Jane thinks of a number. call it X. She doubles her number, then adds 5 to double the number. What is the number?​

Answer:

its B

Step-by-step explanation:

edg

Answer:

Step-by-step explanation:

In step 2, the like terms were not combined properly on the right side of the equation. or B

Answer: C.V=C1.V1 +C2.V2

Step-by-step explanation: C=(C1V1 + C2V2)/V -> C=(20%.V+25%V)/2V-> C=22,5%

The sequence's eighth partial total, then, is zero.

A series is a collection of things that is in order in mathematics. (or events). Similar to a group, it has individuals. (also called elements, or terms). The total length of the series is the number in ordered components (possibly endless).

The sequence is: 24, -24, 24, -24, ...

To find the 8th partial sum, we need to add the first 8 terms of the sequence.

S8 = 24 + (-24) + 24 + (-24) + 24 + (-24) + 24 + (-24)

Simplifying this expression, we see that every pair of adjacent terms cancels each other out, leaving us with:

S8 = 0 + 0 + 0 + 0

Therefore, the 8th partial sum of the sequence is 0.

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Answer:

(2, -2)

Step-by-step explanation:

Multiply the first equation by -3,and multiply the second equation by 1.

−3(5x+6y=−2)

1(15x+4y=22)

Becomes:

−15x−18y=6

15x+4y=22

Add these equations to eliminate x:

−14y=28

Then solve−14y=28for y:

−14y=28

−14y

−14

=

28

−14

(Divide both sides by -14)

y=−2

Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

5x+6y=−2

Substitute−2foryin5x+6y=−2:

5x+(6)(−2)=−2

5x−12=−2(Simplify both sides of the equation)

5x−12+12=−2+12(Add 12 to both sides)

5x=10

5x

5

=

10

5

(Divide both sides by 5)

x=2

Answer:

x=2 and y=−2

Answer:

(2,-2)

Step-by-step explanation:

The relation R is symmetric and antisymmetric, but not reflexive or transitive.

Let's examine each property of the relation R separately:

Reflexive: A relation R is reflexive if every element in the set is related to itself. In this case, we have (x, x-1) or (x-1, x) for any integer x. Therefore, the relation is not reflexive since x is not related to itself.

Symmetric: A relation R is symmetric if for any pair of elements x and y in the set, (x,y) being in R implies that (y,x) is also in R. In this case, we have (x, y-1) or (y, x-1) for any integers x and y. It is clear that if (x, y-1) is in R, then (y, x-1) is also in R, and vice versa. Therefore, the relation is symmetric.

Antisymmetric: A relation R is antisymmetric if for any distinct elements x and y in the set, if (x,y) is in R, then (y,x) cannot also be in R. In this case, if we have (x, y-1) and (y, x-1), then x = y-1 and y = x-1. This implies that x = y, which contradicts our assumption that x and y are distinct. Therefore, the relation is antisymmetric.

Transitive: A relation R is transitive if for any elements x, y, and z in the set, if (x,y) and (y,z) are in R, then (x,z) is also in R. In this case, we have (x, y-1) and (y, z-1) for any integers x, y, and z. If we add these two relations, we get (x, z-2).

However, this does not satisfy the original relation, which requires that (x, z-1) be in R. Therefore, the relation is not transitive.

In summary, the relation R is symmetric and antisymmetric, but not reflexive or transitive.

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The cost of a Powerade is $0.75 if 2 bags of chips and 2 Powerades cost $3.50 and one bag of chips and 3 Powerades cost $3.75.

Let the cost of one Powerade be x

The cost of one bag of chips be y

Cost of 2 bags of chips and 2 Powerades = $3.50

Cost of 2 bags of chips = 2y

Cost of 2 Powerades = 2x

2x + 2y = 3.50 ----(i)

Cost of one bag of chips and 3 Powerades= $3.75

Cost of 1 bag of chips = y

Cost of 3 Powerades = 3x

x + 3y = 3.75

Multiply the above equation by 2

2x + 6y = 7.50 -----(ii)

Subtract (ii) and (i)

4y = 4

y = $1

The cost of one bag of chips is $1

x + 3 = 3.75

x = $0.75

The cost of one Powerade is $0.75

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Answer:

Step-by-step explanation:

Story Problem:

Samantha is baking cookies and her recipe calls for 3 cups of flour. She only has a bag of flour that is 7/8 full. If each cup of flour weighs the same, how much flour does Samantha have left after taking out the 3 cups needed for the recipe?

Solution:

To solve the problem, we need to multiply the amount of flour in the bag by 3/1 (which is the same as multiplying by 3).

3 x 7/8 = (3 x 7)/8 = 21/8

So, Samantha has 21/8 cups of flour in the bag.

To find out how much flour she has left after taking out the 3 cups needed for the recipe, we need to subtract 3 from 21/8:

21/8 - 3 = 21/8 - 24/8 = -3/8

Samantha has -3/8 cups of flour left in the bag, which means she doesn't have enough flour to make the recipe. She needs to get more flour before she can continue baking.

Answer:

Look below

Step-by-step explanation:

Ken drinks 7/8 of a carton of milk each day. How much milk does

he drink in 3 days?

7/8*3

21/8

2 5/8 cartons of milk a day

1.1) The volume of the cube is 27 cubic centimeters. 1.2)the density of the ice cube is approximately 0.917 grams per cubic centimeter (g/cm³).

1.3) the mass of the water cube is 27 grams. 1.4) the weight of the water and the ice would be the same under the same conditions. 1.5)In simpler terms, ice floats on water because it is lighter (less dense) than the water, allowing it to displace an amount of water equal to its weight and float on the surface.

1.1) The volume of the cube can be calculated using the equation: Volume = width x height x length. In this case, the cube measures 3 cm wide, 3 cm tall, and 3 cm long, so the volume is:

Volume = 3 cm x 3 cm x 3 cm = 27 cm³.

Therefore, the volume of the cube is 27 cubic centimeters.

1.2) Density is defined as mass divided by volume. The mass of the ice cube is given as 24.76 grams, and we already determined the volume to be 27 cm³. Therefore, the density of the ice cube is:

Density = Mass / Volume = 24.76 g / 27 cm³ ≈ 0.917 g/cm³.

Therefore, the density of the ice cube is approximately 0.917 grams per cubic centimeter (g/cm³).

1.3) The volume of the water cube is the same as the ice cube, which is 27 cm³. Given the density of liquid water as 1.00 g/cm³, we can calculate the mass of the water cube using the equation:

Mass = Density x Volume = 1.00 g/cm³ x 27 cm³ = 27 grams.

Therefore, the mass of the water cube is 27 grams.

1.4) The weight of an object depends on both its mass and the acceleration due to gravity. Since the volume of the water cube and the ice cube is the same (27 cm³), and the mass of the water cube (27 grams) is equal to the mass of the ice cube (24.76 grams), their weights would also be equal when measured in the same gravitational field.

Therefore, the weight of the water and the ice would be the same under the same conditions.

1.5) Ice floats on water because it is less dense than liquid water. The density of ice is lower than the density of water because the water molecules in the solid ice are arranged in a specific lattice structure with open spaces. This arrangement causes ice to have a lower density compared to liquid water, where the molecules are closer together.

When ice is placed in water, the denser water molecules exert an upward buoyant force on the less dense ice, causing it to float. The buoyant force is the result of the pressure difference between the top and bottom surfaces of the submerged object.

In simpler terms, ice floats on water because it is lighter (less dense) than the water, allowing it to displace an amount of water equal to its weight and float on the surface.

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Answer:

Point f

Step-by-step explanation:

W

Answer:(-5,6)

Step-by-step explanation:

The solution to the equation \((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\) is 10.3891

From the question, we have the following parameters that can be used in our computation:

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\)

Using the following trigonometry ratio

sin²(x) + cos²(x) = 1

We have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = (\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + 1 + e^2\)

The sum to infinity of a geometric series is

S = a/(1 - r)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = \frac{1/2}{1 - 1/2} + \frac{9/10}{1 - 1/10} + 1 + e^2\)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 1 + 1 + 1 + e^2\)

Evaluate the sum

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 3 + e^2\)

This gives

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 10.3891\)

Hence, the solution to the equation is 10.3891

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Hence, in response to the provided question, we can say that As a result,  equation the item's selling price after both markdowns is 166.40$.

An algebraic equation is a method of connecting two quotes by using the equals symbol (=) to express equality. In algebra, an explanation is a definitive expression that verifies the equivalency of two formula. For example, the identical character divides the numbers 3x + 5 and 14. A linear equation might be used to recognize the connection that existing between the texts written on separate sides of a letter. The product and application both frequently the same. 2x - 4 equals 2, for example.

Then, we may determine the item's price after the initial 20% discount.

20% of 520$ equals (20/100) * 520$ = 104$, hence the item's new price is 520$ - 104$ = 416$.

After another six months of not selling, the item gets reduced by 60%.

60% of 416$ equals (60/100) * 416$ = 249.60$, therefore the item's ultimate sale price after both markdowns is 416$ - 249.60$ = 166.40$.

As a result, the item's selling price after both markdowns is 166.40$.

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Using equations, we can find that the item's selling price after both markdowns is 166.40$.

In an algebraic equation, the equals symbol (=), which represents equality, can be used to connect two quotes. In algebra, an explanation is a declarative statement that establishes the similarity of two formulas. For example, the integers 3x + 5 and 14 are divided by the same letter.

A linear equation can be used to identify the relationship between the texts written on the various sides of a letter. Applications and products can typically be used interchangeably. In this instance, 2x – 4 = 2.

After applying the initial 20% discount, we may determine the item's price as:

20% of 520$ equals (20/100) × 520$ = 104$

Hence the item's new price is 520$ - 104$ = 416$.

After another six months of not selling, the item gets reduced by 60%.

60% of 416$ equals (60/100) × 416$ = 249.60$

Therefore, the item's ultimate sale price after both markdowns is

416$ - 249.60$ = 166.40$.

As a result, the item's selling price after both markdowns is 166.40$.

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Answer:

(15+6)÷3

hope it helps!!

so we know the equation to get the total forces is

\(\cfrac{Kg\cdot m}{s^2} ~~ \begin{cases} Kg=kilograms\\ m=meters\\ s=seconds \end{cases}\implies Kg\cdot \cfrac{m}{s^2}\implies Kg\cdot (acceleration)\)

the idea being, well, we have to do unit conversion, we know the object has a mass of 80 grams, hmmm that's not Kilograms, however since there are 1000 grams in a Kg, we can just convert that, and the acceleration of it is 20 m/s², so

\(\stackrel{ Kilograms }{\cfrac{80}{1000}}\cdot \stackrel{ accelaration }{20}\qquad \impliedby \textit{sum of the forces}\)

The difference quotient of the function f(x) = 4x² - 5x is 8x + 4h - 5.

The formula for difference quotient is expressed as:

\(\frac{f(x+h)-f(x)}{h}\)

Given the function in the question:

f(x) = 4x² - 5x

To solve for the difference quotient, we evaluate the function at x = x+h:

First;

f(x + h) = 4(x + h)² - 5(x + h)

Simplifying, we gt:

f(x + h) = 4x² + 8hx + 4h² - 5x - 5h

f(x + h) = 4h² + 8hx + 4x² - 5h - 5x

Next, plug in the components into the difference quotient formula:

\(\frac{f(x+h)-f(x)}{h}\\\\\frac{(4h^2 + 8hx + 4x^2 - 5h - 5x - (4x^2 - 5x)}{h}\\\\Simplify\\\\\frac{(4h^2 + 8hx + 4x^2 - 5h - 5x - 4x^2 + 5x)}{h}\\\\\frac{(4h^2 + 8hx - 5h)}{h}\\\\\frac{h(4h + 8x - 5)}{h}\\\\8x + 4h -5\)

Therefore, the difference quotient is 8x + 4h - 5.

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Answer:

1

Step-by-step explanation:

Mean is the average amount of numbers. To find the mean, add all the numbers up and then subtract by how many there are.

All of those numbers together equal 9 and because there are 9 values there, I divided them which gave me 1.

To calculate the probability that a randomly selected string with exactly ten characters is a valid password, we need to find the number of valid passwords and divide it by the total number of possible strings of length ten.

First, we can calculate the total number of possible strings of length ten. Since the string can contain upper-case letters, lower-case letters, and digits, the size of the sample space is 62^10 (26 upper-case letters + 26 lower-case letters + 10 digits = 62 total characters).

Next, we can calculate the number of valid passwords. The password must be at least 10 characters long, so there are no valid passwords of length less than 10.

For a valid password of length 10, we can choose one character from each of the three sets (upper-case letters, lower-case letters, and digits), and then choose any seven more characters from the 62 total characters. Therefore, the number of valid passwords of length 10 is (26 x 26 x 10) x (62-3)^7.

Thus, the probability that a randomly selected string with exactly ten characters results in a valid password is the number of valid passwords divided by the total number of possible strings, which is:

(26 x 26 x 10) x (62-3)^7 / 62^10 = 0.000144

Therefore, the probability that a randomly selected string with exactly ten characters is a valid password is approximately 0.000144 or 0.0144%.

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Answer:

x = 9

Step-by-step explanation:

Isolate x first by moving 16 to the other side

x = 25 - 16

x = 9

Answer

r=3

Step-by-step explanation:

Use the slope formula

m=y2-y1/x2-x1

r-(-2)/6-1

r+2/5

r+2=5

r=5-2

r=3

Answer:

I am not sure but I think its 4.4 since they are verticle angles

Step-by-step explanation:

Answer:

0.73

Step-by-step explanation:

1/3(ky)

1/3 (2.2)

0.73

i don't know if it's right

i hope it helps uuu

Answer:

Solutions below.

Step-by-step explanation:

This question tests on the concept of Composite Functions

Composite functions are functions that is derived from another new and separate function.

Example: f(x) = 5x, g(x) = 9x , (f • g)(x) = f(g(x)) = f(9x) = 5(9x) = 45x

Given to us are 2 functions:

f(x) =

\( {x}^{2} - 7x + 4\)

g(x) =

\( - 2x\)

We are asked to find (f • g)(4). We first find (f • g)(x).

(f • g)(x) = f(g(x)) = f(-2x) =

\( {( - 2x)}^{2} - 7( - 2x) + 4 \\ = 4 {x}^{2} + 14x + 4 \\ = 2(2 {x}^{2} + 7x + 2)\)

Now, we will find the value of (f • g)(4) by substituting x = 4 into (f • g)(x).

(f • g)(4) =

\(2(2 {(4)}^{2} + 7(4) + 2) \\ = 2(2(16) + 28 + 2) \\ = 2(32 + 28 + 2) \\ = 2(62) \\ = 124\)

Answer:

A relation is defined as the collection of inputs and outputs which are related to each other in some way. In case, if each input in relation has accurately one output, then the relation is called a function.

Based on the given relation, we found that it is not a function because it has repeating x-values. Remember, for a relation to be a function, each input (x-value) must correspond to exactly one output (y-value).

To determine if a relation is a function, you need to check if each input (x-value) corresponds to exactly one output (y-value). You can use the following steps:

1. Identify the given relation as a set of ordered pairs, where each ordered pair represents an input-output pair.

2. Check if there are any repeating x-values in the relation. If there are no repeating x-values, move to the next step. If there are repeating x-values, the relation is not a function.

3. For each unique x-value, check if there is only one corresponding y-value. If there is exactly one y-value for each x-value, then the relation is a function. If there is more than one y-value for any x-value, then the relation is not a function.

Let's consider an example relation: {(1, 2), (2, 3), (3, 4), (2, 5)}.

Step 1: Identify the relation as a set of ordered pairs: {(1, 2), (2, 3), (3, 4), (2, 5)}.

Step 2: Check for repeating x-values. In our example, we have a repeating x-value of 2. Therefore, the relation is not a function.

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Answer:

990

Do 100+890

its simple math

The number that is one hundred more than 890 would be,

⇒ 990

The process of combining two or more numbers is called the Addition. The 4 main properties of addition are commutative, associative, distributive, and additive identity.

Given that,

To find a number that is one hundred more than 890.

Let us assume that,

The number that is one hundred more than 890 = x

Hence, it can be written as,

⇒ x = 890 + 100

Solve for x,

⇒ x = 990

Therefore, the number that is one hundred more than 890 = 990

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\(A=\frac{\pi}{8}+\frac{n\pi}{4}or\ A=\frac{\pi}{2}+n\pi\)

\(cos3A+cos5A=0\)

________________________________________________________

\(2cos(\frac{3A+5A}{2})cos(\frac{3A-5A}{2})=0\)

________________________________________________________

\(2cos(\frac{8A}{2})cos(\frac{3A-5A}{2})=0\\\\ 2cos(\frac{8A}{2})cos(\frac{-2A}{2})=0\)

________________________________________________________

\(cos(\frac{8A}{2})cos(\frac{-2A}{2})=0\)

________________________________________________________

\(cos(\frac{8A}{2})=0\ or\ cos(\frac{-2A}{2})=0\)

________________________________________________________

\(cos\ 4A=0\)

________________________________________________________

\(4A=\frac{\pi}{2}or\ 4A=\frac{3\pi}{2}\)

________________________________________________________

\(4A=\frac{\pi}{2}+2n\pi \ or\\ \\ 4A=\frac{3 \pi}{2}+2n \pi\\ \\A=\frac{\pi}{8}+\frac{n \pi}{4\\}\)

________________________________________________________

\(cos(-A)=0\)

________________________________________________________

\(cosA=0\)

________________________________________________________

\(A=\frac{\pi }{2}\ or\ A=\frac{3 \pi}{2}\)

________________________________________________________

\(A=\frac{\pi}{2}+2n\pi\ or\ A=\frac{3\pi}{2}+2n\pi,n\in\ Z\)

________________________________________________________

\(A=\frac{\pi}{2}+n\pi\)

________________________________________________________

\(A=\frac{\pi}{8}+\frac{n\pi}{4}\ or\ A=\frac{\pi}{2}+n\pi ,n\in Z\)

I hope this helps you

:)

Answer: men: 120 men, 310 women, and 170 children

600*0.2=120

600*0.35=310

600-120-310=170

The rules of the calculation are:

The complete question is added as an attachment

The equation is given as:

0.738 × 0.28 = 0.20664

When approximated, we have:

0.738 × 0.28 ≈ 0.21

The above approximation can mean any of the following:

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Rigid transformation are transformation that preserve the shape and size hence producing congruent figures such as translation, reflection and rotation.

Dilation is a non rigid transformation and does not produce congruent figures.

Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, translation, rotation and dilation.

Rigid transformation are transformation that preserve the shape and size hence producing congruent figures such as translation, reflection and rotation.

Dilation is a non rigid transformation and does not produce congruent figures.

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Answer:

b,c,e,d,a,f

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

\(4x^{2} +6x-3-8x^{2} -2x-9\)

Collect like terms:

\((4x^{2} -8x^{2} )+(6x-2x)+(-3+-9)\)

\(-4x^{2} + 4x -12\)

This matches with Option C

Answer:

It is not the same because 10 to the power of 3 is 10,000 and 10x3 is 30 so no.

Step-by-step explanation:

Answer:

Yes because they both have 3 zeros and have the same value

Step-by-step explanation:

This is the UML diagram for the development of the program, in which Shapes 2D is the superclass and Circle, Square, Triangle, Rectangle, Rhombus, and Parallelogram are subclasses.

​​​​​​​This is the program in C++ demonstrating the above classes.

#include<iostream>

using namespace std;

class shapes

{

public:

   string name;

   string color;

   virtual void getAttributes()=0;

};

class Circle: public shapes

{

public:

   float radius;

   Circle(string n,string c, float r)

   {

       name=n;

       color=c;

       radius=r;

   }

   float getPerimeter()

   {

       return(2*(3.142)*radius);

   }

   float getArea()

   {

       return((3.142)*(radius*radius));

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Square:public shapes

{

public:

   float side;

   Square(string n,string c, float s)

   {

       name=n;

       color=c;

       side=s;

   }

   float getPerimeter()

   {

       return(4*side);

   }

   float getArea()

   {

       return(side*side);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Triangle:public shapes

{

public:

   float base;

   float height;

   float side1;

   float side2;

   float side3;

   Triangle(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter side1\n";

       cin>>side1;

       cout<<"Enter side2\n";

       cin>>side2;

       cout<<"Enter side3\n";

       cin>>side3;

       return(side1+side2+side3);

   }

   float getArea()

   {

       cout<<"Enter base\n";

       cin>>base;

       cout<<"Enter height\n";

       cin>>height;

       return((0.5)*base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rectangle:public shapes

{

public:

   float length;

   float breadth;

   Rectangle(string n,string c, float l,float b)

   {

       name=n;

       color=c;

       length=l;

       breadth=b;

   }

   float getPerimeter()

   {

       return(2*(length+breadth));

   }

   float getArea()

   {

       return(length*breadth);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rhombus:public shapes

{

public:

   float diagonal1;

   float diagonal2;

   float side;

   Rhombus(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter Side\n";

       cin>>side;

       return(4*side);

   }

   float getArea()

   {

       cout<<"Enter diagonal 1\n";

       cin>>diagonal1;

       cout<<"Enter diagonal 2\n";

       cin>>diagonal2;

       return((0.5)*diagonal1*diagonal2);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Parallelogram:public shapes

{

public:

   float base;

   float height;

   Parallelogram(string n,string c, float b,float h)

   {

       name=n;

       color=c;

       base=b;

       height=h;

   }

   float getPerimeter()

   {

       return(2*(base+height));

   }

   float getArea()

   {

       return(base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

int main()

{

   int choice;

   while(1)

   {

       cout<<"\n\nEnter your choice :";

       cout<<"\n1 for Circle\n";

       cout<<"2 for Square\n";

       cout<<"3 for Triangle\n";

       cout<<"4 for Rectangle\n";

       cout<<"5 for Rhombus\n";

       cout<<"6 for Parallelogram\n";

       cin>>choice;

       system("cls");

       switch(choice)

       {

       case 1:

           {

               float r;

               cout<<"Enter radius\n";

               cin>>r;

               Circle c("Circle","Yellow",r);

               c.getAttributes();

               cout<<"Perimeter : "<<c.getPerimeter()<<endl;

               cout<<"Area : "<<c.getArea()<<endl;

           }break;

       case 2:

           {

               float side;

               cout<<"Enter side\n";

               cin>>side;

               Square s("Square","Red",side);

               s.getAttributes();

               cout<<"Perimeter : "<<s.getPerimeter()<<endl;

               cout<<"Area : "<<s.getArea()<<endl;

           }break;

       case 3:

           {

               Triangle t("Triangle","Green");

               t.getAttributes();

               cout<<"Perimeter : "<<t.getPerimeter()<<endl;

               cout<<"Area : "<<t.getArea()<<endl;

           }break;

       case 4:

           {

               float l,b;

               cout<<"Enter Length and breadth\n";

               cin>>l>>b;

               Rectangle r("Rectangle","Blue",l,b);

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 5:

           {

               Rhombus r("Rhombus","Purple");

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 6:

           {

               float b,h;

               cout<<"Enter base\n";

               cin>>b;

               cout<<"Enter height\n";

               cin>>h;

               Parallelogram p("Parallelogram","Pink",b,h);

               p.getAttributes();

               cout<<"Perimeter : "<<p.getPerimeter()<<endl;

               cout<<"Area : "<<p.getArea()<<endl;

           }break;

       }

   }

}

To learn more about objects and classes,

https://brainly.com/question/21113563

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