materials are brittle materials.
Brittle materials include glass, ceramics, graphite, and some alloys that have very low ductility and where cracks can form without plastic deformation and can soon develop into brittleness.
A material is considered brittle when it breaks under tension with little elastic deformation and no significant plastic deformation.
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A refrigerator with a COP of 3.0 removes heat from the refrigerated space at a rate of 10 kW. Determine the rate of power input.
The rate of power input for this refrigerator is 3.33 kW.
A refrigerator with a COP (Coefficient of Performance) of 3.0 is designed to remove heat from the refrigerated space efficiently. The COP is the ratio of the amount of heat removed from the refrigerated space to the work (power input) done by the refrigerator.
In this case, the heat removal rate is given as 10 kW. To determine the rate of power input, we can use the following formula:
COP = (Heat removal rate) / (Power input)
Rearranging the formula to solve for the power input:
Power input = (Heat removal rate) / COP
By substituting the given values:
Power input = (10 kW) / (3.0)
Power input = 3.33 kW (approx.)
So, the rate of power input for this refrigerator is approximately 3.33 kW. This means that for every 3.33 kW of electrical power supplied to the refrigerator, it is able to remove 10 kW of heat from the refrigerated space. A higher COP indicates a more energy-efficient refrigerator.
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A helicopter landing pad is to be constructed over an area of 40 ft by 70 ft. It is to be 2 ft thick. How many cubic feet must be ordered?
The volume of cuboid in cubic feet which must be ordered is equal to 5,600 cubic feet.
Given the following data:
Length of helicopter landing pad = 40 ft.
Width of helicopter landing pad = 70 ft.
Height or thickness of helicopter landing pad = 2 ft.
How to calculate the volume of a geometric figure?Based on the information provided, we can reasonably infer and logically deduce that the shape of this helicopter landing pad is a cuboid.
Mathematically, the volume of a cuboid can be calculated by using this following formula:
Volume = l × w × h
Where:
l represents the length of a cuboid.w represents the width of a cuboid.h represents the height of a cuboid.Substituting the given parameters into the formula, we have;
Volume = 40 × 70 × 2
Volume = 5,600 cubic feet.
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determine the depth of flow in a 12-inch diameter concrete pipe with a channel slope of 0.0085 carrying 0.2 ft3 /s of water.
Answer:
it is not water
One good way to improve your gas mileage is to _____.
to be considered a complete warm up cycle, the engine must reach a temperature of
To be considered a complete warm-up cycle, the engine must reach a temperature that is optimal for its efficient and safe operation.
The specific temperature required for a complete warm-up cycle may vary depending on the engine type, fuel used, and other factors. Generally, the engine should reach its normal operating temperature, which is typically around 195-220 degrees Fahrenheit (90-105 degrees Celsius) for most gasoline-powered vehicles. This temperature allows the engine to operate efficiently, burn fuel effectively, and minimize wear and tear on engine components. However, it's important to consult the manufacturer's guidelines or the vehicle's owner's manual for the recommended warm-up temperature specific to your engine model.
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The first law of thermodynamics relates the heat transfer into ot out of a system to the change of internal and the work done on the system. How much beat, in joules, is transferred into a syatem when its internal energy decreases by 349 f while it was performing 31:53 of work?
The first law of thermodynamics relates the heat transfer into ot out of a system to the change of internal and the work done on the system.
The first law of thermodynamics states that any change in the internal energy of a system is due to heat transfer and the work done on the system. When a system's internal energy decreases by 349 J and performs 31.53 J of work, we need to calculate the amount of heat transferred into the system. The equation is given as follows:ΔU = Q - WWhere,ΔU = Change in internal energyQ = Heat transfer into the systemW = Work done by the systemWe can rearrange the equation to calculate the amount of heat transferred into the system.Q = ΔU + WSubstitute the given values, we get,Q = -349 J + 31.53 JQ = -317.47 JTherefore, the amount of heat transferred into the system when its internal energy decreases by 349 J while performing 31.53 J of work is -317.47 J (joules). Note that the negative sign indicates that heat is being transferred out of the system instead of into it.
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Crude oil at 20 c fills the space between two concentric cylinders 250 mm high and with diameters of 150 mm and 156 mm. Find the torque is required to rotate the inner cylinder at 12 r min, the outer cylinder rernaining stationary
the torque is required to rotate the inner cylinder at 12 r min, the outer cylinder remaining stationary is 11.0807 N-m.
we have left out some other important details, such as the time required to reach that rpm, whether the beginning state is at rest, and the axis around which the cylinder is revolving. However, we'll suppose that it will be 60 seconds (time is necessary to convert rpm to angular acceleration)
rotation around the center axis
Angular acceleration = torque + MOI
Currently, angular acceleration equals 2 rpm/(t 60).
In order to avoid getting an extremely high figure, we estimated that the diameter of the cylinder was 600 mm rather than 600 meters: angular acceleration= 1.047 rad/s² MOI for cylinder across center dia= 1/4MR²+ 1/12ML²
MOI= 10.5833 kg-m
Now, the product of these two is torque.
11.0807 N-m of torque
Various MOI equations can be used to compute for different axes of rotation.
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The complete question is:
Crude oil at 20 c fills the space between two concentric cylinders 250 mm high and with diameters of 150 mm and 156 mm. Find the torque is required to rotate the inner cylinder at 12 r min, the outer cylinder remaining stationary.
A country needs to build new power plants to meet
the increasing demand for electric power. One possibility is
to build coal-fired power plants, which cost $1300 per kW
to construct and have an efficiency of 40 percent. Another
possibility is to build clean-burning Integrated Gasification
Combined Cycle (IGCC) plants where the coal is subjected to
heat and pressure to gasify it while removing sulfur and particulate matter from it. The gaseous coal is then burned in a
gas turbine, and part of the waste heat from the exhaust gases
is recovered to generate steam for the steam turbine. The construction of IGCC plants costs about $1500 per kW, but their
efficiency is about 48 percent. The average heating value of
the coal is about 28,000,000 kJ per ton (that is, 28,000,000 kJ
of heat is released when 1 ton of coal is burned). If the IGCC
plant is to recover its cost difference from fuel savings in five
years, determine what the price of coal should be in $ per ton.
Answer:
To determine the price of coal that would allow the IGCC plant to recover its cost difference from fuel savings in five years, we first need to calculate the cost savings of the IGCC plant compared to the coal-fired power plant. The IGCC plant costs $1500 per kW to construct and has an efficiency of 48 percent, while the coal-fired power plant costs $1300 per kW to construct and has an efficiency of 40 percent. The cost savings of the IGCC plant can be calculated as follows:
$1500/kW - $1300/kW = $200/kW
We can then calculate the total cost savings of the IGCC plant over a five-year period by multiplying the cost savings per kW by the total number of kW the plant will generate in five years. For this calculation, we will assume that the plant will generate 1,000 kW of power.
$200/kW * 1000 kW = $200000
Next, we need to calculate the amount of coal that the IGCC plant would need to burn over a five-year period to generate 1,000 kW of power. We know that the average heating value of coal is 28,000,000 kJ per ton, and that the efficiency of the IGCC plant is 48 percent. We can calculate the amount of coal the IGCC plant would need to burn as follows:
1,000 kW / (28,000,000 kJ/ton * 0.48) = 10.7 tons
Finally, we can calculate the price of coal that would allow the IGCC plant to recover its cost difference from fuel savings in five years by dividing the total cost savings by the amount of coal the plant would need to burn over the same period.
$200000 / 10.7 tons = $18,661.04/ton
Therefore, the price of coal that would allow the IGCC plant to recover its cost difference from fuel savings in five years is $18,661.04/ton.
You are installing network cabling and require a cable solution that provides the best resistance to EMI.Which of the following will you choose for this installation?
Answer: b. STP
Explanation:
Twisted Pair Cables are best used for network cabling but are usually prone to EMI (Electromagnetic Interference) which affects the electrical circuit negatively.
The best way to negate this effect is to use Shielding which will help the cable continue to function normally. This is where the Shielded Twisted Pair (STP) cable comes in.
As the name implies, it comes with a shield and that shield is made out of metal which can enable it conduct the Electromagnetic Interference to the ground. The Shielding however makes it more expensive and in need of more care during installation.
* Question 1: Design alarm system as shown below. The alarm turns on when one of the following
conditions happened:
A. Motion IR sensor & window sensor
activated.
B. Motion IR sensor & door sensor
activated.
C. Otherwise the buzzer off.
(A)
Warning
Motion
Sensors
Buzzer
Suppose that: Warning buzzer on pin 8
Motion sensor on pin 5
Window sensor on pin 6
Door sensor on pin 7
The buzzer works on beating mode.
(C)
Door
sensor
TE
(B)
Window
Sensors
Answer:
A
Explanation:
QU A pipeline was plotted on a map having a scale 1/2000. Its length on
this map = 50cm. What would be the length on a map having a scale 1/1000
Answer:
\(L =100cm\)
Explanation:
Given
\(Scale = \frac{1}{2000}\) ----- \(Length = 50cm\)
Required
Determine the length when the scale is: \(Scale = \frac{1}{1000}\)
The scale to length can be represented as:
\(Ratio = Scale: Length\)
Represent as fraction
\(Ratio = \frac{Scale}{Length}\)
When:
\(Scale = \frac{1}{2000}\) and \(Length = 50cm\)
\(Ratio = \frac{1/2000}{50cm}\)
When \(Scale = \frac{1}{1000}\), represent the length with L
\(Ratio = \frac{1/1000}{L}\)
Equate both ratios
\(\frac{1/2000}{50cm} = \frac{1/1000}{L}\)
Cross Multiply:
\(L * \frac{1}{2000} = 50cm * \frac{1}{1000}\)
Multiply through by 2000
\(L * \frac{1}{2000} * 2000 = 50cm * \frac{1}{1000} * 2000\)
\(L = 50cm * 2\)
\(L =100cm\)
Hence, the length on the new scale would be 100cm